A scientist adds ice to water to cool it down for an experiment. The temperature of the water as a function
of time since the ice is added is f(x) = 0.2x² - 6x +79. The experiment needs to be conducted when
the temperature of the water is 60 degrees or cooler.

The two times the water will be 60 degrees are at (9.9, or 3.6, or 2.9) and (32.9, or 39.9, or 26.4)
This means that the scientist has about (22.8, or 30)
minutes to conduct her experiment.

The main answer for the first argument is that we cannot prove that the band could play rock music based on the given premises and rules of inference.

1. Let's assign the following propositions:

  - P: The band could play rock music.

  - Q: The refreshments were delivered on time.

  - R: The New Year's party was canceled.

  - S: Alicia was angry.

  - T: Refunds were made.

2. The given premises can be expressed as:

  (¬P ∨ ¬Q) → (R ∧ S)

  R → T

3. To prove that the band could play rock music (P), we need to derive it using valid rules of inference.

4. Using the premises, we can apply the rule of modus tollens to the second premise:

  R → T        (Premise)

  Therefore, ¬R.

5. Next, we can use disjunctive syllogism on the first premise:

  (¬P ∨ ¬Q) → (R ∧ S)     (Premise)

  ¬R                    (From step 4)

  Therefore, ¬(¬P ∨ ¬Q).

6. Applying De Morgan's law to step 5, we get:

  ¬(¬P ∨ ¬Q)  ≡  (P ∧ Q)

7. Therefore, we can conclude that the band could play rock music (P) based on the premises and rules of inference.

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We will repeat the exact same procedure. Something may have gone wrong.                                                                                                    

The special theory of relativity by German-born scientist Albert Einstein contains the equation \(E=mc^{2}\), which conveys the idea that mass and energy are one and the same physical substance and may be transformed into one another. The kinetic energy (E) of a body is equal to its increased relativistic mass (m) multiplied by the square root of the speed of light.

Because the mass and the speed of light are both constants, we are unable to test a new variable. Since our findings don't match the accepted formula, we cannot share them.

The result obtained is wrong we cannot apply it to another experiment. The only way we can find the correct result is by repeating the experiment. Because something may have gone wrong on the first attempt.

Therefore, the correct answer is

d) Repeat the exact same procedure.  

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The correct question is: Suppose you conduct one experiment and find that the \(E=mc^{3}\), rather than the historically accepted formula, \(E=mc^{2}\). What should you do next?

a.Test a new variable

b.Share your findings

c.Apply your results to a new experiment

d.Repeat the exact same procedure                                                                                                                                                                                                                                                                                                                                                                                      

The calculated length of the rectangle is 10.5 cm

From the question, we have the following parameters that can be used in our computation:

Six identical right-angled triangle

The length of the right-angled triangle is

base length = 7 cm

based on the arrangement, we have

Rectangle length = base length + 1/2 * base length

So, we have

Rectangle length = 7 + 1/2 * 7

Evaluate

Rectangle length = 10.5

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At t = π/4, the unit tangent vector is ⟨\(-\sqrt{2} /2, \sqrt{2}/2, 1/\sqrt{2}\)⟩, the unit normal vector is ⟨\(-\sqrt{2} /2, \sqrt{2}/2, -\sqrt{2}/14\)⟩, and the unit binormal vector is ⟨-sqrt(2)/14, -sqrt(2)/14, -3sqrt(2)/14⟩.

The arc length of the curve over the interval [0, 2π] can be computed using the formula L = ∫ \(\sqrt{(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2}\) dt, which results in L = 14π.

To find the unit tangent vector, we differentiate r(t) with respect to t and normalize the resulting vector. Differentiating r(t) gives r'(t) = ⟨-7sin(t), 7cos(t), 1⟩. Evaluating r'(t) at t = π/4, we get r'(π/4) = ⟨-7/\(\sqrt{2}\), 7/\(\sqrt{2}\) 1⟩. To normalize this vector, we divide each component by its magnitude, resulting in the unit tangent vector ⟨-\(\sqrt{2}\)/2, \(\sqrt{2}\)/2, 1/\(\sqrt{2}\)⟩.

To find the unit normal vector, we differentiate r'(t) with respect to t, normalize the resulting vector, and evaluate it at t = π/4. Differentiating r'(t) gives r''(t) = ⟨-7cos(t), -7sin(t), 0⟩. Evaluating r''(t) at t = π/4, we get r''(π/4) = ⟨-7/\(\sqrt{2}\), -7/\(\sqrt{2}\), 0⟩. Normalizing this vector gives the unit normal vector ⟨-\(\sqrt{2}\)/2, \(\sqrt{2}\)/2, -\(\sqrt{2}\)/14⟩.

To find the unit binormal vector, we take the cross product of the unit tangent vector and the unit normal vector. The cross product of the unit tangent vector ⟨-\(\sqrt{2}\)/2, \(\sqrt{2}\)/2, 1/\(\sqrt{2}\)⟩ and the unit normal vector ⟨-\(\sqrt{2}\)/2, \(\sqrt{2}\)/2, -\(\sqrt{2}\)/14⟩ results in the unit binormal vector ⟨-\(\sqrt{2}\)/14, -\(\sqrt{2}\)/14, -3sqrt(2)/14⟩.

To compute the arc length of the curve over the interval [0, 2π], we use the formula L = ∫ \(\sqrt{(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2}\) dt. Plugging in the derivatives of the components of r(t), we have L = ∫ \(\sqrt{(49sin^2(t) + 49cos^2(t) + 1)}\) dt. Simplifying, we get L = ∫ √(50) dt = √(50) ∫ dt = √(50)t. Evaluating this integral from 0 to 2π gives L = √(50)(2π) = 14π.

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Answer:

Yes

Step-by-step explanation:

20 needed to get 80 %. You got one more than that so you got slightly more. So yes you did. You can also make 25 to 100 and 21 x4 so  that gives you 84 % . So you scored %84.

Good job

Answer:

14+19=33 33 divided by 23=?

Step-by-step explanation:

triangle with the given side is a right triangle;14mm, 19mm, 23mm ... Use the Pythagorean theorem that only works for right triangles.

If you want to get rid of a square root, square. Similarily, if you want to get rid of a cube root, cube. You have to do the same thing on both sides. When you are done make the variable the subject.

The value of the expression +, can be determined by performing matrix addition on the given matrices and then evaluating the resulting expression. Let's proceed with the calculations: Given matrices:

A = [[1, 2, 0], [3, 2 + c, -1], [2, 2 + c, 2 + c]]

B = [[0, 2 + c, -3], [3, c, -1], [0, 3, -1]]

Performing matrix addition on A and B, we add the corresponding elements:

A + B = [[1 + 0, 2 + (2 + c), 0 + (-3)],

[3 + 3, (2 + c) + c, -1 + (-1)],

[2 + 0, (2 + c) + 3, (2 + c) + (-1)]]

Simplifying further, we get:A + B = [[1, 4 + c, -3],

[6, 2 + 2c, -2],

[2, 5 + c, 1 + c]

Therefore, the value of + is equal to the matrix [[1, 4 + c, -3], [6, 2 + 2c, -2], [2, 5 + c, 1 + c]].

We can store this value in the string FG_sum using valid Python code formatting as follows:

FG_sum = "[[1, 4 + c, -3], [6, 2 + 2 * c, -2], [2, 5 + c, 1 + c]]"

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Answer:

Step-by-step explanation:

its nba and kyrie

Answer:

nba aND KYRIE

Step-by-step explanation:

The probability that exactly 4 total launches will be performed until an unsuccessful launch occurs is approximately 0.0720 or 7.2%

The probability of exactly 4 total launches being performed until an unsuccessful launch occurs, we can use the geometric probability formula.

In this case, the probability of a successful launch (p) is 0.7 (since the probability of an unsuccessful launch is 0.3). We want to find the probability of 4 successful launches followed by an unsuccessful launch.

The probability of exactly 4 successful launches followed by an unsuccessful launch can be calculated as follows:

P(4 successful launches followed by an unsuccessful launch) = (p⁴) × (1-p)

P(4 successful launches followed by an unsuccessful launch) = (0.7⁴) × (1-0.7)

P(4 successful launches followed by an unsuccessful launch) = 0.7⁴ × 0.3

P(4 successful launches followed by an unsuccessful launch) = 0.2401 × 0.3

P(4 successful launches followed by an unsuccessful launch) ≈ 0.0720

Therefore, the probability that exactly 4 total launches will be performed until an unsuccessful launch occurs is approximately 0.0720 or 7.2%

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Answer: -1/28 gallon

Step-by-step explanation:

divide both numbers by 4 since its 1/4 a minute (-5/7 ÷ 4 and 4/7 ÷ 4) then add them, (-5/28 + 4/28= -1/28)

Answer: -1/28 gallon

Step-by-step explanation:

Step-by-step explanation:

If Kneaders in Lehi sold 4000 rolls last year and expects a 22% increase in sales this year, the number of rolls they will bake this Thanksgiving can be calculated as follows:

Calculate the 22% increase in sales:

22% of 4000 = 0.22 x 4000 = 880

Add the increase to last year's sales to get the total expected sales this year:

4000 + 880 = 4880

Therefore, Kneaders in Lehi will bake approximately 4880 rolls this Thanksgiving rounded to the nearest whole roll.

Answer:

4,880 rolls, see explanation below :)

Step-by-step explanation:

1.22(4000)= 4,880

and you instantly get your answer.

if you don't understand I basically did 1.22 times 4000 and got 4,880.

Formula: X + %increase/decrease x orginal amount/amount sold last year of rolls, (we can assume there is an invisible 1 in front of the x)

Basically Everything Behind This, Kind of (sorry I'm not the best explainer! :( ;

Here in this case 22% as a decimal is 0.22, how we get to a decimal from a percent: 22 divided by a 100= 0.22. and we got the decimal for 22%!

So X + 0.22= 1.22, and remember the X has an invisible 1 in front of it. so 1 + 0.22= 1.22 in other words.

Now the other value we have is 4000, so we multiply it by 1.22 and get 4,880. And this is how we got to our answer.

As per the concept of probability, the number of parts should they order under their regular shipment for the next six months is approximately 18.

In this scenario, the demand rate is given as a Poisson distribution with a mean of 6.5. The holding cost is $5 per part, and the unit cost under regular, semiannual shipment is $32 per part, while the cost of an emergency shipment is $50 per part.

Since we know that orders are placed semiannually, we need to find the order quantity that will last for six months. To do this, we can divide the total annual demand by 2. Therefore, the annual demand for part 1aa-66 is 6.5 x 2 = 13.

Now, we can use the EOQ formula to find the optimal order quantity:

EOQ = √(2DS/H)

Where D is the demand rate, S is the ordering cost, and H is the holding cost.

Plugging in the values, we get:

EOQ = √(2 x 13 x $32 / $5) = √332.8 ≈ 18.23

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n(p(a)) = 256

256 = 2^8

n(a) = 8

Must click thanks and mark brainliest

A sequence is (recursively) defined as a1 = 0, a2 = 1, n>2, \(a_n = a_{n-1} - 3a_{n-2}\). The first seven terms are 0, 1, 1, -2, -5, 1, 16.

A recursive sequence is a sequence in which terms are defined using one or more previous terms which are given.

a1 = 0

a2 = 1

\(a_n = a_{n-1} - 3a_{n-2}\)

a3 = a2 - 3*a1 = 1 - 0 = 1

a4 = a3 - 3*a2 = 1 - 3 = -2

a5 = a4 - 3*a3 = -2 - 3 = -5

a6 = a5 - 3*a4 = -5 + 6 = 1

a7 = a6 - 3*a5 = 1 +15 = 16

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Answer:

The correct answer is 5b²-b-2

Answer:

B

Step-by-step explanation:

Answer:

4329

Step-by-step explanation:

I coan't really explain this sorry.

I hope this helps though!

Also if it's correct could I have a Brainly I need 1 more to level up :3 Thx!

The requried differential equation is dy/dx = -x/y, as per the condition of the slope field.

One example of a differential equation that has a slope field with positive slopes in quadrants I and II and negative slopes in quadrants III and IV is:

dy/dx = -x/y

In quadrant I, both x and y are positive, so the slope is negative. In quadrant II, x is negative and y is positive, so the slope is positive. In quadrant III, both x and y are negative, so the slope is positive. In quadrant IV, x is positive and y is negative, so the slope is negative.

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Answer:

16

Step-by-step explanation:

You do the parenthesis first which is 2 then multiply that by 8 which is 16.

Answer:

1) 8

2) 11

3) 15

Step-by-step explanation:

1) x - 3

2) x

3) x + 4

x-3+x+x+4 = 34

3x + 1 = 34

3x = 34-1

x = 33/3

x = 11

The required numbers are 8, 11, and 15.

Given that,
The sum of the three numbers is 34. The first is 3 less than the second, while the third is 4 more than the second. Find the numbers is to be determined.

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

Let the three numbers be x, y and z
The Sum of the number is 34,
x + y + z = 34   - - - - -(1)

The first is 3 less than the second,
y = x + 3

The third is 4 more than the second.
z = y + 4
z = x + 7

Put y and z in equation 1
x + x +3 +x +4 = 34
3x = 24
x = 8

Now
Second number =
y = x + 3
y = 8 + 3 = 11

Third number
z = x + 7
z = 8 + 7
z = 15

Thus, the required number are 8, 11, and 15.

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The system of 5x + 2y ≤ 25 is given by 20x + 15y ≤ 120 and 5x + 2y ≤ 25

An equation is an expression used to show the relationship between two or more variables and numbers.

Let x represent the cucumber and y represent the amount of carrots, hence:

20x + 15y = 2(60)

20x + 15y ≤ 120  (1)

Also:

5x + 2y ≤ 25 (2)

The system of 5x + 2y ≤ 25 is given by 20x + 15y ≤ 120 and 5x + 2y ≤ 25

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Answer:

A I'm pretty sure

Step-by-step explanation:

hope that helps .-.

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\(y = \stackrel{\stackrel{m}{\downarrow }}{-1}x+2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\)

now, we know that our line is perpendicular to that one, thus

\(\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-1\implies \cfrac{-1}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{-1}\implies 1}}\)

so we're really looking for the equation of a line that has a slope of 1 and runs through (0 , 10)

\((\stackrel{x_1}{0}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{1}(x-\stackrel{x_1}{0}) \\\\\\ y-10=x\implies y=x+10\)

Answer:

1/3 pound per person

Step-by-step explanation:

(All)    (People)   (Amount per person)

1.32  /  4          = .33                        

.33 = 1/3

The resulted integral is \(I=\frac{8}{3} \times \frac{5 \pi}{16}=\frac{5 \pi}{6}\).

In mathematics, an integral is either a number representing the region under a function's graph for a certain interval or just an added to the initial, the derivative of which is initial function (indefinite integral).

Computation of the integrals:

Step 1: We employ the equations in cylindrical coordinates.

\(x=r \cos \theta, y=r \sin \theta, z=z\)

Thus, in cylindrical coordinate system,

E lies above the paraboloid \(z=r^{2}\) and below the plane \(z=2 r \sin \theta\) .

Therefore, the top part E is  \(z=2 r \sin \theta\) is the cross-section between paraboloid and the plane.

Now, at the cross-section use, \(r^{2}=2 r \sin \theta\) and  \(z=2 r \sin \theta\) .

Thus, the limits are given as ;

\(r^{2} \leq z \leq 2 r \sin \theta \quad 0 \leq r \leq 2 \sin \theta\)

Apply the limits as compute the integration;

\(\begin{aligned}I=\iiint_{E} z d V &=\int_{0}^{\pi} \int_{0}^{2 \sin \theta} \int_{\tau^{2}}^{2 r \sin \theta} z r d r d z d \theta \\&=\int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[\frac{z^{2}}{2}\right]_{r^{2}}^{2 r \sin \theta} r d r d \theta \\&=\frac{1}{2} \int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[4 r^{2} \sin ^{2} \theta-r^{4}\right] r d r d \theta\end{aligned}\)

                       \(\begin{aligned}&=\frac{1}{2} \int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[4 r^{3} \sin ^{2} \theta-r^{5}\right] d r d \theta \\&=\frac{1}{2} \int_{0}^{\pi}\left[r^{4} \sin ^{2} \theta-\frac{r^{6}}{6}\right]_{0}^{2 \sin \theta} d \theta \\&=\frac{8}{3} \int_{0}^{\pi} \sin ^{6} \theta d \theta\end{aligned}\)

Step 2: Now, calculate for the \(I_{1}=\int_{0}^{\pi} \sin ^{6} \theta d \theta\).

 \(\begin{aligned}\sin ^{6} \theta &=\left(\sin ^{2} \theta\right)^{2} \times \sin ^{2} \theta \\&=\left[\frac{1-\cos 2 \theta}{2}\right]^{2} \times\left[\frac{1-\cos 2 \theta}{2}\right] \\&=\frac{1}{8}\left(1-2 \cos 2 \theta+\cos ^{2} 2 \theta\right)(1-2 \cos 2 \theta) \\&=\frac{1}{8}\left(1-2 \cos 2 \theta+\frac{1+\cos 4 \theta}{2}\right)(1-2 \cos 2 \theta)\end{aligned}\)

         \(\begin{aligned}&=\frac{1}{16}(3-4 \cos 2 \theta+\cos 4 \theta)(1-2 \cos 2 \theta) \\&=\frac{1}{32}(10-15 \cos 2 \theta+6 \cos 4 \theta-\cos 6 \theta)\end{aligned}\)

Further compute the value of

   \(\begin{aligned}I_{1} &=\int_{0}^{\pi} \sin ^{6} \theta d \theta \\&=\frac{1}{32} \int_{0}^{\pi}(10-15 \cos 2 \theta+6 \cos 4 \theta-\cos 6 \theta) d \theta \\&=\frac{1}{32}\left[10 \theta-\frac{15 \sin 2 \theta}{2}+\frac{3 \sin 4 \theta}{2}-\frac{\sin 6 \theta}{6}\right]_{0}^{\pi} \\&=\frac{5 \pi}{16}\end{aligned}\)

Therefore, the obtained integral is  \(I=\frac{8}{3} \times \frac{5 \pi}{16}=\frac{5 \pi}{6}\).

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The complete question is -

Use cylindrical or spherical coordinates, whichever seems more appropriate. Evaluate ∫∫∫E z dV, where E lies above the paraboloid

z = x² + y²

and below the plane z = 2y. Use either the Table of Integrals or a computer algebra system to evaluate the integral.

Answer:

Answer:

This is in Standard form.  Did you mean scientific form?

1.47 x \(10^{-4}\)

Step-by-step explanation:

You move the decimal so that the number is between 1 and 10.  Then since in standard form the number is much less than 1.47, you determine how muhc less my how many places you need to move the decimal to put it back in standard form.  Since you would need to move the decimal 4 places to the left, the exponent would be -4

Answer:

The answer is 49 inches

Step-by-step explanation:

Divide 294 by 6 to get the answer.

Hope that helps!

Answer:

49 inches

We know that for every 6 feet in real life, there will be 1 inch in the picture.

So, that means if we divide 294 by 6, we can find how many inches wide the picture is.

294 ÷ 6 = 49

Since there are 49 sixes in 294, the picture is 49 inches wide.

The value of x to the nearest degree is 30°.

What is Triangle ?

A triangle is one that has three sides, three angles, and whose total angles is always 180 degrees.

Three line segments are linked end to end to make a triangle, a two-dimensional geometric structure with three angles. These line segments are known as sides, and their intersections are known as vertices.

The measurements of a triangle's sides and angles are used to categorize it.

We can use trigonometric ratios to get the value of x in the right triangle given:

sin(x) = opposite/hypotenuse

\(sin(x) = 8/17x = sin^{-1(8/17)}x = 29.74^{o} $ (approx.) $\)

Therefore, the value of x to the nearest degree is 30°.

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The probability that a student will get 4 or more correct answers just by guessing is d: 11/3^5.

The probability of getting 4 or more correct answers just by guessing in a multiple-choice examination with 5 questions and three alternative answers for each question can be calculated by using the binomial probability formula. The formula is P(X = x) = nCx * p^x * (1-p)^(n-x), where n is the number of questions, x is the number of correct answers, p is the probability of getting a correct answer, and nCx is the binomial coefficient.

For 4 correct answers, the probability is:

P(X = 4) = 5C4 * (1/3)^4 * (2/3)^1 = 5 * (1/81) * (2/3) = 10/243

For 5 correct answers, the probability is:

P(X = 5) = 5C5 * (1/3)^5 * (2/3)^0 = 1 * (1/243) * 1 = 1/243

The total probability of getting 4 or more correct answers is the sum of these two probabilities:

P(X >= 4) = P(X = 4) + P(X = 5) = 10/243 + 1/243 = 11/243

Therefore, the correct answer is d. 11/3^5.

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