A stretched string is 120 cm long and has a linear density of 0.022 g/cm. What tension in the string will result in a second harmonic of 590 Hz

Answer:

B. 2nmv

Explanation:

Pressure is force over area.

P = F / A

Force is mass times acceleration.

F = ma

Acceleration is change in velocity over change in time.

a = Δv / Δt

Therefore:

F = m Δv / Δt

P = m Δv / (A Δt)

The total mass is nm.

The change in velocity is Δv = v − (-v) = 2v.

A = 1 and Δt = 1.

Plugging in:

P = (nm) (2v) / (1 × 1)

P = 2nmv

The acceleration due to gravity is 9.8 m/s^2.

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

Answer: i don’t even no I’m getting my credit up tho

Explanation:

I just need a way to cheat

Answer:

educated guesses about the outcome of an experiment

Answer:

The frequency of light can be calculated using the formula:

`c = λv`

Where `c` is the speed of light in a vacuum, `λ` is the wavelength of light, and `v` is the frequency of light.

The speed of light in a vacuum is `3.00 × 10^8 m/s`.

To convert the wavelength from nanometers to meters, we need to divide by `1 × 10^9`.

Thus, the frequency of light with a wavelength of 655 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(655 × 10^-9 m)`

`v = 4.58 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`.

Similarly, the frequency of light with a wavelength of 515 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(515 × 10^-9 m)`

`v = 5.83 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz`.

Finally, the frequency of light with a wavelength of 475 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(475 × 10^-9 m)`

`v = 6.32 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.

So, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz` and the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The time between when the bat emits the sound and when it hears the echo is 0.05 s

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s

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Answer:

0.0491

Explanation:

Answer:

option a 0.027 A

Explanation:

I = V/R

-> 9/330 = 0.027

Answer:

b

Explanation:

1st grade common sense

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

Answer:

Trawler B should set off on a course of 120°.

Trawler A is traveling at 20km/h on a bearing of 60°. This means that Trawler A is traveling north-east. Trawler B is traveling at 25km/h. In order to intercept Trawler A, Trawler B must travel on a bearing of 120°. This means that Trawler B must travel south-east.

The two trawlers will eventually meet at a point that is 40km east of Trawler A's starting position and 20km north of Trawler B's starting position.

We are given the following two vectors

(a) Greater x component

Vector A (1.2 m) has a greater x component as compared to vector B (-3.4 m) because vector A is positive and vector B is negative.

Vector A has a greater x component

(b) Greater magnitude

Vector B (3.4 m) has a greater magnitude as compared to vector A (1.2 m) because the absolute value of vector B is greater than the absolute value of vector A.

Vector B has a greater magnitude.

B and A

Yes, just a B and an A.

Answer:

1. B

2. A

Explanation:

edge2020

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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The speed of the wave on the vibrating string is 17,080 m/s.

In a standing wave on a vibrating string, the length of the string is related to the wavelength of the wave. In the harmonic shown in the figure, we can observe one complete wavelength in the length of the string, which means the length of the string is equal to one wavelength.

Since the frequency of the vibrating motor is given as 854 Hz, we can use the formula v = fλ to calculate the speed of the wave. Here, v represents the speed of the wave, f represents the frequency, and λ represents the wavelength.

Since the length of the string is equal to one wavelength, we can substitute the length of the string (20 m) for the wavelength (λ).

v = fλ

v = (854 Hz)(20 m)

v = 17,080 m/s

Therefore, the speed of the wave on the vibrating string is 17,080 m/s.

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Answer: The half-life is the amount of time it takes for a given isotope to lose half of its radioactivity. If a radioisotope has a half-life of 14 days, half of its atoms will have decayed within 14 days. In 14 more days, half of that remaining half will decay, and so on.

\(\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{60}{120}=\dfrac{1}{2}=0.5A\)

Answer:

13.8 m

Explanation:

Dark fringes are formed in a single slit experiment due to destructive interference that occurs due to interference.

The position of these dark fringes formed on a screen is given by:

\(y = \frac{\lambda }{d} (m + 1/2)D\)

where y = position of  mth minimum

m = order of the minimum

D = distance of the slit from the screen

d = width of the slit

λ = wavelength of the light used

We need to find D:

\(D = \frac{yd} {\lambda (m + 1/2)} \\\)

From the question:

m = 11

y = 9.85 cm = 0.0985 m

λ  = \(6.83 * 10^{-7} m\)

d = 1.11 mm = 0.0011 m

Therefore:

\(D = \frac{0.0985 *0.0011} {6.83 * 10^{-7} *(11 + 1/2)} \\\\D = \frac{0.00010835} {6.83 * 10^{-7} * (23/2)} \\\\D = 13.8 m\)

The slit is 13.8 m far from the screen

Projectile motion is the movement of an object in the curved path toward the ground as it has both a horizontal force and the downward force of gravity acting on it.

Projectile motion is the movement of an item thrown or projected into the air, situation to only the acceleration of gravity. The item is referred to as a projectile, and its path is referred to as its trajectory.

The path of a projectile is parabolic. at some point in the motion, the acceleration of the projectile is steady and acts vertically downwards being identical to g.

Projectile movement is the movement of an item thrown up within the air at a perspective from the horizontal (or floor) with the item shifting below gravitational acceleration pointed vertically downwards, Now depending on the perspective of projection.

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The question is incomplete. The complete question is :

First Law of Thermodynamics - Sign Convention The first law of thermodynamics applies the conservation of energy principle to systems where heat transfer and doing work are the methods of transferring energy into and out of the system. The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system. In equation form, the first law of thermodynamics is AU = Q-W. Here AU is the change in internal energy U of the system. Q is the net heat transferred into the system that is, Q is the sum of all heat transfer into (positive) and out of (negative) the system. W is the net work done by the system—that is, W is the sum of all work done by (positive) and on (negative) the system. We use the following sign conventions: if Q is positive, then there is a net heat transfer into the system; if W is positive, then there is net work done by the system. So positive Q adds energy to the system and positive W takes energy from the system. Thus AU = Q-W. Note also that if more heat transfer into the system occurs than work done, the difference is stored as internal energy. The first law of thermodynamics AU = 9 - W Ur-U, Heat Work System AU--W system w Qin: talu Qout:

The first law of thermodynamics AU = Q - W U-U Heat Work System AUQ-W Qin: ta Qout: - Wout: + WK w Win: - - volume expands t volume decreases o All answers can be positive or negative. (a) Suppose there is heat transfer of 42 ) into a system, while the system does 6 ) of work. Later, there is heat transfer of 22 J out of the system while 6 ) of work is done on the system. What is the net heat transfer? 20 Correct (100.0%) Submit What is the total work? Enter a number Submit (5 attempts remaining) What is the net change in internal energy of the system? Enter a number

What is the net change in internal energy of the system? Enter a number Submit (5 attempts remaining) (b) What is the change in internal energy of a system when a total of 140 J of heat transfer occurs out of (from) the system and 165 ) of work is done on the system? Enter a number Submit (5 attempts remaining) (c) An athlete doing push-ups performs 645 kJ of work and loses 440 kJ of heat. What is the change in the internal energy (in kJ) of the athlete? Enter a number Submit (5 attempts remaining) kJ (d) An athlete doing push-ups performs 690 kJ of work and loses 450 kJ of heat. Then he takes in 830 kJ of energy from eating food, What is the total change in the internal energy (in kJ) of the athlete? Enter a number kJ.

Solution :

a). Given :

\($Q_1 = 42 \ J$\) , \($Q_2 = -22 \ J , \ W_1 = 6 \ J, \ W_2 = -6 \ J $\)

Net heat transfer

\($Q= Q_1+Q_2$\)

   = 42 + (-22)

   = 20 J

Total work

\($W= W_1+W_2$\)

   = 6 + (-6)

   = 0 J    

∵ ΔU = Q - W

       = 20 - 0

        = 20 J

This is the net change in the internal energy of the system.

b). ΔU = Q + W

           = (-140) + (-165)

           = -305 J

c). ΔU = Q + W

           = (-440) + (645)

           = 205 J

d). ΔU = Q + W

           = (-450) + (690)

           = 240 J

Answer:

j120

Explanation:

qll energy for residential is 120 and that's what ruffly is always used for wiring

If I had the opportunity to travel in time and take a single technological device to the past, I would take one of these devices;

Many would be the technological devices that would take to the past, some of the main ones would be:

¡Hope this helped!

Answer:

F' = F/12

Therefore, the electrostatic force is reduced to one-twelve of its original value.

Explanation:

The electrostatic force of attraction or repulsion between to charges is given by Coulomb's Law:

F = kq₁q₂/r²   ---------- equation 1

where,

F = Electrostatic Force

k = Coulomb's Constant

q₁ = magnitude of first charge

q₂ = magnitude of 2nd charge

r = distance between charges

Now, if we double the distance between charges and reduce one charge to one-third value, then the force will become:

F' = kq₁'q₂'/r'²

where,

q₁' = (1/3)q₁

q₂' = q₂

r' = 2r

Therefore,

F' = k(1/3 q₁)(q₂)/(2r)²

F' = (1/12)kq₁q₂/r²

using equation 1:

F' = F/12

Therefore, the electrostatic force is reduced to one-twelve of its original value.

a. The magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity is 8.72 m/s^2 and 654.0 N respectively.

b.  The astronaut is experiencing 0.89 g when moving at constant angular velocity.

c. The torque that is needed to bring the centrifuge to a stop 6875 Nm.

Angular velocity is described as a pseudovector representation of how fast the angular position or orientation of an object changes with time.

The magnitude of the centripetal acceleration and force, we will use the formula: a = v^2 / r, where v is the tangential velocity and r is the radius of the centrifuge.

a = (2pi20m15.02pi/60)^2 / 20m = 8.72 m/s^2

To calculate the force, we will use the formula

F_ = ma, where m is the mass of the astronaut, 75.0 k

F_ = 75.0 kg * 8.72 m/s^2 = 654.0 N

b. To calculate  the number of g's the astronaut is experiencing when moving at constant angular velocity, we will divide the centripetal acceleration by the acceleration due to gravity, 9.8 m/s^2

8.72 m/s^2 / 9.8 m/s^2 = 0.89 g

c.

Torque = I * alpha, where I is the moment of inertia and alpha is the angular acceleration.

I = (1/2) * 5500.0 kg * 20.0m^2 = 55000 kgm^2

The angular acceleration can be found using the formula

Alpha = (change in angular velocity) / (change in time)

The change in angular velocity is 15.0 rpm - 0 rpm = 15.0 rpm and the change in time is 2.0 minutes = 120 seconds

alpha = 15.0 rpm / 120 s = 0.125 rad/s^2

Torque = 55000 kgm^2 * 0.125 rad/s^2 = 6875 Nm

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Answer:

measurement of mass means a measure of mass in an object and measurement of length is the distance from one point to another.

Explanation:

i think so lol

Answer:

x = 4.03 10⁻² m

Explanation:

Let's start by finding the acceleration for each particle due to the electric field

           F = ma

the electric force is F = qE

         q E = m a

          a = qE / m

proton

m = 1.67 10⁻²⁷ kg

           a₁ = 1.6 10⁻¹⁹  698 /1.67 10⁻²⁷

           a₁ = 6.687 10¹⁰ m / s²

directed to the right

electron

m = 9.11 10⁻³¹ kg

           a₂ = 1.6 10⁻¹⁹  698 /9.11 10⁻³¹

           a₂ = 1.23 10¹⁴ m / s²

directed to the left

Taking the acceleration of the two bodies, we set a reference system with zero at the initial position of the proton on the positive plate, the point where it is located is x for the proton and x for the electron,

for the proton

           x₁ = x₀₁ + v₀₁ t + ½ a₁ t²

as we start from rest vo1 = 0 and the initial position is xo = 0

          x₁ = ½ a₁ t²

for the electron

          x₂ = x₀₂ + v₀₂ t + ½ a₂ t²

in this case the initial velocity is zero v₀₂ = 0 and the initial position is x₀₂=d

          x₂ = x₀₂ + ½ a₂ t²

at the meeting point x₁ = x₂, so we can equalize the two equations

         ½ a₁ t² = x₀₂ + ½ a₂ t²

         ½ t² (a₁ -a₂) = x₀₂

         t = \(\sqrt{ \frac{2 x_{o2} }{ (a_1 - a_2)} }\)

let's calculate

         t = \(\sqrt{\frac{2 \ 4.04 \ 10^{-2} }{ ( 6.687^{10} + 1.23 10^{14} ) } }\)

         t = \(\sqrt{ \frac{8.08 \ 10^{-2} }{ 1.2306 \ 10^{14} } }\)

         t = 2.56 10⁻⁸ s

now we can calculate the position

         x = ½ a₂ t²

         x = ½ 1.23 10¹⁴ (2.56 10⁻⁸)²

         x = 4.03 10⁻² m

Answer:

5.4×10⁶J

Explanation:

1 cal = 4.184 J

1.3×10⁶ cal × (4.184 J/cal) = 5.4×10⁶J

Answer:

Aluminum and steel are good conductors of electricity.

Explanation:

1) All materials are good conductors of electricity.

This is false because nonmetal materials such as plastic or wood cannot conduct electricity.

2) Aluminum and steel are good conductors of electricity.

This is true. All metals are conductors of electricity.

3) Gold and wood are poor conductors of electricity.

This is false. Although gold can conduct electricity, wood can't.

4) Plastic and copper are good conductors of electricity.

This is false. Although copper can conduct electricity, plastic can't.

I hope this helps!

Answer:

B) Aluminum and steel are good conductors

Explanation: