Answer:
Explanation:
The investigation is on differences between light waves and sound waves. Because the light and sound are transmitted at a 30° angle at a capsule with glass and vacuum, questions asked should show difference answers for light and sound.
First and third question talk about liquid which is not related here.
Fouth and sixth prediction are wrong as electromagnetic wave will not slow down or speed up in vacuum.
That leaves the second and fifth set as correct answers:
question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?
prediction: The electromagnetic waves will continue through the vacuum, while the mechanical waves will go no farther.
question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?
prediction: The electromagnetic waves will travel in a straight line, showing that they have maintained a constant speed.
Answer:
The two questions and predictions are:
question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?
prediction: The electromagnetic waves will continue through the vacuum, while the mechanical waves will go no farther.
question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?
prediction: The electromagnetic waves will travel in a straight line, showing that they have maintained a constant speed.
Explanation:
light is EM wave which is transverse while sound is longitudinal. speed changes for long wave but not EM.
what is the average speed in miles per hour if you ran 100 yard in 9.0 s
Given:
Distance covered, d = 100 yards
Time, t = 9.0 seconds
Let's find the average speed in miles per hour.
To find the average speed, apply the formula:
\(\text{speed}=\frac{\text{distance}}{\text{time}}\)Since, we are to find the average speed in miles per hour, we are to convert the distance from yards to miles and time from seconds to hours.
We have:
• Distance.
Where:
1 mile = 1760 yards
\(100\text{yards}=\frac{100}{1760}\text{miles=0.0568 miles}\)• Time.
Where:
1 hour = 3600 seconds
\(9\text{seconds}=\frac{9}{3600}=0.0025\text{ hour}\)The distance in miles is 0.0568 miles.
The time in hours is 0.0025 hour.
Hence, to find the average speed we have:
\(\text{speed}=\frac{\text{distance}}{\text{time}}=\frac{0.0568\text{ miles}}{0.0025\text{ hour}}=22.72\text{ mph}\)Therefore, the average speed in miles per hour is 22.72 miles per hour.
ANSWER:
22.72 mph
Bob creates an instrument that is able to play C4 (261.63 Hz). He does some analysis with the sound equipment and it shows that when he plays it, he also gets the frequencies 523.26 Hz, 784.89 Hz, and 1308.15 Hz. What could be true about the instrument? It’s a stringed instrument, it’s a closed pipe, or it’s an open pipe?
Answer:
It could be a stringed instrument or an open pipe.
Explanation:
Let v be the speed of sound, y be wavelength and f be frequency.
v = yf
f= v/y; v is constant.
In a stringed instrument, the fundamental frequency note is heard when the length of the string, l = y/2; y= 2l
f′= v/2l
The second harmonic is heard when l= y
f"= v/y
...
f'''= 3v/2l
We can infer that f"= 2f'
f'''= 3f'
This is similar to the values in the question as;
523.26 =2(261.63) and so on.
Same thing happens with open pipes.
A wax is applied to the bottom surface of cross country skis to achieve a good balance between traction when
the skier needs to climb a small hill and speed on downhill slopes. The coefficients of both static and kinetic
friction between the waxed surface and snow increase as temperature decreases. If the temperature rises
during the day and the skier begins to slip backward on hills they should re-wax their skis with what type of
wax? (1 point)
A. One where the coefficient of kinetic friction is smaller
B. One where the coefficient of static friction is larger.
C. One where the coefficient of kinetic friction is larger
D. One where the coefficient of static friction is smaller
The defined friction force allows you to find which is the correct result for what type of wax you should use:
B. One where the coefficient of static friction is larger.
The friction force is a macroscopic force that opposes the relative movement of bodies, it is the sum of many interactions at the microscope level.
In general for solid bodies the expression of the out of friction is
\(fr = \mu N\)
Where fr is the friction force, μ the friction coefficient and N the normal.
The friction coefficient can be of two types:
Static for when the relative velocity between the two bodies is zero. Dynamic when the relative velocity between the two bodies is different from zero.
In general, the dynamic coefficient is less than the static one.
In this case, as the temperature increases, the friction coefficient decreases, so the skier begins to slide downwards. To prevent this sliding, he must use a wax with a higher friction coefficient.
If you only want to stand on the hill, a wax with a static coefficient must be used, while standing if you want to advance on the hill you must use a wax with a dynamic coefficient since there is a relative movement between the skier and the hill.
Let's examine the different alternatives:
A. False. The friction coefficient must be higher, so that there is more friction force.
B. True. The friction increases and can be stopped on the hill and move up the hill.
C. False In this case, you can go up the hill, but if you stop, you can go back.
D. False. The coefficient must be higher, to increase friction.
Consequently we see that the only type of wax that will allow you to stand or advance on the hill is
B. A wax with a higher statutory coefficient.
In conclusion, using the defined friction force we can find the correct result for what type of wax to use is:
B. One where the coefficient of static friction is larger.
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Answer:
One where the coefficient of static friction is larger
Explanation:
If it takes 50.0 seconds to lift 10.0 Newtons of books to a height of 7.0
meters, calculate the power required to lift it?
According to the Valence Shell Electron Repulsion (VSEPR) model, atoms that surround single different atoms do so in a way that positions themas far apart as possible.
a. True
b. False
Is a light bulb that is on potential or kinetic?
Answer:
pretty sure its kinetic
Explanation:
Answer:
Kinetic
Explanation:
The stored chemical potential energy of a battery converts to electrical kinetic energy to transport electricity to a light bulb, which radiates thermal kinetic energy.
What gravitational attraction does the moon have on the earth? (mass of earth is 6 x
1024 kg, mass of moon is 7.4 x 1022 kg and distance between earth and moon is 3.8 x 108 m).
Answer:
The moon's gravitational pull on the Earth is the main cause of the rise and fall of ocean tides. The moon's gravitational pull causes two bulges of water on the Earth's oceans—one where ocean waters face the moon and the pull is strongest and one where ocean waters face away from the moon and the pull is weakest.
Explanation:
what is the maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water
The maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water is 26.8 %
η = ( \(T_{H}\) - \(T_{C}\) ) / \(T_{H}\) * 100
η = Efficiency
\(T_{H}\) = Hottest temperature
\(T_{C}\) = Coldest temperature
Hottest temperature = Boiling point
Coldest temperature = Freezing point
\(T_{H}\) = 100 °C = 373 K
\(T_{C}\) = 0 °C = 272 K
η = ( 373 - 273 ) / 373 * 100
η = 100 / 373 * 100
η = 26.8 %
In a heat engine, the heat energy is converted into mechanical energy which will be used to do mechanical work like pushing a piston out from the cylinder.
Therefore, the maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water is 26.8 %
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Suppose the demand for air travel decreases (as illustrated in the graph below). A decrease in demand _____ the equilibrium price for air travel and _____ the equilibrium quantity for air travel. decreases, decreases increases, increases decreases, increases
Answer:
decreases, decreases
Explanation:
A decrease in the demand will create a fall in equilibrium prices and the quantity supplied will also decrease. As the equilibrium prices in the market are the price in which the quantity demanded equals to quantity supplied. If the demand for the air decreases then the quantity of the air travel will also decrease and thus when the supply and demand change so do the changes associated with the equilibrium prices.You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
30°
110
34°
120
38°
128
42°
133
46°
127
50°
119
54°
109
At which angle will the performer travel the shortest distance?
A. 44°
B. 54
Ο Ο Ο Ο
C. 32
D. 50°
Answer:
128
Explanation:
Answer:
54 degrees
Explanation:
A fire truck emits an 880Hz siren. As the truck approaches an observer on the sidewalk, he perceives the pitch to be 950Hz. Approximately what pitch does he hear after the truck passes and is moving away?
Answer:
The pitch that he hears after the truck passes and is moving away is 819.6 Hz.
Explanation:
The pitch that he hears after the truck passes and is moving away can be calculated using the following equation:
\( f = f_{0}*\frac{v_{s} \pm v_{o}}{v_{s} \pm v_{f}} \)
Where:
\(f\): is the perceived frequency
\(f_{0}\): is the emitted frequency
\(v_{s}\): is the speed of sound = 340 m/s
\(v_{o}\): is the speed of the observer = 0 (he is not moving)
\(v_{f}\): is the speed of the fire truck
First, we need to find the speed of the fire truck. When it approaches the observer we have:
\( f = f_{0}*\frac{v_{s} + v_{o}}{v_{s} - v_{f}} \)
\( 950 Hz = 880 Hz*\frac{340 m/s}{340 m/s - v_{f}} \)
\( v_{f} = 340 m/s - \frac{880 Hz*340 m/s}{950 Hz} \)
\( v_{f} = 25.05 m/s \)
Hence, the speed of the fire truck is 25.05 m/s.
Now, we can calculate the pitch that the observer hears after the truck passes:
\( f = f_{0}*\frac{v_{s} - v_{o}}{v_{s} + v_{f}} \)
\( f = 880 Hz*\frac{340 m/s}{340 m/s + 25.05 m/s} \)
\( f = 819.6 Hz \)
Therefore, the pitch that he hears after the truck passes and is moving away is 819.6 Hz.
I hope it helps you!
An object moves from position x = -1.88 m to x = -4.27 m. What is it's displacement?
Answer: Displacement = -2.39 m
Explanation: The displacement of an object is the difference between its final position and its initial position. In this case, the object moved from x = -1.88 m to x = -4.27 m, so its displacement is:
Displacement = Final position - Initial position
Displacement = (-4.27 m) - (-1.88 m)
Displacement = -4.27 m + 1.88 m
Displacement = -2.39 m
Therefore, the displacement of the object is -2.39 m.
Please mark me brainliest if you understand now! Thank you
Which of the following. Chemical represent the law of conservation of Matter?
Answer:
The answer is first one 1...
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Which one of the following is the longest length?
(a) 100 m
(b) 104 µm
(c) 107 nm
(d) 102 mm
Okay, let's convert all the lengths to the same unit to compare:
(a) 100 m = 100 meters
(b) 104 μm = 104 micrometers = 104 × 10^-6 meters = 0.000104 meters
(c) 107 nm = 107 nanometers = 107 × 10^-9 meters = 0.000000000997 meters
(d) 102 mm = 102 millimeters = 102 × 10^-3 meters = 0.0102 meters
The longest length is:
(a) 100 m = 100 meters
The answer is option (a).
Answer: 100 m
Explanation:
1 μm = \(10^{-6}\) m = 0,000001 m
1 nm = \(10^{-9}\) m = 0,000000001 m
1 mm = \(10^{-3}\) m = 0,001 m
∴ 100 m es la mayor longitud
What was the initial speed of a truck that ended up with a speed of 65 Km/hr after it accelerated 3 Km/hr/sec for a period of 5 seconds?
ANSWER:
50 km/hr
STEP-BY-STEP EXPLANATION:
Given:
Final speed (v) = 65 km/hr
Acceleration (a) = 3 km/hr/sec
Time (t) = 5 sec
We have the following formula, we substitute and solve for the initial speed, just like this:
\(\begin{gathered} v=u+at \\ \\ 65=u+3\cdot5 \\ \\ u=65-15 \\ \\ u=50\text{ km/hr} \end{gathered}\)Therefore, the initial speed is 50 km/hr.
Taking off on both feet and landing on both feet
Question 2 options:
running
jumping
skipping
hopping
Answer:
Your answer is Jumping
Explanation:
Answer:
jumping
Explanation:
1. A plane is flying from Indianapolis to Los Angeles with an air speed of 211 km/hr towards the west. The air current that day is blowing at 12 km/h towards the east. Find the speed of the plane relative to the ground.
2. A tug boat called SS Walnut is traveling upstream with a still water speed of 22 km/h in a river with a current of 5.0 km/h. What is the velocity of the boat relative to an object on the shore?
3. Dante flies his jet plane from Spokane, WA to Cincinnati OH. The plane flies towards the east with a ground speed of 740 km/h. The wind that day is blowing from the west with a speed of 38 km/h. What is the jet's air speed?
4. A kayaker traveling downstream is pulled out of his kayak in a river with a current of 31 km/h. The Kayaker continues downstream. A hiker on the shore observes the kayaker to be swimming at 33 km/h. What is the kayaker's still water velocity?
5. A prop engine plane takes off from the ground and reaches its cruising altitude and air speed of 216 km/h towards the east. At this altitude the easterly wind speed is measured at 67 m/s.
a. What is the plane's ground speed while flying at this altitude?
b. What is the distance this plane has flown after 7.0 hours at its cruising altitude?
Answer:
1.199km/h towards west
2.17km/h towards upstream direction
3.702km/h towards east
4.2km/h towards downstream direction
5.a.149km/h towards east
b.1043km
Explanation:
1.V p,e = Vp,w + Vw,e
= 211km/h-12km/h
=199km/h towards west
2. Vb,o=Vb,r+Vr,o
Vb,o=22-5km/h
=17km/h towards upstream direction
3.Vj,w= Vj,e + Ve,w
Vj,w = 740-38km/h
= 702km/h towards east
4.Vk,r= Vk,e+ Ve,r
Vk,r=33 - 31km/h
=2km/h towards downstream direction
5.a.Vp,e=Vp,w +Vw,e
Vp,e=216-67km/h
=149km/h towards east
b. distance =speed * time
= 149km/h * 7h
=1043km
[V p,e-velocity of plane relative to earth(ground)]
[p-plane ,w-wind ,e-earth, b-boat, r-river, o-object, j-jet, k-kayaker,]
4. What are the 4 basic components of a circut?
Answer:
Every electric circuit, regardless of where it is or how large or small it is, has four basic parts: an energy source (AC or DC), a conductor (wire), an electrical load (device), and at least one controller (switch). Visualize what happens when you switch on a room light.
Explanation:
Hope this helps you
which object has a weight of about 22.5 n the book the rock the box the fish
Answer: The rock
Explanation:
Geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s2, and finds that it takes 24.0 s for 14 complete cycles.
1) Calculate the length of the pendulum. (Express your answer to three significant figures.)
The length of the pendulum is 0.910m if acceleration due to gravity is 9.8 m/\(s^{2}\) and it takes 24 s to go 14 cycles.
First we will calculate Time period of pendulum
T = no of oscillations/ time
= 14/24
= 0.5833
We can find length of pendulum using formula
L=g(T/2π)^2
= 9.8(0.583/2×3.14
=9.8(0.583/6.28)
= 0.910 m
A simple pendulum is an arrangement of oscillating bob that has periodic motion. The simple pendulum has a small bob of mass ‘m’ suspended by a thin string fixed to a platform and length of string is L.
The time taken to complete one oscillation is defined as the time period of the pendulum. For simple pendulum of length L , time period is T = 2π √R/2g.
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What is the correct answer choice to the question above?
Answer: A. a straight line inclined to the time axis
Explanation:
During the data transmission there are chances that the data bits in the frame might get corrupted. This will require the sender to re-transmit the frame and hence it will increase the re-transmission overhead. By considering the scenarios given below, you have to choose whether the packets should be encapsulated in a single frame or multiple frames in order to minimize the re-transmission overhead.
Justify your answer with one valid reason for both the scenarios given below.
Scenario A: Suppose you are using a network which is very prone to errors.
Scenario B: Suppose you are using a network with high reliability and accuracy.
1. Based on Scenario A, multiple frames will minimize re-transmission overhead and should be preferred in the encapsulation of packets.
2. Based on Scenario B, the encapsulation of packets should be in a single frame because of the high level of network reliability and accuracy.
Justification:
There will not be further need to re-transmit the packets in a highly reliable and accurate network environment, unlike in an environment that is very prone to errors. The reliable and accurate network environment makes a single frame economically better.
Encapsulation involves the process of wrapping code and data together within a class so that data is protected and access to code is restricted.
With encapsulation, each layer:
provides a service to the layer above itcommunicates with a corresponding receiving nodeThus, in a reliable and accurate network environment, single frames should be used to enhance transmission and minimize re-transmission overhead. This is unlike in an environment that is very prone to errors, where multiple frames should rather be used to minimize re-transmission overhead.
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how did we compensate for friction ?
A postal worker on a bicycle travels at an average speed of 4 m/s for 3 minutes. Work out how far she travelled.d by the car in miles.
Answer:
Before we begin, first convert the minutes unit to seconds to match the unit for speed. Since there are 60 seconds in a minute, and there are 3 minutes, 3*60 = 180 seconds. Using the formula s = d/t, we can manipulate this formula to solve for d, the distance. So we isolate the d variable, to get d = st, and we can substitute the values of s and t into this formula. Now we have d = 4m/s*180s. Now we solve this to get d = 720m. Now we can convert meters to miles, to get approximately 0.45 miles.
Explanation:
Calculate weight if an object, given its mass
Answer:
Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity
Explanation:
A dart is thrown horizontally at a speed of 12 m/s at the bull's-eye of a dartboard 2.7 m away. How far below the intended target does the dart hit (in m)?
The distance below the intended target the dart hit is 0.26 m.
Time of motion of the dartThe time taken for the dart to fall is calculated as follows;
X = Vxt
where;
X is the horizontal displacementVx is the horizontal speedt is time of motiont = X/Vx
t = 2.7/12
t = 0.23 seconds
Height of fall of the darth = vt + ¹/₂gt²
where;
v is initial vertical velocity = 0h = ¹/₂gt²
h = ¹/₂(9.8)(0.23²)
h = 0.26 m
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A motorcyclist increases the velocity of his bike from 30.0 meters/second to 55.0 meter/second under a constant acceleration of 5.00 meters/second^2. How long does it take the bike to reach the final velocity?
Answer:
Time, t = 5 seconds.
Explanation:
Given the following data;
Initial velocity = 30m/s
Final velocity = 55m/s
Acceleration = 5m/s²
To find the time, we would use the first equation of motion;
\( V = U + at\)
Where;
V is the final velocity. U is the initial velocity. a is the acceleration. t is the time measured in seconds.Making time, t the subject of formula, we have;
\( t = \frac{V - U}{a}\)
Substituting into the equation, we have;
\( t = \frac{55-30}{5}\)
\( t = \frac{25}{5}\)
Time, t = 5 seconds.
Therefore, it would take the bike 5 seconds to reach the final velocity.
Question 1 of 20:
Select the best answer for the question.
1. What's an example of being proactive in your workouts?
A. Wearing appropriate running shoes for your environment
O B. Choosing to use the next available cardio machine
O C. Going on a run without planning your path ahead of time
O D. Working out twice as long as expected since you're not fatigued
O Mark for review (Will be highlighted on the review page)
A. Wearing appropriate running shoes for your environment is an example of being proactive in your workouts.
What are the ways of becoming proactive in workouts?There are several ways to become proactive in workouts:
(1) Set specific goals: Setting specific and measurable fitness goals can help you stay focused and motivated. It can also help you track your progress and make necessary adjustments to your workout routine.
(2) Plan your workouts: Planning your workouts ahead of time can help you stay organized and committed to your fitness routine. This can include scheduling your workouts in advance and creating a workout plan that targets your specific goals.
(3) Track your progress: Tracking your progress can help you stay motivated and see how far you've come. This can include keeping a workout journal, taking progress photos, or using a fitness tracker.
(4) Stay consistent: Consistency is key when it comes to achieving fitness goals. Set a regular workout schedule and stick to it as much as possible.
(5) Listen to your body: Pay attention to how your body feels during and after workouts. If something doesn't feel right, make adjustments or seek guidance from a fitness professional.
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A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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