A rock sample has the density of 3.2 g/cm3. When you place it in a graduated cylinder with water, the water level rises from 50 ml to 57 ml. What is the mass of the rock?

Answer:

C)

Explanation:

a. The rate law for this reaction is: Rate = k[Cl] [H₂]. This means that the rate of the reaction is directly proportional to the concentrations of both Cl and H₂ molecules.

Rate law is an equation that describes the rate of a chemical reaction as a function of the concentrations of reactants. The rate law allows us to describe how the rate of a reaction changes when the concentrations of reactants are changed. It is derived from the rate equation, which is a mathematical expression that can be used to calculate the rate of a reaction from the concentrations of the reactants and the rate constant.

b. The rate law for this reaction is: Rate = k[O] [Os]. This means that the rate of the reaction is directly proportional to the concentrations of both O and Os molecules.
c. The rate law for this reaction is: Rate = k[NO₂]₂. This means that the rate of the reaction is directly proportional to the square of the concentration of NO₂ molecules.

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Complete Question:

Answer:

The answer to your question is given below

Explanation:

We'll begin by converting 500 cm³ to L. This can be obtained as follow:

1000 cm³ = 1 L

Therefore,

500 cm³ = 500 cm³× 1 L / 1000 cm³

500 cm³ = 0.5 L

Next, we shall determine the number of mole of Na₂CO₃ in the solution. This can be obtained as follow:

Volume = 0.5 L

Molarity = 2 M

Mole of Na₂CO₃ =?

Molarity = mole /Volume

2 = Mole of Na₂CO₃ / 0.5

Cross multiply

Mole of Na₂CO₃ = 2 × 0.5

Mole of Na₂CO₃ = 1 mole

Finally, we shall determine the mass of 1 mole of Na₂CO₃. This can be obtained as follow:

Mole of Na₂CO₃ = 1 mole

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mass of Na₂CO₃ =?

Mass = mole × molar mass

Mass of Na₂CO₃ = 1 × 106

Mass of Na₂CO₃ = 106 g

Thus, to prepare the solution, weigh 106 g of Na₂CO₃ and dissolve in 500 cm³ (i.e 0.5 L) of water.

The volume in cubic meters is 4096m.

To calculate the volume or volume of an object or room in cubic feet measure the length, width, and height in feet and multiply length x width x height. The volume of an object is the amount of space it fills. Large capacity is measured in cubic meters m3. Smaller volumes are measured in cubic centimeters cm3 or cubic millimeters mm3.

Board foot is the most commonly used standard in lumber and lumber. One foot of board is equivalent to 144 cubic inches of lumber, or a board 1 inch thick, 12 inches wide, and 1 foot long. The second unit of measure is code. The volume of a box can be calculated as length x width x height. Taking a single-layer box as an example 102 x 102 x 102 is equivalent to 1,061,208 cubic millimeters. In metric units, volume is usually expressed in millimeters and liters.

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The amount, in mL, of the suspension that should be given to an infant weighing 17 lb will be 1.16 mL

0.8 mL of the liquid contains 80.0 mg of the drug.

The recommended dose is 15 mg per kg of body weight

The infant to be given the drug weighs 17 lb.

First, let's convert the weight of the infant to kg.

1 lb = 453.59 g

17 lb =       453.59 x 17/1

                   = 7711.03 g

1000 g = 1 kg

7711.03 g = 7711.03 x 1/1000

               = 7.711 kg

So, the baby's weight is 7.711 kg.

The drug dose for the baby can thus be calculated as:

15 mg x 7.711 = 115.67 mg

But 0.8 mL of the drug contains only 80.0 mg. How many mL will contain 115.67 mg?

                   0.8 x 115.67/ 80.0 = 1.16 mL

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An average copper penny minted in the 1960s contained about 3.000g of Copper. 866.49 g chalcopyrite had to be mined to produce 100 pennies.

The term mole is defined as the amount of substance of a system which contains as many elementary entities.

1 mole is equal to 6.023 × 10 ²³ molecules.

Given:

Copper used = 100 pennies x 3.0g Cu per penny

= 300.0 g Cu

Then, identify the pathway and molar ratio from Cu formed back to CuFeS₂ required using the balanced reactions:

1 Cu₂S from 2 CuS : 2Cu from 1 Cu₂S : 2CuS from 2CuFeS₂

Therefore, 2Cu from 2CuFeS₂, they are in same molar ratio.

Now, convert g Cu to moles and g of CuFeS₂

= 300.0 g Cu × 1 mol Cu / 63.546g Cu × 2 mol CuFeS₂ / 2 moles Cu

= 4.72 moles CuFeS₂

The chalcopyrite had to be mined to produce 4.72 moles CuFeS₂ × 183.54 g CuFeS₂ / 1 mole CuFeS₂

= 866.49 g CuFeS₂

Thus,866.49 g chalcopyrite had to be mined to produce 100 pennies.

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Answer: C. Gas particles move faster and farther apart at higher temperatures.

Explanation:

The options include:

A. the number of gas particles increases at higher temperatures

B. the number of gas particles decreases at higher temperatures

C. gas particles move faster and farther apart at higher temperatures

D. gas particles move more slowly and get closer together at higher temperatures

The statement that describes how the outcome (dependent) variable changes as a result of the changes made to the tested (independent) variable is that gas particles move faster and farther apart at higher temperatures.

It should be noted that the particles in the gases will collide more frequently with one another because of the shorter space that is between them.

The increase in the temperature will bring about a faster movement of the particles which in turn, brings about a rise in the diffusion rate and also the collision rate.

Hydrobromic acid...

I hope that it helps you...

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The volume (in mL) of the 0.167 M sodium hydroxide, NaOH solution needed is 26.9 mL

The balanced equation for the reaction is given below:

HClO₄ + NaOH —> NaClO₄ + H₂O

The volume of NaOH can be obtained as follow:

MaVa / MbVb = nA / nB

(0.242 × 18.53) / (0.167 × Vb) = 1

4.48426 / (0.167 × Vb) = 1

Cross multiply

0.167 × Vb = 4.48426

Divide both side by 0.167

Vb = 4.48426 / 0.167

Vb = 26.9 mL

Thus, the volume of the NaOH solution needed is 26.9 mL

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Answer: Cytosine, Thymine, Cytosine, Guanine (option A)

Explanation:

In DNA strands, you must use base-pairing rules to complete strands.

The base-pairing rules are:

Adenine (A) bonds with Thymine (T)

Guanine (G) bonds with Cytosine (C)

By using these rules, you can pair the sequence GAGC with CTCG

The sequence CTCG is also represented as the bases Cytosine, Thymine, Cytosine, and Guanine, making A the correct answer.

I hope this helps!

Answer:

electrons are combining with other electrons

The maximum allowable annual dose of radiation has been set at 1000 uSv by the worldwide commission on radiological protection. At this threshold or lower, there is no risk.

What is S(sievert)?

Here are some details concerning the risks increasing radiation levels cause to our health:

Therefore the correct choice is an option (A).

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Answer:

Answer D

Explanation:from founders Edtell :

A dose of 1000 uSv is believed to carry a 1/100,000 risk of getting cancer over 40 years due to your exposure to radiation. The average dose is around 2400 uSv.

Answer:

26.981539 u

Explanation:

Answer:

Evaporation is a change of phase from liquid to gas explained as follows : When particles in the liquid phase are heated, they gain kinetic energy and move faster and further apart.

Answer:

pH of the solution will decrease & hydronium ion concentration will increase in the solution as the acid is added.

Explanation:

Answer:

Conc = 1.64 Mol / dm3

Explanation:

We have to first put down the equation of the neutralization reaction. This is given as;

2HCl + Ca(OH)2 --> CaCl2  + 2H2O

This means that 2 mol of HCl requires 1 mol of Ca(OH)2.

2 = 1

x = 0.042

x = 0.084 mol of HCl required.

Volume = 51.21 ml = 0.05121 dm3

Concentration = Mass / Volume

Conc = 0.084 / 0.05121

Conc = 1.64 Mol / dm3

Answer:

1) Oxidation-Reduction (Redox) Reaction

2) Combustion Reaction

3) Decomposition Reaction

4) Synthesis Reaction

5) Single Displacement (Substitution) Reaction

6) Double Displacement (Metathesis) Reaction

7) Acid-Base Neutralization Reaction

8) Precipitation Reaction

Here are the Answer:

1. Oxidation-Reduction (Redox) Reaction

2. Combustion Reaction

3. Decomposition Reaction

4. Synthesis Reaction

5. Single Displacement (Substitution) Reaction

6. Double Displacement (Metathesis) Reaction

7. Acid-Base Neutralization Reaction

8. Precipitation Reaction

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Answer:

A.

Explanation:

The pressure of 1.27 L of a gas at 288°C, if the gas had a volume of 875 ml at 145 kPa and 176°C is 1.195 atm.

Ideal gas equation of any gas will be represented as:
PV = nRT, where

P = pressure

V = volume

n = moles

R = universal gas constant

T = temperature

First we calculate the moles of gas, when the volume of gas 875 ml at

145 kPa and 176°C as:

n = (1.431atm)(0.875L) / (0.082L.atm/K.mol)(449.15K)

n = 1.252 / 36.83 = 0.033 moles

Now we measure the pressure of 0.033 moles of gas of 1.27 L of a gas at 288°C as:

P = (0.033mol)(0.082L.atm/K.mol)(561K) / (1.27L) = 1.195 atm

Hence required pressure of gas is 1.195 atm.

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Answer:

PCl₃

Explanation:

To determine the empirical formula of a compound, we need to follow a series of steps.

Step 1: Divide each percent composition by the atomic mass of the element

P: 22.6/30.97 = 0.729

Cl: 77.4/35.45 = 2.18

Step 2: Divide all the numbers by the smallest one, i.e. 0.729

P: 0.729/0.729 = 1

Cl: 2.18/0.729 ≈ 3

The empirical formula of the compound is PCl₃.

Answer:

zero

Explanation:

Answer:

Zero.

Explanation:

The overall formal charge in CF4 is zero.

To obtain more accurate values of the densities of the pennies:

The density of a substance is the ratio of the mass of the substance to the volume of that substance.

It is a measure of the compactness of the matter in a substance.

The densities of the pennies made before 1982 was 8.7 g/ml

The actual density of pennies made before 1982 is about 8.8 g/mL.

The densities of the pennies made after 1982 was 6.9 g/ml

The actual density of pennies made after 1982 is about 7.2 g/mL.

Due to several random and experimental errors, the values obtained from the experiment are not exactly the same with the accepted values.

To obtain more accurate values:

In conclusion, the densities varied as as a result of random and experimental errors.

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Answer:

Prior to 1982, the densities of pennies were 8.7 g/ml.

The density of pre-1982 pennies is approximately 8.8 g/mL.

The densities of pennies produced after 1982 were 6.9 g/ml.

The density of pennies made after 1982 is approximately 7.2 g/mL.

The values obtained from the experiment do not exactly match the accepted values due to several random and experimental errors.

Explanation:

The piece of evidence that best identifies the type of reaction as nuclear or chemical is: Chemical, because a new substance is formed. Option 4

In this scenario, the observation that a new substance is formed is a key characteristic of a chemical reaction. Chemical reactions involve the rearrangement of atoms to form different substances with distinct properties. The formation of a new substance indicates a chemical change has occurred.

The other pieces of evidence listed do not necessarily point to a nuclear reaction:

Chemical, because energy is released during the reaction: Energy can be released in both nuclear and chemical reactions, so this observation alone is not sufficient to determine the type of reaction.

Nuclear, because energy is released during the reaction: While energy can be released in nuclear reactions, it is not exclusive to them. Chemical reactions can also release energy, such as in exothermic reactions.

Nuclear, because the mass decreased after the reaction: This observation suggests a change in mass, which could be indicative of a nuclear reaction. However, it is important to consider that chemical reactions can also involve changes in mass, such as the formation of gases or dissolution of a solid.

Overall, the most conclusive evidence to identify the type of reaction is the formation of a new substance, which aligns with a chemical reaction.

Option 4

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Answer:

A. The reaction shifts to the right (products) and the concentrations of I and H₂ decrease.

Explanation:

If gas is removed from the system at equilibrium, the system will try to compensate for the loss by shifting the reaction in a direction that produces more gas molecules. This is known as Le Chatelier's principle, which states that a system at equilibrium will respond to a disturbance by shifting in a way that minimizes the effect of the disturbance.

In this case, since gas is being removed from the system, the reaction will shift to the side that produces more gas molecules. Looking at the balanced equation, we can see that 2HI(g) has a greater number of gas molecules compared to H₂(g) and I₂(g). Therefore, the system will shift to the right (products) to produce more HI(g) and reestablish equilibrium.

Answer:

0.001968 M min-1

Explanation:

NH2NO2(aq) --> N2O(g) + H2O(l)

[NH2NO2],M       0.978 0.476 0.232    0.113

time, min              0          255     510      765

The average rate of disappearance over the time period form t = 0 min to t = 255 min is given as;

Average rate = Change in concentration / time taken

Change in concentration = Final Concentration - Initial concentration

Change = 0.476 - 0.978 = 0.502

time taken = 255min - 0min = 255 min

Average rate = 0.502 / 255 = 0.001968 M min-1

A: The biodiversity of the pond has decreased.

B: The species richness

Biodiversity is all life on this earth including plants, animals, fungi and microorganisms as well as the various genetic materials they contain and the diversity of the ecological systems in which they live. This includes the relative abundance and genetic diversity of organisms from all habitats, whether on land, sea or other aquatic systems.

Biodiversity can be classified into three levels:

a. Species diversity

Species or types have the meaning, individuals who have morphological, anatomical, physiological similarities and are able to interbreed with each other (inter-hybridization) which produce fertile offspring to continue their generation.

Another example is the diversity of species in coconut trees, palm trees, areca palm trees and also in palm trees.

b. Genetic diversity

Gene diversity is the diversity of individuals within one type of living thing. Gene diversity results in variations between individuals of the same kind. Examples of diversity at this gene level are white roses, red roses, and yellow roses which have differences, namely different in terms of flower color.

c. Ecosystem diversity

Ecosystem can be interpreted as a relationship or mutual interaction between one living thing and another living thing and also between living things and their environment. Every living thing will only grow and develop in a suitable environment.

Your question is incomplete but most probably your full question was:

Directions: Each of the questions or incomplete statements below is followed by five suggested answers or completions. Select the one that is best in each case.

A) A one-hectare pond is sampled in early September. The sample yields 1 small catfish as well as 17 benthic invertebrates that represent 10 species. If the pond is resampled a year later, which of the following would best indicate that the pond had been adversely affected by adjacent development?

B) A one-hectare pond is sampled in early September. The sample yields 1 small catfish as well as 17 benthic invertebrates that represent 10 species. Which of the following can be estimated from the sample for the invertebrates in the pond?

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The mass, in grams, of one atom of magnesium is 4.040 × 10^-23 g (to 4 significant figures).

Mass of 1 mole of magnesium = 24.32 g

Number of atoms in 1 mole of magnesium = 6.022 × 10²³

We are to calculate the mass of one atom of magnesium.

We can start by finding the mass of one mole of magnesium, which is given as 24.32 g.

1 mole of magnesium contains 6.022 × 10²³ atoms of magnesium, which means the mass of one magnesium atom is equal to the mass of one mole divided by the number of atoms in one mole.

Thus, the mass of one atom of magnesium can be calculated as follows:

Mass of one magnesium atom = mass of 1 mole of magnesium / number of atoms in 1 mole

= 24.32 g / (6.022 × 10²³)

= 4.04 × 10^-23 g

We can express this value in scientific notation to four significant figures as: 4.040 × 10^-23 g.

Therefore, the mass, in grams, of one atom of magnesium is :

4.040 × 10^-23 g (to 4 significant figures).

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