A super rocket car traverses a straight track 2.10 x 10 m long in 1.00 x 10-s as measured by an observer next to the track. 1. How much time At clock elapses on a clock in the rocket car during the run? At clock = 2. What is the distance L driver traveled in traversing the track as determined by the driver of the rocket car? L driver =
Answers
The clock in the rocket car will not show any time elapsed during the run and the distance traveled by the driver of the rocket car is 2.11 x 10 m.
For the first question, we know that the distance traveled by the rocket car is 2.10 x 10 m and the time measured by the observer next to the track is 1.00 x 10^-s. To find the time elapsed on the clock in the rocket car, we need to use the time dilation equation:
Δt' = Δt/√(1 - v²c²)
where Δt is the time measured by the observer, v is the velocity of the rocket car, and c is the speed of light.
Since the rocket car is moving very fast, we can assume that v ≈ c. Therefore, the equation becomes:
Δt' = Δt/√(1 - 1)
= Δt/0
= ∞
This means that the clock in the rocket car will not show any time elapsed during the run, as time dilation causes time to slow down as velocity approaches the speed of light.
For the second question, we can use the distance formula:
d = vt
where d is the distance traveled, v is the velocity of the rocket car, and t is the time elapsed on the clock in the rocket car.
From the first question, we know that Δt' = ∞, which means that
t = Δt' + 1.00 x 10^-s = ∞. Therefore, we cannot use this equation to find the distance traveled by the driver.
Instead, we can use the Lorentz transformation formula:
L' = γ(L - vt)
where L' is the distance measured by the observer, v is the velocity of the rocket car, and γ is the Lorentz factor, given by:
γ = 1/√(1 - v²/c²)
Substituting the given values, we get:
γ = 1/√(1 - (v/c)²)
= 1/√(1 - (2.10 x 10/1.00 x 10^-s)²/(3.00 x 10^8 m/s)²)
= 1.007
L' = 2.10 x 10 m
v = L/Δt' = L/∞ = 0 m/s
Substituting these values, we get:
L driver = γ(L - vt)
= 1.007(2.10 x 10 m - 0 m/s x ∞)
= 2.11 x 10 m
Therefore, the distance traveled by the driver of the rocket car is 2.11 x 10 m.
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Related Questions
what is importance of measurment in our daily life ?
Answers
Measurement tools improve the quality and quantity of our lives by making them easier and safer. The ability to precisely quantify physical qualities has arguably enormous survival value, providing humans with an adaptive, evolutionary advantage refined over thousands of years of natural selection.
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according to the universal law of gravitation, the force due to gravity is:____.
Answers
According to the universal law of gravitation, the force due to gravity is directly proportional to the product of the masses of two objects and inversely proportional to the square of the distance between them.
Explain universal law of gravitation?The force of attraction between two objects caused by their masses is described by the universal law of gravitation, a physical principle put forth by Sir Isaac Newton. This law states that every particle of matter attracts every other particle in the cosmos with a force that is directly proportional to the product of their masses and inversely proportional to the square of their separation.
The equation provides the law's mathematical expression:
F = G * (m1 * m2) / r^2
Where r is the distance between the centers of the two objects, m1 and m2 are their masses, and G is the gravitational constant.
The gravitational constant is a fundamental constant of nature that has a value of approximately 6.674 x 10^-11 Nm^2/kg^2.
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A long, hollow wire has inner radius R1 and outer radius R2. The wire carries current I uniformly distributed across the area of the wire.a) Use Ampere's law to find an expression for the magnetic field strength in the region 0
Answers
The magnetic field strength B in the region 0 < r < R1 is B = (μ₀I * r) / (2π * (R2² - R1²)), and in the region R1 < r < R2 is B = (μ₀I * (R2² - r²)) / (2π * r * (R2² - R1²)).
To find the magnetic field strength, we can use Ampere's law, which states that the line integral of the magnetic field B around a closed loop equals μ₀ times the current enclosed by the loop.
For the region 0 < r < R1, consider a circular Amperian loop of radius r inside the wire.
Applying Ampere's law and solving for B, we obtain B = (μ₀I * r) / (2π * (R2² - R1²)).
For the region R1 < r < R2, consider a circular Amperian loop of radius r that encloses the entire inner radius.
Applying Ampere's law and solving for B in this case, we obtain B = (μ₀I * (R2² - r²)) / (2π * r * (R2² - R1²)).
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Which nucleus completes the following equation?
Cle+?
OA. S
OB. S
16
OC. Ar
18
OD. 39 y
18
Answers
The equation below is completed by the chromium nucleus.
Where can one locate chrome?Chromium is mostly found in chromite. The locations where this ore can be found include South Africa, India, Kazakhstan, and Turkey. In an electric arc furnace, chromite is often reduced with carbon to generate chromium metal, as is chromium(III) oxide when it is reduced with silicon or aluminum.
Why is chromium necessary?An important mineral called chromium helps insulin work properly in the body by regulating blood sugar levels. Your body uses the hormone insulin to convert sugar, starchy carbs, and other foods into the energy you require for daily activities.
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Write your views on pyramid.
=> No copy Paste
=> Conspiracy theories are accepted
Answers
Answer:
pyramid is a body or structure whose outer surfaces are triangular and converge to a first step at the the top which base may be in a shape of triangle ,rectangle,square and other any shape.
Explanation:
its volume is equal to product of area of base and height of it..
the lateral surface area of a regular pyramid is equal to the sum of the areas of its lateral faces.
the total surface area of a regular pyramid is equal to the sum of the lateral surface areas of pyramid and base.
Answer:
A pyramid is a polyhedron for which the base is a polygon and all lateral faces are triangles. A pyramid is described by the shape of its base . for example , a triangular pyramid has a triangular base , square pyramid has a square base .hope it is helpful to you
3. Since Aspeon is not expected togrow, Emily believes that the following equations can be used in the valuation analysis: (1) S=[EBIT−kd(D)](1−ks)
(2) V=S+D
(3) P=(V−D0)/n0
(4) n1=n0−D/P
(5) VL=VU+TD
Answers
The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:
1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.
2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.
3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.
4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.
5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.
These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.
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The Hall voltage across a conductor in a 55.0 mT magnetic field is 1.90 mV. When used with the same current in a different magnetic field, the voltage across the conductor is 2.80 mV. What is the strength of the second magnetic field?
Answers
To solve this problem, we can use the formula for Hall voltage:
V_H = (IB)/ne
where V_H is the Hall voltage, I is the current, B is the magnetic field strength, n is the number of charge carriers per unit volume, and e is the charge of each carrier.
We can rearrange this formula to solve for the magnetic field strength:
B = (V_H * ne)/I
Using the given values for the Hall voltage, current, and magnetic field strength in the first scenario, we can calculate n*e/I:
n*e/I = V_H/B = 1.90 mV / 55.0 mT = 0.0347
Now, we can use this value along with the Hall voltage and current in the second scenario to solve for the magnetic field strength:
B = (V_H * ne)/I = (2.80 mV) * (0.0347) / I
We don't know the current, but we do know that it's the same in both scenarios. Therefore, we can set the two expressions for B equal to each other:
(V_H1 * ne)/I = (V_H2 * ne)/I
Simplifying and solving for I:
I = ne * (V_H1 / V_H2) * I
I cancels out, leaving us with:
ne * (V_H1 / V_H2) = 0.0347
Plugging in the given values:
0.0347 = (1.90 mV / 2.80 mV) * n*e/I
Simplifying and solving for n*e/I:
n*e/I = 0.0252
Finally, we can use this value to solve for the magnetic field strength in the second scenario:
B = (V_H * ne)/I = (2.80 mV) * (0.0252) / I
Again, I cancels out, leaving us with:
B = 0.185 T
Therefore, the strength of the second magnetic field is 0.185 T.
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Please help me
Thank you!
Answers
Answer:
29.436 J/g.°C
Explanation:
We are given;
Mass of tungsten; m_t = 215 g
Initial temperature of tungsten; T_ti = 100°C
Final temperature; T_f = 21.5°C
Mass of water; m_w = 450 g
Initial temperature of water; T_tw = 20°C
From tables, specific heat capacity of water; c_w = 4.184 J/g.C
Thus;
Energy lost by tungsten = energy gained by water
Thus;
215 × c_t × (100 - 21.5) = 450 × 4 184 × (21.5 - 20)
Where c_t is specific heat capacity of tungsten
16877.5c_t = 496800
c_t = 496800/16877.5
c_t = 29.436 J/g.C
the secondary atmosphere of the earth was composed mainly of
Answers
A copper sphere with density 8900 kg/m3, radius 5. 00 cm, and emissivity e = 1. 00 sits on an insulated stand. The initial temperature of the sphere is 300 K. The surroundings are very cold, so the rate of absorption of heat by the sphere can be neglected.
a. How long does it take the sphere to cool by 1. 00 K due to its radiation of heat energy? Neglect the change in heat current as the temperature decreases.
b. To assess the accuracy of the approximation used in part A, what is the fractional change in the heat current H when the temperature changes from 300 K to 299 K?
Answers
a.The time it will take the sphere to cool by 1. 00 K due to its radiation of heat energy is 3225s.
b. The fractional change in the heat current H when the temperature changes from 300 K to 299 K is 3.18 %.
(a) The rate of cooling of a copper sphere is given by Newton's law of cooling, i.e.,
H = kA(Ts - T0),
where k is the heat-transfer coefficient, A is the surface area of the sphere, Ts is the temperature of the surroundings, and T0 is the temperature of the sphere.
Since the surroundings are very cold, Ts can be taken to be zero.The heat transfer coefficient k depends on the emissivity e of the sphere and is given by:
k = σeA,
where σ is the Stefan-Boltzmann constant.
The surface area A of the sphere is:
A = 4πr²,
where r is the radius of the sphere.
The heat transfer coefficient k is therefore k = 4πr²σe.
Substituting the values of the parameters for the copper sphere in the above equations, we get
k = 4π(0.05 m)²(5.67 × 10^-8 W/m²K⁴)(1) = 0.0562 W/m²K⁴
H = kA(Ts - T0) = 0.0562(4π(0.05 m)²)(300 K - 0) = 1.41 W.
The rate of cooling of the sphere is therefore 1.41 W.
The heat capacity C of the sphere is given by
C = mCp,
where m is the mass of the sphere and Cp is the specific heat capacity of copper.
The mass of the sphere is m = (4/3)πr³ρ= (4/3)π(0.05 m)³(8900 kg/m³) = 0.0118 kg
The specific heat capacity of copper is Cp = 385 J/kgK.
The heat capacity of the sphere is therefore
C = 0.0118 kg × 385 J/kgK = 4.54 J/K.
The time Δt taken for the sphere to cool by ΔT = 1.00 K is given by
Δt = ΔQ/H = CΔT/H = (4.54 J/K)/(1.41 W) ≈ 3225s.
(b) The fractional change in the heat current H when the temperature changes from 300 K to 299 K is given by
ΔH/H = (dH/dT)ΔT/H,
where ΔT is the change in temperature and dH/dT is the rate of change of the heat current H with temperature.
To find dH/dT, we differentiate the equation
H = kA(Ts - T0) with respect to T and get dH/dT = -kA = -4πr²σe.
Substituting the values of the parameters for the copper sphere, we get
dH/dT = -4π(0.05 m)²(5.67 × 10^-8 W/m²K⁴)(1) = -0.0449 W/K/m².
The fractional change in the heat current is therefore:
ΔH/H = (dH/dT)ΔT/H = (-0.0449 W/K/m²)(-1 K)/(1.41 W) = 0.0318 or 3.18%.
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The following conversion equivalents are given: 1.0 m = 100 cm 1.0 in = 2.54 cm 1.0 ft = 12 in if a bin has a volume of 1.5 m3, the volume of the bin, in ft3, is closest to?
Answers
The volume of the bin in ft^3 is determined as 53 ft3
CalculationGiven,
1m = 100cm ⇒ 1cm = \(10^{-2}\)
1in = 2.54 cm = 2.54 x \(10^{-2}\) m
1ft = 12in = 12 x 2.54 x \(10^{-2}\) = 30.48 x \(10^{-2}\) m
⇒ 1m = 1/30.48 x \(10^{2}\) ft
Volume = 1.5\(m^{3}\)
= 1.5 x \((1m)^{3}\)
= 1.5 x (1/30.48 x \(10^{2}\) ft)^3
= 52.97ft^3
V= 53 ft^3 (nearly)
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Camille knows that range of motion is very important. She is designing a weekly exercise program and is not sure where flexibility fits in. What
type of exercise will BEST allow her to work on range of motion?
O A.
aerobic
B. balance
C. flexibility
D. strength training
Answers
The best activity for her to do to improve her range of motion is flexibility.
What are a few range of motion illustrations?The term the range of motion (ROM) describes the extent to which a joint or muscle may be moved or stretched. Everybody has a distinct experience. For instance, whereas some people can perform a complete split, others cannot because their joints are stiff and their muscles are unable to extend as far.
What restricts motion range?A joint is said to have a restricted range of motion when it cannot move easily and completely in its typical position. A mechanical issue within the joint, swollen tissues around the joint, or pain may restrict motion.
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Which of the following graphs represent an object at rest? (There could be more than one correct cho 0' 0' 0 0 graph a graph b graph c graph d
Answers
Graph A, because distance-time graph is a straight line parallel to the time-axis because the position of the object does not change when it is at rest.
Distance is the length between two points or items, and it is directionless. Since distance is a scalar attribute, it only takes into account the overall magnitude and ignores the start and end locations. Being a scalar attribute, distance may only be positive or zero; it cannot be the opposite.
Although kilometers (km) and centimeters (cm) or millimeters (mm) can also be used to express shorter distances, the meter (m) is the most used unit of measurement for distance (mm). When calculating distance, the letter D is usually used to denote the distance traveled.
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An object moves in a circular path at a constant speed. What is the direction of the net force acting on the object?.
Answers
Answer:
The net force is directed toward the center of the circular path.
A man drives south to work every day. If his 55 mile
commute usually takes 0.75 hours, what is his average velocity?
Answers
Answer:
73.34 mph to 2dp
Explanation:
veolcity = distance/ time
55 / 0.75 = 73.34 mph
An object moving at a constant velocity of 5.4 m/s travels for 12 s. How far will it move during that time?
Answers
Answer:
Explanation:
we know that
s=vt
given
v=5.4 m/s
t=12 s
s=5.4 m/s*12 s=64.8m
At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is about 100 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron in this environment, assuming that the electron has an instantaneous velocity of 8.50 ✕ 106 m/s directed to the east.
Answers
Answer:
A) F_g = 8.9278 × 10^(-30)
B) F_e = 1.6 × 10^(-17) N upwards
C) F_m = 6.8 × 10^(-17) N downwards
Explanation:
A) Formula for gravitational force is;
F_g = m_e × g
m_e is mass of electron = 9.11 x 10^(-31) kg
F_g = 9.11 x 10^(-31) × 9.8
F_g = 8.9278 × 10^(-30) N downwards
B) Formula for Electric force is;
F_e = qe
q is charge on electron = 1.6 × 10^(-19) C
E is electric field = 100 N/C
F_e = 1.6 × 10^(-19) × 100
F_e = 1.6 × 10^(-17) N upwards
C) Magnetic force is given by the formula;
F_m = qVB
q is charge on electron = 1.6 × 10^(-19) C
V is velocity given as 8.50 × 10^(6) m/s
B is magnetic field = 50.0 μT = 50 × 10^(-6) T
F_m = 1.6 × 10^(-19) × 8.50 × 10^(6) × 50 × 10^(-6)
F_m = 6.8 × 10^(-17) N downwards
To observe a chemical property, a chemical change must occur (new substances produced). To see if a piece of paper has the chemical property of combustability (will burn in oxygen), you must actually try to burn it, producing carbon (ash), water vapor, carbon dioxide – the material is no longer paper. What are some clues, observations that might indicate that a chemical change has occurred?
Answers
Answer:
Explanation:
Chemical reaction is described as the process of rearrangement of the atoms to produce a new product which will have a different chemical identity.
For the observatory evidences to prove a chemical reaction has occurred we can look to the following:
Emission of heat/loss of heatEmission of lightchange in the physical formFormation of precipitateEvolution of gasescolor changeDecomposition of the organic matterGenerally chemical change is irreversibleAbsolute result for the chemical change can be observed using the chemical analysis
Determine the image distance and image height for a 5.00 cm tall object placed 45.0 cm from a double convex lens with a focal length of 15.0 cm.
Answers
Given,
object distance = Given that, an object placed 45.0 cm from a convex lens having a focal length of 15.0 cm
and the height of the image is 5.0 cm
we know,
\(\begin{gathered} \frac{1}{f}=\frac{1}{v}-\frac{1}{u}\frac{}{} \\ \\ \frac{1}{15}=\frac{1}{v}-\frac{1}{-45} \\ \\ \frac{1}{v}=\frac{1}{15}-\frac{1}{45} \\ \\ \frac{1}{v}=\frac{2}{45} \\ \\ \therefore\text{ v=22.5cm} \end{gathered}\)we know,
\(\begin{gathered} \frac{h_i}{h_o}=\frac{v}{u} \\ \\ \frac{\begin{equation*}h_i\end{equation*}}{5}=\frac{22.5}{-45} \\ \\ h_i=-2.5cm \end{gathered}\)result,
image distance = 22.5cm towards right side of convex lens .
image height=2.5cm, {Enlarged and inverted}
What is the wavelength of an electron moving at 3. 94 x 107 m/s?.
Answers
The wavelength of an electron moving at 3.94 x 10^7 m/s is 1.67 × 10^-10 m.
The de Broglie wavelength formula is λ = h / mv where λ is the wavelength of the particle, h is Planck's constant, m is the mass of the particle, and v is its velocity.
To calculate the wavelength of an electron moving at 3.94 x 10^7 m/s, we need to know the mass of the electron and Planck's constant. The mass of an electron is 9.10938356 × 10^-31 kilograms. Planck's constant is 6.62607015 × 10^-34 Joule seconds. Using these values, we can calculate the wavelength of an electron moving at 3.94 x 10^7 m/s as follows:λ = h / mvλ = 6.62607015 × 10^-34 J.s / (9.10938356 × 10^-31 kg) × (3.94 × 10^7 m/s)λ = 1.67 × 10^-10 m
Therefore, the wavelength of an electron moving at 3.94 x 10^7 m/s is 1.67 × 10^-10 m.
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A 12kg aluminum box is sliding along a horizontal steel surface while experiencing a rightward applied force of 60N. The box has a displacement of 20m. What is the Net Force acting on the box? *
A.)60N
B.)117.72N
C.)4.67 N
D.)-55.33N
Answers
The speed of sound is determined by the temperature and density of the medium through which it travels. Based on the speed data above, which choice below lists the media in order from most to least dense?
A. Wood, water, air
B. Air, water, wood
C. Air, wood, water
D. Wood, air, water
Answers
Answer:
A?
Explanation: put them in order
Sorry if its wrong...
Answer:
It's A
Explanation:
It wants it in order from most dense to least. Wood is most dense so it's first, then water, and then air is last.
reset the simulation (circular orange button) and check the force and speed boxes. apply a force of 50 n to the right for about 5 seconds (the timing is not critical) and then make the applied force zero. let the simulation keep running. describe the motion of the box on the skateboard. what happens on the speedometer?
Answers
When a force of 50 N is applied to the right for 5 seconds, the box will begin to move to the right with an increasing speed.
The speedometer will show the increasing speed of the box. After the applied force is made zero, the box will continue to move to the right due to its acquired momentum but its speed will begin to decrease as it loses energy due to friction and other resistive forces.
A speedometer is a device that measures the speed of a vehicle. It is typically mounted on the dashboard of a car and displays the speed in either miles per hour (mph) or kilometers per hour (km/h). The speedometer is linked to the car's transmission and is powered by either a cable or an electronic signal. It works by measuring the number of rotations of the wheels, which is then translated into a speed reading on the gauge.
The speedometer is an important safety feature as it helps drivers stay within the speed limit and drive safely. It also helps drivers monitor their speed to avoid receiving a speeding ticket or getting into an accident. A speedometer is a critical component of any vehicle and should be checked regularly to ensure that it is functioning properly.
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Why does a bowling ball have more
gravity than a soccer ball?
Answers
bc it weig more then a soccer ball
Hope this helps
Have a great day/night
Three different experiments are conducted that pertain to the oscillatory motion of a pendulum. For each experiment, the length of the pendulum and the mass of the pendulum are indicated. In all experiments, the pendulum is released from the same angle with respect to the vertical.The pendulum in Experiment 2 is released from rest at an angle of with respect to the vertical. What is the magnitude of the change in kinetic energy of the pendulum from its lowest point to the highest point along its arc?A. ZeroB. 2MgLC. 2MgLcos0oD. 2Mg(L-L cos0o)
Answers
The magnitude of the change in kinetic energy of the pendulum from its lowest point to the highest point along its arc can be determined based on the given information.
In Experiment 2, the pendulum is released from rest at an angle θ with respect to the vertical.
At the lowest point of the pendulum's arc, its kinetic energy is maximum, and its potential energy is minimum. As the pendulum swings upwards, it reaches its highest point where its potential energy is maximum and its kinetic energy is minimum.
Since the pendulum is released from rest in Experiment 2, its initial kinetic energy is zero. Therefore, the change in kinetic energy from the lowest point to the highest point is the difference between its initial kinetic energy (zero) and its final kinetic energy (which is also zero at the highest point).
Hence, the magnitude of the change in kinetic energy of the pendulum from its lowest point to the highest point along its arc is A. Zero.
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a stroboscopic photo of a club hitting a golf ball, was made by Harold Edgerton in 1993. the ball was initially at rest, and the club was shown to be in contact with the ball for about 0.0020 s. Also, the ball was found to end up with a speed of 2.0x10^2 feet per second. Assuming that the golf ball had a mass of 55 g, find the average force exerted by the club on the ball
Answers
The average force exerted by the club on the ball is 838,400 N. Force can be characterized by its magnitude, direction, and point of application.
What is a force ?It can be a push or pull, and it can cause an object to start moving, stop moving, or change its direction of motion.
Force is indeed a physical factor that alters or has the potential to alter an object's state at rest or motion as well as its shape. Newton is the SI unit of force.
Finally, the average force exerted by the club on the ball is:
F = I / t = (1676.8 N·s) / (0.0020 s) = 838,400 N
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If 5x instead of 10x oculars were used in your microscope with the same objectives, what magnifications would be achieved?
Answers
The magnification is doubled when 10x oculars are used instead of 5x in our microscope with the same objectives.
When multiple lenses are lined together, the overall magnification can be calculated by multiplying the individual magnifications of each lens.
M = M1 × M2 × M3 × ... × Mn
where M is the overall magnification and M1, M2, M3, ..., Mn are the magnifications of the individual lenses.
Let M be the magnification of the objective, then the overall magnification,
when 5x ocular is used,
M1 = M × 5
M1 = 5M
when 10x ocular is used
M2 = M × 10
M2 = 10M
Therefore, the magnification is doubled when 10x ocular is used instead of 5x in our microscope with the same objectives.
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a physics professor demonstrates the doppler effect by tying a 900 hz sound generator to a 1.0-m -long rope and whirling it around her head in a horizontal circle at 100 rpm .
Answers
The highest and lowest frequencies heard by a student in the classroom are Doppler effect.
What is frequency?Frequency is the number of occurrences of a repeating event per unit time. It is also referred to as temporal frequency, which emphasizes the contrast to spatial frequency and angular frequency. In the fields of physics and engineering, frequency is usually denoted by the letter f or by the Greek letter ν. It is measured in hertz (Hz), which is equal to one occurrence of a repeating event per second.
In this demonstration, the professor is demonstrating the Doppler effect by whirling a 900 Hz sound generator tied to a 1-meter-long rope around her head in a horizontal circle at 100 rpm. As the sound generator moves in a circle, it is moving toward the observer and away from the observer at different points in the circle, causing the frequency of the sound to increase and decrease, respectively. This is the Doppler effect - the frequency of the sound wave changes depending on the relative motion of the source and the observer.
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Complete Question:
A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it around her head in a horizontal circle at 100 rpm. What are the highest and lowest frequencies heard by a student in the classroom?
Help ASAP I’ll give u branliest!! This isn’t really hard
Answers
Answer:
I'm pretty sure it's mist, drizzle, droplet, and then rain.
Which of the following lines of reasoning involves proving a event occurs, and assuming
something about the mechanisms leading to that conclusion?
O productive reasoning
O inductive reasoning
O deductive reasoning
O reductive reasoning
Answers
Correct option is C, deductive reasoning involves proving a event occurs, and assuming something about the mechanisms leading to that conclusion.
Deductive reasoning -In deductive reasoning, a conclusion is drawn from the agreement of multiple premises that are frequently assumed to be true. Deductive reasoning is also referred to as top-down reasoning. Deductive reasoning is built on making logical assumptions and drawing conclusions from them.
It is predicated on a broad assertion or hypothesis that is assumed to be true (sometimes referred to as a premise). In order to arrive at a clear, logical conclusion, the premise is used. The if/then statement is a typical illustration. Deductive reasoning informs us that A Equals C if A = B and B = C.
To learn more about deductive reasoning from given link
https://brainly.com/question/7284582
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