a satellite is revolving around the sun in a circular orbit with uniform velocity v. if the gravitational force suddenly disappears the velocity of the satellite will be?​

Roll a skateboard on sand, then roll it on gravel. - this experiment could answer this question. Hence, option (B) is correct.

An experiment is a technique used to confirm or deny a hypothesis, as well as assess the likelihood or effectiveness of something that has never been tried before. Experiments show what happens when a specific factor is modified, which sheds light on cause-and-effect relationships.

The purpose and scope of experiments vary widely, but they all rely on a repeatable process and a logical examination of the outcomes. Natural experimental experiments are also a thing.

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The period of the simple harmonic motion of the center of mass of the two spheres is approximately 0.770 seconds.

To find the period of the simple harmonic motion of the center of mass of the two spheres, we need to use the equation for the period of a mass-spring system:

T = 2π√(m/k)

where T is the period, m is the total mass of the system (two spheres), and k is the spring constant.

First, we need to find the total mass of the system:

m = 2m1 = 2(0.852 kg) = 1.704 kg

where m1 is the mass of one sphere.

Next, we need to find the spring constant:

k = 153 N/m

Now, we can calculate the period:

2π√(1.704 kg/153 N/m) ≈ 0.770 s

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The net charge enclosed by the outer surface before Q was introduced is 1530 \text{ nC}$$. The charge Q is 847 \text{ nC}$$. After Q is introduced, the charge on the inner surface of the conductor is -847 \text{ nC}$$.The charge on the outer surface of the conductor is  2377 \text{ nC}$$.

(a) The net charge enclosed by the outer surface before Q was introduced can be found using Gauss's Law:

$$\oint \vec{E} \cdot d\vec{A} = \frac{Q_{enc}}{\epsilon_0}$$

Since the electric field is uniform and directed outward, we can simplify this to:
$$E \cdot 4\pi r² = \frac{Q_{enc}}{\epsilon_0}$$

Plugging in the given values for E and r:
$$475 \cdot 4\pi (0.32)² = \frac{Q_{enc}}{8.85 \times 1\(0^{-12}\)}$$

Solving for Qenc:
$$Q_{enc} = 475 \cdot 4\pi (0.32)² \cdot 8.85 \times 1\(0^{-12}\)

= 1.53 \times 1\(0^{-9}\)\text{ C}

= 1530 \text{ nC}$$

(b) The charge Q can be found by comparing the electric field before and after it was introduced:
$$E_{before} - E_{after} = \frac{Q}{4\pi \epsilon_0 r²}$$

Plugging in the given values:
$$475 - 212 = \frac{Q}{4\pi (8.85 \times 1\(0^{-12}\)) (0.32)²}$$

Solving for Q:
$$Q = (475 - 212) \cdot 4\pi (8.85 \times 1\(0^{-12}\)) (0.32)²

= 8.47 \times 1\(0^{-10}\) \text{ C}

= 847 \text{ nC}$$

(c)After Q is introduced, the charge on the inner surface of the conductor will be equal and opposite to Q, so:

$$Q_{inner} = -Q = -847 \text{ nC}$$

(d) The charge on the outer surface of the conductor will be equal to the net charge enclosed by the outer surface, which is the sum of the original charge and Q:

$$Q_{outer} = Q_{enc} + Q =

1530 + 847

= 2377 \text{ nC}$$

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Given that the apparent weight of a passenger in an elevator is greater than his true weight, let's select the correct statement.

We have:

• Net force on the passenger when the elevator moves upward with an increasing speed:

ma = N - mg

Where mg is the weight of the passenger which acts downwards

N is the normal force which acts upwards.

• Apparent weight of the passenger:

N = mg + ma

Hence, we can see the apparent weight is greater than true weight.

• Also, when the elevator moves downward with a decreasing speed, the Net force is:

N = mg + ma

The elevator is speeding as it moves upward while it is slowing down when it is moving downward.

Therefre, the correct statement is that the elevator is speeding as it moves upward.

ANSWER:

b)The elevator is speeding as it moves upward.

Answer: C. Ask a question that can be answered by making observations.

Explanation: Just did it

Answer:

0.012 N

Explanation:

The formula to apply is that adopted from the Ampere law which is;

F= μ* I₁*I₂*l /2πd   where

F is force that one conductor exerts on the other.

μ = magnetic permeability of free space = 4π×10⁻⁷ T. m/A

I₁ = current in conductor one=10 A

I₂ = current in conductor two= 10 A

l= length of conductor= 3 m

d= distance between the conductors = 5 mm = 0.005 m

Applying the values in the equation

F= 4π×10⁻⁷ *10*10*3 / 2π*0.005

F= 6 * 10⁻⁵ / 0.005

F=0.012 N

Answer:

C) time and date

Explanation:

Celestial event is an astronomical phenomenon. This involves the conjunction of one or more celestial objects such as lunar and solar eclipse or meteor shower. The intersecting horizontal and vertical lines allow the astrologists to determine the time and date of the celestial event.

The kinetic energy is increased by the number of flights of steps that the rider will climb. The correct option is D.

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the stated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Given that the engineers are testing the waterslide for the theme park.

As we can know that kinetic and potential energy are two energies which are converted from one to another. The potential energy is increased by increasing the height of the slide from the ground level.

If the potential energy is higher than the kinetic energy of the slider will also increase during the downward journey.

So by increasing the number of flights of steps that the rider will climb there will be more kinetic energy in the slide. The correct option is D.

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Answer:

The charge in each ball will be 3 * 10^-12 C

Explanation:

(Assuming the correct charge of the second ball is 8 * 10^-12)

When the balls are brought in contact, all the charges are split evenly among then.

So first we need to find the total charge combined:

(-3 * 10^-12) + (8 * 10^-12) + (4 * 10^-12) = 9 * 10^-12 C

Then, when the balls are separated, each ball will have one third of the total charge, so in the end they will have the same charge:

(9 * 10^-12) / 3 = 3 * 10^-12 C

So the charge in each ball will be 3 * 10^-12 C

Electronegativity, symbol χ, measures the tendency of an atom to attract a shared pair of electrons (or electron density). An atom's electronegativity is affected by both its atomic number and the distance at which its valence electrons reside from the charged nucleus.

Answer:

True

Explanation:

If an object is at rest it will stay at rest unless a force acts on it.

Answer:

C the metal handle because it is a good conductor

Answer:

D.

Explanation:

Although the metal handle will last longer, if heated up enough it could burn her hand.

The magnetic force per unit length of the wire is (C) (0.49i - 0.51j - 1.37k) N/m.

To calculate the magnetic force per unit length of the wire, we can use the formula:

F = I * (L x B),

where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field.

Given:

Current, I = 3A

Length vector, L = √√3 * (i + j + k)

Magnetic field, B = 0.75i + 0.4k

Let's calculate the cross product of L and B:

L x B = | i j k |

|√√3 √√3 √√3|

|0.75 0 0.4|

To evaluate this cross product, we calculate the determinants:

(i) component: (√√3 * 0 - √√3 * 0.4) = -0.4√√3

(j) component: (-√√3 * 0.75 - √√3 * 0) = -0.75√√3

(k) component: (√√3 * 0.75 - √√3 * 0) = 0.75√√3

Now, multiply the cross product by the current:

F = 3A * (-0.4√√3i - 0.75√√3j + 0.75√√3k)

Simplifying this expression gives:

F = (-1.2√√3i - 2.25√√3j + 2.25√√3k) N

Therefore, the magnetic force per unit length of the wire is approximately (-1.2√√3i - 2.25√√3j + 2.25√√3k) N/m.

Comparing the given answer options, the closest match is C. (0.49i - 0.51j - 1.37k) N/m.

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Answer:

B 1,3, and 4

Explanation:

Answer:

In this text the upper case Greek letter Δ (delta) always means “change in” whatever quantity follows it; thus, Δx means change in position. Always solve for displacement by subtracting initial position x0 from final position xf

Wendy must stand 1.19m to the left of the edge of the roof so that the orange just barely passes over her head.

Bob's orange will travel down the slanted roof with a velocity of 4.47 m/s, and it will hit the ground 3.0 m below the edge of the roof. The height of the orange above the ground at the edge of the roof is 1.8 m, and the angle of the roof is 28.5° relative to the horizontal.

To calculate the distance Ar that Wendy has to stand from the edge of the roof, we must first calculate the time it takes for the orange to reach the ground. Using the equation for the vertical displacement of an object with an initial velocity, we can solve for the time, t:

d = v*t - (1/2)*g*t^2

0 = 4.47*t - (1/2)*9.8*t^2

t = 0.938s

Next, we must calculate the horizontal displacement of the orange from the time, t. Using the equation for the horizontal displacement of an object with an initial velocity and a constant acceleration we can solve for the displacement:

x = v*t + (1/2)*a*t^2

x = 4.47*0.938 + (1/2)*0*0.938^2

x = 4.19m

To calculate the distance Ar that Wendy must stand from the edge of the roof, we must subtract the horizontal displacement of the orange from the height of the edge of the roof:

Ar = 3.0 - 4.19

Ar = -1.19m

Therefore, Wendy must stand 1.19m to the left of the edge of the roof so that the orange just barely passes over her head.

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a) Cart is speeding up ; b) cart is slowing down and c) cart is not moving.

Force of friction is a contact force whereas friction is the force that resists motion when surface of one object comes in contact with surface of another. Example is the force of friction between two stones rubbed with each other.

Static friction magnitude is directly proportional to normal force magnitude and the roughness between sliding surfaces. The ratio of magnitude of frictional force divided by normal force magnitude is called as coefficient of friction. Friction takes place at the point of contact between two bodies.

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Yes, black holes 100% exist. They suck everything in their paths through a process known as spaghettification.

Answer:3000

Explanation:

given:u=0v=20m/st= 8sec

thereforea=v-u/t=20-0/8=20/8=5/2 m/som=1200 kg

thereforef=ma=1200*5/2=600*5=3000N

Answer:

towards the north.

Explanation:

The pressure at the upper level of a water flow into the house by means of pipe is 1081 kPa.

Calculate the cross-sectional area of the lower pipe:

A₁ = πr₁²

where:

A₁ = cross-sectional area of the lower pipe (m²)

π = mathematical constant (3.14)

r₁ = radius of the lower pipe (m)

A₁ = π(0.12 m)² = 0.0452 m²

Calculate the cross-sectional area of the upper pipe:

A₂ = πr₂²

where:

A₂ = cross-sectional area of the upper pipe (m²)

π = mathematical constant (3.14)

r₂ = radius of the upper pipe (m)

A₂ = π(0.06 m)² = 0.0113 m²

Calculate the flow rate per unit area:

q = Q/A

where:

q = flow rate per unit area (m³/s)

Q = flow rate (m³/s)

A = cross-sectional area (m²)

q = 6 m³/s / 0.0452 m² = 13.28 m²/s

Calculate the velocity of the water in the lower pipe:

v₁ = q/A₁

where:

v₁ = velocity of the water in the lower pipe (m/s)

q = flow rate per unit area (m³/s)

A₁ = cross-sectional area of the lower pipe (m²)

v₁ = 13.28 m²/s / 0.0452 m² = 29.3 m/s

Calculate the velocity of the water in the upper pipe:

v₂ = q/A₂

where:

v₂ = velocity of the water in the upper pipe (m/s)

q = flow rate per unit area (m³/s)

A₂ = cross-sectional area of the upper pipe (m²)

v₂ = 13.28 m²/s / 0.0113 m² = 117.0 m/s

Calculate the head loss:

hL = (v₁² - v2₂²) / 2g

where:

hL = head loss (m)

v₁ = velocity of the water in the lower pipe (m/s)

v₂ = velocity of the water in the upper pipe (m/s)

g = acceleration due to gravity (9.8 m/s²)

hL = (29.3 m/s)² - (117.0 m/s)² / 2(9.8 m/s²) = 23.2 m

Calculate the pressure at the upper level:

p₂ = p₁ + ρghL

where:

p₂ = pressure at the upper level (Pa)

p₁ = pressure at the lower level (Pa)

ρ = density of water (1000 kg/m³)

g = acceleration due to gravity (9.8 m/s²)

hL = head loss (m)

p₂ = 400 kPa + 1000 kg/m³(9.8 m/s²)(23.2 m) = 1081 kPa

Therefore, the pressure at the upper level is 1081 kPa.

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Hey,

This is a complicated question that would be debated by many physicists. How to answer this question when we are struggling with the genesis of the universe? Many theories on the origin of the universe have been put forward, but the Bing Bang is probably, or at least to date, the most likely theory. If today the universe is expanding, some astronomers hypothesise that before the Bing Bang the universe already existed but that it was condensing, according to this hypothesis the Bing Bang would correspond to the limit point of compression of the universe.  

But if we remain in the traditional theory the Bing Bang is at the origin of all the matter we know, as well as light. Before the Bing Bang, in other words before the universe, there was NOTHING.

Answer:

for a mass m = 10kg on Earth it`s weight is W = mg = 10 x 10 = 100N.

Explanation:

Answer:

F= mg= 0.180 kg x 9.8 m/s^2= 1.80 N

The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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The position they could possibly have zero electric field is C.

An electric field is a physical field that exists in the space surrounding electrically charged particles or objects. It is a vector field, meaning that it has both magnitude and direction.

When a charged particle is present in a space, it creates an electric field that exerts a force on any other charged particles in the vicinity.

The strength of the electric field at any given point is defined as the force per unit charge that a small test charge would experience if placed at that point.

The magnitude and direction of the electric field depend on the distance between the charges and their magnitudes. The electric field is stronger when the charges are closer together and weaker when they are farther apart.

So position they could experience zero electric field is C, assuming point C if very far from the two charges.

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Answer:

-48cm

Explanation:

For a convex lens f is +ve and V is +ve

Using the formula 1/f=1/v+1/u

u=12cm and f=16cm

1/16-1/12=1/v

1/v=-1/48

v=-48cm