A running track has two straight sides with length 140 m and two semicircle ends with radius 70 m. It takes Kat 40 seconds to jog 160 m. How long would it take her to jog around the track 51 times? Give your answer in hours and minutes, to the nearest minute.

Answer:

21°

angles don't change in dilutions but lengths do

plssmark brainliesttt

Answer:

A' = (3, 6)

B' = (9, -3)

C' = (-12, -6)

Step-by-step explanation:

you can mulitply both the x and y coordinates of each point by the scale factor (3)

point (1, 2) becomes point (3, 6)

(3, -1) becomes (9, -3)

(-4, -2) becomes (-12, -6)

hope this helps!! have a lovely day :)

{this is why whoever wrote the problem gave that hint--you can follow through on that logic, but just remember that it has to be a scaled version of the original figure--so the ratios between points (and x/y values) must be consistent}

Answer:

y = -x + 9

Step-by-step explanation:

The line that passes through the points (-2,4) and (0,6) has a slope of 1, and a y intercept of 6. The equation to the first line is y = x + 6. and perpendicular lines always have the opposite, reciprocal slope of the other line. So the slope for the second line would be -1. A line with the slope of -1 and a point of (5,4) would contain the points (5,4) , (4,5) , (3,6) , (2,7) , (1,8) , and (0,9) , which is the y intercept for the second line. So the equation for the second line would be y = -x + 9

The volume of a silo cylinder with radius of 8 feet and height of 36 feet is 7235 feet cube.

The volume of a cylinder can be calculated as follows;

Volume = πr²h

where

Therefore,

r = 8 ft

h = 36 ft

volume = 3.14 × 8² × 36

volume = 3.14 × 64 × 36

volume of the silo = 7234.56

Therefore, the volume of the cylindrical silo is 7235 ft³

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Given:

The combination is:

\(^{34}C_{21}\)

To find:

The \(^{34}C_{21}\) as the sum of two terms from pascals triangle.

Solution:

According to the pascals triangle:

\(^{n+1}C_{r+1}=^nC_r+^nC_{r+1}\)

We have,

\(^{34}C_{21}\)

Using the pascals triangle formula, we get

\(^{34}C_{21}=^{33}C_{20}+^{33}C_{21}\)

Therefore, \(^{34}C_{21}=^{33}C_{20}+^{33}C_{21}\).

Compound interest formula:

A = P (1+ r/n) ^tn

Where:

P = initial principal balance

r= interest rate (decimal form)

t = number of periods

n= number of times interest is compounded in the period

A= balance after t periods

Replacing:

A = 25,000 (1+ 0.021/365)^16*365

A = 25,000 (1 + 0.0000575)^5,840

A = $34,983.14

To determine if the distribution of SAT scores is normal for any group, we need to examine the characteristics of the scores and compare them to the features of a normal distribution, such as symmetry and the percentages of scores within specified standard deviations from the mean. A sketch of a normal distribution would have a bell shape with the peak at the mean value (852 in this case) and tails that taper off as scores move further from the mean.

Based on the given information, the average SAT score for the Native American male is 852 with a standard deviation of 120 points. To determine if the distribution of SAT scores is normal for any group, we can follow these steps:

1. Consider the characteristics of a normal distribution: It is symmetrical, bell-shaped, and has a mean value at its peak.

2. If the distribution of SAT scores were normal, we would expect approximately 68% of the scores to fall within one standard deviation (120 points) from the mean (852), meaning scores would be between 732 and 972. Similarly, about 95% of the scores would fall within two standard deviations (240 points) from the mean, or between 612 and 1092.

3. To sketch the distribution, draw a symmetrical bell-shaped curve with the peak at 852. The curve should taper off as the scores move further away from the mean, indicating fewer individuals with scores in those ranges.

4. Without more specific data, we cannot definitively say whether the SAT scores' distribution is normal for any group. However, if the distribution closely matches the characteristics outlined above, it can be considered approximately normal.

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The ratios of their perimeters and the ratios of their areas are 1) 3:1 and 9:1 and 2) 7:4 and 49:16.

Given the scale factor of two similar polygons, we need to find the ratio of their perimeters and the ratios of their areas,

To find the ratio of the perimeters of two similar polygons, we can simply write the scale factor as it is because the ratio of the perimeter is equal to the ration of the corresponding lengths.

