a piece of a thick ring of metal with height h and resistance r is connected to a battery, creating a uniform current i throughout the piece of ring, as shown in the figure above. a second piece of a ring has height 2h but is otherwise identical to the first piece. the second piece of ring is connected to the battery in the same way as the first piece. what is the resistance of the second piece?
Answers
The resistance of the second piece of the thick ring of metal is half the resistance of the first piece, or R2 = r/2.
Given that a piece of a thick ring of metal with height h and resistance r is connected to a battery, creating a uniform current i throughout the piece of ring, and a second piece of a ring has height 2h but is otherwise identical to the first piece and is connected to the battery in the same way as the first piece, we can determine the resistance of the second piece by following these steps:
1. Recall the formula for resistance:
R = ρ(L/A)
where
R is resistance,
ρ is resistivity,
L is length, and
A is the cross-sectional area.
2. For the first piece, the cross-sectional area A1 is height h times width w, so A1 = hw.
3. For the second piece, the height is 2h. The cross-sectional area A2 is height (2h) times width w, so A2 = 2hw.
4. The ratio of the cross-sectional areas of the two pieces is
A1/A2 = (hw)/(2hw)
= 1/2.
5. Since the pieces are otherwise identical, their resistivities (ρ) are the same. The ratio of the resistances is
R1/R2 = (ρL1/A1) / (ρL2/A2)
= (L1/A1) / (L2/A2).
6. Both pieces have the same length, so L1 = L2. Therefore, the ratio of the resistances is
R1/R2 = (1/A1) / (1/A2)
= A2/A1.
7. Substituting the ratio of the cross-sectional areas, we have R1/R2 = 1/2.
8. The resistance of the second piece is R2 = R1 * (1/2).
Thus, the resistance of the second piece of the thick ring of metal is half the resistance of the first piece, or R2 = r/2.
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Related Questions
Astronomers believe that the mergers of smaller galaxies can trigger the formation of
Answers
Astronomers believe that the mergers of smaller galaxies can trigger the formation of larger galaxies and active galactic nuclei (AGN).
When smaller galaxies merge, their stars, gas, and dark matter combine, creating a larger and more massive galaxy. This process also often leads to an increase in star formation, as the colliding gas clouds create regions of high density, which are conducive to the birth of new stars.
Additionally, the merger can cause gas and dust to accumulate in the central region of the new galaxy, leading to the formation of an active galactic nucleus (AGN). This AGN consists of a supermassive black hole surrounded by an accretion disk of gas, which emits high amounts of energy as the gas spirals into the black hole.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
Answers
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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apply the necessary conversions to find: a) the speed in m/s equal to 78.0 mi/h b) the area in ft2 of a rectangle with sides 18.6 m and 3.82 m. c) the height in cm of a person who is 5 ft 7 in tall.
Answers
The speed in m/s equal to 78.0 mi/h AND the area in ft2 of a rectangle with sides 18.6 m and 3.82 m AND the height in cm of a person who is 5 ft 7 in tall.
a) To find the speed in m/s equal to 78.0 mi/h, we use the conversion factor,
1 mi = 1609.344 meters and 1 h = 3600 s.78.0 mi/h = (78.0 mi/h) x (1609.344 m/mi) x (1 h/3600 s)= 35.0 m/s
Therefore, the speed in m/s equal to 78.0 mi/h is 35.0 m/s.
b) The area in ft2 of a rectangle with sides 18.6 m and 3.82 m is calculated as follows:
First, we convert the sides from meters to feet using the conversion factor
1 m = 3.281 ft.18.6 m = 18.6 m x (3.281 ft/m) = 61.024 ft3.82 m = 3.82 m x (3.281 ft/m) = 12.532 ft
The area is given by the formula A = L x W, where L is the length and W is the width.
A = (61.024 ft) x (12.532 ft)A = 765.69 ft2Therefore, the area in ft2 of a rectangle with sides 18.6 m and 3.82 m is 765.69 ft2.
c) The height in cm of a person who is 5 ft 7 in tall can be found by converting the height to inches and then to centimetres.
1 ft = 12 in5 ft = 5 ft x 12 in/ft = 60 in5 ft 7 in
= 60 in + 7 in = 67 in1 in = 2.54 cm67 in
= 67 in x (2.54 cm/in) = 170.18 cm
Therefore, the height in cm of a person who is 5 ft 7 in tall is 170.18 cm.
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What property of an electromagnetic wave changes when the wave is encoded with analog information?
a)Speed
b)Ampltude
c)frequency
d)Wave length
Answers
Answer: C
Frequency
Explanation:
In an analog to digital converter, the analog voltage is sampled at a regular interval of time which is known as sampling frequency. Therefore, the property of an electromagnetic wave that changes when the wave is encoded with analog information is frequency.
Air is being pumped into a spherical balloon so that its volume increases at a rate of 50 cm3/s. How fast is the radius of the balloon increasing when the diameter is 30 cm
Answers
A spherical balloon being filled with air at a rate of 50 cm3/s, increasing its volume. The spherical balloon has a 30 cm diameter. The spherical balloon's radius is therefore r = d/2 = 30/2 = 15 cm.`.
We need to find the rate of change of radius, i.e., `dr/dt` when `d = 30 cm`. The volume of the spherical balloon is given by the formula: `V = (4/3)πr³`Differentiating w.r.t t on both sides of the above equation, we get: `dV/dt = 4πr²(dr/dt)`Now, we are given that `dV/dt = 50 cm³/s` and `r = 15 cm`. Substituting these values in the above equation, we get: 50 = 4π(15)²(dr/dt) ⇒ `dr/dt = 50/(4π×15²)`On solving, we get:` dr/dt = 0.0222 cm/s`. Therefore, the rate of change of radius when the diameter of the balloon is 30 cm is `0.0222 cm/s`.
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four pieces of graph paper a ruler two pencils a helper Follow these steps: Choose which person will be the sender (satellite) and which will be the receiver (television). Each person then draws a 10" by 10" square on a piece of graph paper. Draw a grid within the square, so that each small square of the grid is about 1 inch square. This should give you an area with 100 squares in it. The size of the small squares will depend somewhat on the graph paper used - make sure you use some of the lines on the graph paper as guidelines. The sender now draws a simple picture within the 10" x 10" square without letting the receiver see what he or she is drawing. The sender should now “read” the picture to the receiver, using a digital code. If a square on the graph paper is blank, the sender says “Zero”; if the square is filled in or has any mark in it at all, the sender says, “One.” Using this code, the sender starts with the top row and reads from left to right, one square at a time. The receiver, upon hearing this code, transfers the information to his own graph paper. The receiver must mark the graph paper by starting with the top row of squares and going from left to right. If the sender says “zero,” no mark is made. If the sender says “one,” the receiver should fill in the square completely! At the end of the first row, the sender should say, “End row 1,” and repeat this at the end of each row. At the end of the last row, compare the two pictures. Check the results to see how accurate the transfer was. Now, get two more pieces of graph paper and draw 10” by 10” squares on them. This time, your grid size should be close to 1/4 inch rather than one inch. You will have many more squares than before! You can use the same drawing or switch people and the new sender can draw another picture. Follow the same procedure. Describe your results. Compare the accuracy of the two pictures drawn by the receiver. Which one is more precise
Answers
Answer:
is there a picture? so I can understand it more and it will be easier for me to answer. thank you
Answer:
The second one is more accurate because we were able to draw more precisely and accurately, the first picture was more of a general idea of the picture and the second picture was more of a detailed version.
Explanation:
I just did this assignment and this is what I turned in so yeah I hope this is good enough, if you need more of an explanation though ill try to lengthen it. =]
10 poin
What is the momentum of a 25kg cart traveling left with a velocity of 10
m/s?
Answers
Mass times velocity gives you momentum 25*10=250
below are four different objects. their centre of mass c is shown. which object is not in equilibrium?
Answers
option B. The ruler is the object that is not in equilibrium. Option B.
The ruler is not in equilibrium. What is equilibrium? Equilibrium is a state of balance in which all the forces and moments on a body are equal and balanced, resulting in no net force or acceleration. When an object is at equilibrium, it is either at rest or moving with a constant velocity. The stability of an object is determined by the location of its center of mass. If the object's center of mass is above its base of support, it is unstable and will tip over.To determine whether the four given objects are in equilibrium, we must first determine their centers of mass. In the figure, the black dot indicates the center of mass. Let's start with object A: A metal sphere: The center of mass is located at the center of the sphere, which is also the geometric center, so the sphere is in equilibrium. Object B: A ruler: The center of mass is located at the center of the ruler, which is also the geometric center. However, the base of the ruler is not wide enough to support it when it is not vertical, so it is not in equilibrium. Object C: A box: The center of mass is located at the center of the box, which is also the geometric center, so the box is in equilibrium. Object D: A cone: The center of mass is located slightly above the geometric center, which is at the bottom of the cone. The base of the cone, however, is wide enough to support it, so it is in equilibrium.
