a projectile is launched at an angle of 600 with the horizontal and a speed of 30 m/s. what is its height after one second?

Answer:

Weight is what you get when a certain amount of gravity is acting on that mass, and something, like the surface of a planet, is resisting that action. In space, when falling freely, there's nothing resisting the pull of gravity so weight disappears. Mass however stays.

hope this helps u

Explanation:

Fracking has become widely used in the US, raising worries about its effects on the environment and public health. Large volumes of wastewater are produced, along with greenhouse gases like methane, hazardous air pollution, and noise.

Fracking, also known as hydraulic fracturing, is a technique for obtaining gas and oil through shale rock. With the help of a high-pressure injection of water, sand, and chemicals into bedrock, gas and oil can flow into a well and be collected for sale.

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Explain any environmental issue that arose from fluid technology.

Answer:

d = 61.75 m

Explanation:

Given that,

A ball droped from a building.

We need to find how fast is it traveling after falling 3.55 s.

As it is dropped, its initial velocity is equal to 0.

Let d is the distance it covers after falling 3.55 s.

We can use second equation of motion to find d.

\(d=ut+\dfrac{1}{2}at^2\)

Here, u = 0 and a =g

\(d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times (3.55)^2\\\\d=61.75\ m\)

So, it will cover 61.75 m after falling 3.55 seconds.

The bass strings in a concert grand piano are typically very long and thick to produce the low-frequency sounds that give the instrument its rich, full-bodied tone. To achieve the desired sound, the strings are made of steel wire, which is a strong and durable material that can withstand the tension required to produce the notes.

However, steel wire alone is not enough to produce the desired sound for the bass notes. When a string is plucked or struck, it vibrates back and forth, and the resulting sound wave travels through the air. The vibration of the string creates a complex pattern of harmonics and overtones, which are additional frequencies that give the sound its characteristic timbre.

The fundamental frequency of a steel string is determined by its length, tension, and mass per unit length. To achieve the lower frequencies required for the bass notes, the string must be longer and thicker. However, this increases the mass per unit length of the string, which can lead to a loss of clarity and definition in the sound.

To address this issue, the bass strings in a concert grand piano are wrapped with a loose coil of lead wire. The lead wire is much denser than the steel wire, so it adds mass to the string without increasing its diameter. This helps to lower the fundamental frequency of the string, while maintaining clarity and definition in the sound. The lead wire also helps to dampen unwanted harmonics and overtones, resulting in a clearer and more focused sound.

Overall, the combination of the steel wire and lead wire in the bass strings of a concert grand piano allows for a rich, full-bodied sound that is essential to the instrument's unique character and versatility.

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Answer:

Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996).

Explanation:

I hope this helps.

Answer: gravity is one major force that creates tides

Explanation:

in 1687, sir Isaac newton explained that ocean tides result from the gravitational attraction of the sun and the moon on the oceans of the earth

Answer:

165 kPa

Explanation:

Absolute pressure is:

P = Patm + ρgh

where Patm is the atmospheric pressure,

ρ is the density,

g is acceleration due to gravity,

and h is the depth.

P = 101,300 Pa + (1000 kg/m³) (9.8 m/s²) (6.50 m)

P = 165,000 Pa

P = 165 kPa

The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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To find Vy and ay when y = 4RE, we need to differentiate the expression for y(t) with respect to time (t).

Given:

y(t) = (RE^(3/2) + (3√g/2)RE^t)^(2/3)

RE = radius of the Earth = 6.38 x 10^6 m

g = acceleration due to gravity = 9.81 m/s^2

First, let's find Vy by differentiating y(t) with respect to t:

Vy = dy/dt.

Taking the derivative of y(t) with respect to t, we get:

dy/dt = (2/3) * (RE^(3/2) + (3√g/2)RE^t)^(-1/3) * [(3√g/2)RE^t * ln(RE) + (3√g/2)RE^t].

Now, let's find ay by differentiating Vy with respect to t:

ay = dVy/dt.

Taking the derivative of Vy with respect to t, we get:

dVy/dt = d^2y/dt^2 = -(2/3) * (RE^(3/2) + (3√g/2)RE^t)^(-4/3) * [(3√g/2)RE^t * ln(RE) + (3√g/2)RE^t]^2 + (2/3) * (RE^(3/2) + (3√g/2)RE^t)^(-1/3) * [(3√g/2)RE^t * ln(RE) + (3√g/2)RE^t * (3√g/2)RE^t * ln(RE) + (3√g/2)RE^t * ln(RE) + (3√g/2)RE^t].

Now, substitute y = 4RE into the expressions for Vy and ay:

Vy = (2/3) * (RE^(3/2) + (3√g/2)RE^t)^(2/3) * [(3√g/2)RE^t * ln(RE) + (3√g/2)RE^t],\

ay = -(2/3) * (RE^(3/2) + (3√g/2)RE^t)^(-4/3) * [(3√g/2)RE^t * ln(RE) + (3√g/2)RE^t]^2 + (2/3) * (RE^(3/2) + (3√g/2)RE^t)^(-1/3) * [(3√g/2)RE^t * ln(RE) + (3√g/2)RE^t * (3√g/2)RE^t * ln(RE) + (3√g/2)RE^t * ln(RE) + (3√g/2)RE^t].

Note that the expressions for Vy and ay are in terms of t. To evaluate them when y = 4RE, we need to find the corresponding value of t using the expression for y(t).

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The Sirius star in the constellation Canis Major will set in the middle of March at a time approximately one hour earlier compared to the middle of February.

The time at which a star sets in the sky gradually shifts earlier each night due to the Earth's orbit around the Sun. This phenomenon is known as sidereal time. In the middle of February, at 2 am, Sirius would be setting. As we move towards the middle of March, the Earth's orbital motion causes the constellations to appear to shift slightly earlier each night. Consequently, Sirius would set at around 1 am in the middle of March, around one hour earlier than in February. It is important to note that the exact time may vary based on the observer's location and specific year, but the general trend remains the same.

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Answer:

Explanation:

time =d/s

therefore, t =8.5/2.8

t=3.02s

Answer:

Oh god

i have nooooo idea

Five activities that will see the application of relation between pressure and area include:

When the handle of a pump is squeezed, the pressure inside the tire increases, causing the tire to inflate. By adjusting the size of the opening in the showerhead, the water pressure can be increased or decreased.

When a car is placed on a hydraulic lift, the pressure in the lift's cylinder is increased, causing the lift to raise the car off the ground. When a hydraulic jack is used to lift a heavy object, the pressure in the jack's cylinder is increased, causing the jack to lift the object.

A blood pressure cuff uses pressure to measure the blood pressure in a person's artery. The pressure in the cuff is increased until it is high enough to stop the flow of blood, and then the pressure is slowly released. The pressure readings at various points during this process can be used to determine a person's blood pressure.

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The work function of potassium is approximately 3.564 x 10^-19 J.  The threshold (cutoff) wavelength for potassium is 5.33 x 10^-7 m. The frequency corresponding to the cutoff wavelength is 5.63 x 10^14 Hz.

(a) To find the work function of potassium, we need to calculate the energy of a photon with the given wavelength and equate it to the maximum kinetic energy of the emitted electrons. The energy of a photon (E) is given by the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength. E = hc/λ = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (350 x 10^-9 m) = 5.66 x 10^-19 J
Since the maximum kinetic energy is given as 1.31 eV, we convert it to joules:
1.31 eV = 1.31 x 1.6 x 10^-19 J = 2.096 x 10^-19 J
Now, we can determine the work function:
Work function = Energy of a photon - Maximum kinetic energy = 5.66 x 10^-19 J - 2.096 x 10^-19 J = 3.564 x 10^-19 J
Therefore, the work function of potassium is approximately 3.564 x 10^-19 J.
(b) The threshold (cutoff) wavelength corresponds to the minimum wavelength of light required to emit electrons from the potassium surface. At this wavelength, the energy of the photon matches the work function.
E = hc/λ_cutoff = Work function
λ_cutoff = hc/Work function = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (3.564 x 10^-19 J) = 5.33 x 10^-7 m
Therefore, the threshold (cutoff) wavelength for potassium is approximately 5.33 x 10^-7 m.
(c) To find the frequency corresponding to the cutoff wavelength, we can use the equation:
f = c/λ_cutoff = (3 x 10^8 m/s) / (5.33 x 10^-7 m) = 5.63 x 10^14 Hz
Therefore, the frequency corresponding to the cutoff wavelength is approximately 5.63 x 10^14 Hz.

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The nuclear reaction becomes:

U₉₂²³⁸ → Th₉₀²³⁴+ α⁴₂

Thus, here (i) 234 and (ii) 90

Uranium-238 decays to thorium-234 via alpha decay. (The numbers after the chemical names indicate the number of protons and neutrons.) Uranium-238 loses two protons and two neutrons in this process, forming the isotope thorium-234.

Reactors based on thorium are safer since the reaction is simple to stop and does not need to be carried out under intense pressure. When compared to uranium reactors, thorium reactors produce significantly less waste, and the waste produced is far less radioactive and far shorter in duration.

Now, here (i) 234 and (ii) 90

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Answer:

(i) 234 and (ii) 90

.05 cm far must the lens be moved to change the focus of the camera from a person 25 m away to one that is 4.0 m away

The focal length of a thin lens in air is the separation between its major foci, also known as focal points, and its center. The focal length is the distance at which a beam of collimated light will be concentrated to a single spot for a converging lens (for instance, a convex lens).

If v is the image distance in the first scenario

1 / v - 1 / -25 = 1 / .05

1 / v = 1 / .05 - 1 / 25

= 20 - .04 = 19.96

v = .0501 m = 5.01 cm

The second instance

u = 4 ,

1 / v - 1 / - 4 = 1 / .05

1 / v = 20 - 1 / 4 = 19.75

v = .0506 = 5.06 cm

Therefore, the lens must be advanced by 5.06 - 5.01 =.05 cm.

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Answer: The given equation is balanced as  \(SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)\)

Explanation:

A chemical equation that contains same number of atoms on both reactant and product side are called balanced chemical equation.

For example, \(SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)\)

Here, number of atoms on reactant side are as follows.

Number of atoms on product side are as follows.

To balance this equation, multiply \(SO_{2}\) by 2 on reactant side and multiply \(SO_{3}\) also by 2 on product side.

Hence, the equation will be rewritten as follows.

\(2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)\)

Here, number of atoms on reactant side are as follows.

Number of atoms on product side are as follows.

As there are same number of atoms on both reactant and product side. So, this equation is a balanced equation.

Thus, we can conclude that the given equation is balanced as  \(SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)\)

Answer:

Options (3) and (6)

Explanation:

Janine drives 2.2 km East.

Since, distances measured in the East are positive,

Displacement = 2.2 km

Then she drives 4.4 km west

Displacement = -4.4 km

Followed by 1.7 km in the East

Displacement = 1.7 km

Total displacement = 2.2 - 4.4 + 1.7 = -0.5 km

\(\overrightarrow{d}=-0.5\) km

Total distance covered by Janine = 2.2 + 4.4 + 1.7 = 8.3 km

d = 8.3 km

Therefore, Options (3) and (6) will be the answer.

Answer:

solid

Explanation:

In a solid, particles are packed tightly together so they don't move much. The electrons of each atom are constantly in motion, so the atoms have a small vibration, but they are fixed in their position. Because of this, particles in a solid have very low kinetic energy.

The distance of the motorboat relative to the home, which travels in various directions, is 3.07 km.

Relative velocity is a velocity of an object which is in respect to another observer, or it is a ratio of change in the position of a point to time with respect to another observer.

Given: Travel in East direction (\(d_{E}\))= 5 km,

velocity in N35E(v) = 2 m / s, time taken(t)  = 90 min = 5400 seconds,
Displacement in south (\(D_S}\)) = 6.5 km

Firstly, find the displacement  in N35E so

Displacement   = Velocity × time,

\(d_{NE}\) = 2 × 5400 = 10800 meters or 10.8 km

Now by using Pythagoras' theorem
We can calculate the return displacement in the south direction(\(d_{S}\)),

\(d_{S}\) = \(\sqrt{d^{2} _{NE}- d^{2} _{E } }\)
\(d_{S}\) = \(\sqrt{10.8^{2}-5^{2} }\)

\(d_{S}\) = 9.57 km

Therefore, the distance of the boat from the home (D) = \(d_S}\) - \(D_S}\)

D = 9.57 - 6.5;

D = 3.07 Km

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Answer:

In an inductive circuit, when frequency increases, the circuit current decreases and vice versa.

Explanation:

Answer:

Gravitational force can be seen as the pull that the earth has on an piece of matter. Everything on earth has a force acting on it which is gravity. It tries to pull two object closer to each other but never apart. The numerical value for gravitational force is 9.8 m/s^2 for free falling objects

When pulled, springs apply a restoring force, according to Newton's Third Law of Motion. Hooke's Law governs the relationship between the spring force, spring constant, and spring displacement.

Rubber band stretched  x = F/k = 12.74 / 20 =0.64 m

The weight of the airplane hanging from the rubber band is given by the product between its mass (1.3 kg) and the acceleration due to gravity (g=9.8 m/s^2):

W = mg = 1.3* 9.8 = 12.74 N

This is the force that stretches the rubber band, according to Hooke's law:

F= kx

where

k = 20 N/m is the spring constant

x is the stretching of the spring with respect to its equilibrium position

Substituting F = 12.74 N and re-arranging the formula, we get:

x = F/k = 12.74 / 20 =0.64 m

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Answer:

c: will expand and demonstrate the Charles's law

Answer:

The correct option is;

D. There is not enough information to answer this question

Explanation:

The universal gravitational constant = 6.67408 × 10⁻¹¹ 3³/(kg·s²)

For an in between distance of 1 m and equal masses of 60 kg, we have;

\(F = G \times \dfrac{m_{1} \times m_{2}}{r^{2}} = 6.67408 \times 10^{-11} \times \dfrac{60 \times 60}{1^{2}} \approx 2.403 \times 10^{-7} N\)

The gravitational attraction ≈ 2.403 × 10⁻⁷ N, which does not correspond with the answers, therefore, the best option is that there is not enough information to answer this question.

The statement "scientific thinking developed only in the past few decades" is  false because Scientific thinking has its roots in ancient civilizations such as the Greek, Egyptian, and Chinese, which date back thousands of years. It has evolved and refined over time but is not limited to just the past few decades.

Scientific thinking did not originate solely in the past few decades. Instead, it has evolved and developed over centuries. For a long time, the systematic and evidence-based approach to comprehending the natural world, including making observations, formulating hypotheses, conducting experiments, and analyzing data, has been integral to scientific thinking. The scientific method, which serves as the basis for scientific thinking, has been employed for many centuries to advance knowledge across various fields of study. Although scientific thinking continues to progress and benefit from new discoveries and advancements, it is not a recent occurrence confined to the past few decades.Therefore ,option B is correct.

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The volume of the balloon is increased to 2.9 L.

Initial volume of the balloon, V₁ = 0.5 L

Initial temperature of the balloon, T₁ = 20°C = 293 K

Final temperature, T₂ = 150°C = 423 K

According to Charle's law,

V₁/T₁ = V₂/T₂

The final volume,

V₂ = (V₁/T₁)T₂

V₂ = 0.5 x 423/293

V₂ = 2.9 L

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Your question was incomplete, but most probably your question will be:

A balloon has a volume of 0.5 L at 20°C. If the balloon is heated to 150°C, assuming the atmospheric pressure to be constant at 101,325 pa, by what amount does the volume of the balloon change?

Answer:

In order to answer this correctly I will need the answers to the question

Explanation:

I can then work it out and give you the best answer I can give you

The situation in which the object with greater kinetic energy can be identified is when the wildlife keeper and the rabbit are both in motion, and their velocities and masses are known. The object with greater kinetic energy would be the one with a higher mass and/or a higher velocity.

Kinetic energy is given by the equation KE = (1/2)mv^2, where m is the mass and v is the velocity of an object. In this scenario, if both the wildlife keeper and the rabbit are in motion, and their masses and velocities are known, we can calculate their respective kinetic energies using the equation. The object with the greater kinetic energy will have a larger product of mass and velocity, indicating higher energy of motion. Therefore, by comparing the calculated values, we can identify the object with greater kinetic energy.

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Answer:

A. Generator

Explanation:

Hope this will help

Answer:

A. Generator

Explanation:

That is the correct answer