A sample of hydrogen at 1. 65 atm had its pressure decreased to 0. 454 atm producing a new volume of 755 ml. What was its original volume (v^1)

Answers

Answer 1

The original volume of the hydrogen sample was 0.2997 L if a sample of hydrogen at 1. 65 atm had its pressure decreased to 0. 454 atm producing a new volume of 755 ml.

We can use the Ideal Gas Law to find the original volume of the hydrogen sample. The Ideal Gas Law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature. Assuming that the temperature remains constant, we can write:

P1V1 = P2V2

where P1 is the initial pressure of 1.65 atm, V1 is the initial volume, P2 is the final pressure of 0.454 atm, and V2 is the final volume of 755 mL. Converting the volumes to liters and the pressures to atmospheres, we have:

V1 = (P2V2) / P1

V1 = (0.454 * 0.755) / 1.65

V1 = 0.2997 L

So, the original volume of the hydrogen sample was 0.2997 L.

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Related Questions

using newton's second law, why does a hunter always presses the butt of a rifle tightly against his shoulder before firing a bullet ?

Answers

Answer:

Below

Explanation:

SO the equal but opposite force of the bullet being fired forward doesn't cause the backward force of the rifle to slam into his shoulder possibly causing injury

A hunter always presses the butt of a rifle tightly against his shoulder before firing a bullet because this causes a change in the momentum of the bullet being fired.

What is Newton's second law of motion?

Newton's second law of motion states that the rate of change of momentum of a body is directly proportional to the force which is applied to it and the change in momentum of an object takes place in the direction in which the force is being applied.

The acceleration of an object as produced through a net force is directly proportional to the magnitude of the net force, in the same direction as that of the net force, and inversely proportional to the mass of the object.

The butt of the rifle is pressed tightly against the shoulder of the hunter to cause a change in the momentum of the bullet.

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An object of mass(0.8kg) is attached to massless string of length (2.0),and swung with a tangential velocity of (3.0m/s) what is the tension in the string?

Answers

Answer:

3.6 N

Explanation:

The magnitude of centripetal force in this case is equal to the magnitude of tension in the spring.

The formula is :

T= mv²/r ------where T is tension

m= mass of object =0.8 kg

v= velocity of object {tangential velocity} = 3.0 m/s

r= length of string = 2m

Applying the formula with real values;

T= mv²/r

T= {0.8 * 3²} / 2

T= { 7.2}/2 = 3.6 N

The diffusion of inanimate forms of energy was vital to the accelerated development of the modern world. The industry is completely dependent on the techniques of extracting energy from nature. The development of energy sources or the lack of them determined the fate of countries. Those that were able to develop and exploit them led the industrialization process, those that did not invest in the energy sector became technologically lagging countries.

Discuss about:

a) the evolution of the main energy matrices after the industrial revolution (main sources of energy);

b) The social and environmental consequences of these energy sources;

c) relate energy development and degree of industrial development.

Answers

The evolution of energy matrices, the social and environmental consequences of energy sources, and the relationship between energy development and industrial development are critical aspects of understanding the interplay between energy and the modern world. Balancing the need for energy with sustainability and minimizing environmental impacts is a key challenge for societies today.

a) The evolution of the main energy matrices after the industrial revolution:

The industrial revolution marked a significant shift in the sources of energy used to power the growing industries and societies. Prior to the industrial revolution, human and animal labor, along with limited use of water and wind power, were the primary sources of energy. However, with the advent of steam engines and mechanization, there was a need for more abundant and efficient sources of energy.

Coal: Coal became the dominant energy source during the early stages of the industrial revolution. It provided the necessary fuel for steam engines and played a crucial role in powering factories, railways, and steamships.

Oil: The discovery and commercialization of oil in the late 19th century revolutionized the energy landscape. Oil became a major source of energy for transportation, as it fueled the internal combustion engines of automobiles, trucks, and airplanes.

Natural Gas: With the expansion of oil drilling, natural gas also emerged as an important energy source. It is used for heating, electricity generation, and as a feedstock for various industrial processes.

Nuclear Energy: The development of nuclear power in the mid-20th century introduced a new source of energy. Nuclear reactors harness the energy released from nuclear fission reactions to generate electricity.

Renewable Energy: In recent decades, there has been a growing emphasis on renewable energy sources such as solar, wind, hydroelectric, and geothermal power. These sources offer sustainable alternatives to fossil fuels, with lower environmental impact and the potential for long-term energy security.

b) The social and environmental consequences of these energy sources:

Each energy source has its own social and environmental consequences:

Fossil Fuels: The burning of fossil fuels, such as coal, oil, and natural gas, releases greenhouse gases and contributes to climate change. Extraction of fossil fuels can lead to habitat destruction, water pollution, and health hazards for workers and nearby communities.

Nuclear Energy: While nuclear energy does not produce greenhouse gas emissions during operation, it presents risks associated with accidents, radioactive waste disposal, and potential weaponization of nuclear materials. Public safety concerns and environmental risks have led to debates over the use of nuclear power.

Renewable Energy: Renewable energy sources offer benefits in terms of reduced greenhouse gas emissions and environmental sustainability. However, their deployment may require land use changes, and some technologies (e.g., large-scale hydroelectric dams) can cause ecological disruptions and displacement of communities.

c) The relationship between energy development and degree of industrial development:

Energy development and industrial development are closely intertwined. The availability of affordable and reliable energy sources is crucial for driving industrialization and economic growth. Access to abundant energy resources enables countries to power their industries, expand transportation networks, and improve living standards.

Countries that have invested in the development and exploitation of energy sources have typically experienced accelerated industrialization and technological advancement. The ability to secure and utilize energy resources efficiently has been a determining factor in a country's competitiveness and economic prosperity.

Conversely, countries that lack access to energy sources or fail to invest in their energy sectors may face challenges in industrial development. Limited energy availability can constrain production capacities, limit access to modern technologies, and hinder economic progress.

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the girl has a weight of 72N on moon.what will be the mass and the weight of the girl on earth.(use g earth=10m/s 2/g 9 moon=1.6m/s 2)​

Answers

Answer:

F(m)= mg(m)

m=F(m)/g(m)=72/1.6=45kg

F(e)= mg(e)= 45 x 10 m/s= 450N

1. A 65 kg student, starting from rest, slides down an 16.2 m high water slide. On the way down, friction does 5700 J of work on him. How fast is he going at the bottom of the slide

Answers

Answer:

11.94

Explanation:

Remark

Find the Potential Energy at the top.

Givens

m = 65 kg

h = 16.2 m

g = 9.81

PE = 65 * 9.81 * 16.2

PE = 10329.93

The tricky part is what do you do about Friction?

Formula

PE = Friction + KE

Solution

PE = 10329.93 Joules

Friction = 5700 Joules

Find the KE

10329.93 = 5700 + KE

KE = 10329.93 - 5700

KE = 4629.93

Find V from the KE formula

KE = 4629.93

m = 65

KE = 1/2 m v^2

KE = 1/2 65 v^2

4629.93 = 1/2 65 v^2

v^2 = 142.46

v = √142.46

v = 11.94

The amplitude of wave is

A) the distance the wave moves in one second

B) the distance between one crest and the next crest

C) half the distance from a crest to a trough

D) the distance equal to one wavelength

Answers

Answer:

A

Explanation:

what more to say.. :| it's the distance from x to a crest or trough

Answer:

The answer is A

Explanation:

The amplitude of wave is the distance the wave moves in one second

An ac generator consists of 6 turns of wire. Each turn has an area of 0. 010 m2. the loop rotates in a uniform field (b = 0. 20 t) at a constant frequency of 40 hz. What is the maximum induced emf?

Answers

If an ac generator consists of 6 turns of wire. Each turn has an area of 0. 010 m2. the loop rotates in a uniform field (b = 0. 20 t) at a constant frequency of 40 hz. The maximum induced emf is 0.048 volt.

Given,

Number of turns (N) = 6

Area of each turn (A) \(=0.010 m^{2}\)

Magnetic field (B) = 0.2 T

The loop rotates at a constant frequency of 40 Hz

Thus angular frequency of rotation (ω) = 40 Hz

∴ The maximum induced emf,

    ε = NABω

⇒ ε= 6×0.01×0.02×40 = 0.048 volt

∴The maximum induced emf in ac generator is 0.048 volt.

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Which statement about force is incorrect

A. Some forces cause objects around us to move.
B. Some forces keep objects around us from moving
C. Force is the ability to change motion and transfer matter.
D. Force causes changes in the motion and energy of matter.​

Answers

Answer:

I don't know sorry brother/sister

Explanation:

please mark as brilliant

a light board that is 10 m long is supported by two sawhorses, one at one end of the board and a second at the midpoint. a 48-n object is placed between the two sawhorses, 3.2 m from the end and 2.2 m from the center. a second object, with a weight of 15 n, is placed on the supported end. what magnitude forces do the sawhorses exert on the board?

Answers

Magnitude forces do the sawhorses exert on the board 11.6N and 36.4N

Calculation:

Given that a light board that is 10 meters long is supported by two sawhorses, one at each edge and the middle. Between the two sawhorses, 3.2 meters from the edge and 2.2 meters from the center, is a small 48-N weight.

We must take into account the balance of forces operating on the board in order to determine the forces that the sawhorses are exerting on it.

Let P1 and P2 represent the two upward forces generated by the saw horses.

Considering that the weight is insignificant

The descending pressures are equal to the sum of the upward forces.

P1 + P2 = 48....... (1) (1)

Additionally, the anticlockwise moments are equal to the sum of the clockwise moments.

Take for granted that the board is uniform. The center will be where the weight acts.

Spending a moment in the middle:

P1 × 5 + 48× 2 = 0\sP1 = 58/ 5\sP1 = 11.6N

P1 should be replaced in equation 1.

11.6 + P2 = 48\sP2 = 48 - 11.6\sP2 = 36.4N

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Where would you expect to find volcanic mountain ranges and why?

Answers

Answer:

Sixty percent of all active volcanoes occur at the boundaries between tectonic plates. Most volcanoes are found along a belt, called the “Ring of Fire” that encircles the Pacific Ocean. Some volcanoes, like those that form the Hawaiian Islands, occur in the interior of plates at areas called “hot spots.”

Explanation:

Volcanoes are found around tectonic plates because the convection currents move the plates. Where convection currents diverge near the Earth's crust, plates move apart. Where convection currents converge, plates move towards each other, plates converge and the plates move together, also known as ridge push, therefore mountains and volcanoes are formed

Hope this helps :)

How do you convert temperatures in degrees Fahrenheit to Celsius?

Answers

Answer:(x-32) * 5/9

Explanation:

(52°F − 32) × 5/9 = 11.1111°C

how much force must be applied to accelerate a 3 kg remote control car from rest to 10 m/s in 5 seconds

Answers

10/5 = 2 m/s^2
F =ma = 3 x 2 = 6 N

Can you solve this?

Can you solve this?

Answers

45466 I think yeah or 12,365

and electric motor lifts an elevator a vertical distance of 18.0m in a time of 30.0s by exerting an upward force of 6.0x10^3 N . what power does the electric motor produce?

Answers

Answer:

\(\fbox {3.6kW}\)

Explanation:

Formula used :

\(\boxed {P = F \times v} \leftarrow \rightarrow \boxed {P = \frac{F \times S}{t}}\)

Given :

⇒ F = 6 × 10³ N

⇒ S = 18 m

⇒ t = 30 s

Solving :

⇒ P = 6 × 10³ × 18 / 30

⇒ P = 2 × 100 × 18

⇒ P = 3600 W

⇒ P = 3.6kW

Graphs are pictorial representations of

Answers

A graph is a pictorial representation of a set of objects where some pairs of objects are connected by links.

An image graph or pictograph is a graph used to display data that use pics or symbols to represent facts. The interconnected items are represented through factors termed vertices, and the hyperlinks that connect the vertices are known as edges. amongst different forms of information representations possible, the representation which includes images and pictorial representation of facts is referred to as a pictograph.

Pictographs and bar graphs are pictorial representations of numerical records. answer: real. with the aid of the definition, pictographs and bar graphs are pictorial representations of the numerical data. the records presented thru pictures or image of various objects is called a pictorial representation of facts. The photos of different objects are used to symbolize specific statistics, so such pictorial data are called pictographs.

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A car is traveling at a speed of 30m/s when it leaves a ramp set up at an angle of 37 degrees from the ground. How much time does it take for the car to reach the maximum height of its jump?

Answers

The time in which the car reaches it maximum Haight is ≈1.8 seconds.

We know that when the car leaves the ramp , it will move in upward direction and forward direction .

velocity of moving forward=  v cos(a).......(initial velocity of moving front)

velocity of moving  upward = v sin(a).......(initial velocity of moving up)

v is the  initial velocity of car(30m/s), a is the angle of ramp(37°).

velocity of moving up for car at Max. hight = 0m/s

We know that,

final velocity=initial velocity - gt (g is acceleration due to gravity, t is time)

when something moves upward .

so,

0=v sin(a)-9.8t

t≈1.8 seconds

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Question 4 of 10
When you go along with a group because you don't want to cause trouble, it is
called:
A. informational social influence.
B. normative social influence.
C. attribution
.
D. fundamental social influence.

Answers

Answer:

Normative

Explanation:

It is normal occurance but not unnatural

Molly is investigating the change in the motion of an object. She kicks a soccer ball that Is sitting on a soccer field three times. Molly uses a device to measure the force of her kick, and changes the force of her kick each time. The data that she collected are shown in the table below.
Force of Kick
(N)
Distance Traveled (m)
150
31
200
39
270
47
In 6-10 sentences explain how Molly altering the force of her kicks altered the movement of the ball. You may discuss the experiment in terms of Newton's three laws of motion, acceleration and momentum, energy transfer, and /or conservation of energy. Be sure to use appropriate vocabulary in your explanation.
B
i
U
§
×.
x2
=
=
E
=트 트 41 x
Special Characters

Answers

Molly's experiment involved kicking a soccer ball with varying amounts of force and observing the resulting change in the ball's motion.

How does altering the force alter the movement of the ball?

Newton's three laws of motion can help explain how the force of Molly's kicks affected the ball's movement.

Newton's first law of motion states that an object at rest will stay at rest and an object in motion will stay in motion with a constant velocity unless acted upon by an unbalanced force. In this experiment, the soccer ball was at rest before each kick, so the force of Molly's kicks acted as an unbalanced force, causing the ball to accelerate and move. The greater the force of her kick, the greater the acceleration and resulting distance the ball traveled.

Newton's second law of motion states that the acceleration of an object is directly proportional to the force applied and inversely proportional to its mass. In this case, the mass of the soccer ball remained constant, but the force of Molly's kicks varied. As a result, the acceleration of the ball was directly proportional to the force of her kick.

Finally, Newton's third law of motion states that for every action, there is an equal and opposite reaction. When Molly kicked the soccer ball, the ball exerted an equal and opposite force back on her foot, which is why she felt the impact of the kick.

Energy transfer also played a role in this experiment. When Molly kicked the ball, she transferred energy from her foot to the ball. The greater the force of her kick, the more energy was transferred to the ball, resulting in a greater distance traveled.

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Two point charges are separated by a certain distance. How does the strength of the electric field produced by the first charge, at the position of the second charge, change if the second charge is doubled?

Answers

Answer:

The field will remain the same

Explanation:

This is because electric field given as

E1= kq1/r²

And that of second charge

E² = kq2/r²

Is not affected by the size of the second charge q2

the electric force generated by two point charges separated by distance a is 4 times greater than the electric force generated when separated by distance b. how does distance a compare to distance b?

Answers

The distance b is twice the distance a.

The electric force between two point charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them, according to Coulomb's law.

Let's assume the charges are q1 and q2. According to the problem, when the charges are separated by distance a, the electric force is 4 times greater than when they are separated by distance b.

So we can write the equation as:
( Fa = k {q1 q2/a²} )
( Fb = k {q1 q2/b²} )
where ( Fa ) is the electric force when separated by distance a, and ( Fb ) is the electric force when separated by distance b.

Given that ( Fa) is 4 times greater than ( Fb ), we have:
4Fb = k {q1 q2/a²}
Dividing both sides by 4, we get:
Fb = k { q1 q2/4a²}

Comparing this equation to the equation for ( Fb ), we can see that the denominator is the same. Therefore, the distance b must be twice the distance a.

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Parents and teachers should strive to have children engage in activities within the child's zone of proximal growth, meaning that the activities are:
A. easily accomplished on the first try, so that the child does not become discouraged
B. not so easy that the child can accomplish them right off the bat, nor so difficult that even with help, they cannot be accomplished
C. difficult to accomplish, so that the child always seeks assistance in order to actively engage in social interactions
D. easily accomplished, so that child does not become dependent on adult assistance

Answers

Parents and teachers should strive to have children engage in the activities within child's zone of proximal growth, meaning that the activities are : B.)not so easy that the child accomplish them right off the bat and nor so difficult that even with help, they cannot be accomplished.

What are the activities that parents and teachers should strive to have children engage in?

Activities in a child's zone of proximal development are those that parents and teachers should try to get kids involved in. ZPD is the range of activities that are not too easy for the child to accomplish on their own, but also not too difficult that they cannot be accomplished with some guidance or assistance from adults or more capable peers.

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calculate the nuclear binding energy per nucleon for ba137ba137 which has a nuclear mass of 136.906 amu136.906 amu .

Answers

Binding energy per nucleon=1.314810^-13J/nucleon

To calculate the nuclear binding energy per nucleon, we need to determine the total binding energy of the nucleus and divide it by the total number of nucleons.

Given:

Nuclear mass of Ba-137 = 136.906 amu

To calculate the total binding energy, we need to know the atomic mass unit (amu) equivalent to energy. One atomic mass unit (1 amu) is approximately equal to 931.5 MeV/c^2 (megaelectron volts per speed of light squared).

Converting the nuclear mass from amu to kilograms:

Mass of Ba-137 = 136.906 amu * (1.66054 x 10^(-27) kg/amu)

Now, to calculate the total binding energy (E), we use Einstein's mass-energy equivalence equation:

E = Δm * c^2,

where Δm is the mass defect (difference between the mass of the nucleus and the sum of the masses of its individual nucleons), and c is the speed of light.

To find the mass defect, we subtract the total mass of the individual nucleons from the mass of the nucleus:

Mass defect = (Mass of Ba-137 - (number of nucleons * mass of a single nucleon))

Since Ba-137 has 137 nucleons, and we are considering Ba-137 specifically, we substitute these values into the equation:

Mass defect = (136.906 amu - (137 * mass of a single nucleon))

Now, we calculate the total binding energy using the mass-energy equivalence equation:

E = Mass defect * c^2,

where c = 3.0 x 10^8 m/s.

Finally, to find the binding energy per nucleon, we divide the total binding energy by the total number of nucleons (137 in this case):

Binding energy per nucleon = Total binding energy / Total number of nucleons=1.314810^-13J/nucleon

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If the block compresses the spring 4. 8 cm before coming to rest, what is the force constant of the spring?.

Answers

The force constant of the spring is 40.91 N/m, which can be written as 2133.33 N/m if the value is rounded to the nearest hundredth.

The work done by the block is given by the formula:W = (1/2)kx²

where W is the work done, k is the force constant of the spring, and x is the maximum compression of the spring.

Substituting the given values into the equation,

W = (1/2)kx²= (1/2) x k x (0.048 m)²= (1/2) x k x (0.002304 m²)= (1/2) x 0.11 kJ= 0.055 kJ

The work done by the block is equal to the initial kinetic energy of the block, which is given by the formula:

W = (1/2)mv²

where m is the mass of the block and v is the initial velocity of the block.

Substituting the given values into the equation, W = (1/2)mv²= (1/2) x 0.5 kg x (3 m/s)²= 2.25 J

Comparing the two equations, we have:

0.055 kJ = 2.25 J0.055 x 10³ J = 2.25 J

k = (2.25 J) / (0.055 x 10³ J/m)

k = 40.91 N/m

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How can the potential energy in magnets be used to create kinetic energy in an object without making contact?

Answers

Answer:  If you move a magnet quickly through a coil of copper wire, the electrons will move - this produces electricity.

Explanation:

what color of light does a low-pressure sodium street lamp give off?

Answers

Answer:

Yellow Light

Explanation:

Low-pressure sodium  lamps gives of a yellow/orange light/glow. Which can also be said as monochromatic yellow light. Because they only produce a single wavelength of yellow light, which results in a less intense light output.

Hopefully this is right! :D good luck

An airplane is dropping bales of hay to cattle stranded in a blizzard on the Great Plains. The pilot releases the bales at 160 m above the level ground when the plane is flying at 60.0 m/s 45.0 degrees above the horizontal.


How far in front of the cattle should the pilot release the hay in meters so that the bales will land at the point where the cattle are stranded?

Answers

In order to find how far in front of the cattle should the pilot release the hay so that the bales will land at the point where the cattle are stranded, we need to determine the horizontal distance the bales travel from their release point to the point of landing.

We can solve for the time it takes the bales to reach the ground using the vertical component of the plane's velocity and the equation of motion for constant acceleration in the y-direction:y = yo + voyt + 1/2gt^2where y is the final position in the y-direction, yo is the initial position in the y-direction, voy is the initial velocity in the y-direction, t is time, and g is acceleration due to gravity.

For this problem,y = -160 m (the final position of the bales is at the level of the ground, which is below the release point)yo = 0 (the initial position of the bales is at the release point)voy = (60.0 m/s)sin45.0 = 42.4 m/st = ?We can solve for t by rearranging the equation to:t = (-voy ± √(voy² - 2g(y - yo))) / gThe quadratic formula was used to obtain this equation.

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(a) calculate the tension in a vertical strand of spider web if a spider of mass 8.00 × 10−5 kg hangs motionless on it. (b) calculate the tension in a horizontal strand of spider web if the same spider sits motionless in the middle of it. the strand sags at an angle of 12° below the horizontal.

Answers

The lateral string has a tension of 1.89*10⁻³N, the vertical string has a tension of 7.84 * 10⁻⁴ N, and indeed the ratio of both strings is 2.41.

What is the physics of tension?

The force produced that whenever a load is placed at a few of the ends of a fabric in a direction away from the material's cross-section is known as the tension force. It's common to describe a strain as a "grabbing" force.

Briefing:

(a). The net force acting on the strand is T =mg

Here,

T = Tension in the strand

m = mass of the spider

g = acceleration due to gravity

Substitute 8.00×10⁻⁵ kg for m and 9.8m/s² for g in equation.

T = mg

T = 8.00×10⁻⁵ * 9.8m/s²

T = 7.84 * 10⁻⁴ N

Hence, the tension in the vertical strand is 7.84 * 10⁻⁴ N

(b). The net force in the vertical direction is-

2Tsin∅ = mg

Here, g seems to be the acceleration caused by gravity, r is really the stiffness with in strand, m is the spider's mass, and ∅ is the angle the strand is making.

Substitute 8.00×10⁻⁵ kg for m, 9.8m/s² for g and 12º for ∅ in equation.

2Tsin∅ = mg

2T (sin12º) = 8.00×10⁻⁵ kg * 9.8m/s²

T = 8.00×10⁻⁵ * 9.8/ 2sin12º

T = 1.89*10⁻³N

Hence, the tension in the horizontal string is 1.89*10⁻³N.

The ratio of vertical and horizontal string is,

= 1.89*10⁻³N/7.84 * 10⁻⁴ N

= 2.41

Hence, the ratio of vertical and horizontal string is 2.41

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The complete question is-

(a) Calculate the tension in a vertical strand of spider web if a spider of mass 8.00×10⁻⁵ kg hangs motionless on it. (b) Calculate the tension in a horizontal strand of spider web if the same spider sits motionless in the middle of it much like the tightrope walker in Figure 4.17. The strand sags at an angle of 12º below the horizontal. Compare this with the tension in the vertical strand (find their ratio).

Lifting a heavy piano in the air 30
feet to a second story room would
be the easiest by doing which of
the following actions?
A. jumping up 30 feet with the piano on your
back
B. carrying the piano up a ladder that is very
steep
C. carrying the piano up a long staircase with
many steps spread apart

Answers

IMA = inclined mechanical advantage = distance (L) : height (h)

the longer the track / distance the easier we lift it

C. carrying the piano up a long staircase with many steps spread apart


Show that strong monotonicity implies local non-satiation but
not vice versa.

Answers

In microeconomics, both strong monotonicity and local non-satiation have different meanings and implications. Both terms refer to the preferences of the consumer. The two concepts are related but have some differences.

Let's define each term.

Strong monotonicity: Strong monotonicity is defined as a preference relation of a consumer, such that for any two bundles of goods, if bundle A has more of each good than bundle B, then the consumer strictly prefers A to B.

Local non-satiation: Local non-satiation implies that a consumer always prefers any bundle of goods that contains slightly more of any good than a different bundle, holding the other goods in the two bundles constant.

Now, we'll see that strong monotonicity implies local non-satiation but not vice versa.

Let's suppose a consumer has a preference for bundle A over bundle B if A has more of each good than B. This preference implies that if any good in bundle B is increased, the consumer will prefer the new bundle to the original bundle. This is a simple proof that strong monotonicity implies local non-satiation. If bundle A is preferred to bundle B due to monotonicity, then any bundle with a slightly higher quantity of any good in bundle A will also be preferred over B.

However, the reverse is not true. Local non-satiation does not imply strong monotonicity. Local non-satiation requires that the consumer prefers any bundle with slightly more of any good to a bundle with slightly less of any good. But this condition does not imply the monotonicity condition. For example, consider a preference relation such that the consumer prefers A to B and B to C, but prefers D to A.

This preference relation satisfies local non-satiation but not strong monotonicity because bundle D contains less of each good than A, but is preferred over A. Hence, strong monotonicity implies local non-satiation, but not vice versa.

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A 4.0-kg object moving at 3.0 m/s experiences a 16.0-Newton resistive force over a duration

of 0.20 seconds. What is the impulse experienced by the object?

a. 2.7 Nos

b.3.2 Nos

c. 4.0 kg•m/s2

d. 12.0 kg•m/s

A... nonsense! None of these are equal to the impulse.

a

b

с

d

е

Answers

Answer:

D is the answer hope you it helps you

A 4.0-kg object moving at 3.0 m/s experiences a 16.0-Newton resistive force over a duration of 0.20 seconds. The impulse experienced by the object is 3.2 N·s. The correct answer is: b. 3.2 N·s

To calculate the impulse experienced by the object, we can use the formula for impulse:

Impulse (J) = Force (F) * Time (Δt)

Given:

Mass of the object (m) = 4.0 kg

Initial velocity (u) = 3.0 m/s

Resistive force (F) = 16.0 N

Duration (time) (Δt) = 0.20 seconds

First, we need to find the final velocity (v) of the object using the following equation of motion:

v = u + (F/m) * Δt

where:

u = initial velocity

F = force

m = mass

Δt = time

v = 3.0 m/s + (16.0 N / 4.0 kg) * 0.20 s

v = 3.0 m/s + 4.0 m/s

v = 7.0 m/s

Next, we calculate the impulse:

J = F * Δt

J = 16.0 N * 0.20 s

J = 3.2 N·s

Therefore, the correct answer is: b. 3.2 N·s

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