A suction line accumulator is used to ensure that liquid refrigerant enters the compressor.True or False

Answer:

A)

It should be Non- toxic

It should possess high Thermal conductivity

It should have the Required Thermal diffusivity

B)

C)   All the materials are suitable because they serve different purposes when making modern kitchen cookware

Explanation:

A) characteristics required of a ceramic material to be used as a kitchen cookware

B) comparison of three ceramic materials as to their relative properties

C) material most suitable for the cookware.

 All the materials are suitable because they serve different purposes when making modern kitchen cookware

Answer:

home,public,or private

Explanation:

Answer:

measures, dissolves, liquid, carbon dioxide, evaporates, water vapor, mold, decompose

Switching terminal screws on switches are always connected to the ungrounded conductor.

An electrical circuit can be defined as an interconnection of different electrical components, in order to create a pathway for the flow of electric current (electrons) due to a driving voltage.

In Electrical engineering, a switch can be defined as an electrical component (device) that is typically designed and developed for interrupting the flow of current or electrons in an electrical circuit.

This ultimately implies that, a switch that can open or close an electric circuit should always be connected to the underground conductor, in order to avert any form of hazard and as a safety precaution.

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Answer:

The exhaust is the major source of air pollution. This is composed of completely oxidized constituents such as H2O and CO2, both of which are considered harmless. Emphasis is placed on the partially oxidized components -- nitrogen oxide, carbon monoxide, and hydrocarbons -- as being the major pollutants.

Explanation:

Answer:

max temp = 711.32 k

mini temp = 331.29 k

Explanation:

Given data:

2kg block of Iron : temperature = 600k , C = 0.460 kJ/kgk

3 kg block of copper : temp = 800k ,  C = 0.385 KJ /kgk

10 kg block of granite : temp = 300k , C = 0.790 KJ/kgk

Cp = Cv at constant pressure and constant volume

Determine the minimum temperature that is obtained in any one of the block

considering the heat transfer equation

Q = mC ( T2 - T1 )

attached below is a detailed solution of the problem

Answer:

I think it's 23 ohms.

Explanation:

Not entirely sure about it.

hope this helps

Answer:

The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.

Explanation:

We must estimate the monthly storage change of the lake by considering inflows, outflows, seepage and evaporation losses and precipitation. That is:

\(\Delta V_{storage} = V_{inflow} -V_{outflow}-V_{seepage}-V_{evaporation}+V_{precipitation}\)

Where \(\Delta V_{storage}\) is the monthly storage change of the lake, measured in cubic feet.

Monthly inflow

\(V_{inflow} = \left(30\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)

\(V_{inflow} = 77.76\times 10^{6}\,ft^{3}\)

Monthly outflow

\(V_{outflow} = \left(27\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)

\(V_{outflow} = 66.98\times 10^{6}\,ft^{3}\)

Seepage losses

\(V_{seepage} = s_{seepage}\cdot A_{lake}\)

Where:

\(s_{seepage}\) - Seepage length loss, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{seepage} = 1.5\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{seepage} = (1.5\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{seepage} = 2.86\times 10^{6}\,ft^{3}\)

Evaporation losses

\(V_{evaporation} = s_{evaporation}\cdot A_{lake}\)

Where:

\(s_{evaporation}\) - Evaporation length loss, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{evaporation} = 6\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{evaporation} = (6\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{evaporation} = 11.44\times 10^{6}\,ft^{3}\)

Precipitation

\(V_{precipitation} = s_{precipitation}\cdot A_{lake}\)

Where:

\(s_{precipitation}\) - Precipitation length gain, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{precipitation} = 4.25\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{precipitation} = (4.25\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{precipitation} = 8.10\times 10^{6}\,ft^{3}\)

Finally, we estimate the storage change of the lake during the month:

\(\Delta V_{storage} = 77.76\times 10^{6}\,ft^{3}-66.98\times 10^{6}\,ft^{3}-2.86\times 10^{6}\,ft^{3}-11.44\times 10^{6}\,ft^{3}+8.10\times 10^{6}\,ft^{3}\)

\(\Delta V_{storage} = 4.58\times 10^{6}\,ft^{3}\)

The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.

The volume of water gained and the loss of water through flow,

seepage, precipitation and evaporation gives the storage change.

Response:

Given parameters:

Area of the lake = 525 acres

Inflow = 30 ft.³/s

Outflow = 27 ft.³/s

Seepage loss = 1.5 in. = 0.125 ft.

Total precipitation = 4.25 inches

Evaporator loss = 6 inches

Number of seconds in a month is found as follows;

\(30 \ days/month \times \dfrac{24 \ hours }{day} \times \dfrac{60 \, minutes}{Hour} \times \dfrac{60 \, seconds}{Minute} = 2592000 \, seconds\)

Number of seconds in a month = 2592000 s.

Volume change due to flow, \(V_{fl}\) = (30 ft.³/s - 27 ft.³/s) × 2592000 s = 7776000 ft.³

1 acre = 43560 ft.²

Therefore;

525 acres = 525 × 43560 ft.² =  2.2869 × 10⁷ ft.²

Volume of water in seepage loss, \(V_s\) = 0.125 ft. × 2.2869 × 10⁷ ft.² = 2,858,625 ft.³

Volume gained due to precipitation, \(V_p\) = 0.354167 ft. × 2.2869 × 10⁷ ft.² = 8,099,445.123 ft.³

Volume evaporation loss, \(V_e\) = 0.5 ft. × 2.2869 × 10⁷ ft.² = 11,434,500 ft.³

Which gives;

ΔV = 7776000 - 2858625 + 8099445.123 - 11434500 = 1582823.123

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Answer:

Both Tech A and Tech B are correct.

Explanation:

In order to ensure that some intake manifolds have coolant running through them to assist them to warm up and to also ensure that an electric heater grid is used in some intake manifolds to warm up the intake air, a preheat grid is positioned between the intake manifold and throttle body.

This therefore implies that both Tech A and Tech B are correct. That is, it is true that coolant circulates through some intake manifolds to ensure that they warm up. And it is also true that some intake manifolds use an electric heater grid to warm up the intake air. This however occurs when a preheat grid is positioned between the intake manifold and throttle body.

When the catalyst of a catalytic converter is contaminated with lead and silicone, then the converter must be typically B. Replaced

When the something which incites activity of a catalytic preacher is contaminated accompanying lead and lubricator, the preacher must typically be having another in its place.

Cleaning or fix the preacher by driving the car for an comprehensive occasion at freeway speeds is useless in killing these contaminators, and restoring the preacher by chastising some conditions that precipitated the adulteration is also strange expected direct in reversing the damage that has before happened approved.

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Centrifugal force is the force exerted on an object moving in a circular path and directed outward from the center. In order to determine the centrifugal force in pound-force of a centrifuge carrying 50mL of blood, we will need to use the formula for centripetal force:

Centrifugal force = (mass x acceleration)/radius

Here's how to solve the problem:

First, we need to determine the mass of the blood being carried by the centrifuge. We know the volume of blood (50 mL) and the density of blood (0.994 g/mL), so we can use the formula:

mass = volume x density

mass = 50 mL x 0.994 g/mL

mass = 49.7 g

Next, we need to convert the given units to SI units (meters and seconds):

Centripetal acceleration = 64 ft/s^2
1 ft = 0.3048 m
Centripetal acceleration = 64 ft/s^2 x 0.3048 m/ft = 19.5072 m/s^2

Rotational speed = 345 rpm
1 rpm = 1/60 s
Rotational speed = 345 rpm x 1/60 s = 5.75 s^-1

Now we can use the formula to calculate centrifugal force:

Centrifugal force = (mass x acceleration)/radius

The radius of the centrifuge is half the diameter (3.5 inches or 0.0889 meters):

Centrifugal force = (49.7 g x 19.5072 m/s^2)/0.0889 m

Centrifugal force = 10,879.52 N

Finally, we need to convert Newtons to pound-force:

1 N = 0.22481 lb-f
Centrifugal force = 10,879.52 N x 0.22481 lb-f/N

Centrifugal force = 2,442.69 lb-f

Therefore, the centrifugal force in pound-force is 2,442.69 lb-f.

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Answer: ⚠this is not my answer it from hamzaahmeds⚠

Water: h = 35.53 W/m².k

Engine oil: h = 18.84 W/m².k

Mercury: h = 1.19 W/m².k

Explanation:

Assuming the steady state, one-dimensional heat flow, it is clear that the added to the fluid by tube heat will be equal to the heat transfer through convection outside the tube.

Therefore,

mCΔT = hAΔT

mC = hA

h = mC/A

where,

h = convection coefficient

m = mass flow rate =  0.01 kg/s

C = specific heat capacity of fluid

A = surface area of tube = 2πrL = 2π(0.0125 m)(15 m) = 1.178 m²

FOR WATER:

C = 4186 J/Kg.k

Therefore,

h = (0.01 kg/s)(4186 J/Kg.k)/(1.178 m²)

h = 35.53 W/m².k

FOR ENGINE OIL:

C = 2220 J/Kg.k

Therefore,

h = (0.01 kg/s)(2220 J/Kg.k)/(1.178 m²)

h = 18.84 W/m².k

FOR LIQUID MERCURY:

C = 140 J/Kg.k

Therefore,

h = (0.01 kg/s)(140 J/Kg.k)/(1.178 m²)

h = 1.19 W/m².k

To reduce concerns that could further impair your machine, use the appropriate formulas and methods at every point in this process.

To create an overall ratio of 656:1, a three-stage compound spur gear train can be formed with specific ratios between the gears. These ratios are 4:1, 4:1, and 41:1.

The quantities that correspond to these gears are as followed:

- First stage - N1 = 16 teeth and pair with N2 which has 64 teeth

- Second stage - N3 = 64 teeth and pair with N4 which entails 256 teeth

- Third stage - N5= 41 teeth and collaborate with N6 which contains 1641 teeth.

After specifying all the individual tooth numbers for each gear, several calculations must be performed using mathematical formulas such as CR (Contact Ratio) and NP_min (Minimum number of teeth on the pinion).

Additionally, it is possible to find the pitch diameters for each gear pair by multiplying its corresponding standard module value 'm' by their respective tooth count (N).

The values placed in millimeters would then result in the following:

- Pitch diameter (First Stage Gears): D1 = 32mm, D2 = 128mm

- Pitch diameter (Second Stage Gears): D3 = 128mm, D4 = 512mm

- Pitch diameter (Third Stage Gears): D5 = 82mm, D6 = 3282mm.

In addition to finding out each gear's appropriate pitch diameter, we need to acquire information regarding two critical geometric parameters; Addendum and Dedendum.

Depending on the gear type, they may take unique forms, although for ordinary cylindrical gears, ha equals m whereas hd equal's 1.25m.

Exceptions do exist that change these individually. To increase both ease and efficiency, the Center Distance for every set must also be found.

- Center distance (Between First and Second Set): C12 = (D1+D2)/2 = 80mm

- Center distance (Between Second and Third Set): C34 = (D3+D4)/2 = 320mm

- Center distance (Betwen Third and Fourth Set): C56 = (D5+D6)/2 = 1682mm.

After properly investigating the previous variables, it is also conceivable to discover other details regarding this specific design. Contact Ratio denotes how often two teeth interact with one another throughout their life cycle while NP_min determines how many teeth are needed on a pinion for no snags to occur due to pressure variations. Finally, we determine NP_min by using the formula:

Np_min = 2*(1+sqrt(2/(2+2*sqrt(2)))*m) ≈ 12 teeth.

To reduce concerns that could further impair your machine, use the appropriate formulas and methods at every point in this process.

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In conclusion, Technician B is more correct than Technician A. While Technician A's statement is partially accurate, Technician B's statement better reflects the general control mechanism of fuel pumps in late-model vehicles.

Technician A and Technician B have different statements regarding the control of fuel pumps in vehicles.
Technician A states that on some vehicles, the fuel pressure is monitored by a fuel rail pressure sensor, and the output of the fuel pump is controlled by the Powertrain Control Module (PCM) through pulse-width modulation.
Technician B claims that all fuel pumps on late-model vehicles are controlled by the PCM based on inputs received on the Controller Area Network (CAN) bus and other specific sensors.
To determine who is correct, we need to evaluate both statements.
Technician A's statement is partially correct. Some vehicles do indeed have a fuel rail pressure sensor that monitors the fuel pressure. However, the claim that the output of the fuel pump is controlled by the PCM through pulse-width modulation is not universally applicable to all vehicles. While some vehicles may use this method, it is not the only way fuel pumps are controlled.
Technician B's statement is more accurate. Late-model vehicles typically rely on the PCM to control the fuel pump based on inputs received from various sensors, including those on the CAN bus. The PCM uses this information to regulate the fuel pump's operation.
In conclusion, Technician B is more correct than Technician A. While Technician A's statement is partially accurate, Technician B's statement better reflects the general control mechanism of fuel pumps in late-model vehicles.

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Incorrect result: (C) ?- bachelor(Who). Who = henry; Who = joe; false. The Option C.

The query bachelor(Who) is expected to find all individuals who are male and not married, providing their names as solutions. However, the incorrect result is obtained in this case.

The correct part of the result, Who = henry, is consistent with the knowledge base, as Henry is declared as a male and is not married. However, the incorrect part of the result, Who = joe, is unexpected. There is no mention of Joe in the knowledge base, so the query should not yield him as a solution.

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A drive axle is a split axle that has a differential between the two half axles and universal joints (UV joints). It refers to the axles or drive shafts of the car's driving wheels and is a crucial part of the drivetrain.

The drivetrain of a car could be the component with the least knowledge. This is caused by a number of things, including the frequent conflation of the terms "drivetrain," "powertrain," and "driveline."

The transmission, driveshaft, axles, and wheels make up the drivetrain. To put it simply, it assists the engine in moving the wheels. A vehicle's powertrain system is a crucial part, and the transmission is a crucial component of the drivetrain.

The drivetrain is made up of a number of parts that help a car move ahead by transferring power from the transmission to the wheels. The driveshaft, CV joints, differential, axle shafts, and U-joints are some of these parts.

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Answer:

this is the answer

Explanation:

this the summery about engineering

Some of the most commonly used chemical methods of sterilization are:

Sterilization is the process of eliminating or removing all forms of microbial life, including bacteria, viruses, fungi, and spores of nucleic acids. Chemical methods of sterilization use chemicals to kill or inactivate microorganisms.

Note also the use of Glutaraldehyde: This is a liquid sterilant that is effective against a wide range of microorganisms, including bacteria, viruses, and fungi. It is often used to sterilize heat-sensitive medical devices, such as endoscopes.

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Answer:

Agricultural engineer

Answer:

The correct response is "821.88". A further explanation is given below.

Explanation:

According to the question,

The largest amount unresolved after five years would have been:

= \(35000\times (\frac{F}{P}, 4 \ percent,5 )\)

= \(35000\times 1.216 7\)

= \(42584.50\)

Now,

time (t) will be:

= \(5\times 12\)

= \(60 \ monthly \ payments\)

So, monthly payment will be:

= \(42582.85\times (\frac{A}{P}, 0.5 \ percent,60 )\)

= \(42584.50\times 0.0193\)

= \(821.88\)

The system is operated at a feed rate of 15 × 10^(-3) m^3/h with an initial glucose concentration of 10 kg/m^3.

The steady-state mass balance for the reactor can be written as:

F = QX + Qs

where F is the feed rate, QX is the volumetric flow rate of cells, and Qs is the volumetric flow rate of glucose.

At steady-state, QX and Qs are constant. Therefore, we can write:

QX = F - Qs

In this case, the system is operated at a feed rate of 15 × 10^(-3) m^3/h with an initial glucose concentration of 10 kg/m^3.

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A hydraulic oil cooler, for instance, will remove heat from heated oil by utilizing cold water or air. A heat exchanger is a device that transfers heat from one medium to another.

Instead, a swimming pool The pool water is heated using a heat exchanger using hot water from a boiler or solar heated water circuit. Heat is transferred from one medium to another using heat exchangers. These media could be a gas, a liquid, or a mix of the two. The media may be in direct contact or separated from one another by a solid wall to prevent mixing. One typical illustration of a heat exchanger is the radiator in a car, where hot water used for engine cooling transmits heat to air passing through the radiator.

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Answer:

ESTABLISHED

Explanation:

What is TCP?

A Transmission Control Protocol (TCP) is a communication protocol which allows the exchange of data between computers in a network.  

When a Transmission Control Protocol connection is up and running meaning that both sides can send and receive data then the corresponding TCP socket states is known as "ESTABLISHED".

The most common socket states are:

LISTEN:

Before a TCP connection is made, there needs to be a server with a listener that will listen on incoming connection request.

ESTABLISHED:

When a TCP connection is up and running meaning that both sides can send and receive data.

CLOSED:

The CLOSED state means that there is no TCP connection.

There are a total of 11 TCP socket states:

1. LISTEN

2. SYN-SENT

3. SYN-RECEIVED

4. ESTABLISHED

5. FIN-WAIT-1

6. FIN-WAIT-2

7. CLOSE-WAIT

8. CLOSING

9. LAST-ACK

10. TIME-WAIT

11. CLOSED

RAM is called “random access” because any storage location on the computer can be accessed directly (as opposed to randomly).

The pedal does not push the master cylinder farther into the master cylinder bore.

What is the advantage of using a left foot?

The theory used in this question is the principle of using a left foot to apply pressure to the brake pedal while seating the brake pads. By using the left foot on the brake pedal while the right foot applies pressure, the technician is able to prevent the master cylinder from being pushed farther into the master cylinder bore.

The steps for this process are as follows:

1. Place the brake pads into the caliper.

2. Place the left foot on the brake pedal.

3. Use the right foot to apply pressure to the pedal, pushing it down slowly.

4. Allow the pressure from the left foot to prevent the master cylinder from being pushed farther into the master cylinder bore.

5. When the brake pads are seated correctly, release the pressure from the pedal.

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If a pilot-operated check valve (POC) does not check flow, you will see a. erratic actuator movement.

Pilot operated test valves paintings through permitting loose float from the inlet port via the opening port. Supplying a pilot strain to the pilot port permits float withinside the contrary direction. Air strain on pinnacle of the poppet meeting opens the seal permitting air to float freely.

An actuator fault is a form of failure affecting the machine inputs. Due to strange operation or fabric aging, actuator faults might also additionally arise withinside the machine. An actuator may be represented through additive and/or multiplicative fault.

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Answer:

First, we need to calculate the volume of concrete needed to line the canal. The volume of a cylinder is given by the formula:V = πr^2hWhere V is the volume, r is the radius of the cylinder, and h is the height (length) of the cylinder.Since we are lining a canal, the cross-sectional shape of the canal is a rectangle, not a circle. However, we can still use the formula for the volume of a cylinder by treating the width of the canal as the radius and the height of the canal as the length.In this case, the width of the canal is w and the height is h, so the volume of the concrete needed to line the canal is:V = πw^2hWe are given that the length of the canal is 227 ft, so h = 227 ft. We are not given the width of the canal, so we cannot use the formula to calculate the volume of concrete needed.Next, we need to calculate the volume of concrete needed with the 12% allowance for waste and overexcavation. The volume of concrete needed with the allowance is the original volume plus 12% of the original volume.The volume of concrete needed with the allowance can be calculated using the following formula:V' = V + (V * 12%)Where V' is the volume of concrete needed with the allowance and V is the original volume.Since we do not know the original volume, we cannot use this formula to calculate the volume of concrete needed.To solve this problem, we need to know the width of the canal in order to calculate the volume of concrete needed. Without this information, it is not possible to determine the volume of concrete that must be delivered.

Explanation:

Answer: 0

Explanation: i need to add it up to get what u want