If a rock rests on the ground. A force pulls the rock toward the earth, and another force pulls the rock toward the moon, the rock stays on the ground because the force pulling the rock toward the earth is greater than the force pulling the rock toward the moon.
Therefore the correct answer is option D.
What is gravity?It can be defined as the force by which a body attracts another body towards its center as the result of the gravitational pull of one body and another,
if a rock is lying on the surface. The rock is being pulled in opposite directions—one toward the earth and the other toward the moon—but it remains on the ground because the force pushing it toward the earth is stronger than the force dragging it toward the moon.
Thus, the correct answer is option D.
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Particles q₁ = -1.21 μC, q2 = -55.0 μC, and
93 +148 μC are in a line. Particles 9₁ and q2 are
separated by 0.447 m and particles q2 and q3 are
separated by 0.447 m. What is the net force on
particle q3?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
–1.21 μC
q1
0.447 m
-55.0 C
q2
0.447 m
148 μC
q3 +
The net force on q₃ is -0.091 N.
Given information:Charge of particle q₁, q₂, q₃ are -1.21 μC, -55.0 μC, and +148 μC, respectively
Particles q₁ and q₂ are separated by 0.447 m and particles q₂ and q₃ are separated by 0.447 m. Let's solve the above problem, The net force on particle q₃ can be determined by Coulomb's Law.
The force acting on q₃ due to q₂ can be expressed as :F2 = kq2q3/r²₂Where k is Coulomb's constant = 8.99×10⁹ Nm²/C², q₂ is the charge of particle q₂, q₃ is the charge of particle q₃, and r₂ is the separation distance between the particles.
The force acting on q₃ due to q₁ can be expressed as:F1 = kq1q3/r¹₁Where k is Coulomb's constant = 8.99×10⁹ Nm²/C², q₁ is the charge of particle q₁, q₃ is the charge of particle q₃, and r₁ is the separation distance between the particles.
The net force acting on q₃ is:F₃ = F1 + F2The force acting between q₁ and q₂ is repulsive since they are of the same sign. So, the net force on q₃ will be to the right-hand side.
The force acting between q₂ and q₃ is attractive since they are of different signs. So, the net force on q₃ will be to the left-hand side.The distances between q₁ and q₂ and between q₂ and q₃ are the same. This implies that the magnitudes of F1 and F2 are the same, and they cancel each other out.
So, the net force acting on q₃ is only due to the force acting between q₂ and q₃. Hence, the net force acting on q₃ can be expressed as:
F₃ = F2 - F1= kq2q3/r²₂ - kq1q3/r¹₁
F₃ = 8.99×10⁹ (-55.0×10⁻⁶)(+148×10⁻⁶)/(0.447)² - 8.99×10⁹ (-1.21×10⁻⁶)(+148×10⁻⁶)/(0.447)²= -0.091 N, to the left of q₃.
The net force on q₃ is -0.091 N.
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A lamp plugged into an electrical outlet is turned on. The lightbulb in the lamp glows and gets hot. What energy transformations are taking place?
Answer: thermal and elterical
Explanation:thermal and eltrical
Answer:
Electric energy from the outlet transforms to radiant energy and thermal energy in the lightbulb.
Explanation:
which object exerts a downward force on the book? which object exerts a downward force on the book? the book itself the earth the surface of the table
The object that exerts a downward force on the book is the Earth.
A force is an influence that causes an object to undergo a change in motion. Force is a vector quantity that has both magnitude and direction. A force can cause an object to accelerate, deform, or experience a change in velocity.
The downward force in the book: Gravity is a force that pulls objects towards the Earth's center. As a result, the Earth exerts a downward force on the book. This force is known as the weight of the book.
Weight is the force acting on an object due to gravity. An object's weight is proportional to its mass and acceleration due to gravity.
The formula for weight is given by: W = mg
Where W is weight, m is mass, and g is the acceleration due to gravity.
Therefore, the Earth exerts a downward force on the book.
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Comparison of rarefraction and compression
Answer:
In a longitudinal wave, a compression is a region when the particles are closest together. A rarefaction is an area in a longitudinal wave where the particles are the furthest distant from one another. A compression is a zone where the medium is compressed, while a rarefaction is a region where the medium is spread out.
What are the three fundamental aspects of an ideal training progression?a-Volume, intensity, and loadb-Endurance, strength, and power Movementc- competency, strength, and powerd- Functional capacity, cardiorespiratory fitness, and injury resiliency
The three fundamental aspects of an ideal training progression are competency, strength, and power. These three aspects are crucial for building a solid foundation for physical fitness and achieving one's fitness goals.
Competency refers to the ability to perform exercises with proper form and technique.Strength refers to the ability to generate force and lift heavy loads. Power refers to the ability to produce force quickly and explosively.By focusing on these three aspects in a training progression, one can improve their overall fitness and reduce the risk of injury. All three components need to be taken into account when creating an effective training program.
Hence, the correct option is c.
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A 60 litre steel gasoline tank is full of gas, so that both the tank and the gasoline
have a temperature of 15 °C. The amount of gasoline has been spilled by the time
they warm up to 35 °C will be:
(A) 50.2 litre
(B) 1.10 litre
(D) None
(C) 3.26 litre
Answer:
To solve this problem, we need to use the coefficient of thermal expansion for gasoline, which tells us how much the volume of gasoline will increase as its temperature increases. The coefficient of thermal expansion for gasoline is approximately 950 x 10^-6 /°C.
Using this information, we can calculate the increase in volume of gasoline as it warms up from 15°C to 35°C:
ΔV = V * α * ΔT
where V is the initial volume of gasoline (60 L), α is the coefficient of thermal expansion for gasoline (950 x 10^-6 /°C), and ΔT is the change in temperature (20°C).
ΔV = 60 * 950 x 10^-6 * 20
ΔV = 0.114 L
Therefore, the amount of gasoline spilled as it warms up from 15°C to 35°C is:
60 L - 0.114 L = 59.886 L
Explanation:
So the answer is (A) 50.2 litre.
The first law of thermodynamics states that energy can neither be created nor destroyed. If this is true then why are we always looking for new sources of energy? Use the 2nd law of thermodynamics to answer this question.
Answer:
The second law of thermodynamics states in an isolated system, the entropy (the amount of thermal energy that cannot be converted into mechanical work, also known as the amount of disorder) always increases, therefore, an isolated system always require an external input (new sources) of energy for there to be orderliness or for the available energy of the system to remain constant or increase
Explanation:
Some incandescent light bulbs are filled with argon gas, because it is inert. What is the rms speed, in meters per second, for argon atoms near the filament, assuming their temperature is 2400 K?
To calculate the root mean square (rms) speed of argon atoms near the filament of an incandescent light bulb at a temperature of 2400 K, we can use the formula for the rms speed of a gas molecule is 1.23 x 10³ m/s
The rms speed of a gas molecule can be calculated using the formula:
\(V_{rms} =\sqrt{3KT/m}\)
where v(rms) is the rms speed, k is the Boltzmann constant (1.38 ₓ 10⁻²³ J/K), T is the temperature in Kelvin, and m is the mass of the gas molecule.
To determine the rms speed of argon atoms near the filament, we need to find the mass of an argon atom. The atomic mass of argon (Ar) is approximately 39.95 atomic mass units (u).
Vrms=√3×1.38 ₓ 10⁻²³ ×2400/1.67 ₓ 10⁻²⁷
=1.23 x 10³ m/s
First, we convert the atomic mass to kilograms by multiplying it by the atomic mass constant (1.67 ₓ 10⁻²⁷ kg/u). Then we substitute the values into the rms speed formula, using the given temperature of 2400 K.
By performing these calculations, we can determine the rms speed of argon atoms near the filament of the incandescent light bulb at the specified temperature. The result will be in meters per second.
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Which of these does not represent a direct transfer of carbon
1.Air to trees
2.Giraffe to tree
3.Tree to giraffe
Answer:
The correct answer is - 2. Giraffe to trees.
Explanation:
In the carbon cycle, the movement of carbon is represented how it moves from one sphere to other and how it transfer among the different organism. The carbon moves from air to the trees in the form of carbon dioxide that is used by trees for the production of glucose by the process of photosynthesis through stomata.
The movement of the carbon among trees to different herbivores including giraffe is transferred by the eating of the leaves or fruits of the tree that carries glucose or starch. The transfer of carbon through giraffe does not take place directly but takes the release of carbon dioxide by the process of cellular respiration to the atmosphere.
A car travels 300km in six hour. What is the average speed
Answer:
50 km/hrExplanation:
The average speed of the car can be found by using the formula
\(s = \frac{d}{t} \\ \)
d is the distance
t is the time taken
From the question we have
\(s = \frac{300}{6} = 50 \\ \)
We have the final answer as
50 km/hrHope this helps you
Answer:
50mph
Explanation:
Just do\(\frac{300}{6}\) (aka 300 divided by 6)
And you'll get 50 as your answer!
Hope this helps! Ty!
Suppose the Pathfinder moves at a rate of 0.2m/s for 20 seconds and then turns around and travels at the same speed for 3 seconds, what is the Pathfinder's current position?
Answer:
PLEASE BE MORE SPECIFIC
Explanation:
The pathfinder is currently 3.4 m away from its initial position. Speed can be defined by the change in position of the object over time.
What is Speed?
It can be defined by the change in position of the object over time. The distance can be calculated by the formula,
\(d = s \times t\)
Where,
\(d\)- distance
\(s\) - speed
\(t\) - times -
Initially, Pathfinder moves,
\(d = 0.2 \times 20 \\\\d = 4 \rm \ m\)
Then he turns back and moves,
\(d' = 0.2 \times 3 = 0.6 \rm m\)
So the current position is:
\(D = d - d'\\\\D = 4 - 0.6 \\\\D = 3.4\rm m\)
Therefore, the pathfinder is currently 3.4 m away from its initial position.
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In this example we will look at the volume deformation of water. The bulk modulus of water is 2.2×109Pa (=2.2×109N/m2). By how much does a cubic meter of water decrease in volume when it is taken from the surface of the ocean down to a depth of 1.0 km, where the pressure is 9.8×106Pa greater than at the surface?
SET UP AND SOLVE The bulk modulus is
B=−ΔpΔV/V0
We solve this equation for ΔV:
ΔV==−ΔpV0B=−(9.8×106Pa)(1.0m3)(2.2×109N/m2)−4.5×10−3m3=−4500cm3
REFLECT The negative sign indicates that the volume has decreased while the pressure has increased. Although the pressure at a 1 km depth is roughly 100 times that at the surface, the fractional change in volume is only about 0.5%.
A fluid with an initial volume of 0.26 m3 is subjected to a pressure decrease of 4.3×103Pa. The volume is then found to have increased by 0.21 cm3 . What is the bulk modulus of the fluid?
The formula for bulk modulus is B= -Δp * V0 / ΔV, where Δp is the pressure change, V0 is the initial volume, and ΔV is the change in volume. The bulk modulus of the fluid is 5.34 × 10⁵ Pa.
In this problem, we are given the initial volume (V0) of a fluid, the change in pressure (Δp), and the change in volume (ΔV). Our goal is to determine the bulk modulus (B) of the fluid.
We are given:
V0 = 0.26 m³
Δp = -4.3 × 10³ Pa (negative since pressure decreases)
ΔV = 0.21 cm³ (positive since volume increases)
First, we need to convert ΔV to cubic meters:
ΔV = 0.21 cm³ × (1 m/100 cm)³ = 2.1 × 10⁻¹² m³
Now we can use the formula for the bulk modulus:
B = -Δp × V0 / ΔV
Plug in the given values and solve for B:
B = (-(-4.3 × 10³ Pa) × 0.26 m³) / (2.1 × 10⁻¹² m³)
B = 5.34 × 10⁵ Pa
So, the bulk modulus of the fluid is 5.34 × 10⁵ Pa.
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How are mass and acceleration related?
Answer:
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
Explanation:
Which of the following is a good example of a contact force? A. Earth revolving around the Sun B. a bridge suspended by cables C. a ball falling downward a few seconds after being thrown upward D. electrically charged hairs on your head repelling each other and standing up
Answer: a bridge suspended by cables
With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in ____________ twitches per stimulus.
With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in identical twitches twitches per stimulus.
Alpha motor neurons are the motor neurons that innervate the fibers of the skeletal muscle. A number of branches, each innervating a different muscle fiber, are formed as the alpha motor neuron enters the muscle. A motor unit is made up of one alpha motor neuron and all of the muscle fibers it innervates. Small motor units with 3-5 muscle fibers per motor neuron are found in muscles that are involved in delicate, coordinated control. Our hand and eye muscles, as well as those that control eye movement, have very small motor units.
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Astronomers classify galaxies by their shape. Which of the following terms describes a galaxy that looks like a round or flattened ball and contains little gas and dust between the stars?
A.
elliptical galaxy
B.
irregular galaxy
C.
No galaxies are shaped like a ball
D.
spiral galaxy
a car of mass 450 kg is acted on by a resultant force of 1575 N.Calculate its acceleration
Answer:
a=3.5m/s^2
Explanation:
f=ma(f=force m=mass a=acceleration)
1575=450a
a=1575/450
a=3.5m/s^2
Answer:
3.5ms^-2
Explanation:
m = 450kg, F = 1575N, a = ?
Since F = ma
Making acceleration subject of the formula
We have;
a = F/m
Substituting we have;
a = 1575/450
a = 3.5ms^-2
I don't know what to do so first people to answer get 30 points
also tell me your favorite football team and hockey team
Answer:
seahawks, la kings
Explanation:
Which of the following is not a true statement about atomic bonds?
Answer:
Havent seen this one before but the explanation should help you out :)
Explanation:
There are only three atomic bonds.
Ionic bonding.
Covalent bonding.
Metallic bonding.
after how much time does an imaging plate exposed to radiation start losing its enrgy
In computed radiography, an imaging plate does not start losing its energy after a specific time period like 10 minutes.
The energy stored in the imaging plate remains relatively stable until the plate is intentionally processed. After the imaging plate is exposed to radiation, it retains the energy stored within it until it undergoes a processing step. The processing typically involves scanning the imaging plate with a laser or light source, which stimulates the release of the trapped energy. This released energy is then detected and converted into a digital image.
The time between exposure and processing can vary depending on the specific radiographic workflow and equipment used. It is not a fixed time frame but is determined based on the operational needs and procedures of the imaging facility.
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what is the greatest distance you can be from base camp at the end of the third displacement regardless of direction
To determine the greatest distance you can be from the base camp at the end of the third displacement, regardless of direction, we need more specific information about the magnitudes and directions of the displacements.
Displacement is a vector quantity that has both magnitude and direction. The distance covered during multiple displacements depends on the individual magnitudes and directions of each displacement. Without specific values, it is not possible to determine the exact greatest distance from the base camp.
If you provide the magnitudes and directions of the three displacements, I can help you calculate the total distance and determine the maximum possible distance from the base camp at the end of the third displacement.
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o
10 points
What is the period of a pendulum consisting of a 6-kg object oscillating
on a 4-m string? *
0.25 s
2 s
O O O
35
45
A mass-spring system makes 20 complete oscillations in 5 seconds. What 10 points
is the period and frequency of the oscillations? *
Hi there!
1.
The period of a pendulum can be calculated using the following equation:
\(\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}\)
T = period (s)
L = length of string (m)
g = acceleration due to gravity (m/s²)
Plug in the values:
\(T = 2\pi \sqrt{\frac{4}{9.8}} = \boxed{4.014 s}\)
2.
Calculate the period:
\(T = \frac{\text{Time}}{\# of oscillations} = \frac{5}{20} = \boxed{0.4 s }\)
Frequency is the reciprocal of the period, so:
\(f = \frac{1}{T} = \frac{1}{0.4} = \boxed{2.5 Hz}\)
Two equal mass objects are moving towards each other with equal speeds. If they collide completely inelastically, which of the following situations will occur?
The two equal-mass objects will stick together and move as one object after the completely inelastic collision.
In an inelastic collision, the two objects involved stick together and move as a single object after the collision. Since the objects have equal masses and are moving towards each other at equal speeds, their momenta will be equal and opposite before the collision.
During the collision, the objects come into contact and exert forces on each other. These internal forces cause the objects to deform and redistribute their velocities. However, due to the conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision.
Since the initial momenta of the objects are equal and opposite, the final momentum of the combined object will also be zero. This means the objects will stick together and move as one object after the collision, with a common velocity. This scenario is known as a completely inelastic collision.
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In 3–4 sentences, describe how a particle accelerator works and give an example of the applications of the discoveries made with them.(4 points)
While being employed for study, the beam strikes the intended target, allowing researchers to learn a little about atoms, structures, and physical principles.
How does a collider operate?Particle beams are directed and focused by electric flux, and particle accelerators utilize electric fields that compress and enhance the energies of the beam. The protons or electrons that need to be accelerated come from the particle source.
What kind of device is a particle accelerator like?Cathode ray tubes seen in tv sets with X-ray generators are common examples of machines. These low-energy accelerators employ a single electrode pair with some few kilowatts or Current dc source across them. The target acts as one of the cathode in an X-ray generator.
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if the moment of inertia of the shaded area about the a-a' axis is 18e6mm^4 what is the moment of inertia about the b-b' axis
The moment of inertia about the b-b' axis is 24.6E6 mm^4.
To find the moment of inertia of the shaded area about the B-B' axis, we can use the formula I = ∑m*r^2, where m is the mass of each particle in the shaded area, r is the distance of each particle from the B-B' axis, and the sum is taken over all particles in the shaded area.
We are given that the moment of inertia of the shaded area about the A-A' axis is
18E6 mm^4,and that the area of the shaded region is
A = 6E3 mm^2.We are also given the distances
ds = 50 mm and d₂ = 10 mm,which correspond to the distances of the two particles in the shaded region from the B-B' axis.
The mass of each particle in the shaded region can be calculated by dividing the total mass of the region (which is equal to the product of the area and the density of the material) by the number of particles. Since the density of the material is not given, we cannot calculate the mass of each particle.
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Complete Question:
If the moment of inertia of the shaded area about the A-A' axis is 18E6 mm, what is the moment of inertia about the B-B' axis?
Given: A6E3 mm², ds-50 mm, d₂-10 mm
a. none of these answers
B. 21.2E6 mm^4
C 25.2E6 mm^4
D. 26.3E6 mm^4
E. 24.6E6 mm^4
Metal cutters have long handles.Give Reason.
Answer: For leverage and so the can be easily handled.
Explanation:
2. A pitcher threw a baseball straight up at 39 meters per second. What
was the ball's velocity after 2.50 seconds?
Improperly installed air conditioners can occasionally fall from apartment windows down onto the road below. How long does a pedestrian have to get out of the way of an air conditioner falling eight stories [24m] hello I just need help idea my vi vf t d a and I am not certain if it is a horizontal question or not
Given data:
* The distance traveled by the air conditioner is,
\(d=24\text{ m}\)Solution:
As the air conditioner is falling freely under the action of gravity.
Thus, the acceleration of the air conditioner is equal to the acceleration due to gravity.
\(\begin{gathered} a=g \\ a=9.8ms^{-2} \end{gathered}\)As the air conditione ris falling itself from the height.
Thus, the initial velocity of the air conditoner is,
\(v_i=0\text{ m/s}\)By the kinematics equation, the final velocity of the air conditioner is,
\(v^2_f-v^2_i=2ad\)Substituting the known values,
\(\begin{gathered} v^2_f-0=2\times9.8\times24 \\ v^2_f=470.4 \\ v_f=21.69\text{ m/s} \end{gathered}\)Thus, the final velocity of the air conditioner is 21.69 m/s.
By the kinematics equation, the time taken by the air conditioner,
\(v_f-v_i=at\)where t is the time taken by the air conditioner to reach the ground,
Substituting the known values,
\(\begin{gathered} 21.69-0=9.8t \\ t=\frac{21,69}{9.8} \\ t=2.21\text{ s} \end{gathered}\)Thus, the time taken by the air conditioner ot reach the ground is 2.21 seconds.
Two bowling balls are rolling towards each other at constant velocities. ball one has a velocity of 3 ft/s and ball two has a velocity of 5 ft/s. if they start 30 feet apart, how long (in seconds) will it take for them to collide?
The two balls will collide in 2 seconds if they start 30 feet apart.
To calculate the time it takes for the two balls to collide, we first need to calculate the distance between them. The distance between two objects is equal to their speed multiplied by the time it takes them to travel that distance: velocity × time = distance
In this case, we want our distance formula to be 3 ft/s × 2 seconds = 6 ft
Then, using our formula, we can find how long it would take for the two balls to collide by plugging in our numbers: 6 ft + 5 ft = 11 ft. When we add 11 ft into both sides of our equation, we get 0 seconds, which means that when these two balls collide, they collide at the same time.
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a ball moving at 60 m/s toward a wall to its right gets back at a speed of 40m/s after striking the wall . if the mass of the ball of
3kg . what is the change in momentum
Answer:
-300 kg*m/s
Explanation:
The velocity of the ball before the collision is +60 m/s, and the velocity after the collision is -40 m/s (since the ball bounces back in the opposite direction). The mass of the ball is 3 kg.
The momentum of the ball before the collision can be calculated as:
p1 = mv1 = 3 kg * 60 m/s = 180 kgm/s
The momentum of the ball after the collision can be calculated as:
p2 = mv2 = 3 kg * (-40 m/s) = -120 kgm/s
The change in momentum is then:
Δp = p2 - p1 = (-120 kgm/s) - (180 kgm/s) = -300 kg*m/s
Note that the negative sign indicates that the momentum of the ball has decreased (since it bounced back in the opposite direction), and the magnitude of the change in momentum is 300 kg*m/s.