The ruler is the object that is not in equilibrium. Option B.
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Element Z has a half-life of 5 hours. After 1 day has passed, what percentage of Element Z would be remaining? After 1 day, % of Element Z would be remaining.
Answers
After 1 day has passed, approximately 6.25% of Element Z would be remaining.
The half-life of an element is the time it takes for half of the initial amount of the element to decay or transform into another element or isotopes. In this case, Element Z has a half-life of 5 hours.
To determine the percentage of Element Z remaining after 1 day (24 hours), we need to calculate the number of half-lives that have occurred.
Since the half-life of Element Z is 5 hours, there are 24 hours divided by 5 hours, which equals 4.8 half-lives.
Each half-life reduces the amount of Element Z by half. So, after 4.8 half-lives, the remaining amount of Element Z would be (1/2)^(4.8) = approximately 0.0625 or 6.25%.
Therefore, after 1 day has passed, approximately 6.25% of Element Z would be remaining.
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the speed of light in water compared to the speed of light in a vacuum is a. can be faster or slower depending on the intensity. b. can be faster or slower depending on the color. c. slower. d. the same. e. faster.
Answers
Option c. The speed of light in water compared to the speed of light in a vacuum is slower.
Light refers to electromagnetic radiation of any wavelength, whether it is visible or not. Light is a kind of energy that travels in waves. This implies that light, like other waves, has both frequency and wavelength. A vacuum is a space that is entirely devoid of matter. There is no air, liquid, or solid in a vacuum. The pressure in a vacuum is also zero. A vacuum is a place where the atmosphere's pressure is lower than the atmospheric pressure at sea level.
Speed of light in water compared to the speed of light in vacuum. The speed of light in vacuum is approximately 300,000 kilometers per second (km/s), whereas the speed of light in water is around 225,000 km/s. Light travels slower in water than in a vacuum, which means that the speed of light in water is slower than the speed of light in vacuum. Therefore, option c. slower is the correct answer.
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What is the velocity of a wave with a frequency of 300 Hz and a wavelength of 0.45 m?
Answers
Answer:
velocity= 135m/s
Explanation:
velocity = 300×0.45
= 135m/s²
Are you made of time particles? Explain.
Answers
SOMEONE PLS HELP!!! THIS IS HARD!!! I will make brainliest and this is in science!
Answers
Answer: It has the skill to nest
sorry if I'm wrong
Answer:
B: A colorful beak
Explanation:
i hope this helped!
Study the distance-time graph, showing the distances that eight different things cover in 120 seconds or less. The letters below correspond to the lines on the graph. For each object, calculate the average speed, and then match it with the closest correct answer.
A:
B:
C:
D:
E:
F:
G:
H:
Answers
Answer:
This question appear incomplete
Explanation:
This question appear incomplete because there is no list of closest correct answer there. Although can still be well attempted.
The formula to be used here is
average speed = distance ÷ time
The unit of speed here would be meters per second (m/s). However, some of the lines do not really fall on a measurable line on the graph and can only be "best assumed".
A: distance is 1600 meters
time appear to be 4 seconds (definitely less than 5 seconds according to the graph).
speed = 1600 ÷ 4
speed = 400 m/s
B: distance is 1600 meters
time appear to be 18 seconds (definitely less than 20 seconds according to the graph)
speed = 1600 ÷ 18
speed = 88.89 m/s
C: distance is 1600 meters
time is 65 seconds
speed = 1600 ÷ 65
speed = 24.62 m/s
D: distance is 1600 meters
time is 105 seconds
speed = 1600 ÷ 105
speed = 15.24 m/s
E: distance is 1100 meters
time is 120 seconds
speed = 1100 ÷ 120
speed = 9.17 m/s
F: distance is 500 meters
time is 120 seconds
speed = 500 ÷ 120
speed = 4.17 m/s
G: distance appear to be 250 meters
time is 120 seconds
speed = 250 ÷ 120
speed = 2.08 m/s
H: distance appear to be 50 meters
time is 120 seconds
speed = 50 ÷ 120
speed = 0.42 m/s
The average speed for each object are:
1. The average speed of A is 400 m/s
2. The average speed of B is 88.89 m/s
3. The average speed of C is 24.62 m/s
4. The average speed of D is 15.24 m/s
5. The average speed of E is 9.17 m/s
6. The average speed of F is 4.17 m/s
7. The average speed of G is 2.08 m/s
8. The average speed of H is 0.33 m/s
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.
Average speed = Total distance / total timeWith the above formula, we can obtain the average speed for each object as follow:
1. Determination of average speed of A
Total distance = 1600
Total time = 4 s
Average speed =?Average speed = 1600 / 4
Average speed of A = 400 m/s2. Determination of average speed of B
Total distance = 1600
Total time = 18 s
Average speed =?Average speed = 1600 / 18
Average speed of B = 88.89 m/s3. Determination of average speed of C
Total distance = 1600
Total time = 65 s
Average speed =?Average speed = 1600 / 65
Average speed of C = 24.62 m/s4. Determination of average speed of D
Total distance = 1600
Total time = 105 s
Average speed =?Average speed = 1600 / 105
Average speed of D = 15.24 m/s5. Determination of average speed of E
Total distance = 1100
Total time = 120 s
Average speed =?Average speed = 1100 / 120
Average speed of E = 9.17 m/s6. Determination of average speed of F
Total distance = 500
Total time = 120 s
Average speed =?Average speed = 500 / 120
Average speed of F = 4.17 m/s7. Determination of average speed of G
Total distance = 250
Total time = 120 s
Average speed =?Average speed = 250 / 120
Average speed of G = 2.08 m/s8. Determination of average speed of H
Total distance = 40
Total time = 120 s
Average speed =?Average speed = 40 / 120
Average speed of H = 0.33 m/sLearn more: https://brainly.com/question/14988345
How can the direction of a tensional force be changed without diminishing the force?
Answers
Given what we know, we can confirm that the tensional force of a system can in theory be changed without diminishing its force through the use of an ideal pulley.
What is an ideal pulley?A pulley is a small wheel through which a string or chain is run. These are used in order to change the direction of a force. An ideal pulley would be one in which there is no friction and the pulley itself would have no mass. Therefore, the force would be able to change directions without giving part of its force to the pulley system.Therefore, we can confirm that the only known way to change the direction of a force without diminishing its value would be through the use of a frictionless and massless pulley system otherwise known as an ideal pulley.
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Select the correct answer
A car moves with an average speed of 45 miles/hour How long does the car take to travel 90 miles?
Answers
Answer:the 2 hours
Explanation: Its just simple math
Answer:
2
Explanation:
hope this helps
a marble rolls off of a desk with a speed of 3 m/s. the top of the desk is 1.5 m above the floor. a. how long does it take for marble to hit the ground? b. how far away from the table is the marble when it hits the ground?
Answers
The height represented by s is equal to the height represented by theta which is 74. The value of t square is used to add half negative 9.81 to the power of 2. The h value is 42.51 in meters.
How do you calculate the speed & time of an object just before it hits the ground?Pick the duration of the fall of the item. We'll use a time of 8 seconds in this illustration. The formula v = v0 + gt = 0 + 9.80665 * 8 = 78.45 m/s may be used to get the final free fall speed (right before impact).As a result of gravity, there is a downward vertical acceleration of 9.8 m/s/s. A projectile's vertical velocity changes by 9.8 meters per second (m/s) each second, A projectile's vertical motion does not affect how it moves horizontally.Formula T tof=2(v 0 sin 0)g. A projectile's flight period begins at this point, whether it is being launched or colliding with a flat, horizontal surface.Given data :
Equation 1: y=y0+v0yt+1/2 at²
where y0=1.5m , y=0 meters (the floor), v0y=0, and a=-9.8 m/s2
. Plugging
these numbers in we get
The substitution of the horizontal component of this velocity was made. The 190 is equal to 74 cos 23 and we use the value of t to figure out the distance. equal to a square and a y t square.
The acceleration in the direction of the y is negative if we make the substitution. The height represented by s is equal to the height represented by theta which is 74. The value of t square is used to add half negative 9.81 to the power of 2. The h value is 42.51 in meters.
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Which set of experimental conditions would result in the least amount of force on the egg?
a. Drop a small egg from a height of 1 meter into a box of foam.
b. Drop a jumbo egg from a height of 10 meters on a hard surface.
c. Drop a jumbo egg from a height of 10 meters onto 1-inch foam.
d. Drop a small egg from a height of 1 meter into a box of foam.
e. Drop a small egg from a height of 10 meter into a box of foam.
Answers
A because it is the it is the it is the it is there ither iee dd
What ate the 4 types of orbitals within the electron cloud?
Answers
Answer:
I don't know all but three I know are: d orbitals, transition and d-block
Problem 1 Line Broadening II Which cause for line broadening is dominant in the following cases? (a) Starlight moves through a cloud of hydrogen atoms of particle density n = 105/m³ and temper- ature T 10 K. Is the natural line width AwN, the Doppler width Awp or the collision width Awc the dominant cause for the broadening of the hyperfine transition and the Lyman a-line? The decay time for the hyperfine transition 1¹S1/2 (F= 0 F = 1) at λ = 21 cm is to = 109 s and the collision cross section to 10-9 s and o= 10-15 cm². = 10-22 cm², whereas for the Lyman a-line A = 121.6 nm, 5 (3+2) points (b) A laser beam of wavelength λ = 3.39 µm and a beam diameter of 1 cm is sent through a methane cell, in which CH4-molecules at T = 300 K absorb on the transition ik (tok = 20 ms). Is the natural line width Awy, the Doppler width Awp, or the flight time width AwFT the largest?
Answers
In the case of starlight passing through a cloud of hydrogen atoms, the dominant cause for line broadening is ________.
In the case of a laser beam passing through a methane cell, the largest line broadening effect is due to ________.
In the case of starlight passing through a cloud of hydrogen atoms, the dominant cause for line broadening depends on the given parameters. The natural line width (AwN) is primarily determined by the lifetime of the excited state, which is given as to. The Doppler width (Awp) is influenced by the temperature (T) and the mass of the particles. The collision width (Awc) is influenced by the collision cross section and the particle density (n). To determine the dominant cause, we need to compare these factors and assess which one contributes the most significantly to the line broadening.
In the case of a laser beam passing through a methane cell, the line broadening is affected by different factors. The natural line width (AwN) is related to the energy-level structure and transition probabilities of the absorbing molecules. The Doppler width (Awp) is influenced by the temperature (T) and the velocity distribution of the molecules. The flight time width (AwFT) is determined by the transit time of the molecules across the laser beam. To identify the largest contributor to line broadening, we need to evaluate these effects and determine which one has the most substantial impact on the broadening of the spectral line.
the dominant cause of line broadening in starlight passing through a cloud of hydrogen atoms and in a laser beam passing through a methane cell depends on various factors such as temperature, particle density, collision cross section, and energy-level structure. To determine the dominant cause and the largest contributor, a thorough analysis of these factors is required.
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If two objects have a total of 24 kg m*s of momentum before they collide, how much momentum do the two objects have afterwards
Answers
The total momentum of the two objects after the collision is still 24 kg m/s.
According to the principle of conservation of momentum, the total momentum of a system remains constant before and after a collision in the absence of external forces.
If the two objects have a total momentum of 24 kg m/s before the collision, it means that the sum of their individual momenta is 24 kg m/s.
Let's denote the momentum of the first object as p1 and the momentum of the second object as p2. According to the given information, we have:
p1 + p2 = 24 kg m/s
After the collision, the total momentum of the system is still 24 kg m/s. Therefore, we can conclude that the total momentum of the two objects after the collision is also 24 kg m/s.
The total momentum of the two objects after the collision remains unchanged at 24 kg m/s.
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A bowling ball with a mass of 9 kg is moving at a speed of 4 m/s. What is its
kinetic energy?
O A. 144 J
O B. 72J
O C. 18J
O D. 36 J
Help please!!
Answers
A plane mirror is mounted on the back of a truck which is traveling 20m/s. how fast does the image of a man standing in the road behind the truck seem to be moving away from him
Answers
20m/s
Explanation:
the distance of the image formed in the mirror is the same distance from which the object is
the period of oscillation of a nonlinear oscillator depends on the mass m, with dimensions of m; a restoring force constant k with dimensions of ml2t2 , and the amplitude a, with dimensions of l. dimensional analysis shows that the period of oscillation should be proportional to
Answers
The correct option is C, The period of oscillation should be proportional to A^-1 square root of m/k.
mass m, with dimensions of M
force constant k with dimensions of ML^-2T^-2
amplitude A, with dimensions of L
To find the relation for period of oscillation with dimension T
To get the dimension T from m,k and A
\(1/A*\sqrt{(m/k)} = 1/L*\sqrt{(M/ML^{-2}T^{-2}) }= 1/L*LT = T\)
Oscillation refers to the repetitive variation of a physical quantity around a central value or equilibrium position. It is a common phenomenon in many natural and man-made systems, ringing from simple pendulums and springs to complex electrical circuits and biological processes.
In an oscillating system, the physical quantity, such as displacement, velocity, or current, continuously changes between maximum and minimum values with a fixed frequency and amplitude. The frequency of oscillation is the number of cycles per unit time, usually measured in Hertz (Hz), while the amplitude is the maximum deviation from the equilibrium position. Oscillations can be periodic, where the motion repeats itself exactly over a fixed time interval, or non-periodic, where the motion is irregular and unpredictable.
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Complete Question: -
The period of oscillation of a nonlinear oscillator depends on the mass m, with dimensions of M; a restoring force constant k with dimensions of ML^-2T^-2 and the amplitude A, with dimensions of L. Dimensional analysis shows that the period of oscillation should be proportional to
a) A square root of m/k b) A^2 m/k c) A^-1 square root of m/k d) (A^2k^3)/m
A 1.25 m long pendulum on Mars
has a period of 3.65 s. What is the
acceleration of gravity g on Mars?
(Unit = m/s^2)
Help please
Answers
Explanation:
\(period = 2\pi \sqrt{ \frac{length}{g} } \)
\(3.65 \: s = 2\pi \sqrt{ \frac{(1.25 \: m)}{g} } \)
Squaring both sides and solving for g, we get
g = 3.70 m/s^2
which is close to what is expected (3.71 m/s^2).
What is missing from the graph? consistent intervals grid lines variables a best-fit line
Answers
A best-fit line is missing from the graph above.
About GraphicsThe definition of graphics is a combination of numbers, letters, symbols, pictures, symbols, sayings, paintings, which are presented in one medium to convey concepts and ideas from the sender to the target in the process of conveying information.
There is also another understanding of graphics, which is a framework for forming table visualization objects. Tables consisting of numbers can be presented or can be displayed in the form of images, can be in the form of lines, circles, bars etc.
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Describe two vectors a andb such that vector a+ vector b= vector c and a+b=c
(b) vector a + vector b= vector a - vector b
(c) vector a + vector b + vector c and a2 +b2=c2
can you show me how to do this problem and show all work myprofessor didn't go over any of this and i dont have a clue.
Answers
Answer:
a + b = c where a and b and c are vector quantities
Since c is the result of adding vector b to vector a (to add two vectors the vectors are connected head to tail)
a^2 + b^2 - 2 ab cos θ = c^2 is an expression of such a relationship
Note that a^2 + b^2 = c^2 if a and b are at right angles to one another
Another way to express this is:
a x + b x = c x where a and b are the x-components of a and b
a y + b y = c y describes the y -components of a and b
The above two equations will provide the x and y components of vector c
If you cross a long haired guinea pig (hh) with one that is heterozygous and short haired (Hh), how many of the offspring will have long hair?
Answers
Two of the guinea pig offspring will have long hair.
The allele for short hair is dominant in guinea pigs. This indicates that it can express under both homozygous (HH) and heterozygous (Hh) conditions.
When we cross an hh with an Hh,
(h h) X (H h)
The possible offspring are:
Hh, Hh, hh, hh
Two heterozygous short-haired offspring and two homozygous long-haired offspring.
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Attaching the image file here.
1. Convert 100 m, the length of a well-known track event, to kilometers.
Answers
Answer:
0.1 km
Explanation:
Each km is 1000 m. 100 m is 1/10 of 1000 m. in decimal form that is 0.1 km.
Which of the following is a vector quantity?
O speed
O time
O force
O displacement
O temperature
O momentum
O velocity
O acceleration
Answers
According to the given information temperature and velocity of the following is a vector quantity
Is temperature a vector quantity?A vector quantity is one that just has magnitude, whereas a vector quantity has both orientation and magnitude. Given that it is direction-independent at a given position, heat is a scalar number.
Is the force of gravity a vector?Vectors include gravity and displacement. They possess both a value and a direction. The fact that gravity and displacement are pointing in the same direction in this instance allows us to derive a scalar energy from them (in this example, their direction are down and down, respectively).
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