A sulfide of gold is composed of 6.462 g of sulfur and 25.06 g of gold. calculate the percent of both elements in the compound.

The experiment that is reference above is Copper Wire in a Solution of Silver Nitrate. The color of the solution changes to from clear to blue because Copper is oxidizing and forming copper(II) ions, which have a blue color in solution.

Oxidation is a process that happens when certain materials interact with oxygen or other substances.

It can make things change color, rust, or even burn. It's like when an apple turns brown when exposed to air. Oxidation can happen slowly over time or quickly in a chemical reaction.

Because oxidation and reduction always occur together in a redox reaction, with one species losing electrons and another acquiring those electrons, the overall balance of electrons and charge in the reaction is maintained.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

The experiment is called "Copper Wire in a Solution of Silver Nitrate.

13. What caused the color that you observed in the 150-mL beaker as the experiment proceeded?

A circumpolar animal dwells at the poles.

Animals are found in different areas. The areas that are inhabited by an animal is called the habitat of the animal. Different animals have different habitats.

However, the animals that are found around the poles are said to be circumpolar. In nutshell, a circumpolar animal dwells at the poles.

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Answer:

it should be +0.46 :)

Explanation:

I just took the test and got it right.

Answer:

I think it's +1.14 V, but don't take my word for it..

Answer:

Carbon and Hydrogen

Explanation:

So the C stands for Carbon and H is for Hydrogen. Methane (CH4) is made up of one atom of Carbon and 4 atoms of Hydrogen.

Hope this helps

Answer:

Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products.

A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Chemical reactions are an integral part of technology, of culture, and indeed of life itself. Burning fuels, smelting iron, making glass and pottery, brewing beer, and making wine and cheese are among many examples of activities incorporating chemical reactions that have been known and used for thousands of years. Chemical reactions abound in the geology of Earth, in the atmosphere and oceans, and in a vast array of complicated processes that occur in all living systems.

Explanation:

hope it help

plss brainlys me

Answer:

Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products

Explanation:

Substances are either chemical elements or compounds. A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Answer:

334.7g of Calcium Hydroxide are needed

Explanation:

Based on the reaction:

2Ca(OH)2 + 2Cl2 → Ca(ClO)2 + CaCl2 + 2H2O

2 moles of chlorine react with 2 moles of calcium hydroxide.

To solve this question we must find the moles of chlorine in 300.0g. These moles = Moles of Ca(OH)2. With the moles of calcium hydroxide we can find its mass as follows:

Moles Cl₂ (Molar mass: 70.90g/mol)

300.0g Cl₂ * (1mol / 70.90g) = 4.2313 moles Cl₂ = Moles Ca(OH)₂

Mass Ca(OH)₂ (Molar mass: 74.093g/mol)

4.2313 moles Ca(OH)₂ * (74.093g / mol) =

Thermolysis, photolysis, and electrolysis are three different forms of breakdown reactions. A single source was cooked to yield two or more objects in each instance (decomposition).

Decomposition reactions happen when complex chemical entities split apart into smaller components. Decomposition reactions often demand energy input. For instance, the thermal breakdown of potassium hydroxide (KClO3) is a typical technique used during laboratories to generate oxygen gas.

Below is a typical illustration of a thermal breakdown reaction. Calcite breaks down into calcareous dioxide and atmospheric co2 when heated. The production of quick lime, a crucial component in numerous industries, uses this procedure.

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Answer:

This question appears incomplete

Explanation:

This question appears incomplete because of the absence of options. However, hydrogen is placed in group 1 because it has just one electron in it's outermost shell (which happens to be the only shell it has) just like every other group 1A/group 1 element. While helium is placed in group 8A/group 18 because it has a completely filled outermost shell (which is also the only shell it has) just like every other element in group 8A/group 18.

In the periodic table hydrogen is placed in Group 1A (group 1) and helium is placed in Group 8A (group 18). The most likely reason for this is configuration, energy level and properties.

Hydrogen is located in group 1 of the periodic table, although its electronic configuration is 1s¹ and its properties do not correspond to those of the alkali metals of that group. But in its electronic configuration you can see that it has only one electron in its outermost shell (which turns out to be the only shell it has), just like any other element of group 1A /group 1, so it is located in that group.

On the other hand, although the electronic configuration of helium is 1s², this element does not appear in group 2 of the periodic table of elements, but is placed in group 18. This is because it has the energy level complete, so it has the properties of a noble gas, that is, it is inert (it does not react), and it is a colorless and odorless monatomic gas.

In summary, in the periodic table hydrogen is placed in Group 1A (group 1) and helium is placed in Group 8A (group 18). The most likely reason for this is configuration, energy level and properties.

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5g of LiCl is dissolved in 40 ml of water at 17°C. When the temperature of a solution rises to 40.3°C, the molar heat of a LiCl solution is 32.7 kJ/mol.

The molar heat of a solution(ΔH) is calculated by the formula

ΔH=q/n

Where, n-Number of moles

q- Energy of the system

q is calculated by the formula

q=m×c×ΔT

Where ΔT=(T_f-T_i)

T_f=40.3°C, T_i=17°C

ΔT=(40.3-17)°C=23.3°C

c=4.18 J/g°C

The mass of water is

m=40 ml×(1 g/1 ml)=40 g

Plug all values in the formula

q=40g×(4.18 J/g°C)×23.3°C

q=3895.76 J

The molar mass of LiCl is 42g/mol. Therefore, the moles of LiCl is

moles=5g×(1 mol/42 g)

moles=0.11905 mol

Hence, the molar heat of a solution is

ΔH=3895.76 J/0.11905 mol

ΔH=32723.7295 J/mol

Convert the value in kJ

ΔH=32723.7295 J/mol×(1 kJ/1000 J)

ΔH=32.7 kJ/mol

Therefore, the molar heat of a solution is 32.7 kJ/mol.

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Fog remains suspended in the air because they are supported by slight movement in the air

If the air near the ground cools down enough and is humid and light wind (stable), water vapour in the air may condense into minute water droplets. Near ground level, these raindrops make it harder to see. Fog is the term for the phenomenon.

Fog is defined as "air that is near to the surface and contains suspended water droplets, typically generated by diabatic cooling" in Understanding Weather and Climate.

When the air close to the ground cools down sufficiently, the water vapor condenses into liquid water or ice, creating fog. Fog comes in a wide variety of forms. When the air close to the ground is chilly enough, ice fog develops.

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Minerals, water, and forests are all part of the broad resource category known as natural resources. Natural resources are materials or substances that exist in nature and can be used by humans for various purposes. They are essential for the survival and well-being of both individuals and societies.

1. Minerals: These include precious metals like gold and silver, as well as common minerals like iron, copper, and coal. Minerals are extracted from the earth and used in industries such as construction, manufacturing, and energy production.

2. Water: Water is a vital natural resource that is necessary for all forms of life. It is used for drinking, agriculture, industrial processes, and generating electricity. Water scarcity is a global concern, making the conservation and efficient use of this resource crucial.

3. Forests: Forests provide a wide range of resources, including timber for construction and fuel, as well as non-timber products like fruits, nuts, and medicinal plants. Forests also play a crucial role in maintaining biodiversity, regulating climate, and preserving ecosystems.

These resources are finite and require careful management to ensure their sustainability for future generations. By understanding the importance of these natural resources and implementing sustainable practices, we can ensure their availability and protect the environment.

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Minerals, water, and forests are all considered to be part of the broad resource category known as natural resources.

The existence of life on Earth depends on the availability of natural resources, which are elements or chemicals that occur naturally in the environment. First and foremost, natural resources give us the components we need to satisfy our most fundamental requirements. For instance, water is a crucial resource that is essential for preserving ecosystem balance, drinking, and irrigation. Forests and other plants also provide humans with oxygen, stop soil erosion, and provide home for a variety of animals.

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Answer:

C. Lower Electronegativity

Periodic table is divided into metals, non metals, semiconductors and noble gases on the basis of electron gain or loss. Metals have lower electronegativity. The correct options is option C.

Metals are those elements which is hard, conduct electricity, ductile, lustrous and malleable.

Lets take properties

1.Since metals have free electrons that's why they can conduct electricity.

2. Since atoms in metals are very closely packed in a definite crystal so these are solid. Metals are not brittle that is, it can not be broken down easily

3.Metals  do not react with water easily.

4.Metals are denser than water hence sink in water.

5. Metals are meant to give electrons so these have low ionization energy. and lower electronegativity.

6. Metals form basic form of oxide.

7. Metals have lower electron shielding.

Therefore the correct options is option C.

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Answer:

150

Explanation:

300 divided by 2

Scientist mean when he or she says an object is at rest then the object is not moving relative to its surroundings

Velocity of the object is said to be uniform when its speed and direction does not change and the object at rest has uniform speed of zero all the time and does not even change the direction and when object is at rest position then the velocity is zero such an object will not change its state of motion that's why when he or she says an object is at rest the scientist says that the object is not moving relative to its surroundings

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The number of dilutions required to reach 2.5% as the final concentration would be 2.

Any dilution in which the concentration is reduced by the same amount in each subsequent stage is referred to as a serial dilution.

In serial dilutions, the original volume divided by the final amount is known as the dilution factor.

\(DF = \frac{V_i}{V_f}\)

Now we are given that we must do 50% serial dilution, which indicates that the concentration must be reduced to half of its starting value after each dilution.

∴ \(DF=\frac{10}{50}\) × \(100\)

DF = 2

This indicates that starting with a 10% concentration, a single dilution would result in a 5% concentration. And again diluting this 5% concentration would result in a 2.5% concentration.

Hence, the number of dilutions required to reach 2.5% as the final concentration would be 2.

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Answer:

what is the question?

.........

Explanation:

.....................

A conjugate acid-base pair is composed of two species that are related to each other through the transfer of a proton. In this case, the species that can donate a proton is called the acid, and the species that can accept a proton is called the base.

Therefore, the conjugate acid-base pairs are as follows:
- HNO3 / NO3- : Nitric acid (HNO3) is the acid that donates a proton, while nitrate ion (NO3-) is the base that accepts a proton. Thus, they form a conjugate acid-base pair.
- H3O+ / OH- : Hydronium ion (H3O+) is the acid that donates a proton, while hydroxide ion (OH-) is the base that accepts a proton. Thus, they form a conjugate acid-base pair.
- H2SO4 / SO42- : Sulfuric acid (H2SO4) is the acid that donates a proton, while sulfate ion (SO42-) is the base that accepts a proton. Thus, they form a conjugate acid-base pair.
- H3PO4 / HPO42- : Phosphoric acid (H3PO4) is the acid that donates a proton, while hydrogen phosphate ion (HPO42-) is the base that accepts a proton. Thus, they form a conjugate acid-base pair.
In summary, all of the given options are conjugate acid-base pairs.

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Hydrogen is the chemical element that is placed separately from the other elements because it has atomic number 1.

It is the simplest chemical element (consisting of only one proton and one electron) with atomic number 1.

It is the lightest of the elements and the most abundant in the universe and in the earth's crust,  in the atmosphere, hydrogen is found as a colorless, odorless and flammable gas, in its molecular form H2.

Therefore, we can conclude that Hydrogen is the chemical element that is placed separately from the other elements because it has atomic number 1.

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The rate law for the reaction between iodide ion and dibromothane (C₂H₄Br₂) in methanol is determined to be Rate = k[C₂H₄Br₂][I], indicating that the reaction is first-order with respect to both reactants.

The rate constant (k) for the reaction is calculated to be approximately 4.88 M⁻¹s⁻¹ using the initial rate data from Experiment 1.

The rate of consumption of iodide ion (I) is estimated to be around 1.79 M/s when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M.

The activation energy (Ea) for the reaction is found to be approximately 51.3 kJ/mol using the Arrhenius equation and temperature data from Experiment 4.

To determine the rate law, we need to examine how the initial rates change with respect to the initial concentrations of the reactants. Let's consider the first experiment (Experiment 1) and compare it with the other experiments:

Experiment 1: [C₂H₄Br₂]₀ = 0.127 M, [I]₀ = 0.102 M, Initial rate = 6.45x10⁻² M/s

Experiment 2: [C₂H₄Br₂]₀ = 0.254 M (2 * [C₂H₄Br₂]₀), [I]₀ = 0.127 M (2 * [I]₀), Initial rate = 0.102 M/s (2 * Initial rate)

Experiment 3: [C₂H₄Br₂]₀ = 0.204 M (1.6 * [C₂H₄Br₂]₀), [I]₀ = 1.29x10⁻² M (0.126 * [I]₀), Initial rate = 0.204 M/s (3.16 * Initial rate)

From the comparisons above, we can see that doubling the initial concentrations of both reactants (Experiment 2) doubles the initial rate, indicating that the reaction rate is first-order with respect to both [C₂H₄Br₂] and [I].

The rate law for the reaction can be expressed as:

Rate = k[C₂H₄Br₂]ᵃ [I]ᵇ

Since the reaction is first-order with respect to both reactants, we have a = 1 and b = 1.

Therefore, the rate law for the reaction is:

Rate = k[C₂H₄Br₂][I]

To determine the rate constant (k), we can choose any of the experiments and use the given data. Let's use Experiment 1:

[C₂H₄Br₂]₀ = 0.127 M

[I]₀ = 0.102 M

Initial rate = 6.45x10⁻² M/s

Plugging these values into the rate law equation, we can solve for k:

6.45x10⁻² = k(0.127)(0.102)

k = 6.45x10⁻² / (0.127)(0.102)

k ≈ 4.88 M⁻¹s⁻¹

So, the rate constant for the reaction is approximately 4.88 M^(-1)s^(-1).

Now, to determine the rate of consumption of iodide ion (I) when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M, we can use the rate law:

Rate = k[C₂H₄Br₂][I]

Plugging in the given concentrations and the rate constant we just determined:

Rate = (4.88 M^(-1)s⁻¹)(0.74 M)(0.52 M)

Rate ≈ 1.79 M/s

Therefore, the rate of consumption of iodide ion when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M is approximately 1.79 M/s.

The Arrhenius equation is given as:

k = Ae^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin.

From the given data, we have:

Experiment 1: T = 20°C = 293 K

Experiment 2: T = 20°C = 293 K

Experiment 3: T = 20°C = 293 K

Experiment 4: T = 40°C = 313 K

Let's consider Experiment 1:

[C₂H₄Br₂]₀ = 0.127 M

[I]₀ = 0.102 M

Initial rate = 6.45x10⁻² M/s

We can rearrange the rate law equation to solve for the pre-exponential factor (A):

A = k / ([C₂H₄Br₂]₀[I]₀)

Plugging in the values for Experiment 1:

A = (4.88 M⁻¹s⁻¹) / (0.127 M * 0.102 M)

A ≈ 37.80 s⁻¹

Now, we can use the Arrhenius equation with Experiment 4 to determine the activation energy (Ea):

k = Ae^(-Ea/RT)

Rearranging the equation:

ln(k) = ln(A) - (Ea/RT)

Taking the natural logarithm of the rate constant from Experiment 4:

ln(k) = ln(1.79 M/s)

Substituting the values into the equation:

ln(1.79 M/s) = ln(37.80 s^(-1)) - (Ea / (8.314 J/(mol·K) * 313 K))

Simplifying the equation:

ln(1.79) = ln(37.80) - (Ea / (8.314 * 313))

Now, solve for Ea:

Ea = -(ln(1.79) - ln(37.80)) * (8.314 * 313)

Ea ≈ 51,253 J/mol or 51.3 kJ/mol

Therefore, the activation energy for this reaction is approximately 51.3 kJ/mol.

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Answer:

The are we made of matter?

C. Decreasing the temperature

D. Raising the pressure​

Given

Reaction

2SO₂+O₂⇔2SO₃+energy

Required

Changes to  the formation of products

Solution

The formation of SO₃ is an exothermic reaction (releases heat)

If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)  

While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient  

in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2

As the temperature decreases, the equilibrium will shift towards the exothermic reaction, so the reaction shifts to the right towards SO₃( products-favored)

And increasing the pressure, then the reaction shifts to the right SO₃( products-favored)⇒the number of coefficients is greater

Answer:

C. Decreasing the temperature

D. Raising the pressure​

Explanation:

A.P.E.X

Answer:B

Explanation:

False

complete combustion produces carbon dioxide + water

The balance and net ionic equation are;

1. Ca (s) + Br2 (l) → CaBr2 (s)

2. HNO3 (aq) + BaCl2 (aq) → Ba(NO3)2 (aq) + 2HCl (aq)

3. C7H16 (l) + 11O2 (g) → 7CO2 (g) + 8H2O (l)

4. balanced equation:Cl2 (g) + 2KI (aq) → 2KCl (aq) + I2 (s),

Net ionic equation:

Cl2 (g) + 2I- (aq) → 2Cl- (aq) + I2 (s)

5. Zn (s) + Ca(NO3)2 (aq) → No reaction (since Ca is less reactive than Zn)

6. 2Na3PO4 (aq) + 3Mg(NO3)2 (aq) → Mg3(PO4)2 (s) + 6NaNO3 (aq)

Net ionic equation: 2PO4^3- (aq) + 3Mg^2+ (aq) → Mg3(PO4)2 (s)

7. 2Al (s) + 3ZnCl2 (aq) → 2AlCl3 (aq) + 3Zn (s)

8. 2Fe2O3 (s) → 4Fe (s) + 3O2 (g)

9. Balanced equation: LiOH (aq) + HCl (aq) → LiCl (aq) + H2O (l)

Net ionic equation: OH- (aq) + H+ (aq) → H2O (l)

10A. Solid sodium in water.

2Na (s) + 2H2O (l) → 2NaOH (aq) + H2 (g)

10B. What would happen if you bring a burning splint to the previous reaction?

10 C - The burning splint would go out (since the H2 produced in the reaction may ignite and cause a "pop" sound, but the burning splint itself would go out).

A balanced equation is a chemical equation with equal numbers of atoms for each element on both sides, following the law of conservation of mass.

A net ionic equation is a simplified version of a balanced equation that only shows species participating in the reaction as ions, excluding spectator ions that remain unchanged throughout the reaction. This highlights the actual chemical changes occurring in the reaction.

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The electrons that are shared, lost, or gained are called valence electrons. The charge an ion will have after gaining or losing electrons is indicated by the oxidation number.

According to the octet rule, elements interact with one another to form a noble gas electron configuration by either gaining electrons or losing them. The number of electrons in an element's outermost shell is known as its valency, whereas the number of electrons an element has gained or lost in a compound is known as its oxidation state. The primary distinction between valency and oxidation state is this. Each shell can hold a maximum of half the number of elements in the corresponding period in terms of electrons.

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Answer:

semiconductors

Explanation:

Answer: Semiconductors

Explanation:

Answer:

210 grams

Explanation:

just add them all up

Answer:

Calcium has a smaller radius in comparison to Potassium.

Explanation:

When we move down a group, the atomic radius increases, and when we move from left to right in a period, the atomic radius decreases. Since both Potassium and Calcium are in the 4th period, we have to look left to right. Calcium is to the right of Potassium making the radius smaller.