a student has built a 10-cm-long pinhole camera for a science-fair project. she wants to photograph her friend, who is 180 cm tall, and have the image on the film be 5 cm high. how far should the front of the camera be from her friend

Answer:

filament bulb, filament lamp

Explanation:

More length of a wire is a component that has a greater resistance as the current through it increases​.

The resistance of a long wire is greater than the resistance of a short wire because electrons collide with more ions present in the wire as they pass through. The moving electrons can collide with the ions present in the metal.

This makes more difficult for the current to flow and causes resistance in the wire so we can conclude that more length of a wire is a component that has greater resistance as more current passes through it.

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Fg=Fc has already been stated; hence the following equivalence can be written: mc*(2*/T)2*rcj = G*mc*mj / rcj2.

The gravitational force, as stated by Newton's Universal Law of Gravitation, is the only force acting on Calisto while it is spinning around Jupiter: rcj2 = Fg = G*mc*mj. where G = 6.67*1011 N*m2/kg2, mc = mass of Callisto, mj = mass of Jupiter, and rcj = distance from Jupiter, where rcj = 1.88*109 m for Callisto. In addition, there is a force known as the centripetal force, which is identical to the gravitational force we previously described and keeps Callisto in orbit. The orbital period and this centripetal force are related in the following ways: Fc equals m*(2*/T)2*rcj. We must translate the orbital period from days to seconds in order to be consistent in our use of units: T = 1.44*106 seconds (86,400 seconds per day x 16.69 days) .

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Answer:

4 (N/kg) or B

Explanation:

An application of the equation for Newton’s law of universal gravitation can be used to determine the gravitational field strength at the 2 kg object’s location.

The approximate gravitational field strength of Earth’s gravitational field at the location of the 10 kg object is 4.00 N/kg. Hence, option (B) is correct.

Given data:

The mass of object is, \(m = 2\;\rm kg\).

The distance of object from Earth is, \(d=10,000,000\;\rm m\).

The mass of Earth is, \(M=6 \times 10^{24} \;\rm kg\).

The expression for the gravitational field strength of Earth is,

\(g = \dfrac{GM}{d^{2}}\)

Here, G is the universal gravitational constant and its standard value is \(6.67\times10 ^{-11} \;\rm Nm^{2}/kg^{2}\).

Solve by substituting the values as,

\(g = \dfrac{6.67 \times 10^{-11} \times 6 \times 10^{24}}{(10,000,000)^{2}}\\g \approx 4.00 \;\rm N/kg\)

Thus, we can conclude that approximate value of gravitational field strength of Earth at the location of object is 4.00 N/kg. And option (B) is correct.

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Answer:

Explanation:

P.E. = mgh = 7.7 * 9.81 * 20   j

Answer:

C.

Explanation:

c. the source is written by the person who conducted the experiment. A primary source is an original piece of information created at the time under study. It can be a diary, a letter, a photograph, a recording, or any other type of artifact. It provides firsthand information about an event or topic, and is created by a person who was directly involved or witnessed it.

Answer:

A

Explanation:

Because of the convectional currents

The isolines are always opposite to the electric field vectors in the region around q1q1 and q2q2.

isolines - The lines known as isolines link points with equal values.

To draw Isolines of Electric Potential :

The isolines are always opposite to the electric field vectors in the region around q1q1 and q2q2.

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Answer:

True

Explanation:

Dietary fiber contains an indigestible material known as cellulite. This is false statement.

Plant substances that are not broken down by human digestive enzymes are referred to as dietary fiber.

Only lignin and a few polysaccharides were recognized as meeting this criterion in the late 20th century, but resistant starch and oligosaccharides were listed as dietary fiber components in the early 21st century.

The phrase "all polysaccharides and lignin, which are not digested by the endogenous secretion of the human digestive tract" is commonly used to define dietary fiber.

At the moment, the majority of animal nutritionists either use a physiological definition, which states that "dietary components resistant to breakdown by mammalian enzymes," or a chemical definition, which states that "the sum of non-starch polysaccharides (NSP) and lignin."

