A penguin can dive 48 meters below the surface of the water to reach a fish. It dives 2% of the total depth every 1 second.

What is the total depth of the penguin after 4 seconds?

−3.84 meters
−0.96 meters
−1.92 meters
−2.88 meters

Answer:

I think it's false

Step-by-step explanation

Answer:

(4, 10)

Step-by-step explanation: you go 4 over from 2 and you get -2. if you go over 10 you get -5

An expression for given sequence of operations is: j + 3^9

In this question, we need to write an expression for the sequence of operations described below.

raise 3 to the 9th power, then add the result to j

Consider the part of given statement,

raise 3 to the 9th power

We write this as: 3^9

then we add this result to j.

So, we get an expression: 3^9 + j

Therefore, an expression for given sequence of operations is: j + 3^9

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The range of the exponential function y based on its equation and the context of the problem is; 0 < y ≤ 45529

The range of a function is the set that contains all possible output values for the function.

In this question, the function is given as: y = 45,529(0.78)^x.

It is an exponential function with initial value 45,529 and rate of change  of 0.78.

Now, it should be noted that exponential functions that are not shifted down, such as this one, are never negative nor zero. Thus, the range also has the restriction y > 0, and is given by:

D. 0 < y ≤ 45529

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Answer:

The population of deer at any given time = 200(e^0.03t)  ÷ (1.5 + (e^0.03t))

Step-by-step explanation:

This is an example of logistic equation on population growth

carrying capacity, k = 200

Rate, r = 3% = 0.03

Initial Population, P1 =  80

P(t) =?

P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))

P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))

     = (16000(e^0.03t))  ÷ (120 + 80(e^0.03t))

      = 200(e^0.03t)  ÷ (1.5 + (e^0.03t))

Answer:

Concept:

When encountering questions that ask for simplifying expressions through operation, following the PEMDAS method would be easier:

Therefore, the whole process of simplifying the given expression should follow the PEMDAS method. For extra, whenever there are two occurences of the same operation, then prioritize the leftmost and go right.

Hope this helps!! :)

Please let me know if you have any questions or need further explanation

Step-by-step explanation:

Heron's formula when all 3 sides (a, b, c) are given :

s = (a + b + c)/2

A = sqrt(s(s-a)(s-b)(s-c))

in our case

s = (34+73+89)/2 = 98

A = sqrt(98(98-34)(98-73)(98-89)) =

= sqrt(98×64×25×9) = sqrt(98)×8×5×3 =

= sqrt(2×49)×120 = sqrt(2)×7×120 =

= sqrt(2)×840 = 1,187.939392... ≈ 1,188 in²

The nearest Whole percent, the percent increase of women students is approximately 21%.

The percent increase of women students, we need to compare the number of women students in 2005 and 2006.

In 2005, the number of women students was 123.

In 2006, the number of women students was 149.

To find the increase, we subtract the initial value (2005) from the final value (2006):

Increase = Final Value - Initial Value

Increase = 149 - 123

Increase = 26

Next, we need to calculate the percent increase. The percent increase is given by the formula:

Percent Increase = (Increase / Initial Value) * 100

Plugging in the values:

Percent Increase = (26 / 123) * 100

Calculating the percent increase:

Percent Increase ≈ 21.14%

Rounding to the nearest whole percent, the percent increase of women students is approximately 21%.

Therefore, the answer is 21%.

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Step-by-step explanation:

SI=P×R×T/100

=90000×6×10(12)\100

=648000

amount=principal+simple interest

648000+90000

738000

Conniving these points and connecting them, we get a V- shaped graph that's reflected vertically and shifted 4 units to the left wing.

       To graph the function g( x) = - f( x 4), we need to start with the graph of the function f( x) = | x| and  also apply the given  metamorphoses.  The function f( x) = | x| represents the absolute value function, which is a V- shaped graph symmetric with respect to the y- axis.  

First, we shift the graph of f( x) = | x| horizontally by 4 units to the left by replacing x with( x 4). This results in f( x 4).  Next, we multiply the entire function by-1, which reflects the graph vertically. This gives us- f( x 4).  Combining these  metamorphoses, we've the function g( x) = - f( x 4). To graph g( x), we can  compass a many points and  also draw the graph by connecting them.

Let's start with the original graph of f( x) = | x| and apply the  metamorphoses

For f( x)  x = -3,-2,-1, 0, 1, 2, 3  

f( x) =  3, 2, 1, 0, 1, 2, 3  For

g( x) = - f( x 4)  x = -7,-6,-5,-4,-3,-2,-1  

g( x) = -3,-2,-1, 0,-1,-2,-3

conniving these points and connecting them, we get a V- shaped graph that's reflected vertically and shifted 4 units to the left wing.

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Answer:

To find the radius of the circle inscribed in an isosceles triangle, we can use the following formula:

r = (a/2) * cot(π/n)

where r is the radius of the inscribed circle, a is the length of one of the equal sides of the isosceles triangle, and n is the number of sides of the polygon inscribed in the circle.

In this case, we have an isosceles triangle with two sides of 5cm and one side of 6cm. Since the triangle is isosceles, the angle opposite the 6cm side is bisected by the altitude and therefore, the two smaller angles are congruent. Let x be the measure of one of these angles. Using the Law of Cosines, we can solve for x:

6^2 = 5^2 + 5^2 - 2(5)(5)cos(x)

36 = 50 - 50cos(x)

cos(x) = (50 - 36)/50

cos(x) = 0.28

x = cos^-1(0.28) ≈ 73.7°

Since the isosceles triangle has two equal sides of length 5cm, we can divide the triangle into two congruent right triangles by drawing an altitude from the vertex opposite the 6cm side to the midpoint of the 6cm side. The length of this altitude can be found using the Pythagorean theorem:

(5/2)^2 + h^2 = 5^2

25/4 + h^2 = 25

h^2 = 75/4

h = sqrt(75)/2 = (5/2)sqrt(3)

Now we can find the radius of the inscribed circle using the formula:

r = (a/2) * cot(π/n)

where a = 5cm and n = 3 (since the circle is inscribed in a triangle, which is a 3-sided polygon). We can also use the fact that the distance from the center of the circle to the midpoint of each side of the triangle is equal to the radius of the circle. Therefore, the radius of the circle is equal to the altitude of the triangle from the vertex opposite the 6cm side:

r = (5/2) * cot(π/3) = (5/2) * sqrt(3) ≈ 2.89 cm

Therefore, the radius of the circle inscribed in the isosceles triangle with sides 5cm, 5cm, and 6cm is approximately 2.89 cm.

The range of the given equation is [-1, infinity).

We are given that;

Equation  y= underroot(x+5​)

Now,

The domain of this equation is the set of x values that make the expression under the square root non-negative.

That is, x+5 >= 0, or x >= -5. So the domain is [-5, infinity).

The range of this equation is the set of y values that are obtained by plugging in the domain values into the equation. Since the square root function is always non-negative, and we are subtracting 1 from it, the smallest possible value of y is -1, when x = -5. As x increases, y also increases, and there is no upper bound for y.

Therefore, by the range the answer will be [-1, infinity).

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Answer:

70 ish

Step-by-step explanation:

The completed table of the functions and inverses can be presented as follows;

1. t(x) → a(x)

2. Q(x) → B(x)

3. G(x) → c(x)

4. f(x) → D(x)

5. y(x) → w(x)

6. e(x) → R(x)

7. U(x) → H(x)

8. P(x) → J(x)

9. m(x) → k(x)

10. S(x) → n(x)

Making x the subject of the given functions to find the inverse gives;

1. a(x) = 2•(x - 6)

Therefore;

x = (a(x)/2) + 6

t(x) = (x/2) + 6

Therefore;

2. G(x) = (1/4)•x²

4•G(x) = x²

x = 2•√(G(x))

3. B(x) = √(x)/4

4•B(x) = √(x)

x = 16•(B(x))²

Q(x) = 16•x²

Therefore;

4. D(x) = (x + 6)/2

x = 2•D(x) - 6

f(x) = 2•x - 6

Therefore;

5. y(x) = (4•x + 2)²

(√(y(x)) - 2)/4 = 4•x

w(x) = (√(x) - 2)/4

Therefore;

6. R(x) = (1/4)•(4•x)²

x = √(4•R(x))/4 = √(R(x))/2

e(x) = √(x)/2

Therefore;

7. H(x) = 2•x + 6

(H(x) - 6)/2 = H(x)/2 - 3

x = H(x)/2 - 3

U(x) = x/2 - 3

Therefore;

8. J(x) = (√(x + 2))/4

x = (4•J(x))² - 2

P(x) = (4•x)² - 2

Therefore;

9. k(x) = x/4 + 3

x = 4•(k(x) - 3) = 4•k(x) - 12

m(x) = 4•x - 12

Therefore;

10. n(x) = 4•(x + 3)

x = n(x)/4 - 3

S(x) = x/4 - 3

Therefore;

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The possible exact values of the trigonometric functions of θ are:

sin θ = -1/√3,  cos θ = √3/3, sec θ = √3

The law of sines, also known as the sine rule, is a mathematical principle that relates the sides and angles of a triangle. It states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is constant for all three sides of the triangle.

Trigonometric functions are mathematical functions that relate angles to the ratios of the sides of a right triangle. The six primary trigonometric functions are sine (sin), cosine (cos), tangent (tan), cosecant (csc), secant (sec), and cotangent (cot). Each function represents a different ratio of two sides of a right triangle and can be used to solve problems in geometry, physics, engineering, and other fields that involve angles and triangles.

According to the given information,

Given that tan θ = -√(1/3) and 0 < θ < 180°, we can use the trigonometric identities to find the values of the other trigonometric functions of θ.

First, we can use the definition of the tangent function:

tan θ = opposite/adjacent

Since tan θ = -√(1/3), we can assign opposite = -1 and adjacent = √3 as their ratio equals -√(1/3). This means that the terminal side of the angle θ will lie in the fourth quadrant of the unit circle since the opposite is negative and the adjacent is positive.

Next, we can use the Pythagorean identity:

sin²θ + cos²θ = 1

to find the value of sin θ. Since we know that θ is in the fourth quadrant, we can assign sin θ = -1/√3, since sin θ is negative in the fourth quadrant and the ratio of opposite/hypotenuse of a 30-60-90 triangle is √3/2, which means the ratio of hypotenuse/opposite is 2/√3 = √3/3.

Then, we can use the definition of the cosine function:

cos θ = adjacent/hypotenuse

to find the value of cos θ. We know that adjacent = √3 and the hypotenuse is positive (since it is a length), so we can assign cos θ = √3/3.

Finally, we can use the reciprocal identity:

sec θ = 1/cos θ

to find the value of sec θ. We know that cos θ = √3/3, so we can assign sec θ = √3.

Therefore, the possible exact values of the trigonometric functions of θ are:

sin θ = -1/√3

cos θ = √3/3

tan θ = -√(1/3)

sec θ = √3

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The simplified expression is  d/ c⁴.

To simplify the expression cd³ c⁻⁵ x d⁻², we can combine the variables with the same base (c and d) by adding their exponents:

Using the property of exponents as

When multiplying two exponential expressions with the same base, you can add the exponents. This can be expressed as follows:

aᵇ x aⁿ= aᵇ⁺ⁿ

When dividing two exponential expressions with the same base, you can subtract the exponents. This can be expressed as follows:

aᵇ / aⁿ= aᵇ⁻ⁿ

So, cd³ c⁻⁵ x d⁻²

= c¹⁻⁵ x d³⁻²

= c⁻⁴ x d¹

= dc⁻⁴

Again from the property of exponents

a⁻ᵇ = 1/aᵇ

So,  dc⁻⁴

= d/ c⁴

Therefore, the simplified expression is  d/ c⁴.

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The area of the square with a side length of 3.1 meters is 9.61 square meters.

To find the area of a square, we need to multiply the length of one side by itself. In this case, the square has a side length of 3.1 m.

Area of a square = side length × side length

Substituting the given side length into the formula:

Area = 3.1 m × 3.1 m

To perform the calculation:

Area = 9.61 m²

It's worth noting that when calculating the area, we are working with squared units. In this case, the side length is in meters, so the area is expressed in square meters (m²). The area represents the amount of space enclosed within the square.

Remember, to find the area of any square, you simply need to multiply the length of one side by itself.

The area of the square with a side length of 3.1 meters is 9.61 square meters.

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Answer:

41.6 km/h

Step-by-step explanation:

Nao drives 95mi/2.5hr or 38 miles per hour, or 60.8 km/h

1 hr 15 min is the same as 1.25 hours

Arban drives 128km/1.25hr or 102.4 km/h

The difference is 102.4-60.8 = 41.6

Answer: 0.78

Step-by-step explanation:

Given : P(bridge and swim) = 0.67

P(bridge)= 0.86

Formula for conditional probability :

\(P(B|A)=\dfrac{P(\text{A and B})}{P(A)}\)

So, \(\text{P(swim }|\text{ bridge) = }\dfrac{\text{ P(bridge and swim)}}{\text{P(bridge)}}\)

\(=\dfrac{0.67}{0.86}\approx0.78\)

Hence, the probability that the member swims, given that the member plays bridge = 0.78

Answer:

2

Step-by-step explanation:

60/30 is 2

HOpe this helps :D

PLz mark brainliest if correct :D

Answer:

inequality form: x \(\leq\) -2 or x > 3

interval notation form: (-∞,-2] ∪ (3,∞)

Step-by-step explanation:

I attached a picture that shows all the work. You begin by isolating then solving for x on both sides. Then form a solution using the information found out about x. For example, you can combine the found inequalities for x to solve that x must be GREATER than 3 while being LESS than -2. Using that you can form an line and make a line. Remember, when writing in interval notation form you always begin from the left to the right (in reference) to the number line.

Answer:

Yes

The two 48 degree angles given show that the 90 degree angle intersects both lines at the same position, making the lines parallel

Answer: You have to save $128 more dollars.

Step-by-step explanation: The iPad costs $353 and you already have $225, so to find the answer you have you subtract what you already have from how much it costs. So 353 - 225 = 128. You need to save up $128 more dollars to get the iPad. (I think this is correct, I tried)

1) Number of participants whose headache remained is: 62

2) The probability of randomly selecting an individual whose headache remained is: 0.4133

3) The probability of randomly selecting an individual whose headache remained and took a placebo is: 0.2933

From the table, we have the parameters as:

Number of participants that took medicine and headache went away = 120

Number of participants that took placebo and headache went away = 68

Number of participants that took and headache remained = 18

Number of participants that took placebo and headache remained = 44

1) Number of participants whose headache remained = 18 + 44 = 62

2) The probability of randomly selecting an individual whose headache remained is:

62/(62 + 120 + 68)

= 62/150

= 0.4133

3) The probability of randomly selecting an individual whose headache remained and took a placebo is:

44/150 = 0.2933

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