A pendulum on planet x, where the value of g is unknown, oscillates with a period of 2.0 s. what is the period of this pen dulum if: a. its mass is doubled? b. its length is doubled? c. its oscillation amplitude is doubled? note: you do not know the values of m, il, or g, so do not assume any specific values.

Answer:

:)

Explanation:

Answer:

measure what

Explanation:

?????????????

Answer:

B. Mass

Explanation:

\(velocity = \frac{distance}{time} \)

\( \frac{(30 + 10 + 80) \times 1000}{83 \times 60} \)

\( = 0.024m.{s}^{ - 1} \)

(Hand-held) Pencil sharpener, and an Axe.

A simple machine is a (to its name) simple machine, used to complete a task that is uncomplicated. Such as the first example, a pencil sharpener. It has a small razor, and you turn a pencil inside to shave off unnecessary wood.

- - - - - - - - - - - - - - - - - - - - - -

My second example is a wedge. A hatchet (or axe) is a wedge, it pushes between two sides and increases force, therefore, breaking it apart.

- - - - - - - - - - - - - - - - - - - - - -

Good luck! :)

~pinetree

Answer:

centimeters

Explanation:

earth's plates move only a few centimeters per year.

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Experimental measurements don't necessarily reflect a physical quantity's genuine value. The ideal or theoretical value of a physical quantity, which is never perfectly measurable in reality, is that quantity's true value.

When a physical quantity is measured, it is always subject to a variety of causes of error, including the constraints of the measuring device, the environment, operator error, and random fluctuations.

The most that can be done is an estimation of the true value, which is expressed as a measured value with a corresponding uncertainty. The range of values that can be logically regarded as the actual value of the quantity being measured is reflected in the uncertainty. The accuracy of the measuring device, the operator's expertise, and the repeatability of the measurement process are all elements that influence the measurement's uncertainty. In conclusion, experimental measurements provide an estimate of a physical quantity's real value rather than the actual value.

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(a) The potential difference between the plates is approximately 8.97 Volts.

(b) The mass of the plastic sphere is approximately 1.94x10^-17 kg.

To calculate the potential difference between the plates, we can use the formula for electric force:

Electric force (F_e) = Charge (q) * Electric field (E)

The electric field (E) between the plates is given by:

Electric field (E) = Voltage (V) / Distance (d)

where;

Setting the electric force equal to the force of gravity (F_g) on the sphere, we have:

Charge (q) * Electric field (E) = Mass (m) * Acceleration due to gravity (g)

Solving for the electric field (E), we get:

Electric field (E) = (Mass (m) * Acceleration due to gravity (g)) / Charge (q)

Since the electric force (F_e) is given as 2.5x10^-15N and the charge (q) on the plastic sphere is +7.6x10^-19C, we can substitute these values into the equation:

2.5x10^-15N = (Mass (m) * 9.8 m/s^2) / 7.6x10^-19C

Solving for mass (m), we get:

Mass (m) = (2.5x10^-15N * 7.6x10^-19C) / (9.8 m/s^2)

Mass (m) ≈ 1.94x10^-17 kg

b. Now that we know the mass of the plastic sphere is 1.94x10^-17 kg, we can calculate the potential difference (V) between the plates using the formula for electric field:

Electric field (E) = Voltage (V) / Distance (d)

Solving for voltage (V), we get:

Voltage (V) = Electric field (E) * Distance (d)

We already know the distance between the plates (d) is 0.020 m, and we can use the electric field (E) that we calculated in part a, which is approximately:

Electric field (E) ≈ (2.5x10^-15N * 7.6x10^-19C) / (1.94x10^-17 kg * 9.8 m/s^2)

Plugging in the values, we can now calculate the potential difference (V):

Voltage (V) ≈ 8.97 V

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An example of heat converted into work is a steam turbine in a power plant, where high-pressure steam expands and drives a turbine to generate electricity. An example of work converted into heat is the operation of an electric heater, where electrical energy is converted into heat energy.

The temperature of water before it is boiled is typically lower than the temperature after boiling. The increase in temperature indicates that energy in the form of heat has been transferred to the water during the boiling process.

Heat converted into work:

An example of heat converted into work is a steam turbine in a power plant. The process involves the following steps:

High-pressure steam is produced by heating water in a boiler.

The high-pressure steam is then directed to a turbine, where it expands and pushes the turbine blades, causing the rotor to spin.

The spinning rotor is connected to a generator, which converts the mechanical energy into electrical energy, producing work in the form of electricity.

Work converted into heat:

An example of work converted into heat is the operation of an electric heater. The process involves the following steps:

Electrical energy from a power source is supplied to the electric heater.

The electrical energy is converted into heat energy by the resistive element inside the heater.

The generated heat is transferred to the surroundings, increasing the temperature of the surrounding environment.

When water is boiled in a pot, the temperature of the water before boiling is typically lower than the temperature after boiling. This increase in temperature indicates that energy in the form of heat has been transferred to the water during the boiling process.

The heat energy supplied to the water causes the water molecules to gain kinetic energy, increasing their motion.

As the kinetic energy of the water molecules increases, the temperature of the water rises.

Therefore, the increase in temperature of water after boiling indicates the transfer of heat energy to the water during the boiling process.

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The dog walked 5 meters backwards in the first 10 seconds, then 5 meters forward from 10-20 seconds. After 20 sec he was back where he started. Displacement (20sec) = zero.

Explanation:

To find displacement using velocity - time graph, we need to find area under the curve during time period 0 to 20 seconds.

Displacement [ area of Triangle (b=10 units & h=1 units) - area of trapezium (sum of parallel sides=30 units & h=1 unit)

= (1/2 * 10 * 1) - (1/2 * 30 * 1)

= - 10 m

Answer:

1 atm = 1.01E5 nt/m^2 = 1.01E5 pascals

5.05E5 nt/m^2 = 5.05E5 pascals

1 pascal = 1 nt/m^2

Answer:

the speed of the wave is 0.65 m/s

Explanation:

Given;

distance between two successive crests, λ = 1.4 m

number of crests, n = 8

number of waves formed = 7

The total distance covered by the wave, d= 7λ = 7 x 1.4 = 9.8 m

time of motion of the wave, t = 15 s

The speed of the wave is calculated as;

V = d/t

V = 9.8 / 15

V = 0.65 m/s

Therefore, the speed of the wave is 0.65 m/s

The kinematics and Newton's second law allow to find the results for the questions about the motion of the ball are:

Given parameters

To find

Kinematics studies the movement of bodies, looking for relationships between the position, speed and acceleration of bodies.

         v² = v₀² - 2 ax

Wher vo es la initial veloicity, a the acceleration y x is the distance,

When the ball stops the velocity is zero.

         0 = v₀² - 2ax

         a = \(\frac{v_o^2}{2x}\)  

Let's calculate

         a = \(\frac{38.2^2}{2 \ 0.135}\)  

         a = 5.4 10³ m / s²

Newton's second law establishes a relationship between force, mass, and acceleration of the body.

             F = ma

             F = 0.145 5.4 10³

             F = 7.84 10² N

In conclusion using kinematics and Newton's second law we can find the results for the questions about the motion of the ball are:

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The process of PLACING a compass wherever you want it involves Biology.  Biology deals with everything that has to happen for your brain to send instructions to your muscles, your muscles to operate your arm and your hand, and your hand to move the compass to where you want it, while your eyes keep track of what's happening and send course-corrections through your brain.

Once you get the compass there and see it start doing strange things, those EFFECTS are explained by laws of nature that are covered in Physics.

Placing a compass near a wire with live electrical current involves physics. Because, the deflection in magnetic field by the current from the electrical wire is dealt with physics.

A magnetic field is generated by the field lines originating from a magnet or an electrical  coil. The moving current is always associated with a magnetic field.

A compass acts as a tiny magnet and it deflects to the north in  the absence of an electrical field. If an electric field is brought in contact with the compass the needle will deflect into the direction of the magnetic field from the wire.

The strength of a magnetic field, associated electric field, magnetic flux etc. are more focused in the branches of physics. The magnetic properties of a substance is a physical property.

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Answer:

La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.

Explanation:

La masa de agua contenida dentro de la botella es igual a la diferencia entre la masa pesada totalmente llena y la masa pesada totalmente vacía, es decir:

\(m_{w} = 86.55\,g-24.25\,g\)

\(m_{w} = 62.3\,g\)

Ahora, de acuerdo con la definición de densidad, la masa es directamente proporcional a la densidad, entonces, podemos calcular la densidad del solvente mediante la siguiente relación:

\(\frac{m_{x}}{m_{w}} = \frac{\rho_{x}}{\rho_{w}}\) (1)

Donde:

\(m_{x}\) - Masa del tetracloruro de carbono, en gramos.

\(m_{w}\) - Masa del agua, en gramos.

\(\rho_{x}\) - Densidad del tetracloruro de carbono, en gramos por centímetro cúbico.

\(\rho_{w}\) - Densidad del agua, en gramos por centímetro cúbico.

Si sabemos que \(m_{x} = 123.95\,g\), \(m_{w} = 62.3\,g\) y \(\rho_{w} = 1\,\frac{g}{cm^{3}}\), entonces la densidad del tetracloruro de carbono es:

\(\rho_{x} = \left(\frac{m_{x}}{m_{w}} \right)\cdot \rho_{w}\)

\(\rho_{x} = 1.990\,\frac{g}{cm^{3}}\)

La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.

Answer:

Magnetic forces are non contact forces; they pull or push on objects without touching them. Magnets are only attracted to a few 'magnetic' metals and not all matter.

Answer:

the person above me is correct i think respectlfully he

not correct

Explanation:

lots of time spent wondering

For the two stars, star A appears 1/9 as bright as star B because of the inverse square law of brightness and their relative distances from Earth.

The apparent brightness of a star is inversely proportional to the square of its distance from Earth. Since star A is three times farther away from us than star B, its apparent brightness will be 1/9th of the brightness of star B, even though both stars have the same luminosity.

This is because the light from star A is spread out over a larger area by the time it reaches us, making it appear dimmer than star B.

To understand this concept, imagine two light bulbs of equal brightness, one placed 1 meter away from you and the other placed 3 meters away. The bulb placed 3 meters away will appear one-ninth as bright as the bulb placed 1 meter away, even though both bulbs have the same brightness.

Similarly, due to the inverse square law of brightness and their relative distances from Earth, star A appears 1/9 brighter than star B.

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COMPLETE QUESTION

Two stars are of equal luminosity. Star A is 3 times as far from you as star B. Star A appears ___ star B.

Answer:

The efficiency of the hammer is 72%.

Explanation:

output work/input work x 100%

18J/25J x 100%

0.72 x 100%

72%

Given:

Height = 53 m

Given that the rock is dropped from the top of a bridge above the river, let's answer the following questions:

• (a). The acceleration of the rock as it falls.

Since the rock is in free fall, the acceleration of the rock as it falls will be the acceleration due to gravity.

a = 9.8 m/s²

Therefore, the acceleration of the rock as it falls is 9.8 m/s².

• (b). How long does it take to hit the water?

To find the time, apply the formula:

Where:

s = 53 m

t is the time

a is the acceleration

u is the initial velocity = 0 m/s

Let's solve for the time, t:

Therefore, the time is 3.29 seconds.

(c). If the rock is dropped horizontally instead, there will be no change in the vertical velocity.

The time will also not change.

The time will be 3.29 seconds

ANSWER:

(a). 9.8 m/s^2

(b). 3.29 seconds

(c). 3.29 seconds

Velocity of the satellite that is orbiting earth is 83.45m/s, which makes the velocity of the rivet relative before striking also 83.45m/s and the time duration of collision is 4.53× 10⁻⁵ s. The avg force that is exerted by the rivet on the satellite is 9.27N and the energy that is generated by the collision is 1.63J.

a) Velocity of the satellite in an orbit 900 km above Earth's surface can be calculated as follows: Formula: `v = sqrt(GM/r)` Where,v = velocity, M = Mass of Earth, r = radius of the orbit (r = R + h)R = radius of the Earth = 6.37 × 10⁶ mh = height above Earth's surface = 900 km = 9 × 10⁵ mG = 6.67 × 10⁻¹¹ N m²/kg²By substituting the given values, we getv = sqrt((6.67 × 10⁻¹¹ × 5.97 × 10²⁴)/(6.37 × 10⁶ + 9 × 10⁵))= sqrt(6.965 × 10³) = 83.45 m/s.

Therefore, the velocity of the satellite in an orbit 900 km above Earth's surface is 83.45 m/s.

b) Velocity of the rivet relative to the satellite just before striking it can be calculated as follows: Velocity of the rivet, `v_rivet = v_satellite * sin(θ)`Where, v_satellite = 83.45 m/sθ = 90°By substituting the given values, we getv_rivet = 83.45 * sin 90°= 83.45 m/s.

Therefore, the velocity of the rivet relative to the satellite just before striking it is 83.45 m/s.

c) The time duration of collision, `Δt` can be calculated as follows:Δt = (2 * r_rivet)/v_rivet, Where,r_rivet = radius of the rivet = 3/2 × 10⁻³ m. By substituting the given values, we getΔt = (2 * 3/2 × 10⁻³)/83.45= 4.53 × 10⁻⁵ s.

Therefore, the time duration of collision is 4.53 × 10⁻⁵ s.

d) The average force exerted by the rivet on the satellite, `F` can be calculated as follows: F = m_rivet * Δv/ΔtWhere,m_rivet = mass of the rivet = 0.5 g = 0.5 × 10⁻³ kgΔv = change in velocity of the rivet = 83.45 m/sΔt = time duration of collision = 4.53 × 10⁻⁵ sBy substituting the given values, we get F = (0.5 × 10⁻³ * 83.45)/4.53 × 10⁻⁵= 9.27 N.

Therefore, the average force exerted by the rivet on the satellite is 9.27 N.

e) The energy generated by the collision, `E` can be calculated as follows: E = (1/2) * m_rivet * Δv²Where,m_rivet = mass of the rivet = 0.5 g = 0.5 × 10⁻³ kgΔv = change in velocity of the rivet = 83.45 m/s. By substituting the given values, we getE = (1/2) * 0.5 × 10⁻³ * 83.45²= 1.63 J.

Therefore, the energy generated by the collision is 1.63 J.

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mercury??????? my only guess

Mercury is that it?                        

Answer:

The formulas of the reactants are C3H8 and O2. The formulas of the products are CO2 and H2O.

Explanation:

Propane is the third member of the alkane group with the general formula CnH2n+2. According to this question, propane burns in oxygen to produce carbon dioxide and water. This means that propane and oxygen are the reactants of this reaction while carbon dioxide and water are the products.

The chemical formulas of the respective reactants and products are as follows:

REACTANTS:

Propane = C3H8 i.e C3H(2×3)+2

Oxygen = O2

PRODUCTS:

Carbon dioxide = CO2

Water = H2O

The balanced chemical reaction is as follows:

C3H8 + 5O2 ----> 3CO2 + 4H2O

Answer:

Option C would be your answer!

The formulas of the reactants are C3H8 and O2. The formulas of the products are CO2 and H2O.

Also, for the second part, the answer is Option B!

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Explanation:

This is correct on Edge! :D

I hope this helped!

The machine's efficiency is 81.61%, indicating that it converts 81.61% of the input energy into useful output energy, while the remaining percentage is lost as waste or dissipated in the process.

To calculate the efficiency, we can use the formula:

Efficiency = (Actual Output / Design Capacity) × 100

Given:

Actual Output = 7,407

Design Capacity = 9,050

Substituting the values into the formula:

Efficiency = (7,407 / 9,050) × 100

          = 0.817 × 100

          = 81.61%

Therefore, the efficiency of the machine is 81.61%.

Efficiency is a measure of how effectively a machine or system is utilizing its available capacity. In this case, the machine has a design capacity of 9,050 units, but it only produced an actual output of 7,407 units.

By dividing the actual output by the design capacity and multiplying by 100, we find that the machine's efficiency is 81.61%. This indicates that the machine is operating at approximately 81.61% of its full capacity.

A higher efficiency percentage would indicate a more optimal utilization of the machine's capacity, while a lower percentage suggests room for improvement in maximizing output.

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Answer:

If the velocity is constant, then there is no acceleration. That is, the value of the acceleration is 0.

Explanation:

Answer:

bc we play when we are bored and some people use it as a tradition to play on thanksgiving

Question:

A block of mass 1kg is placed on an inclined plane at an angle of 30° to the horizontal. Calculate the frictional force, normal reaction, the coefficient of the static friction​

Answer:

Break the mg force into components in the plane of the inclined plank. Now force acting parallel is mgsin37°. Perpendicular force is mgcos37° which is equal to normal force.  

Now calculate max value of friction force which is 0.8*mg cos37°. Since its greater than pulling force mgsin37°, the body will be at rest and acceleration is zero.  

Force applied by surface is vector sum of normal force and friction force acting.

Answer:

red supergiants can

(a) The radius of the wheel = 22 ft

The wheel is rotating 13 RPM counterclockwise

Angular speed = angular velocity = ω = 2πf = 2 × π × 13 = 26π rad/min (since 1 rev = 2π radians)

Since 1 min = 60 sec, ω = (26π)/60 rad/sec = 13π/30 rad/sec

The linear speed v of a point on the rim of the wheel is given by v = r × ω = 22 × 13π/30 = 22.82 ft/s

Therefore, w = 13π/30 rad/sec and v = 22.82 ft/sec

(b) The radius of the wheel = 6 inThe wheel is rotating at 30°/sec

The angular speed = ω = 30°/sec × (π/180°) = π/6 rad/sec

The linear speed v of a point on the rim of the wheel is given by v = r × ω = 6 × π/6 = π in/sec

The angular speed in RPM can be calculated as follows:

In 1 min, the angle rotated = 360°No. of seconds in 1 min = 60∴

The angle rotated in 1 sec = 360°/60 = 6° or (π/30) radThe angular speed in rad/sec and the angular speed in RPM is given by w = π/6 rad/sec and w = (30/π) × π/6 = 5 RPM

(c) The radius of the Earth = 3960 milesThe circumference of the Earth = 2 × π × radius = 2 × π × 3960 ≈ 24,902 miles (approx.)

One rotation of the Earth is completed in 24 hours or 24 × 60 × 60 = 86,400 secLinear speed v of a point on the equator of the Earth is given byv = circumference of the Earth/time taken for 1 rotation= 24,902/86,400 ≈ 0.2887 miles/sec

Therefore, v = 0.2887 × 60 × 60 = 1040 miles/hourAngular speed = ω = 2πf = 2π/Twhere T = time taken for 1 rotation of the Earth= 24 hours = 24 × 60 × 60 = 86,400 sec∴ ω = 2π/86,400 rad/sec

Angular speed in RPM can be calculated as follows:In 1 min, the angle rotated = 360°No. of seconds in 1 min = 60∴

The angle rotated in 1 sec = 360°/60 = 6° or (π/30) radThe angle rotated in 24 hours = 360°No. of seconds in 24 hours = 24 × 60 × 60 = 86,400∴

The angle rotated in 1 sec = 360°/86,400 = 1/240° or π/43,200 radThe angular speed in RPM is given by w = (360°/43,200) × 60 = 0.1666 RPM (approx.)

(d) The radius of the tire = 12 inchesThe speed of the car = 75 mphLet the car travel for 1 hour in which the tire makes x revolutions∴

The distance travelled by the car in 1 hour = 75 miles = circumference of the tire × x= 2π × 12 × x inches= 24πx inchesTherefore, 24πx = 75 × 5280 × 12 inches or x = 19600 revolutions∴

The tire makes 19600 revolutions in 1 hour= 19600 × 2π radians= 39200π radians∴ Angular speed = ω = 39200π/3600 = 109.11 rad/sec= (109.11/2π) RPM= 17.36 RPM (approx.)

Therefore, the angular speed in rad/sec is 109.11 rad/sec and the angular speed in RPM is 17.36 RPM.

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The estimated product of 7 7/9 x 6 7/9 to the nearest whole number is 56.

to estimate 7 7/9 x 6 7/9 to the nearest whole number, you can round both numbers to the nearest whole number and then multiply. Rounded to the nearest whole number, 7 7/9 is approximately 8 and 6 7/9 is approximately 7. Therefore, 8 x 7 is 56. So the estimated answer to the nearest whole number is 56.

estimate the product of 7 7/9 x 6 7/9 to the nearest whole number. Let's follow these steps:

1. First, we'll round both mixed numbers to their nearest whole numbers. In this case, 7 7/9 rounds up to 8 and 6 7/9 rounds up to 7.

2. Now that we have rounded numbers, we can multiply them together: 8 x 7 = 56

So, the estimated product of 7 7/9 x 6 7/9 to the nearest whole number is 56.

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