The amount of cashews needed to be mixed with the peanuts so that the mixture will produce the same revenue as selling the nuts separately is 10 pounds.
To solve this problem, we need to use the equation:
$3(20) + 6x = 4(20 + x)$
where x is the number of pounds of cashews needed.
First, we simplify the equation by multiplying:
$60 + 6x = 80 + 4x$
Then we isolate x by subtracting 4x from both sides and subtracting 60 from both sides:
$2x = 20$
Finally, we solve for x by dividing both sides by 2:
$x = 10$
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Combine these radicals
-\(\sqrt{5} - 3\sqrt{5} \\A: -4\sqrt{10} \\B: -4\sqrt{5} \\C: -2\sqrt{10} \\D: -2\sqrt{5}\)
Answer:
D is the correct answer.
Step-by-step explanation:
\( \sqrt{5} - 3 \sqrt{5} = - 2 \sqrt{5} \)
please help asap i’ll mark you brainliest!
Answer:
A
Step-by-step explanation:
-4 is the y-intercept, so there will always be an arrow that crosses over that point. And for the slope (2x) you need to go up two places from the y-intercept and then one to the right :)
Answer:
A
Step-by-step explanation:
The 2 in 2x-4 tells us that the line is rising, so that disqualifies answer B and C.
The -4 tells us the line passes the y axis at -4, so that disqualifies C and D.
Leaves A!
Please simplify the problem in the pdf. It is a multiple choice question. Is it A,B,C, or D?
I am offering 15 points. Please help.
The simplified form of expression \(5\sqrt[3]{4x^2y} \times 2\sqrt[3]{6xy^4}\) is \(20xy\sqrt[3]{3y^2}\)
The correct answer is an option (C)
We know that the rule of exponents.
\((ab)^m=a^mb^m\)
\((a^m)^n=a^{m\times n}\)
consider an expression,
\(5\sqrt[3]{4x^2y} \times 2\sqrt[3]{6xy^4}\)
We need to simplify this expression.
\(5\sqrt[3]{4x^2y} \times 2\sqrt[3]{6xy^4}\)
\(=10(4x^2y)^{\frac{1}{3} }\times (6xy^4)^{\frac{1}{3} }\) ........(write radical form to exponent form)
\(=10\times 4^{\frac{1}{3} }\times (x^2)^{\frac{1}{3} }\times y^{\frac{1}{3} }\times 6^{\frac{1}{3} }\times x^{\frac{1}{3} }\times (y^4)^{\frac{1}{3} }\) ..........(seperate the exponents)
\(=20\times \sqrt[3]{3}\times x^{\frac{2}{3} }\times y^{\frac{1}{3} }\times x^{\frac{1}{3} }\times y^{\frac{4}{3} }\) ..............(simplify)
We know that the exponent rule while multiplying the two numbers if the base of exponents is same then we add the powers.
i.e., \(a^m\times a^n=a^{m+n}\)
So our expression becomes,
\(=20\times \sqrt[3]{3}\times x^{(\frac{2}{3} + \frac{1}{3} )}\times y^{(\frac{1}{3} + \frac{4}{3} )}\)
\(=20\times \sqrt[3]{3}\times x^{\frac{3}{3}}\times y^{\frac{5}{3} }\) ...............(simplify)
\(=20x\times \sqrt[3]{3}\times y^{(\frac{2}{3} +\frac{3}{3} )}\) .........(exponent rule \(a^m\times a^n=a^{m+n}\))
\(=20xy\times \sqrt[3]{3}\times \sqrt[3]{y^2}\)
Here, the powers of \(\sqrt[3]{3}\) and \(\sqrt[3]{y^2}\) are same.
This means that we can write the product \(\sqrt[3]{3}\times \sqrt[3]{y^2}\) as \(\sqrt[3]{3y^2}\)
So our expression becomes,
\(=20xy\times \sqrt[3]{3y^2}\)
\(=20xy\sqrt[3]{3y^2}\)
This is the simplified form of expression \(5\sqrt[3]{4x^2y} \times 2\sqrt[3]{6xy^4}\)
Therefore, the correct answer is an option (C)
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For which integers 0 ≤ c < 30, does the congruence 12x ≡ c (mod 30) have solutions? When there are solutions, determine how many incongruent solutions there are.
