The concentration of the reactant after 2.00 minutes is 0.03399 M or approximately 0.034 M.
The second-order reaction can be represented by the following equation:
rate = k[A]^2
where [A] is the concentration of the reactant and k is the rate constant.
We can use the integrated rate law for a second-order reaction to determine the concentration of the reactant at a given time:
1/[A] - 1/[A]_0 = kt
where [A]_0 is the initial concentration of the reactant, t is the time elapsed, and k is the rate constant.
Substituting the given values into the equation, we get:
1/[A] - 1/1.50 = (0.004501 M^-1 s^-1)(2.00 min * 60 s/min)
Solving for [A], we get:
1/[A] = 0.03399 M^-1
[A] = 29.42 M
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what type of solution do you have if you dissolve 20.2 g of potassium chlorate in 0.300 L
solution of potassium chlorate,
K
C
I
O
3
, has 20 grams of the salt dissolved in 100 grams of water at 70 C. Approximately how many more grams of the salt can be added to the solution before reaching the saturation point?
which of the following correctly shows the measurement 9.603 s rounded to three significant figures? 9.6030s 9.6s 9.60s 9.603s
Answer: I think the answer is 9.60s
Explanation: Hope it helps :)
Mg + S --> MgS Determine the number of grams of magnesium sulfide produced when 2.3 grams of magnesium combines with 7.6 grams of sulfur.
The balanced chemical equation for the reaction between magnesium and sulfur can be written as:Mg + S → MgSUsing this equation, we can determine the number of grams of magnesium sulfide produced when 2.3 grams of magnesium combines with 7.6 grams of sulfur. The first step is to determine which of the reactants is limiting.
The limiting reactant is the reactant that is completely consumed when the reaction goes to completion. The other reactant is in excess and will be left over once the reaction is complete.To determine the limiting reactant, we need to convert the mass of each reactant to moles. The molar mass of magnesium is 24.31 g/mol, and the molar mass of sulfur is 32.06 g/mol.Moles of Mg = 2.3 g / 24.31 g/mol = 0.0945 molMoles of S = 7.6 g / 32.06 g/mol = 0.237 molThe ratio of moles of magnesium to moles of sulfur is 1:1.
Therefore, magnesium is the limiting reactant.To determine the mass of magnesium sulfide produced, we need to use the stoichiometry of the balanced equation. One mole of magnesium reacts with one mole of sulfur to produce one mole of magnesium sulfide. Therefore, 0.0945 moles of magnesium will react with 0.0945 moles of sulfur to produce 0.0945 moles of magnesium sulfide.Mass of MgS = 0.0945 mol × 56.30 g/mol = 5.32 g.
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If a current of 5 amperes is passed through an electrolytic cell containing agno3 for 2.5 hours, how many teaspoons of silver will precipitate?
To calculate the amount of silver that will precipitate, we need to use Faraday's laws of electrolysis, which relate the substance produced or consumed in a cell to the amount of electric charge passed through it.
What are Faraday's laws of electrolysis?The first law of electrolysis states that the amount of substance produced or consumed in an electrolytic cell is proportional to the amount of electric charge passed through the cell. The proportionality constant is known as the Faraday constant, which is equal to 96,485 coulombs per mole of electrons.
The second law of electrolysis states that the amount of different substances produced or consumed in an electrolytic cell is proportional to their respective chemical equivalents.
In this problem, the substance being produced is silver, which has a chemical equivalent of 1 (i.e., one mole of electrons produces one mole of silver). The electric charge passed through the cell can be calculated as follows:
electric charge = current x time
electric charge = 5 A x 2.5 hours x 3600 s/hour
electric charge = 45,000 C
The amount of silver that will precipitate can be calculated using the first law of electrolysis and the Faraday constant:
moles of silver = electric charge / Faraday constant
moles of silver = 45,000 C / 96,485 C/mol
moles of silver = 0.467 mol
To convert moles of silver to mass, we need to know the molar mass of silver. The molar mass of silver is 107.87 g/mol. One teaspoon is approximately 5 mL.
mass of silver = moles of silver x molar mass
mass of silver = 0.467 mol x 107.87 g/mol
mass of silver = 50.4 g
number of teaspoons = mass of silver / (density of silver x volume of teaspoon)
Assuming the density of silver is 10.5 g/mL, we get:
number of teaspoons = 50.4 g / (10.5 g/mL x 5 mL)
number of teaspoons = 0.96 teaspoon
Therefore, approximately 0.96 teaspoons of silver will precipitate.
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what element has an electron
configuration of 2-8-8-1:
OSSIBLES2
Mulchem with what would happen we have
Langs
Besi
III
Sko
Het
* Vedhere very little proteson against uyiri, Senal amage, ara pathogens the viruses are busers
35 Wd be able to be one to our body and remove carbon diote on our biker
45 Wd be able to gicky react to save ourselves from daneous stations
3 Wed he wable to crostate and deliver orygen ad carbon dioxide throughout our body
1
2
2
4
5
Next >
the specific heat capacity of liquid water is 4.18 j/g oc. calculate the quantity of energy required to heat 1.50 g of water from 26.5oc to 83.7oc
The specific heat capacity of liquid water is 4.18 J/g °C. The quantity of energy required to heat 1.50 g of water from 26.5°C to 83.7°C is 359 J.
The specific heat of a substance is defined as the heat required to raise a temperature of a substance by 1°C. In other words, it is also referred as a mass heat capacity.
The quantity of energy for a substance is calculated as
q=m×c×ΔT
Where ΔT=(T_f-T_i)
T_f=83.7°C, T_i=26.5°C
ΔT=(83.7-26.5)°C=57.2°C
And c=4.18 J/g °C
m=1.50g
Substitute all the values in the formula
q=1.50g×(4.18 J/g°C)×57.2°C
q=358.644 J
q=359 J
Therefore, the heat required for 1.50g of water is 359 J.
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Select the correct answer.
What is the mole ratio of Cl₂ to Br₂ in the given reaction?
Cl₂ + 2NaBr-2NaCl + Br₂
OA 1:1
OB. 1:2
OC. 2:3
O D. 2:1
Answer:
A.) 1:1
Explanation:
You can determine the mole ratio between substances by comparing their coefficients in the balanced equation. Both Cl₂ and Br₂ have coefficients of 1. Therefore, they have a 1 to 1 (1:1) relationship.
If you were comparing the mole ratio of Cl₂ and NaBr, they would have a 1:2 relationship because Cl₂ has a coefficient of 1 and NaBr has a coefficient of 2.
Calculate the molarity of each of the following solutions. Use the periodic table if necessary.
A salt solution with a volume of 250 mL that contains 0.70 mol NaCl.
M
Answer: ;)
Explanation:
Molarity of a salt solution with a volume of 250 mL that contains 0.70 mol NaCl is 2.8.
Molarity = (No. of moles of solute ÷ Volume of solution in liters)
Molarity = (0.70 ÷ 0.250)
Molarity = 2.8
Molarity of a given solution is known as the total number of moles of solute per litre of the solution. A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.
Therefore, Molarity of a salt solution with a volume of 250 mL that contains 0.70 mol NaCl is 2.8.
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Need this asap!!!
Which type of substance gives off hydroxide ions when dissolved in water?
Acid
Base
Gas
Metal
Answer:
Acid
Explanation:
The reaction of ethane gas C2H6 with chlorine gas produces C2H5Cl as its main product along with HCl. (In addition, the reaction invariably produces a variety of other minor products, including C2H4Cl2, C2H2Cl3, and others. Naturally, the production of these minor products reduces the yield of the main product.) (a) Write out the complete, balanced chemical reaction of main reaction taking place. (b) Calculate the percent yield of C2H5Cl if the reaction of 300. grams of ethane with 650. grams of chlorine produced 490. grams of C2H5Cl.
a) The balanced equation is :
C₂H₆ + Cl₂ ---> C₂H₅Cl + HCl
b) The percent yield is the 83.0 % %.
a) The balanced equation is given below :
C₂H₆ + Cl₂ ---> C₂H₅Cl + HCl
b) mass of the ethane = 300 g
molar mass of the ethane = 30 g/mol
moles of the ethane = 300 / 30
= 10 mol
mass of chlorine = 650 g
molar mass of the chlorine = 71 g /mol
moles = 650 / 71
= 9.15 mol
it is clear the the chlorine is the limiting reactant.
1 mole of the chlorine produces the 1 mole of the C₂H₅Cl
moles of the C₂H₅Cl = 9.15 mol
mass of the C₂H₅Cl = 9.15 × 64.5
= 590.175 g
The percent yield = (experimental yield / theoretical yield ) × 100 %
= ( 490 / 590 .175 ) × 100 %
= 83.0 %
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You have two test tubes containing white crystalline solids labeled a and b. the solubility and melting point ranges of each solid are the same. describe how you could use a melting point apparatus to determine if a and b were the same or different compounds
Using a melting point apparatus, you can compare the melting point ranges of compounds A and B to determine if they are the same or different compounds.
To determine if compounds A and B are the same or different using a melting point apparatus, follow these steps:
1. Set up the melting point apparatus according to the manufacturer's instructions.
2. Take a small amount of compound A and place it into a capillary tube.
3. Insert the capillary tube into the melting point apparatus.
4. Gradually increase the temperature and observe the melting process of compound A.
5. Note the temperature range over which compound A melts and record it.
6. Repeat steps 2-5 for compound B.
7. Compare the melting point ranges of compounds A and B.
8. If the melting point ranges of A and B are identical, it suggests they are the same compound.
9. If the melting point ranges of A and B differ, it suggests they are different compounds.
10. To confirm the results, additional tests such as solubility and chemical analysis may be performed.
In summary, using a melting point apparatus, you can compare the melting point ranges of compounds A and B to determine if they are the same or different compounds.
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Data And Report Submission - Synthesis of Aspirin (1pt) Synthesis of Aspirin How will you collect data for this experiment? Data entryMass of salicylic acid used 0.152Volume of acetic anhydride used 0.36Mass of aspirin obtained 0.176Beginning of melting point range for product 125.8End of melting point range for product 131.3Moles of salicylic acid _________________Moles of acetic anhydride (mol)
To collect data for the Synthesis of Aspirin experiment, you will measure the mass of salicylic acid, volume of acetic anhydride, mass of aspirin obtained, and the beginning and end of the melting point range for the product.
- Mass of salicylic acid used: 0.152 g
- Volume of acetic anhydride used: 0.36 mL
- Mass of aspirin obtained: 0.176 g
- Beginning of melting point range for product: 125.8 °C
- End of melting point range for product: 131.3 °C
Salicylic acid has a molar mass of 138.12 g/mol, and acetic anhydride has a molar mass of 102.09 g/mol. You can then calculate moles using the formula: moles = mass (g) / molar mass (g/mol).
Hence, For the Synthesis of Aspirin experiment, collect data by measuring the mass of salicylic acid, volume of acetic anhydride, mass of aspirin obtained, and the beginning and end of the melting point range for the product.
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What is the organelle that builds the protein molecules using the instructions from the genes?
1 Gene version
2 nucleus
3 ribosomes
4DNA
5 Golgi Bodies
what are the two main elements found in ceramics? sodium (na) and silicon (si) carbon (c) and oxygen (o) hydogen (h) and silicon (si) oxygen (o) and silicon (si)
The two main elements that are found in ceramics are Oxygen and silicon.
Ceramics are extra than pottery and dishes: clay, tiles, glass, as well as cement are in all likelihood the best-regarded examples. Ceramic substances are utilized in electronics because, relying on their composition, they'll be semiconducting, superconducting, ferroelectric, or an insulator. They are hard wearing, resistant to high temperatures and good corrosion resistance.
Therefore, option d is the correct choice as the two main elements are silicon and oxygen.
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. Classify each of the organisms in Figures 2 and 3 as
herbivore, carnivore, or omnivore. Explain your
classifications.
HELLLPPPP MEEEE PLEASE
Answer:
Herbivore, Omnivore & Carnivore
Explanation:
Herbivore they eat grass, Omnivores eat fruits and vegetables & Carnivores eat meat or flesh so that's why herb then omni and last carni bc so omni and herbi eat like the same thing
Answer:
Herbivore, Omnivore & Carnivore
Explanation:
Gold-198 is used to treat liver cancer. its half-life is 2.7 days. if you ingest 3.75 mg of au-198, how long would you have to wait for the amount of au-198 to fall to 0.75 mg?
To wait for the amount of Au-198 to fall to 0.75 mg when Gold-198 is used to treat liver cancer and has half-life is 2.7 days if ingest 3.75 mg of Au-198 would wait 6.26 days.
Gold-198 has a half-life of 2.7 days, which means that after 2.7 days, half of the initial amount of gold-198 would decay. To find out how long it would take for the amount of gold-198 to fall to 0.75 mg, we can use the following formula:
Final amount = Initial amount × (1/2)^(number of half-lives)
Let's assume that the initial amount of gold-198 is 3.75 mg, and we want to find out how many half-lives it would take for the amount to fall to 0.75 mg. We can set up the equation as follows:
0.75 mg = 3.75 mg × (1/2)^(number of half-lives)
Dividing both sides by 3.75 mg, we get:
0.2 = (1/2)^(number of half-lives)
Taking the logarithm of both sides, we get:
log(0.2) = number of half-lives x log(1/2)
Solving for the number of half-lives, we get:
number of half-lives = log(0.2) / log(1/2)
Using a calculator, we get:
number of half-lives ≈ 2.32
Therefore, it would take approximately 2.32 x 2.7 days = 6.26 days for the amount of gold-198 to fall to 0.75 mg.
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Skepticism is important in this scenario because it would help him to learn from the investigations of his colleagues. Ask future questions related to the investigation. Communicate his results at a conference. Ensure that his conclusion is supported by evidence.
Answer:
hello your question is incomplete below is the missing part of the question
A biochemist performs an experiment to study the behavior of water molecules near proteins. He concludes that water molecules occur in groups of five in the presence of proteins.
answer : Ensure that his conclusion is supported by evidence.
Explanation:
Skepticism during the conduction of an experiment is an act/trait that a scientist possess that will make him/her repeat an experiment for the purpose of verifying the data gotten from the previous experiment
hence the answer to the question is to Ensure that his conclusion is supported by evidence.
Carbon buildup can be removed from the metal portion of a pressing comb by immersing the metal portion of the comb in a solution containing _____.
Carbon buildup can be removed from the metal portion of a pressing comb by immersing it in a solution containing an acid.
When a pressing comb is used for styling hair, it can accumulate carbon buildup over time. This buildup can affect the comb's performance and hinder smooth gliding through the hair.
To remove the carbon buildup, the metal portion of the comb can be immersed in a solution containing an acid. The acid helps to dissolve and break down the carbon deposits, making it easier to clean the comb.
Acids such as vinegar, lemon juice, or citric acid are commonly used for this purpose. These acids have properties that help in dissolving carbon and other residues. The comb should be soaked in the acid solution for a specific period of time, allowing the acid to work on the carbon buildup.
After soaking, the comb can be scrubbed gently with a brush or cloth to remove any remaining residue. Finally, rinsing the comb thoroughly with water and drying it properly completes the process.
Hence, immersing the metal portion of a pressing comb in a solution containing an acid is an effective method to remove carbon buildup and restore the comb's functionality.
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How is a spectroscope used in astronomy?
Explanation:
using a spectroscope astronomers can split light from space into a spectrum and examine its spectral lines to infer what compounds are emitted or absorbed.
12 Calculate An object has a mass of 77 kg and
an acceleration of 2.3 m/s2. Use the equation
F=
= ma to calculate the net force acting on the
object. Show your work.
Answer:
F=ma.
mass=77, acceleration=2.3.
77×2.3=177.1Newton
EXERCISE 3: WHAT DOES pCO2 CHANGE? - When pCO
2
increases, the concentration of total CO
2
dissolved in water - When pCO
2
increases, the concentration of only CO
2
dissolved in water - When pCO
2
increases, the pH - Which form of dissolved CO
2
is most common in water? Ocean acidification is the decrease in pH due to increasing atmospheric CO
2
concentration.
2
. Choose the correct word option in the statements below: - An organism that needs CO
2
is likely to fare better / worse under ocean acidification. - An organism that needs HCO
3
- is likely to fare better/worse under ocean acidification. - An organism that needs CO
3
2−
is likely to fare better/worse under ocean acidification.
pCO2 is an important factor that affects various aspects of water chemistry and the impacts of ocean acidification. When pCO2 increases, the concentration of total CO2 dissolved in water also increases. This leads to changes in pH, which decreases due to increasing atmospheric CO2 concentration.
When pCO2 rises, the concentration of only CO2 dissolved in water increases. The dissolved CO2 forms carbonic acid, which contributes to the acidification of the ocean. This increase in CO2 affects the equilibrium between CO2, HCO3-, and CO3^2-, shifting it towards higher levels of dissolved CO2 and H+ ions, resulting in a lower pH.
In terms of the impacts of ocean acidification on different organisms, the effects can vary depending on their specific needs. An organism that requires CO2 is likely to fare better under ocean acidification since the increase in dissolved CO2 can provide them with a favorable environment. However, organisms that rely on HCO3- or CO3^2- may fare worse under ocean acidification, as the lower pH interferes with the availability of these carbonate ions, which are essential for shell formation and calcification in some marine organisms.
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what are the chemical names for KF
tin ( , ) is a soft metal that is used in alloys such as bronze. melts at , and has a heat of fusion of what is the entropy change of a sample of of in , when it melts at ?
The entropy change of a sample of 26.7g of Sn in J/K when it melts at 232°C is 0.055 J/K.
We can use the formula ΔS = ΔHfus/T to calculate the entropy change of a sample of Sn as it melts at 232°C, where ΔHfus is the heat of fusion and T is the temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin by adding 273.15 to it;
T = 232°C + 273.15
= 505.15 K
Next, we need to calculate the number of moles of Sn in the sample. We can do this using the molar mass of Sn;
n = m/M = 26.7 g / 118.71 g/mol
= 0.2246 mol
Now we can use the formula to calculate the entropy change:
ΔS = ΔHfus/T = (7.03 kJ/mol) / (0.2246 mol × 505.15 K)
= 0.055 J/K
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--The given question is incomplete, the complete question is
"Tin (Sn, MM = 118.71G/mol) is a soft metal that is used in alloys such as bronze. Sn melts at ,232 degree C, and has a heat of fusion of Δ Hf = 7.03 KJ/mol. what is the entropy change of a sample of 26.7g of Sn in J/K when it melts at 232 degree C?"--
write 2 typical properties that are only common to transition metals
Answer:
Properties of transition elements
they are all metals and that most of them are hard, strong, and lustrous, have high melting and boiling points, and are good conductors of heat and electricity.
Find the formula for a hydrate (salt containing water) which is 55.2% NiSO4, and 44.8% H20.
The formula for a hydrate : NiSO₄. 7H₂O
Further explanationGiven
55.2% NiSO₄, and 44.8% H₂O
Required
The formula
Solution
MW NiSO₄ = 154,75 g/mol
MW H₂O = 18 g/mol
Mol ratio :
NiSO₄ : 55.2 : 154,75 g/mol = 0.357
H₂O : 44.8 : 18 g/mol = 2.49
Divide by 0.357 :
NiSO₄ = 0.357/0.357 = 1
H₂O = 2.49/0.357 = 7
The morning temperature in a city is 41°F. If a sunny, mild day is forecast, which temperature is most likely for 2:00 p.m.?
Answer:
huh
Explanation:
Help me please ????
Answer:
I think it is more that one is correct, so sorry if I'm wrong, if it isn't, it is one of the electron bonding ones
1. Choose the correct answer from the given alternative. 1. A blood sample analysis showed that a total of 0.0000036g lead. Express it in micrograms? A. 0.0036 micro gram B. 0.036 micro grams C. 0.36 micro grams D. 3.6 micrograms.
Answer:
3.6 micrograms answers (c)
Explanation:
It's actually Science but I didn't find it.
Word Bank: friction, gravity, equal, motion, balanced, unbalanced, change, changing, direction speed
Forces acting on an object are balanced or unbalanced. Forces acting on an object have _____ strength and act in opposite directions they are ______ . These forces cancel each other, and _____ of the object does not _____ . When the Forces acting on an object are, _____ they do not cancel out another. An unbalanced force on an object results on the object's motion _____ . The object may change its _____ (speed up or slow down), or it may change its _____ . _______ is a force that resists the motion or the tendency toward motion between two objects in contact with each other. _____ is a force that pulls objects toward one another. For example, Earth pulls all objects toward it.
Someone please help me
Answer:
Forces acting on an object may be balanced or unbalanced. When the forces acting on an object have equal strength and act in opposite directions, they are balanced. These forces cancel out one another, and the motion of the object does not change. When the forces acting on an object are unbalanced, they do not cancel out one another. An unbalanced force acting on an object results in the object’s motion changing. The object may change its speed (speed up or slow down), or it may change its direction. Friction is a force that resists the motion or the tendency toward motion between two objects in contact with each other. Gravity is a force that pulls objects toward one another. For example, Earth pulls all objects toward it.
Explanation: