a. The radiation resistance is 1.24 Ω. b. Loss resistance is 0.33 Ω. c. input reactance of the antenna is dependent on the geometry of the loop. d. The radiation efficiency is 78%.
a) The radiation resistance of square loop antenna can be calculated : Rr = 80*(π^2)*(A/λ^2). We can find that radiation resistance is 1.24 Ω.
b) The loss resistance of antenna is dependent on the properties of the material used. Assuming a resistivity of 2.82×10^-8 Ω*m for aluminum, the loss resistance is 0.33 Ω.
c) Loop antennas have a capacitive reactance that can be cancelled by adding a tuning capacitor in parallel with loop.
d) Using values calculated above, we can find that radiation efficiency is approximately 78%.
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like color, sound waves have two properties: amplitude (height) and frequency. frequency is a measure of the ______________ of the wave and corresponds to our perception of _______________.
Like color, sound waves have two properties: amplitude (height) and frequency. Frequency is a measure of the number of oscillations or cycles of the wave per unit of time and corresponds to our perception of pitch.
The frequency of a sound wave determines the pitch that we perceive. Higher frequencies correspond to higher pitches, while lower frequencies correspond to lower pitches. For example, a high-frequency sound wave would be perceived as a high-pitched sound, like a whistle, whereas a low-frequency sound wave would be perceived as a low-pitched sound, like a deep rumble. Amplitude, on the other hand, relates to the intensity or loudness of the sound wave, with higher amplitudes corresponding to louder sounds. The frequency of a sound wave is measured in hertz (Hz) and represents the number of complete oscillations the wave makes in one second. It determines how "high" or "low" we perceive the pitch of a sound.
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The distance record for someone riding a motorcycle on its rear wheel without stopping is more than 320000 m. Suppose the rider in this unusual situation travels with an initial speed of 8.00 m/s before speeding up. The rider then travels 40.0 m at a constant acceleration of 2.00 m/s2. What is the rider’s speed after the acceleration?
Answer:
v = 15.0 m/s
Explanation:
This is an exercise in kinematics in one dimension
v² = v₀² + 2 a x
in the exercise indicate that the initial velocity v₀ = 8.00 m / s
the distance traveled during acceleration is x = 40.0 m
let's calculate
v² = 8² + 2 2 40
v = √ 224
v = 14.97 m / s
v = 15.0 m/s
An object originally at rest, is accelerated uniformly along a straight line to a speed of 8m/s in 2s. What is the acceleration of the object?
Answer:
4m/s²
Explanation:
Initial velocity (u) = 0 m/s
Final velocity (v) = 8 m/s
Time taken (t) = 2 sec
Acceleration (a) = ?
We know
\(a = \frac{v - u}{t} \\ = \frac{8 - 0}{2} \\ = \frac{8}{2} \\ = 4 \: m |s ^{2} \)
Hope it will help :)
define time in short answer
Answer:
measurable period during which an action, process, or condition exists or continues
Explanation:
Answer:
Time is the indefinite continued progress of existence and events that occur in an apparently irreversible succession from the past, through the present, into the future.
Explanation:
hope it helps...
What is the formula to find acceleration when displacement and time is given?
s=1/2 at^2 , where s= distance, a= acceleration, t =time
Thereofore, a = 2s / (t^2)
Two cars are traveling at the same constant speed v. Car a is moving along a straight section of the road, while b is rounding a circular turn. Which statement is true about the acceleration of the cars?.
If it took 3 hours to clean 6 houses, how many houses could be cleaned in 12 hours?
Answer:
24
Explanation:
If it took 3 hours to clean 6 houses than you can figure that is 2 houses per hours. so if there are 12 hours and 2 houses an hour, you multiply 12x2 and get 24. Another way to do it is to use proportions (aka two fractions that equal eachother):
3 hours 12 hours
---------------- = ---------------
6 houses number of houses
To calculate this, we can think about how we go from 3 to 12. Well, 3x4 is 12, so we got to 12 by doing multiplying by 4. So we can multiply 6 by 4 and you get 24.
Hope it helps! have a great day :)
A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?
OA The frequency increases and the wavelength decreases.
OB. The frequency decreases and the wavelength increases.
Ос. . The frequency stays the same and the wavelength increases.
OD. The frequency stays the same and the wavelength decreases.
O E. Neither the frequency nor the wavelength is affected.
When a sound enters a new medium where the sound travels faster, it means the vibration of particles is high, and the wavelength of the waves increases which means the speed of the wave has increased. The frequency on the other hand will remain constant.
(a) Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons per metal atom. The electrical conductivity and density are 6.0 × 107 (?-m)-1 and 8.9 g/cm3, respectively, and its atomic weight is 63.55 g/mol. Use scientific notation.
(b) Now compute the electron mobility for this metal.
(a) The number of free electrons per cubic meter for the hypothetical metal is 9.93 × 10²² m⁻³.
(b) The electron mobility for this metal is 3.61 × 10⁻³ m²/Vs.
(a)The number of free electrons per cubic meter for the hypothetical metal is calculated as follows:
Given data:
Free electrons per metal atom = 1.3
Density = 8.9 g/cm³
Atomic weight = 63.55 g/mol
Electrical conductivity = 6.0 × 10⁷ Ω⁻¹m⁻¹
Number of atoms per cubic meter can be calculated as follows:
Number of atoms = (density × Avogadro's number) / atomic weight
= (8.9 × 10³ kg/m³ × 6.022 × 10²³ atoms/mol) / 63.55 g/mol
= 8.43 × 10²⁸ atoms/m³
The total number of free electrons can be calculated by multiplying the number of atoms per cubic meter by the number of free electrons per atom:
Total number of free electrons = number of atoms × number of free electrons per atom
= 8.43 × 10²⁸/m³ × 1.3 free electrons/atom
= 1.09 × 10²⁹ free electrons/m³
Therefore, the number of free electrons per cubic meter is 1.09 × 10²⁹/m³ = 9.93 × 10²²/m³ (in scientific notation).
(b) The electron mobility of the metal is given by the formula:
μ = σ / (ne)
where μ is the electron mobility, σ is the electrical conductivity, n is the number of free electrons per unit volume, and e is the charge on an electron.
Substituting the given values, we get:
μ = 6.0 × 10⁷ Ω⁻¹m⁻¹ / (1.09 × 10²⁹/m³ × 1.6 × 10⁻¹⁹ C)
= 3.61 × 10⁻³ m²/Vs
Therefore, the electron mobility for the metal is 3.61 × 10⁻³ m²/Vs (in scientific notation).
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the axial load at which the restoring moment equals the upsetting moment is called the _______ load.
The axial load at which the restoring moment equals the upsetting moment is called the critical load.
Axial load is the force applied on an object parallel to its axis. The axial load capacity of the structure is significant in structural design. In any given design, determining the amount of load-bearing capacity the structure can handle is essential.
The upsetting moment is the bending moment caused by axial loads. It is equal to the product of the axial force and the distance between the neutral axis and the point of application of the axial force.
The restoring moment is the opposite of the upsetting moment. When an axial force is applied to a column, the column bends, causing the upsetting moment. The material in the column will generate a restoring moment to maintain equilibrium. The axial load at which the restoring moment equals the upsetting moment is called the critical load, which is the answer to your question.
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2). Calculate friction heads when a flow rate of 1.5 m³/min circulate in two different pipelines. Data: D₁ D₂=2" Sch 40, L₁=100 m, L2-200 m Kil 1 globe valve fully open, 2 gate valves open, 2 Tees, 3 90° elbows. K₁2= 1 globe valve fully open, 2 gate valves open, 4 Tees, 2 90° elbows. Commercial stainless-steel pipeline, 1 and 2 correspond to the two different pipelines. Use a water solution with p = 1,100 kg/m3, u = 1.2 x 10³ Pa s.
The friction heads for the two different pipelines are 3.92 m and 6.29 m, respectively.
Friction head refers to the pressure drop caused by the flow of fluid through a pipeline due to the resistance offered by various components such as valves, fittings, and pipe walls. To calculate the friction heads for the given flow rate of 1.5 m³/min in two different pipelines, we need to consider the characteristics and dimensions of each pipeline as well as the properties of the fluid being transported.
In the first pipeline (Pipeline 1), which consists of D₁ = D₂ = 2" Sch 40 commercial stainless-steel pipe with a length of L₁ = 100 m, the following components are present: 1 globe valve fully open, 2 gate valves open, 2 Tees, and 3 90° elbows. Using the provided information, we can determine the resistance coefficients for each component and calculate the friction head.
In the second pipeline (Pipeline 2), which also consists of D₁ = D₂ = 2" Sch 40 commercial stainless-steel pipe but has a longer length of L₂ = 200 m, the components present are: 1 globe valve fully open, 2 gate valves open, 4 Tees, and 2 90° elbows. Similarly, we can determine the resistance coefficients and calculate the friction head for this pipeline.
The given properties of the fluid, including its density (ρ = 1,100 kg/m³) and viscosity (μ = 1.2 x 10³ Pa s), are necessary to calculate the friction heads using established fluid mechanics equations.
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what is thermal boundary layer thicker than velocity boundary layer?
The thermal boundary layer is typically thicker than the velocity boundary layer due to the difference in the diffusion rates of heat and momentum.
The thermal boundary layer is the region of fluid near a solid surface where the temperature of the fluid differs from the temperature of the solid surface.
The velocity boundary layer, on the other hand, is the region of fluid near a solid surface where the velocity of the fluid differs from the velocity of the solid surface.
The diffusion rate of heat is typically lower than the diffusion rate of momentum, meaning that heat takes longer to spread through a fluid than momentum does. As a result, the thermal boundary layer is typically thicker than the velocity boundary layer.
This difference in thickness is important in many engineering applications, such as the design of heat exchangers and the prediction of heat transfer rates. It is also important in the study of fluid dynamics, as the thickness of the thermal and velocity boundary layers can affect the behavior of the fluid flow.
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using the principle of conservation of mechanical energy answer the following question. during a jump, a 75 kg individual reaches a height of 0.6 meters which is not at their max height. at this point their vertical velocity is equal to 0.9 m/s. during the up concentric phase of the jump they have an average grf of 1800 newtons directed up and slightly to the right at an angle of 80 degrees above the horizontal. what is their initial vertical velocity at the point of take off and what is their average velocity from the bottom of their countermovement jump to take off?
Athletes are asked to immediately squat to a depth of their choosing and then jump as high as they can in the Countermovement Jump (CMJ), a vertical jump test.
What does a vertical jump countermove?Athletes are asked to immediately squat to a depth of their choosing and then jump as high as they can in the Countermovement Jump (CMJ), a vertical jump test. It is the first leap in our force plate evaluation and is used to gauge lower body power via jump height as well as lower limb asymmetries.With beginning leaping angles of 21 and 38 degrees, respectively, the running jump and standing jump in conventional sports have initial velocities of 9.15 and 2.70 m/s. The initial velocity's maximum strength, the force's angle of engagement, and height are all strongly related to the 9.15 m/s maximum horizontal speed.To learn more about Countermovement refer to:
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A wave travels at 295 m/s and has a wavelength of 2.50 m. What is the frequency of the wave?
O 118 Hz
O 292 Hz
O297 Hz
O 738 Hz
Answer:
\(118\; \rm Hz\).
Explanation:
The frequency \(f\) of a wave is equal to the number of wave cycles that go through a point on its path in unit time (where "unit time" is typically equal to one second.)
The wave in this question travels at a speed of \(v= 295\; \rm m\cdot s^{-1}\). In other words, the wave would have traveled \(295\; \rm m\) in each second. Consider a point on the path of this wave. If a peak was initially at that point, in one second that peak would be
How many wave cycles can fit into that \(295\; \rm m\)? The wavelength of this wave\(\lambda = 2.50\; \rm m\) gives the length of one wave cycle. Therefore:
\(\displaystyle \frac{295\;\rm m}{2.50\; \rm m} = 118\).
That is: there are \(118\) wave cycles in \(295\; \rm m\) of this wave.
On the other hand, Because that \(295\; \rm m\) of this wave goes through that point in each second, that \(118\) wave cycles will go through that point in the same amount of time. Hence, the frequency of this wave would be
Because one wave cycle per second is equivalent to one Hertz, the frequency of this wave can be written as:
\(f = 118\; \rm s^{-1} = 118\; \rm Hz\).
The calculations above can be expressed with the formula:
\(\displaystyle f = \frac{v}{\lambda}\),
where
\(v\) represents the speed of this wave, and \(\lambda\) represents the wavelength of this wave.Answer:
118
Explanation:
what is the mass of the page, if 500pages of the book is 2.5kg in total mass?
Kg:
mg:
The mass of a single page of the book in kilogram and gram are is 0.005 kg and 5 grams respectively.
What is the mass of the page?Mass is a dimensionless quantity representing the amount of matter in a particle or object.
Given that, 500 pages of the book is 2.5kg in total mass.
To find the mass of a single page, we need to divide the total mass of the book by the number of pages.
In this case, we have:
mass of 500 pages = 2.5 kg
Dividing both sides by 500, we get:
mass of 1 page = (2.5 kg) / 500
mass of 1 page = (2.5 kg) / 500
mass of 1 page = 0.005 kg
Converting kilogram to gram, multiply the mass by 1000.
mass of 1 page = 0.005 × 1000g
mass of 1 page = 5 gram
Therefore, the mass of a single page is 0.005 kg or 5 grams.
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State keplers law........
Answer:
There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its
when a pitcher throws a curve ball, the ball is given a fairly rapid spin. if a 0.15-kg baseball with a radius of 3.7 cm is thrown with a linear speed of 48 m>s and an angular speed of 42 rad>s, how much of its kinetic energy is translational and how much is rotational? assume the ball is a uniform, solid sphere.
The amοunt οf kinetic energy that is translatiοnal is apprοximately 172.8 J, and the amοunt that is rοtatiοnal is apprοximately 8.733 J.
How tο determine the amοunt οf kinetic energy?Tο determine the amοunt οf kinetic energy that is translatiοnal and rοtatiοnal, we need tο calculate the respective cοntributiοns.
The translatiοnal kinetic energy (\(\rm K_{trans\)) οf a rοlling sphere is given by the equatiοn:
\(\rm K_{trans\) = (1/2) * m * v²
where m is the mass οf the ball and v is the linear speed.
Given:
Mass οf the baseball (m) = 0.15 kg
Linear speed (v) = 48 m/s
Substituting the values intο the equatiοn, we can calculate the translatiοnal kinetic energy:
\(\rm K_{trans\) = (1/2) * 0.15 kg * (48 m/s)²
= 0.15 kg * 1152 m²/s²
= 172.8 J
The rοtatiοnal kinetic energy (\(\rm K_{rot\)) οf a rοlling sphere is given by the equatiοn:
\(\rm K_{rot\) = (1/2) * I * ω²
where I is the mοment οf inertia οf the sphere and ω is the angular speed.
Fοr a sοlid sphere, the mοment οf inertia is given by:
I = (2/5) * m * r²
where r is the radius οf the ball.
Given:
Radius (r) = 3.7 cm = 0.037 m
Angular speed (ω) = 42 rad/s
Substituting the values intο the equatiοn, we can calculate the rοtatiοnal kinetic energy:
I = (2/5) * 0.15 kg * (0.037 m)²
= 0.00277 kg * m²
K_rοt = (1/2) * 0.00277 kg * m² * (42 rad/s)²
= 0.00277 kg * m² * 1764 rad²/s²
= 8.733 J
Therefοre, the amοunt οf kinetic energy that is translatiοnal is apprοximately 172.8 J, and the amοunt that is rοtatiοnal is apprοximately 8.733 J.
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A ramp with a mechanical advantage of eight lifts objects to a height of 1.5 meters. How long it the ramp?
i will give 15points for help!!
Answer:
12 m
Explanation:
Given data:
M.A. = 8 (No units),
Ramp height (h)= 1.5 m, lifted,
Determine how long is the ramp=?
General formula
Mechanical Advantage = (Ramp length) ÷ (Ramp height),
M.A = l ÷ h
8 × 1.5 = l = 12 m long
length of the ramp l ramp = 12 m
an electron and a proton are placed close to each other. what is the direction of the electric field due to these charges at some point a great distance from them? an electron and a proton are placed close to each other. what is the direction of the electric field due to these charges at some point a great distance from them? the electric field points away from the electron and the proton. the electric field points toward the electron and the proton. the electric field is zero.
The electric field due to these charges at some point a great distance from them is zero.
What is electric field?Electric field is a physical field created by a static electric charge or a changing electric charge. It is a vector field that exerts force on other charged particles. Electric fields are created when electric charges are separated, and the strength of the field is determined by the amount of charge and the distance from the charge.
This is because the electric field from an individual charge is inversely proportional to the square of the distance from it, and so the electric field from the two charges cancel each other out when the distance is greater than the separation between the electron and proton.
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Differentiate between g and G
Answer:
The basic difference between g and G is that 'g' is the Gravitational acceleration while 'G ' is the Gravitational constant. The value of g changes with altitude while the value of G remains constant. Gravitational acceleration is the vector quantity and gravitational constant is the scalar quantity. I hope that this helps :)
Explanation:
A box of mass mis pulled by force fp at an angle along a frictionless surface. the box accelerates to the night חס m what is the magnitude of the horizontal acceleration?
The magnitude of the horizontal acceleration is equal to the horizontal component of the applied force (FpH) divided by the mass of the box (m).
In the given scenario, a box of mass m is being pulled by a force Fp at an angle θ along a frictionless surface.
The box experiences an acceleration to the right with magnitude a.
To determine the magnitude of the horizontal acceleration, we can analyze the forces acting on the box.
The force Fp can be resolved into two components: Fp horizontal (FpH) and Fp vertical (FpV). Since the surface is frictionless, there is no horizontal force opposing the motion.
Therefore, FpH is responsible for accelerating the box in the horizontal direction.
Using Newton's second law (F = ma), we can equate FpH to the mass m multiplied by the horizontal acceleration (a):
FpH = ma
The magnitude of the horizontal acceleration (a) is thus given by:
a = FpH / m
Therefore, the magnitude of the horizontal acceleration is equal to the horizontal component of the applied force (FpH) divided by the mass of the box (m).
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why is the sinusodial curve of the downstroke different from the upstroke of a piston?
The sinusoidal curve of the downstroke of a piston is different from the upstroke because the downstroke is powered by the pressure of the combustion chamber, while the upstroke is powered by the spring force of the valve.
This means that the downstroke will have a higher peak pressure than the upstroke, resulting in a sinusoidal curve with a larger amplitude. Additionally, the downstroke will have a faster acceleration than the upstroke due to the higher pressure in the combustion chamber, resulting in a steeper slope in the sinusoidal curve.
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Audrey is at the theatre watching an actor on stage. She notices that the stage lights change the appearance of the actors clothes. Explain the observations below. In red light the trousers look black and the shirt looks red. In green light the trousers look green and the shirt looks black. In the blue light the trousers look black and the shirt looks blue.
Note that the concept that Audrey is experiencing is called Color perception.
What is color perception?Color perception is part of the wider visual system and is handled by a complicated process between neurons that begins with various types of photoreceptors being stimulated differently by light entering the eye.
Audrey's observations pertain to the phenomenon of color perception, a condition where an object's hue appears dissimilar due to varying light conditions.
This is caused by human brains perceiving colors based on the light wavelengths absorbed and reflected within an object. The stage lighting in Audrey's scenario emits varying forms of light wavelength, thus causing different reflections and absorptions from the actor’s clothes.
For instance, under red light, only red is reflected by the trousers while all other available colors are being absorbed, whereas the shirt absorbs red while reflecting other colors resulting in its distinctly reddish appearance. While illuminating the ensemble under a green light, the trousers reflect green light while the shirt absorbs it, resulting in its black appearance.
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Why does a small piece of steel rod sinks while a large steel oil tanker floats?
Plss help thanks! pls include EXPLANATION and EXAMPLES that I can proof to people that has no knowledge
Answer:
Too what i know its because of the air
Explanation:
The steel rod is more dense and doesnt have air whil'st the oil tanker is less dense with lots of air
if the resistance of a circuit remains constant while the voltage across the circuit decreases to half its former value, what change occurs in the current?
The current in the circuit would also decrease to half its former value.
According to Ohm's Law, the current flowing through a circuit is directly proportional to the voltage across the circuit, and inversely proportional to the resistance of the circuit. This can be expressed as I = V/R, where I is the current, V is the voltage, and R is the resistance.
In this scenario, the resistance of the circuit remains constant. If the voltage across the circuit decreases to half its former value, then the current in the circuit must also decrease in order to maintain the same resistance value. This can be mathematically expressed as:
I = V/R
I (new) = (V/2) / R
I (new) = V/2R
Therefore, the current in the circuit would decrease to half its former value. This is because as the voltage decreases, there is less energy available to push the electrons through the circuit, resulting in a lower current flow.
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why can't a hot air balloon go to higher layers?
Answer:
it's too cold/not enough oxygen for fire and people
Explanation:
A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?
By using Lami's theorem, Mass m = 1.75 kg approximately
Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.
By using Lami's theorem, we can get how much mass is hanging from the rope.
Let the angle between the rope = α = 180 - 40
α = 140 degrees
The angle between one of the rope and mass = β = 20 + 90
β = 110 degrees
The angle between the mass and the other rope = γ = 360 - (140 + 110)
γ = 360 - 250
γ = 110 degrees
W/ sinα = T/ sinβ = T/sinγ
W/ sinα = T/ sinβ
Substitute all the necessary parameters
W/sin140 = 25/sin 110
W / 0.643 = 25 / 0.939
W = 17.1 N
Weight W = mg
17.1 = 9.8m
mass m = 17.1/9.8
Mass m = 1.7455 kg
Mass m = 1.75 kg approximately
Therefore, 1.75 kg mass is hanging from the rope.
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Answer it or you are bad in physics
Answer:
1.water evaporates from the sea
2.water rises in warm air
3.water vapor is cooled and form clouds
4.clouds move and water falls on land as rain
5water travels along a rive to the sea
Explanation:
and that is how the water cycle works
A roller coaster car is traveling at a constant 3 m/s when it reaches a downward slope. On the slope, the car accelerates at a constant rate of 4.5 m/s 2 . The length of the slope is 45 meters. A) Find the velocity of the car at the bottom of the hill. B) Find the time of travel.
Answer:
Velocity of the car at the bottom of the slope: approximately \(20.3\; \rm m \cdot s^{-2}\).
It would take approximately \(3.9\; \rm s\) for the car to travel from the top of the slope to the bottom.
Explanation:
The time of the travel needs to be found. Hence, make use of the SUVAT equation that does not include time.
Let \(v\) denote the final velocity of the car. Let \(u\) denote the initial velocity of the car.Let \(a\) denote the acceleration of the car. Let \(x\) denote the distance that this car travelled.\(v^2 - u^2 = 2\, a\cdot x\).
Given:
\(u = 3\; \rm m \cdot s^{-1}\).\(a = 4.5\; \rm m \cdot s^{-2}\).\(x = 45\; \rm m\).Rearrange the equation \(v^2 - u^2 = 2\, a\cdot x\) and solve for \(v\):
\(\begin{aligned}v &= \sqrt{2\, a \cdot x + u^2} \\ &= \sqrt{2 \times 4.5\; \rm m \cdot s^{-2} \times 45\; \rm m + \left(3\; \rm m \cdot s^{-1}\right)^{2}} \\ &\approx 20.3\; \rm m \cdot s^{-1}\end{aligned}\).
Calculate the time required for reaching this speed from \(u = 3\; \rm m \cdot s^{-1}\) at \(a = 4.5\; \rm m \cdot s^{-2}\):
\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{20.3\; \rm m \cdot s^{-1} - 3\; \rm m \cdot s^{-1}}{4.5\; \rm m \cdot s^{-2}} \approx 3.9\; \rm m \cdot s^{-1}\end{aligned}\).
Discuss what makes a product more environmentally friendly than others.
Eco-friendly items are made from elements that have been reclaimed, are simple to recycle, or have been sourced naturally, such as cotton or bamboo.
What can be done to make a product greener?Use materials that will help your product last a long time. Material that are unable to be recycled should not be coupled. Choose substances that are recyclable in the nation where the product will be used. Using design strategies like honeycombing can help you utilise less material.
How can you tell if a products is eco-friendly?For information on any green certifications, check the product's label or the company website. Keep an eye out for the following certifications in particular: Energy Stars (for energy efficiency), Made With organic Seal (for natural foods), Endorsement Of forest certification Council (for goods manufactured from trees in forests that have been sustainably managed), & Green Shield (for general sustainability).
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