The 99% confidence interval for the difference in approximately (-0.409123, -0.095277).
Calculating the 99% confidence intervalTo obtain the confidence interval for the difference in the proportions, we use the formula:
Confidence Interval = (p₁ - p₂) ± Z × √((p₁ × (1 - p₁) / n₁) + (p₂ × (1 - p₂) / n₂))
Where:
p₁ and p₂ are the proportionsn₁ and n₂ are the sample sizes of the city and rural areas respectively.Z = Z-score level (99% confidence level means Z = 2.576).Given the parameters:
p₁ = 73 / 201 = 0.3632
p₂ = 56 / 91 = 0.6154
n₁ = 201
n₂ = 91
Z = 2.576
Plugging in the values:
Confidence Interval = (0.3632 - 0.6154) ± 2.576 × √((0.3632 × (1 - 0.3632) / 201) + (0.6154 × (1 - 0.6154) / 91))
Confidence Interval = -0.2522 ± 2.576 × √((0.3632 × 0.6368 / 201) + (0.6154 × 0.3846 / 91))
Confidence Interval = -0.2522 ± 2.576 × √(0.003712)
Confidence Interval = -0.2522 ± 2.576 × 0.060851
Confidence Interval = -0.2522 ± 0.156923
Confidence Interval = (-0.409123, -0.095277)
Therefore, the 99% confidence interval is approximately (-0.409123, -0.095277).
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5. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach - 350 m.
It will take the elevator 60 minutes, or 1 hour, to reach a depth of -350 m.
To calculate the time it will take for the elevator to reach -350 m, we need to use the following formula:
Time = Distance ÷ Rate
In this case, the distance is the difference between the starting point (10 m) and the final destination (-350 m), which is:
Distance = -350 m - 10 m = -360 m
Since the elevator is descending, the rate is negative (-6 m/min). Substituting these values into the formula, we get:
Time = (-360 m) ÷ (-6 m/min) = 60 min
Therefore, it will take the elevator 60 minutes, or 1 hour, to reach a depth of -350 m.
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Write each expression as a single power of 10
Answer:
a) 10²
b) 10 ⁻³
c) 10⁸
d) 10⁻⁶
Step-by-step explanation:
a) (10³ * 10⁴) ÷ 10⁵ = 10⁷ ÷ 10⁵ = 10²
b) (10⁴ * 10⁵ * 10⁶) ÷ (10⁸ * 10⁹) = 10¹⁵ ÷ 10¹⁸ = 10 ⁻³
c) (10⁵ ÷ 10³)⁴ = (10²)⁴ = 10⁸
d) (10⁵)² ÷ (10²)⁸ = 10¹⁰ ÷ 10¹⁶ = 10⁻⁶
HELP PLEASE I NEED IT ASAP IT WILL MEAN A LOT TO ME!! PLEASE
Find all values of x that solves this system.
x^2 - 9y^2 = 72
x + 3y = 9
Please dont make cap i rlly need help i was stuck on this!
Answer:
1: \(x=3\sqrt{8+y^{2} }\) and the same, but its -3 instead of 3
2: x=9-3y
Answer:
2 one x=9−3y
1 one I don't know
Erie Company manufactures a mobile fitness device called the Jogging Mate. The company uses standards to control its costs. The labor standards that have been set for one Jogging Mate are as follows:
Standard
Hours Standard Rate
per Hour Standard
Cost
18 minutes $17.00 $5.10
During August, 5,750 hours of direct labor time were needed to make 20,000 units of the Jogging Mate. The direct labor cost totaled $102,350 for the month.
Required:
1. What is the standard labor-hours allowed (SH) to makes 20,000 Jogging Mates?
2. What is the standard labor cost allowed (SH × SR) to make 20,000 Jogging Mates?
3. What is the labor spending variance?
4. What is the labor rate variance and the labor efficiency variance?
5. The budgeted variable manufacturing overhead rate is $4 per direct labor-hour. During August, the company incurred $21,850 in variable manufacturing overhead cost. Compute the variable overhead rate and efficiency variances for the month.
(1) Standard hours allowed for actual output are 6000 Hours.
(2) Standard labor cost allowed is 102,000.
(3) Labor spending variance is $350 unfav.
(4) The labor rate variance is $4600 unfav.
(5) Variable rate is $1150 Fav and efficiency variance is $1000 Fav.
What is labor spending variance?
The labor rate variance, sometimes referred to as the spending variation for direct labor, is calculated by multiplying the number of hours worked by the difference between the actual and standard labor rates per hour.
Given: Erie Company manufactures a mobile fitness device called the Jogging Mate.
The company uses standards to control its costs.
During August, 5,750 hours of direct labor time were needed to make 20,000 units of the Jogging Mate.
The direct labor cost totaled $102,350 for the month.
(1) Standard hours allowed per unit: 18 min
Actual output: 20000 units
Standard hours allowed for actual output (20000(18/60)): 6000 Hours
(2) Standard labor hours allowed: 6000 hours
Standard rate per hour: $ 17
Standard labor cost allowed: (6000 hours at 17): 102,000
(3) Labor Spending Variance: (Standard hours*Standard rate) - (Actual hours*Actual rate)
6000 *17 - 102350 = $ 350 Unfav
(4) Actual labor rate per hour (102350/5750): $ 17.80 per hour
Labor Rate variance: Actual hours (Standard rate-Actual rate) 5750 hours (17.00-17.80)= $ 4600 Unfav
(5) Standard Variable rate per hour: $ 4 per hour
Actual rate per hour (21850/5750): $ 3.80 per hour
Variable rate variance: Actual hours (Standard OH rate-Actual OH rate)
5750 (4.00-3.80)= $ 1150 Fav
Variable OH efficiency variance: Standard rate (Standard hours-Actual hours)
4.00 (6000-5750)= $ 1000 Fav
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The length of a car is \(\sqrt{163}\) ft. Will this car fit in a garage that measures 10 ft long? If not, what is the minimum length of a garage long enough for this car?
Step-by-step explanation:
example:
{163} you dont enough the texGiven the exponential equation, y = 100(1/5)x, circle the letter that accurately describes the table of values:
A. Increasing by a multiplication of 5. B. Increasing by an addition of 5.
C. Decreasing by a division of 5. D. Decreasing by a subtraction of 5.
Answer:
the answer is D.
Step-by-step explanation:
8.18. let s,t be sets. prove that s = t if and only if s\ t = t \ s.
If S, T be sets, then we have proved that S = T if and only if S \ T = T \ S.
Assume S = T. Then, S \ T = T \ S = {}.
This is because if S = T, then there are no elements in S that are not in T, and vice versa.
Therefore, the difference between the sets is the empty set.
Hence, S \ T = T \ S = {} and we have shown that S = T implies S \ T = T \ S.
Assume S \ T = T \ S.
We will show that S is a subset of T and T is a subset of S, which will imply that S = T.
Let x be an arbitrary element of S.
If x is also in T, then x is not in S \ T = T \ S, which contradicts the assumption S \ T = T \ S.
Therefore, x is not in T.
This means that x is in S \ T, which implies that x is also in T \ S (by the assumption S \ T = T \ S).
But this means that x is in T, which is a contradiction.
Therefore, there are no elements in S that are not in T, so S is a subset of T.
Similarly, let y be an arbitrary element of T.
If y is also in S, then y is not in T \ S = S \ T, which contradicts the assumption S \ T = T \ S.
Therefore, y is not in S.
This means that y is in T \ S, which implies that y is also in S \ T (by the assumption S \ T = T \ S).
But this means that y is in S, which is a contradiction.
Therefore, there are no elements in T that are not in S, so T is a subset of S.
Since S is a subset of T and T is a subset of S, S = T.
Therefore, we have shown that S \ T = T \ S implies S = T.
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The given question is incomplete, the complete question is:
let S, T be sets. prove that S = T if and only if S \ T = T \ S.
what are the conditions for using the normal approximation for a sampling distribution of proportions g
The normal approximation for sampling distributions of proportions can be used when the sample size is large enough.
What prerequisites must be met for a sampling distribution of proportions g in order to use the normal approximation?The conditions for using the normal approximation for a sampling distribution of proportions are as follows: The sample size (n) must be sufficiently large (usually 30 or more). The sample proportion (p) should not be close to 0 or 1. The population distribution should be normally distributed.The general rule is that if the sample size (n) is greater than or equal to 30, then the normal approximation can be used. When using the normal approximation for a sampling distribution of proportions, the sample size must be greater than or equal to 30 and the population proportion (p) must be between 5% and 95%. Furthermore, the sample size must be large enough that the expected number of successes (np) and expected number of failures (nq) are both greater than or equal to 10. Finally, the sampling distribution should be approximately normal and the sample should be randomly selected from the population. The normal approximation is a useful tool for estimating confidence intervals and the probability of extreme values, as well as for hypothesis testing. It can be used to estimate the probability of success in a given sample of proportions, which can be helpful when making decisions about a population or understanding the behavior of a system.To learn more about distribution of proportions refer to:
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wilma drove at an average speed of 55 55 mi/h from her home in city a to visit her sister in city b. she stayed in city b 20 20 hours, and on the trip back averaged 60 60 mi/h. she returned home 50 50 hours after leaving. how many miles is city a from city b
The distance between City A and City B is 519.75 miles.
Let d be the distance from City A to City B.
\(t_{AB} = \frac{d}{55}\)
where \(t_{AB}\) is the time taken from City A to City B. And
\(t_{BA} = \frac{d}{45}\)
\(\therefore \frac{d}{55} + \frac{d}{45} = 41-20\)
\(\implies 45d+55d = 21\times 45 \times 55\)
\(\implies 100d = 51975\)
\(\therefore d = 519.75 \text{ miles}\)
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ΔABC is similar to ΔDEF. m∠BAC = (x² - 5x)º, m∠BCA = (4x - 5)º and
m∠EDF = (4x + 36)º. Find m∠F.
please show your work.
Thus, m∠F = 33º for the corresponding angle measures for each similar triangle ΔABC and ΔDEF.
To start, we know that similar triangles have corresponding angles that are congruent. Therefore, we can set up the following proportion:
m∠BAC/m∠EDF = m∠BCA/m∠DFE
Substituting the given angle measures, we get:
(x² - 5x)/(4x + 36) = (4x - 5)/m∠F
To solve for m∠F, we need to isolate it on one side of the equation. First, we can cross-multiply to get:
(4x - 5)(4x + 36) = (x² - 5x)m∠F
Expanding the left side, we get:
16x² + 116x - 180 = (x² - 5x)m∠F
Next, we can divide both sides by (x² - 5x):
(16x² + 116x - 180)/(x² - 5x) = m∠F
Simplifying the left side, we get:
(4x + 29)/(x - 5) = m∠F
Therefore, m∠F = (4x + 29)/(x - 5).
To check our answer, we can plug in a value for x and find the corresponding angle measures for each triangle. For example, if x = 6:
m∠BAC = (6² - 5(6))º = 16º
m∠BCA = (4(6) - 5)º = 19º
m∠EDF = (4(6) + 36)º = 60º
Using our formula for m∠F, we get:
m∠F = (4(6) + 29)/(6 - 5) = 33º
We can see that this satisfies the proportion and therefore our answer is correct.
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Which answer choice correctly identifies the extraneous information in the problem?
Samuel is 10 years old. He mowed the neighbors lawn on Saturday and earned $40. It took him 4 hours to mow the lawn and 2 hours to clean his room. How much money did Samuel earn an hour?
A. The extraneous information is Samuel earned $40 and it took him 4 hours to mow the lawn.
B. The extraneous information is Samuel took 4 hours to mow the lawn and 2 hours to clean his room.
C. The extraneous information is Samuel is 10 years old and earned $40.
D. The extraneous information is Samuel is 10 years old.
Option D is correct.
Extraneous information means irrelevant or unrelated to the problem or issue.
In this question, Samuel's Age is not a matter of concern and totally unrelated to the money he earns by mowing the lawn and cleaning the room
evaluate the triple integral given π:0≤x≤2,0≤y≤3,0≤z≤3. ∫∫∫x2y2z2dxdydz
The triple integral of x²y²z² over the given limits is evaluated by integrating with respect to x, y, and z is -243.
Firstly, we integrate x² from π to 0, which gives -8/3. Then, we integrate y² from 0 to 3, which gives 27/3. Finally, we integrate z² from 0 to 3, which gives 27/3. Multiplying all the values together, we get the final answer of -243. Therefore, the value of the given triple integral is -243.
In order to evaluate a triple integral, we must integrate the given function over three variables with respect to their limits of integration. In this case, we are integrating x²y²z² over the limits 0≤x≤2, 0≤y≤3, and 0≤z≤3. We start by integrating with respect to x, then y, and finally z, using the limits given.
Each integral gives us a value which is then multiplied together to get the final answer. It is important to follow the order of integration correctly, and to keep track of the limits for each variable. In this way, we can evaluate the triple integral and find the value of the given function over the given region of integration.
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A fair coin is flipped 5 times
What is the probability that no two consecutive flips have the same result?
Express ur answer as a common fraction
HELP ME!!
Answer:
2/5
Step-by-step explanation:
The answer is common sense.
The probability that no two consecutive flips have the same result is \(\frac{1}{16}\).
If a coin is flipped then there are two possible outcomes Head(H) and Tail (T).
So each flip can have 2 possible outcomes. It means 5 flips have \(2^5=32\) possible outcomes.
Among these 32 outcomes only 2 outcomes : HTHTH and THTHT have "no two consecutive flips have the same result".
So the probability that no two consecutive flips have the same result is = \(\frac{2}{32} =\frac{1}{16}\).
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a binding less than or equal to (≤) constraint in a maximization problem meansa. the variable is up against an upper limit. b. the minimum requirement for the constraint has just been met. c. another constraint is limiting the solution. d. the shadow price for the constraint will be positive.
The variable is up against an upper limit. in a maximization problem, a binding less than or equal to (≤)
constraint indicates that the variable associated with the constraint has reached or is at its upper limit. It implies that the variable cannot increase further without violating the constraint.
This constraint acts as a restriction that limits the potential values the variable can take in the optimization problem.
When a constraint is binding, it means that the optimal solution to the problem is achieved when the constraint is satisfied with equality. In the context of a maximization problem,
if a variable is up against an upper limit and the constraint is binding, it suggests that the variable is already maximizing its value within the given constraint.
In contrast, if the constraint is not binding, it means that the variable has not reached its upper limit and has the potential to increase further while still satisfying the constraint. In such cases, the variable can be increased to improve the objective function value and optimize the problem further.
It's important to note that the shadow price, also known as the dual value or marginal value, represents the rate of change of the objective function with respect to a constraint. It indicates the sensitivity of the objective function to changes in the constraint.
The sign of the shadow price is not determined by the direction of the constraint (≤ or ≥), but rather by the problem formulation and the specific constraints and variables involved.
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can someone explain how this is done?
Answer:
Just put in the values in the equation for example 4(1)-5<7 and solve it if the eqution is true at the end than that the right answer
Step-by-step explanation:
Answer:
x = 2
x < 2
x < 3
Step-by-step explanation:
2x + 5 = 9
Since there is an addition sign in front of 5, you must do the opposite: subtraction. Subtract 5 from 9.
9 - 5 = 4.
Lastly, divide the difference by the number in front of x (2).
2x = 4
4 ÷ 2 = 2
x = 2
--------------------------------------------------------------------------------------------------------------
2x + 5 < 9
Again, subtract 5 from 9.
9 - 5 = 4
Lastly, divide the difference by the number in front of the x (2).
2x = 4
4 ÷ 2 = 2
x < 2
--------------------------------------------------------------------------------------------------------------
4x - 5 < 7
Since there is a subtraction sign in front of the 5, you must do the opposite: addition. Add 5 to 7.
5 + 7 = 12
Lastly, divide the sum by the number in front of the x (4).
4x = 12.
12 ÷ 4 = 3
x < 3
The radius of the base of a cone is 16 m. Its slant height is 28 m. What is the surface area in
terms of pi?
Answer:
704π m^2
Step-by-step explanation:
Given data
radius r= 16m
Slant height l= 28m
Required
The surface area of the cone
The expression for the surface area is given as
T.S.A=πrl+πr^2
substitute
T.S.A=π*16*28+π*16^2
T.S.A=448π+256π
T.S.A=704π m^2
Hence the T.S.A is 704π m^2
if the value of x is 3 and the value of y is 5, what is displayed as a result of executing the code segment?
The result of executing the code segment is -2
How to determine the result of executing the code segment?The complete question is added at the end of this solution as an attachment
The code in the question is given as
IF X > Y
DISPLAY X + Y
ELSE
DISPLAY X - Y
Given that
X = 3 and Y = 5
When x and y are compared, we have the truth value to be
Y > X
This means that the executed segment is
DISPLAY X - Y
So, we have
DISPLAY 3 - 5
Evaluate
DISPLAY -2
Hence. the displayed result is -2
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What is the missing reason in the following proof?
Given: BC=AD, AB=DC
Prove: BE=ED
Answer:
bc=ad
Step-by-step explanation:
2log 2+ 3log x - 1/2 [log(x+3)+log(x+2)]
The given logarithmic expression 2log 2+ 3log x - 1/2 [log(x+3)+log(x+2)] can be written as single logarithm as log [(2^2)(x^3)/(x+3)^1/2 (x+2)^1/2] .
A single logarithm by virtue of the laws of logarithms as follows;
= 2log 2+ 3log x - 1/2 [log(x+3)+log(x+2)]
= log(2)^2 + log x^3 - log(x+3)^1/2 + log(x+2)^1/2
= log [(2^2)(x^3)/(x+3)^1/2 (x+2)^1/2]
Therefore, the single logarithm is log [(2^2)(x^3)/(x+3)^1/2 (x+2)^1/2].
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The complete question is
'Rewrite the following expression as a single logarithm: 2log 2+ 3log x - 1/2 [log(x+3)+log(x+2)].'
Which values of x and y would make the following expression represent a real number? (4 5i)(x yi) x = 4, y = 5 x = –4, y = 0 x = 4, y = –5 x = 0, y = 5
The product will be a real number when x = 4 and y = -5.
Which values of x and y should we use?We have the product of complex numbers:
\((4 + 5i)*(x + yi)\)
We want this to be a real number, then the second complex number must be the complex conjugate of the first one, so we must have:
\((x + yi) = (4 - 5i)\)
Now, if we take the product, we get:
\((4 + 5i)*(4 - 5i)\\\\4*4 - 4*5i + 4*5i - (5*5)*i^2 = 16 + 25 = 41\)
So we can see that the outcome is a real number.
Then we must have x = 4 and y = -5.
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Answer: C
Step-by-step explanation:
What number is 115% of 106? (Show your work)
Answer:
121.9
Step-by-step explanation:
1% of 106 = 1.06
1.06 x 15 = 15.9
106 + 15.9 = 121.9
The bottom of a cylinder has a circumference of about 60 in. What is the approximate diameter of the cylinder? Round to the nearest tenth. Use 3.14 for π . Enter your answer in the box.
Answer:
19.1 inches
Step-by-step explanation:
Circumference divide by diameter = 3.14 (C/d = 3.14)
60/d = 3.14
multiply both sides of the equation by d
60 = 3.14d
divide both sides by 3.14
d = 60/3.14
d = 19.108
d = 19.1
the right hand side value for the starting node in a shortest path problem has a value of
In a shortest path problem, the right-hand side (RHS) value for the starting node has a value of 0. This indicates that the shortest path from the starting node to itself has a cost of 0.
In summary, the RHS value for the starting node in a shortest path problem is 0, indicating that the shortest path from the starting node to itself has a cost of 0.
The RHS value is used in the context of the Dijkstra's algorithm, which is commonly used to solve shortest path problems. In this algorithm, a priority queue is used to store the nodes that have not yet been visited, sorted based on their tentative distances from the starting node. Initially, the starting node is assigned a tentative distance of 0, indicating that it is the source node for the shortest path. The RHS value is used to update the tentative distance of a node when a shorter path is discovered. When a node is added to the priority queue, its tentative distance is compared to its RHS value, and the smaller of the two values is used as the node's priority in the queue. By setting the RHS value of the starting node to 0, we ensure that the starting node always has the highest priority in the queue and is processed first by the algorithm.
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how do u do thissss??
reflect this shape in the line y=x :)
Answer:
the x-coordinate and y-coordinate change places.
Step-by-step explanation: so you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).
The mean of the values in a data set is r. If each of the values in the data set were multiplied by 13.5, what would be the mean of the resulting data? O A 13.5/ O B. C. 15.5r D. 11.5
Answer:
C.15.5r
Step-by-step explanation:
Answer:
13.5r
Step-by-step explanation:
Just took it
Simplify 1.5m7(-4m5)2
Answer:
-6m^14
Step-by-step explanation:
Answer:
It's 24m^17
Step-by-step explanation:
I got it right on my test
Can somebody help me with this. Will Mark brainliest.
Answer:
2) 10.1
Step-by-step explanation:
Detergent A contains 48 fluid ounces and cleans 16 loads of dishes. Detergent B contains 76 fluid ounces and cleans 38 loads of dishes. Which comparison of the detergents is accurate?
Detergent A uses exactly 1 fluid ounce per load more than detergent B.
Detergent A uses exactly 1 fluid ounce per load less than detergent B.
Detergent A uses less than 1 fluid ounce per load more than detergent B.
Detergent A uses less than 1 fluid ounce per load less than detergent B.
Answer:
Detergent A uses exactly 1 fluid ounce per load more than detergent B.
Step-by-step explanation:
We are given that Detergent A contains 48 fluid ounces and cleans 16 loads of dishes. Detergent B contains 76 fluid ounces and cleans 38 loads of dishes.
We have to compare that which detergent is accurate.
As we know that the formula for finding fluid ounce per load is given by;
Fluid ounce per load = \(\frac{\text{Amount of fluid ounces}}{\text{Amount of loads}}\)
For detergent A;Fluid ounces = 48
Loads of dishes = 16
So, fluid ounce per load = \(\frac{48}{16}\)
= 3 fluid ounce per load
For detergent B;
Fluid ounces = 76
Loads of dishes = 38
So, fluid ounce per load = \(\frac{76}{38}\)
= 2 fluid ounce per load
So, we can clearly see that Detergent A uses exactly 1 fluid ounce per load more than detergent B, ie. (3 - 2) = 1 fluid ounce per load.
You have collected 20 samples of 100 items each. The total number of defective items is 75. Determine the upper control limit (UCL) at a 99% confidence interval (z value =3 ). Answer A. 0.7935 B. 0.0945 C. 0.165 D. 0.0375
The upper control limit (UCL) at a 99% confidence interval with a z value of 3 is 0.165.(option c)
In statistical process control, the UCL is a key parameter used to determine the upper boundary for acceptable variation in a process. To calculate the UCL for a defect rate, we use the formula UCL = p' + z * sqrt(p'(1-p')/n), where p' is the proportion of defects in the sample, z is the z value corresponding to the desired confidence level, and n is the sample size.
In this case, we have collected 20 samples of 100 items each, and the total number of defective items is 75. Therefore, the proportion of defects in the sample is 75/2000 = 0.0375. Using the formula mentioned earlier, with a z value of 3 and n value of 100, we can calculate the UCL as follows: UCL = 0.0375 + 3 * sqrt(0.0375 * (1-0.0375)/100) ≈ 0.165.
Therefore, the correct answer is C. 0.165.
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if the day after tomorrow is two days before thursday then what day is it today? friday monday wednesday saturday tuesday sunday
Today is Saturday, because tomorrow will be Sunday and the day after will be Monday two days after will be the day before Thursday, Wednesday
We have,
The day after tomorrow is two days before Thursday.
Since, tomorrow will be Sunday and the day after will be Monday two days after will be the day before Thursday, Wednesday.
Hence, Today is Saturday.
Therefore, Today is Saturday, because tomorrow will be Sunday and the day after will be Monday two days after will be the day before Thursday, Wednesday.
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