The congruence 12x ≡ c (mod 30) has solutions if and only if c is even, and in this case there are 15 incongruent solutions for x modulo 30.
To solve this congruence, we can first simplify it by dividing both sides by the greatest common divisor of 12 and 30, which is 6. This gives us the equivalent congruence:
2x ≡ c/6 (mod 5)
Now we can use modular arithmetic to find the solutions. Since 2 and 5 are relatively prime, we know that 2 has a modular inverse modulo 5, which is 3, since 2*3 ≡ 1 (mod 5). Multiplying both sides of the congruence by 3, we get:
6x ≡ 3c/6 ≡ c/2 (mod 5)
Since 6 is congruent to 1 modulo 5, we can simplify this to:
x ≡ 3c/2 (mod 5)
Now we need to find the values of c such that there are solutions to this congruence. Since we are looking for solutions modulo 30, we only need to consider the values of c modulo 30.
If c is even, then c/2 is an integer and we can find a solution for x modulo 5. Specifically, there is exactly one solution for x modulo 5 for each value of c/2 modulo 5, since 3 is a primitive root modulo 5. Therefore, there are 15 incongruent solutions for x modulo 30 in this case.
If c is odd, then c/2 is not an integer and there are no solutions for x modulo 5. Therefore, there are no solutions for x modulo 30 in this case.
In summary, the congruence 12x ≡ c (mod 30) has solutions if and only if c is even, and in this case there are 15 incongruent solutions for x modulo 30.
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49 kilogram of baking soda costs $2. How much does 1 kilogram of baking soda cost?
Answer:
4.5
Step-by-step explanation:
Answer:
4.5
Step-by-step explanation:
4.5
3.4k+(0.63−0.81k)÷0.9=5.7
Part I: Converting the terms into fraction form
Given equation:
3.4k + (0.63 - 0.81k) ÷ 0.9 = 5.7First, let's convert the terms (that are in decimals) into fractions.
3.4k = 34k/100.63 = 63/1000.81k = 81k/1000.9 = 9/105.7 = 57/10Replace the fraction forms in the equation:
3.4k + (0.63 - 0.81k) ÷ 0.9 = 5.734k/10 + (63/100 - 81k/100) ÷ 9/10 = 57/10Part II: Simplifying the division being performed
Since the expression in the parenthesis can't be simplified, we can open the parenthesis. Before we do that, we need to divide the expression by 9/10 (as division is third in BODMAS). This can be done by converting the divisor into it's reciprocal and changing the sign to a multiplication sign.
34k/10 + (63/100 - 81k/100) × 10/9 = 57/10Since there is no other division being performed, we can simplify the distributive property (as multiplication is fourth in BODMAS).
34k/10 + [63/100 × 10/9] - [81k/100 × 10/9] = 57/1034k/10 + [7/10] - [9k/10] = 57/1034k/10 + 7/10 - 9k/10 = 57/10Part III: Isolating "k" to determine it's value
Combine like terms as needed:
34k/10 + 7/10 - 9k/10 = 57/10k(34/10 - 9/10) + 7/10 = 57/1025k/10 + 7/10 = 57/10Subtract 7/10 both sides of the equation to isolate "x" and it's coefficient.
25k/10 + 7/10 - 7/10 = 57/10 - 7/1025k/10 = 50/10Cancel the denominators (as a/b = c/b ⇔ a = c)
25k/10 = 50/1025k = 50Divide both sides by 25 to isolate "k"
25k/25 = 50/25k = 2As part of the United States Department of Agriculture’s Super Dump Cleanup in the early 2000s, various sites in the country were targeted for cleanup. Three of the targeted sites - River X, River Y, and River Z - had become contaminated with pesticides because they were located near abandoned pesticide dump sites. Measurements of the concentration of aldrin (a commonly used pesticide) were taken at twenty randomly selected locations in each river near the dump sites.
The boxplots shown below display the five-number summaries for the concentrations, in parts per million (ppm) of aldrin, for the twenty locations that were sampled in each of the three rivers.
