a production line operation is designed to fill cartons with laundry detergent to a mean weight of 128 ounces. a sample of cartons is periodically selected and weighed to determine whether underfilling or overfilling is occurring. if the sample data lead to a conclusion of underfilling or overfilling, the production line will be shut down and adjusted to obtain proper filling. Formulate the null and alternative hypotheses that will help in deciding whether to shut down and adjust the production line.

Answers

Answer 1

The null hypothesis in the sampling is u = 128 and the alternative is that it isn't equal to 128.

Given a mean of 128. The claim here is that the mean is 128.

Therefore, the null hypothesis and alternative hypothesis, would be:

H0 : u = 128

Ha: u ≠ 128

How is the null hypothesis depicted?

It should be noted that based on the information, when the null hypothesis is rejected, it implies that the weight is 128.

Also, there's no enough evidence to conclude that there's either overfilling or underfilling. When the null hypothesis is rejected, it means that the mean weight is not equal to 128.

Hence the answer is The null hypothesis in the sampling is u = 128 and the alternative is that it isn't equal to 128.

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Related Questions

Solve the triangle.
a = ?

Solve the triangle.a = ?

Answers

9514 1404 393

Answer:

  a = 7

Step-by-step explanation:

The Pythagorean theorem tells you the value of 'a' is ...

  a^2 = b^2 - c^2

  a^2 = 25^2 -24^2 = 625 -576 = 49

  a = √49 = 7

The length of side 'a' is 7 units.

What are the MRSs? Determine if there is a diminishing MRS
a. U(x,y)=3x+y
b. U(x,y)=x.y
c. U(x,y)=x​⋅y
d. U(x,y)=x2−y2
​e. U(x,y)=x+yx.y​ 3.

Consider each of a. U(x,y)=x0.1y0.4 b. U(x,y)=min(αx,βy) c. U(x,y)=αx+βy calculate the following i. Demand curves for x and y ii. Indirect utility function iii. (Indirect) expenditure function iv. Show that the demand curve is homogeneous in degree zero in terms of income and prices

Answers

a. The MRS is constant (not diminishing) at 1/3.

U(x,y) = 3x + y

The MRS for this utility function can be found by taking the partial derivative of x concerning y:

MRS = ∂U/∂y / ∂U/∂x = 1 / 3

The MRS is constant (not diminishing) at 1/3.

b. The MRS is diminishing because as y increases, the MRS decreases.

U(x,y) = x * y

The MRS for this utility function can be found by taking the partial derivative of x concerning y:

MRS = ∂U/∂y / ∂U/∂x = 1 / y

The MRS is diminishing because as y increases, the MRS decreases.

c. The MRS is diminishing because as y increases, the MRS decreases.

U(x,y) = x * y

The MRS for this utility function can be found by taking the partial derivative of x concerning y:

MRS = ∂U/∂y / ∂U/∂x = 1 / y

Similar to the previous case, the MRS is diminishing because as y increases, the MRS decreases.

d. The MRS depends on the ratio of y to x and can vary.

U(x,y) = x^2 - y^2

The MRS for this utility function can be found by taking the partial derivative of x concerning y:

MRS = ∂U/∂y / ∂U/∂x = -2y / 2x = -y / x

The MRS depends on the ratio of y to x and can vary. It is not necessarily diminishing.

e. The MRS depends on the values of x and y and can vary.

U(x,y) = x + y / (x * y)

The MRS for this utility function can be found by taking the partial derivative of x concerning y:

MRS = ∂U/∂y / ∂U/∂x = -1 / (y^2) + 1 / (x^2 * y)

The MRS depends on the values of x and y and can vary. It is not necessarily diminishing.

Now let's move on to the second part of the question:

For parts a, b, and c, we need more specific information about the utility functions, such as the values of α and β, to calculate the demand curves for x and y, the indirect utility function, and the expenditure function.

To show that the demand curve is homogeneous in degree zero in terms of income and prices, we need the specific functional form of the utility functions and information about the prices of x and y. Please provide the necessary details for parts A, b, and c to continue the analysis.

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A hospital near a ski resort records the types of injuries treated during ski season and other seasons
over a year. The results shown in the table will help determine the medical staff that is required at
different times of the year. According to the data in the table, what is the probability that a patient will
need to be treated for a broken bone during ski season?

Answers

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the types of injuries and the frequency of each injury are not given.

A general way to solve a question like this, is as follows;

First: Calculate the total frequency.

Assume the given dataset is:

\(\begin{array}{cc}{Injury} & {Frequency} & {Dislocation} & {20} & {Strain} & {5} & {Broken\ Bone} & {10} & {Bruise} & {15} \ \end{array}\)

The total frequency is:

\(Total =20 + 5 + 10 + 15\)

\(Total =50\)

Next, write out the frequency of broken bone injuries

\(Broken\ Bone = 10\)

Calculate the probability by dividing the number of broken bone by the total frequency

\(Pr= \frac{10}{50}\)

\(Pr = 0.20\)

write down the multiplication tables for z/6zand z/7z. list the elements have multi- plicative inverses.

Answers

For Z/6Z and Z/7Z, the multiplication tables are 1-5 and 0 and 1-6 and 0 correspondingly. The elements 1, 2, 3, 4, 5 and 1, 3, 5, 6 respectively have multiplicative inverses.

The multiplication table is as follows for the group Z/6Z:

1 * 1 = 1\s2 * 1 = 2\s3 * 1 = 3\s4 * 1 = 4\s5 * 1 = 5\s0 * 1 = 0

1, 2, 3, 4, and 5 are the elements with multiplicative inverses.

The multiplication table is as follows for the group Z/7Z:

1 * 1 = 1\s2 * 1 = 2\s3 * 1 = 3\s4 * 1 = 4

5 * 1 = 5\s6 * 1 = 6\s0 * 1 = 0

1, 3, 5, and 6 are the elements with multiplicative inverses.

The group members in a group Z/NZ are the remainders after dividing the integers by N. For instance, the elements in Z/6Z are 0, 1, 2, 3, 4, and 5. The product of each element is shown in the multiplication table.by itself when multiplied. The multiplication table for Z/6Z is as follows: 0 * 1 = 0; 1 * 1 = 1, 2 * 1 = 2, 3 * 1 = 3, 4 * 1 = 4, 5 * 1 = 5. 1, 2, 3, 4, and 5 are the elements with multiplicative inverses. The multiplication table is also the same for Z/7Z: 1 * 1 = 1, 2 * 1 = 2, 3 * 1 = 3, 4 * 1 = 5, 6 * 1 = 6, 0 * 1 = 0. 1, 3, 5, and 6 are the elements with multiplicative inverses.

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50 is what percent of 1000

Answers

Answer:500

explanchion: 1000/50=500

A cell phone tower services a circular region
within 20 miles of the tower. What is the
area of the region? (Use it = 3.14)

A cell phone tower services a circular regionwithin 20 miles of the tower. What is thearea of the region?

Answers

Area of a circle: pi x r^2

---r is the radius of the circle

A = pi x 20^2

A = 3.14 x 400

A = 1256 square miles

Hope this helps!

determine the intervals on which the graph of =()y=f(x) is concave up or concave down, and find the points of inflection.

Answers

the graph of f(x) = x^3 - 3x^2 - 9x + 5 is concave down on the interval (-∞, 1), concave up on the interval (1, +∞), and has a point of inflection at x = 1.

To determine the intervals on which the graph of a function is concave up or concave down, we need to analyze the second derivative of the function. The concavity of a function can change at points where the second derivative changes sign.

Here's the step-by-step process to find the intervals of concavity and points of inflection:

Find the first derivative of the function, f'(x).

Find the second derivative of the function, f''(x).

Set f''(x) equal to zero and solve for x. The solutions give you the potential points of inflection.

Determine the intervals between the points found in step 3 and evaluate the sign of f''(x) in each interval. If f''(x) > 0, the graph is concave up; if f''(x) < 0, the graph is concave down.

Check the concavity at the points of inflection found in step 3 by evaluating the sign of f''(x) on either side of each point.

Let's go through an example to illustrate this process:

Example: Consider the function f(x) = x^3 - 3x^2 - 9x + 5.

Find the first derivative, f'(x):

f'(x) = 3x^2 - 6x - 9.

Find the second derivative, f''(x):

f''(x) = 6x - 6.

Set f''(x) equal to zero and solve for x:

6x - 6 = 0.

Solving for x, we get x = 1.

Therefore, the potential point of inflection is x = 1.

Determine the intervals and signs of f''(x):

Choose test points in each interval and evaluate f''(x).

Interval 1: (-∞, 1)

Choose x = 0 (test point):

f''(0) = 6(0) - 6 = -6.

Since f''(0) < 0, the graph is concave down in this interval.

Interval 2: (1, +∞)

Choose x = 2 (test point):

f''(2) = 6(2) - 6 = 6.

Since f''(2) > 0, the graph is concave up in this interval.

Check the concavity at the point of inflection:

Evaluate f''(x) on either side of x = 1.

Choose x = 0 (left side of x = 1):

f''(0) = -6.

Since f''(0) < 0, the graph is concave down on the left side of x = 1.

Choose x = 2 (right side of x = 1):

f''(2) = 6.

Since f''(2) > 0, the graph is concave up on the right side of x = 1.

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A particle which moves with curvilinear motion has coordinates in millimeters which vary with the time t in seconds according to x= 1.3t
2
−6.6t and y=2.8t
2
−t
3
/4.0. Determine the magnitudes of the velocity v and acceleration a and the angles which these vectors make with the x-axis when t=4.1 s. Answers: When t=4.1 s
v=
a=


mm/s,
mm/s
2
,


θ
x

=
θ
x

=

eTextbook and Media

Answers

To find the magnitudes of the velocity (v) and acceleration (a) and the angles they make with the x-axis at t = 4.1 s, we need to differentiate the given equations for x and y with respect to time (t).

Given:

x = 1.3t^2 - 6.6t

y = 2.8t^2 - (t^3)/4.0

Velocity (v):

The velocity is the rate of change of position with respect to time. It can be calculated by taking the derivatives of x and y with respect to t:

vx = dx/dt = d/dt(1.3t^2 - 6.6t)

vy = dy/dt = d/dt(2.8t^2 - (t^3)/4.0)

Calculate vx and vy by differentiating the expressions:

vx = 2.6t - 6.6

vy = 5.6t - (3t^2)/4.0

At t = 4.1 s, substitute t = 4.1 into vx and vy to find the components of the velocity vector at that time.

Acceleration (a):

The acceleration is the rate of change of velocity with respect to time. We can calculate it by taking the derivatives of vx and vy with respect to t:

ax = d(vx)/dt = d/dt(2.6t - 6.6)

ay = d(vy)/dt = d/dt(5.6t - (3t^2)/4.0)

Calculate ax and ay by differentiating the expressions:

ax = 2.6

ay = 5.6 - (3t)/2.0

Again, substitute t = 4.1 s into ax and ay to find the components of the acceleration vector at that time.

Angles with the x-axis (θx):

To find the angles that the velocity and acceleration vectors make with the x-axis, we can use the inverse tangent function:

θx = arctan(vy / vx)

Calculate θx using the values of vx and vy at t = 4.1 s.

Substitute the values of v, a, and θx into the answers to complete the solution.

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What are the 3 similarity rules?

Answers

The three similarity rules are

AA ( Angle-Angle) SSS ( Side-Side-Side)SAS ( Side-Angle-Side)

What is similarity rule?

Two triangles are said to be similar if the two sides of a triangle are in the same proportions as the two sides of another triangle and the angles inscribed by the two sides of both triangles are the same. There are three rules to determine the similarity in two triangles :

1) AA postulate: Two triangles are similar if their corresponding angles are congruent. The sum of the angles in a triangle is 180°, so you don't need the third.

2) SSS Postulate: Two triangles are similar if all corresponding sides are proportional.

3) SAS Assumption: Two triangles are similar if their corresponding sides are proportional and the angles between them are congruent.

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Ted has three cards 5, 2, 6 Make a list of all the 3-didget numbers he can make

Answers

562, 265, 526, 625, 256, 652,

Una impresora imprime 28 fotos en 8 minutos ¿cuántas fotos imprimirá en 20 minutos?

Answers

Answer:

70 fotos

Step-by-step explanation:

28 fotos en 8 minutos

3.5 fotos por minuto.

Entonces, 3.5 x 20 = 70 fotos

what is the LCM of 9 and 15?

what is the LCM of 9 and 15?

Answers

Answer:

B

Step-by-step explanation:

15+15=30

30/9=3 r3 doesn't work

30+15=45

45/9=5

It’s 45. B. Hope this helped!

The diagram shows a rectangle with length
2)
(3d + 2) am and width (d+5) cm.
3d+2
d+5
a Write an expression for the perimeter of the
rectangle.
b Given that the perimeter is 30 cm, make and
solve an equation to find a
c Find the area of this rectangle
M

The diagram shows a rectangle with length2)(3d + 2) am and width (d+5) cm.3d+2d+5a Write an expression

Answers

Step-by-step explanation:

Given that,

Length, l = (3d+2) m

Width, b = (d+5) m

(a) Perimeter of the rectangle,

P = 2(l+b)

P = 2(3d+2+d+5)

= 2(4d+7)

P = 8d+14

(b) If P = 30 cm.

8d+14 = 30

8d = 16

d = 2

(c) l = (3(2)+2) = 8 m

b = (2+5) = 7 m

The area of this rectangle,

A = lb

A = 8×7

A = 56 cm²

Hence, this is the required solution.

Please help, I will give brainliest, and look at the screen shot!

Please help, I will give brainliest, and look at the screen shot!

Answers

Where’s the question?? I can’t answer without a question.

Job #1 pays $42.50 for 5 hours of work. Job #2 pays $136.50 for 13
hours of work.
What does Job #1 pay in dollars per hour (to the nearest cent)?

Answers

Answer:

$8.50

Step-by-step explanation:

42.50 divided by 5 = 8.50

What is the ratio of red to blue squares in its simplest form?
14 red 4 blue

Answers

Simplest Form: \(7 : 2\)

How to Simplify a Ratio A : B when A and B are both whole numbers:

List the factors of AList the factors of BFind the greatest common factor of A and B, GCF(A, B)Divide A and B each by the GCFUse the whole number results to rewrite the ratio in simplest form

Try to reduce the ratio further with the greatest common factor (GCF).

The GCF of 14 and 4 is 2

Divide both terms by the GCF, 2:

14 ÷ 2 = 7

4 ÷ 2 = 2

The ratio 14 : 4 can be reduced to lowest terms by dividing both terms by the GCF = 2 :

14 : 4 = 7 : 2

Therefore:

14 : 4 = 7 : 2

what is the linear function ?

what is the linear function ?

Answers

Answer:

f(x)= 5x+2

Step-by-step explanation:

Slope is 5, y intercept is (0,2)

At the end of July, the Salisbury family headed home after a vacation. The Salisbury's were 750 km from home when they started out, but 4 h later they were only 394 km from home. They did not stop and they maintained a constant speed.
a. How fast were they driving?

Please show your work but not in the physics formula do it a diffirent way and please explain

Answers

To find the speed at which the Salisbury family was driving, we can use the formula: Speed = Distance / Time. So, the Salisbury family was driving at a speed of 89 kilometers per hour.



The distance they traveled is the difference between their initial distance from home (750 km) and their distance from home after 4 hours (394 km):
Distance = 750 km - 394 km = 356 km
The time they took to cover this distance is 4 hours.

Now we can calculate the speed:
Speed = 356 km / 4 h = 89 km/h
Therefore, the Salisbury family was driving at a speed of 89 kilometers per hour.

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You have at most $10 to spend on markers and notebooks. Markers
cost $1.25 each, and notebooks cost $2.50 each. Write and graph an
inequality that represents the numbers of markers and notebooks you
can buy. Identify and interpret two solutions of the inequality.

Answers

The Possible Solutions are

(i) 0 Marker and 4 Notebooks

(ii) 8 Marker and 0 Notebooks

What is Linear Inequality?

A linear inequality is a mathematical inequality that incorporates a linear function. A linear inequality contains one of the inequality symbols. It displays data that is not equal in graph form.

Solution:

Given: Total Money in hand = $10

Price of Marker Per Piece = $1.25

Price of Notebook Per Piece = $2.5

Let, number of marker be x and number of notebook be y

The inequalitites are

1.25x < 10

2.5y < 10

The Possible Solutions are

(i) 0 Marker and 4 Notebooks

(ii) 8 Marker and 0 Notebooks

Refer the Graph attached

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You have at most $10 to spend on markers and notebooks. Markerscost $1.25 each, and notebooks cost $2.50

what is the surface area of this solid?

A: 37.68
B: 40.82
C: 28.26
D: 31.4

what is the surface area of this solid?A: 37.68B: 40.82C: 28.26D: 31.4

Answers

The surface area of the given shape above would be = 47.2

How to calculate the surface area of the given solid shape?

To determine the surface area of the solid shape above,the surface area of a cone and a cylinder is first determined and then added together.

The formula for the surface area (SA) of cone = πrs + πr²

where;

r = 1

s = 6

S.A = 3.14×1×6 + 3.14×1×1²

= 18.84+3.14

= 21.98

Formula for Surface area of cylinder = 2πr(r+h)

where;

r = 1

h = 3

SA = 2×3.14×1 (1+3)

= 25.12

Therefore, the surface area of the solid shape = 21.98+25.22 = 47.2

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solve inequality for x : -46 - 8x > 22

Answers

Answer:

x < -17/2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right  

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

-46 - 8x > 22

Step 2: Solve for x

[Addition Property of Equality] Add 46 on both sides:                                  -8x > 68[Division Property of Equality] Divide -8 on both sides:                                x < -17/2

Answer: x < −17/2

Step-by-step explanation:

Let's solve your inequality step-by-step.

−46 − 8x > 22

Step 1: Simplify both sides of the inequality.

−8x − 46 > 22

Step 2: Add 46 to both sides.

−8x − 46 + 46 > 22 + 46

−8x > 68

Step 3: Divide both sides by -8.

−8x/−8 > 68/−8

x < −17/2

If 5y+9=5+3y then the value of y is ????

Answers

Answer:

\(y=-2\)

Step-by-step explanation:

\(5y+9=5+3y\)

\(5y+9-9=5+3y-9\)

\(5y=3y-4\)

\(5y-3y=3y-4-3y\)

\(2y=-4\)

\(\cfrac{2y}{2}=\cfrac{-4}{2}\)

\(y=-2\)

Answer

y=-2

Step-by-step explanation:

5y+9=5+3y

5y-3y=5-9

2y=-4

y=-2

Suppose that the daily miles driven by a trucking company is normally distributed with a mean of 330 miles and a standard deviation of 115 miles. One day a randomly selected driver drives 580 miles. (a) Calculate the Z-score corresponding to x=580 miles. (b) What is the probability of a driving 580 or more miles? (c) What is the probability of driving between 250 and 580 miles? 2. The times required by three workers to perform an assembly-line task were recorded on five randomly selected occasions. Here are the times, to the nearest minute. Using the data given below apply a one way ANOVA test at 0.05 significant level. ANOVA Test Table: (a) Calculate the effect size with ANOVA, η2 (Eta squared). (b) Fill in the calculated values in the ANOVA test table. (c) Writeup APA format results.

Answers

(a) Z-score for x=580 miles ≈ 2.30.

(b) Probability of driving 580+ miles ≈ 0.0107 or 1.07%.

(c) Probability of driving between 250 and 580 miles ≈ 0.7840 or 78.40%.

(a) To calculate the Z-score, we use the formula Z = (x - mean) / standard deviation. Plugging in the values, we have Z = (580 - 330) / 115 ≈ 2.30.

(b) To find the probability of driving 580 or more miles, we calculate the area under the normal distribution curve to the right of the Z-score. This can be done using a Z-table or a calculator. The probability is approximately 0.0107 or 1.07%.

(c) To find the probability of driving between 250 and 580 miles, we calculate the area under the normal distribution curve between the Z-scores corresponding to those values. Again, using a Z-table or calculator, the probability is approximately 0.7840 or 78.40%.

For the second part of the question, ANOVA (Analysis of Variance) is conducted to compare the means of three or more groups. However, the provided information does not include the data for the assembly-line task times or the calculated values for the ANOVA test table. Without this data, it is not possible to perform the ANOVA test or calculate the effect size (η2) or fill in the ANOVA test table. Additionally, the instructions for writing up the APA format results are not provided.

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.
How is 700,000,000 expressed in standard scientific notation?
7.0 × 10^-8

7.0 × 10^+8
IS IT POSITIVE 8 OR NEGATIVE 8?

Answers

Positive.

Hope this helps.

whenever hugo buys a 12-ounce soda at his nearby convenience store, he gets a stamp for the card that he carries in his wallet. when he has 8 stamps, he can exchange the card for a free soda. this is an example of a(n):

Answers

20 ounces

Step-by-step explanation:

no exceptions

When interpreting F(2,27) = 8.80,p < 0.05,what is the within-groups df?
A)30
B)27
C)3
D)2

Answers

The degrees of freedom (df) for the within-groups scenario is 27.

In the F-test, which is used to compare variances between groups, the degrees of freedom consist of two components: the numerator df and the denominator df. The numerator df corresponds to the number of groups being compared, while the denominator df represents the total number of observations minus the number of groups.

In the given scenario, F(2,27) = 8.80 indicates that the F-test is comparing variances between two groups. The numerator df is 2, representing the number of groups being compared.

To determine the within-groups df, we need to calculate the denominator df. The denominator df is calculated as the total number of observations minus the number of groups. Since the denominator df is given as 27, it implies that the total number of observations is 27 + 2 = 29, considering the two groups being compared.

Therefore, the within-groups df is 27, as it represents the total number of observations minus the number of groups in the F-test.

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calculate the following fractions and leave the answer correct to two decimal places. 3 2/5 - 2 2/3​

Answers

Answer:

0.73

Step-by-step explanation:

3 2/5 = 17/5, 2 2/3 = 8/3

17/5 - 8/3

3/3 x 17/5 = 51/15

5/5 x 8/3 = 40/15

51/15 - 40/15 = 11/15

11/15= 0.73

I also give brainliest on this, help please is for today ​

I also give brainliest on this, help please is for today

Answers

Step-by-step explanation:

\( \frac{42}{14} = \frac{x}{12} \\ x = \frac{42 \times 12}{14} \\ x = \frac{504}{14} \\ x = 36\)

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The function y = 3.28 x converts length from x meters to y feet.
a. Graph the function. Which variable is independent? dependent? b. Is the domain discrete or continuous

Answers

The given function y = 3.28x converts length from x meters to y feet.