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Answer:

When the rock has fallen 12.0 m;

The kinetic energy of the rock is approximately 3,531.6 J

The potential energy of the rock is approximately 6,768.9 J

Explanation:

The question relates to the characteristic constant total mechanical energy of a body

The mass of the rock that falls, m = 30.0 kg

The height of the cliff from which the rock falls, h₁ = 35.0 m

The required information = The kinetic and potential energy when the rock has falling 12.0 m

The kinetic energy is given by the formula, K.E. = 1/2×m×v²

The potential energy is given by the formula, P.E. = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

The velocity of the rock after falling through a given height, h is given by the formula, v² = 2·g·Δh

The total mechanical energy of the rock, M.E. = K.E. + P.E. = Constant

At the height of the cliff before falling, Δh =0, therefore v₁ = 0, therefore, K.E. = 1/2×m×v₁² = 0 J

The potential energy at the cliff before the rock begins to fall, P.E. is goven as follows;

P.E. = 30.0 kg × 35.0 m × 9.81 m/s² = 10,300.5 J

At the top of the cliff, M.E. = K.E. + P.E. = 0 J+ 10,300.5 J = 10,300.5 J

∴ M.E. = 10,300.5 J

When the rock has fallen, 12.0 m, Δh = 12.0 m, the speed of the rock, v₂, is given as follows;

v₂² = 2 × 9.81 m/s² × 12.0 m = 235.44 m²/s²

v₂ = √(235.44 m²/s²) ≈ 15.344 m/s

∴ When the rock has fallen 12.0 m, K.E., is given as follows;

K.E. = 1/2×m×v₂²

K.E. = 1/2 × 30.0 kg × 235.44 m²/s² = 3,531.6 J

When the rock has fallen 12.0 m the kinetic energy, K.E. = 3,531.6 J

When the rock has fallen 12.0 m, M.E. = P.E. + K.E.

M.E. = Constant = 10,300.5 J

K.E. = 3,531.6 J

∴ 10,300.5 J = P.E. + 3,531.6 J

P.E. = 10,300.5 J - 3,531.6 J = 6,768.9 J

∴ When the rock has fallen 12.0 m, the potential energy, P.E. = 6,768.9 J.

Answer:

it means it will become faster because more force are applied. This means that if you get pushed, the harder you are pushed, the faster you'll move (accelerate). The bigger you are, the slower you'll move.

hope this helps bby<3

Answer:

The deltoid muscle is a large triangular shaped muscle associated with the human shoulder girdle, explicitly located in the proximal upper extremity.

Explanation:

A plane layer of coal of thickness L=1 m experiences uniform volumetric generation at a rate of q˙ =10 W/m³ due to slow oxidation of the coal particles.

Averaged over a daily period, the top surface of the layer transfers heat by convection to ambient air for which h= 5 W/m²K and T[infinity] =25 °C, while receiving solar irradiation in the amount GS =400 W/m². Irradiation from the atmosphere may be neglected. The solar absorptivity and emissivity of the surface are each αs =ε=0.95.

Thickness of the plane layer of coal (L) = 1m Volumetric generation rate (q) = 10 W/m³The transfer of heat by convection to the air surrounding the surface of the layer h= 5 W/m²K, and the temperature of the surrounding environment is T[infinity] =25 °C. The amount of solar irradiation received = GS =400 W/m²The solar absorptivity (αs) and emissivity (ε) of the surface are both equal to 0.95.Due to the slow oxidation of coal particles, the plane layer of coal experiences a uniform volumetric generation rate of q˙ =10 W/m³.  

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The water bottle  has given out thermal energy of 168000 Joule.

By virtue of its temperature, a system is in a state of thermodynamic equilibrium, which contains thermal energy.

Unlike the energy of systems that are not in a state of thermodynamic equilibrium, thermal energy cannot be transformed into meaningful work as quickly.

The water bottle  has given out thermal energy = mass of the water × specific heat capacity of water × change in temperature

= 0.8 kg × 4200 J/kg-°C × (80° C - 30° C)

= 168000 Joule.

So, the water bottle  has given out energy of 168000 Joule.

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The magnification of the image formed by the lens is -0.982.

To determine the magnification of the image formed by the lens, we can use the lens formula:

1/f = (n - 1) * (1/r1 - 1/r2)

Where f is the focal length of the lens, n is the refractive index of the lens material, r1 is the radius of curvature of the front surface, and r2 is the radius of curvature of the back surface.

Given that the radii of curvature are 34.5 cm and -26.9 cm, and the refractive index is 1.66, we can substitute these values into the lens formula to calculate the focal length.

Using the lens formula, we find that the focal length of the lens is approximately 13.54 cm.

The magnification of the image formed by the lens can be determined using the magnification formula:

m = -v/u

Where m is the magnification, v is the image distance, and u is the object distance.

Given that the object is placed 42.6 cm from the lens, we can substitute this value and the focal length into the magnification formula to calculate the magnification.

Substituting the values, we find that the magnification of the image formed by the lens is approximately -0.982.

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Answer:

Stars appear to move in the sky because earth rotates on its axis.

Explanation:

Stars appear to move in the sky because of Earth's rotation on its axis. As Earth rotates, it creates the illusion that the stars are moving in the opposite direction across the sky. This movement is similar to how objects appear to move past us when we are driving down the road. The stars themselves do not actually move, but our perspective from Earth makes it seem as though they are. This movement, along with the changing position of the sun, creates the patterns and movements that we see in the sky throughout the day and night.

Answer:

Charging a phone is the exact opposite of discharging a battery's energy. By supplying current (the manipulated variable), a charger transfers lithium ions from the positive electrode to the negative electrode, thus restoring energy

Explanation:

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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a solid rod of length l and mass m has a pivot through its center and is originally horizontal. The maximum speed is called terminal velocity.

Maximum speed restrictions set a ceiling on possible speeds and, if followed, can lessen the variations in vehicle speeds among users of the same road at the same time. The point is a minimum velocity if the acceleration is negative to the left and positive to the right. The point is a maximum velocity if acceleration is positive to the left and negative to the right. Except where a decreased speed is required for safe operation or in conformity with Regulatory Measures, vehicles may not be operated in such a way as to restrict or block the regular and reasonable flow of traffic.

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The required number of circles is 83.33.

Scale ratio, S = 10:1

Maximum discharge of reservoir, Q = 200 m³/s

Maximum discharge of model, q = 0.1 m³/s

Time measured by model, t = 1 hour

Time measured in a circle, T = ?

We can use the following equation to relate the discharges, lengths, areas, and times of the reservoir and the model:

Q₁/Q₂ = (L₁/L₂)² × (A₁/A₂) × (t₁/t₂)

where Q₁ and Q₂ are the discharges, L₁ and L₂ are the lengths, A₁ and A₂ are the areas, and t₁ and t₂ are the times.

In the given problem:

L₁/L₂ = 10/1 (scale ratio)

A₁/A₂ = 1 (as the shapes are similar)

Q₁ = 200 m³/s

Q₂ = 0.1 m³/s

t₁ = 1 hour

Therefore,

200/0.1 = (10/1)² × 1 × (1/t₂)

Simplifying the equation, we get:

2000 = 100 × (1/t₂)

Solving for t₂, we find:

t₂ = 1/2000 hour

Now, we need to find out how many hours are in a circle. In a circle, the time period is 24 hours, i.e., T = 24 hours.

So, the number of circles in 1 hour is 1/24. Therefore, the number of circles in 1/2000 hour is:

(1/24) × (1/(1/2000)) = (1/24) × (2000) = 83.33

Thus, 1 hour is approximately equal to 83.33 circles.

Hence, the required number of circles is approximately 83.33.

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Answer:

111.4 m

Explanation:

PE = m x g x h

349,300 = 320 x 9.8 x h

h = 349300 : 3136

h = 111,384 m

When particles of matter absorb electrical energy, they change it to heat or light, depending on the nature of the material and the specific conditions.

The transformation of electrical energy into heat is a common outcome when particles within a material gain energy due to the electrical current passing through it. This process is known as Joule heating or resistive heating. It occurs due to the resistance of the material, which converts the electrical energy into thermal energy, resulting in an increase in temperature.

Alternatively, when electrical energy is absorbed by certain materials or substances, it can be converted into light energy. This phenomenon is observed in devices such as light bulbs, LED lamps, and other lighting systems, where electrical energy is transformed into visible light. In these cases, the electrical energy excites electrons within the material, causing them to transition to higher energy states and subsequently release energy in the form of photons (light).

Therefore, the two common forms of energy conversion when particles of matter absorb electrical energy are heat and light. The specific outcome depends on factors such as the material's properties, electrical conditions, and intended use of the energy.

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Answer:

\(\boxed {\boxed {\sf 157.5 \ Joules }}\)

Explanation:

Work is equal to the product of force and distance.

\(W=F*d\)

The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.

\(F= 45 \ N \\d= 3.5 \ m\)

Substitute the values into the formula.

\(W= 45 \ N * 3.5 \ m\)

Multiply.

\(W= 157.5 \ N*m\)

\(W= 157.5 \ J\)

157.5 Joules of work are done on the crate.

Explanation:

voltage = current × resistance

5.

12 V = 4.2 A × resistance

resistance = 12 V / 4.2 A = 2.857142857... Ohm

FYI :

4.2 A would be a lot for a small electronic device like a CD player. that would be 12×4.2 = 50.4 Watt, and the CD player would get really hot.

6.

120 V = current × 12 Ohm

current = 120 V / 12 Ohm = 10 A

21-centimeter radiation provides information about the velocity, density, temperature, magnetic fields, and cosmic evolution of the gas cloud that emitted it.

21-centimeter radiation, or the 21-cm line, emitted by neutral hydrogen atoms, offers valuable insights about the gas cloud that emitted it.

By analyzing the Doppler shift, astronomers can determine the cloud's velocity and motion. The intensity of the 21-cm line provides information about the cloud's density and distribution, while the line width indicates its temperature.

Additionally, the polarization of the line reveals the presence and strength of magnetic fields within the cloud. Overall, studying the 21-cm radiation helps understand the structure, dynamics, and cosmic evolution of the gas cloud.

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Answer:

1.F = 256 N

2.a = 8 m/s/s

By looking at the given information, you know force, and an acceleration. Therefore you have enough information to use the first formula.

F = ma

256 N = m * 8 m/s/s

m = 256 N/8 m/s/s

m = 32 Kg

Answer:

W = ?

F = 20 N

s = 50 m

W = F s

W = 20 × 50

W = 1000 J

The work done when a force of 20N displaces a body by 50m is 1000 joules (J).

The work done (W) by a force (F) on an object that moves a displacement (d) is given by the formula:

W = Fd

Where:

W = Work done

F = Force applied

d = Displacement

In this case, the force applied is 20N and the displacement is 50m. Therefore, the work done is:

W = Fd

W = 20N x 50m

W = 1000 joules (J)

Therefore, the work done in displacing the body by 50 m by applying a force of 20 N is 1000 joules.

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The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.

The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.

Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:

E/B = (NC^(-1))/(NA^(-1) m^(-1))

To simplify this expression, we can cancel out the common units in the numerator and denominator:

E/B = (N/C)/(N/(A m))

Now, let's simplify further by dividing the numerator and denominator:

E/B = (N/C) * (A m/N)

Canceling out the common units:

E/B = (A m)/(C)

Therefore, the unit of E/B is A m/C (ampere meter per coulomb).

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It takes approximately 0.477 seconds for the cylinder to travel the first 3.1 meters down the ramp.

We can use conservation of energy to solve this problem. The initial potential energy of the cylinder is converted to kinetic energy as it rolls down the ramp. Since the cylinder is rolling without slipping, we can also relate its linear speed to its angular speed.

The potential energy of the cylinder at the top of the ramp is:

PE = mgh

where m is the mass of the cylinder, h is the height of the ramp, and g is the acceleration due to gravity.

The kinetic energy of the cylinder at the bottom of the ramp is:

KE = 1/2 * mv^2 + 1/2 * I * ω^2

where v is the linear speed of the cylinder, I is its moment of inertia about the center of mass, and ω is its angular speed.

For a thin cylindrical shell, the moment of inertia about the center of mass is:

I = 1/2 * m * R^2

where R is the radius of the cylinder.

The linear and angular speeds of the cylinder are related by:

v = R * ω

Since the cylinder is rolling without slipping, we also have:

v = R * ω

Solving for ω and substituting into the equation for KE, we get:

KE = 1/2 * mv^2 + 1/4 * mR^2 * v^2/R^2

= 3/4 * mv^2

Equating the initial potential energy to the final kinetic energy, we get:

mgh = 3/4 * mv^2

Solving for v, we get:

v = sqrt(4/3 * gh)

Substituting the given values, we get:

h = 3.1 m, θ = 30°, R = r, m = M, g = 9.81 m/s^2

v = sqrt(4/3 * g * h)

= 6.51 m/s

The time it takes for the cylinder to travel the first 3.1 m is given by:

t = d/v

where d is the distance traveled and v is the linear speed of the cylinder.

Substituting the given value, we get:

d = 3.1 m , v = 6.51 m/s ,t = d/v

= 0.477 s

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