(a) Compare the distributions of concentration of aldrin among the three rivers.
(b) The twenty concentrations of aldrin for River X are given below.
3.4 4.0 5.6 3.7 8.0 5.5 5.3 4.2 4.3 7.3
8.6 5.1 8.7 4.6 7.5 5.3 8.2 4.7 4.8 4.6
Construct a stemplot that displays the concentrations of aldrin for River X.
(a) Comparing the distributions of aldrin concentration among the three rivers based on the given boxplots would involve
analyzing the five-number summaries for each river (minimum, lower quartile, median, upper quartile, and maximum) as well as the overall shape and spread of the boxplots.
By comparing these measures and characteristics, one can determine if there are any noticeable differences or similarities in the distributions of aldrin concentration among the three rivers.
(b) To construct a stemplot that displays the concentrations of aldrin for River X, we can use the given data points: 3.4, 4.0, 5.6, 3.7, 8.0, 5.5, 5.3, 4.2, 4.3, 7.3, 8.6, 5.1, 8.7, 4.6, 7.5, 5.3, 8.2, 4.7, 4.8, and 4.6.
In a stemplot, the stems represent the leading digit(s) of each data point, while the leaves represent the trailing digit(s). For example, the data point 3.4 would have a stem of 3 and a leaf of 4.
The stemplot for the given data points would look like this:
3 | 4
4 | 0 2 2 3 3 4 4 5 6 6 7 7 8 8 8
5 | 1 3 3 4 4 5 5 5 6 7 8 8
6 |
7 | 3 5
8 | 0 2 2 6 7
The stemplot helps to visualize the distribution of aldrin concentrations for River X, showing the frequency of data points within each stem.
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Given the following proposition:
[(X ⊃ A) • (B ⊃ ∼ Y)] ⊃ [(B ∨ Y) • (A ⊃ X)]
Given that A and B are true and X and Y are false, determine the truth value of Proposition 2A.
a.
True.
b.
False.
Therefore, the truth value of Proposition 2A is False.
To determine the truth value of Proposition 2A, let's substitute the given truth values for the variables:
A = True
B = True
X = False
Y = False
Now let's evaluate the truth value of each component of the proposition:
(X ⊃ A) • (B ⊃ ∼ Y):
(False ⊃ True) • (True ⊃ ∼ False)
(True ⊃ True) • (True ⊃ True)
True • True
True
(B ∨ Y) • (A ⊃ X):
(True ∨ False) • (True ⊃ False)
True • False
False
[(X ⊃ A) • (B ⊃ ∼ Y)] ⊃ [(B ∨ Y) • (A ⊃ X)]:
True ⊃ False
False
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Solve the inequality 4x - 6 > 6x - 20.
Ox>7
0x<7
0x<2
Ox> 2
Answer:
7>0x
0x<7
Step-by-step explanation:
4x-6>6x-20
-6>2x-20
14>2x
7>x
which number comes next in this series 5, 7, 11, 19, 35
Answer: 67
Step-by-step explanation:
We see a pattern where we multiply the number we added by previously by two.
For example, from 5 to 7, it is 2.
From 7 to 11, we add by 4.
From 11 to 19, we add by 8.
From 19 to 35, we add by 16.
This means the next number would be 32, adding 35 by 32 gives us 67,
When comparing three or more populations means within a set of quantitative data that is categorized according to one factor/treatment, a one-way anova is appropriate. It is also appropriate in this situation, however, to compare two means at a time using multiple independent two sample t-tests. True or false?.
According one-way ANOVA, the test is false.
In the given question,
When comparing three or more populations means within a set of quantitative data that is categorized according to one factor/treatment, a one-way ANOVA is appropriate. It is also appropriate in this situation, however, to compare two means at a time using multiple independent two sample t-tests. We have to check whether this is true or false.
We firstly learn about one-way ANOVA
"One-Way ANOVA, also known as "analysis of variance," examines the means of two or more independent groups to see if there is statistical support for the notion that the related population means are statistically substantially different."
According to the given method it is inappropriate to compare two means at a time using multiple independent two sample t-tests. It will create multiple testing problem and error.
So using one way ANOVA test when comparing three or more populations means within a set of quantitative data that is categorized according to one factor/treatment and compare two means at a time using multiple independent two sample t-tests is false.
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Sixty and sixty eight thousandths
Answer: 60 and 68/1000
Step-by-step explanation:
Not sure if you wanted it in fraction, decimal, or percentage form.
Answer:
60 and 68.000
Step-by-step explanation:
i not sure if that was what u were looking for
If M(-4,3) and N(1,0) are two fixed points and P(x, y) is a moving point which moves such that PM^2 -PN^2=20, find the locus of the point P.
The locus of point P is a circle with center at the midpoint of points M and N, and radius equal to half the distance between the two points.
How do we determine the value?The midpoint of M and N is given by:
((-4+1)/2, (3+0)/2) = (-1.5, 1.5)
The distance between M and N is given by the distance formula:
√((1-(-4))^2 + (0-3)^2) = sqrt(25 + 9) = √(34)
So, the radius of the circle is √(34)/2.
Hence, the equation of the locus of point P is given by:
(x-(-1.5))^2 + (y-1.5)^2 = (√(34)/2)^2
or
(x+1.5)^2 + (y-1.5)^2 = (√(34)/2)^2
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PLEASE I AM BEGGING FOR SOMEONE TO HELP ME THROUGH THIS PLEASE PLEASE I NEED HELP I have to work on many other things PLEASE HELP
The figure consists of two rectangles of dimensions 5 by 7 and 3 by 4, which is rotated to give a solid with volume of approximately 882.9 unit³
How can the volume of the solid generated by the rotation be found?
The volume of the solid generated by rotating the figure that can be considered as consisting of two rectangles, is a composite solid consisting of two cylinders.
Volume of a cylinder = π•r²•h
Radius of one the larger cylinder = 7
Height of the large cylinder = 5
Volume of the large cylinder, V, is therefore;
V1 = π × 7² × 5 = 769.69 unit³Radius of the smaller cylinder = 7 - 4 = 3
Height of the smaller cylinder = 9 - 5 = 4
The volume is therefore;
V2 = π × 3² × 4 = 113.1 unit³The volume of the solid generated by rotating the figure about side \( \mathbf{\overline{RW}} \) is therefore;
V = V1 + V2
Which gives;
V = 769.7 + 113.1 ≈ 882.8The volume of the solid generated by rotating the figure is therefore;
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A bag contains 6 blue marbles, 9 red marbles, and 5 green marbles. What-
is the probability of picking a blue marble out of the bag below? Type
your answer as a fraction in simplest form.
Answer:
3/10
Step-by-step explanation:
total marbles: 6+9+5 = 20blue marbles: 66/20 = 3/10find the mean of the numbers
1, -3, -10
-15, 4, -22
-7.5, 3, -6.5
Answer:
13. -4 14. -11 15. \(-\frac{11}{3}\)
Step-by-step explanation:
13. (1-3-10)/3
14. (-15+4-22)/3
15. (-7.5+3-6.5)/3
Answer:
13. -4 14. -11 15. -3.6 continued
Step-by-step explanation:
13. 1+-3= -2+-10 -12/3= -4
14. -15+4= -11+-22= -33/3 -11
15. -7.5+3= -4.5+ -6.5= 11/3= -3.6 continued
What is 66.6% as a fraction ( simplest form )
48. Revenue, cost, and profit. The company in Problem 47 is also planning to manufacture and market a four-slice toaster. For this toaster, the research department’s estimates are a weekly demand of 300 toasters at a price of $25 per toaster and a weekly demand of 400 toasters at a price of $20. The financial department’s estimates are fixed weekly costs of $5,000 and variable costs of $5 per toaster.
the profit for both the 300 toaster and 400 toaster demands is $1,000.To analyze the revenue, cost, and profit for the four-slice toaster, we can use the given estimates.
The research department estimates a weekly demand of 300 toasters at a price of $25 per toaster and a weekly demand of 400 toasters at a price of $20. This allows us to determine the revenue for each demand level.
Revenue at 300 toasters: 300 toasters * $25/toaster = $7,500
Revenue at 400 toasters: 400 toasters * $20/toaster = $8,000
The financial department estimates fixed weekly costs of $5,000 and variable costs of $5 per toaster. The variable costs depend on the number of toasters produced.
Variable costs at 300 toasters: 300 toasters * $5/toaster = $1,500
Variable costs at 400 toasters: 400 toasters * $5/toaster = $2,000
To calculate the total costs, we add the fixed costs to the variable costs:
Total costs at 300 toasters: $5,000 + $1,500 = $6,500
Total costs at 400 toasters: $5,000 + $2,000 = $7,000
Finally, we can calculate the profit by subtracting the total costs from the revenue:
Profit at 300 toasters: $7,500 - $6,500 = $1,000
Profit at 400 toasters: $8,000 - $7,000 = $1,000
Therefore, the profit for both the 300 toaster and 400 toaster demands is $1,000.
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A friend of yours, a senior, took the Graduate Record Exam in September and scored in the 99th percentile. In February, your friend took the same exam over again. This time your friend scored in the 90th percentile. As a research methods student, you told your friend that his/her lowered score was most likely due to:
His/her lowered score was most likely due to statistical regression.
How to determine the reason?The missing options in the question are:
A. compensation rivalry B. Demoralization C. Differential selection
D. Testing E. Statistical regression
From the question, we have:
September = 99th percentileFebruary = 90th percentileA change (whether higher or lower) in the score is caused by statistical regression.
This is so because several variables could attribute to the change in the score.
The relationship between these variables is referred to as statistical regression
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A hardware company has two locations with a total of 21 employees. If four times the number of employees at the larger location is six less than six times the number of employees at the smaller location, how many employees are at each location? The smaller location has employee(s) and the larger location has employee(s).
There are 9 employees at the smaller location and 12 employees at the larger location.
Let's use the following variables:
Let x be the number of employees at the smaller location.
Let y be the number of employees at the larger location.
We know that the total number of employees is 21, so we can write:
x + y = 21
We also know that "four times the number of employees at the larger location is six less than six times the number of employees at the smaller location". In other words, we can write:
4y = 6x - 6
Simplifying this equation, we get:
2y = 3x - 3
We now have a system of two equations with two variables:
x + y = 21
2y = 3x - 3
We can solve this system using substitution or elimination. Here, we'll use substitution method:
From the second equation, we can solve for x in terms of y:
2y = 3x - 3
3x = 2y + 3
x = (2/3)y + 1
We can now substitute this expression for x into the first equation:
x + y = 21
(2/3)y + 1 + y = 21
(5/3)y = 20
y = (3/5) × 20
y = 12
Substitute y = 12 back into x + y = 21, we get:
x + 12 = 21
x = 9
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Calculate the distance traveled if an object is dropped and falls for 10 seconds.
When an object is dropped, it falls under the influence of gravity. In a vacuum, all objects fall at the same rate, regardless of their mass. The acceleration due to gravity is 9.8 m/s². the distance traveled by an object that is dropped and falls for 10 seconds is 490 meters.
The distance traveled by the object after it falls for 10 seconds can be calculated using the formula d = (1/2)gt², where d is the distance traveled, g is the acceleration due to gravity, and t is the time. So, the distance traveled by an object that is dropped and falls for 10 seconds can be calculated as follows:d = \((1/2)gt²d = (1/2)(9.8 m/s²)(10 s)²d = (1/2)(9.8 m/s²)(100 s²)d\) = 490 m
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zfgffdhzgdfghdhuifhdSUGhdioghfiSGjDIHjtihgjDPIddh
Answer: :P
adjfdfdjskfabdklnfkbsb;dowafdsbkcbsnbw;abbu;rgsdj;sk
using common factor method factorise a²b - ab²
The factored form of the expression a²b - ab² is, ab(a - b).
What are the basic properties of arithmetic laws of operations?There are three types of basic arithmetic laws of operation.
Commutative law for addition and multiplication states,
a + b = b + a.
a×b = b×a.
Distributive law states,
a(b ± c) = ab ± ac.
Associative law states,
a + (b + c) = (a + b) + c.
We know, Distributive law, a(b ± c) = ab ± ac.
Given, An expression a²b - ab²,
Now, The HCF of a²b and ab² is ab.
Therefore, a²b - ab².
= ab(a - b).
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Evaluate the function below for x=4. f(x)=3e
−x+2
−2 Round your answer to three decimal places.
The evaluated value of the function f(x) = 3e^(-x+2) - 2 for x = 4 is approximately 0.045.
To evaluate the function, we substitute x = 4 into the given equation and simplify the expression. Plugging in x = 4, we have f(4) = 3e^(-4+2) - 2. Simplifying further, we get f(4) = 3e^(-2) - 2.
Using the approximate value of e as 2.71828, we can calculate the evaluated value. Evaluating 3e^(-2) - 2, we find that f(4) is approximately equal to 0.045 when rounded to three decimal places.
Therefore, when x is 4, the function f(x) = 3e^(-x+2) - 2 evaluates to approximately 0.045.
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Multiply and write in standard form: 10x + 3)(2x - 1) Show all work
Explanation
\((10x+3)(2x+1)\)Step 1
apply distributive property
\(\begin{gathered} (10x+3)(2x+1)=(10x\cdot2x)+(10x\cdot1)+(3\cdot2x)+(3\cdot1) \\ (10x+3)(2x+1)=20x^2+10x+6x+3 \end{gathered}\)Step 2
add similar terms and order
\(\begin{gathered} (10x+3)(2x+1)=20x^2+10x+6x+3 \\ (10x+3)(2x+1)=20x^2+16x+3 \\ \text{the standard form is} \\ ax^2+bx+c,so \\ ax^2+bx+c\Rightarrow20x^2+16x+3 \end{gathered}\)so, the answer is
\(20x^2+16x+3\)I hope this helps you
What is the measure of angle SRW
Answer:95
Step-by-step explanation:
plss help i'll give 80 points!! no links please
Answer:
domain [-1, ∞)
range [ -3, ∞)
Step-by-step explanation:
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To completely specify the shape of a Normal distribution you must give:
A: the mean and the standard deviation
B: the five number summary
C: the median and the quarties
A: The mean and the standard deviation.
To completely specify the shape of a Normal distribution, you need to provide the mean and the standard deviation. The mean determines the center or location of the distribution, while the standard deviation controls the spread or variability of the distribution.
The five number summary (minimum, first quartile, median, third quartile, and maximum) is typically used to describe the shape of a distribution, but it is not sufficient to completely specify a Normal distribution. The five number summary is more commonly associated with describing the shape of a skewed or non-Normal distribution.
Similarly, while the median and quartiles provide information about the central tendency and spread of a distribution, they alone do not fully define a Normal distribution. The mean and standard deviation are necessary to completely characterize the Normal distribution.
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Convert 25cm to inches. Round to the hundredths place.
1 inch =2.54cm
Answer:
Step-by-step explanation: By multiplying 25 cm by the 2.5 cm per inch conversion factor, we can convert 25 cm to inches.
25 cm/2.5 cm per inch = 10 inches
Rounding to hundredths place, we get: 10 inches = 10.00 inches
Please help with this
Answer:
1. x = {-3, 3}
2. a = {-12, -2}
3. v = {-7, 10}
4. m = {-8, 8}
5. k = {-11, 1}
6. y = {-13, 19}
Step-by-step explanation:
|-2x| = 6
means that
-2x = 6 or -2x = -6
x = -3 or x = 3
|a + 7| = 5
means that
a + 7 = 5 or a + 7 = -5
a = -2 or a = -12
|8v-12| = 68
means that
8v-12 = 68 or 8v-12 = -68
8v = 80 or 8v = -56
v = 10 or v = -7
| m / -4 | + 1 = 3
| m / -4 | = 2
means that
m/-4 = 2 or m/-4 = -2
m = -8 or m = 8
3|k + 5| = 18
|k+5| = 6
means that
k + 5 = 6 or k + 5 = -6
k = 1 or k = -11
|2y - 6| / 4 = 8
|2y - 6| = 32
means that
2y - 6 = 32 or 2y - 6 = -32
y = 19 or m = -13