Answers
The man is pulled upward by a net force of
∑ F = (86 kg) (1.35 m/s²) = 116.1 N
The net force is comprised of the tension T in the cable and the man's weight W, such that
∑ F = T - W = 116.1 N
T = (86 kg) (9.80 m/s²) + 116.1 N
T = 958.9 N ≈ 960 N
Related Questions
The weight of an object on the surface of mass is 1850 Newton and its mass is 500kg.Find the acceleration due to gravity on mars
Answers
F = m.a
a = F/m
a = 1850/500
a = 3.7 m/s²
By what percent is the torque of a motor decreased if its permanent magnets lose 6.5 % of their strength
Answers
How can you determine the number of neutrons in an atom?
A. Mass number plus number of electrons
B. Atomic number minus mass number
C. Mass number minus atomic number
D. Atomic number plus mass number
Answers
Answer:
B. Atomic number minus mass number
Explanation:
Two point charges are separated by 12cm what is the force between them
Answers
Answer:
Coulomb's law calculates the magnitude of the force F between two point charges, q1 and q2, separated by a distance r. F=k|q1q2|r2.
Explanation:
a point object is 10 cm away from a plane mirror while the eye of an observer(pupil diameter is 5.0 mm) is 28 cm a way assuming both eye and the point to be on the same line perpendicular to the surface find the area of the mirror used in observing the reflection of the point
Answers
Answer:
1.37 mm²
Explanation:
From the image attached below:
Let's take a look at the two rays r and r' hitting the same mirror from two different positions.
Let x be the distance between these rays.
\(d_o =\) distance between object as well as the mirror
\(d_{eye}\) = distance between mirror as well as the eye
Thus, the formula for determining the distance between these rays can be expressed as:
\(x = 2d_o tan \theta\)
where; the distance between the eye of the observer and the image is:
\(s = d_o + d_{eye}\)
Then, the tangent of the angle θ is:
\(tan \theta = \dfrac{R}{d_o+d_{eye}}\)
replacing \(tan \theta = \dfrac{R}{d_o+d_{eye}}\) into \(x = 2d_o tan \theta\), we have:
\(x = 2d_o \Big( \dfrac{R}{d_o+d_{eye}}\Big)\)
\(x = 2(10) \Big( \dfrac{0.25}{10+28}\Big)\)
\(x = 20\Big( \dfrac{0.25}{38}\Big) cm\)
x = (0.13157 × 10) mm
x = 1.32 mm
Finally, the area A = π r²
\(A = \pi(\frac{x}{2})^2\)
\(A = \pi(\frac{1.32}{2})^2\)
A = 1.37 mm²
Two very large parallel metal plates, separated by 0.20 m, have a potential difference of 12V. An electron is released from rest at a location a distance d from the negative plate.
(a) Describe the motion of the electron after its release in as much detail as possible.
(b) At what distance from the positive plate, will the electron have a speed of 1 x 10^6 m/s?
Answers
Given that two large parallel plates are separated by 0.20 m and that the potential difference is 12V.
(a) Describe the motion of an electron released from rest at a distance "d" from the negative plate.
(b) What distance from the positive plate will the electron have a speed of 1 x 10^6 m/s?
For part (a):
The magnitude of an electric field can be given as \(||\vec E||=\frac{\Delta V}{d}\), where "ΔV" is the potential difference and "d" is the distance between the plates.
So, \(||\vec E||=\frac{12 \ V}{0.20 \ m} \Longrightarrow \boxed{||\vec E||=60 \ \frac{N}{C} }\)
An electric field is created between the plates pointing from positive towards negative. We know that negative charges accelerate opposite the direction of electrical fields. So the electron placed "d" meters away from the negative plate will accelerate towards the positive plate at a constant rate.
For part (b):
We know that...
- the charge of an electron is \(\bold{-1.602 \times10^{-19} \ C}\).
- the mass of an electron is \(\bold{9.11 \times10^{-31} \ kg}\).
- \(\vec F_e=q\vec E\)
- \(\vec F =m\vec a\)
\(\Longrightarrow \vec F_e=(-1.602 \times10^{-19} \ C)(60 \ \frac{N}{C} }) \Longrightarrow \boxed{\vec F_e= -9.612 \times10^{-18} \ N}\)
\(\Longrightarrow \vec F =m\vec a \Longrightarrow \vec a=\frac{\vec F}{m} \Longrightarrow \vec a=\frac{-9.612 \times10^{-18}}{9.11 \times10^{-31} \ kg} \Longrightarrow \boxed{\vec a=-1.06 \times10^{13} \ m/s^2}\)
Kinematic Equation: \(\vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x\)
\(\Longrightarrow 1 \times10^{12} \ m^2/s^2=-2.11 \times10^{13} \ m/s^2 \Delta \vec x \Longrightarrow \Delta \vec x= \frac{1 \times10^{12} \ m^2/s^2}{-2.12 1\times10^{13} \ m/s^2}\)
\(\Longrightarrow \boxed{\Delta \vec x= -0.047 \ m}\)
The distance from the positive plate we'll call, "D."
\(D=0.20+\Delta \vec x\)
\(\Longrightarrow D=0.20+\Delta \vec x \Longrightarrow D=0.20 \ m+(-0.047 \ m) \Longrightarrow \boxed{D=0.153 \ m} \therefore Sol.\)
Question 2 of 10
What is the current in the 10.0 2 resistor?
10.00
w
120.0 V
20.00
w
30.00
A. 10.0 A
B. 12.0 A
C. 0.0833 A
O D. 2.00 A
Answers
Answer:
2.00 A
Explanation:
Total resistance = 10 + 20 + 30 = 60 ohms
Potential difference (V) = 120volts
Current (I) =?
from Ohms law V = IR
==> I = V/R = 120/60 = 2 A
Note: for resistors in series equal amount of electric current flows through the circuit
To win the game, a place kicker must kick a football from 30m from the goal, and the ball must clear the crossbar which is 3.05 m high. When kicked, the ball leaves the ground with the speed of 19 m/s at the angle of 37.2° from the horizontal. Acceleration of gravity is 9.8 m/s^2
How much vertical distance does the ball clear the crossbar?
Answers
Answer:
Explanation:
Ignore air resistance
The horizontal velocity is
vx =19cos37.2 = 15.134 m/s
The ball travels 30 m in a time of
30 / 15.134 = 1.982 s
In that time, the ball will be at an altitude of
s = vy₀t + ½at²
s = 19sin37.2(1.982) + ½(-9.8)1.982² = 3.5137... m
so the ball clears the bar by
h = 3.5137 - 3.05 = 0.4637... = 0.46 m
Brainliest for best answer
Using Hooke's law, what happens when the displacement is tripled?
A.
The restoring force is tripled.
B.
The restoring force is reduced by one third.
C.
The amplitude is reduced by one third.
D.
The spring constant is tripled.
Answers
According to Hook's law, the restoring force is tripled when the displacement is tripled. Hence, option A is correct.
What is Hook's law?Hook's law states that, the stress applied on the elastic material is proportional to the strain resulted. The strain of the material is the ratio of the change in length to the original length.
The force applied on the material is directly proportional to the displacement x.
F = -k x
where k is called the spring constant.
As the displacement increases spring constant decreases.
The restoring force is the opposing force to regain the actual size. Thus, as the displacement increases, the force required to bring it to the original position also increases. Thus, option A is correct.
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An object rotates with period of 10s.how many revolutions will it make in25s
Answers
Answer:
2¹/2
Explanation:
if the revolution is in 10 seconds the R,=Total time÷time of the revolution
Answer:
The object will make \(2\frac{1}{2}\) (2.5) revolutions in 25s.
This indicates that it will revolve through two full revolutions before rotating a third time in the opposite direction.
Explanation:
A rotational period of 10 seconds indicates that an object completes one full rotation every 10 seconds. The object's frequency is therefore 1/10 Hz, or 0.1 Hz. We must apply the calculation to determine how many revolutions it will complete in 25 seconds:
Number of revolutions = frequency x time passed
We are informed that 25 seconds have passed. Using the following formula, we can determine the frequency:
Frequency = 1 / period.
The frequency is because the period is 10 seconds:
Frequency equals 1/10, or 0.1 Hz.
Now we can calculate the number of revolutions using the formula above:
Number of revolutions = (25 s) x (0.1 Hz) = 2.5 revolutions
It takes 10 seconds for the first complete revolution, another 10 seconds for the second full revolution, and 5 seconds for the final half revolution.
In other words, the object starts at its starting location, rotates a whole anticlockwise revolution, another full anticlockwise revolution, and then eventually rotates a further half anticlockwise revolution before returning to its initial position. As a result, the item in this instance rotates in the opposite direction of clockwise.
As a result, in 25 seconds, the object will complete 2.5 revolutions.
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The social model was created by
Answers
2 An electric kettle is marked "230V, 1.5 kW.
a Explain what these numbers mean.
b Calculate the correct fuse that should be used.
c Explain why a 230V, 100 W bulb glows more brightly than a 230 V, 60 W
bulb when both are connected to the mains supply.
Answers
The power needed to boil the water is divided by the element's power output, and the result is multiplied by 100 to get the efficiency of the kettle as a percentage. The answer is 79 %.
To Find the efficiency of electric kettle ?We are informed that
Electric kettle power is 1 kW.
Electric kettle voltage is 230 V.
The time it takes the kettle to bring the water to boiling point is 7.5 minutes.
1 kg = mass of water.
Heat generated equals V x I x t + Pt.
generated heat = 1000 W x 7.5 x 60
Heat absorbed equals (100 - 15) x 1 x 4200 = 4200 x 85
Efficiency is determined by multiplying the heat produced by the heat absorbed by 100.
= 4.2 x 85 x 10^3 / 4.5 x 10^5 x 100
= 357 / 4.5 = 79 %
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
Answers
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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Which one these statements describes how to typically tell the difference
between a synthesis (S) reaction and a decomposition (D) reaction?
Tap to select or deselect answer.
An S reaction has one product and two or more reactants and a D reaction
has one reactant and two or more products.
An Sreaction has one reactant and two or more products and a D reaction
has one product and two or more Reactants.
An S reaction has oxygen as a reactant and a Dreaction has oxygen as a
product
An S reaction has oxygen as a product and a D reaction has oxygen as a
reactant
Answers
Answer: An S reaction has one product and two or more reactants and a D reaction has one reactant and two or more products.
Explanation:
In a synthesis reaction, two or more simple molecules or substances interact to form a more sophisticated product. (General equation: A + B → AB)
When one reactant decomposes into two or more products, this is known to as a decomposition reaction. (General equation: AB → A + B)
Two equal-mass stars maintain a constant distance
of 8.0 x 10^10 m and rotate about a point mid-
way between them at a rate of one revolution every
12.6 yr.
(a) Why don't the two stars crash into one
another due to the gravitational force between
them?
(b) What must be the mass of each star?
Answers
A. Centripetal force acting on the two stars is the reason why the two stars will not crash into one another
B. The mass of each stars, given they maintain a constant distance of 8×10¹⁰ m is 7.68×10²⁷ Kg
A. Why don't the two stars crash into one another?
Centripetal force is the force that acts to keep an object moving in a circle. Since the two stars undergoes revolution, this means they rotate in a circle. Thus, centripetal force is acting on them.
Therefore, we can say that the two stars will not crash into one another due to the centripetal force
B. How do I determine the mass of each stars?
We can obtain the mass of each stars as illustrated below:
F = GM₁M₂ / r²
Note: They rotate mid-way. Thus distance apart (r) = 2r
F = GM₁M₂ / (2r)²
F = GM₁M₂ / 4r²
Also, centripetal force is given as:
F = mv² / r
Thus, we have:
mv² / r = GM₁M₂ / 4r²
But
v = 2πr / T
v² = (2πr / T)² = 4π²r² / T²
M₁ = M₂ = m
Thus, we have
m4π²r² / rT² = Gmm / 4r²
4π²r / T² = Gm / 4r²
Cross multiply
mGT² = 4r² × 4π²r
mGT² = 16π²r³
Divide both sides by GT²
m = 16π²r³ / GT²
From the question given, we have:
Distance (r) = 8×10¹⁰ mPeriod (T) = 12.6 years = 12.6 × 3.154×10⁷ = 3.97×10⁸ sGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Pi (π) = 3.14Mass of each stars (m) =?m = 16π²r³ / GT²
m = [16 × 3.14² × (8×10¹⁰)³] / [6.67×10¯¹¹ × (3.97×10⁸)²]
m = 7.68×10²⁷ Kg
Thus, the mass of each stars is 7.68×10²⁷ Kg
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¿Cuál es el trabajo neto en J que se necesita para acelerar un auto de 1500 kg de 55 m/s a 65 m/s?
What is the net work in J required to accelerate a 1500 kg car from 55 m/s to 65 m/s?
Answers
The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J
How do i determine the net work done?First, we shall obtain the initial kinetic energy. Details below:
Mass (m) = 1500 Kginitial velocity (u) = 55 m/sInitial kinetic energy (KE₁) =?KE₁ = ½mu²
= ½ × 1500 × 55²
= 41250 J
Next, we shall final kinetic energy. Details below:
Mass (m) = 1500 KgFinal velocity (v) = 65 m/sFinal kinetic energy (KE₂) =?KE₂ = ½mv²
= ½ × 1500 × 65²
= 3168750 J
Finally, we shall determine the net work done. Details below:
Initial kinetic energy (KE₁) = 41250 JFinal kinetic energy (KE₂) = 3168750 JNet work done (W) =?W = KE₂ - KE₁
= 3168750 - 41250
= 3127500 J
Thus, the net work done is 3127500 J
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A learner pulls a box with a force of 500 N over a distance of 20 m. The an angle of 30° with the horizontal. The total mass of the box is 350 kg while the coefficient of friction between the box and the ground is 0,24. Draw a FORCE DIAGRAM indicating all forces acting on the box ?
Answers
Answer:
I can describe the forces acting on the box based on the information provided.
The force diagram for the box being pulled by the learner would include the following forces:
The force applied by the learner: This is a horizontal force of 500 N, which is directed at an angle of 30° with the horizontal.
The weight of the box: This is a vertical force that is equal to the mass of the box multiplied by the acceleration due to gravity (9.8 m/s²). The weight of the box can be calculated as follows: Weight = mass x gravity = 350 kg x 9.8 m/s² = 3430 N.
The normal force: This is the force exerted by the ground on the box in a direction perpendicular to the surface of the ground. It is equal and opposite to the weight of the box, and acts vertically upward.
The force of friction: This is a horizontal force that opposes the motion of the box and is equal to the coefficient of friction multiplied by the normal force. It can be calculated as follows: Force of friction = coefficient of friction x normal force = 0.24 x 3430 N = 823.2 N.
These forces are illustrated in a force diagram as arrows pointing in the direction of the force with the length of the arrow indicating the magnitude of the force. The force diagram helps to visualize the different forces acting on the box and how they contribute to the overall motion of the box.
6th grade measuring wavelengths!
PLEASE HELP!
Answers
Wavelength of the given wave is 8 cm and frequency is 37.5 *\(10^{8}\) Hz.
What is frequency?The number of vibrations counted per second is called frequency. A wave is a group of vibrations that are referred to as energy. The bottom node is known as the crest, and the top node is known as the trough.
The frequency of an alternating current is the number of full cycles per second. The hertz, also known as Hz, is the accepted unit of frequency. The frequency of a current is 1 Hz if one cycle is completed per second; 60 cycles per second equals 60 Hz.
There are 8 waves so assume one wave is 1 cm so wavelength is 8 cm and frequency of wave = speed of light/ wavelength
frequency = \(3*10 ^{8} / .08\)
Frequency = 37.5 *\(10^{8}\) Hz
Wavelength of the given wave is 8 cm and frequency is 37.5 *\(10^{8}\) Hz.
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A baseball strikes the catcher's glove with a horizontal velocity of 40 m/s. The mass of the baseball is 0.15 kg. The displacement of the baseball due to the deformation of the catcher's glove and the movement of the catcher's hand is 8 cm from the instant it first makes contact with the glove until it stops. a. How much kinetic energy does the baseball possess just before it strikes the glove
Answers
Answer:
the kinetic energy is 120 J
Explanation:
a. The computation of the kinetic energy before it strikes the glove is as follows:
As we know that
The Kinetic energy is
= 1 ÷ 2 × m × v^2
= 1 ÷ 2 × (0.15)(40^2)
= 120 J
Hence, the kinetic energy is 120 J
A ball is dropped. Assuming free fall, what is its initial speed?
Answers
For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.
The supplied problem informs us that a ball was dropped and is supposed to be falling freely. Since the problem does not specify whether any other forces were present to influence the ball's motion, we must assume that the initial speed is v0=0 m/s.
Free-falling accelerates at a rate of 9.8 m/s2, which is referred to as the acceleration owing to gravity because it is being drawn towards the center of the earth. This indicates that a=9.8m/s2 is the value of the initial and final accelerations.
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Question 3 of 10
Which statement describes the law of conservation of energy?
A. Air resistance has no effect on the energy of a system.
B. Energy cannot be created or destroyed.
C. The total energy in a system can only increase.
D. Energy cannot change forms.
هما
SUBMIT
Answers
Answer:
B . energy cannot be created or destroyed
Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.
Answers
The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.
How to find displacement ratio?To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:
d = vt + 1/2at²
where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.
Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.
Assume that the time at which they meet is t, then:
d₁ = 1/2 * 2.4t²
And the equation for the displacement of the second body:
d₂ = 1/2 * 4.8t²
If d₁ = d₂
then, 1/2 * 2.4t² = 1/2 * 4.8t²
Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2
So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.
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The Greek root astro means "stars." Use the context clues to choose the correct definition of the word astronomer. According to the astronomer, the bigger the telescope, the more detail we can see in the images. O A. a person who studies astronauts O B. a person who studies the stars O C. a person who tells the future O D. a person who studies other people
Answers
Answer:
b, it's a pretty easy explanation
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.40 the weight of the object is 4.2
Answers
The frictional force of an object is the product of the normal force and coefficient of kinetic friction. Here the frictional force acting on the object is 16.4 N.
What is frictional force?
Frictional force is a kind of force acting on a body to resist it from motion. Thus, the direction of the force will be in negative with the magnitude. Frictional force is the product of coefficient of friction and the normal force.
The normal force acting on the object of mass 4.2 Kg is N = mg
N = 4.2 Kg × 9.8 m/s² = 41.16 N
Frictional force = ц N
= 0.40 × 41.16 N
= 16.4 N.
Therefore, the frictional force acting between the surface of the object and the floor is 16.4 N
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Your question is incomplete. But your complete question probably was:
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.40 the weight of the object is 4.2 kg. What is the frictional force of the object?
By quadrupling the mass of the body hanging on the thread what will become the period of oscillation?
Answers
Well, the tension in the thread will probably quadruple, but the hanging body will continue to just hang there.
The question gives us no evidence that it is doing any oscillating, and there's no reason for it to start just because it suddenly got heavier.
What type of force is jumping a trampoline?
Answers
Answer:
Tension
Explanation:
The valid digits in a measurement are called the significant digits. True or False
Answers
i think
Answer:
physics. The ______ is a systematic way to observe, experiment, and analyze the world. scientific method. The valid digits in a measurement are called the. significant digits.
Explanation:
truth'
Newton’s law of gravitation says that gravity is a mutually attractive force. Explain the following observation: A small object is dropped on Earth and we see it fall toward Earth. However, we do not observe Earth moving toward the object.
Answers
Answer:
Explanation:
The explanation involves another Newton's law: his second law of motion says force is a product of mass and acceleration.
When a small object is dropped on Earth, gravity pulls the object down towards Earth. The same mutually attractive gravity force also pulls Earth towards the object. But as mass of Earth is much larger than that of the small object, the acceleration of Earth and hence its movement toward the object will be much smaller as to be not noticeable.
Data supporting the theory of a round earth was collected as early as _____.
1570 AD by Galileo
1500 AD by Copernicus
250 BC by Aristarchus
1640 AD by Kepler
Answers
250 BC by Aristarchus is the answer ot the question
Data supporting the theory of a round earth was collected as early as _____.
1570 AD by Galileo
1500 AD by Copernicus
250 BC by Aristarchus
1640 AD by Kepler
for our four-wire resistors (pictured below) the current is measured through which two terminals (numbered 1-4 in the figure)?
Answers
For our four-wire resistors (shown in the image below), terminals 1 and 4 are used to measure current.
How does the 4-wire resistance method work?The four-wire approach makes use of four test leads, one pair of which is used to measure the voltage across the resistor Rmeas and the other pair is used to measure the injected current. The device only measures the voltage that develops across the resistance because there is no current flowing through the sense lead.
How is 4-wire RTD resistance measured?Two wires connect the sensing element to the monitoring device on both sides of the sensing element in a four-wire RTD configuration. The measurement current is delivered by one set of wires, and the voltage drop across the resistor is measured by another set.
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