) a positive displacement pump is to be used to fill a liquid into a package. test with the pump reveal that it dispenses 128 milliliters of liquid for each revolution of the pump. an encoder is attached to the shaft of the pump. the encoder generates 1024 pulse for each revolution. the pump runs at 25 revolutions per minute. the encoder counts will be run into a control system. based on this information, how many counts will the control system see if 2 liters are dispensed from the pump? how many revolutions of the pump will occur to dispense that 2 liter amount? how many seconds would it take the pump to dispense the 2 liters?
Answers
The control system will see 15,984 counts if 2 liters are dispensed from the pump, 16 revolutions of the pump will occur to dispense that 2 liter amount and it will take 37.5 seconds for the pump to dispense the 2 liters of liquid.
The information given in the question is as follows:
Number of milliliters of liquid dispensed per revolution of pump = 128Encoder generates 1024 pulses for each revolution of the pumpThe pump runs at 25 revolutions per minute1. To calculate the counts that the control system will see if 2 liters are dispensed from the pump, we need to convert 2 liters to milliliters as all the other units are given in milliliters.
1 liter = 1000 milliliters
Therefore, 2 liters = 2 × 1000 = 2000 milliliters
2. To calculate the number of revolutions of the pump that will occur to dispense 2 liters of liquid, we can use the following formula:
Number of revolutions of the pump = Volume of liquid to be dispensed / Volume of liquid dispensed per revolution of pump = 2000 / 128 = 15.625 revolutions (approx.)
3. To calculate the time taken by the pump to dispense 2 liters of liquid, we can use the following formula:
Time taken = Number of revolutions of pump × Time taken for one revolution= 15.625 × 60/25= 37.5 seconds (approx.)
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Related Questions
A star is known to be moving at 8.46km/s toward the earth. If you observe the spectral line to be at 5.02nm, at what wavelength would you expect to measure the spectral line in a lab?
Answers
Answer:
\(\lambda_x=5.019858nm\)
Explanation:
From the question we are told that
Speed of star \(S=8.46km/s\)
Distance of spectral line \(\lambda_0= 5.02nm\)
Generally the equation for wavelength with respect to spectral lines is mathematically given by
\(\lambda=\lambda _0 *\frac{v}{c}\)
where
\(\lambda_0= length\ of\ spectral\ line\)
\(c=The\ speed\ of\ light\)
\(v= speed\ of\ moving\ object\)
therefore
\(\lambda=5.02*10^{-9} *\frac{8.46*10^{12}}{299 792 458*10^9}\)
\(\lambda=1.42*10^{-4} nm\)
Generally the equation for new wavelength is mathematically given as
\(\lambda_x=\lambda _0-\lambda\)
\(\lambda_x=5.02 nm-1.42*10^{-4} nm\)
\(\lambda_x=5.02-1.42*10^{-4}\)
Therefore
\(\lambda_x=5.019858nm\)
I need help I think is b what I’m not sure
Can you explain me ?
Answers
Answer: B
Explanation: We see the color black when no light is being reflected. Black absorbs all of the light unlike white which reflects all of it.
The law of conservation of energy states that (1 point) Group of answer choices all energy in the universe comes from the sun and remains in the same form energy is neither created nor destroyed; it is transformed and transferred new energy within a system is converted or transferred and destroyed as it is used energy is created from the sun and is transformed from one type to another
Answers
The law of conservation of energy states that energy is neither created nor destroyed; it is transformed and transferred (option B).
What is the law of conservation of energy?The law of conservation of energy is a principle stating that energy may not be created or destroyed but can only be transformed i.e. converted from one form to another.
This means that a system always has the same amount of energy, unless it's added from the outside.
The law states that the total energy of an isolated system remains constant; it is said to be conserved over time.
Therefore, according to this question, the law of conservation of energy is described correctly by option B.
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what is the two kinds of solids in amorphous
Answers
Solids can be classified into two types: crystalline and amorphous. Crystalline solids are the most common type of solid. They are characterized by a regular crystalline organization of atoms that confer a long-range order. Amorphous, or non-crystalline, solids lack this long-range order.
Explanation: Solids can be classified into two types, crystalline and amorphous. They are characterized by a regular crystalline organization of atoms that confer a long-range order.
Amorphous, or non-crystalline, solids lack this long-range order.
If this does not answer your question, we can have a conversation in the comments of this answer. Thank you.
a battery supplies 0.75 a to three resistors connected in parallel. the current through the first resistor is 0.25 a and the current through the second resistor is 0.23 a. what is the exact current (in a) through the third resistor? do not include units with your answer.
Answers
Since the three resistors are connected in parallel, the voltage across each resistor is the same, but the current flowing through each resistor may be different.
Let's use Ohm's Law, which states that the current through a resistor is equal to the voltage across it divided by its resistance:
I = V/R
where I is the current in amperes (A), V is the voltage in volts (V), and R is the resistance in ohms (Ω).
We are given that the battery supplies 0.75 A of current. The total current flowing through the three resistors is therefore 0.75 A:
0.75 A = I1 + I2 + I3
where I1 is the current through the first resistor, I2 is the current through the second resistor, and I3 is the current through the third resistor.
We are also given that I1 = 0.25 A and I2 = 0.23 A. We can use these values to find I3:
0.75 A = 0.25 A + 0.23 A + I3
0.75 A - 0.25 A - 0.23 A = I3
I3 = 0.27 A
Therefore, the exact current flowing through the third resistor is 0.27 A.
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what was the acceleration for the whole fall?
Answers
The acceleration for the whole fall = 6 m/s²
Since the object falls freely without being pushed, we are able to conclude it falls with constant acceleration.
As per the formula,
Acceleration = \(\frac{Final Velocity - Initial Velocity}{Total Time}\)
The Final Velocity of the space - mobile would be the total displacement it covered in the given time.
Final Velocity = 96/4 m/s
= 24 m/s
The Initial Velocity will be zero since as given in the image attached that the object falls freely with no external force.
Initial Velocity = 0/0 m/s
= 0 m/s
Total time taken = 4 sec
∴ Acceleration of the space - mobile = \(\frac{24-0}{4}\)
= 24/4 m/s²
= 6 m/s²
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Check
What happens to the light coming from the Sun?
What happens to light on the surface of water?
What happens to light on the surfaces of rocks?
Photo by Andres Nieto Porras
Answers
2.speculated reflection
3.diffuse reflection
State 3 advantages and 3 disadvantages of using the magnetic
particle method of defect detection.
Answers
The advantages and disadvantages may vary depending on the specific application, material, and the expertise of the personnel conducting the magnetic particle testing.
Advantages of using the magnetic particle method of defect detection:
Sensitivity to Surface and Near-Surface Defects: Magnetic particle testing is highly sensitive to surface and near-surface defects in ferromagnetic materials. It can detect cracks, fractures, and other discontinuities that may not be easily visible to the eye.
Rapid and Cost-Effective: Magnetic particle testing is a relatively fast and cost-effective method compared to other non-destructive testing techniques.
Real-Time Results: The method provides immediate results, allowing for real-time defect detection. This enables quick decision-making regarding the acceptability of the tested components or structures, leading to faster production cycles and reduced downtime.
Disadvantages of using the magnetic particle method of defect detection:
Limited to Ferromagnetic Materials: Magnetic particle testing is applicable only to ferromagnetic materials, such as iron, nickel, and their alloys. Non-ferromagnetic materials, such as aluminum or copper, cannot be effectively inspected using this method.
Surface Preparation Requirements: Proper surface preparation is crucial for effective magnetic particle testing. The surface must be cleaned thoroughly to remove dirt, grease, and other contaminants that can interfere with the test results. This additional step may require additional time and effort.
Limited Detection Depth: Magnetic particle testing is primarily suited for detecting surface and near-surface defects. It may not be as effective in detecting deeper or internal defects. Other non-destructive testing methods, such as ultrasonic testing or radiographic testing, may be more appropriate for inspecting components with deeper or internal flaws.
It's important to note that the advantages and disadvantages may vary depending on the specific application, material, and the expertise of the personnel conducting the magnetic particle testing.
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a measurement of an object’s inertia is made via its
Answers
A measurement of an object's inertia is made via its mass.
Inertia is the property of an object that resists changes in its motion, and mass is a measure of the amount of matter in an object. The greater an object's mass, the greater its inertia, and the more force is required to change its motion. Therefore, the mass of an object is a crucial factor in determining its inertia.
Mass is a fundamental property of matter that measures the amount of matter in an object. It is a scalar quantity that is expressed in units of kilograms (kg) in the International System of Units (SI). The more massive an object is, the greater its inertia, meaning that it is more resistant to changes in its motion.
The inertia of an object is related to the amount of force required to accelerate it. Newton's second law of motion states that the force required to accelerate an object is directly proportional to its mass and the rate of acceleration. That is, F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration of the object.
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A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a distance of 0.5 m
before the 1.56-kg target launched. What is the target's velocity as it leaves the spring?
Please help.
(A) 10m/s
(B) 20m/s
(C) 40m/s
(D) 30m/s
Answers
Answer:
(C) 40m/s
Explanation:
Given;
spring constant of the catapult, k = 10,000 N/m
compression of the spring, x = 0.5 m
mass of the launched object, m = 1.56 kg
Apply the principle of conservation of energy;
Elastic potential energy of the catapult = kinetic energy of the target launched.
¹/₂kx² = ¹/₂mv²
where;
v is the target's velocity as it leaves the catapult
kx² = mv²
v² = kx² / m
v² = (10000 x 0.5²) / (1.56)
v² = 1602.56
v = √1602.56
v = 40.03 m/s
v ≅ 40 m/s
Therefore, the target's velocity as it leaves the spring is 40 m/s
We know that Gravitational Force F g
is given by F g
=G d 2
Mm
where - G is the universal gravitational constant - M and m are the masses of the two objects - d is the distance between the two objects and the acceleration due to gravity is given by g= d 2
GM
. We are interested in the change in g with distance between masses and for different masses so we are going to compare Earth, Moon, Mars and Jupiter. Task 1 Create a script 'task1.m' to create and save the following variables: - universal gravitational constant: G - mass, radius and names of Earth, Moon, Mars and Jupiter as arrays: mass, radius, planet respectively - refer to NASA:size, NASA:mass - height of different strata of Earth's atmosphere as an array: atmosphere - refer to Wikipedia: Atmosphere of Earth Use SI system units for each. Add comments to the script with information on the array indices and corresponding planet. Save the workspace as 'project_1.mat'. Remember dimensional homogeneity when using these values in equations. You are expected to load these values from memory to use in the following tasks. Task 2 Create a script function 'gcalculate.m' with a function 'gcalculate' to take G,M and d as inputs to return the value of g. The function and script name should be the same to use the function in other scripts. You should also be in the same directory or have the directory holding this script in Matlab's saved paths. Create a live script 'task2.mlx'. Load the stored variables from 'project_1.mat' and use the function 'gcalulate' in a loop to do the following: - Calculate and display the value of g at the surface of each planet. - Calculate and display the value of g at the different strata of Earth's atmosphere - Accept text input on desired planet and cistance to calculate and display g at that value - you need to check for valid inputs for each Create a script 'task3.m'. Load the stored variables from 'project_1.mat'. - Define an implicit function to calculate the value of g with a variable x for distance from the surface of the planet. - Sample 1000 evenly distributed values between [1,10 8
] and save as an array. - Calculate and plot a graph showing the variation of g with height for the different planets. The plot should be titled, axes labelled and have a legend clearly identifying each plot line. Save the plot as a figure - 'task3_graph.fig'.
Answers
Create three scripts: 'task1.m' to save variables, 'gcalculate.m' to calculate gravitational acceleration, and 'task3.m' to plot and analyze the variation of g with height for different planets, using stored variables from 'project_1.mat'.
Accomplish the given tasks, you need to create three MATLAB scripts: 'task1.m', 'gcalculate.m', and 'task3.m'.
In 'task1.m', you will define and save the required variables, such as the universal gravitational constant (G), masses, radii, and names of Earth, Moon, Mars, and Jupiter, as well as the heights of different strata of Earth's atmosphere. These values will be stored in the 'project_1.mat' workspace.
In 'gcalculate.m', you will create a function called 'gcalculate' that takes inputs G, M, and d to calculate and return the gravitational acceleration (g) using the given formula. This function will be used in the subsequent tasks.
In 'task2.mlx', you will load the stored variables from 'project_1.mat' and use the 'gcalculate' function in a loop to calculate and display the values of g at the surface of each planet and at different strata of Earth's atmosphere.
The script will also accept user input for the desired planet and distance to calculate and display the corresponding g value.
In 'task3.m', you will load the stored variables and define an implicit function to calculate g with respect to the variable x, representing the distance from the surface of the planet.
You will sample 1000 evenly distributed values for x, calculate the corresponding g values, and plot a graph showing the variation of g with height for different planets. The plot will be properly labeled and saved as 'task3_graph.fig'.
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An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) What is the average angular acceleration in rad/s^2
(b) What is the tangential acceleration of a point 9.50 cm from the axis of rotation?
Answers
(a) To find the average angular acceleration in rad/s^2, we need to convert the given rotational speed from rpm (revolutions per minute) to rad/s (radians per second) and divide it by the time taken. First, let's convert 100,000 rpm to rad/s:
Angular speed (ω) in rad/s = (100,000 rpm) * (2π rad/1 rev) * (1 min/60 s) = (100,000 * 2π) / 60 rad/s.
Next, we divide the angular speed by the time taken to find the average angular acceleration:
Average angular acceleration = (Angular speed) / (Time taken) = [(100,000 * 2π) / 60] / (2 * 60) rad/s^2.
Simplifying the equation gives us the average angular acceleration in rad/s^2.
(b) To find the tangential acceleration of a point 9.50 cm from the axis of rotation, we use the formula:
Tangential acceleration = (Angular acceleration) * (Radius).
Given that the average angular acceleration is calculated in part (a), and the radius is given as 9.50 cm (0.095 m), we can substitute these values into the equation to find the tangential acceleration.
Tangential acceleration = (Average angular acceleration) * (Radius) = [(100,000 * 2π) / 60] / (2 * 60) * 0.095 m.
Calculating this expression gives us the tangential acceleration in m/s^2.
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Determine whether the series is convergent or divergent. 1 + 7n Σ 57 n = 1 convergent divergent If it is convergent, find its sum. (If the quantity diverges, enter DIVERGES.) 7 4
Answers
The given series, 1 + 7n Σ 57 n = 1, is divergent because the terms in the series continue to increase without bounds, the sum of the series also increases indefinitely.
To determine the convergence or divergence of the series, we can analyze its behaviour as n approaches infinity. The series can be written as Σ(1 + 7n*57) for n = 1 to infinity. By simplifying the expression, we have Σ(399n + 1) for n = 1 to infinity.
As n increases, the summand of the series grows linearly with a coefficient of 399. Since the coefficient is nonzero and positive, the series will diverge. This means that the sum of the series will not approach a finite value as n tends to infinity.
Therefore, the given series is divergent, and we cannot find its sum. It is important to note that a divergent series does not have a finite sum. Therefore, the sum of the given series is "DIVERGES."
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if rain drops of equal size fall with terminal velocity of 0.50m/s. what will be the terminal velocity if the drops collaspe to form a big drop?
Answers
Answer:
0.25m/s
Explanation:
m1v1 =m2 v2. law of conservation the of momentum. since they smash together to form a big drop M2 =2m1
m1*0.50m/s=2m1*v2
V2= m1*0.50m/s÷2m1
V2= 0.25m/s
8. what force will exert apressure of
50000 PA
0.5 meter
Square ?
Answers
Answer:
25000 N
Explanation:
\(force \: = pressure \times area \\ = 50000 \times 0.5 \\ = 5000 \times 5 \\ = 25000 \: N\)
The ratio of the diameters of the small piston to the large piston of a hydraulic lift is 1:10. Find (a) the ratio of the force on the small piston to the force on the large piston and (b) the ratio of the pressure on the small piston to the pressure on the big piston.
Answers
Answer:
a) 1: 100 F₂ = 100 F₁, b) P₁ = P₂ 1:1
Explanation:
The pressure in a system is the same for a given horizontal line, therefore
P₁ = P₂
where subscript 1 is for small piston and index 2 is for large piston 2
a) they ask the relation of the forces
pressure is defined by
P = F / A
for the small piston
P₁ = F₁ / A₁
the area of the piston is
A₁ =π r₁²
P₁ = F₁ /π r₁²
for big piston
P₂ = F₂ / A₂
in the exercise indicates that the diameter of the large piston is 10 times the diameter of the small piston
A = π r₂²
r₂ = 10 r₁
r₂ = π 10² r₁²
we substitute
P₂ = \(\frac{F_2}{ \pi \ 100 \ r_1^2}\)
we equalize the pressures
\(\frac{F_1 }{ \pi \ r_1^2 } = \frac{F_2}{ \pi \ 100 r_1^2}\)
F₁ = F₂ / 100
F₂ / F₁ = 100
therefore the force ratio is
1: 100
b) according to Pascal's principle for the same height the pressure is the same regardless of the shape of the container, therefore the pressure of the two pistons is the same
P1 = P2
1: 1
1. What is Paschen's law? What is the significance of Paschen's law in high voltage engineering? \( [10] \)
Answers
Paschen's Law is named after the physicist Friedrich Paschen. He discovered the breakdown voltage of gases between parallel metallic electrodes is inversely proportional to the pressure of the gas for a fixed distance. The law is one of the most essential laws in high voltage engineering, and it provides a reliable estimate of the voltage range in which a gas discharge is possible.
In this sense, it is a valuable tool in understanding electrical discharges. The following are the highlights of Paschen's law:ExplanationPaschen's law is a crucial concept in the field of electrical engineering. It explains the manner in which electrical discharges occur in gases. The law says that the breakdown voltage of a gas between two metal electrodes is a function of the pressure of the gas and the distance between the electrodes. It is possible to calculate the breakdown voltage if we know these variables.
The law is used to calculate the minimum voltage necessary for a gas to break down between two electrodes, which is crucial in determining the safety of electrical devices. Paschen's law is essential in the design and construction of electrical equipment like transformers and circuit breakers that are used in high voltage applications.
Conclusion Paschen's Law plays a critical role in high voltage engineering. It explains how electrical discharges occur in gases and provides a reliable estimate of the voltage range in which a gas discharge is possible. The law is valuable in understanding electrical discharges, determining the safety of electrical devices and equipment like transformers and circuit breakers used in high voltage applications.
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The swimmer swims in a straight line in the pool. Her motion is shown on the following graph of position 2
VS. time t.
*(m)
2
10
12
Answers
Fossils, plants, and animals are what make rocks different from minerals.
true of fales
Answers
mark me brainliest
a system of particles is known to have a positive total kinetic energy. what can you say about the total momentum of the system?
Answers
If the total kinetic energy of a system of particles is positive, it suggests that the system has a non-zero total momentum.
In a system of particles, if the total kinetic energy is positive, it implies that the particles within the system are in motion. The total momentum of the system depends on the individual momenta of the particles and their respective masses.
Since the kinetic energy is positive, it indicates that the particles have non-zero velocities. In order for the total momentum to also be positive, the velocities of the particles must have a net direction. This means that the particles are either moving collectively in the same direction or their individual velocities are such that the sum of their momenta is positive.
In summary, if the total kinetic energy of a system of particles is positive, it suggests that the system has a non-zero total momentum, which indicates either a collective motion in the same direction or a combination of individual velocities that result in a positive net momentum.
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Suppose the clean water of a stream flows into Lake Alpha, then into Lake Beta, and then further downstream. The in and out flow for each lake is 400 liters per hour. Lake Alpha contains 500 thousand liters of water, and Lake Beta contains 100 thousand liters of water. A truck with 200 kilograms of Kool-Aid drink mix crashes into Lake Alpha. Assume that the water is being continually mixed perfectly by the stream. A. Let x be the amount of Kool-Aid, in kilograms, in Lake Alpha t hours after the crash. Find a formula for the incremental change in the amount of Kool-Aid, Δx, in terms of the amount of Kool-Aid in the lake x and the incremental change in time Δt. Enter Δt as Deltat
Answers
Let x be the amount of Kool-Aid in Lake Alpha t hours after the crash. We can use the law of conservation of mass to determine the incremental change in the amount of Kool-Aid in Lake Alpha over time.
At any given time t, the amount of Kool-Aid in Lake Alpha is x kilograms. The Kool-Aid in Lake Alpha is flowing into Lake Beta at a rate of 400 liters per hour, so the concentration of Kool-Aid in Lake Alpha is decreasing by 400x / (500,000 liters) = 0.0008x kilograms per hour. At the same time, Lake Beta is flowing into Lake Alpha at a rate of 400 liters per hour, so the concentration of Kool-Aid in Lake Alpha is increasing by 0.0008y kilograms per hour, where y is the amount of Kool-Aid in Lake Beta at time t. Therefore, the incremental change in the amount of Kool-Aid in Lake Alpha over a small time period Δt can be approximated by: Δx ≈ (-0.0008x + 0.0008y) Δt. Note that this is an approximation since the concentration of Kool-Aid in Lake Beta also changes over time, but it should be accurate enough for small time periods.
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You're in an airplane that flies horizontally with speed 1000km/h(280m/s) when an engine falls off. Ignore air resistance and assume it takes 30 s for the engine to hit the ground.
a) Show that the airplane is 4.5km high.
b) Show that the horizontal distance that the aircraft engine moves during its fall is 8400.
c) If the airplane somehow continues to fly as if nothing had happened, where is the engine relative to the air-plane at the moment the engine hits the ground?
Answers
(a)The airplane is approximately 4.41 km (or 4.5 km, rounded) high. (b)the horizontal distance that the aircraft engine moves during its fall is 8400 meters.(c)the moment the engine hits the ground, it will be directly beneath the airplane in the horizontal direction.
a) To determine the height of the airplane, we can use the equation of motion for an object in free fall:
h = (1/2) × g ×t^2
where:
h is the height
g is the acceleration due to gravity
t is the time taken for the object to fall
Substituting the given values into the equation, we have:
h = (1/2) ×9.8 × (30^2)
h = 1/2 ×9.8 × 900
h = 4410 m
Therefore, we show that the airplane is approximately 4.41 km high.
b) The horizontal distance that the aircraft engine moves during its fall can be calculated using the equation:
d = v × t
where:
d is the horizontal distance
v is the horizontal velocity of the airplane
t is the time taken for the object to fall
Substituting the given values into the equation, we have:
d = 280 × 30
d = 8400 m
Therefore, we show that the horizontal distance that the aircraft engine moves during its fall is 8400 meters.
c) Since the engine falls vertically due to the force of gravity, while the airplane continues to fly horizontally at a constant speed, the engine will fall behind the airplane. The horizontal distance between the airplane and the engine at the moment the engine hits the ground will be the same as the horizontal distance traveled by the engine during its fall, which we calculated in part (b) as 8400 meters.
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(a) Calculate the initial momentum of each object and write the result in rectangular form.(b) Calculate the momentum of the combined mass after collision and write the result in polar form.(c) Calculate the final velocity after collision and write the result in polar form.
Answers
Given data:
Mass of ball is,
\(m_b=5.75\text{ kg}\)Magnitude of initial velocity of ball is,
\(v_{ib}=5.75\text{ m/s}\)Direction of initial velocity of ball with respect to x-axis is,
\(\theta=30^o\)Magnitude of initial velocity of embeds is,
\(v_{ie}=2.50\text{ m/s}\)Direction of initial velocity of embeds with respect to x-axis is,
\(\theta_e=140^0\)Formula of momentum is as follows:
\(\vec{P}=m\vec{v}\ldots(1)\)Initial momentum of ball,
Component of velocity of ball along x-axis is as follows:
\(v_{ibx}=v_{ib}\cos \theta\)Substitute known values above equation,
\(\begin{gathered} v_{ibx}=6.34\times\cos 30^o \\ v_{ibx}=5.49\text{ m/s} \end{gathered}\)Component of velocity of ball along y-axis is as follows:
\(\begin{gathered} v_{iby}=v\sin \theta \\ v_{iby}=6.34\times\sin 30^o \\ v_{iby}=3.17\text{ m/s} \end{gathered}\)Therefore, momentum of ball is as follows:
\(\begin{gathered} \vec{P}=m(v_{ibx}\hat{i}+v_{iby}\hat{j}) \\ \vec{P}=5.75\text{ kg(5.49}\hat{i}+3.17\hat{j}) \\ \vec{P}=(31.5675\hat{i}+18.2275\hat{j})kg\text{ }\cdot\text{ m/s} \end{gathered}\)Component of velocity of embeds along x-axis,
\(\begin{gathered} v_{iex}=v_{ie}\cos \theta_e \\ v_{iex}=2.50\times140^o \\ v_{iex}=-1.915\text{ m/s} \end{gathered}\)Component of velocity of embeds along y-axis,
\(\begin{gathered} v_{iey}=v_{ie}\sin \theta_e \\ v_{iey}=2.50\times\sin 140^o \\ v_{iey}=1.61\text{ m/s} \end{gathered}\)Initial momentum of embeds is as follows:
\(\begin{gathered} \vec{P}=m_e(v_{iex}\hat{i}+v_{iey}\hat{j}) \\ \vec{P}=3.85\text{ kg(}-1.915\hat{i}+\hat{1.61\hat{j}})\text{ m/s} \\ \vec{P}=(-7.37\hat{i}+6.20\hat{j})\text{ kg}\cdot\text{ m/s} \end{gathered}\)Part-B:
After collision if both objects are stick together, this type of collision is called plastic collision.
Momentum of system remains constant before plastic collision and after plastic collision.
Hence,
\(\vec{P}+\vec{P}_e=\vec{P}_f\)\(\text{Here }\vec{\text{P}}_f\text{ is momentum of combine mass after collision}\)Substitute known values in above equation,
\(\begin{gathered} \vec{P}_f=(31.5675\hat{i}+18.2275\hat{j})+(-7.37\hat{i}+6.20\hat{j})_{} \\ \vec{P}=(24.1975\hat{i}+24.4275\hat{j})\text{ kg}\cdot\text{ m/s} \end{gathered}\)Polar form of momentum of combined mass is as follows:
Magnitude of momentum of combined mass is as follows:
\(\begin{gathered} P_f=\sqrt[]{(24.1975)^2+(24.4275)^2} \\ P_f=34.38\text{ kg}\cdot\text{ m/s} \end{gathered}\)Direction of momentum of combined mass,
\(\begin{gathered} \theta_f=\tan ^{-1}\frac{P_{fy}}{P_{fx}} \\ \theta_f=\tan ^{-1}(\frac{24.4275}{24.1975}) \\ \theta_f=45^o \end{gathered}\)Polar form of momentum,
\(P_f=(34.38\text{ kg}\cdot m/s,45^o)\)Part-C:
Final velocity of system is as follows:
\(\begin{gathered} \vec{P}_f=m_c\vec{v} \\ (24.1975\hat{i}+24.4275\hat{j})kg\text{ }\cdot\text{ m/s =}(5.75\operatorname{kg}+3.85\text{ kg)}\vec{\text{ v}} \\ \vec{v}=(\frac{24.1975}{9.6}\hat{i}+\frac{24.4275}{9.6}\hat{j}) \\ \vec{v}\text{ =(2.52}\hat{\text{i}}+2.54\hat{j})\text{ m/s} \end{gathered}\)Magnitude of final velocity is as follows:
\(\begin{gathered} v=\sqrt[]{2.52^2+2.54^2} \\ v=3.58\text{ m/s} \end{gathered}\)Direction of final velocity with respect to x-axis,
\(\begin{gathered} \theta_{fv}=\tan ^{-1}(\frac{2.54}{2.52}) \\ \theta_{fv}=\tan ^{-1}(1.00) \\ \theta_{fv}=45^o \end{gathered}\)Polar form of final velocity,
\(v=(3.58m/s,45^o)\)a parallel-plate capacitor with circular plates of radius 0.17 m is being discharged. a circular loop of radius 0.39 m is concentric with the capacitor and halfway between the plates. the displacement current through the loop is 2.6 a. at what rate is the electric field between the plates changing?
Answers
The electric field between the plates of the capacitor is changing at a rate of approximately 3.38×10⁷ V/m²/s.
The displacement current, Id, is related to the rate of change of electric flux, \(\phi_E\), as follows:
\(I_d = \epsilon_0 \dfrac{d\phi_E}{dt}\)
where \(\epsilon_0\) is the permittivity of free space. In this problem, the circular loop is halfway between the plates of the capacitor, so it is parallel to the plates and perpendicular to the electric field between the plates. Therefore, the electric flux passing through the loop is proportional to the electric field between the plates.
Let E be the electric field between the plates of the capacitor, and let A be the area of the loop. Then, the electric flux passing through the loop is given by:
\(\phi_E = E \times A\)
Differentiating both sides with respect to time, we get:
\(\dfrac{d\phi_E}{dt} = A \times \dfrac{dE}{dt}\)
\(I_d = \epsilon_0 \times A \times \dfrac{dE}{dt}\)
Solving for dE/dt, we get:
\(\dfrac{dE}{dt} = \dfrac{I_d}{(\epsilon_0 \times A)}\)
Substituting the given values, we get:
\(\dfrac{dE}{dt} = \dfrac{(2.6) }{(8.85\times 10^{-12} \times \pi(0.39)^2)}\)
Solving this expression, we get:
\(\dfrac{dE}{dt} = 3.38\times 10^7 \text{V/m^2/s}\)
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Denise heats a beaker of dilute acid on a hot plate in a fume hood. What should Denise wear to best protect herself when she transports the beaker to a balance outside the hood?
Answers
Answer:
D . goggles, a lab coat, heat-proof gloves, and close-toed shoes
Explanation:
Answer:
goggles, a lab coat, heat-proof gloves, and close-toed shoes
Explanation:
a pulley wheel is 77 mm diameter and transmits 1 kw of power at 373 rev/min. the maximum belt tension is 1,116 n at this point. calculate the initial tension applied to the stationary belts.
Answers
The initial tension applied to the stationary belts is 1116 N.
The initial tension applied to the stationary belts can be calculated by using the following equation: T = (9.55 * P * n)/(π * D), where T is tension, P is power, n is rev/min, and D is diameter.
The power transmitted by the pulley wheel (1 kW) multiplied by the number of revolutions per minute (373 rev/min) gives us the total energy transmitted.
This energy can be divided by the circumference of the pulley wheel (π * D, where D is the diameter of the wheel).
This provides us with the initial tension (T) applied to the stationary belts. Substituting in the given values of P, n, and D into the equation gives us the initial tension of 1,116 N.
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Please Answer Question 7
Answers
7. a) The bulbs will not light up in Circuit B when the switches are closed.
b) To correct the problem, the wire connecting the two switches in Circuit B should be moved to connect the two bulbs in parallel, as shown in Circuit A.
What is a closed circuit?A closed circuit is a complete and continuous path of an electric current through a conducting wire that permits electrical energy to be transmitted from a power source to an electrical device.
In a closed circuit, current flows from the power source to the electrical device and back to the power source. An open circuit, on the other hand, arises when there is a gap in the circuit that prevents current from flowing.
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chilling is the number of hours between 12 and 20 degrees centigrade. T/F
Answers
Chilling refers to the process of cooling or lowering the temperature of something. It is not a specific measurement of time or temperature range. False.
The term "centigrade" is used to measure temperature on a scale of 0 to 100, with 0 being the freezing point of water and 100 being the boiling point of water. Therefore, the statement is incorrect.
Chilling refers to the process of cooling or lowering the temperature of something. It is not a specific measurement of time or temperature range. The term "centigrade" is used to measure temperature on a scale of 0 to 100, with 0 being the freezing point of water and 100 being the boiling point of water.
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Compounds are made from the atoms of two or more______?
Answers
Answer:
elements
not really an explanation
i need help plz A model rocket lifts off with an upward thrust of 35 Newtons. It has a mass of 2.5 kilograms and a weight of 25 Newtons. How quickly does the rocket accelerate?
Answers
Answer:
thanks for the points
Explanation: