A sample of nitrogen gas has a pressure of 6. 00 kpa at 540 K. If the volume does not change, what will the pressure bat at 250. 0 K?

Answer:

small molecules move into the cell, Then it is by diffusion or facilliated diffusion.

Answer:

Different number of neutrons

Explanation:

Isotopes are different versions of an element, in which the only difference is that they have different numbers of neutrons in the nucleus, and therefore slightly different atomic masses.

When a reaction has reached equilibrium with a given set of conditions, if the conditions are not changed, the reaction will remain at equilibrium forever. The forward and reverse reactions continue at the same equal and opposite rates and the macroscopic properties remain constant.

It is possible, however, to disturb that equilibrium by changing conditions. For example, you could increase the concentration of one of the products, or decrease the concentration of one of the reactants, or change the temperature. When a change of this type is made within a reaction at equilibrium, the reaction is no longer in equilibrium. When you alter something in a reaction at equilibrium, chemists say that you put stress on the equilibrium. When this occurs, the reaction will no longer be in equilibrium and the reaction itself will begin changing the concentrations of reactants and products until the reaction comes to a new position of equilibrium. How a reaction will change when a stress is applied can be explained and predicted. That is the topic of this section.

Answer: B) You are to continue heating the round-bottom flask until all liquid has been distilled.

Explanation:

Fractional distillation refers to a method that's useful for the separation of mixtures of solvents whereby there is less than 40°C in the boiling point difference.

With regards to the options given, the incorrect statement about the procedure for distillation is that you are to continue heating the round-bottom flask until all liquid has been distilled. This isn't correct.

reactants because it had other chemicals, when more are mixed it will be more stronger.

It is the correct answer

Indeed, 13C NMR spectroscopy can be used to differentiate between borneol and isoborneol. Because the chemical structures of borneol and isoborneol differ.

A potent analytical method for examining the carbon nuclei in molecules is 13C NMR spectroscopy. It is based on the observation of the resonance frequencies of various carbon atoms within a molecule through the interaction of carbon-13 nuclei with an external magnetic field. The identification, quantification, and structural clarification of a wide variety of organic compounds are made possible by the information that 13C NMR spectra provide about the chemical environment and connectivity of carbon atoms in molecules. It has become a vital instrument for the characterisation of complex mixtures, natural products, and synthesised substances and is frequently utilised in disciplines including chemistry, biochemistry, and pharmacology.

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Answer:

NO! It would be in violation of the workplace regulation regarding oxygen.

Explanation:

Bulk oxygen systems convey liquified oxygen which is of geat use and importance in institutions like a nuirsing home.

Liquified oxygen is gaseos oxygen that has been condensed under high presures into liquid form. It is transported via a complex system of vaporizers, storage tanks and pipes around the facility it is needed. Liquified oxygen is oxygen- rich.

Asphalt is a petroleum derivative that is often used to in coating surfaces and tarring roads.

Its primry constituent is Carbon with minor constitunets like sulphur, nirogen, oxygen. As a petrolem derivative, it is very combustible.

In the event of an oxygen leak on an asphalt surtface, oxygen acting as an oxidizing agent can combine with asphalt in the presence of air, to cause a large fire.

Hence, asphalt surfacing in areas of oxygen leaks, would not be in compliance with the workplace regulation as it has the potential of causing a fire in the nursing home.    

Answer:

Equation of Reaction = AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaNO3 (aq)

Steps:

1. Find the moles of AgNO3 with formula n= Mass/Mr (molecular mass)

so you will get moles= 10.0/ 169.87 = 0.05886854654

2. Using stoichiometry you know the equation has 1 mole so the moles of AgCl are gonna be the same; therefore, you will use again the same formula.

3.  moles= mass/molecular mass

0.05886854654 = x/ 143.32

You rearrange the formula to find the mass

so mass = moles x molecular mass

mass = 0.05886854654 x 143.32

mass= 8.44 grams

Explanation:

Answer:

D. and B.

Explanation:

I got it right on my quiz

The number of moles of gas in the expanded container would be 0.5 moles.

According to Avogadro's law, an equal volume of gases at the same temperature and pressure will contain the same number of molecules.

Avogadro's law can be mathematically expressed as:

\(v_1/n_1 = v_2/n_2\)

Where \(v_1\) = initial volume, \(v_2\) = final volume, \(n_1\) = the initial number of moles, and \(n_2\) = the final number of moles.

In this case, \(n_1\) = 1.25 moles, \(v_1\) = 25.0 L, \(v_2\) = 10.0 L

Thus, we are to make \(n_2\) the subject of the formula:

\(n_2 = v_2n_1/v_1\)

     = 10 x 1.25/25

     = 0.5 moles

In other words, the number of moles of gas in the expanded container is 0.5 moles.

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Answer: 13.00

Explanation: got it right

The bond angles in a molecule depend on the repulsion between the electrons in the valence shell of the central atom thus, the correct order of increasing bond angles is (2) OF\(^{2}\) < SnF\(^{2}\) < XeF\(^{2}\).

In the case of OF\(^{2}\), the central atom is oxygen, which has two lone pairs of electrons and two fluorine atoms as bonded atoms. The lone pairs exert greater repulsion than bonded atoms, leading to a bent shape and a bond angle of approximately 103 degrees. Moving on to SnF\(^{2}\), the central atom is tin, which has two bonded fluorine atoms and two lone pairs.

The lone pairs again exert greater repulsion, leading to a bent shape and a bond angle of approximately 101 degrees. Finally, XeF\(^{2}\) has a central atom of xenon, which has three lone pairs and two bonded fluorine atoms. The greater number of lone pairs leads to a linear shape and a bond angle of 180 degrees. Therefore, the correct order of increasing bond angles is (2) OF\(^{2}\) < SnF\(^{2}\) < XeF\(^{2}\).

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Answer:

Agriculture accounts

Answer: Thermoelectric power

Explanation:

took the test!! good luck :)

The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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The Henderson-Hasselbach equation is used to calculate the pH of a simple conjugate-pair buffer system. For an ammonia/ammonium chloride buffer, the equation would be expressed as pH = 9.25 + log([NH4+]/[NH3]).

This equation takes into account the equilibrium between the weak acid (NH4+) and its conjugate base (NH3) and the dissociation constant (Kb) of the weak base (NH3), which is given as 1.8 x 10-5. By knowing the concentration of the weak acid and its conjugate base, the pH of the buffer solution can be calculated.

The correct expression of the Henderson-Hasselbalch equation for an ammonia/ammonium chloride buffer system would be:

pH = 9.25 + log([NH4+]/[NH3])

This equation takes into account the pKa value (9.25) of the conjugate acid (NH4+) and the ratio of the concentrations of the conjugate acid ([NH4+]) and base ([NH3]) in the buffer solution.

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33× 10⁻⁷ A current is needed to plate 5g of Copper metal on a cathode.

It states that during electrolysis, the amount of chemical reactions occurring at the electrodes under the influence of electrical energy is proportional to the amount of electricity conducted through the electrolyte.

n = zFQ

Where, n = moles of copper metal

n = 5/63.54

n = 0.078 moles

z = Number of electrons in the half-cell reaction

Cu²⁺ + 2e⁻ ⇔ Cu

z = 2

F = Faraday constant (96,485 A/mol)

Now, substitute the values in the equation mentioned above:

0.078 = 2 × 96,485 × Q

Q = 4.04 × 10⁻⁷ C

Since Q = I × t

Where, Q = charge

I = Current

t = Time (2 hours or 120 min.)

4.04 × 10⁻⁷ C = I × 120

I = 4.04 × 10⁻⁷/120

I = 33× 10⁻⁷ A

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Answer:

Freezing and condensation

Explanation:

Because they are exothermic, they release energy

Answer:

b

Explanation:

. B. atoms of the elements hydrogen and oxygen are in the reactants and also in the productsatoms of the elements

The jejunum region of the small intestine is where one would expect to find the highest concentration of dipeptides after protein and polypeptide hydrolysis by proteases.

The most dipeptides would be expected to be found in the small intestine, specifically in the region known as the jejunum.

After proteins and polypeptides are hydrolyzed by proteases, such as pepsin in the stomach and pancreatic enzymes (trypsin, chymotrypsin, and carboxypeptidases) in the small intestine, the resulting products are primarily dipeptides, tripeptides, and amino acids.

As the partially digested food moves from the stomach to the small intestine, further enzymatic digestion occurs in the lumen of the small intestine. The majority of enzymatic activity and absorption of nutrients take place in the jejunum, which is the middle section of the small intestine.

In the jejunum, dipeptides, which are two amino acids linked together, are further broken down by enzymes known as peptidases or dipeptidases. These enzymes hydrolyze dipeptides into individual amino acids, which can then be absorbed through the intestinal lining into the bloodstream for further utilization by the body.

Therefore, the jejunum region of the small intestine is where one would expect to find the highest concentration of dipeptides after protein and polypeptide hydrolysis by proteases.

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Answer:

A, gamma rays

Explanation:

Radio waves, on the other hand, have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation. In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

150, tank, concentration

A tank filled with 1000 liters contains 400 liters of a solution saline A in which 20 kg of salt are dissolved then,

The solution for the concentration rho is 0.12 kg/l.

Therefore, the rate of salt being added to the tank is equal to the rate of salt being removed from the tank.

Using the above formula, the concentration of solution B can be calculated.

Let rho be the concentration of solution B.Concentration of saline A is given bymass of salt/volume of solution = 20/400 = 0.05 kg/l

Concentration of saline A after t minutes of mixing with saline B of concentration rho = (20 + 0.1 * rho * t)/(400 + (t * (5 - 3)))In 1 hour = 60 minutes, concentration = 0.12 kg/l

Therefore, we can say:(20 + 0.1 * rho * 60)/(400 + (60 * (5 - 3))) = 0.12

By solving this equation, we get  rho = 150 kg/m3.

Answer: 150, tank, concentration

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Copper is formed through geological processes, typically in porphyry copper deposits, skarn deposits, or sediment-hosted copper deposits. These deposits are formed through a combination of hydrothermal processes, magma intrusion, and weathering.

The distribution of copper around the world is related to the distribution of these deposits, which tend to occur in areas with specific geological characteristics. For example, the largest copper deposits are found in Chile, Peru, and the United States, which all have extensive copper mining operations. These countries have abundant porphyry copper deposits, which are formed by the intrusion of magma into the Earth's crust. Other copper deposits are found in regions with skarn deposits, such as China and Russia, or in sedimentary rocks, such as in the Democratic Republic of Congo.

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Answer:d

Explanation:

The specific rate constant of the second-order irreversible reaction is 122.34 L/mol.s.

A second-order irreversible reaction A-3R was studied in a PFR reactor, where reactant pure A (CAO=0.121 mol/lit) is fed with an inert gas (40%), and flow rate of 1 L/min (space velocity of 0.2 min-1). Product R was measured in the exit gas as 0.05 mol/sec.

To calculate the specific rate constant, we use the following equation:0.05 mol/sec = -rA * V * (1-X). The negative sign is used to represent that reactants decrease with time. This equation represents the principle of conservation of mass.Here, V= volume of the PFR. X= degree of conversion. And -rA= the rate of disappearance of A= k.CA^2.To calculate the specific rate constant, k, we need to use a few equations. We know that -rA = k.CA^2.We can also calculate CA from the volumetric flow rate and inlet concentration, which is CAO. CA = (CAO*Q)/(Q+V)The volumetric flow rate, Q = V * Space velocity (SV) = 1 * 0.2 = 0.2 L/min.

Using this, we get,CA = (0.121*0.2)/(1+0.2) = 0.0202 mol/LNow, we can substitute these values in the equation of rate.0.05 = k * (0.0202)^2 * V * (1 - X)The volume of PFR is not given, so we cannot find the exact value of k. However, we can calculate the specific rate constant, which is independent of volume, and gives the rate of reaction per unit concentration of reactants per unit time.k = (-rA)/(CA^2) = 0.05/(0.0202)^2 = 122.34 L/mol.

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To fix the issue, the student should carefully reapply the sample in a smaller amount, allow it to dry completely, and adjust the solvent system if necessary to achieve proper separation of the components on the TLC plate.

The student might have made the following technical mistake while running the TLC plate:

1. Overloading the sample: When spotting the TLC plate, the student may have applied too much sample, causing the components to streak rather than separate into individual spots. To resolve this, the student should apply a smaller amount of sample and ensure that it is evenly distributed.

2. Insufficient drying: If the student did not allow the spotted sample to dry properly before placing it in the solvent, it can cause the components to streak. To prevent this, the student should ensure the sample is completely dry before running the TLC plate.

3. Inappropriate solvent system: Although the student used a 10% ethyl acetate/hexane mixture, it is possible that this solvent system was not suitable for the specific sample. Adjusting the solvent ratio or trying different solvent systems could help achieve better separation.

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Answer:

Explanation:

This is an aluminum atom with 13 proton because from what henry said in the year 1914 he said that the number of protons of an element is equal to the number of electrons for an neutral atom..an you expect the number of electrons to be the atomic number.( The number that is used to locate the elements in the periodic table (1869).

And the number of neutron is 13 because form the mass number of the elements and we no that the mass number of an element is the sum of the proton and the neutron..MN=P + N.....so when 13 is substracted from 27 the answer is 14. So the answer is option D.

When the nuclide strontium-80 decays by electron capture, the name of the product nuclide is Zirconium-80, and the symbol for the product nuclide is 80Zr.

In atomic physics, electron capture is a phenomenon that occurs when an electron merges with a nucleus and a neutrino to generate a neutron. The process takes place inside the nucleus, and it is one of the mechanisms for radioactive decay of atoms.

The process of electron capture takes place when the nuclide is not in the lowest energy state. This occurs mostly in atomic nuclei with a large neutron-to-proton ratio, such as isotopes of polonium, tin, and iodine. Nuclide strontium-80 is a nuclide that has 38 protons and 42 neutrons.

When this nuclide decays by electron capture, it results in the formation of a product nuclide. The product nuclide is Zirconium-80, which has 40 protons and 40 neutrons.

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The experimental value for the enthalpy of combustion will be lower than the true value.

There may be other causes, but the calorimeter itself is the most frequent one. The calorimeter is typically not completely insulated, unless it is an industrial model, allowing some heat to escape. The heat of combustion is subsequently underestimated because this heat is not recorded as a rise in temperature.

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Answer: Substances giving off heat and light, themselves, is always chemical. What we see in the sky are new colors and light. 1. Changing the size and shapes of pieces of wood would be a chemical change. 2. In a physical change, the makeup of matter is changed.

Explanation: