Answer:
p = w/t = mgh/t = 60kg*7.2m*10.4sec/10.4 = 432 watt
When the sideways force is 100 Newtons on Skelly who has a mass of 25kg, but there is a constant 50 N drag force, then Skelly's acceleration will bem/s,
In order to determine the force on Skelly, use the following formula:
\(F=m\cdot a\)where:
m: mass = 25 kg
a: acceleration = 10m/s^2
Replace the previous values of the parameters into the formula for F:
\(F=(25kg)(10\frac{m}{s^2})=250N\)Hence, the force on Skelly is 250N
Answer:
0.33 0.17
Explanation:
2) What does the specific heat capacity of a material tell you about how easy it is to heat up
that material
Answer:
See the explanation below
Explanation:
In order to understand in a better way what the specific heat is, we must analyze the units of measurement of this scalar magnitude.
\([\frac{kJ}{kg*C} ]\) or [kJ/kg*°C]
For example for water Cp = 4.1 [kJ/kg*°C]
That is, to increase the temperature by one degree celsius in one kilogram of water, 4.14[kJ] of energy is required.
What will happen to the property of the electromagnet with an increasing number of coils
The number of turns determines the strength; whether the core is made of soft or hard magnetic material. Soft iron is more easily magnetized than steel. As a result, using a soft core increases the electromagnet's strength.
What is magnetic field ?The magnetic field is mathematically described as a vector field. This vector field can be directly plotted as a grid of many vectors. Each vector points in the same direction as a compass and has a length proportional to the strength of the magnetic force. This technique is demonstrated by arranging many small compasses in a grid pattern and placing the grid in a magnetic field. The only difference is that a compass does not indicate field strength. Field lines are another way to represent the information contained within a vector field. We remove the grid pattern and connect the vectors with smooth lines. We are free to draw as many lines as we want.
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A 14.0-kg solid homogeneous disk of radius 0.600 m is rotating with an initial angular speed of 50.0 rad/s about africtionless horizontal shaft. A 6.00-kg solid homogeneous disk of radius 0.400 m is initially at rest on the sameshaft. The disks are pushed into contact, as shown. Because of surface friction, the two disks eventually attain a finalcommon angular speed 64.(a) Find the final common angular speed of the system.(b) In the collision of the two disks, kinetic energy is not conserved because nonconservative (frictional) internalforces act during the contact. How much energy was lost to friction in the collision?
Given data
The mass of the first solid is m1 = 14 kg
The mass of the second solid is m2 = 6 kg
The radius of the first solid is r1 = 0.6 m
The radius of the second solid is r2 = 0.4 m
The angular speed of the first solid is w1 = 50 rad/s
The angular speed of the second solid is w2 = 0 rad/s
The expression for the final common angular speed of the system from the conservation of angular momentum is given as:
\(\begin{gathered} I_1\omega_1+I_2\omega_2=(I_1+I_2)\omega_f \\ \omega_f=\frac{I_1\omega_1+I_2\omega_2}{(I_1+I_2)} \\ \omega_f=\frac{\frac{m_1(r_1)^2}{2}\omega_1+\frac{m_2(r_2)^2}{2}_{}\omega_2}{(\frac{m_1(r_1)^2}{2}+\frac{m_2(r_2)^2}{2})} \end{gathered}\)Substitute the value in the above equation.
\(\begin{gathered} \omega_f=\frac{\frac{14\text{ kg}\times(0.6m)^2}{2}\times50\text{ rad/s +}\frac{6\text{ kg}\times(0.4m)^2}{2}\times0\text{ rad/s}}{\frac{14\text{ kg}\times(0.6m)^2}{2}+\frac{6\text{ kg}\times(0.4m)^2}{2}} \\ \omega_f=42\text{ rad/s} \end{gathered}\)Thus, the final common angular speed of the system is 42 rad/s.
(b)
The expression for the energy lost to friction in the collision is given as:
\(\begin{gathered} \Delta E=E_i-E_f \\ \Delta E=\frac{1}{2}I_1(\omega_1)^2-\frac{1}{2}(I_1+I_2)(\omega_f)^2 \end{gathered}\)Substitute the value in the above equation.
\(undefined\)State the hamilton's equation of
motion and derive each of them
Hamilton's equations of motion are a set of equations that describe the dynamics of a classical mechanical system in terms of a generalized coordinate and its conjugate momentum.
How to explain the equationThe equations are derived from the Hamiltonian formalism. Hamilton's equations can be derived from the Hamilton's principle, which is a variational principle that states that the action of a dynamical system is stationary.
To derive these equations, we start with the Hamiltonian function H(p, q) and use the principle of least action. The action S is defined as the integral of the Lagrangian L(q, q', t) over time:
S = ∫[L(q, q', t)] dt
To find dp/dt, we differentiate the Lagrangian with respect to q:
∂L/∂q = ∂(p * q' - H)/∂q
= -∂H/∂q
Using the chain rule, we find:
dL/dt = (∂L/∂q) * dq/dt + (∂L/∂q') * dq'/dt
= -∂H/∂q * dq/dt + p * d(q')/dt
= -∂H/∂q * dq/dt + p * d^2q/dt^2
= -∂H/∂q * dq/dt + dp/dt
Since the Lagrangian is equal to p * dq' - H, we can write:
dL/dt = -∂H/∂q * dq/dt + dp/dt
From the principle of least action, we know that the action S is stationary, so dL/dt = 0. Thus, we have:
-∂H/∂q * dq/dt + dp/dt = 0
Rearranging the equation, we obtain the first equation of motion:
dp/dt = -∂H/∂q
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can any one help me with this?
if an atom was a scale, in which the nucleus is the size of an apple the electron.....
Answer:
the nucleus is the size of an apple, approximately 5 cm of radius e, the atom has a radius of R = 5 cm 104 = 50000 cm = 50 km
Explanation:
In the Rutherford experiments it was proved that the atomic nucleus has the volume 10-4 the volume of the atom.
If we make a scale design in which the nucleus is the size of an apple, approximately 5 cm of radius e, the atom has a radius of R = 5 cm 104 = 50000 cm = 50 km
This shows that almost the entire volume of the atom is empty.
: A small block with mass 0.130 kg is attached to a string passing through a hole in a frictionless, horizontal surface. The block is originally revolving in a circle with a radius of 0.800 m about the hole with a tangential speed of 4.00 m/s. The string is then pulled slowly from below, shortening the radius of the circle in which the block revolves. The breaking strength of the string is 30.0 N. What is the radius of the circle when the string breaks
Answer:
r = 0.0173 m = 1.73 cm
Explanation:
Here, the centripetal force of the block will be providing the required breaking tension in the string:
\(Tension = Centripetal Force\\T = F_c\\\\T = \frac{mv^2}{r} \\\\r = \frac{mv^2}{T}\\\)
where,
r = radius = ?
m = mass of block = 0.13 kg
v = tangential spee of block = 4 m/s
T = Breaking Strength = 30 N
Therefore,
\(r = \frac{(0.13\ kg)(4\ m/s)^2}{30\ N}\)
r = 0.0173 m = 1.73 cm
When finding the radius of the string at the point it breaks, the tangential
velocity is assumed to be constant.
The radius when the string breaks is \(\underline{6.9 . \overline 3 \times 10^{-3}} \ m\)Reasons:
The mass of the small block, m = 0.130 kg
Initial radius of the circle of rotation = 0.800 m
Tangential velocity, v = 4.00 m/s
The radius of the path of rotation is reduced as the string is pulled
Breaking strength of the string = 30.0 N
Required:
The radius of the circle when the string brakes
Solution:
\(Centripetal \ force = \dfrac{m \cdot v^2}{r}\)
Where;
r = The radius of the circle of rotation
When the string brakes, w have;
Centripetal force = Breaking strength of the string = 30.0 N
Which gives;
\(\displaystyle r = \mathbf{\dfrac{m \cdot v^2}{Centrifugal \ force}} = \frac{0.130 \times 4^2}{30} =6.9\overline 3 \times 10^{-2}\)
The radius of the circle when, the string breaks r = \(\underline{6.9\overline 3 \times 10^{-2}} \ m\)
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Question 5 of 10
The graph below shows the downloads of two songs over time.
70
Song 1
60
50
40
Number of downloads
(spopunu)
Song 2
30
20
10
O
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Time (minutes)
Which term describes the slope of the graph of song 2 between minute 6 and
minute 7?
A. Positive
B. Zero
C. It is impossible to calculate
D. Negative
SUBMIT
Answer:
b
Explanation:
ONLY answer if you know FOR SURE. if your not 100% on it, DONT FREAKING ANSWER. ONLY IF YOU KNOW FOR SURE!
Which type of graph is best to use with data that shows a comparison of categories?
A. Pie Chart (Circle Graph)
B. Line Graph
C. Bar Graph
D. Frequency Table
Answer: the answer is (C)
Explanation: Bar graphs show comparisons using number comparisons
How has Physics improved
or affected our society?
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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Please help with these MCQs.
1. Filter absorbs __________________.
- only primary coloured lights
- only secondary coloured lights
- only tertiary coloured lights
- all colors of white light
2. The light that has passed through a filter, is always ______________.
- dim
- bright
- sharp
- blur
1. Filter absorbs all colors of white light.
2. The light that has passed through a filter, is always dim.
Which colors are being absorbed by the filter?The filter selectively transmits the red and blue portions of the incident white light spectrum, but absorbs most of the green wavelength.
Color filters absorb certain wavelengths of color and transmit the other wavelengths allowing them to be seen.
Therefore in conclusion, the right filter can reduce glare, increase contrast, and make lunar features pop.
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A piano has been pushed to the top of the ramp at the back of a moving van. The workers think it is safe, but as they walk away, it begins to roll down the ramp. Neglect the friction between the piano and the ramp.
If the back of the truck is 1.0 m above the ground and the ramp is inclined at 24 ∘, how much time do the workers have to get to the piano before it reaches the bottom of the ramp?
The time the workers have to get to the piano before it reaches the bottom of the ramp is 0.7 second.
What is the distance travelled by the piano?The distance travelled by piano is calculated by applying the following formula as shown below.
sin (24) = h / L
L = h / sin (24)
where;
h is the height of the truck above the groundL is the distance travelled by piano along the rampL = ( 1 m ) / ( sin 24 )
L = 2.46 m
The time taken for the piano to reach the ground is calculated as follows;
s = ut + ¹/₂gt²
where;
u is the initial velocity of the pianot is the time s is the distance travelled = LL = 0 + ¹/₂gt²
t = √ ( 2L / g )
t = √ ( 2 x 2.46 / 9.8 )
t = 0.7 second
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Which of the following is NOT part of the grain group?
Answer:
Any food made from wheat, rice, oats, cornmeal, barley, or another cereal grain is a grain product. Anything else is not
Explanation:
You're working in mission control for an interplanetary space probe. A trajectory correction calls for a rocket firing that imparts an impulse of 5.51N/s. If the rocket's average thrust is 124mN , how long should the rocket fire
A trajectory correction calls for a rocket firing that imparts an impulse of 5.51N/s. If the rocket's average thrust is 124mN , then the rocket should fire for
What is Rocket ?The pace at which electrical energy is transmitted by an electric circuit is referred to as its power. The watt is the SI unit of power, equal to one joule per second. Watts, like other SI units, have standard prefixes: thousands, millions, and billions of watts are referred to as kilowatts, megawatts, and gigawatts, respectively.
It is a popular misperception that electric power is purchased and sold, whereas electrical energy is. Electricity, for example, is sold to users in kilowatt-hours (kilowatts multiplied by hours), because energy is defined as power multiplied by time.
Given,
Impulse = 5.51 N/s
force = 125 mN
impulse = Force × Time
5.51 = 125 × 10⁻³ × Time
Time = 5.51 ÷ 125 × 10⁻³
time = 44.08 s
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if no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is lily to worsen lessen or remain the same during the next 50 years
If no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is then a. likely to worsen
Astronomers already have a serious problem with light pollution from cities and other sources, which makes it more challenging to detect dim objects in the night sky. Light pollution is predicted to get worse unless action is taken to stop it as urbanisation grows and more artificial lights are installed.
Astronomical observations can be affected by radio interference from telecommunications, and unless steps are taken to reduce the issue, the issue is only going to become worse as the number of radio-emitting devices rises. In addition, astronomers' instruments and spacecraft are increasingly in danger from space debris. The probability of collisions and other accidents is anticipated to rise as the amount of trash in space continues to rise.
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Complete Question:
If no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is then -
a. likely to worsen
b. lessen or remain the same during the next 50 years
A 10 KVA, 380 V, 50 Hz, 3-phas, star-connected salient pole alternator has direct axis and quadrature axis reactances of 12 ohms and 8 ohms respectively. The armature has resistance of 1 ohin per phase, The generator delivers rated load at 0.8 p,f lagging with the terminal voltage being maintained at rated value. If the load angle is 16.15, determine (i) the direct axis and quadrature axis components of armature current, (b) excitation voltage of the generator.
Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.
Given:
Apparent power (S) = 10 KVA = 10,000 VA
Line voltage (V) = 380 V
Frequency (f) = 50 Hz
Xd = 12 ohms
Xq = 8 ohms
Ra = 1 ohm
Power factor (pf) = 0.8 lagging
Load angle (δ) = 16.15 degrees
(i) Armature current's direct axis and quadrature axis components
We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:
S = 3Vphase Iphase cos(φ)
Iphase = S / (3Vphase cos(φ))
For a lagging power factor, cos(φ) = 0.8, so
Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A
The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current. Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:
Id = (VL - IaRa) / Xd
Iq = (VL - IaRa) / Xq
where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,
Ia = Iphase / √3 = 10.46 / √3 = 6.03 A
Substituting the given values:
Id = (380 - 6.03 x 1) / 12 = 30.28 A
Iq = (380 - 6.03 x 1) / 8 = 46.92 A
(ii) Excitation voltage of the generator:
The excitation voltage (E) of the generator is given by:
E = Vphase + IqXq
Substituting the given values:
E = 380 + 46.92 x 8 = 765.36 V
Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.
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Why did the model spacecraft go so much faster than expected on Wednesday?
Write your final explanation to the Universal Space Agency. It may be helpful to review the USA Evidence Cards on the next screen or refer to your Modeling Tool: Spacecraft Launches student sheet as you write. write a essays
Amplify magnetic field lesson 3.3 activity 5
Because of the larger magnetic field close to the magnet, the Wednesday launch was able to store more potential energy and propel the spacecraft at the a faster rate.
Which type of energy is most crucial for our planet*?The sun is a significant energy source. The main source of energy is the solar, from which every energy the earth is derived. Sunlight not only provides us with solar thermal energy but also allows sun (photo - voltaic) cells to generate electricity.
What is the primary energy source utilised to run equipment in deep space?Since 1961, Radiopharmaceutical Thermoelectric Devices (RTGs) have provided the majority of the electricity for American space operations. Plutonium-238 can be used as an energy source in the RTGs for spacecraft, satellites, and navigation beacons due to its high decay heat (0.56 W/g).
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A 250 kg cart is traveling at 8 m/s when it strikes a 100 kg cart at rest. After the elastic collision, the 250 kg cart continues to travel forward but at a lower velocity of 3 m/s. Determine the velocity of the 100 kg cart after the elastic collision.
Answer: In this scenario, we have two carts colliding with each other. One cart weighs 250 kg and is moving at a speed of 8 m/s, while the other cart weighs 100 kg and is initially at rest.
After the collision, the 250 kg cart continues moving forward, but at a slower speed of 3 m/s. We want to find out the speed at which the 100 kg cart moves after the collision.
To solve this, we use the principle that the total "push" or momentum before the collision should be the same as the total momentum after the collision.
Since the 100 kg cart is initially at rest, its momentum is zero. The momentum of the 250 kg cart before the collision is 250 kg * 8 m/s = 2000 kg·m/s.
After the collision, the momentum of the 250 kg cart becomes 250 kg * 3 m/s = 750 kg·m/s.
To find the momentum of the 100 kg cart after the collision, we subtract the momentum of the 250 kg cart after the collision from the total momentum before the collision: 2000 kg·m/s - 750 kg·m/s = 1250 kg·m/s.
Now, we divide this momentum by the mass of the 100 kg cart to find its velocity: 1250 kg·m/s / 100 kg = 12.5 m/s.
Therefore, the 100 kg cart moves at a velocity of 12.5 m/s after the collision, in the opposite direction of the 250 kg cart's motion.
The two solid pieces of confirmation data for the Big Bang are A). That dark matter parameter is not 1.0 B). That the heavy elements are produced in the early universe C). That the CMB is nearly uniform and cold D). That hydrogen, helium, and just a few other light elements are in high abundance
Answer:
C) That the CMB is nearly uniform and cold
D) That hydrogen, helium, and just a few other light elements are in high abundance
Explanation:
The Big Bang theory predicts that there is cosmic microwave background that should be uniform and it is the result of the heat at the beginning of the universe. It also says how much of elements like hydrogen and helium should be in the universe when everything starts. Scientifics discover this cosmic microwave background CMB and where they look over old galaxies, the amount of hydrogen and helium is accurate to the theory. Therefore, the two solid pieces of conformation data for the Big Bang are:
C) That the CMB is nearly uniform and cold
D) That hydrogen, helium, and just a few other light elements are in high abundance
an electricity company claims to generate all of its electricity from environmently friendly energy sources.
the energy sources used by the company are shown in the pie chart
Do you think that the claim made by the company is correct?
The claim made by the company is not correct because gas and nuclear are energy source of pollution.
It is sometimes referred to as a non-conventional or renewable source of energy. For instance, geothermal energy, solar energy, and wind energy. Conventional Source of Energy – Energy sources that are finite and exhaustible are referred to as conventional sources of energy. For instance, fossil fuels like coal, petroleum, etc.
Wind mills may use the kinetic energy that the wind has in large amounts. The windmill's rotation is programmed to drive the turbine, which ultimately produces electricity. In Denmark, more than 25% of all electrical needs are met by electricity. It is referred to as the "country of winds" since a massive network of windmills is used to generate the energy.
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A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance traveled by the biker?
100 m
80 m
30 m
48 m
PLZ heeeeelp
Answer:
48m
Explanation:
Given the following data;
Initial velocity = 0m/s
Final velocity = 6m/s
Time, t = 6 secs
Time, T2 = 5 secs
Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
Substituting into the equation;
\(a = \frac{6 - 0}{6}\)
\(a = \frac{6}{6}\)
Acceleration, a = 1m/s²
To find the distance covered in the first phase;
Solving for distance, we would use the second equation of motion;
\( S = ut + \frac {1}{2}at^{2}\)
Substituting the values into the equation;
\( S = 0(6) + \frac {1}{2}*1*(6)^{2}\)
\( S = 0 + \frac {1}{2}*1*36\)
\( S = 0.5 *36\)
Distance, S1 = 18m
For the second phase, time T2 = 5 secs;
Mathematically, speed is given by the equation;
\(Speed = \frac{distance}{time}\)
Making distance the subject of formula, we have;
\(Distance, S = speed * time\)
Substituting into the above equation;
\(Distance, S = 6 * 5\)
Distance, S2 = 30m
Total distance = S1 + S2 = 18m + 30m = 48m
Total distance = 48m
Therefore, the total distance traveled by the biker is 48m.
For an object having a mass m falling in the z direction, the potential energy is 1/2mz, where g is the gravitational acceleration constant (approximately 9.8 m/s2) and z is position. For this one-dimensional motion, determine the Lagrangian function L and write the Lagrangian equation of motion.
The Lagrangian function L for an object having a mass m falling in the z direction is given by: L = T - U Where T is the kinetic energy and U is the potential energy. For an object falling in the z direction, the kinetic energy T is given by:
T = 1/2 mv^2
And the potential energy U is given by:
U = 1/2mz
Substituting these expressions into the Lagrangian function L, we get:
L = 1/2 mv^2 - 1/2mz
The Lagrangian equation of motion for this system is given by:
d/dt (∂L/∂v) - ∂L/∂z = 0
Substituting the expression for L into this equation, we get:
d/dt (mv) - ∂(1/2 mv^2 - 1/2mz)/∂z = 0
Simplifying, we get:
d/dt (mv) - 1/2m = 0
This is the Lagrangian equation of motion for an object having a mass m falling in the z direction. It can be used to determine the position and velocity of the object as a function of time.
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How much heat has to be added to 1 gallon of water to raise the temperature from
68F to 40C?
Answer:
The heat needed to raise the temperature of 1 gallon of water from 68°F to 40°C is approximately 28,265 Joules.
Explanation:
If you dropped the hoop without any string so it did not rotate as it fell, how fast would its center be moving when it had fallen a distance h
Although we do not have the necessary information to provide an exact answer, we can confirm that the object will have fallen by a multiple of 9.8 meters due to gravity.
How does gravity affect this fall?When an object is dropped, its acceleration is determined by gravity. This force applies a constant acceleration of 9.8 meters per second. Therefore, to calculate its speed at distance h, we would need to know the time it has taken the object to reach this point, and use that together with our known acceleration in order to calculate its current speed.
Therefore, we can confirm that in order to calculate the current speed of the object at point h, we require the time taken to reach this point or the value of the distance itself and that the answer will be a multiple of 9.8, due to gravity.
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Welding requires extensive training.
True
False
Answer:
True.
Explanation:
Welding requires extensive training because welding involves fire and we need to use fire safety measurements. A normal man can't just simply go and weld so a person must require extensive training for welding.
You see a boat sitting at the end of a dock. Ten minutes later you see the same boat in a cove to the right of the dock. You did not see the boat move.
However, you know that the boat moved because its
relative to the dock changed.
The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .
Everything is always in motion, but the way we perceive it depends on our frame of reference.
In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.
It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.
In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.
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A .50 kg mass attached to an ideal spring of spring constant 80N/c oscillate on horizontal frictionless surface , the mechenical energy is .12j , the greatest energy from y to x is
The greatest energy or the greatest extension from its equilibrium positions is equal to 0.12 J.
What is mechanical energy?Mechanical energy is the sum of potential energy and kinetic energy that is used to do work. Mechanical energy defines the energy of a system because of its motion or position.
The total mechanical energy is conserved as we know the energy can neither be created nor destroyed. The mechanical energy of a system can only be changed from one form to another whenever the forces used to do work are conservative in nature.
The energy is stored in the form of potential energy in a compressed string. If the elastic potential energy is changed into kinetic energy as it is used to accelerate the mass.
The total mechanical energy required to compress the spring is the maximum amount of elastic potential energy stored in the spring. The greatest energy of the spring will be at the maximum displacement. Therefore, the spring will have the greatest potential energy at equilibrium positions equal to 0.12 J.
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On an aircraft carrier, a catapult provides an accelerating force on the aircraft. The catapult provides a constant force for a distance of 150 m along the deck. Calculate the resultant force on the aircraft as it accelerates. Assume that all of the kinetic energy at take-off is from the work done on the aircraft by the catapult.
To calculate the resultant force on the aircraft as it accelerates from the catapult, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.
Since all of the kinetic energy at take-off is from the work done on the aircraft by the catapult, we can equate the work done by the catapult to the kinetic energy of the aircraft at take-off, that is:
Work done by catapult = kinetic energy of aircraft at take-off
The work done by the catapult is given by the force provided by the catapult multiplied by the distance over which it acts, that is:
Work done by catapult = force × distance
The distance over which the force provided by the catapult acts is given as 150 m, so we have:
Work done by catapult = force × 150
The kinetic energy of the aircraft at take-off is given by:
(1/2) × mass × velocity^2
Since the aircraft is initially at rest, its initial velocity is zero, so we have:
kinetic energy of aircraft at take-off = 0.5 × mass × (final velocity)^2
Using the work-energy principle, we can equate the two expressions for work done and kinetic energy, that is:
force × 150 = 0.5 × mass × (final velocity)^2
Solving for force, we get:
force = 0.5 × mass × (final velocity)^2 / 150
Therefore, the resultant force on the aircraft as it accelerates is given by:
force = 0.5 × mass × (final velocity)^2 / 150
Note that we need to know the mass and final velocity of the aircraft in order to calculate the resultant force.