The angular momentum of the ball of clay before grazing the surface is (2/3)mrv.
What is the angular momentum of the sphere?The angular momentum of the ball of clay about the shaft before it grazes the surface is calculated as follows;
Moment of inertia of the ball;
I = (2/3) mr²
where;
m is the mass of the spherer is its radius.Angular velocity is given as;
ω = v / r
where;
v is linear velocityr is the radiusThe angular momentum of the ball of clay before grazing the surface is calculated as;
L = Iω
L = (2/3)mr² x (v / r)
L = (2/3)mrv
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sam is an astronomer on planet hua, which orbits the distant star barnard. it has recently been accepted that hua is spherical in shape, although its exact size is unknown. while studying in the library, in the city of joy, sam learns that during equinox, barnard is directly overhead in the city of bar, located 1100.0 km north of his location. on the equinox, sam goes outside and measures the altitude of barnard at 78 degrees. what is the radius of hua in km?
There are 90 degrees directly overhead. Barnard is at 74 degrees at Sam's position, 1300.0 kilometers south. The part of the 360 degree circle that corresponds to Hua's circumference is the difference between 90 and 74, or 16 degrees. 1300.0 km is therefore 16/360 of the circle, or 0.044 times the circumference. 29.250 km is the circumference (1300 divided by 0.044). Radius divided by two gives the circumference equation. Therefore, 2r=29250 and the radius of Hua=4655.3 km
What do you mean by Astronomy?Astronomy is a scientific science that examines celestial objects and phenomena (from the Ancient Greek "o" (astronoma), "science that investigates the laws of the stars"). In order to describe their creation and evolution, it makes use of mathematics, physics, and chemistry. Planets, moons, stars, nebulae, galaxies, and comets are among the interesting celestial bodies. Supernova explosions, gamma ray bursts, quasar, blazar, pulsar, and cosmic microwave background radiation are examples of relevant phenomena. Astronomy is the study of everything that comes from outside the atmosphere of the Earth. Astronomical cosmology is the study of the cosmos as a whole.
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Arrange the following in order of increasing radius: O2-, F- , Ne ,Rb+ ,Br- Rb+ < F- < Br- < O2- < Ne Br- < Rb+ < Ne < F- < O2- Ne < F- < O2- < Rb+ < Br- O2- < F- < Ne < Rb+ < Br- O2- < Br- < F- < Ne < Rb + Br- < F- < O2- < Ne < Rb+ F- < O2- < Ne < Br- < Rb + Rb+ < F- < Br- < Ne
Radii is a vital feature of the elements, and it can be useful in determining the characteristics of elements in various chemical and physical processes. The radii of atoms and ions of the same element differ due to their various charge and mass characteristics.
Atomic and ionic radii increase as you move down a group on the periodic table, and decrease as you move across a period from left to right due to increased nuclear charge, making the electrons closer to the nucleus. The size of an atom and ion also changes due to the number of electrons charge, and electronic configuration.In order of increasing radius, the arrangement of \(Ne, F-, O2-, Br-, Rb\) is given as follows:
\(Ne < F- < O2- < Br- < Rb+\)
Rb+ has the smallest radius due to its large nuclear charge and fewer electrons in the valence shell.
As a result, they are larger than Rb+. O2- has more electrons than Ne and is the largest among the given ions and atoms. It is important to note that in certain conditions, the trends in radii may not be valid because of hybridization and other factors. Nonetheless, this arrangement is valid for the given ions and atoms.
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A subway car moves at a constant speed of 10 m/s over a period of 10 s. What is the instantaneous speed halfway through this motion
Answer: 10 m/s
We're told the speed is constant, so it's not changing throughout the time period given to us. So throughout the entire interval, the speed is 10 m/s.
A teacher wants to demonstrate that the radioactive source emits alpha beta and gamma radiation. describe a method the teacher could use
Place a piece of paper in front of and behind the monitor. If the numbers are reduced sufficiently, the source emits alpha particles.
What is radioactivity?The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that wants to give up some energy in order to move to a more stable form.
Determine the background count rate first, followed by the source count rate without an absorber, to identify the radiation type.
Put a piece of paper in front of the monitor and behind the source. The source emits alpha particles if the numbers are sufficiently decreased.
Hence by founding the count rate the teacher will find the type of radiation.
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Which of the following statements about developing a personal fitness program is NOT true?
A When developing a personal fitness program, it is important to implement strategies that will help
maintain the program as well as give it a successful start
B. Personal factors such as age, health concerns, and likes are important to consider when developing
a personal fitness program
C. The starting skill level of the physical activities included in a personal fitness program should be
determined from other individuals' fitness programs
D. The FITT principle should be used when developing a personal fitness program,
Please select the best answer from the choices provided
A
B
Save and Exit
Next
Answer:
C
Explanation:
The starting skill level of the physical activities included in a personal fitness program should be determined from other individuals' fitness programs is a statement which is not true. Everyone starts their personal fitness journey at a different level which should be regarded . A fitness test should be taken to determine where an individual should start their new lifestyle.
Answer:
C. I got it right :)
Explanation:
ignore this accident
So free point OK ty see ya!
If I push on the wall with 75 Newtons of force, the wall will push back with __
Answer: 0
Explanation:
75 newtons will push back canceling it out make it 0
If I push on the wall with 75 Newtons of force, the wall will push back with 75 Newtons of force.
What is force?Force is defined as a cause which is capable of changing the motion of an object. It can cause an object which has mass to change it's velocity. It is also simply a push or a pull . It has both magnitude as well as direction.Hence, it is a vector quantity.
It has SI units of Newton and is represented by'F'.Newton's second law states that force which acts on an object is equal to momentum which changes with time. If mass of object is constant, acceleration is directly proportional to net force acting on an object.
The concepts which related to force are thrust and torque .Thrust increases the velocity of an object and torque produces change in rotational speed of an object.
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the current produced by voltage in a circuit is impeded by
The current produced by voltage in a circuit is impeded by Electric resistance
Explain what is voltage?When charged electrons (current) are propelled through a conducting loop by the pressure of an electrical circuit's power source, they can complete activities like lighting a lamp. In an essence, voltage represents pressure and is measured in volts.
Why does electricity resist?This is so because resistance arises from the collision of electrons with the conductor's atoms. In this situation, a longer conductor will result in more interactions and more resistance. The area of a conductor's cross-section has an inverse correlation with the conductor's resistance. An electrical circuit's resistance to current flow is measured as electrical resistance. The Greek letter omega () represents the measurement unit for resistance, known as ohms.
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find the odd one out: asteroids on the asteroid belt, a comet, the moon or Saturn
Answer:
Explanation:
A change in an object’s motion—such as Xander speeding up on his scooter—is called acceleration. Acceleration occurs whenever an object is acted upon by an unbalanced force. The greater the net force acting on the object, the greater its acceleration will be, but the mass of the object also affects its acceleration. The smaller its mass is, the greater its acceleration for a given amount of force. Newton’s second law of motion summarizes these relationships. According to this law, the acceleration of an object equals the net force acting on it divided by its mass.
The standard free energy for the reaction of oxygen binding to myoglobin Mb+O2(g)⇌ MbO2 is ΔG∘=−30.0kJmol−1 at 298 K and pH=7. The standard state of O2 is the dilute solution, molarity scale; therefore the concentration of O2 must be in M. What is the ratio MbO2/Mb in an aqueous solution at equilibrium with a partial pressure of oxygen pO2=400 Pa? Assume ideal behavior of O2 gas and for the protein in solution.
The ratio of MbO₂ to Mb at equilibrium with a partial pressure of oxygen pO₂ is 0.00002.
The ratio of MbO₂ to Mb in an aqueous solution at equilibrium with a partial pressure of oxygen pO₂ = 400 Pa can be calculated using the equation ΔG∘=−30.0 kJmol−1 at 298 K and pH = 7.
The equation used is: ΔG∘ = -RT ln (MbO₂/Mb), where R is the ideal gas constant and T is temperature in Kelvin. Rearranging this equation gives MbO₂/Mb = e^(-ΔG∘/RT).
Therefore, the ratio of MbO₂ to Mb at equilibrium with a partial pressure of oxygen pO₂ = 400 Pa is e^(-30.0/8.314*298) = 0.00002.
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A box of books weighing 315 N is shoved across the floor by a force of 477 N exerted downward at an angle of 35° below the horizontal. If the coefficient of kinetic friction between the box and the floor is 0.58, how long does it take to move the box 4.20 m starting from rest?
Answer:
It takes 1.14 s to move the box 4.20 m.
Explanation:
Using Newton's second law we have:
\(Fcos(35)-F_{f}=ma\)
\(Fcos(35)-\mu mg=ma\)
F is the force exerted and m the mass of the books
\(Fcos(35)-\mu mg=ma\)
\(477cos(35)-(0.58*315)=\frac{315}{9.81}a\)
So, the books accelerate at:
\(a=6.48\: m/s^{2}\)
We know that the initial velocity is zero, so using the kinematic position equation, we have:
\(x=\frac{1}{2}at^{2}\)
So, we just need to solve the equation for t.
\(4.2=\frac{1}{2}6.48t^{2}\)
\(t=\sqrt{\frac{2*4.2}{6.48}}\)
Taking the positive value of t:
\(t=1.14\: s\)
Therefore, it takes 1.14 s to move the box 4.20 m.
I hope it helps you!
A gas-turbine power plant operates on the simple Brayton cycle between the pressure limits of 100 and 1600 kPa. The working fluid is air, which enters the compressor at 40∘C at a rate of 850m3/min and leaves the turbine at 650∘C. Assuming a compressor isentropic efficiency of 85 percent and a turbine isentropic efficiency of 88 percent, determine
(a) the net power output,
(b) the back work ratio, and
(c) the thermal efficiency.
Use constant specific heats with
cv=0.821kJ/kg?
K,cp=1.108kJ/kg?
K, and k=1.35.
Answer:
a) 6498.84 kW
b) 0.51
c) 0.379
Explanation:
See the attached picture below for the solution
Given-
Temperature at state 1 \(T_{1}\) is 40 degree cel. This is equal to the 313 K.
Temperature at state 1 \(T_{2}\) is 650 degree cel. This is equal to the 923 K.
To know the mass flow rate use the idol gas equation. Idol gas equation for a substance can be given as,
\(PV=nRT\)
Rewrite this equation for \(n\),
\(n=\dfrac{PV}{RT}\)
Put the value of known variable from the question,
\(n=\dfrac{100\times\dfrac{850}{60} }{0.287\times 313}\)
\(n=15.77\)
Thus the value of n is 15.77 kg/sec.
Temperature at state 2 is,
In Bryon cycle we know that the processes 1-2 and 3-4 are isotropic. Hence,
\(T_{2} =T_{1}\left (1+ \dfrac{r_{p}^{\dfrac{\gamma-1}{\gamma}-1} }{c_{v} } \right )\)
\(T_{2} =313\left (1+ \dfrac{16^{\dfrac{1.35-1}{1.35}-1} }{0.821 } \right )\)
\(T_{2} =700\)
Temperature at state 3 is,
\(T_{3} =\dfrac{T_4}{1+c_p(r_p^{\dfrac{\gamma-1}{\gamma}-1}-1)}\)
Put the value in above equation we get,
\(T_3=1682\)
Net power output is,\(W=mc_p(T_i{n}-T_{out})\)
\(W=mc_p(T_3-T_2-T_4+T_{1})\)
\(W=15.77\times1.109(1682-700-923+313)\)
\(W=65\)
Thus the net power output is 70 watt.
