A television of mass 15 kg sits on a table. The coefficient of static friction
between the table and the television is 0.35. What is the minimum applied
force that will cause the television to slide?

A) 38 N
B) 147 N
C) 51 N
D) 79 N

A. The average speed you can use to pull the safe is 1.02 m/s

B. The time needed to pull the safe up is 17.65 s

First, we shall obtain the force. This is shown below:

F = mg

F = 60 × 9.8

F = 588 N

Finally, we shall obtain the average speed. Details below:

Power = force × average speed

600 = 588 × average speed

Divide both sides by 588

Average speed = 600 / 588

Average speed = 1.02 m/s

The time needed to pull the safe up can be obtained as follow:

Time = Total distance / average speed

Time = 18 / 1.02

Time = 17.65 s

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Complete question:

You know you can provide 600 W

of power to move large objects. You need to move a 60-kg

safe up to a storage loft, 18 m

above the floor.

Part A

With what average speed can you pull the safe straight up?

Part B

What is the time needed to pull the safe up?

Answer:

Friction is when 2 solids move against each other. The cause of friction is adhesion, and surface roughness. Surface roughness is when a surface is rough enough that is causes friction against another surface. Adhesion is when 2 surfaces collide because of thier molecular force.

The net force acting on the particle would be and the magnitude of the force would be -12.92i + 6.49j and the magnitude of the force would be 14.46 Newtons.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The net force on the particle = mass of the particle × acceleration

                                                =3.80*(−3.40i + 1.70j)

                                                = -12.92i + 6.49j

Thus, the magnitude of the net force on the particle would be 14.46 Newtons.

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To solve the given problems, we'll use the principles of work-energy and conservation of energy. Let's address each question one by one:

(1) What is the work done by Chris on the box when the speed of the box reaches 2.1 m/s?

The work done by Chris on the box is equal to the change in the box's kinetic energy. Since the box starts from rest, the initial kinetic energy is zero. The final kinetic energy can be calculated using the formula:

Kinetic energy = (1/2) * mass * velocity^2

Plugging in the values:

Mass of the box (m) = 53 kg

Final velocity (v) = 2.1 m/s

Kinetic energy = (1/2) * 53 kg * (2.1 m/s)^2

Calculate the value of the kinetic energy, which represents the work done by Chris on the box.

(2) What is the speed of the box when it reaches the bottom of the slope (Point B in the diagram)?

To determine the speed at the bottom of the slope, we'll use the principle of conservation of energy. The total mechanical energy of the box is conserved as it moves from the top to the bottom of the slope.

The initial potential energy at the top of the slope is converted into kinetic energy at the bottom of the slope, neglecting any energy losses due to friction.

Potential energy at the top = m * g * h1

Where:

Mass of the box (m) = 53 kg

Acceleration due to gravity (g) = 10 m/s^2

Height difference between floors (h1) = 3.2 m

Calculate the initial potential energy.

The final kinetic energy at the bottom is given by:

Kinetic energy at the bottom = (1/2) * m * v^2

Where:

Mass of the box (m) = 53 kg

Velocity at the bottom (v) = ?

Equating the initial potential energy to the final kinetic energy, solve for v to find the speed of the box at the bottom of the slope.

(3) To what speed does the box slow down when it reaches the bottom of the ramp to the pickup truck?

Since the ramp connecting the first floor to the bed of the pickup truck is frictionless, there is no external force doing work on the box. Thus, the mechanical energy of the box is conserved as it moves from the bottom of the slope to the bottom of the ramp.

Using the same principle of conservation of energy, equate the final kinetic energy at the bottom of the slope to the initial potential energy at the bottom of the ramp.

Potential energy at the bottom of the ramp = m * g * h2

Where:

Mass of the box (m) = 53 kg

Acceleration due to gravity (g) = 10 m/s^2

Height difference between the first floor and the truck bed (h2) = 0.90 m

Calculate the potential energy at the bottom of the ramp.

Equating the potential energy at the bottom of the ramp to the final kinetic energy, solve for the speed of the box at the bottom of the ramp.

(4) What is the speed of the box when it reaches the bed of the pickup truck?

Since the ramp connecting the first floor to the truck bed is frictionless, there is no external force doing work on the box. The mechanical energy of the box is conserved as it moves from the bottom of the ramp to the truck bed.

Using the same principle of conservation of energy, equate the final potential energy at the bottom of the ramp to the final kinetic energy at the truck bed.

Potential energy at the truck bed = m * g * h

The speed of the object for 1 second is 3 m/s.

The speed of the object for 2 seconds is 1.5 m/s.

The speed of the object for 3 seconds is 1.0 m/s.

The speed of the object for 4 seconds is 0.75 m/s.

The speed of the object for 5 seconds is 0.6 m/s.

The speed of an object is the distance travelled by the object divided by the total time taken for the motion.

The speed of the object for each of the time of motion and total distance traveled is calculated as follows;

v (1 ) = ( 3 m ) / ( 1 s ) = 3 m/s

v ( 2 ) = ( 3 m ) / ( 2 s ) = 1.5 m/s

v ( 3 ) = ( 3 m ) / ( 3 s ) = 1 m/s

v ( 4 ) = ( 3 m ) / ( 4 s ) = 0.75 m/s

v ( 5 ) = ( 3 m ) / ( 5 s ) = 0.6 m/s

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In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.

Answer:

distance

Explanation:

Speed is the rate of change of position expressed as distance travelled per unit of time

Answer:

Volcanic Eruptions

Explanation:

The volcano can start showing signs that it may be about to explode.

Answer:

Volcanic eruptions.

Explanation:

I had the same question on an assignment and I got it right.

Explanation:

Volume ( L X W X D)   * density = mass

(5 * 4 * 10) m^3      *     2000 kg/m^3   = 400 000 kg

    ( see how the ' m^3'  cancels out and you are left with kg as your answer units?)

The number of cycles (or full oscillations) that take place in a particular amount of time makes up a wave's frequency.

The wave frequency is the quantity of waves that pass a certain location in a predetermined amount of time. The SI unit for wave frequency is the hertz (Hz), and 1 hertz is equal to 1 wave passing through a fixed point in 1 second.

The number of cycles a wave can complete in a period of time—typically one second—is its frequency. A wave's frequency can be calculated by dividing its wavelength by velocity.

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Answer:

it is double the temperature change of iron

(-2, -1)(3, 1)

Therefore,

Answer:

a. If the frequency of light is increased above the threshold frequency, the energy of the electrons emitted will increase.

b. If the frequency of light is decreased to below the threshold frequency, the rate at which electrons are emitted will decrease.

c. If the intensity of light is decreased, the energy of the electrons emitted will remain the same, but fewer electrons will be emitted.

d. If the intensity of light is decreased, the rate at which electrons are emitted will decrease.

Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.

Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10

Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5

Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2

Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1

Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.

Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.

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Answer:

What is the effect of clouds on the "output" of a Solar PV module?

Clouds do impact photovoltaic panels. The quantity of power your photovoltaic panels can produce is directly dependent on the level of light they receive. ... They will see complete direct sunlight “plus” reflected light from the clouds! They will drink in more energy than they could on a cloudless day!

Explanation:

I hope it will help you...

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(1) The tension in cable 2 is 34.83 N.

(2) The coefficient of friction between the block and the floor is 0.45.

The tension in the cable 2 is determined by resolving the forces into various component as shown below.

The vertical component of the forces on the picture is given as;

∑Fy = T₁ sin (65) + T₂ sin (32) - 20 N = 0

T₁ sin (65) + T₂ sin (32) - 20 N = 0

1.7 x sin (65) + 0.53T₂ - 20 = 0

1.54 + 0.53T₂ = 20

0.53T₂ = 18.46

T₂ = 18.46 / 0.53

T₂ = 34.83 N

The value of coefficient of friction is calculated by applying Newton's second law of motion as follows;

F (net) = ma

(F₁ + F₂) - Ff = ma

where;

Ff is the force friction

a is the acceleration of the block

m is the mass of the block

(F₁ + F₂) - μmg = ma

where;

When block moves at a constant velocity, the acceleration a = 0

(F₁ + F₂) - μmg = 0

μmg  = (F₁ + F₂)

μ = (F₁ + F₂) / mg

μ = ( 195 + 222 ) / ( 95 x 9.8 )

μ = 0.45

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Answer:

e

Explanation:

Answer:

As traditionally used, impairment refers to a problem with a structure or organ of the body; disability is a functional limitation with regard to a particular activity; and handicap refers to a disadvantage in filling a role in life relative to a peer group.

Explanation:

Hope this helps u

Crown me as brainliest:)

\(\\ \sf\longmapsto Work\:Done=Force\times Displacement\)

\(\\ \sf\longmapsto Work\:Done=25(100)\)

\(\\ \sf\longmapsto Work\:Done=2500J\)

Explanation:

Solution,

Given:-

By the formula of work, we have

So, the work done is 2500 J.

The power rating of the heater is 277.8 W and the current drawn from the supply is 0.07015mA.

The power is obtained from the ratio of work and time and the power is measured in watts(W). The current is defined as the flow of electrons in the circuit and it is measured in ampere(A).

From the given,

The energy of the electric heater = 0.5MJ = 0.5×10⁶ J

Voltage (V) = 220 V

time (t) = 30 minutes = 30×60 s = 1800 s.

To find power (P):

Power = Energy / Time

          = 0.5×10⁶ / 1800

          = 277.77 W

Power of the electric heater = 277.8 W

To find current from the given:

Power (P) = V×I×t

Current (I) = P/(V×t)

                = 277.8 / (220×1800)

               = 0.7015 mA

The current drawn from the supply is 0.7015 mA.

Hence, the power rating of the heater is 277.8 W and the current drawn from the supply is 0.7015 mA.

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Answer:

Water because the salt will just make it colder and the sugar won't do anything

The energy lost to friction and air resistance is 186 J.

option B.

The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.

The initial potential energy of the pendulum at the initial position is calculated as;

PEi = mghi

where;

P.Ei = 12 kg x 9.8 m/s² x 20 m

P.Ei = 2,352 J

The final kinetic energy of the pendulum is calculated as follows;

K.Ef = 0.5 x 12 kg x (19 m/s)²

K.Ef = 2,166 J

ΔE = 2,166 J - 2,352 J

ΔE = -186 J

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The car needs to slow down to a minimum velocity before the collision, which is  0.789 meters per second (m/s), to avoid a fatal crash., and the mass of water needed in the barrels to bring the 1200 kg car down to the required speed is 42,344.1 kg.

To determine the minimum velocity the car can slow down to during a collision without the crash being fatal, we need to consider the concept of deceleration and the forces involved.

Deceleration and Minimum Velocity:

Let's assume the car slows down uniformly with a deceleration, denoted as 'a', until it comes to a stop. We can use the equation of motion to relate the initial velocity (100 km/h) with the final velocity (0 m/s), deceleration (a), and the distance traveled (unknown in this case).

The equation of motion is:

v^2 = u^2 + 2as

where:

v = final velocity (0 m/s)

u = initial velocity (100 km/h or approximately 27.78 m/s)

a = deceleration

s = distance traveled

Substituting the values into the equation, we have:

0^2 = (27.78)^2 + 2a(s)

Simplifying, we get:

0 = 771.84 + 2as

Since the car comes to a stop, the final velocity is 0, and we're left with:

771.84 = 2as

Now, we need to consider the impact force experienced by the car during the collision. This force is related to the deceleration and the mass of the car by Newton's second law of motion:

F = ma

We want to find the minimum velocity at which the crash won't be fatal, so we need to determine the maximum acceptable force the car can withstand without causing severe harm.

The maximum acceptable force depends on various factors, including the design and safety features of the car, but let's assume a commonly used threshold of 50 g's (where g is the acceleration due to gravity, approximately 9.8 m/s^2).

Converting 50 g's to m/s^2, we have:

50 g's * 9.8 m/s^2 = 490 m/s^2

Thus, we want to limit the deceleration to 490 m/s^2.

Now we can rearrange the equation 771.84 = 2as to solve for 's' (the distance traveled):

s = 771.84 / (2a)

Substituting the maximum acceptable deceleration (490 m/s^2) into the equation:

s = 771.84 / (2 * 490)

s ≈ 0.789 m

Therefore, the car needs to slow down to a minimum velocity before collision, which is approximately 0.789 meters per second (m/s), to avoid a fatal crash.

Mass of Water in Barrels:

To calculate the mass of water needed in the barrels to bring the 1200 kg car down to the required speed, we need to consider the conservation of momentum.

The initial momentum of the car is given by:

initial momentum = mass of the car * initial velocity

The final momentum of the car-barrels system is given by:

final momentum = mass of the car-barrels system * final velocity

Since the car forms a combined moving unit with the barrels after the collision, their final velocity will be the same. We can equate the initial and final momentum to find the mass of the car-barrels system.

initial momentum = final momentum

mass of the car * initial velocity = mass of the car-barrels system * final velocity

Solving for the mass of the car-barrels system:

mass of the car-barrels system = (mass of the car * initial velocity) / final velocity

Substituting the given values:

mass of the car-barrels system = (1200 kg * 27.78 m/s) / 0.789 m/s

mass of the car-barrels system ≈ 42344.1 kg

To bring the car-barrels system to a stop, an equal and opposite force needs to act on it. In this case, we assume the force is provided by the water in the barrels.

The force required to decelerate the car-barrels system is given by:

force = mass of the car-barrels system * deceleration

We can use this force to calculate the mass of water needed in the barrels. Let's assume the deceleration required is the maximum acceptable deceleration we determined earlier (490 m/s^2).

mass of water = force / deceleration

mass of water = (mass of the car-barrels system * deceleration) / deceleration

mass of water = mass of the car-barrels system

So, the mass of water needed in the barrels to bring the 1200 kg car down to the required speed is approximately 42,344.1 kg.

Hence, To avoid a fatal collision, the car must slow down to a minimum velocity of 0.789 metres per second (m/s) before the collision, and the mass of water required in the barrels to bring the 1200 kg car down to the required speed is 42,344.1 kg.

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Answer:

It makes work require less force perform.

Explanation: