A simple pendulum, consisting of a mass m, is attached to the end of a 1.5 m string. If the mass is held out horizontally, and then released from rest, its speed at the bottom is O 4.4 m/s O 5.4 m/s 9

Your math problem

8−−>8−−>3−−>12<−−

whats your question xD

One light year is the distance traveled by light in one year and the distance of the star is 3.40x10¹⁶ meters

It is known that the speed of light has a value of 3x10⁸m/s in vacuum. That is, it travels 3x10⁸m in one second, according with the following equation: v=x/t, where v is the speed, x is the distance and t is the time.

x = v×t ......(1)

Equation 1 can be used to determine the distance that the light travels in 1 year, it is necessary to find how many seconds are in 1 year (365.25 days).

365.25 days × 86400 sec/1 day = 31557600 seconds

x = 3x10⁸m/s × 31557600 seconds

x = 9.46x10¹⁵m

Therefore, in 1-year, light travels 9.46x10¹⁵m meters.

Now we need to do a simple conversion between units can be used to get the distance in meters:

x star = 5.3ly × 9.46x10¹⁵m/1 light year = 5x10¹⁷m

Hence, the distance of the star is 5x10¹⁷ meters.

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Answer:

2100 m

2804 g

4 '2 mm squares'

20,000 photos

Explanation:

1.5 km = 1500 m

1500 m + 600 m = 2100 m

2.8 kg = 2800 g

2800 g + 4 g = 2804 g

8mm tube / 2 mm squares

4 can fit

1 Gb = 1000 mb

40 Gb = 40,000 mb

40,000 mb / 2 mb = 20,000 photos

Here's all the help you need:

1).  1 km  =  1,000- m

2).  1 kg  =  1,000 g

3).  Freebie.  2 fits into 8 four times.

4).  1 mega...  =  1,000 kilo...

5).  1 Giga...  =  1,000 Mega...

Answer:

   I = 2.667 kg m²

Explanation:

The moment of inertia of a body can be calculated by the expression

         I = ∫ L² dm

For high symmetry bodies the expressions of the moment of inertia are tabulated, for a rod with its axis of rotation at its midpoint it is

         I = \(\frac{1}{12}\) m L²

let's calculate

         I = \(\frac{1}{12}\)  2  4²

         I = 2.667 kg m²

The magnitude of the self-induced emf produced by the increasing current in the solenoid is approximately 130 mV.

To calculate the self-induced emf produced by the increasing current in the given solenoid, we can use the formula:

e = -L (di ÷ dt)

where e is the self-induced emf, L is the inductance of the solenoid, and (di/dt) is the rate of change of current.

The inductance of a solenoid can be calculated using the formula:

L = μ × n² × A × l

where μ is the permeability of the material inside the solenoid (we will assume it to be the permeability of free space, μ0), n is the number of turns per unit length, A is the cross-sectional area, and l is the length of the solenoid.

Substituting the given values, we get:

μ0 = 4π x 10⁷ T m/A

n = 268 ÷ 0.179 m = 1497 turns/m

A = 3.14159 cm² = 3.14159 x 10⁻⁴ m²

l = 17.9 cm = 0.179 m

(di ÷ dt) = 9.55 A/s

L = μ0 × n² × A × l

= 4π x 10⁻⁷ × (1497)² × 3.14159 x 10⁻⁴ × 0.179

= 0.0136 H

e = -L (di ÷ dt)

= -0.0136 × 9.55 x 10⁶ (since 1 mV = 10⁻³ V)

= -129.98 mV

≈ 130 mV

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check the pictures(2 pictures)check the pictures(2 pictures)check the pictures(2 pictures)

The vector sum of the two forces is 20  and the magnitude of the resultant is 20 towards positive x-axis.

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

If no vector can be written as a linear combination of the others, a set of vectors is said to be linearly independent.

The vector representation for the forces F and F are:

\(\rm \vec F_1 = 20 COS 60^0 \vec i + 20 SIN 60^0 \vec j\\\\ F_1 =20 \times \frac{1}{2} \vec i+20 \times \frac{\sqrt{3} }{2} \vec j \\\\ \vec F_1 = 10 \vec i+ 10 \sqrt{3} \vec J\)

\(\rm F_2 = 20 cos 60^0 \vec i+20 sin(-60) \vec j \\\\ F_2 = 20 \times \frac{1}{2} \times \vec i+20 \times \frac{\sqrt{3} }{2} \vec j \\\\ \vec F_2 = 10 \vec I -10\sqrt{3} \vec J\)

The vector sum of the two forces are;

\(\rm \vec R = \vec F_1+\vec F_2\\\\ \vec R = 10 \vec i+ 10 \sqrt{3} \vec J+10 \vec i-10\sqrt{3} \vec J\\\\ \vec R =20 i\)

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Answer:

324 J

Explanation:

KE= 1/2 m*v^2

1/2*8*9^2

324 joules (=^w^=) woof woof

Answer:

6.075×10²³ Electrons

Explanation:

From the question,

Q = it............................. Equation 1

Where Q = quantity of charge, i = current, t = time.

Given: i = 27 A, t = 1 hours = 1×60×60 = 3600 seconds.

Substitute these values into equation 1

Q = 27×3600

Q = 97200 C.

If, one electron = 1.6×10⁻¹⁹ C,

Therefore, n electron = 97200×1/1.6×10⁻¹⁹ C.

n = 6.075×10²³ Electrons

If a 6-uf capacitor is initially charged to 100 v and then connected across a 500 resisor, the initial charge on the capacitor is 600 μC

The initial charge on the capacitor can be found using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. Given that the capacitance is 6 μF and the voltage is 100 V, the initial charge on the capacitor is:

Q = CV = (6 μF)(100 V) = 600 μC

After the capacitor is connected across the 500 Ω resistor, it will start to discharge through the resistor. The time constant for this circuit can be calculated using the equation τ = RC, where R is the resistance and C is the capacitance. The time constant represents the time it takes for the voltage across the capacitor to decrease to 36.8% of its initial value.

τ = RC = (500 Ω)(6 μF) = 3 ms

The voltage across the capacitor as a function of time is given by the equation \(V(t) = V_0e^{(-t/τ)\), where V₀ is the initial voltage (100 V) and t is the time since the capacitor was connected to the resistor. Therefore, the charge on the capacitor as a function of time is Q(t) = CV(t).

To find the charge on the capacitor after a certain amount of time, we need to know the time elapsed since the capacitor was connected to the resistor.

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The statement that best explains why the system looses energy is; the Collison of the molecules of hydrogen with the wall of the can carries off energy to the environment.

We know that energy is defined as the rate of doing work. Now the temperature of a gas is measure of the kinetic energy of the molecules of the body. In this case, the temperature of the hydrogen in the cannister has to do with how fast the molecules of the hydrogen are moving.

The higher the temperature, the faster the molecules of the hydrogen move. The lower the temperature, the slower the molecules of the hydrogen moves.

As such, the molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.

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Answer:

horrible, but how about you?

Explanation:

Answer:

Explanation:

The addition of two simple harmonic motions will produce a result that is also simple harmonic if the two simple harmonic motions have the same frequency and phase.

When two simple harmonic movements attain their maximum or lowest values at the same moment, they are said to be in phase. If the amplitudes of two simple harmonic movements have the same frequency and are in phase, the amplitude of the resulting motion may be calculated. This indicates that the combined system's motion will still oscillate at the same frequency as the separate movements and will be sinusoidal in form, as is the distinguishing feature of simple harmonic motion. As a result, adding two simple harmonic movements with the same frequency and phase results in a consequent motion that is likewise simple harmonic.

B is the answer!!!!!!!!!!!!!

To find the tangential and normal accelerations at the point (2, 12), we need to analyze the particle's motion using calculus.

First, let's find the velocity vector. The given information tells us that the velocity component in the direction of the x-axis is constant and equal to 2 m/s^2. Since the motion is along the trajectory y = x^4 - x^2, the velocity vector can be written as:

To find dy/dt, we differentiate the equation of the trajectory with respect to time:

So, the velocity vector becomes:

Now, let's find the acceleration vector. The tangential acceleration (at) is the rate of change of the magnitude of velocity, and the normal acceleration (an) is the centripetal acceleration perpendicular to the trajectory.

To find at, we differentiate the magnitude of velocity (speed) with respect to time:

Differentiating |v| with respect to time, we get:

To find an, we use the formula:

where r is the radius of curvature. The radius of curvature can be found using the equation:

Differentiating the equation of the trajectory, we get:

Differentiating again, we get:

Substituting these values into the equation for r, we have:

Now we can calculate the tangential and normal accelerations at the point (2, 12) by substituting x = 2 into the respective equations.

Calculating these values will give us the tangential and normal accelerations at the point (2, 12).

Velocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second.

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Answer:

1. 59 Ω

2. 3 Ω

3. 0.625 kΩ

Explanation:

1. The total resistance in a series circuit is equal to the sum of the resistance.

\(R_T=R_1+R_2+R_3...\\R_T=20+19+20\\R_T=59\)

Therefore, the total resistance in the first circuit is 59 Ω.

2. The total resistance in a parallel circuit is equal to the sum of the reciprocals of the resistance.

\(\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{6.0} +\frac{1}{12} +\frac{1}{36}+\frac{1}{18} \\\frac{1}{R_T} = \frac{1}{3} \\R_T=3\)

Therefore, the total resistance in the second circuit is 3 Ω.

3. This is another parallel circuit, so we use the same equation from above:

\(\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{10} +\frac{1}{2} +\frac{1}{1} ...\\\frac{1}{R_T} =1.6\\R_T=\frac{1}{1.6}\)

Therefore, the total resistance in the third circuit is \(\frac{1}{1.6}\) kΩ, or 0.625 kΩ.

I hope this helps!

Answer:

Explanation: A ball is thrown into the air at an angle of 50 degrees with a horizontal, and initial velocity of 12m/s. (i) we to find the total time of the flight, and (ii) maximum height that the ball reaches

(i) Total flight time:

To find the total time, we much keep in mind that it is the time that the bill would take to reach the same height level as its starting height, the equation that will be used is as follows:

By setting equation (1) equal to zero and solving for the "t" , the total flight time can be solved, it can be done as follows:

(ii) Maximum height of the ball:

The maximum height that the ball can reach would be attained in half of the total flight time, therefore we need to simply find the y(t) at half of the total flight time, this is done as follows:

(a) In the diamond structure, the Fourier component Uc of the crystal potential seen by an electron is zero for G = 2A, where A is a basis vector in the reciprocal lattice referred to the conventional cubic cell.

(b) In the first-order approximation to the solutions of the wave equation in a periodic lattice, the energy gap vanishes at the zone boundary plane normal to the end of the vector A since at the boundary plane, the energy difference between the highest occupied energy level and the lowest unoccupied energy level becomes zero.

(a) We must take into account the symmetry characteristics of the crystal lattice and its reciprocal lattice in order to demonstrate that the Fourier component u-g of the crystal potential is equal to zero for g = 2a in the diamond structure.

The lattice of the diamond structure is made up of two face-centered cubic (FCC) lattices that are interpenetrating and each have a body diagonal shift of half a lattice constant. Two atoms make up the traditional cubic cell of a diamond.

The set of all reciprocal lattice vectors, which may be determined by applying the Fourier transform to the real-space lattice vectors, serves as the definition of the reciprocal lattice of a crystal.

The reciprocal lattice in the diamond structure is likewise face-centered cubic (FCC) and has the following relationships with the real-space lattice:

g = h₁a₁* + h₂a₂* + h₃a₃*

where g is a reciprocal lattice vector, h₁, h₂, and h₃ are integers, and a₁*, a₂*, and a₃* are the reciprocal lattice vectors.

Since we are interested in the Fourier component u-g of the crystal potential, we can express it as:

u-g = Σ uₙexp(-2πig⋅rₙ)

where uₙ is the crystal potential at lattice site rₙ.

Now, let's consider the case when g = 2a. Since a is a basis vector in the reciprocal lattice, we can express it as a combination of the reciprocal lattice vectors a₁*, a₂*, and a₃*:

a = p₁a₁* + p₂a₂* + p₃a₃*

where p₁, p₂, and p₃ are integers.

Substituting g = 2a into the expression for u-g:

u-2a = Σ uₙexp(-2πi(2a)⋅rₙ)

    = Σ uₙexp(-4πia⋅rₙ)

Due to the periodic nature of the lattice, the sum of all lattice sites will result in zero because the exponential term depends on the dot product of 4ia and rn. This indicates that when g = 2a in the diamond structure, the Fourier component u-2a of the crystal potential is equal to zero.

We have therefore demonstrated that for the diamond structure, the Fourier component of the crystal potential, u-g, is equal to zero for g = 2a, where an is a basis vector in the reciprocal lattice, also known as the conventional cubic cell.

(b) Bloch's theorem, which asserts that the wavefunction may be written as a product of a periodic portion and a plane wave term, can be used to solve the wave equation in a periodic lattice in the first-order approximation. Near the zone boundary plane, the Bloch functions corresponding to the valence and conduction bands can be combined linearly to approximate the periodic part of the wavefunction.

The Bloch functions' wavevectors become equal in size but opposite in direction at the zone boundary plane normal to the end of vector A. The energy difference between the valence and conduction bands is thus closed as a result of their energies, which are determined by the dispersion relation, being equal. This closure allows for the easy transition of electrons from the valence band to the conduction band, promoting electrical conductivity in that particular direction.

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Answer:

According to potential energy, the height of the object is 2.296 meters.

We need to know about potential energy to solve this problem. The potential energy is the object's energy caused by its position. Potential energy can be determined as

PE = m . g . h

where PE is potential energy, m is mass, g is the gravitational acceleration (9.8 m/s²) and h is height.

From the question above, we know that

PE = 342 joules

m = 15.2 kg

By substituting the given parameters, we can calculate the height

PE = m . g . h

342 = 15.2 . 9.8 . h

148.96 h = 342

h = 2.296 meters

Hence, the height of the object from the ground is 2.296 meters.

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Answer: Created Fall 2016 by Ronald Wilson Inductive reasoning uses a set of specific observations to reach an overarching conclusion; it is the opposite of deductive reasoning. So, a few particular premises create a pattern which gives way to a broad idea that is likely true.

Explanation: No explanation lol. But I hope this is helpful!

Answer:

40m

Explanation:

v^2=gh

h=v^2/g

h=20^2/10

h=400/10

h=40

An engine moves a boat through the water at a constant speed of 15 m/s. The engine must exert a force of 6.0 kN to balance the force that the water exerts against the hull. Power is the measure of how fast work can be done. The unit of power is watts (W), which can be defined as the amount of work done in one second.

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Answer:

D. Segment Addition Postulate

Explanation:

I got it correct on the quiz.

Answer:

Only winter is caused by the tilt of the earth's axis.False

it caused summer or autumn too

To cause the 46 g particle to move to the right at 46 m/s, a net work must be done on the particle to change its velocity from 12 m/s to 46 m/s and its direction from left to right. The net work required to change the velocity and direction of the particle is 43.3352 J.

The kinetic energy of the particle when it is moving to the left at 12 m/s can be calculated using the formula:

K = (1/2)mv^2

where K is the kinetic energy, m is the mass of the particle, and v is its velocity. Plugging in the given values, we get:

K = (1/2) x 0.046 kg x (12 m/s)^2 = 3.3288 J

The kinetic energy of the particle when it is moving to the right at 46 m/s can also be calculated using the same formula:

K' = (1/2) x 0.046 kg x (46 m/s)^2 = 46.664 J

The change in kinetic energy is therefore:

ΔK = K' - K = 46.664 J - 3.3288 J = 43.3352 J

Thus, the net work required to change the velocity and direction of the particle is 43.3352 J. This work can be done by an external force acting on the particle over a certain distance.

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Answer:B

Explanation:onec thwy tried others

To determine the middle of a group of variables, use the mean. It works well for averaging data that are often quite comparable to one another.

The average is more frequently used to refer to mean. By summing up each value and dividing by the total number of values, it is computed. It is a useful method for condensing the core values, which are frequently extremely similar to one another.

Since it takes the average of all values in the data set, the mean is the most often used measure of central tendency. The median performs better than the mean for data from skewed distributions since it is unaffected by high values.

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--The complete question is, _________ is used to measure the center of a set of values. It is good for summarizing values that are generally pretty similar to each other.--

Answer:

pyramid is a body or structure whose outer surfaces are triangular and converge to a first step at the the top which base may be in a shape of triangle ,rectangle,square and other any shape.

Explanation:

its volume is equal to product of area of base and height of it..

the lateral surface area of a regular pyramid is equal to the sum of the areas of its lateral faces.

the total surface area of a regular pyramid is equal to the sum of the lateral surface areas of pyramid and base.

Answer:

hope it is helpful to you

In the Modified Block letter style, the date, complimentary close, and signature block are positioned approximately one-half inch to the right of center or at the right margin.

Following the proper format while writing business letters is crucial. There are specific methods that business letters have to be written.

The modified block letter style, which places one space between the body of the letter and the addresses of the sender and recipient, is one of the several letter kinds. In this form of letter, one space corresponds to around half an inch to the right of centre or at the right margin. Modified block letter formats are largely the same as full-block business letters.

Modified block format is a different extensively used format. The letter body, along with the sender and recipient's addresses, are left justified and single-spaced in this format. On the other hand, tab to the centre and start typing for the date and closure. Semi-Block. Semi-block is the last and least popular type of style.

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