To graph the function, we can plot a few points and connect them.

Here are some points that we can plot:

x (meters) y (feet)0 03.28 10.7613.12 42.9456.56 214.5489.14 299.8720 65.6160 524.9340.3048 1

Since y depends on x, x is the independent variable, and y is the dependent variable.

We can see that as the value of x increases, so does the value of y, which means that the graph slopes upward

The domain of a function is the set of all values that the independent variable can take on. Since we can have any positive value of x (in meters), the domain of this function is continuous.

In conclusion, the given function y = 3.28x converts length from x meters to y feet. x is the independent variable, and y is the dependent variable. The graph of the function slopes upward, indicating that as x increases, y also increases. The domain of the function is continuous because x can take on any positive value.

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3.12 If h(t)= [u(t-1)- u(t - 4)] and x(t) = t[u(t)- u(t-2)], obtain graphically the response y(t). For what value of t does y(t) reach its maximum value?

Answers

The response y(t) graphically, we can first plot the individual functions h(t) and x(t) on a graph, and then determine their convolution to obtain y(t). Let's go step by step:

Plotting h(t):

The function h(t) is defined as h(t) = [u(t-1) - u(t-4)].

The unit step function u(t-a) is 0 for t < a and 1 for t ≥ a. Based on this, we can plot h(t) as follows:

For t < 1, h(t) = [0 - 0] = 0

For 1 ≤ t < 4, h(t) = [1 - 0] = 1

For t ≥ 4, h(t) = [1 - 1] = 0

So, h(t) is 0 for t < 1 and t ≥ 4, and it jumps up to 1 between t = 1 and t = 4. Plotting h(t) on a graph will show a step function with a jump from 0 to 1 at t = 1.

Plotting x(t):

The function x(t) is defined as x(t) = t[u(t) - u(t-2)].

For t < 0, both u(t) and u(t-2) are 0, so x(t) = t(0 - 0) = 0.

For 0 ≤ t < 2, u(t) = 1 and u(t-2) = 0, so x(t) = t(1 - 0) = t.

For t ≥ 2, both u(t) and u(t-2) are 1, so x(t) = t(1 - 1) = 0.

So, x(t) is 0 for t < 0 and t ≥ 2, and it increases linearly from 0 to t for 0 ≤ t < 2. Plotting x(t) on a graph will show a line segment starting from the origin and increasing linearly with a slope of 1 until t = 2, after which it remains at 0.

Obtaining y(t):

To obtain y(t), we need to convolve h(t) and x(t). Convolution is an operation that involves integrating the product of two functions over their overlapping ranges.

In this case, the convolution integral can be simplified because h(t) is only non-zero between t = 1 and t = 4, and x(t) is only non-zero between t = 0 and t = 2.

The convolution y(t) = h(t) * x(t) can be written as:

y(t) = ∫[1,4] h(τ) x(t - τ) dτ

For t < 1 or t > 4, y(t) will be 0 because there is no overlap between h(t) and x(t).

For 1 ≤ t < 2, the convolution integral simplifies to:

y(t) = ∫[1,t+1] 1(0) dτ = 0

For 2 ≤ t < 4, the convolution integral simplifies to:

y(t) = ∫[t-2,2] 1(t - τ) dτ = ∫[t-2,2] (t - τ) dτ

Evaluating this integral, we get:

\(y(t) = 2t - t^2 - (t - 2)^2 / 2,\) for 2 ≤ t < 4

For t ≥ 4, y(t) will be 0 again.

Maximum value of y(t):

To find the value of t at which y(t) reaches its maximum value, we need to examine the expression for y(t) within the valid range 2 ≤ t < 4. We can graphically determine the maximum by plotting y(t) within this range and identifying the peak.

Plotting y(t) within the range 2 ≤ t < 4 will give you a curve that reaches a maximum at a certain value of t. By visually inspecting the graph, you can determine the specific value of t at which y(t) reaches its maximum.

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