A shoe store uses a 40% markup for all of the shoes it sells. What would be the selling price of a
pair of shoes that has a wholesale cost of $67?

Answer:

6.96*1000 this is the standard form ok

Answer:

0.696x10^5

Step-by-step explanation:

Answer:

Step-by-step explanation:

do I

Step-by-step explanation:

Break it up into two trapezoids as shown

area = trap1 + trap2

      = 2 *   (7+3) / 2   + 3 *  ( 7 + 3) / 2 = 10 + 15 = 25 units^2

Step-by-step explanation:

marlena steps should look like this:

2x + 5 = -10 - x

(minus 5 from both sides)

2x = -15 - x

(add x to both sides)

3x = -15

(divide by 3)

x = -5

Answer:

step 1 addition property of equality

step 2 subtraction property of equality

step 3 division property of equality

Answer:

$13 overpayment

Step-by-step explanation:

We can find the amount Trevor should pay each month by dividing the $26,555 by 36 months:

               ($26,555/(36 months)) = $737.64 per month

Since Trevor decide to round up to the nearest dollar, he will pay $738 each month.  That's an overpayment of $0.361 each month.

After 36 months of overpaying by $0.361 each month, Trevor will have overpaid:

  ($0.36/month)*(36 months) = $13 overpayment

Devon's expression had the greatest value which is 20.

What is an expression?

In mathematics, an expression is a combination of numbers, variables, and operators (such as +, -, ×, ÷, etc.) that represents a mathematical value or relationship. Expressions can be simple or complex, and they can take on many different forms depending on the context.

They are also used to represent real-world problems, and also used to evaluate mathematical expressions to get numerical results.

Step-by-step explanation:

Let's use t=1 to compare all the expressions:

1. -5(12t+9)

if t = 1, -5(12+9) = -5(21) = negative number

2. 2(-6t-8)

if t = 1, 2(-6-8) = 2(-14) = negative number

3. -6(-2t+18)

if t = 1, -6(-2+18) = -6(16) = negative number

4. (-4(-3t-2)

if t = 1, -4(-3-2) = -4(-5) = 20 positive number

Therefore, Devon's expression had the greatest value which is 20.

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Answer:

answer below

Step-by-step explanation:

a) will be all of them

b)will be all of their unions, so the values they all have in common in this case 4, 6

c)will be the values in common with a and b and all of c,

d)will be all of the values of a and b and all of the values in common with c

sorry I csnnot give an actual answer at the moment, but i can explain what each question wants from you in literal word form.

The quadrilateral WXYZ is not a square using the distance formula

From the question, we have the following parameters that can be used in our computation:

W(-1,1),X(3,4),Y(6,0) and Z(2,3)

The lengths of the sides can be calculated using the following distance formula

Length = √[Change in x² + Change in y²]

Using the above as a guide, we have the following:

WX = √[(-1 - 3)² + (1 - 4)²] = 5

XY = √[(3 - 6)² + (4 - 0)²] = 5

YZ = √[(6 - 2)² + (0 - 3)²] = 5

ZW = √[(2 + 1)² + (3 - 1)²] = 13

The sides that are congruent are WX, XY and YZ

This means that WXYZ is not a square

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When we differentiate the function y = f(x) with respect to x, we obtain dy/dx = 10x - 6. The differential of the function is then expressed as dy = (10x - 6)dx.

Let's go through the steps in more detail:

Start with the equation y = f(x).

To find the differential, we differentiate both sides of the equation with respect to x, which gives us dy/dx on the left side and d/dx (5x^2 - 6x) on the right side.

Applying the power rule of differentiation, the derivative of 5x^2 with respect to x is 10x. The derivative of -6x with respect to x is -6.

Combining these derivatives, we get dy/dx = 10x - 6.

The differential of the function is represented as dy = (10x - 6)dx, where dx represents a small change in the x-value and dy represents the corresponding small change in the y-value.

In summary, when we differentiate the function y = f(x) with respect to x, we obtain dy/dx = 10x - 6. The differential of the function is then expressed as dy = (10x - 6)dx.

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Answer:

So the answer is A-The mean doesn't change

Step-by-step explanation:

With the outliers the mean is 25, how?

well if we put down the numbers 15,23,24,25,26,27,35 and add them together  15+23+24+25+26+27+35 we get 175 now we have to divide by how many numbers are there 175/7=25. That is the mean WITH the outliers.

Now, WITHOUT the outliers. The outliers are 15 and 35. We know this because, there is a huge gap between 15 and 23, and 27 and 35. We basically do the same thing but without the outliers. 23+24+25+26+27=125 we divide by how many numbers are there 125/5 then we get 25.

Hey love! <3

Answer:

The correct answer is A. The mean doesn't change

Step-by-step explanation:

Since this is a dot plot, first we have to count up the total x-axis amount from the dot plots, then divide it by the numeral amounts (y-axis), then repeat this after removing the outlier from the dot plot.

Thus, the mean remaining the same.

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Answer:  Option C, neither.

Step-by-step explanation:

Here we have the table:

x: -10    -3    4    11

y:   1      6    30   120

This means that if our function is f(x), then:

f(-10) = 1

f(-3) = 6

f(4) = 30

f(11) = 120

We want to know if this represents a linear equation or an exponential equation or neither.

First, let's try with a linear equation.

We know that a linear equation can be written as:

f(x) = a*x + b

Then let's input the known values and let's see if this equation works.

We can use two of the known points to get:

f(-10) = 1 = a*-10 + b

f(4) = 30 = a*4 + b

With these equations, we can find the value of a and b, once we find these values, we can see if the equation also works for the other two points.

1 = a*-10 + b

30 = a*4 + b

First, we need to isolate one of the variables in one of the equations.

I will isolate b in the first one:

b = 1 + a*10

Now we can replace this in the other one to get:

30 = a*4 + 1 + a*10

30 = 1 + a*14

30 - 1 = a*14

29 = a*14

29/14 = a = 2.07

and using the equation b = 1 + a*10 we can find the value of b:

b = 1 + 2.07*10 = 1 + 20.7 = 21.7

Then the equation we get is:

f(x) = 2.07*x +  21.7

Now we need to see if this works for the other two points:

for x = -3, we need to get: f(-3) = 6

f(-3) = 2.07*-3 + 21.7 = 15.49

We did not get the value we expected, then we already know that the relationship is not linear.

Now let's see if the relationship can be exponential.

An exponential function is written as:

f(x) = A*(r)^x

Let's do the same as above, let's use two of the known points to find the values of A and r

f(-3) = 6 = A*(r)^(-3)

f(4) = 30 = A*(r)^4

Now we have the system of equations:

30 = A*(r)^4

6 = A*(r)^(-3)

If we take the quotient of these two equations, we get:

(30/6) = (A*(r)^4)/( A*(r)^(-3))

5 = (r^4)*r^3 = r^(4 + 3) = r^7

(5)^(1/7) = r = 1.258

And the value of A is given by:

30 = A*(1.258)^4

30/( (1.258)^4 ) = 11.98

Then the exponential equation is something like:

f(x) = 11.98*(1.258)^x

Now let's see if this equation also works for the other two points:

for x = -10, we should get f(-10) = 1

Let's see that:

f(-10) = 11.98*(1.258)^(-10) = 1.2

And for x = 11 we should get f(11) = 120

f(11) =  11.98*(1.258)^(11) = 149.6

So we get values closer to the ones we should get, but not the exact ones, so this is not an exponential relation.

Then the correct option is C, neither.

We have shown that every integer in the form of 6n-1 has at least one prime factor congruent to 5 mod 6. This proof is valid for any integer n.

To show that every integer in the form of 6n-1 has at least one prime factor congruent to 5 mod 6, we can use proof by contradiction.

Assume that there exists an integer, say x, in the form of 6n-1 that does not have a prime factor congruent to 5 mod 6. Let's consider the prime factorization of x.

The prime factorization of x can be written as x = p1^a1 * p2^a2 * ... * pk^ak, where p1, p2, ..., pk are prime numbers and a1, a2, ..., ak are positive integers.

Since x is in the form of 6n-1, we can write x as x = 6n-1 = 2^a * 3^b - 1, where a and b are non-negative integers.

Now, let's consider the congruence of x mod 6:
x ≡ 2^a * 3^b - 1 ≡ (-1)^a * 1^b - 1 ≡ (-1)^a - 1 (mod 6)

We know that for any integer x, (-1)^x ≡ 1 (mod 6) if x is even, and (-1)^x ≡ -1 (mod 6) if x is odd.

Since x is in the form of 6n-1, a must be odd. Therefore, (-1)^a ≡ -1 (mod 6).

This means that x ≡ -1 - 1 ≡ -2 (mod 6). However, since we assumed that x does not have a prime factor congruent to 5 mod 6, this means that x cannot be congruent to -2 (mod 6), which is a contradiction.

Hence, our assumption was incorrect, and every integer in the form of 6n-1 must have at least one prime factor congruent to 5 mod 6.

In conclusion, we have shown that every integer in the form of 6n-1 has at least one prime factor congruent to 5 mod 6. This proof is valid for any integer n.

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Answer:

\(\frac{x^2}{16} +xy+4y^2\) can be factored out as: \((\frac{x}{4} +2\,y)^2\)

Step-by-step explanation:

Recall the formula for the perfect square of a binomial :

\((a+b)^2=a^2+2ab+b^2\)

Now, let's try to identify the values of \(a\) and \(b\) in the given trinomial.

Notice that the first term and the last term are perfect squares:

\(\frac{x^2}{16} = (\frac{x}{4} )^2\\4y^2=(2y)^2\)

so, we can investigate what the middle term would be considering our \(a=\frac{x}{4}\), and \(b=2y\):

\(2\,a\,b=2\,(\frac{x}{4}) \,(2\,y)=x\,y\)

Therefore, the calculated middle term agrees with the given middle term, so we can conclude that this trinomial is the perfect square of the binomial:

\((\frac{x}{4} +2\,y)^2\)

The process involves finding the complementary solution x_c(t) by solving the homogeneous equation, determining the particular solution x_p(t) using the method of variation of parameters, and combining them to obtain the general solution x(t).

1. The method of variation of parameters can be used to solve the initial value problem x' = axf(t), x(a) = xa, where a and f(t) are given functions. In this case, we have the values a = 4 - 2t and f(t) = 16t^2. We need to find the solution x(t) using the initial condition x(0) = 2.

2. To solve the initial value problem using the method of variation of parameters, we first find the complementary solution x_c(t) by solving the homogeneous equation x' = ax.

3. For the given a = 4 - 2t, the homogeneous equation becomes x' = (4 - 2t)x. By separation of variables and integration, we find the complementary solution x_c(t) = Ce^(2t - t^2).

4. Next, we find the particular solution x_p(t) by assuming a particular solution of the form x_p(t) = u(t)e^(2t - t^2), where u(t) is a function to be determined.

5. Differentiating x_p(t) and substituting it into the original differential equation, we can solve for u'(t) and determine the form of u(t). After finding u(t), we substitute it back into x_p(t).

6. Finally, the general solution is given by x(t) = x_c(t) + x_p(t). By substituting the values and integrating, we can obtain the specific solution x(t) for the given initial condition.

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a) The original statement can be expressed as: For all x and y, if N(x) and N(y), then P(x,y)

b) The original statement can be expressed as: For all x, if R(x), then D(x)

c) For all x, if P(x), then there exist y and z such that S(x,y) and S(x,z) and y is not equal to z.

d) The original statement can be expressed as: For all x, if N(x) and R(y), then not S(x,y).

a) The product of two negative real numbers is positive:

Let P(x,y) be the statement "the product of x and y is positive", N(x) be the statement "x is a negative real number". Then the original statement can be expressed as:

For all x and y, if N(x) and N(y), then P(x,y)

b) The difference of a real number and itself is zero:

Let D(x) be the statement "the difference of x and itself is zero", R(x) be the statement "x is a real number". Then the original statement can be expressed as: For all x, if R(x), then D(x)

c) Every positive real number has exactly two square roots:

Let S(x,y) be the statement "y is a square root of x", P(x) be the statement "x is a positive real number". Then the original statement can be expressed as:

For all x, if P(x), then there exist y and z such that S(x,y) and S(x,z) and y is not equal to z.

d) A negative real number does not have a square root that is a real number:

Let R(x) be the statement "x is a real number", N(x) be the statement "x is a negative real number", S(x,y) be the statement "y is a square root of x". Then the original statement can be expressed as:

For all x, if N(x) and R(y), then not S(x,y).

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In the given scenario, where there is a positive correlation between the number of mailboxes and the number of traffic lights in a town, the most likely lurking variable that explains the correlation is the town's population size or density.

The lurking variable in this case refers to a variable that is not directly measured or observed but can influence or explain the relationship between the variables of interest. In this situation, it is reasonable to assume that the population size or density of a town could be the lurking variable that is driving the correlation between the number of mailboxes and the number of traffic lights.

A larger or denser population in a town would generally lead to increased residential areas, resulting in a greater need for mailboxes. Additionally, a higher population density often corresponds to increased traffic congestion and safety concerns, necessitating the installation of more traffic lights.

While the number of mailboxes and traffic lights are directly correlated, it is likely that the underlying factor influencing both variables is the population size or density of the town.

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we can find horizontal asymptotes by looking at the degrees of the numerator and denominator.

The horizontal asymptote of a rational function can be determined by looking at the degrees of the numerator and denominator. If N is the degree of the numerator and D is the degree of the denominator and N < D then the horizontal asymptote is y = 0.

To create a new graph and type your expression in the expression list bar. As you are typing your expression  the calculator will immediately draw your graph on the graph paper. Click here to save your graph.A horizontal asymptote of a graph is a horizontal line y = b where the graph approaches the line as the inputs approach ∞ or –∞.

Hence we can find horizontal asymptotes on desmos graphing.

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Reason:

There are two mountain peaks, which show the two modes (at 0.27 and 0.31). Therefore, this data set is bimodal.

The data set is also symmetric because of the mirror line at 0.29; stuff to the left of 0.29 can be reflected over the mirror line to get the stuff on the right side.

We can rule out choice A since the curve doesn't represent a normal distribution. A normal distribution has exactly one mode only.

Choice C is ruled out because a skewed distribution isn't symmetric, and vice versa.

The data set isn't uniform since all stacks of points aren't the same height. This rules out choice E.

Answer:

6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

the smallest composite number that can be written as a product of four different prime numbers is 6

The standard deviation of dataset is 22.4659.Calculation of mean. Mean can be calculated using the formula : mean = sum of values / total number of values in dataset .So, the mean of dataset is 51.033. The standard deviation of dataset is 22.4659.

Given dataset is:{21, 48, 25, 36, 35, 87, 32, 53, 77, 36, 86, 40, 13, 47, 45, 64, 46, 75, 32, 47, 73, 67, 89, 50, 96, 42, 53, 24, 12, 64}a) Calculation of mean Mean can be calculated using the formula : mean = sum of values / total number of values in datasetFor calculating mean, we need to add all the values in dataset and divide it by the total number of values in dataset.Here, there are 30 values in datasetSum of values in dataset = 1531mean = (sum of values) / (total number of values)= 1531 / 30 = 51.033So, the mean of dataset is 51.033

b) Calculation of standard deviation Standard deviation is the measure of dispersion of values of dataset. It gives the idea about the spread of dataset with respect to the mean.For calculating standard deviation, we use the formula :standard deviation = square root ( sum of (xi - mean)² / n )where xi is the ith value of dataset and n is the total number of values in datasetHere, there are 30 values in datasetMean of dataset = 51.033Standard deviation can be calculated by using the following steps:Step 1: Calculate the deviation of each value from the mean i.e., xi - meanStep 2: Square the deviation value i.e., (xi - mean)²Step 3: Sum all the squared deviation values.Step 4: Divide the sum of squared deviations by the total number of values.Step 5: Take the square root of the above value.Step 1: Calculation of deviation of each value from meanmean =  of standard deviationstandard deviation = square root ( sum of (xi - mean)² / n )= square root ( 15130.64 / 30 )= square root ( 504.354667 )= 22.4659So, the standard deviation of dataset is 22.4659.

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Answer:

The final cost is 7.85

Step-by-step explanation:

Take 3.14 and multiply it by 2.5

Answer:

there y= -x - 3 is correct

Step-by-step explanation:

(-4,1) ; (-3,0)

y= -x - 3

with (-4,1)

1 = -(-4) - 3 = 4 - 3 = 1. left = right

with (-3,0)

0 = -(-3) - 3 = 3 - 3 = 0. left = right

so the line y = -x - 3 is passes through points (-4,1) and (-3,0)

The smallest positive angle that is equivalent to A=343 degrees is 703 degrees.

To find the measure of the least positive angle that is coterminal with A, we need to determine the equivalent angle within one full revolution (360 degrees) of A.

A is given as 343 degrees. To find the coterminal angle within one revolution, we can subtract or add multiples of 360 degrees until we obtain a positive angle.

Let's subtract 360 degrees from A:

343 - 360 = -17

The result is a negative angle, so we need to add 360 degrees instead:

343 + 360 = 703

Now, we have a positive angle of 703 degrees, which is coterminal with 343 degrees.

The measure of the least positive angle that is coterminal with A is 703 degrees.

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Answer:

14x>200+5.5, She must sell 15 or more vases

Step-by-step explanation:

14x>200+5.5

14x>200+5.5

14x>205.5

x>14.68*

She must sell 15 or more vases

*You round up because you cannot sell a partial vase

Answer:

14v > 200 + 5.50v, she will have to sell 24 vases to make a profit

Step-by-step explanation:

It costs $5.50 PER VASE for materials, so you would subtract this from what she sells each vase for. 14 - 5.50 = 8.50. She makes an $8.50 profit per vase sold. We can write 8.50n > 200 to show her profit margin minus the booth fee. If she sold 24 vases, she would be making a profit and this would represent the lowest amount of vases she can sell to make a profit. We can write the inequality 24 ≤ n to show that she can sell 24 vases or more to make a profit.

14n > 200 + 5.50n

336 > 332, true

n > 23

Hope This Helps!

Answer:

14) \(f(10) = 10\), 15) \(f(-2) = -2\), 16) \(f(a) = a\), 17) \(f(a+b) = a+b\), 18) \(g(10) = 38\), 19) \(g(-2) = -22\), 20) \(g(a) = 5\cdot a - 12\), 21) \(g(a+b) = 5\cdot a +5\cdot b -12\)

Step-by-step explanation:

Let \(f(x) = x\) and \(g(x) = 5\cdot x - 12\), we proceed to resolve on each case:

14) \(f(10)\)

\(f(x) = x\)

\(f(10) = 10\)

15) \(f(-2)\)

\(f(x) = x\)

\(f(-2) = -2\)

16) \(f(a)\)

\(f(x) = x\)

\(f(a) = a\)

17) \(f(a+b)\)

\(f(x) = x\)

\(f(a+b) = a+b\)

18) \(g(10)\)

\(g(x) = 5\cdot x - 12\)

\(g(10) = 5\cdot (10) -12\)

\(g(10) = 38\)

19) \(g(-2)\)

\(g(x) = 5\cdot x - 12\)

\(g(-2) = 5\cdot (-2) -12\)

\(g(-2) = -22\)

20) \(g(a)\)

\(g(x) = 5\cdot x - 12\)

\(g(a) = 5\cdot a - 12\)

21) \(g(a+b)\)

\(g(x) = 5\cdot x - 12\)

\(g(a+b) = 5\cdot (a+b) -12\)

\(g(a+b) = 5\cdot a +5\cdot b -12\)

No, a square matrix with two identical columns is not invertible.

For a square matrix to be invertible (or non-singular), it must have linearly independent columns (or rows). In other words, each column (or row) of the matrix must be unique and not a linear combination of the other columns (or rows).

If two columns of a square matrix are identical, it means that one column is a scalar multiple of the other. This results in linear dependence between the columns, and the matrix does not have full rank.

Since an invertible matrix must have full rank, a square matrix with two identical columns cannot be invertible.

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False. The triple exponential smoothing method does consider seasonality variations in the analysis of the data, along with trend and level components, to provide accurate forecasts.

The statement is false. Triple exponential smoothing, also known as Holt-Winters method, is a time series forecasting method that incorporates trend and seasonality variations in the analysis of the data, but it does not specifically use seasonality variations.

Triple exponential smoothing extends simple exponential smoothing and double exponential smoothing by introducing an additional component for seasonality. It is commonly used to forecast data that exhibits trend and seasonality patterns. The method takes into account the level, trend, and seasonality of the time series to make predictions.

The triple exponential smoothing method utilizes three smoothing equations to update the level, trend, and seasonality components of the time series. The level component represents the overall average value of the series, the trend component captures the systematic increase or decrease over time, and the seasonality component accounts for the repetitive patterns observed within each season.

By incorporating these three components, triple exponential smoothing can capture both the trend and seasonality variations in the data, making it suitable for forecasting time series that exhibit both long-term trends and repetitive seasonal patterns.

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Answer:

"C" has to be the answer...

there is a vertical asymptote at -5

thus you need a denominator that is zero at -5

plug in -5 into the equations only "C" ends up with a zero in the denominator at that point

Step-by-step explanation:

The outward flux of ⁻F across the surface of the solid bounded by the cylinder y² + z² = 4 and the plane x = z + 2 in the first octant is 6π.

To find the outward flux, we need to evaluate the surface integral of the vector field ⁻F over the given surface. The surface consists of the curved part of the cylinder and the plane in the first octant. We can parameterize the surface using cylindrical coordinates as follows:

x = ρcosθ

y = ρsinθ

z = z

The normal vector to the surface is given by n = ∇r, where r is the position vector of the surface. The outward flux is then given by the surface integral ∬S ⁻F · n dS.

Considering the cylindrical surface S1: ρ = 2, and the plane S2: x = z + 2, we can rewrite the surface integral as a double integral over the cylindrical surface in terms of ρ and θ:

∬S1 ⁻F · n dS + ∬S2 ⁻F · n dS

Using the parametric equations and the normal vector, we can calculate ⁻F · n for each surface:

For S1, ⁻F · n = ⁻F · (∇r) = ⁻F · (∂ρ/∂x, ∂ρ/∂y, ∂ρ/∂z)

             = (2xy)(∂ρ/∂x) + (2xy)(∂ρ/∂y) + (2xz + y - y²)(∂ρ/∂z)

For S2, ⁻F · n = ⁻F · (∇r) = ⁻F · (∂x/∂x, ∂x/∂y, ∂x/∂z)

             = (2xy)(∂x/∂x) + (2xy)(∂x/∂y) + (2xz + y - y²)(∂x/∂z)

Evaluating these dot products and performing the double integrals, we find the outward flux to be 6π.

The outward flux of the vector field ⁻F across the surface of the solid bounded by the cylinder y² + z² = 4 and the plane x = z + 2 in the first octant is 6π. This result indicates the net flow of the vector field outward through the surface.

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