A player kicks a football from ground level with an initial velocity of 27. 0 m/s.

Answers

Answer 1

Here we have to find the maximum height by which the football can be kicked.

Given:

Initial velocity v0=27 m/sv0=27 m/s

Angle of projection θ=30∘θ=30∘

Gravitational acceleration g=9.8 m/s2g=9.8 m/s2

Required:

Time of flight T=??T=??

Range R=??R=??

Maximum height H=?H=?

Using the 1st equation we will calculate Time of flight of the ball

T=2v0sinθgT=2(27 m/s)sin30∘9.8 m/s²

T≈2.755 sT=2v0sin⁡θgT=2(27 ms)sin⁡30∘9.8 m/s²

T≈2.755 s

Using the 2nd equation we will calculate the horizontal range

R=v20sin2θgR=(27 m/s)2sin(2×30∘)9.8 m/s²

R≈64.422 mR=v02sin⁡2θgR=(27 m/s)2sin⁡(2×30∘)9.8 m/s²

R≈64.422 m

Using 3rd equation we get the maximum height

H=v20sin2θ2g

H=(27 m/s)2sin230∘2(9.8 m/s²)

H=9.298 m

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Answer 2

The utmost height the ball may reach, according to the question, is 9.3 meters. The total time required is 2.75 seconds, and also the total distance traveled is 63 meters.

What is the straightforward meaning of velocity?

The displacement that such an element or particle experiences with the passage of time is expressed vectorially as velocity. The meters per second (m/s) is the accepted unit of velocity profile (also known as speed).

Briefing:

Horizontal angle = 30°

Initial velocity, V = 27.0 m/s

then,

\($$\begin{aligned}& V_x=23 \mathrm{~m} / \mathrm{s} \\& V_{i y}=13.5 \mathrm{~m} / \mathrm{s}\end{aligned}$$\)

(a). The maximum height will be:

   \($$V_f^2=V_i^2+2 a d$$\)

0 = (13.5)² + 2(-9.8)*d

0 = 182 + (19.6)d

d = 9.3m

(b). The total time taken will be:

       \($$V_f=-V_i$$\)

or,

\($$\begin{aligned}a & =\frac{V_f-V_i}{t} \\-9.8 & =\frac{-13.5-13.5}{t}\end{aligned}$$\)

-9.8t = -27

t = -27/-9.8

t = 2.75 sec

(c). The total distance covered will be:

\($$\begin{gathered}V_x=\frac{d_x}{t} \\23=\frac{d_x}{2.75}\end{gathered}$$\)

\($$d_x$$\) = 2.75 * 23

    = 63m

Thus the approach above is appropriate.

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The complete question is-

A football player kicks a football, from ground level, with an initial velocity of 27.0 m/s at an angle 30° above the horizontal.

a. What is the maximum height the ball attained?

b. How long did it take the ball to return to the launching height?

c. How far away did it land?​


Related Questions

if potential difference across a lightbulb is 12 V, what amount of charge is required to transfer 60 J of energy to the lightbulb

Answers

60/12=5

Reason: trust

Answer:

Explanation:

Given:

U =12 V

E = 60 J

________

q - ?

E = U·I·t

q = I·t

E = U·q

q = E / U = 60 / 12 = 5 С

A horizontal tube consists of a 7.0-cm diameter pipe that narrows to a 2.0-cm-diameter throat. In the pipe, the water pressure is twice atmospheric pressure and the water flows with a speed of 0.40 m/s. What is the pressure in the throat, assuming that the water

Answers

A horizontal tube consists of a 7.0-cm diameter pipe that narrows to a 2.0-cm-diameter throat. In the pipe, the water pressure is twice atmospheric pressure and the water flows with a speed of 0.40 m/s.

The continuity equation relates the speed of a fluid to its cross-sectional area and the flow rate, and it is as follows:A1V1 = A2V2Where, A1 and A2 are the cross-sectional areas of the pipe and throat, respectively; V1 is the speed of water in the pipe, and V2 is the speed of water in the throat. The following equation may be derived from Bernoulli's equation:P1 + 1/2ρV1² = P2 + 1/2ρV2²Where, P1 is the pressure in the pipe, P2 is the pressure in the throat, and ρ is the density of the fluid. Bernoulli's equation applies to any incompressible fluid flowing through a pipe at a steady state Since the water is in turbulent flow at the throat, the assumption is that all of the pressure energy in the fluid is converted to kinetic energy. This occurs when the kinetic energy of water molecules is larger than the pressure energy in the fluid, resulting in turbulent flow.

The pressure in the throat can then be computed by equating the kinetic energy of water molecules in the throat to the pressure energy in the fluid at that location.ρV22/2 = P2where ρ is the density of water, and V2 is the velocity of water in the throat Substitute the value in the equation:ρ = 1000 kg/m³V2 = A1V1/A2 = π/4d₁²V1/A2 = (π/4 × 0.07² × 0.4)/ (π/4 × 0.02²) = 1.96 m/sP2 = ρV22/2 = 1000 × 1.962/2 = 1960  the pressure in the throat is 1960 Pa, assuming that the water's speed at that point is large enough that the water there is in turbulent flow.

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A player hits a ball with a bat. The action is the force of the bat against the ball.
What is the reaction to this force?

Answers

Answer:

Force of the ball against the bat

Explanation:

Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a player hits a ball with a bat, the force the player exerted on the ball through the bat gave the ball a push force in the forward direction. This is an action force. Now that an action has been initiated, there must be a reaction according to Newton's third law of motion. The magnitude of the force on the ball equals the magnitude of the force on the bat. The direction of the force on the ball is opposite to the direction of the force on the ball. The ball will give the bat an equal and opposite force trying to push the bat backward by resisting the impact of the bat. This is the reaction. The ball will only move if the applied force is able to overcome the resisting force by the bat.

Where;

is the action force of the bat against the ball.

is the equal and opposite reaction force of the ball towards the ball.

Which property of matter is an extensive, rather than an intensive, property of matter?.

Answers

 A property known as an extensive property depends on the quantity of materials in a sample. A couple of instances of extensive attributes are mass and volume. A property of matter that is intensive depends solely on the type of matter in a sample and not on the quantity.

Which of the following is intensive as opposed to extensive?

An intense property is a structural characteristic of a system that is independent of the system's size or the volume of its constituent parts. Volume and internal energy are extensive qualities while density, pressure, and temperature are intensive ones.

What is an illustration of a extensive property?

The features that depend on the amount of matter present are referred to as extensive properties. Volume, mass, internal energy, etc. are some examples.

What are some instances of a substance's extensive and intensive properties?

Temperature, T, refractive index, n, density, and object hardness are a few examples of intensive attributes. In contrast, subsystems' comprehensive attributes, such as mass, volume, and entropy, are additive. However, not all physical characteristics of matter fit within those categories.

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15. true or false convection drives movement of the tectonic plates which does not involve subduction.

Answers

The given statement "convection drives movement of the tectonic plates which does not involve subduction" is false because tectonic plate movement caused by mantle convection involves subduction.

Convection plays a crucial role in driving the movement of tectonic plates, which includes subduction. The Earth's mantle is divided into several convection cells that transfer heat and matter from the interior of the Earth towards the surface.

As the hotter material rises towards the surface, it displaces colder and denser material, which sinks back down into the interior. This convection cycle causes the movement of tectonic plates, as the plates are essentially riding on top of the flowing mantle.

Subduction occurs when one tectonic plate is forced beneath another due to differences in density and temperature. This process is driven by the movement of the plates themselves, which in turn is driven by the underlying convection currents in the mantle.

In summary, the movement of tectonic plates is driven by convection currents in the mantle, and subduction is one of the important processes involved in this movement.

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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS

URGENT!! ILL GIVEBRAINLIEST! AND 100 POINTS

Answers

The correct order of the waves based on their amplitudes from largest to smallest is W, X, Z, Y.

What is the amplitude of a wave?

The amplitude of a wave is the maximum displacement or distance from the equilibrium position of a particle in a medium as a wave passes through it. In other words, it is the height or intensity of the peak of a wave.

The amplitude of a wave can be described as the amount of energy that is carried by the wave. For example, in a sound wave, the amplitude determines the loudness of the sound, while in an electromagnetic wave such as light, the amplitude determines the brightness of the light.

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An object is thrown off a cliff with a horizontal speed of 10 m/sec and some unknown initial vertical velocity. After 3 seconds the object hits the ground which is 30 meters below the cliff. Find the initial vertical velocity and the total horizontal distance traveled by the object.
a. What do you know?
b. What do you need to solve for?
c. What equation(s) will you use?
d. What is the solution to this problem?

Answers

The answers to the questions of the object thrown off a cliff with a horizontal speed of 10 m/s and that reach the ground which is 30 m below after 3 seconds, are:

a. We know:

The height of the cliff = 30 mThe time for the object to reach the ground = 3 sThe initial horizontal velocity = 10 m/s

b. We need to find the initial vertical velocity and the total horizontal distance traveled.

c. To calculate the initial vertical velocity and the total horizontal distance traveled by the object, we need to use the following equations:

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

\( v_{i_{x}} = \frac{x}{t} \)  (2)

d. The initial vertical velocity and the horizontal distance traveled by the object are 4.72 m/s and 30 m, respectively.

a. From the statement, we know:

The initial horizontal velocity (\(v_{i_{x}} \)) = 10 m/sThe time for the object to reach the ground = 3 sThe height of the cliff = 30 m

b. We need to find the initial vertical velocity and the total horizontal distance traveled.

c. To calculate the initial vertical velocity we can use the following equation:

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

Where:

\( y_{f}\): is the final height = 0 m  

\( y_{i}\): is the initial height = 30 m  

\( v_{i_{y}}\): is the initial vertical velocity =?  

g: is the acceleration due to gravity = 9.81 m/s²

t: is the time = 3 s  

And, to find the horizontal distance traveled by the object we need to use the equation:

\( v_{i_{x}} = \frac{x}{t} \)   (2)

Where:

\(v_{i_{x}} \): is the initial horizontal velocity = 10 m/s

x: is the horizontal distance =?

d. The solution to this problem is the following.

Calculation of the initial vertical velocity (eq 1)

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)  

\( 0 = 30 m + v_{i_{y}}*3 s - \frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} \)

Solving for \(v_{i_{y}}\)

\( v_{i_{y}} = \frac{\frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} - 30 m}{3 s} = 4.72 m/s \)

Hence, the initial vertical velocity is 4.72 m/s.  

Calculation of the horizontal distance (eq 2)

\( v_{i_{x}} = \frac{x}{t} \)

\( 10 m/s = \frac{x}{3 s} \)

\( x = 10 m/s*3 s = 30 m \)

Therefore, the horizontal distance traveled by the object is 30 m.

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A decorative plastic film on a copper sphere of 10 mm diameter in an oven at 750C. Upon removal from the oven, the sphere is subjected to an air stream at 1 atm. , and 230C having a velocity of 10 meter/sec. Estimate how long it will take to coal the sphere to 350C? Density of copper is 8933 kg/m3 , thermal conductivity k = 399 W/m.K and specific heat Cp = 387 J/kg.K. for Air at an average temperature of T[infinity] = 296 K has viscosity µ= 181x10-7 N.s/m2 , kinematic viscosity ν = 15.36x10-6 m2/s and thermal conductivity k = 0.0258 W/m.K and Prandtl No. Pr = 0.709 and air at surface temperature Ts = 328 K will have viscosity µs = 197x10-7 N.s/m2

Answers

Answer:

3.26 secs

Explanation:

Diameter of sphere ( D )= 10 mm

T1 = 75°C

P = 1 atm

T∞ = 23°C

T2 = 35°c

Velocity = 10 m/s

Determine how long it will take to cool the sphere to 35°C

Using the properties of copper and air given in the question

Nu = 2 + (Re)^0.8 (Pr)^0.33

hd / k = 2 + ( vd/v )^0.8 (Pr)^0.33

∴ h ≈  2594.7 W/m^2k

Given that :

(T2 - T∞) / ( T1 - T∞ )  = exp [ ( -hA / pv CP ) t ]  

( 35 - 23 ) / ( 75 - 23 ) = exp [  - 2594.7 * 6 * t / 8933 * 387 * 10 * 10^-3 ]

=  ln ( 12/52 ) = -1.466337069  =     - 0.45032919 *  t

∴ t ≈ 3.26 secs        ( -1.466337069 / -0.45032919 )

A decorative plastic film on a copper sphere of 10 mm diameter in an oven at 750C. Upon removal from

If an airplane is flying west at 300mph, and a crosswind is blowing south at 35 mph (90°), what is the
true speed of the plane? Will the plane truly fly west if the pilot does not compensate for the crosswind?

Answers

Answer:

no

Explanation:

John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s

Answers

The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

Velocity = 30 m/sAngle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

\(V_x = Vcos(\theta)\)

Substituting the given parameters into the formula, we have;

\(\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5\)

Horizontal component, Vx = 15 m/s

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If we wish to find life with a carbon-return process similar to the one here on Earth, we should look for planets
(A) with thin, unstable surfaces.
(B) with volcanos..
(C) with thick, stable surfaces.

Answers

Planets with thick, stable surfaces would provide the best conditions for the development and sustenance of carbon-based life forms. Here option C is the correct answer.

In the search for life in the universe, one approach is to look for planets with conditions similar to those found on Earth. Carbon-based life, like the kind found on Earth, requires a planet with a stable surface and a source of carbon.

A thick, stable surface would provide a protective environment for life to evolve and thrive. Such a surface would prevent the loss of gases, including water and carbon dioxide, that are essential for life. Additionally, a stable surface would ensure that the planet's climate remains relatively constant, allowing life to adapt to the environment.

Carbon is one of the key elements required for life as we know it. On Earth, carbon is cycled through various processes, such as photosynthesis and respiration, which involve the exchange of carbon between the atmosphere, oceans, and land. Planets with volcanoes, as mentioned in option (B), may also have a source of carbon, but this does not necessarily mean they have stable surfaces. In fact, volcanoes can destabilize a planet's surface, making it unsuitable for life.

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1. What type of VOM reading requires the meter to be placed in series with the circuit?
A. Resistance
B. Voltage
C. Current
O
D. Power

Answers

Answer:

C.  Current.

Explanation:

In a series circuit the current is equal in all of its components, so to measure the current we put the meter in series with the circuit.

do the question in the photo below
Also What Grade is this?

do the question in the photo belowAlso What Grade is this?

Answers

Answer:

9 th grade

Explanation:

(choose )
Ramy covered a distance 3080 cm on foot. This distance is equivalent to.........


a) 0.03Km + 80cm

b) 0.3Km +8cm

c) 3Km + 8cm

d) 30Km + 80cm​

Answers

Answer:

a) 0.03km + 80 cm is the right answer

A = (1 point) A particle is moving with acceleration a(t) = 6t + 8. its position at time t = O is s(0) = 6 and its velocity at time t = 0 is v(O) = 2. What is its position at time t = 7? =

Answers

Answer:

\(559\).

Explanation:

Integrate \(a(t)\) with respect to time \(t\) to find an expression for velocity:

\(\begin{aligned} v(t) &= \int a(t)\, d t \\ &= \int (6\, t + 8)\, d t && (\text{power rule}) \\ &= 3\, t^{2} + 8\, t + C_{v} \end{aligned}\).

Note that since this integral is indefinite, the expression for \(v(t)\) includes a constant \(C_{v}\).

Find the value of \(C_{v}\) using the fact that \(v(0) = 2\). Specifically, substitute \(t = 0\) into the expression \(v(t) = 3\, t^{2} + 8\, t + C_{v}\) and solve for \(C_{v}\!\):

\(v(0) = 3\, (0)^{2} + 8\, (0) + C_{v} = C_{v}\).

\(v(0) = 2\).

\(C_{v} = 2\).

In other words, \(v(t) = 3\, t^{2} + 8\, t + 2\).

Similarly, integrate \(v(t)\) with respect to \(t\) to find an expression for position:

\(\begin{aligned} s(t) &= \int v(t)\, d t \\ &= \int (3\, t^{2} + 8\, t + 2)\, d t\\ &= t^{3} + 4\, t^{2} + 2\, t + C_{s} \end{aligned}\).

Similarly, find the value of constant \(C_{s}\) using the fact that \(s(0) = 6\):

\(s(0) = (0)^{3} + 4\, (0)^{2} + 2\, (0) + C_{s} = C_{s}\).

\(s(0) = 6\).

\(C_{s} = 6\).

In other words, \(s(t) = t^{3} + 4\, t^{2} + 2\, t + 6\). Substitute in \(t = 7\) and evaluate to find the position of the particle at that moment:

\(s(7) = 7^{3} + 4\, (7)^{2} + 2\, (7) + 6 = 559\).

The pοsitiοn of the particle at time t = 7 is 559 units.

How tο find the pοsitiοn at time?

Tο find the pοsitiοn at time t = 7, we need tο integrate the given acceleratiοn functiοn tο οbtain the velοcity functiοn and then integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn.

Given:

Acceleratiοn functiοn: a(t) = 6t + 8

Initial pοsitiοn: s(0) = 6

Initial velοcity: v(0) = 2

First, let's integrate the acceleratiοn functiοn tο οbtain the velοcity functiοn:

v(t) = ∫(a(t)) dt

= ∫(6t + 8) dt

= 3t^2 + 8t + C

Tο find the cοnstant οf integratiοn (C), we can use the initial velοcity v(0) = 2:

2 = 3(0)² + 8(0) + C

C = 2

Sο, the velοcity functiοn becοmes:

v(t) = 3t² + 8t + 2

Next, let's integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn:

s(t) = ∫(v(t)) dt

= ∫(3t² + 8t + 2) dt

= t³ + 4t² + 2t + C'

Tο find the cοnstant οf integratiοn (C'), we can use the initial pοsitiοn s(0) = 6:

6 = (0)³ + 4(0)² + 2(0) + C'

C' = 6

Sο, the pοsitiοn functiοn becοmes:

s(t) = t³ + 4t² + 2t + 6

Finally, we can find the pοsitiοn at time t = 7:

s(7) = (7)³+ 4(7)² + 2(7) + 6

= 343 + 196 + 14 + 6

= 559

Therefοre, the pοsitiοn at time t = 7 is 559 units.

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what is the splitting of water using light energy called

Answers

The splitting of water using light energy is called photolysis.

Photolysis is a chemical process in which water molecules are broken down into their constituent parts, hydrogen (H2) and oxygen (O2), using light energy. This process occurs during photosynthesis in plants and algae, specifically in the light-dependent reactions of photosynthesis.

Photolysis is an essential step in the production of oxygen and the generation of energy-rich molecules like ATP and NADPH during photosynthesis. It involves the absorption of light energy by specialized pigments, such as chlorophyll, which triggers the splitting of water molecules. The liberated oxygen is released into the atmosphere, while the hydrogen atoms are utilized in the synthesis of energy-rich compounds. Photolysis is a vital process that sustains life on Earth by contributing to the production of oxygen and the storage of energy in organic molecules.

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What are the 2 forces acting on a projectile?
A. Gravity and Tension
B. Air Resistance and Tension
C. Gravity and Air Resistance
D. Gravity and Normal Force

What are the 2 forces acting on a projectile?A. Gravity and TensionB. Air Resistance and TensionC. Gravity

Answers

Answer:

Gravity and Air resistance.

Explanation:

A projectile is an object that is launched into the air by the application of an external force and they are able to move freely under the influence of gravity and air resistance.

Therefore,

The 2 forces acting on a projectile are:

Gravity and Air resistance.

The third Kepler law suggests a relationship between the orbital period and the distance from the parent star for a planet as following: T2/R3 = constant. Assuming that we discovered a new planet in our solar system with an orbital period 1000 years, please estimate the distance of the new planet from the Sun in the unit of AU. Please take Earth (TE = 1 year and RE = 1 AU) as reference.

Answers

The estimated distance of the new planet from the Sun in AU would be approximately 100 AU.

To estimate the distance of the new planet from the Sun in AU (astronomical units), we can use the third Kepler's law:

(\(T1^2/R1^3\)) = (\(T2^2/R2^3\))

where T1 is the period of reference planet (Earth), R1 is the distance of the reference planet (Earth) from the Sun, T2 is the period of the new planet, and R2 is the distance of the new planet from the Sun.

Using the values for Earth as the reference:

T1 = 1 year (Earth's orbital period)

R1 = 1 AU (Earth's distance from the Sun)

T2 = 1000 years (orbital period of the new planet)

Now, we can solve for R2:

(\(T1^2/R1^3\)) = (\(T2^2/R2^3\\\))

(\(1^2/1^3\)) = (\(1000^2/R2^3\))

1 = (\(1000^2/R2^3\))

\(R2^3\) = (\(1000^2/1\))

\(R2^3\) = 1,000,000

R2 = cube root of 1,000,000

R2 ≈ 100

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#11 What is the volume of a cube with a side length of 1/5 inches ?​

Answers

Answer:

\( \boxed{\sf Volume \ of \ cube \ (V) = \frac{1}{125} \ in^3} \)

Given:

Side length of the cube (a) = \( \sf \frac{1}{5} \) in

To Find:

Volume of the cube (V)

Explanation:

Volume of cube = (side length)³

\( \boxed{ \bold{V = a^3}}\)

Substituting value of a in the formula:

\( \sf \implies V = {( \frac{1}{5} )}^{3} \\ \\ \sf \implies V = \frac{ {1}^{3} }{ {5}^{3} } \\ \\ \sf \implies V = \frac{1}{ {5}^{3} } \\ \\ \sf \implies V = \frac{1}{125} \: {in}^{3} \)

Which substance has a melting point greater than room temperature?
A.
oxygen

B.
aluminum

C.
mercury

D.
water

Answers

Answer:

I think the answer is D.)

Explanation:

If it means something needs to melt into liquid i would have gone with B.) or C.) but since it doesn't specifiy. I thought D.) since all you have to do is heat it and it melts or boils.

3. Light travels from the Sun to Earth in 8.3 min. Given that the speed of light is 3.00108 m/s, what is the distance in meters between the Sun and Earth?

Answers

Answer:

13

Explanation:

13.0120481928 it is the distance

brick falls from a height of 10 m. Calculate the time taken for the brick to reach the ground.​

Answers

Use physics kinematic equations to solve for t. Lookup physics kinematic problems on Kahn for more understanding.

brick falls from a height of 10 m. Calculate the time taken for the brick to reach the ground.

Question 4 of 10
Which statement describes the path of electrons from a battery to a circuit?
O A. Electrons move through the battery from the positive terminal to
the negative terminal and then into the circuit.
OB. Electrons move away from the positive end of a battery and then
through the circuit toward the negative end of the battery.
O C. Electrons move away from the negative end of a battery and then
through the circuit toward the positive end of the battery.
OD. Electrons move through the battery from the negative terminal to
the positive terminal and then into the circuit.
SUBMIT

Answers

Which statement describes the path of electrons from a battery to a circuit?

The correct answer would be:

C. Electrons move away from the negative end of a battery and then

through the circuit toward the positive end of the battery.

George weighs 200 lb. what is his weight in Newtons (think metric, ha ha 1 kg=2.2 lb)

Answers

Answer:

889.644 newton

Explanation:

multiply the pound value by 4.448

Give reason:

colour, taste and smell can't be used to differentiate between water and oxygen gas​

Answers

Answer:

All three characteristics are common between the two

Explanation:

Both water and oxygen are odourless, tasteless, colourless substances and so it is not possible to tell the difference between the two just based off of these three characteristics.

Wood is a biofuel. Suggest why wood has been used constantly for many years whereas other fuels have only been used much more recently. :)

Answers

Wood has been used constantly for several years because of its availability, ease of obtaining, and high energy density.

Why wood has been in constant use

Wood has been used as a fuel for many years because it is readily available in most parts of the world, easy to obtain and process, and has a relatively high energy density compared to other biomass fuels.

Additionally, wood is a renewable resource, as long as it is harvested sustainably, meaning that new trees are planted to replace those that are cut down.

In contrast, other fuels, such as coal, oil, and natural gas, were only discovered and exploited much more recently in human history. These fossil fuels have higher energy densities than wood, which means they can produce more energy per unit volume or mass.

However, their extraction and processing are more complex and require specialized equipment and infrastructure, which was not available until the industrial revolution. Moreover, the environmental and social impact of fossil fuels has become a growing concern in recent times.

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20V Calculate: Total resistance from the given diagram. Fig:(a) 4W 12v 6W Fig:(b) 6W 6W 12v​

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Answer:

please help

Explanation:

What conclusions can you draw about the relationship between the temperature of a ball and its bounce height? Is there a direct or inverse relationship? Write an evidence-based claim.

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The temperature of the ball is directly proportional to its bounce height.

This is dealing about the effect of temperature on a bouncing ball.

According to Gay-Lussacs Law, Pressure is directly proportional to temperature when the volume is constant. This means that an increase in temperature will lead to an increase in pressure.

Now, Pressure is Force/Area and so the higher the air pressure, the higher will be the force on the ball and consequently, the higher the ball will bounce. Likewise, the lower the temperature, the lower the pressure and thus the lower the height at which the ball will bounce.

This means, we can conclude that since temperature is directly proportional to pressure and pressure is directly proportional to the height of bounce of the ball, the temperature of the ball is directly proportional to its bounce height.

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calculate the speed of the disk in conceptual example 10-17 at the bottom of the inclined plane if the height of the incline is 0.55 m .

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The speed of the cylinder at the bottom of the inclined plane is approximately 1.44 m/s.

To determine the speed of the cylinder at the bottom of the incline, we can use the conservation of energy principle, which states that the total mechanical energy of the system is conserved.

At the top of the incline, the cylinder has only potential energy, which is given by:

PE = mgh

where m is the mass of the cylinder, g is the acceleration due to gravity, and h is the height of the incline.

At the bottom of the incline, the cylinder has both kinetic energy due to its translational motion and rotational energy due to its spinning motion. The total kinetic energy is given by:

KE = (1/2)mv^2 + (1/2)Iw^2

where v is the linear speed of the cylinder, I is its moment of inertia, and w is its angular speed.

Since the cylinder rolls without slipping, we can relate v and w using the equation:

v = rw

where r is the radius of the cylinder.

The moment of inertia of a solid cylinder is given by:

I = (1/2)mr^2

Substituting these expressions for KE and I into the conservation of energy equation, we obtain:

mgh = (1/2)mv^2 + (1/2)(1/2)mr^2w^2

Simplifying and substituting v = rw, we get:

v = √(2gh/3)

Plugging in the given values, we get:

v = √(2 × 9.81 m/s^2 × 0.55 m/3)

≈ 1.44 m/s

Therefore, the speed of the cylinder at the bottom of the inclined plane is approximately 1.44 m/s.

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To calculate the speed of the disk in conceptual example 10-17 at the bottom of the inclined plane, we need to use the conservation of energy principle. The potential energy at the top of the incline is converted into kinetic energy at the bottom.

First, we need to calculate the potential energy at the top of the incline. The potential energy can be calculated using the formula:

PE = mgh

Where m is the mass of the disk, g is the acceleration due to gravity (9.81 m/s^2), and h is the height of the incline (0.55 m).

PE = (0.5 kg) x (9.81 m/s^2) x (0.55 m) = 2.7 J

This potential energy is converted into kinetic energy at the bottom of the incline, which can be calculated using the formula:

KE = 0.5mv^2

Where v is the speed of the disk at the bottom.

Since energy is conserved, we can set PE equal to KE:

PE = KE

2.7 J = 0.5(0.5 kg)v^2

Solving for v, we get:

v = sqrt(2.7 J / 0.25 kg)

v = 3.3 m/s

Therefore, the speed of the disk in conceptual example 10-17 at the bottom of the inclined plane is 3.3 m/s.
In the conceptual example 10-17, a disk rolls down an inclined plane. To calculate the speed of the disk at the bottom of the inclined plane with a height of 0.55 meters, we can use the conservation of mechanical energy principle. This principle states that the total mechanical energy (potential energy + kinetic energy) of the disk remains constant if no external forces are acting on it.

At the top of the incline, the disk has only potential energy (PE) due to its height, and no kinetic energy (KE) since it is not moving. As it rolls down, the potential energy is converted into kinetic energy (both translational and rotational).

The potential energy at the top is given by PE = m * g * h, where m is the mass of the disk, g is the acceleration due to gravity (approximately 9.81 m/s^2), and h is the height of the incline (0.55 m).

At the bottom of the incline, the disk has no potential energy, and its kinetic energy is a combination of translational (KE_t) and rotational (KE_r) components. The total kinetic energy is given by KE = (1/2) * m * v^2 + (1/2) * I * ω^2, where v is the linear velocity, I is the moment of inertia of the disk, and ω is the angular velocity.

Since the total mechanical energy is conserved, we can set the potential energy at the top equal to the kinetic energy at the bottom:

m * g * h = (1/2) * m * v^2 + (1/2) * I * ω^2

To solve for the linear velocity (v) at the bottom of the incline, we also need to know the mass of the disk, the moment of inertia, and the angular velocity. These values are not provided in your question. However, once you have this information, you can use the conservation of mechanical energy equation to find the speed of the disk at the bottom of the inclined plane.

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suppose that the original resistor is replaced by a resistor of the same length and identical material but twice the cross sectional area. further suppose that the potential drop across the resistor is the same as for the original. the current through the new resistor will be

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The current through the new resistor will be half of the original current.

The resistance of a conductor depends on its material, length, and cross-sectional area, and is given by: R = (ρL) / A

Where R is the resistance, ρ is the resistivity of the material, L is the length, and A is the cross-sectional area.

Since the new resistor has twice the cross-sectional area of the original, its resistance will be half that of the original, assuming the length and material are the same.

According to Ohm's Law, the current through a resistor is directly proportional to the potential difference across it, and inversely proportional to its resistance: I = V / R

where I is the current, V is the potential difference, and R is the resistance.

Since the potential drop across the resistor is the same for the new resistor as for the original, and the new resistor has half the resistance, the current through the new resistor will be twice the current through the original resistor.

Therefore, the current through the new resistor will be half of the original current.

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