1) So, perimeter = 3:1

The ratio of areas between two similar polygons is equal to the square of the scale factor.

Since the scale factor is 3:1, the ratio of their areas is:

(Ratio of areas) = (Scale factor)² = 9/1 = 9:1

Similarly,

2) Perimeter = 7:4

Area = 49/16

Hence the ratios of their perimeters and the ratios of their areas are 1) 3:1 and 9:1 and 2) 7:4 and 49:16.

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The formula for the uncertainty of x, Δx, is given by: Δx = √(\(b^2\) * Δ\(c^2\)/\(a^2\) + \(c^2\) * Δ\(a^2\)/\(a^4\) + \(c^2\) * Δ\(b^2\)/\(a^2\)). To derive the formula for the uncertainty of x when x = c/a * b, we can use partial derivatives.

The uncertainty in x can be determined by considering the uncertainties in c, a, and b and their respective contributions to the overall uncertainty. By applying the rules of error propagation, we can derive a formula that expresses the uncertainty in x based on the uncertainties in c, a, and b.

To derive the formula for the uncertainty of x, we start by considering the relationship between x, c, a, and b: x = c/a * b. Let's denote the uncertainties in c, a, and b as Δc, Δa, and Δb, respectively.

Using the rules of error propagation, we can express the uncertainty in x, Δx, as:

Δx = √\(((\partial x/\partial c * \Delta c)^2 + (\partial x/\partial a * \Delta a)^2 + (\partial x/\partial b * \Delta b)^2)\)

Taking partial derivatives of x with respect to c, a, and b, we have:

∂x/∂c = 1/a * b

∂x/∂a = -c/\(a^2\) * b

∂x/∂b = c/a

Substituting these derivatives into the formula for Δx, we get:

Δx = √\(((1/a * b * \Delta c)^2 + (-c/a^2 * b * \Delta a)^2 + (c/a * \Delta b)^2)\)

Simplifying further, we can rewrite this as:

Δx = √(\(b^2\) * Δ\(c^2\)/\(a^2\) + \(c^2\) * Δ\(a^2\)/\(a^4\)+ \(c^2\) * Δ\(b^2\)/\(a^2\))

Therefore, the formula for the uncertainty of x, Δx, is given by:

Δx = √(\(b^2\) * Δ\(c^2\)/\(a^2\) + \(c^2\)* Δ\(a^2\)/\(a^4\) + \(c^2\) * Δ\(b^2\)/\(a^2\))

This formula allows us to calculate the uncertainty in x based on the uncertainties in c, a, and b.

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The solution to the recurrence T(n) = T(n-1) + log(n) is O(log n).

To argue the solution to the recurrence T(n) = T(n-1) + log(n) is O(log n), we can use the master theorem. The master theorem states that if a recurrence is in the form T(n) = aT(n/b) + f(n), where a is the number of subproblems, n/b is the size of each subproblem, and f(n) is the cost of dividing the problem into subproblems and combining the solutions, then the running time is given by:

T(n) = O(n^logb a) if f(n) = O(n^logb a - ϵ)
T(n) = O(n^logb a log n) if f(n) = Θ(n^logb a)
T(n) = O(f(n)) if f(n) = Ω(n^logb a + ϵ)

In this case, a = 1 and b = 1, so we have:

T(n) = T(n-1) + log(n)
    = T(n-2) + log(n-1) + log(n)
    = T(n-3) + log(n-2) + log(n-1) + log(n)
    = ...
    = T(1) + log(2) + log(3) + ... + log(n-1) + log(n)

The sum of the logarithms is:

log(2) + log(3) + ... + log(n)
= log(2*3*...*n)
= log(n!)

By Stirling's approximation, we have:

log(n!) = n log n - n + O(log n)

Therefore, we can conclude that:

T(n) = O(n log n)

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Answer:

Net force: 14 kilograms

Acceleration: 2 Newtons

Step-by-step explanation:

The speed that an aeroplane is intended to fly at is called its maximum operating speed (VA). With elevations of 12, 15, and 18 degrees, the lift and G-force grow.

 Speed.

It is the rate at which a displacement adapts to its surroundings. A body's speed is a scalar quantity since it is directionless. It is also the rate at which displacement in relation to the environment is shifting in a particular direction.

Here,

The maximum operational speed of an aeroplane is the speed at which it is designed to fly (VA). Elevations of 12, 15, and 18 degrees result in increasing lift and G-force.

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Answer:

C) 1/2

Step-by-step explanation:

We know that 3/8 cup of brown sugar and 1/3 cup of white sugar are mixed together to make the sugar mixture.

From this sugar mixture, 1/4 cup is set aside for the crumb topping.

To find out how much sugar mixture is used to make the cake, we need to subtract the amount set aside for the crumb topping from the total sugar mixture.

We can start by converting the mixed unit of measurement (brown sugar in cups and white sugar in cups) to a single unit of measurement (cups)

3/8 cup of brown sugar + 1/3 cup of white sugar = (3/8)+(1/3) = 5/12 cup + 4/12 cup = 9/12 cup.

1/4 cup is set aside for the crumb topping.

So, the remaining sugar mixture used to make the cake is 9/12 cup - 1/4 cup = (9/12) - (1/4) = (9-3)/12 = 6/12 cup = 0.5 cup

The probability of obtaining a head on the next toss of a coin after obtaining two heads from two tosses is still 1/2 or 50%.

This is because each coin toss is an independent event, and the outcome of one toss does not affect the outcome of another toss. Therefore, the fact that two heads have been obtained in the previous two tosses does not change the probability of obtaining a head on the next toss, which is always 1/2 or 0.5 for a fair coin.

Probability is the likelihood of an event occurring. The values are between 0 and 1. The closer it is to 1, the greater the probability.

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To determine the percentage of students who passed the 90 point statistics test, we need to know the lowest score achieved by a passing student. The stem plot shows that the lowest score recorded was 54 out of 90, which was also the lowest possible passing grade.

This means that all students who scored 54 or above passed the test. Out of the 26 students, we do not know how many scored above 54. Therefore, we cannot determine the exact percentage of students who passed the test.

However, we can say that the percentage of students who passed the test is equal to or greater than the percentage of students who scored 54 or above out of the total number of students who took the test. We can calculate this percentage by dividing the number of students who scored 54 or above by 26 and multiplying the result by 100.

To find the percentage of students who passed the test, follow these steps:

1. Determine the passing grade: The lowest possible passing grade is 54 out of 90 points.
2. Count the number of students who scored at least 54 points on the stem plot.
3. Calculate the percentage of students who passed: Divide the number of students who passed (from step 2) by the total number of students (26), then multiply by 100 to get the percentage.

For example, if 18 students scored at least 54 points, the calculation would be (18/26) * 100 = 69.23%. This means that 69.23% of students achieved a passing grade on the test.

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Answer:

the total will be $27.31

15 percent tip is $3.56

Step-by-step explanation:

Answer:

(5(x-4))0

evaluate

1

Step-by-step explanation:

your answer is one i believe

Answer:

D. 22  2/3

Step-by-step explanation:

To find area you multiply length times width.

Here:

L = 5 2/3

and W = 4

So multiply 5 2/3 by 4, you get 22 2/3

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Answer:

9x+1

Step-by-step explanation:

combine 2x+7x then add the 1

Answer:

Seria 2x + 1 + 7x entonces 2x + 7x = 9x + 1 = 10x

The test statistic is at α = 0.10 we have sufficient evidence that means weight is given by μ = 132 lb.

What is p-value?

The p-value, used in null-hypothesis significance testing, represents the likelihood that the test findings will be at least as extreme as the result actually observed, presuming that the null hypothesis is true.

As given,

State the hypothesis,

Ha: μ = 132

Ha: μ ≠ 132 (two failed test)

Test satisfies:

As σ is unknown we will use t-test satisfies

t = (x - μ)/(s/√n)

Substitute values,

t = (137 - 132)/(14.2/√20)

t = 1.57

t satisfies is 1.57.

Critical values,

P(t < tc) = P(t < tc) = 0.05

using t table at df = 19

tc = ±1.729

So value is tc = (-1.729, 1.729)

P-value:

P(t > ItstatI) = p-value

P(t > I1.57I) = p-value

Using t-table

p-value = 0.1329

given

α = 0.10

So, p-value < α

Do not reject Null hypothesis.

Conclusion:

At α = 0.10 we have sufficient evidence that means weight is given by μ = 132 lb.

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1. On simplifying the radical expression √28 the result is 2√7.

2. On simplifying the radical expression √40 the result is 2√10.

3. On simplifying the radical expression √72 the result is 6√3.

4. On simplifying the radical expression √99 the result is 3√11.

What is a radical expression?

Radical expressions are algebraic expressions involving radicals. The radical expressions consist of the root of an algebraic expression (number, variables, or combination of both). The root can be an nth root, a square root, or a cube root.

The first radical expression is -

√28

Take the LCM of 28.

The LCM is obtained as - 2 × 2 × 7.

The number that is repeated twice will be outside the square root symbol. The number that is obtained only once should be inside the square root symbol.

So, the simple form is 2√7.

Therefore, the expression is 2√7.

The second radical expression is -

√40

Take the LCM of 40.

The LCM is obtained as - 2 × 2 × 2 × 5.

The number that is repeated twice will be outside the square root symbol. The number that is obtained only once should be inside the square root symbol.

So, the simple form is 2√10.

Therefore, the expression is 2√10.

The third radical expression is -

√72

Take the LCM of 72.

The LCM is obtained as - 2 × 2 × 2 × 3× 3.

The number that is repeated twice will be outside the square root symbol. The number that is obtained only once should be inside the square root symbol.

So, the simple form is 6√3.

Therefore, the expression is 6√3.

The fourth radical expression is -

√99

Take the LCM of 99.

The LCM is obtained as - 3 × 3 × 11.

The number that is repeated twice will be outside the square root symbol. The number that is obtained only once should be inside the square root symbol.

So, the simple form is 3√11.

Therefore, the expression is 3√11.

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The length of the microorganism that measure 5μm is equivalent to 0.005 mm

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

To solve this problem the we have to convert the units with the given information.

1mm is equal to 1000 μm

5μm * (1 mm/1000μm) = (5*1) / 1000 = 5/1000 = 0.005 mm = 5x10^-3 mm

The length of the microorganism that measure 5μm is equivalent to 0.005 mm

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Answer: No because 7^2 + 12^2 doesn’t equal 14^2

Step-by-step explanation:

7^2 + 12^2 equals 193. But 14^2 = 196 so the answer is no.

Answer:

12 and 18

Step-by-step explanation:

Lets say the two numbers are A and B, with A the smaller.

We are told that A/B = 2/3     [in the ratio of 2 to 3]

We also find that A + B = 30  [Their sum is 30]

Rearrange the first equation to isolate A:

A/B = 2/3

A = 2B/3        [multiply both sides by B]

Now use this value of A in the second equation:

A + B = 30

2B/3 + B = 30

(2/3)B + (3/3)B = 30

(5/3)B = 30

B = (30)(3/5)

B = 6*3

B = 18

Since A + B = 30:

A + B = 30

A + 18 = 30

A = 12

A is 12 and B is 18

===================

Check:

Does A/B = 2/3??

(12/18) = (6/9)

(6/9) = (2/3)   YES

Does A + B = 30  ???

12 + 18 = 30   YES

Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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The separate samples would be needed for a two-factor, independent-measures is 6.

According to the statement

we have to find that the number of separate samples be required with the help of the given information.

So, For this purpose, we know that the

Sample is a representative part or a single item from a larger whole or group especially when presented for inspection or shown as evidence of quality.

So,

From given information from the statement is :

2 levels of factor a and 3 levels of factor b

And Now, The

Number of samples required = 2*3

Number of sample required = 6.

hence there are the 6 separate samples needed.

So, The separate samples would be needed for a two-factor, independent-measures is 6.

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Answer:

the greatest common factor is 6

The assumption that is not typically associated with linear programming models is A) normality.

Linear programming models do not assume normality of the variables or the distribution of the data. Linear programming deals with optimizing linear objective functions subject to linear constraints, without any specific assumptions about the underlying distribution of the data. The focus is on finding the optimal solution within the feasible region defined by the constraints.

The other assumptions mentioned in the options are commonly associated with linear programming models:

B) Certainty: Linear programming assumes that all the data and parameters are known with certainty.

C) Divisibility: Linear programming assumes that variables can take fractional or continuous values. This assumption allows for finding optimal solutions that may involve non-integer values for the decision variables.

D) Linearity: Linear programming models assume that the objective function and the constraints are linear in nature. This means that the variables appear in a linear form, without any multiplication or exponentiation.

E) Nonnegativity: Linear programming assumes that the decision variables cannot take negative values, and they are nonnegative or zero.

These assumptions collectively form the foundation for linear programming models and help in formulating and solving optimization problems efficiently.

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Answer:

I had to screenshot from my computer because it said (you have an inappropriate word or link in your answer)    

we do things called culture monday at our school where we write about a problem and then do a discussion on it in the classroom

this was mine so nooooo plagiarism or anything.

please mark brainliest......

Answer:

World War II started on September 1st, 1939, a decade after America’s stock market crash and downfall of the economy, which was in 1929, when Germany, led by a man born in Austria called Adolf Hitler, invaded Poland. France and England immediately declared war on Germany and Germany’s allies.

Germany had two allies, Japan and Italy, Italy mostly provided food and supplies, while Japan provided manpower, along with Germany. Germany, Japan, and Italy were called the Axis powers, and England, Russia (Then called the Soviet Union), and America (When America joined the war), along with many other countries, such as China and France (Except for the four years which Germany occupied France, 1940--1944), were called the Allied powers.

Germany invaded and occupied Austria, Belgium, France, Norway, Luxembourg, Greece, Czechoslovakia, Greece, Denmark, Holland, Hungary, the Netherlands, and many other countries with the help of Italy and Japan.

The United States wanted to be neutral through World War II like the Irish and Swiss, but the Axis Powers did not let this happen. Instead, Japan bombed Pearl Harbor and utterly destroyed and sunk many ships, so the United States had no choice but to join the war and the Allied forces.

The United States both lost and won many battles, and Germany was losing battles against the Soviet Union and England. Germany lost many battles in the Soviet Union, which was fought in harsh and bitter cold, and also lost the Battle of Britain fought in the skies over England between Britain’s Royal Air Force (RAF) and Germany’s Luftwaffe.

Many people died as a result of the Battle of Britain by bombs and flying shrapnel. In order to try to get their country back to normal, Great Britain started to ration food, drafted men over eighteen to go to the war front, made shelters all over England, in cities, towns, even in the country, in case of an air raid. The Battle of Britain was mostly fought in the skies of London, but enemy planes heading towards London to fight might drop a bomb to wipe away towns, cities, or a part of country off the map.

Germany soon retreated from Great Britain and thought that England would surrender with the rest when Germany conquered and ruled the world, which was Germany’s goal, but England, after some recovery, fought Germany as hard as ever, angered by the people and planes lost because of the Battle of Britain.

In the middle of this, President Franklin Delano Roosevelt died because of a mixture of bad health, too much stress, and his polio. Americans grieved for President Roosevelt, and elected a new president, President Harry Truman.

With forces fighting with both the Soviet Union and England, and later fighting on D-Day, Germany could not last for long, even with its two allies. But the number of allies Germany had soon reduced to one, for Italy joined the Allied powers, betraying the Axis Powers. Germany  desperately tried to fight back the forces of the Allied powers, but soon surrendered days after Adolf Hitler’s death, on May 8th, 1945.

Even when its ally Germany had surrendered and Italy had gone over to the Allies, Japan still fought, even though there was very little chance they would win. This was a bad idea, an idea which would change history. The Allied powers turned their full attention on defeating Japan, which was a bad thing, since Japan could only take over a few islands in the Pacific belonging to the United States and could not defeat any others in the beginning when the Allied powers’ attention was divided. As a result, many, at least hundreds, died, deaths that were not even necessary. The United States dropped two atomic bombs from one of America’s bomber planes on Japan’s two major cities, Hiroshima and Nagasaki days apart, so Japan surrendered, unable to lose any more people then it had already.

The two atomic bombs were built in the midst of fighting and stress of World War II in Manhattan, New York by a group of people who specialized in physics, math, and chemistry. The atomic bomb’s code name was: The Manhattan Project. The Manhattan Project, when done and ready, after dropped from an American bomber plane, killed over a hundred thousand Japanese in the two major cities Hiroshima and Nagasaki, most of them regular Japanese civilians going about their daily life.

World War II was a very important war and time period that changed the world. It changed the human race. The atomic bomb, invented in World War II, soon led other countries, such as England, France, the Soviet Union (Later known as Russia), and China to build it too, which gave these countries a huge advantage in war. America’s stock market bounced back. President Harry Truman became popular for ending World War II.

Step-by-step explanation:

Sorry I'm late

803 words