a rock band playing at an outdoor concert produces a sound at 120db 5.0m away from their single working loudspeaker. what is the intensity level 35m away from the speaker?

Answer:

125

Explanation:

you divide km/hrs to find your velocity.

V=km/hr

V= 250km/2hr

V=125

hope this helps !:)

Answer:

Explanation:

Given

Power (p)= 726 watt

Time (t) = 14 sec

distance travelled (d; h) = 36 m

mass (m) = ?

we know

Power (p) = W/t  ( w = work done )

p = m * g * h / t  ( w = m * g* h)

726 = m * 10 * 36 / 14 ( g = 10 m/s^2)

m = 28. 23 kg

or if we use the value of g as 9.8 m/s^2

the mass will be

= 28.8 kg

hope it helps :)

The mass of the object if it takes 726 watts of power to move an object 36 m in 14 s is 28.8 kg.

An object's inertia, a fundamental property, is measured by its mass, a fundamental indicator of the volume of substance inside the thing. Definitions of mass can seem circular since it is such a fundamental quantity and is challenging to define in terms of another.

It is possible to define every mechanical quantity in terms of mass, length, and time. The SI unit for mass, denoted by the letter m, is the kilogram. While mass is typically thought of as an immutable feature of an item, relativistic mass must be taken into account when traveling at speeds close to the speed of light.

Given:

The Power, p = 726 watt

The Time, t = 14 sec

distance travelled, d = 36 m

Calculate the power by the given formula

p = W / t  

p = m * g * h / t  ( w = m * g* h)

726 = m * 9.8 * 36 / 14 ( g = 10 m/s^2)

m = 28. 8 kg

Therefore,  the mass of the object If it takes 726 watts of power to move an object 36 m in 14 s is 28.8 kg.

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Answer:

The Earth is massive enough that the pull of gravity maintains its roughly spherical shape. Most of its deviation from spherical stems from the centrifugal force caused by rotation around its north-south axis. This force deforms the sphere into an oblate ellipsoid.

It is important on diagrams to represent a force with an arrow because force is a vector quantity but it is not important to represent a mass since it is scalar quantity.

Vector quantities are always represented with arrows because they have magnitude and direction.

Scalar quantities have only magnitude, and cannot be represented with arrows.

Thus,  it is important on diagrams to represent a force with an arrow because force is a vector quantity but it is not important to represent a mass since it is scalar quantity.

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Answer:

\( \huge{ \boxed{ \bold{ \sf{90 \: joule}}}}\)

✑ First , Let's know what kinetic energy is :

⇾ The energy possessed by a body by the virtue of it's motion is called kinetic energy of the body. A flying bird , a moving car , running water , wind , a bullet fired from a gun , an arrow left from a bow , rolling stone etc are some examples of kinetic energy.

The Kinetic energy of a moving body is determined by the formula :

\( \boxed{ \underline{ \sf{KE= \frac{1}{2} m {v}^{2} }}}\)

Here ,

--------------------------------------------------------------

☇ Now , Let's solve :

☄ Given :

☄ To find :

⤿ \( \boxed{ \sf{KE= \frac{1}{2} m {v}^{2} }}\)

Plug the values and simplify :

→ \( \sf{ \frac{1}{2} \times 20 \times {(3)}^{2} }\)

→ \( \sf{ \frac{1}{2} \times 20 \times 9}\)

→ \( \boxed{ \bold{\sf{90 \: joule}}}\)

Hope I helped !

Have a wonderful day ! ツ

~TheAnimeGirl ♡

The number of telescopes a wizard needs to study the stars can vary depending on their specific needs and preferences. In many cases, a single high-quality telescope can be sufficient for observing celestial objects.

However, some wizards may prefer to have multiple telescopes with different characteristics, such as varying magnification levels or specialized features for specific types of observations. Additionally, advanced wizards might utilize telescopes with different wavelengths, such as optical, infrared, or radio telescopes, to study various aspects of the stars and the universe. Ultimately, the number of telescopes needed is subjective and based on the wizard's expertise and research interests.

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This measurement demonstrates the conductivity of a certain material. When compared to rubber, which has poor electrical conductivity and high electrical resistance, metal, for instance, has high electrical conductivity and low electrical resistivity.