The back work ratio,
\(r_b=\dfrac{T_2-T_1}{T_3-T_4}\)
\(r_b=\dfrac{700-313}{1682-923}\)
\(r_b=0.51\)
Hence the back work ratio is 0.51.
The thermal efficiency-\(\eta=\dfrac{W}{Q_{in}}\)
\(\eta=\dfrac{65}{mc_p(T_3-T_2)}\)
\(\eta=0.379\)
Hence, for the given problem the net power output is 70 watt,the back work ration is 0.51, and the thermal efficiency is 0.379.
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Please help.. I'm desperate.
Using language from newton's laws of motion, describe why the space shuttle seen in the picture is able to take off.
Answer:
Newton's Second Law tells us that the more mass an object has, the more force is needed to move it. A larger rocket will need stronger forces (eg. more fuel) to make it accelerate. The space shuttles required seven pounds of fuel for every pound of payload they carry.
Explanation:
PLEASE HELP!!! ILL MARK BRAINLYEST!!
How many atoms are in 5 C?
7
5
3
4
6
Answer:
Explanation:
3.011 x 10^24 atoms
Answer:
jskskskssksksksskssksksksksks
A lamp uses a standard 9 V battery, How much resistance is in the circuit is in the current of 1.05 A?
Answer:
R= v/I
R= 9/1.05=8.5714 ohms
A farsighted person has a nearpoint of 60 cm from her eyes. She wants glasses that will let her see objects at a distance of only 25 cm from her eyes. Determine the focal length of the glasses needed if the glasses are 2 cm and 3 cm from her eyes. (Remember, a converging lens has a positive focal length and a diverging lens has a negative focal length.)
f2 cm = ? cm
2) f3 cm = ? cm
3) A nearsighted person has a farpoint of 482 cm from his left eye and 632 cm from his right eye. He wants contact lenses that will let him see objects at a great distance. Determine the focal length of the contact lens needed for each eye. (Remember, a converging lens has a positive focal length and a diverging lens has a negative focal length.)
fleft = ? cm
4) fright = ? cm
The focal length of the glasses needed is 18.04cm.
1) To determine the focal length (f) of the glasses needed when they are 2 cm away from her eyes, we can use the lens equation:
1/f = 1/do + 1/di
Where do is the object distance (25 cm), di is the image distance (60 cm - 2 cm = 58 cm). Plugging in the values:
1/f2cm = 1/25 + 1/58
f2cm = 1/(1/25 + 1/58) ≈ 18.04 cm
2) For the glasses that are 3 cm away from her eyes, di will be 60 cm - 3 cm = 57 cm. Using the lens equation:
1/f3cm = 1/25 + 1/57
f3cm = 1/(1/25 + 1/57) ≈ 17.32 cm
3) To find the focal length of the contact lenses needed for a nearsighted person, we need to use the lens equation:
1/f = 1/do + 1/di
Since he wants to see objects at a great distance (infinity), the image distance (di) will be at his farpoint. For the left eye, the farpoint is 482 cm, and the object is at infinity (do = ∞). Plugging in the values:
1/fleft = 1/∞ + 1/482
fleft = 1/(0 + 1/482) ≈ -482 cm
4) For the right eye, the farpoint is 632 cm. Using the lens equation:
1/fright = 1/∞ + 1/632
fright = 1/(0 + 1/632) ≈ -632 cm
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What is the difference between the chemical bonds formed in molecules of
N2 and the chemical bonds formed in crystals of Mgo?
A. MgO is a covalent substance, and N2 is an ionic substance.
B. Both N2 and MgO are covalent substances, but the bonding
electrons in MgO are shared more equally between atoms than
they are in N2
C. Both N2 and MgO are covalent substances, but the bonding
electrons in N2 are shared more equally between atoms than they
are in Mgo.
D. Mgo is an ionic substance, and N2 is a covalent substance.
Answer:
D
Explanation:
Mgo is ionic and N2 has covalent bonds
What ions are produced from acids and bases?
Answer:
Give person above me brainliest
Explanation:
why is fluorine more chemically reactive than
nitrogen?
Answer:
Nitrogen has Electronic configuration 1s2 2s2 2p3. Fluorine has Electronic configuration 1s2 2s2 2p5 i.e. nitrogen has half filled p subshell that makes it more stable than fluorine and fluorine requires only 1 electron to complete it's octet to get stable..Therefore Fluorine is more reactive than Nitrogen.
Hope it helps you
Write a hypothesis about the use of an object's physical
characteristics to determine its density. Use the format
'if .
then
because
and be sure to answer the
lesson question "How can the density of an object be
determined?"
I just need a short answer
Answer:
Explanation:
then
A thermometer is taken from a room where the temperature is 19
∘
C to the outdoors, where the temperature is −5
∘
C. After one minute the thermometer reads 11
∘
C. (a) What will the reading on the thermometer be after 3 more minutes? (b) When will the thermometer read −4
∘
C ? minutes after it was taken to the outdoors.
The reading on the thermometer after 3 more minutes will be -13∘C. The thermometer will never read -4∘C after being taken outdoors.
To solve this problem, we can assume that the rate of change in temperature follows a linear pattern.
Let's first calculate the rate of change in temperature per minute:
Rate of change = (Final temperature - Initial temperature) / Time
a) After one minute:
Rate of change = (11∘C - 19∘C) / 1 minute = -8∘C/minute
To find the reading on the thermometer after 3 more minutes, we can multiply the rate of change by the time:
Change in temperature = Rate of change × Time
After 3 more minutes:
Change in temperature = -8∘C/minute × 3 minutes = -24∘C
The initial temperature was 11∘C, so the final temperature after 3 more minutes will be:
Final temperature = Initial temperature + Change in temperature = 11∘C - 24∘C = -13∘C
b) To find when the thermometer will read -4∘C, we need to determine the time it takes for the temperature to change from -5∘C to -4∘C.
Rate of change = (-4∘C - (-5∘C)) / Time
Rate of change = 1∘C / Time
We can rearrange the equation to solve for time:
Time = 1∘C / Rate of change
Substituting the given rate of change:
Time = 1∘C / (-8∘C/minute) = -1/8 minute
Since time cannot be negative, we can conclude that the thermometer will never read -4∘C after being taken outdoors.
Please note that this calculation assumes a linear rate of change in temperature, which might not hold true in all situations.
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Two spherical objects have masses of 3. 1 x 105 kg and 6. 5 x 103 kg. The gravitational attraction between them is 65 n. How far apart are their centers?.
The centers of the two spherical objects that are apart is 4.55 x 10³m.
Two spherical objects have masses of 3.1 x 10⁵ kg and 6.5 x 10³ kg. The gravitational attraction between them is 65N. The centers of the two spherical objects that are apart is 4.55 x 10³m. The gravitational force between two objects with masses m1 and m2 that are separated by a distance r is given by the equation:
F = \(\frac{G m1 m2}{r^{2} }\)
where G is the gravitational constant, m1 and m2 are the masses of the objects in kilograms, and r is the distance between their centers in meters. In this problem, we are given the gravitational force between the two objects, F, and the masses of the objects, m1 and m2. We can use these values to solve for the distance r between the centers of the objects. Gravitational force is the force that attracts two bodies in the universe. it is applicable everywhere. it is applicable on every body whether it is small or big, it applies everywhere.
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4.55 x \(10^9\) m are distance between their centre.
The gravitational force between two objects with masses m1 and m2 that are separated by a distance r is given by the equation:
F = \(\frac{Gm_1m_2}{r^2}\) where G is the gravitational constant, m1 and m2 are the masses of the objects in kilograms, and r is the distance between their centers in meters.
In this problem, we are given the gravitational force between the two objects, F, and the masses of the objects, m1 and m2.
We can use these values to solve for the distance r between the centers of the objects.
Substituting the given values into the equation above, we get:
65 = G*(3.1 x 10^5 kg)(6.5 x 10^3 kg)/\(r^2\)
Solving for r, we find that the distance between the centers of the objects is approximately:
r = sqrt(G(3.1 x 10^5 kg)(6.5 x 10^3 kg)/65)
=> sqrt((6.674 x 10^11 )(3.1 x 10^5 kg)(6.5 x 10^3 kg)/65)
= 4.55 x \(10^9\) m
Thus, the distance between the centers of the two objects is approximately 4.55 x \(10^9\) m .
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a bar magnet is oriented perpendicular to a uniform magnetic field as shown in (figure 1). describe the force and/or torque on the magnet.
When a bar magnet is oriented perpendicular to a uniform magnetic field, two important phenomena occur: the force and the torque on the magnet.
Force: The magnetic field exerts a force on the magnet due to the interaction between the magnetic field and the magnetic dipole moment of the magnet. In this case, the force will be perpendicular to both the magnetic field and the magnet. The force will tend to align the magnet with the magnetic field. If the magnet is free to move, it will experience a translational force that may cause it to move in the direction of the force.
Torque: The magnetic field also exerts a torque on the magnet, trying to rotate it. The torque is greatest when the magnet is perpendicular to the magnetic field lines. The torque will try to align the magnet with the magnetic field. If the magnet is free to rotate, it will experience a rotational force that may cause it to align itself with the magnetic field.
The exact magnitude and direction of the force and torque will depend on the strength of the magnetic field, the orientation of the magnet, and the magnetic properties of the magnet.
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This says the acceleration of an object increases by force applied to it, and decreases based on its mass.
Answer:
1) "the acceleration of an object increases by force applied to it" is correct, as long as the force is increasing, acceleration will increase.
2) "acceleration of an object increases by force applied to it" is correct, but only if one assumes the force is increasing (directly proportional).
Explanation:
Newton's second law states that force is the product of mass times acceleration: F=ma
1. "acceleration of an object increases by force applied to it" is correct: As force is increased (and mass stays the same), the acceleration must also increase.
2. "acceleration . . . decreases based on its mass" is confusing, since it does not say in what direction the mass is changing. As the mass increases, the acceleration will decrease, assuming constant force. If the mass decreases, the accelaration will increase.The statment should read "inversely proportional."
which type of switch connects all devices in a rack to the rest of the network?
The type of switch that connects all devices in a rack to the rest of the network is called a "Top of Rack (ToR) switch".
What is a Tor switch?Top of Rack (ToR) switch is a type of network switch that is typically installed in a data center or server room at the top of a server rack. The main purpose of a ToR switch is to provide high-bandwidth connectivity to the servers or other network devices within the rack and to connect them to the rest of the network.
ToR switches are commonly used in large-scale computing environments, such as cloud data centers, web hosting facilities and enterprise server rooms where they help to improve network efficiency and simplify network management.
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the dimension of relative density and tension
Answer:
Relative density is proportional to the frequency of a material's density to its water density. Because both have had the same proportions, their proportion is also dimensionless.
Explanation:
The dimension of relative density:-
Relative Density of a Substance (R.D.) = Substance Density / Water Density.
Therefore, R.D. Is just a ratio or a number. There are no units or dimensions to it.
For example:- The density of iron is 8.5 GM's/cm^3 & the density of water is 1 gm/cm^3 (in cgs units).
Tension:- Surface tension is the propensity of the new worlds and infographics to reduce to the particle size which is least appropriate. Atmospheric pressure helps insects (e.g. water striders) can travel or move and on a water surface, typically object is sensed rather than water.
the reflection of 2.70 mhz ultrasound waves from the surface of a fetus's beating heart is combined with the 2.70 mhz wave to produce a beat frequency that reaches a maximum of 65 hz . what is the maximum speed of the surface of the heart? the speed of ultrasound waves within the body is 1540 m/s . express your answer with the appropriate units.
The speed of ultrasound waves on the surface of the heart is 0.64 Hz
The reflection of 2.70 mhz ultrasound waves from the surface of a fetus's beating heart is combined with the 2.70 mhz wave to produce a beat frequency that reaches a maximum of 65 hz. This means that if we double the speed at which it is reflected, we will find ourselves at 65 hz.
We know that the surface of a fetus's beating heart has an area of approximately 1 sq cm and a thickness of 1 mm. This means that its volume is approximately 1 mm cube. Since we have already calculated that the speed of ultrasound waves within the body is 1540 m/s, this means that they travel through one square centimeter per second.
If we multiply this by our previous calculation, we can determine an upper limit on how fast they can travel:
1 / (1 / π) * 1540 = 1 / 10^6
≈ 0.64 Hz
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Which of the following is a basic unit and symbol in the metric system? A) centimeter (cm) B) kilogram (kg) C) milliliter (mL) D) all of the above E) none of the above
The basic unit and symbol in the metric system is D) all of the above.
The metric system is a decimal-based system of measurement used worldwide. It utilizes a set of standard units and symbols to represent different quantities. In the metric system, there are three fundamental units commonly used: centimeter (cm) for length, kilogram (kg) for mass, and milliliter (mL) for volume. These units are considered basic because they form the foundation for measuring length, mass, and volume in the metric system.
The centimeter (cm) is used to measure small lengths, such as the height of a person or the width of an object. The kilogram (kg) is the unit for mass and is commonly used to measure the weight of an object. The milliliter (mL) is a unit of volume often used to measure the capacity of liquids or small amounts of substances.
All three units (centimeter, kilogram, milliliter) are widely recognized and used in scientific, industrial, and everyday contexts. They provide a standardized and consistent way of measuring and comparing quantities. Therefore, the correct answer is "D) all of the above" because each of these units is a basic unit and symbol in the metric system.
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Which section from the article BEST explains why wavelength and frequency are dependent on each other? (A) "Amplitude And Height" (B) "Wavelength And Cycle" (C) "Frequency And Period" (D) "Speed"
n on
your
27. Base your answer(s) to the following question(s)
on the information below.
A scientist set up an experiment to collect data
about lightning. In one lightning flash, a charge of
25 coulombs was transferred from the base of a
cloud to the ground. The scientist measured a
potential difference of 1.8 x 106 volts between the
cloud and the ground and an average current of
2.0 × 104 amperes.
The scientist was several kilometers from the
lightning flash. Using one or more complete
sentences, explain why the scientist saw the
lightning flash several seconds before he heard the
sound of the thunderclap from that flash.
Sound travels at a known speed, the time interval between the flash and the thunderclap can be used to calculate the approximate distance to the lightning strike.Light travels at a speed of approximately 299,792 kilometers per second in a vacuum, while sound travels at a much slower speed of around 343 meters per second in dry air at 20 degrees Celsius.
The scientist observed the lightning flash several seconds before hearing the sound of the thunderclap because light travels much faster than sound. Light travels at a speed of approximately 299,792 kilometers per second in a vacuum, while sound travels at a much slower speed of around 343 meters per second in dry air at 20 degrees Celsius.Given that the scientist was several kilometers away from the lightning flash, the light from the flash reached the scientist's location almost instantaneously. In contrast, the sound waves generated by the thunderclap took time to travel through the air over the distance between the scientist and the lightning. Consequently, it took several seconds for the sound to reach the scientist's ears.The time difference between seeing the lightning flash and hearing the thunder allows us to estimate the distance of the lightning strike.
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