a ____ pressure usually indicates clearing weather or fair weather. a. steadily rising b. constant c. fluctuating d. steadily falling

Answers

Answer 1

A steadily rising pressure usually indicates clearing weather or fair weather.

In general, changes in barometric pressure can be used to predict changes in weather conditions. A rising barometric pressure usually indicates that the weather is clearing up or will remain fair, while a falling barometric pressure often indicates that stormy weather is on the way.

A steadily rising pressure indicates that the air pressure is increasing and the weather is likely to improve or remain stable. In contrast, a steadily falling pressure indicates that the air pressure is decreasing, which could indicate an approaching storm or other atmospheric disturbance. Fluctuating pressure and constant pressure are not necessarily indicative of any specific weather conditions.

So, the correct answer is a. steadily rising.

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Answer 2

A steadily rising pressure usually indicates clearing weather or fair weather.

The pressure is an important factor in predicting weather conditions.

A barometer is used to measure atmospheric pressure and it is typically reported in inches of mercury or millibars.

Changes in atmospheric pressure can provide important clues about the weather conditions that are expected to occur in the near future.

When the atmospheric pressure is steadily rising, it typically indicates that clearing weather or fair weather is on the way.

This is because high pressure systems generally bring with them clear skies and dry air, which can make for pleasant weather conditions.

In contrast, when the atmospheric pressure is steadily falling, it is typically an indication that stormy weather is on the way.

This is because low pressure systems generally bring with them cloudy skies and moist air, which can lead to precipitation and thunderstorms.

A constant pressure may indicate that the current weather conditions are likely to persist for a while.

However, it is important to note that changes in wind patterns or temperature can still affect the weather, even if the pressure remains constant.

Fluctuating pressure can be an indication that weather conditions are likely to change rapidly.

For example, if the pressure is dropping quickly, it may indicate that a storm is approaching.

In summary, understanding the relationship between atmospheric pressure and weather conditions can be helpful in predicting the weather.

A steadily rising pressure usually indicates clearing weather or fair weather, while a steadily falling pressure usually indicates stormy weather.

A constant pressure may indicate that the current weather conditions are likely to persist, while fluctuating pressure can be an indication that weather conditions are likely to change rapidly.

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Related Questions

A projectile, initially at the origin, moves along a straight-line path through a fluid medium such that its velocity is v=1800(1−e−0.3t)mm/s where t is in seconds.
Determine the displacement of the projectile during the first 2 s .

Answers

The displacement of the projectile during first 2 seconds is 5400 mm.

What is meant by a projectile?

A body projected by external force and continuing in motion by its own inertia is called as projectile.

Motion of an object thrown into the air when, after initial force that launches the object, air resistance is negligible and only other force that object experiences is the force of gravity is known as projectile motion.

∫(0 to 2) v dt = ∫(0 to 2) 1800(1−e−0.3t) dt

= 1800 [t + (1/0.3)e^(-0.3t)] from 0 to 2

= 1800 [(2 + (1/0.3)e^(-0.6)) - (0 + (1/0.3)e⁰)]

= 1800 [2 + (1/0.3)e^(-0.6) - (1/0.3)]

= 1800 [2 + 3.333 - 3.333]

= 5400 mm

Therefore, displacement of the projectile during the first 2 seconds is 5400 mm.

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A driver is moving forward and stepping on the gas pedal. Which
position-time graph best depicts this motion?

A driver is moving forward and stepping on the gas pedal. Whichposition-time graph best depicts this

Answers

Answer:

D

Explanation:

The string shown is replaced with a shorter string, but all other factors remain the same as before. Did the force change?

Answers

Changing the length of a string may alter the force in a physical system, like a pulley mechanism, if it impacts its tension and length.

How to explain the change

Nonetheless, regarding a digital system such as a software application, replacing the string with another one that does not affect any crucial factors is improbable to cause an alteration in said force amount.

Determining whether changing a component of a method leads to any modifications in strength requires recognizing essential aspects influencing that force while keeping in mind how this modification might hinder these key elements.

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Which gear combination would you like to use when you want to pedal with as few strokes as possible and have your wheels turn as many times as possible

Answers

A lower, easier gear, with the smaller chain ring up front and a largercog in the back, lets you accelerate faster.

Which wave measure is changing by the greatest amount in the image?

A. amplitude
B. wavelength
C. speed
D. frequency

Which wave measure is changing by the greatest amount in the image?A. amplitudeB. wavelengthC. speedD.

Answers

Answer: frequency

Explanation:

amplitude is the max height at which the wave reaches
wavelength distance b/w two waves

the speed at which the wave is oscillating

frequency is no. of oscillations of  a wave per unit length

consider a vertical spring with spring constant 29.25 n/m hanging from the ceiling. a small object with a mass of 1.109 kg is added to the spring and the spring stretches to its equilibrium position. the object is then pulled down a distance of 17.93 cm and released. what is the speed of the object a distance 6.969 cm from the equilibrium point?

Answers

The speed of the object a distance 6.969 cm from equilibrium is 0.696 m/s.

In order to find the speed of the object a distance 6.969 cm from the equilibrium point, we first need to determine the maximum displacement of the object from its equilibrium position. We know that the spring stretches to its equilibrium position when the object is added to it, so the initial displacement is 0.

Next, we can use the formula for the potential energy stored in a spring: PE = 0.5kx², where k is the spring constant and x is the displacement from equilibrium. The potential energy stored in the spring when the object is pulled down a distance of 17.93 cm can be calculated as:

PE = 0.5 * 29.25 * (0.1793)² = 0.238 J

This potential energy is converted to kinetic energy when the object is released, so we can use the conservation of energy to find the speed of the object at any point along its path. At the maximum displacement, all of the potential energy has been converted to kinetic energy, so we can set the two equal to each other:

PE = KE

0.238 = 0.5mv²

where m is the mass of the object and v is its speed at the maximum displacement. Solving for v, we get:

v = √(2PE/m)

v = √(2 * 0.238 / 1.109) = 0.343 m/s

To find the speed of the object a distance 6.969 cm from equilibrium, we can use the conservation of energy again. At this point, the object has both kinetic and potential energy. The potential energy can be calculated using the formula we used earlier with x = 0.06969 m:

PE = 0.5 * 29.25 * (0.06969)² = 0.013 J

The kinetic energy at this point can be found by subtracting the potential energy from the initial kinetic energy:

KE = 0.238 - 0.013 = 0.225 J

Using the formula for kinetic energy, we can find the speed of the object at this point:

KE = 0.5mv²

0.225 = 0.5 * 1.109 * v²

v = sqrt(0.225 / 0.5545) = 0.696 m/s

So the speed of the object a distance 6.969 cm from equilibrium is 0.696 m/s.

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is the acceleration of a fluid particle necessarily zero in steady flow? explain.

Answers

No, the acceleration of a fluid particle is not necessarily zero in steady flow. In steady flow, the fluid properties at any point in the fluid remain constant over time, meaning that the fluid flow rate, velocity, and pressure do not change with time.

However, this does not necessarily mean that the acceleration of individual fluid particles within the flow is zero. According to the continuity equation of fluid mechanics, the rate of fluid flow through any given area in the flow must remain constant in steady flow.

This means that if the cross-sectional area of a pipe carrying fluid decreases, the fluid velocity must increase to maintain a constant flow rate. As the fluid velocity changes, the acceleration of individual fluid particles can also change in response to the changing velocity.

In addition, the Navier-Stokes equations, which describe the motion of fluid particles, include terms for acceleration, which can be non-zero in steady flow if the fluid velocity is changing at a given point.

Therefore, even in steady flow, the acceleration of a fluid particle can be non-zero if there is a change in the fluid velocity at a given point. In summary, while steady flow implies that the fluid properties do not change over time.

It does not necessarily mean that the acceleration of individual fluid particles within the flow is zero. The acceleration can be non-zero if there is a change in the fluid velocity at a given point.

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A kangaroo jumps 2 meters high. At what speed must the kangaroo have left the ground at for it to reach such a height?

Answers

In order to reach the maximum height of 2 meters, Kangaroo should jump with an initial speed of 6.26 m/s.

What are the three equations of motion?

The three equations of motion are -

first law → v = u +at

second law → S = ut + 1/2 at²

Third law → v² - u² = 2aS

Given is a kangaroo who jumped 2 meters high.

Assume that the kangaroo jumped with an initial velocity of 'u' m/s.

The maximum height achieved is 2 meters.

Acceleration due to gravity will be -9.8 m/s²

At maximum height, the velocity will be zero. Therefore, the final velocity 'v' will be zero. Using third law →

v² - u² = 2aS

- u² = - 2gS  

u² = 2gS

u² = 2 x 9.8 x 2

u² = 39.2

u = 6.26 m/s

Therefore, in order to reach the maximum height of 2 meters, Kangaroo should jump with an initial speed of 6.26 m/s.

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(a) A projectile's launch speed is five times its speed at maximum height. Find the launch angle 00. (3 points)(b) A boat crossing a wide river moves with a speed of 10.0 km/h relative to water. The water in the river has a uniform speed of 5.0 km/h due east relative to the ground. If the boat heads due north, determine the magnitude the boat velocity relative to the ground. (2 points)

Answers

boat velocity relative to the ground is = 11.18 Km/h.

Full solution in pic.

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(a) A projectile's launch speed is five times its speed at maximum height. Find the launch angle 00.

Lisa is the second daughter of Mr. And Mrs.Santos she have a height of 1.6 and a weight of 49 kilograms. Find her BMI amd weight status.

Answers

Answer:

BMI = 19.14 [kg/m^2]; Normal or Healthy

Explanation:

Body mass index (BMI) is a person’s weight in kilograms divided by the square of height in meters.

BMI = mass/(height^2)

BMI = 49 / (1.6^2)

BMI = 19.14 [kg/m^2]

BMI                                   Weight Status

Below 18.5                    Underweight

18.5 – 24.9                    Normal or Healthy Weight

25.0 – 29.9                    Overweight

30.0 and Above            Obese

BMI is within the range of Normal or Healthy Weight

your task is to build a road joining a ranch to a highway that enables the drivers to reach the city in the shortest time. how should this be done if the speed limit is 40mi/h on the road and 65 mi/h on the highway? the perpendicular distance from the ranch to the highway is 20mi, and the city is 30mi down the highway

Answers

A straight road from the ranch to the highway at a perpendicular angle, with a distance of approximately 36.06 miles.

To minimize the travel time from the ranch to the city, we need to find the shortest distance between the ranch and the highway, and then build a straight road connecting the ranch to the highway.

Let's draw a diagram to represent the situation:

R         C

 \       /

  \     /

   \   /

    \ /

     H

In this diagram, R represents the ranch, C represents the city, and H represents the point on the highway that is closest to the ranch. The perpendicular distance between R and H is given as 20 miles, and the distance between H and C is given as 30 miles.

We can use the Pythagorean theorem to find the distance between R and H:

d(R,H) = sqrt(20^2 + x^2)

where x is the distance from H to C that we need to find.

To minimize the travel time, we need to minimize the total time it takes to travel from R to C. This time is given by the equation:

t = t1 + t2

where t1 is the time it takes to travel from R to H, and t2 is the time it takes to travel from H to C.

The time it takes to travel from R to H is given by:

t1 = d(R,H) / 40

The time it takes to travel from H to C is given by:

t2 = (30 - x) / 65

Therefore, the total time it takes to travel from R to C is:

t = d(R,H) / 40 + (30 - x) / 65

We want to minimize this expression with respect to x.

To do this, we can take the derivative of t with respect to x, set it equal to zero, and solve for x:

dt/dx = -1/65

Setting this equal to zero, we get:

-1/65 = 0

This equation has no solution, which means that there is no minimum or maximum value of t. However, we can use our common sense to see that the shortest time is achieved when the road from the ranch is perpendicular to the highway.

Therefore, we should build a road from the ranch to the highway at a right angle. The distance between the ranch and the closest point on the highway is 20 miles, and the distance between this point and the city is 30 miles. Therefore, the length of the road we need to build is:

\(\sqrt{(20^2 + 30^2)\) = \(\sqrt{ (1300)\) = 36.06 miles (approximately)

So, we should build a straight road from the ranch to the highway at a perpendicular angle, with a distance of approximately 36.06 miles.

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Suppose a spectral line of hydrogen, normally at 500 nm when measured in a lab on Earth, is observed in the spectrum of a star to be at 500.3 nm. This is called a red shift because the wavelength is longer (and red is on the long-wavelength side of the visible spectrum). How fast is the star moving away from Earth? Give your answer in m/s. Hint: follow example 5.6. Compare in particular to the "Check your learning" calculation, and note that larger Δλ means larger speed.

Answers

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 85 m horizontally away from and below the point of release. What is the initial velocity of the ball in the horizontal direction? Express your answer in term of m/s. Write done the number only. Keep two significant figures.

Answers

Answer: 18.81m/s^2

Explanation:

Given the following :

Height of building = 0. 1 km = 100m

Horizontal distance = 85m

Using the equation :

S = 1/2gt^2

And S = 100, g = 9.8m/s^2

100 = 0.5(9.8)(t^2)

100 = 4.9(t^2)

t^2 = (100 / 4.9)

t^2 = 20.408

t = 4.5175214

t = 4.52s

Therefore, initial velocity of ball in horizontal direction;

Using the equation:

S = ut + 0.5at^2

a in horizontal direction = 0

Therefore,

S = ut

85 = u × 4.52

u = (85 / 4.52)

u = 18.805

u = 18.81m/s

A radio announcer's voice is transmitted via radio waves a distance of 998.25 km. How much time, in microseconds, will it take to transmit the wave over this distance?

Answers

A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.

So, to travel a distance of 998.25 km, the time needed is:

\(\begin{gathered} distance=speed\cdot time\\ \\ 998.25=300000\cdot time\\ \\ time=\frac{998.25}{300000}\\ \\ time=0.0033275\text{ seconds}\\ \\ time=3327.5\text{ microseconds} \end{gathered}\)

Therefore the time required is approximately 3327.5 microseconds.

If water vapour at 200kPa and 150∘C is adiabatically compressed to 2500kPa and 250∘C at a mass flow rate of 4680 kg/h, calculate the power input to the compressor. Hint: Check the related tables in the appendix of textbook. Choose one of the following answers. a.438 kW b.234 kW c.145 kW d.112 kW

Answers

The correct option is  a.438 kW. Adiabatic compression is a thermodynamic process where the compression is done so quickly that no heat exchange takes place between the system and surroundings.  In order to calculate the power input to the compressor, the work done during the adiabatic compression of water vapor must be determined.

The work done is equal to the change in enthalpy, ΔH. The mass flow rate of the water vapor is 4680 kg/h. The enthalpy at point 1 is 3414 kJ/kg, while the enthalpy at point 2 is 4136 kJ/kg. At a pressure of 200 kPa and a temperature of 150 °C, the enthalpy of water vapor is 3414 kJ/kg, according to the steam table.

The power input to the compressor can be determined by dividing the work done by the time required to do it.P = W / tThe mass flow rate of water vapor is 4680 kg/h, which is equivalent to 1.3 kg/s.  3395520 J/s ÷ 1.3 kg/s = 2611963.08 J/kg. Therefore, the power input to the compressor is 2611963.08 J/kg or 2611.96 kW.

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Which Ohm's Law formula is used to solve for the total current in a series circuit when voltage and resistance are known?
Select one:

a. IT = ET/ RT
b. RT = ET / IT
c. IT = RT/ ET
d. IT = ET x RT

Answers

The Ohm's Law formula that is used to solve for the total current in a series circuit when voltage and resistance are known is IT = ET/ RT.

Ohm's Law formula is used to determine the relationship between current, voltage, and resistance in an electrical circuit. The formula is given as I = V/R, where I is the current, V is the voltage, and R is the resistance of the circuit.The formula IT = ET/ RT is a rearranged version of the original formula to solve for total current in a series circuit, where IT is the total current, ET is the total voltage, and RT is the total resistance of the circuit. This formula is used to determine the amount of current that flows through each component of a series circuit.

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Newly created features always add to the end of the Feature list.

Choose the correct answer and select Next Question

A. True

B. False

Answers

Answer:

Explanation:

True

14.0g of metal at 24.0c has 250 joules of heat added to it. the metal's specific heat is 0.105 j/gc. what is the final temperature?

Answers

To find the final temperature of the metal, we can use the formula for heat transfer: Q = m * c * ΔT. The final temperature of the metal is approximately 194.07 °C.

Q = m * c * ΔT

where Q is the heat added,

m is the mass of the metal,

c is the specific heat,

and ΔT is the change in temperature.

Rearranging the formula, we can solve for ΔT and then add it to the initial temperature to find the final temperature.

Given:

Mass of the metal (m) = 14.0 g

Initial temperature (T₁) = 24.0 °C

Heat added (Q) = 250 J

Specific heat (c) = 0.105 J/g°C

We can rearrange the formula Q = m * c * ΔT to solve for ΔT:

ΔT = Q / (m * c)

Substituting the given values:

ΔT = 250 J / (14.0 g * 0.105 J/g°C)

Calculating the value of ΔT:

ΔT = 250 J / 1.47 J/°C ≈ 170.07 °C

Now, we can find the final temperature (T₂) by adding ΔT to the initial temperature:

T₂ = T₁ + ΔT

T₂ = 24.0 °C + 170.07 °C ≈ 194.07 °C

Therefore, the final temperature of the metal is approximately 194.07 °C.

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If the orbit of the moon can be modeled using the equation x263,500 y250,900 = 1, what is the shape of the moon's orbit?

Answers

The equation given, x^2/63,500 + y^2/50,900 = 1, represents an ellipse. An ellipse is a closed curve that resembles a flattened circle. In this case, it represents the shape of the moon's orbit around the Earth.

To understand the shape of the orbit, let's analyze the equation step by step. The equation is in the form (x^2/a^2) + (y^2/b^2) = 1, where a and b are positive constants.

The values of a and b determine the shape and size of the ellipse. In this equation, a is equal to √63,500 and b is equal to √50,900.

Comparing these values, we can see that a is greater than b. This means that the major axis of the ellipse is aligned with the x-axis, and the minor axis is aligned with the y-axis.

So, the shape of the moon's orbit is elongated horizontally, resembling a stretched circle. The wider part of the ellipse represents the maximum distance of the moon from the Earth (apogee), while the narrower part represents the minimum distance (perigee).

In summary, the equation x^2/63,500 + y^2/50,900 = 1 represents an elliptical shape for the moon's orbit around the Earth.

(Note: The terms "x263,500" and "y250,900" in the original question seem to be typos. The correct equation is x^2/63,500 + y^2/50,900 = 1.)

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An object moving with a speed of 35 m/a and has a kinetic energy of 1500j, what is the mass of the object

Answers

Explanation:

Speed or velocity (V) = 35 m/s

Kinetic energy (K. E) = 1500 Joule

mass (m) = ?

We know

K.E = 1/2 * m * v²

1500 = 1/2 * m * 35²

1500 * 2 = 1225m

m = 3000 / 1225

m = 2.45 kg

The mass of the object is 2.45 kg

Hope it will help :)

Un hombre camina 400m hacia el oeste luego 200m hacia el norte. Determina la magnitud y la dirección del desplazamiento resultante

Answers

Answer:

d = 447.21 m,   θ = 153.4º

Explanation:

Let's use the Pythagoras network theorem to find the magnitude of the displacement

          d = \(\sqrt{x^2 + y^2}\)

          d = \(\sqrt{ 400^2 + 200^2}\)

          d = 447.21 m

To encode the direction, let's use trigonometry, we take the East and North directions as positive.

          tan θ’= y / x

          θ'= tan⁻¹ y / x

          θ'= tan⁻¹ (200/400)

          θ ’= 26.6º

This angle is in the second quadrant, so measured from the positive side of the x-axis (East direction)

          θ = 180 - θ'

          θ = 180 -26.6

          θ = 153.4º

Submarine Buoyancy Submarines adjust their buoyancy by changing the amount of water held in rigid containers called ballast tanks.
Part A
If the mass of a submerged submarine increases while the volume remains the same, does the buoyant force on the submarine increase, decrease, or remain the same?
Part B
Calculate the change in the buoyant force on a submerged submarine if it pumps 0.92 m3 of seawater into its ballast tank.

Answers

Even if the submarine's mass rises while its volume stays constant, the buoyant force on it doesn't change. As a result, the buoyant force on the submarine has changed by around 9,434.53 N.

What happens to a submerged submarine's buoyant force when water is pumped into its tanks and it dives?

The air in the ballast tanks is evacuated out of the submarine as it dives, and the ballast tanks are flooded with water until the submarine's overall density is greater than the surrounding water, at which point the submarine starts to sink. (negative buoyancy).

Identify the buoyant force change:

The weight of the displaced water changes in proportion to the change in buoyant force. As a result, the buoyant force has changed as follows:

change in buoyant force = change in weight of displaced water

change in buoyant force = 9,434.53 N

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A red sled slides across a sheet of ice toward a stationary green sled. The two sleds collide and continue sliding together.
After the collision, what is true about the velocity of the two sleds?

Answers

If a red sled slides across a sheet of ice and collides to a stationary green sled and continue sliding together, the velocity of the two sleds will be equal.

This type of collision is called as inelastic collision. In this type of collision, the two objects that undergo collision will move a single object after collision. So they cannot have different velocities.

According to law of conservation of momentum,

m1u1+ m2u2 = m1v1 + m2v2

In inelastic collision,

v1 = v2 = v

m1u1+ m2u2 = ( m1 + m2 ) v

Therefore, the velocity of the two sleds will be equal.

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what is the current if 3.29c of charge pass a point in a circuit every 1.72s

Answers

The current is approximately 1.912 A.

To calculate the current, you need to divide the charge passing through a point in the circuit by the time it takes for the charge to pass.

Given that 3.29 coulombs (C) of charge pass a point in the circuit every 1.72 seconds (s), you can calculate the current as follows:

Current = Charge / Time

Current = 3.29 C / 1.72 s

Current ≈ 1.912 A (Amperes)

Here's some additional information about electric current:

Electric current is the flow of electric charge through a conductor. It is measured in units called Amperes (A). Current is caused by the movement of electrons in a circuit. When a voltage source, such as a battery or power supply, is connected to a closed circuit, it creates a potential difference that allows electrons to move.

The current in a circuit can be either direct current (DC) or alternating current (AC). In DC, the flow of electrons is in one direction, while in AC, the flow of electrons alternates periodically in both directions. The standard household electrical supply is typically AC.

The amount of current in a circuit depends on two factors: the voltage (potential difference) applied across the circuit and the resistance of the circuit. According to Ohm's Law, the current (I) is equal to the voltage (V) divided by the resistance (R):

I = V / R

Ohm's Law helps determine the relationship between voltage, current, and resistance in a circuit.

Current can be measured using an ammeter, which is a device designed specifically for measuring electric current. The ammeter is connected in series within the circuit, allowing the current to flow through it and providing a reading of the current.

It's important to note that excessive current can lead to overheating, electrical hazards, and damage to components. Therefore, it is crucial to design and use electrical circuits within the specified current ratings and safety guidelines.

Understanding the concept of current is essential in various fields, including electrical engineering, physics, and electronics, as it forms the basis for studying circuits, power systems, and electrical devices.

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9. Rank the four displacements for the time intervals CD, DE, EF, and FG in
decreasing order. Explain your answer.

Answers

In decreasing order, the ranking is as follows:

CD, DE, EF, and FG

What is displacement?

Displacement can simply be defined as the difference in the position of the two objects and is independent of the path taken when traveling between the two objects.

Displacement is a vector quantity that has both a direction and magnitude.

The displacement of a hiker with a constant acceleration is equal to the average velocity during a time interval multiplied by the time interval.

The reason is because the time intervals are equal, the displacements are in the same order as decreasing average velocities. So therefore, the average velocity decreases in the order CD, DE, EF, and FG.

In conclusion, displacement depends on two positions which is the initial position and the final position.

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Throwing a ball with more force to increase acceleration is an example of which of Newton’s Laws?

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Answer:

Its the 2nd law of motion

Explanation:

Because it talks about force and acceleration

Throwing a ball with more force to increase acceleration is an example of Newton’s 2nd law of motion.

What is Newton's second law of motion?The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.Newton’s second law states that the acceleration of an object depends upon two variables – the net force acting on the object and the mass of the object.  The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body. This means that as the force acting upon an object is increased, the acceleration of the object is increased. Likewise, as the mass of an object is increased, the acceleration of the object is decreased.

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Another 100 points time is running out this has to be correct! Correct answer gets brainiest! Hurry!

Another 100 points time is running out this has to be correct! Correct answer gets brainiest! Hurry!

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Hey there!

I guess the answer will be 30 km/h

Hope it help you

Answer:

I think it is 30km/hr ooh

which of the following best describes the earth's atmosphere? a. an empty space b. a big blanket absorbing the sun's heat c. a thin towel that does very little to protect the earth d. a large cloud that generates the earth's electromagnetic field e. none of the above

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The correct answer is "b. a big blanket absorbing the sun's heat."

The Earth's atmosphere acts like a big blanket, absorbing some of the sun's heat and helping to regulate the planet's temperature. The atmosphere is composed of a mixture of gases, including nitrogen, oxygen, and carbon dioxide, which protect the planet from the harmful effects of solar radiation, meteorites, and other space debris.

The atmosphere also helps to distribute heat and moisture around the planet, which is crucial for life on Earth. While the atmosphere is not a perfect blanket, it does play a vital role in protecting and supporting life on the planet.

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is 41.1 gmcm-2sec-1 in air. a piece of paper has a mass per unit area of approximately 7x10-3gm/cm2. if the frequency is 4.6 khz, what does theory predict for the ratio of the transmitted amplitude to the incident amplitude of the sound wave? (a sound wave is a pressure wave.)

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Theory predicts that the ratio of the transmitted amplitude to the incident amplitude of the sound wave is approximately \(9.89 x 10^(-8)\).

To calculate the ratio of the transmitted amplitude to the incident amplitude of a sound wave, we can use the concept of acoustic impedance.

Acoustic impedance (Z) is a characteristic property of a medium that describes its resistance to the transmission of sound waves. It is given by the product of the density of the medium (ρ) and the speed of sound in the medium (c):

Z = ρ * c

In this case, we are given the mass per unit area of the paper (μ), which can be converted to density (ρ) using the equation:

ρ = μ / c

where c is the speed of sound in air.

Given:

Mass per unit area of paper (μ) = 7 x 10^(-3) gm/cm^2

Frequency (f) = 4.6 kHz = 4.6 x 10^3 Hz

First, let's convert the mass per unit area from gm/cm^2 to kg/m^2:

μ = 7 x 10^(-3) gm/cm^2 = 7 x 10^(-3) kg/m^2

Next, we need to convert the frequency from kHz to Hz:

f = 4.6 kHz = 4.6 x 10^3 Hz

Now, we can calculate the density of the paper:

ρ = μ / c

Since the speed of sound in air is approximately 343 m/s, we have:

ρ = (7 x 10^(-3) kg/m^2) / 343 m/s

Calculating the value of ρ, we find:

ρ ≈ 2.04 x 10^(-5) kg/(m^2 * s)

Next, let's calculate the acoustic impedance of air:

Z_air = ρ_air * c_air

The density of air at standard conditions is approximately 1.2 kg/m^3, and the speed of sound in air is approximately 343 m/s. Therefore:

Z_air = (1.2 kg/m^3) * (343 m/s) = 411.6 kg/(m^2 * s)

Finally, we can find the ratio of the transmitted amplitude to the incident amplitude using the formula:

Transmitted amplitude / Incident amplitude = (2 * Z_paper) / (Z_paper + Z_air)

Substituting the values, we have:

Transmitted amplitude / Incident amplitude = (2 * 2.04 x 10^(-5) kg/(m^2 * s)) / ((2.04 x 10^(-5) kg/(m^2 * s)) + 411.6 kg/(m^2 * s))

Calculating the value of the ratio, we find:

Transmitted amplitude / Incident amplitude ≈ 9.89 x 10^(-8)

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Why doesn’t an orbiting satellite fall back to earth?

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The reason satellites don’t fall from the sky is because they are orbiting Earth. Even though the satellites are thousands of miles away, Earths gravity still tugs on them. Gravity combined with the satellite's momentum from its launch into space, cause the satellite to go into orbit above Earth instead of falling back down to the ground.
P.S sorry if this isn’t the answer you were looking for have a good day
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