a solution has a volume of 375 ml and contains 12.6 moles of NaCI what is it molarity

2.49 * 10^23 formula units make up a sample of aluminum sulfide that weighs 62.2 g.

Describe a mole.

A mole is 6.022 * 10^23 atoms, molecules, ions, or other particles.

The number of formula units in the 62.2 g sample of aluminum sulfide is specified in the question.

Calculating the number of moles is necessary to get the number of formula units.

Aluminum Sulfide has a molecular weight of 150.158 gm.

1 mole is made up of 150.158 g of aluminum sulfide.

62.2 g will yield 0.414 moles when multiplied by 1 / 150.158.

Formula units: 6.022 * 10^23 equals one mole.

0.414 moles = 6.022 * 10²³ *0.414

= 2.49 x 10^23 mathematical units.

A 62.2 g sample of aluminum sulfide therefore has 2.49 * 10^23 formula units.

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By applying Boyle's law, the new volume of this gas is equal to: D. 4.0 L.

Given the following data:

Initial volume = 3.0 L.

New pressure = 1.5 atm.

Initial pressure = 2.0 atm.

In order to calculate the new volume of this gas, we would apply Boyle's law. Mathematically, Boyle's law is given by this formula:

PV = k

P₁V₁ = P₂V₂

Where:

Making V₂ the subject of formula, we have:

V₂ = (P₁V₁)/P₂

Substituting the given parameters into the formula, we have;

V₂ = (2.0 × 3.0)/1.5

V₂ = 6.0/1.5

V₂ = 4.0 L.

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Answer:

D. 4.0 Liters

Explanation:

I took the exam

Answer:

true

because with the both states we increase the surface of reaction

Answer:

  -172.6 °C

Explanation:

You want to know the Celsius equivalent of the temperature 100.6 K.

The relation is ...

  C = K - 273.15

  C = 100.6 -273.15 = -172.55

The temperature is -172.55 °C, about -172.6 °C.

__

Additional comment

We have rounded to tenths, because that is precision of the temperature given. If you use 273 as the conversion constant, you will get -172.4.

The mass in grams of 4.60 x 10^23 atoms is approximately 9.17 g.

To find the mass in grams of 4.60 x 10^23 atoms, we need to consider the molar mass and Avogadro's number. Avogadro's number (6.022 x 10^23) represents the number of atoms or molecules in one mole of a substance.

First, we need to determine the molar mass of the substance in question. Let's assume we are dealing with a specific element, such as carbon (C), which has a molar mass of approximately 12.01 g/mol.

To calculate the mass in grams, we can use the following formula:

Mass (in grams) = (Number of atoms / Avogadro's number) x Molar mass

Substituting the given values:

Mass (in grams) = (4.60 x 10^23 atoms / 6.022 x 10^23) x 12.01 g/mol

Calculating the expression:

Mass (in grams) = (0.763 mol) x 12.01 g/mol

Mass (in grams) = 9.17 g

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According to the forces of attraction, decreasing temperature  is a way to decrease rate of dissolution of a solid in a liquid.

Forces of attraction  is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

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The stage that this most accurately describes while using the PCR is the initiation of DNA synthesis, also known as the denaturation stage.

In the denaturation stage of Polymerase Chain Reaction (PCR), the double-stranded DNA template is heated to a high temperature to separate the two complementary strands and create single-stranded DNA. The denaturation stage is the first step in the PCR cycle.

In this stage, the heat-stable DNA polymerase denatures the DNA and the primers anneal to the complementary single-stranded template. This marks the beginning of the extension stage, where the DNA polymerase synthesizes new complementary strands along the template DNA.

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The correct structure that corresponds to the name in the image above is structure A. Details about hydrocarbons can be found below.

Alkanes are organic compound that belongs to any acyclic saturated hydrocarbon e.g. methane, ethane, etc.

Alkanes have a single carbon bond and can be attached to by certain compounds. Methyl is a compound with the formula; CH3.

Therefore, the correct structure that corresponds to the name in the image above is structure A.

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Answer:

C

Explanation:

It was right on acellus

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

what is this i dont know what kind of math this is

The empirical formula of polyethylene can be determined by converting the given percentages of carbon (C) and hydrogen (H) into grams. To find the grams of each element, we assume a 100.0 g sample of polyethylene.

For carbon:

Mass of carbon = 86.0% × 100.0 g = 86.0 g

For hydrogen:

Mass of hydrogen = 14.0% × 100.0 g = 14.0 g

Therefore, in a 100.0 g sample of polyethylene, there are 86.0 grams of carbon and 14.0 grams of hydrogen.

The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. To determine the empirical formula, we need to find the ratio of carbon to hydrogen in terms of moles.

First, we convert the masses of carbon and hydrogen into moles using their respective molar masses. The molar mass of carbon is approximately 12.01 g/mol, and the molar mass of hydrogen is approximately 1.008 g/mol.

Number of moles of carbon = 86.0 g / 12.01 g/mol ≈ 7.162 mol

Number of moles of hydrogen = 14.0 g / 1.008 g/mol ≈ 13.89 mol

Next, we divide the number of moles of each element by the smallest number of moles to get a simplified ratio.

Carbon: Hydrogen ≈ 7.162 mol : 13.89 mol ≈ 1 : 1.939

Since we want to express the ratio in whole numbers, we multiply both sides by 2 to get a whole number ratio.

Carbon: Hydrogen ≈ 2 : 3.878

Rounding to the nearest whole number, we find that the empirical formula of polyethylene is CH₂.

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Answer:

68g/mol

Explanation:

The formula of ammonium sulfide is:

 Ammonium sulfide  = (NH₄)₂S

 The molar mass of a compound is the mass in gram of one mole of the substance. In a compound, it is expressed gram formula mass or gram-molecular weight.

 It is determined by the addition of the component atomic masses and then expressed in grams;

     Atomic mass of N = 14, H  = 1 and S = 32

 (NH₄)₂S  = 2[14 + 4(1)] + 32  = 36 + 32  = 68g/mol

Answer:

\( \huge{ \boxed{111.30 \: \: \text{moles}}}\)

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\( \bold{n = \frac{N}{L} \\ }\)

where

n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question.

N = 6.7 × 10²⁵ \( \: H_2SO_4 \: \) molecules

\(n = \frac{6.7 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 111.2956...\)

We have the final answer as.

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

The sentence best summarizes the law of conservation of mass is a) The total amount of mass does not change during a chemical reaction.

The law of conservation of mass states that in a chemical reaction the mass neither be created nor be destroyed.

for example :

CH₄   +    2O₂    ----->    CO₂   +   2H₂O

the mass of reactants is = 16 g + 64 g = 80 g

the mass of products is = 44 g + 36 g = 80 g

it is clear from the above that :

The mass of reactants = The mass of Products

Thus , The sentence best summarizes the law of conservation of mass is a) The total amount of mass does not change during a chemical reaction.

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The mass of BaSO₄ formed during the reaction is calculated as 4.67 g.

Equation that has equal number of atoms of each element on both the sides of equation is known as balanced chemical equation.

Balanced chemical equation for the reaction is: BaCl₂(aq) + Na₂SO₄ (aq) → BaSO₄(s) + 2NaCl(aq)

From the equation, we can see that 1 mole of BaCl₂ reacts with 1 mole of BaSO₄.

Given that 0.020 mol BaCl₂ reacts. Therefore, 0.020 mol BaSO₄ is formed.

To determine the mass of BaSO₄ formed, we can use the following formula: mass = moles x molar mass

So, mass = 0.020 mol x 233.39 g/mol

mass = 4.67 g

Therefore, the mass of BaSO4 formed during the reaction is 4.67 g.

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Answer:

2 moles

Explanation:

From periodic table , mole weight of CH4 = 16 gm/mole

32 gm / 16 gm/mole = 2 moles

The pressure of the environment affects the liquid's boiling point. The boiling point of the liquid is higher when it is under high pressure than when it is under normal atmospheric pressure. For a given pressure, various liquids have different boiling points.

The temperature at which a liquid's vapour pressure equals the surrounding atmosphere is known as the boiling point of the liquid. This temperature causes the liquid to become a vapour.

The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapour all affect its boiling point.

We know that change in temperature of a system is given by the following formula:

Initial boiling point (T₁) = 80.1 °C

ΔT = T₂ - T₁

2.25 = T₂ - 80.1

T₂ = 82.35  °C

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Answer:

82.35

Explanation:

acellus

Answer:

Because orginisms need to eat the fruit to gain energy

Explanation:

Answer:

A

Explanation:

Hydrogen isn't an alkali metal

Answer:

hydrogen

Explanation:

hydrogen is a gas not a metal

Steel is produced from pig iron through a process known as steelmaking or iron and steel production.

The pig iron obtained from the blast furnace contains high amounts of carbon, impurities, and other elements. To convert pig iron into steel, the carbon content needs to be reduced to desired levels, and impurities must be removed.One common method of steelmaking is the basic oxygen process (BOP). In this process, pig iron is placed in a vessel called a converter, where oxygen is blown through the molten metal. The oxygen reacts with the carbon and impurities, causing them to oxidize and form gases that are released. Alloying elements and desired additives can be added at this stage to achieve specific steel properties. Another method is the electric arc furnace (EAF), where an electric arc is used to heat and melt the pig iron, allowing impurities to be oxidized and removed.The advantages of using steel are numerous. Steel is strong, durable, and versatile, making it suitable for a wide range of applications. It has high tensile strength, which means it can withstand heavy loads and pressures. Steel is also resistant to corrosion, making it ideal for construction, infrastructure, and transportation projects. It is a recyclable material, contributing to sustainability and reducing environmental impact. Additionally, steel can be fabricated into various shapes and sizes, allowing for customization and flexibility in design.References:

A. Ghosh and A. Chatterjee, Ironmaking and Steelmaking: Theory and Practice, PHI Learning, 2008.

R.H. Tupkary and V.R. Tupkary, An Introduction to Modern Iron Making, Khanna Publishers, 2010.

J.R. Davis, ed., ASM Specialty Handbook: Carbon and Alloy Steels, ASM International, 1995.

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The general form of a neutralization reaction is HF + FrOH → FrF + H₂O

We refer to this as a neutralisation reaction. Only this reaction, which produces NaCl and water as products, is a neutralisation reaction since it involves HCl and NaOH. The resulting response is listed below: NaCl(aq) + H₂O = HCl(aq) + NaOH(aq) (l)

The interaction of H⁺ ions and OH⁻ ions produces water in a neutralisation reaction, which occurs when an acid and a base combine to make water and a salt. The neutralisation of a strong acid and strong base yields a pH of 7.

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Answer: the pH of the given solution is 9.4 and the pOH is 4.6

Explanation:

The question requires us to calculate the pH and pOH values of an aqueous solution that presents a concentration of H+ ions of 3.6 x 10^-10 M.

By definition, the pH of a solution can be calculated applying the negative logarithm of the H+ ions in solution, as it follows:

(where [H+] corresponds to the concentration of H+ ions in solution)

Thus, we can determine the pH of the solution provided by the question as:

Therefore, the pH of the solution is 9.4.

Similarly, the pOH of a solution can be calculated as the negative logarithm of the OH- ions concentration in solution. Since the question does not provide the concentration of OH- ions, we can apply a different equation, which comes from the self-ionization of water.

The equilibrium constant for the self-ionization of water (a reaction where water dissociates into H+ and OH- ions) is 1.0 x 10^-14. Based on this, we can write that:

And, with the calculated value of pH (pH = 9.4), we can determine the pOH value of this solution:

Therefore, the pOH of the solution is 4.6.

In summary, the pH of the given solution is 9.4 and the pOH is 4.6.

Answer:

E 1: cyclohexene

Explanation:

This reaction is an example of the dehydration of cyclic alcohols. The reaction proceeds in the following steps;

1) The first step of the process is the protonation of the cyclohexanol by the acid. This now yields H2O^+ attached to the cyclohexane ring.

2) the water molecule, which a good leaving group now leaves yielding a carbocation. This now leaves a cyclohexane carbocation which is highly reactive.

3) A water molecule now abstracts a proton from the carbon adjacent to the carbocation leading to the formation of cyclohexene and the regeneration of the acid catalyst. This is an E1 mechanism because it proceeds via a carbocation intermediate and not a concerted transition state, hence the answer.

Answer:

140 L

Explanation:

Step 1: Write the balanced equation

2 H₂(g) + O₂(g) → 2 H₂O(g)

Step 2: Calculate the moles corresponding to 100 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

\(100g \times \frac{1mol}{32.00g} =3.13mol\)

Step 3: Calculate the moles of water vapor formed

The molar ratio of oxygen to water vapor is 1:2.

\(3.13molO_2 \times \frac{2molH_2O}{1molO_2} =6.26molH_2O\)

Step 4: Calculate the volume corresponding to 6.26 moles of water vapor

1 mole of any ideal gas under STP has a volume of 22.4 L.

\(6.26mol \times \frac{22.4L}{mol} =140 L\)

Answer:

When conducting a chemistry lab experiment using chalk (calcium carbonate) in vinegar (acetic acid), there are several limitations and precautions to be aware of:

Limitations of chalk in vinegar chemistry experiment:

Reaction rate: The reaction between chalk and vinegar is relatively slow, which may require a longer observation period or higher concentration of vinegar to observe significant changes within a reasonable time frame.

Solubility: Chalk may not dissolve completely in vinegar, resulting in incomplete reaction or difficulty in obtaining accurate results.

Product formation: The reaction between chalk and vinegar produces carbon dioxide gas, water, and calcium acetate. The carbon dioxide gas may escape into the atmosphere, leading to loss of product and inaccurate measurements.

pH: Chalk is a basic substance, and the reaction with vinegar, which is acidic, may result in neutralization, leading to a decrease in the overall acidity of the reaction mixture.

Precautions to take in chalk in vinegar chemistry experiment:

Ventilation: The reaction between chalk and vinegar produces carbon dioxide gas, which can displace air and potentially cause asphyxiation in a closed or poorly ventilated area. Conduct the experiment in a well-ventilated area or under a fume hood to ensure adequate air circulation.

Eye and skin protection: Vinegar is an acid and can cause skin and eye irritation. Wear appropriate personal protective equipment (PPE), such as gloves and goggles, to protect yourself from contact with vinegar or any other chemicals used in the experiment.

Chemical handling: Handle the chemicals, including chalk and vinegar, with care, following proper lab safety protocols. Avoid ingestion, inhalation, or direct contact with the chemicals, and dispose of them properly according to local regulations.

Accuracy in measurements: Use calibrated and accurate measuring tools, such as graduated cylinders or burettes, to measure the amount of chalk, vinegar, and other reagents accurately. This will ensure the reliability and accuracy of the experimental results.

Observations: Make careful and detailed observations during the experiment, noting any changes in appearance, gas evolution, or other relevant observations. Take measurements at appropriate intervals and record the data accurately for analysis and interpretation.

It is important to follow good laboratory practices, including proper chemical handling, accurate measurements, and cautious observations, to ensure safe and reliable results in a chalk in vinegar chemistry lab experiment. Consult with a qualified instructor or supervisor for specific guidelines and precautions related to your experiment.

The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.

The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.

Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.

Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.

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