Electrical resistivity's physical opposite is electrical conductivity. This measurement demonstrates how well a certain material can conduct an electric current.

Rubber has a poor electrical conductivity and a high electrical resistivity, whereas metal has a high electrical conductivity and a low electrical resistance.

We are aware of the following thanks to the values that have been provided:

J = 6.00 10 13 A / m 2 and E = 100 V / m

The following equation provides the current density in terms of the electric field:

J = σ E

Here, E is the electric field, J is the current density, and is the electrical conductivity.

σ = J / E

The known values are then substituted.

σ = ( 6.00 × 10 − 13 A / m 2 ) / ( 100 V / m )

σ = ( 6.00 × 10 − 15 / m ) / ( 100 V )

The corresponding unit for V / A is.

Condense the units.

σ = 6.00 × 10 − 15 Ω − 1 m − 1.

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Answer:

The plastic is too much like other things that are allowed. Sometimes it is too thin, as well. Or sometimes the gates are just not that modern and advanced enough to detect them.

1. The crab nebula is the result of a supernova explosion that was witnessed on earth in the year 1054.

2. Betelgeuse is a supergiant star that will eventually supernova, which means that by mass it is classified as a massive star.

3. The debris from the death of a high-mass star forms a supernova remnant several light years across.

4. A neutron star has a density higher than the density of a white dwarf.

5. Cosmic microwave background radiation actually occurred about 150,000 years ago in the large magellanic cloud.

6. The CNO cycle is the process by which hydrogen fusion proceeds in high-mass stars.

7. Carbon can be converted into oxygen in the cores of high-mass stars if carbon nuclei undergo a triple alpha process.

1. The crab nebula is the result of a supernova explosion that was witnessed on earth in the year 1054. A supernova is a powerful and luminous explosion that occurs when a star exhausts its fuel and collapses.

2. Betelgeuse is a supergiant star that will eventually supernova, which means that by mass it is classified as a massive star. Massive stars have a mass of at least eight times that of the sun.

3. The debris from the death of a high-mass star forms a supernova remnant several light years across. A supernova remnant is the expanding shell of gas and dust left behind after a supernova explosion.

4. A neutron star has a density higher than the density of a white dwarf. A neutron star is the collapsed core of a massive star that has gone supernova. It is extremely dense, with a mass greater than that of the sun packed into a sphere only a few kilometers across.

5. The cosmic microwave background radiation actually occurred about 150,000 years ago in the large magellanic cloud. The cosmic microwave background radiation is the faint afterglow of the Big Bang, which occurred approximately 13.8 billion years ago.

6. The CNO cycle is the process by which hydrogen fusion proceeds in high-mass stars. The CNO cycle is a set of nuclear reactions that convert hydrogen into helium, carbon, and oxygen. It is the dominant source of energy production in stars with a mass greater than about 1.5 times that of the sun.

7. Carbon can be converted into oxygen in the cores of high-mass stars if carbon nuclei undergo a triple alpha process. The triple alpha process is a nuclear reaction that occurs when three alpha particles (helium nuclei) combine to form a carbon nucleus. This process is the primary way in which carbon is produced in stars.

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From the core concept introduced by Al-Haytham, modern cameras are created.

To find the answer, we have to know about the Camera Obscura.

Thus, we can conclude that, from the core concept introduced by Al-Haytham, modern cameras are created.

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Answer:

acceleration is 1.6 m/s^2

Explanation:

This is a question involving Kinematics so we can use one of the kinematic equations.

Given info: Vi= 2.6 m/s. Vf= 15.4 m/s. T= 8s

We need to solve for acceleration

The best equation to use is (Vf = Vi + at) as it contains all the info we need to solve for acceleration.

Now substitute the values given into the equation.

Vf = Vi + at >> 15.4 = 2.6 + a8

Now solve for a by rearranging the equation.

15.4 -2.6= 8a >> 12.8=8a >> 12.8/8= 8a/8 >> 1.6 =a

NOTES:

Acceleration is the rate of increase of velocity

Vf is final velocity or velocity after acceleration/de-accaeleration occurs

Vi is intial velocity or velocity before acceleration or de-accaeleration occurs

Time is time it took for a certain motion to occur.

The Lyman series is in the ultraviolet region, while the Paschen, Brackett, and Pfund series are all in the infrared region of the electromagnetic spectrum.

These series represent the different sets of spectral lines corresponding to electron transitions in the hydrogen atom.

1. Lyman series: This series corresponds to electron transitions from higher energy levels to the first energy level (n=1). The lines in the Lyman series are found in the ultraviolet (UV) region of the electromagnetic spectrum.

2. Paschen series: This series corresponds to electron transitions from higher energy levels to the third energy level (n=3). The lines in the Paschen series are found in the infrared (IR) region of the electromagnetic spectrum.

3. Brackett series: This series corresponds to electron transitions from higher energy levels to the fourth energy level (n=4). The lines in the Brackett series are also found in the infrared (IR) region of the electromagnetic spectrum.

4. Pfund series: This series corresponds to electron transitions from higher energy levels to the fifth energy level (n=5). The lines in the Pfund series are found in the infrared (IR) region of the electromagnetic spectrum as well.

In summary, the Lyman series is in the ultraviolet region, while the Paschen, Brackett, and Pfund series are all in the infrared region of the electromagnetic spectrum.

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The acceleration of a satellite orbiting Earth at an altitude of 500 km is approximately 8.985 m/s².  

The formula for gravitational acceleration is given by:
a = GM / r²
where:
a is the acceleration,
G is the gravitational constant (approximately 6.67430 × 10⁻¹¹ N(m/kg)²),
M is the mass of the Earth,
r is the distance between the center of the Earth and the satellite.

To calculate the acceleration of the satellite, we need to determine the distance from the center of the Earth to the satellite. This can be done by adding the radius of the Earth to the altitude of the satellite:

r = 6380 km + 500 km

= 6880 km

Now we can substitute the values into the formula:

a = (6.67430 × 10⁻¹¹ N(m/kg)² * M) / (6880 km)²

The mass of the Earth, M, is approximately 5.972 × 10²⁴ kg.

a = (6.67430 × 10⁻¹¹ N(m/kg)² * 5.972 × 10²⁴ kg) / (6880 km)²

To simplify the calculation, we need to convert the radius of the Earth and the altitude of the satellite to meters:

r = (6380 km + 500 km) * 1000

= 6880000 m

Now we can substitute the values into the formula and calculate the acceleration:

a = (6.67430 × 10⁻¹¹ N(m/kg)² * 5.972 × 10²⁴ kg) / (6880000 m)²

a = 8.985 m/s²

Therefore, the acceleration of a satellite orbiting Earth at an altitude of 500 km is approximately 8.985 m/s².

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The linear speed of the conveyor belt is 100.5 cm/s, if the radius of the roller is 8 cm and revolution speed 2 revolution per second.

The radius of the roller, r = 8 cm

Number of revolution per second, n = 2

Angular speed of the roller, ω = 2πn/T

Let the linear speed of the conveyor belt = v

ω = 2π×2/1 = 4π/sec

Linear speed is defined as the product of the radius and angular speed.

v = r × ω

v = 8 × 4π

v = 8 × 4 × 3.14

v = 100.5 m/s

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Answi am sorry but i do not know the answer

Explanation:

Answer:

this is the answer

Answer:

To holds the legs apart without rupturing any vein

Explanation:

The purpose of using string to tie the forelegs and hind legs during dissection is to hold the legs apart without rupturing ant vein or artillery for easy dissection procedure( the dismembering of the body of a deceased animal or plant to study its anatomical structure)

when tieing the forelegs and the hind legs the same string is used to tie them and the string is then passed/looped under the dissecting table/tray this way the legs will be held apart and the dissection can commence.

The difference in planets or solar system bodies with no air, moderate amounts of greenhouse gases, and abundant greenhouse gases is the temperatures on the surface can vary greatly, with extreme heat during the day and extreme cold at night.

Moderate amounts of greenhouse gases, like Mars, have a thin atmosphere with some greenhouse gases, such as carbon dioxide. This traps some heat and regulates temperatures, but not to the same extent as Earth. As a result, temperatures on Mars can range from -195°C to 20°C.

In contrast, planets or solar system bodies with abundant greenhouse gases, such as Venus, have a thick atmosphere with high levels of greenhouse gases, mainly carbon dioxide. This causes a strong greenhouse effect, trapping heat and resulting in extremely high temperatures on the surface, which can reach up to 460°C.

Overall, the presence and amount of greenhouse gases in a planet or solar system body's atmosphere greatly affects its surface temperatures and climate conditions.

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Answer:

(a) 1317.44 W/m²

(b) 1.74×10¹⁵ litres of heating oil

(c) -20.63°C

(d) Energy storage in the Earth and the air

Explanation:

The parameters given are;

Luminosity of the Sun = 3.828 × 10²⁶ Watt

Distance of the Earth from the Sun, d = 152.06 × 10⁶ km

The radius of the Sun = 696 × 10³ km

The radius of the Earth, \(r_E\) = 6730 km

The surface area of the Sun = 12000 × Surface area of the Earth

The surface area of the Sun = 6.09 × 10¹² km²

Cross sectional area of the Earth = 1.27 × 10⁴ m² = 0.0127 km²

By the inverse square law, we have;

\(R = \dfrac{Luminosity \, of \, the \, Sun}{4 \pi d^2}\)

Where:

R = Solar radiation reaching the Earth

Therefore;

\(R = \dfrac{3.828 \times 10^{26}}{4 \times \pi \times (1.5206 \times 10^{11})^2} = 1317.44 \ W/m^2\)

Hence, the energy, E, reaching the Earth in a day is given as follows;

E = R × 4×π×\(r_E\)²×60×60×24 = 1317.44 × 4 × π × 6730000² × 60×60×24

E = 6.479×10²² Joules

(b) The number of litres of heating oil is therefore;

6.479×10²² J ÷ (37.3×10⁶ J/litre) = 1.74×10¹⁵ litres of heating oil

(c) 30% of the Energy is reflected, therefore;

0.7 × 6.479×10²² Joules = 4.54×10²² Joules reaches the Earths surface

From Stefan-Boltzmann law, we have;

\(T = \left (\dfrac{\left (1 - \alpha \right ) \times R }{4\times \sigma } \right )^{\dfrac{1}{4}}\)

Where:

α = 0.3

σ = Stefan-Boltzmann constant = 5.6704×10⁻⁸ W/(m²·K⁴)

Therefore;

\(T = \left (\dfrac{\left (1 - 0.3 \right ) \times 1317.44 }{4\times 5.6704 \times 10^{-8} } \right )^{\dfrac{1}{4}} = 252.52 \ K = -20.63 ^{\circ} C\)

(d) The heat storage in the Earth and the air

The beam of light from the lighthouse is moving at a speed of approximately 10π km/minute along the shoreline when it is 1 km away from point P.

To determine the speed at which the beam of light from the lighthouse is moving along the shoreline when it is 1 km away from the point P, we need to consider the relationship between angular velocity, linear velocity, and distance.

Given that the lighthouse makes five revolutions per minute, we can determine its angular velocity (ω) using the formula:

ω = 2πn

where n is the number of revolutions per unit of time. In this case, n is equal to 5 revolutions per minute. Substituting the values, we have:

ω = 2π * 5 = 10π radians per minute

Now, to find the linear velocity (v) of the beam of light along the shoreline, we can use the relationship between angular velocity, linear velocity, and distance. This relationship is given by:

v = r * ω

where r is the distance from the center of rotation (in this case, the lighthouse) to the point at which we want to measure the velocity.

In this scenario, the distance from the lighthouse to the shoreline (point P) is given as 3 km. However, we are interested in finding the velocity when the beam of light is 1 km from point P. Therefore, we need to consider a new distance (r) of 1 km.

Substituting the values into the equation, we have:

v = 1 km * (10π radians per minute)

v = 10π km/minute

Therefore, the beam of light from the lighthouse is moving at a speed of approximately 10π km/minute along the shoreline when it is 1 km away from point P.

In summary, the speed of the beam of light from the lighthouse along the shoreline is determined by the angular velocity of the lighthouse and the distance from the center of rotation to the point of interest. In this case, with an angular velocity of 10π radians per minute and a distance of 1 km, the beam of light is moving at a speed of approximately 10π km/minute.

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(a) The electric field at a point 5.0 cm from the negative charge and along the line between the two charges is -2.58825 x 10⁵ N/C, directed towards the negative charge. (b) The force on an electron placed at that point is 2.58825 x 10⁻⁵ N, directed towards the positive charge.

The electric field at a point due to a point charge is given by the equation E = k * q / r², where E is the electric field, k is the electrostatic constant (k = 9 x 10⁹Nm² /C² ), q is the charge, and r is the distance between the charges.

(a) To find the electric field at a point 5.0 cm from the negative charge, we need to calculate the electric field due to both charges and then subtract the electric field due to the positive charge from the electric field due to the negative charge.

The electric field due to the negative charge (q2) is given by E2 = k * q2 / r², where q2 = -6.4 x 10⁻⁸  C and r = 5.0 cm = 0.05 m.

Plugging in the values, we get E2 = (9 x 10 Nm² /C² ) * (-6.4 x 10 C) / (0.05 m)² = -2.58825 x 10⁵ N/C.

The negative sign indicates that the electric field due to the negative charge is directed towards the negative charge.

(b) To find the force on an electron placed at that point, we need to calculate the force due to both charges and then subtract the force due to the positive charge from the force due to the negative charge.

The force between two charges is given by the equation F = k * |q1 * q2| / r², where F is the force, q1 and q2 are the charges, and r is the distance between the charges.

The force on the electron due to the negative charge (q2) is given by F2 = k * |q2 * e| / r², where q2 = -6.4 x 10⁻⁸ C, e is the charge of an electron (e = -1.6 x 10⁻¹⁹ C), and r = 5.0 cm = 0.05 m.

Plugging in the values, we get F2 = (9 x 10⁹ Nm²/C²) * |-6.4 x 10⁻⁸ C * -1.6 x 10⁻¹⁹ C| / (0.05 m)² = 2.58825 x 10⁻⁵ N.

The positive sign indicates that the force on the electron is directed away from the negative charge, which is towards the positive charge.

So, the answers to the given questions are:

(a) The electric field at a point 5.0 cm from the negative charge and along the line between the two charges is -2.58825 x 10⁵ N/C, directed towards the negative charge.

(b) The force on an electron placed at that point is 2.58825 x 10⁻⁵ N, directed towards the positive charge.

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Marginalized individuals, including people with disabilities and those who identify as LGBTQ+, can experience significant impacts due to trauma, discrimination, negative attitudes, and exclusion. These factors contribute to physical and psychological harm, hinder access to opportunities and resources, and perpetuate systemic inequalities.

Marginalized individuals, such as people with disabilities, face unique challenges that can exacerbate the impact of trauma, discrimination, negative attitudes, and exclusion. Trauma experienced by individuals with disabilities may result from direct incidents or from the effects of living in a society that is not fully inclusive. Discrimination and negative attitudes towards people with disabilities can lead to social isolation, limited employment prospects, and reduced access to healthcare and education. This exclusion can have long-lasting effects on their mental health, self-esteem, and overall well-being. Similarly, individuals who identify as LGBTQ+ may also face trauma, discrimination, negative attitudes, and exclusion. LGBTQ+ individuals often encounter higher rates of bullying, harassment, and violence due to their sexual orientation or gender identity. These experiences can lead to psychological distress, anxiety, depression, and even post-traumatic stress disorder (PTSD). Discrimination and exclusion from healthcare, housing, employment, and social support systems further compound the challenges faced by LGBTQ+ individuals, hindering their ability to thrive and fulfill their potential.

In both cases, the impacts of trauma, discrimination, negative attitudes, and exclusion are far-reaching. They can contribute to a cycle of disadvantage, limiting opportunities for personal growth, social participation, and economic advancement. Recognizing and addressing these issues is essential for fostering a more inclusive society that supports the needs and rights of marginalized groups, empowering individuals to overcome the barriers they face and promoting their overall well-being.

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Answer:

a) La magnitud del desplazamiento es de 5 m

La magnitud de la fuerza es 20 N

b) El trabajo realizado por la fuerza es de 100 J

c) El ángulo entre la fuerza y el plano es 0 °

Explanation:

a) La magnitud del desplazamiento se encuentra por la relación;

\(\left | X \right | = \sqrt{X_{x}^{2}+X_{y}^{2}}\)

Lo que da;

\(\left | X \right | = \sqrt{4^{2}+3^{2}} = 5 \ m\)

De manera similar, la magnitud de la fuerza, F, se encuentra como sigue;

\(\left | F \right | = \sqrt{F_{x}^{2}+F_{y}^{2}}\)

Lo que da;

\(\left | F \right | = \sqrt{16^{2}+12^{2}} = 20 \ N\)

b) El trabajo, W, realizado por la fuerza = Fuerza, F × Distancia, X

∴ Ancho = 20 N × 5 m = 100 N · m = 100 J

c) La dirección de la fuerza viene dada por la siguiente fórmula;

\(tan^{-1} \left (\dfrac{F_y}{F_x} \right ) = tan^{-1} \left (\dfrac{12}{16} \right ) = 38.9^{\circ}\)

La dirección del plano viene dada por la siguiente fórmula;

\(tan^{-1} \left (\dfrac{X_y}{X_x} \right ) = tan^{-1} \left (\dfrac{3}{4} \right ) = 38.9^{\circ}\)

Por tanto, el ángulo entre la fuerza y el plano = 0 °

La fuerza actúa a lo largo del plano.

Answer:

Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface

Answer:

The space around a charge or a pole in which a force is experienced is called a magnetic field. And a cluster of aligned magnetic atoms is a magnetic domain. When the clustered regions are aligned with one another, they form a magnet

Henrietta Leavitt was an astronomer who discovered that RR Lyrae stars pulsate at a regular rate that is directly related to their intrinsic brightness. This relationship, known as the period-luminosity relation, allowed Leavitt to measure the distances to many stars in our Milky Way galaxy and beyond. Her work revolutionized our understanding of the size and structure of the universe and paved the way for future astronomical discoveries.

Why do RR Lyrae stars pulsate?

RR Lyrae stars pulse like Cepheid variables, but the nature and histories of these stars is thought to be rather different. Like all variables on the Cepheid fluctuation strip, pulsations are caused by the κ-mechanism, when the ambiguity of ionized helium varies with its temperature.

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Answer:

D. The reflected ray makes an angle of 90°.

Explanation:

The electric field due to the point charge located at the center of the cube can be calculated using Gauss's law and is given by E = charge / (ε0 x A).

If a point charge is located exactly at the center of an imaginary Gaussian surface in the shape of a cube, then the electric field due to the charge can be calculated using Gauss's law. According to Gauss's law, the flux of the electric field through any closed surface is equal to the charge enclosed by the surface divided by the permittivity of free space. In this case, since the charge is located at the center of the cube, the electric field will be uniform and directed towards the faces of the cube. Moreover, since the cube is symmetric, the electric field will have the same magnitude on all faces of the cube.
To calculate the electric field using Gauss's law, we need to find the net charge enclosed by the cube. Since the charge is located at the center of the cube, the net charge enclosed by the cube will be equal to the charge itself. Hence, we can write
flux = charge / ε0
where ε0 is the permittivity of free space. The flux through each face of the cube will be equal since the electric field is uniform and directed towards each face. Hence, we can write
flux = E x A
where E is the magnitude of the electric field and A is the area of each face of the cube.
Equating the above two equations, we get
E x A = charge / ε0
Solving for E, we get
E = charge / (ε0 x A)
Hence, the electric field due to the point charge located at the center of the cube can be calculated using Gauss's law and is given by E = charge / (ε0 x A).

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Acceleration is the variable that is NOT shown on a velocity-time graph

Velocity - time graph, evidently shows two variables, velocity on one axis and time on other . But as we know , that acceleration can be calculated by the formula which is

acceleration = change in velocity / time

hence , the derivative of velocity is acceleration

which mean that the slope of the Velocity - time graph shows the acceleration , which cannot be seen , but is hidden as the slope of that graph

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