A two-by-four piece of wood is 1 1/2 inches wide. If placed side-by-side, how many boards are needed to make a width of 48 inches?

The expected number of new claims filed per week at this unemployment office is 12.

To find the expected number of new claims filed per week at the unemployment office, we need to multiply the expected number of new claims filed per day by the number of days the office is open in a week.

The expected number of new claims filed per day is given as 2.4. Since the office is open five days per week, we can multiply 2.4 by 5 to find the expected number of new claims filed per week:

Expected number of new claims filed per week = 2.4 * 5 = 12

Therefore, the expected number of new claims filed per week at this unemployment office is 12.

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hey what's up! the answer is c

Answer:

110000=p(1+0.019)^168

23.62p=110000

p=4660

credit: sqdancefan

Answer:

84330

Step-by-step explanation:

The compound interest formula gives the value of an investment.

 A = P(1 +r/n)^(nt)

where principal P is invested at annual rate r compounded n times per year for t years. Using your given values, we can solve for P.

 110,000 = P(1 +0.019/12)^(12·14)

 P = 110,000/(1 +0.019/12)^(12·14) ≈ 110,000/1.00158333...^168

 P ≈ 110,000/1.30446

 P ≈ 84326.04 ≈ 84,330 . . . . dollars

Answer: r=8in

Step-by-step explanation:

The probability of A appearing before B is \(\frac{4}{7}\).

To find the probability that TA < TB, we can use the fact that the probability of a certain pattern appearing in a sequence of coin flips is independent of the position in the sequence. In other words, the probability of A appearing at time n is the same as the probability of A appearing at time n+k for any k.

Using this fact, we can set up a system of equations to solve for the probability of TA < TB. Let p be the probability of A appearing before B, and q be the probability of B appearing before A. Then we have:

\(p = \frac{1}{2} + \frac{1}{2q}\)  (since the first flip can be either 0 or 1 with equal probability)
\(q= \frac{1}{4p} + \frac{1}{2q} + \frac{1}{4}\) (if the first two flips are 0, the sequence B has appeared; if the first flip is 1 and the second is 0, the sequence is neither A nor B and we start over; if the first flip is 1 and the second is 1, we have a new chance for A to appear before B)

Solving for p, we get:
\(p=\frac{4}{7}\)

Therefore, the probability of A appearing before B is \(\frac{4}{7}\).

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Answer:

it is going 1.65 kilometers per minute and it will travel 24.75 kilometers in 15 minutes

Step-by-step explanation:

Using degree of freedom,

Two degrees of freedom would we report when we report the results of our study is (2,24).

Degree of freedom:

The statistical degrees of freedom (DF) indicate the number of independent values that can be changed in the analysis without violating the constraints.

degrees of freedom is the number of independent values that can be estimated in a statistical analysis. It can also be thought of as the number of values that are free to vary when estimating the parameters

DF = N – P

Where:

N = sample size

P = the number of relationships

We given that,

Number of groups , k = 3

Number of total participants, n = 27

Degrees of freedom for F-test is F(k-1,n-k)

= F(3-1 , 27-3)

= F(2,24)

Hence, (2,24,) are required two degrees of freedom.

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In linear equation, 17 seconds it will take to do a complete gaussian elimination of this size.

What are a definition and an example of a linear equation?

Given that your computer completes a 5000 equation back substitution in 0.005 seconds.

then here Work is: n = 5000 and its rate is = (n2) / 0.005 = 5000000000

and Given formula : The approximate operation counts = ((2n^3)/3) = (2.0 * (n3)) / 3.0 = 83333333333.33

then we can found time = operations / rate = 83333333333.33/5000000000 = 16.67 = 17 seconds

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Answer:

The answer is 900

good luck

The fraction of the entire square that is shaded is 2/5.

A square is a two dimensional object that four sides that are of equal length. This means that the dimensions of the length and the width have the same value. A square has two diagonals that bisect each other at 90°.

A fraction is a non-integer that has a numerator and a denominator. The numerator is the number above and the denominator is the number below. An example of a fraction is 1/2.

Fraction = number of shaded squares / total number of squares

16 / 40

When expressed in its simplest form, the fraction becomes 2/5.

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Answer:

4/p

Step-by-step explanation:

4/p=4overp

Answer:

13

Step-by-step explanation:

i think 13 is the answer seeing that she lost 8 point,gained 5 points and they want you to find the sum of the points she lost and gained.. therefore you add since a sum is an answer you get after adding.

8+5=13

I hope this helps

Answer:

A = 974

Step-by-step explanation:

The formula for surface area of a rectangular prism is A=2(wl+hl+hw)

so yeah enjoy freedom for the rest of the day

Answer:

974 inches2

Step-by-step explanation:

Surface Area = 2×(11×8 + 11×21 + 8×21) = 974 inches2

Answer:

Step-by-step explanation:

its 71 my dude :)

Answer:

Step-by-step explanation:

Here you go mate

Step 1

(31)2+3^2  Equation/Question

Step 2

(31)2+3^2  Simplify

62+9

Step 3

62+9  Add them together

answer

71

Hope this helps

The step the student first made an error was step B

The given expression in simplest form is 8

From the question we are to determine the step the student first make an error and we are to simplify the given expression correctly.

The given expression is

5 - (-3)

The student steps are as follows:

Step A: 5+ (3)

Step B: 5+8

Step C: 13

The step the student first made an error was step B because

5 + (3) should evaluate to

5 + 3

and eventually 8

The correct simplification process is as follows:

5 - (-3)

Step A: 5+ (3)

Step B: 5 + 3

Step C: 8

Hence, the expression in simplest form is 8

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The average rate of change between 3 to 6 storms is 0.09.

Given

The price of bread has been increasing over the last month.

Brian believes there is a positive correlation between the number of predicted storms and the price of bread.

Number of Storms Predicted Bread Price;

1  $2.30

3  $2.41

4  $2.50

6  $2.68

7  $2.81

The formula to calculate the average rate of change between two values is as follows;

\(\rm Average \ rate = \dfrac{f(x_2) -f(x_1)}{x_2-x_1}\)

Therefore,

The average rate of change between 3 to 6 storms is;

\(\rm Average \ rate = \dfrac{f(x_2) -f(x_1)}{x_2-x_1}\\\\\rm Average \ rate = \dfarc{2.68-2.41}{6-3}\\\\\rm Average \ rate = \dfrac{0.27}{3}\\\\\rm Average \ rate = 0.09\)

Hence, the average rate of change between 3 to 6 storms is 0.09.

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Answer:

6) x = 3, y = -1 or (3, -1)

8) x = -1, y = ½ or (-1, ½)

Step-by-step explanation:

I will only demonstrate problems 6 and 8 since the process of solving for the solution is practically similar for problems 6 and 7.

Given the following systems of linear equations with two variables:

\(\displaystyle\mathsf{\left \{{{Equation\:1:\:x\:+\:y=2} \atop {Equation\:2:\:2x\:-\:y=7}} \right. }\)

First, isolate y from Equation 1:

x + y = 2

x - x + y = -x + 2

y = -x + 2

Substitute the value of y in the previous step into Equation 2:

2x - (-x + 2) = 7

2x + x - 2 = 7

3x - 2 = 7

Add 2 to both sides:

3x - 2 + 2 = 7 + 2

3x = 9

Divide both sides by 3 to solve for x:

\(\displaystyle\mathsf{\frac{3x}{3}\:=\:\frac{9}{3}}\)

x = 3

Substitute the value of x into Equation 1 to solve for y:

x + y = 2

3 + y = 2

3 - 3 + y = 2 - 3

y = -1

Therefore, the solution to the given system is: x = 3, y = -1 or (3, -1).

\(\displaystyle\mathsf{\left\{Equation\:1:\:3(6x\:-\:4y)\:=24} \atop{Equation\:2:\:3x\:-\:2y\:=4}} \right.}\)

For Equation 2, divide both sides by -3:

\(\displaystyle\mathsf{\frac{-3(6x-4y)}{-3}=\frac{24}{-3} }\)

6x - 4y = -8

Add 6x to both sides:

6x + 6x - 4y = 6x - 8

- 4y = 6x - 8

Divide both sides by -4 to isolate y:

\(\displaystyle\mathsf{\frac{-4y}{-4}=\frac{6x\:-\:8}{-4} }\)

\(\displaystyle\mathsf{y=-\frac{3}{2}+2}\)

Substitute the value of y from the previous step into Equation 2:

3x - 2y = -4

\(\displaystyle\mathsf{3x\:-\:2\Big(-\frac{3}{2}+2\Big)\:=-4}\)

3x + 3 - 4 = -4

3x - 1 = -4

3x - 1 + 1 = -4 + 1

3x = -3

Divide both sides by 3 to solve for x:

\(\displaystyle\mathsf{\frac{3x}{3}=\frac{-3}{3}}\)

x = -1

Substitute the value of x into Equation 2 to solve for y:

3x - 2y = -4

3(-1) - 2y = -4

-3 - 2y = -4

Add 3 to both sides:

-3 + 3 - 2y = -4 + 3

-2y = -1

Divide both sides by -2 to isolate y:

\(\displaystyle\mathsf{\frac{-2y}{-2}=\frac{-1}{-2}}\)

y = ½

Therefore, the solution to the given system is: x = -1, y = ½ or (-1, ½).

The value for sin(t + 6π) is always equal to 0, regardless of the value of t.

If sin(t) = 0, then t must be an integer multiple of π since the sine function is equal to zero at these values. Therefore, we can write t = nπ for some integer n.

To find sin(t + 6π), we can use the periodicity of the sine function, which states that

sin(x + 2π) = sin(x) for any real number x.

Using this property, we can rewrite sin(t + 6π) as sin(t + 2π + 2π + 2π) = sin(t + 2π) = sin(nπ + 2π).

Now, we need to determine the value of sin(nπ + 2π). Since n is an integer, we know that nπ + 2π is also an integer multiple of π, specifically (n+2)π.

Using the definition of the sine function, we can see that sin((n+2)π) = 0, since the sine function is zero at all integer multiples of π. Therefore, we can conclude that sin(t + 6π) = sin(nπ + 2π) = sin((n+2)π) = 0.

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Answer

4.84%

Step-by-step explanation:

trust me

False. An n × n matrix that is orthogonally diagonalizable does not necessarily have to be symmetric. A matrix is said to be orthogonally diagonalizable if it can be expressed as PDP^T, where P is an orthogonal matrix and D is a diagonal matrix.

For a matrix to be symmetric, it must satisfy the condition A = A^T, where A^T denotes the transpose of A. While it is true that symmetric matrices are always orthogonally diagonalizable, the converse is not necessarily true. There exist non-symmetric matrices that can still be orthogonally diagonalized. An example of such a matrix is the following:

  [1  2]

A = [3 4]

This matrix is not symmetric, as A^T is:

  [1  3]

A^T = [2 4]

However, it is still orthogonally diagonalizable. The matrix A can be diagonalized as:

A = PDP^T, where P = [0.8507 -0.5257]

[0.5257 0.8507]

          and D = [-0.3723   0     ]

                    [ 0      5.3723]

Therefore, it is not necessary for an n × n matrix that is orthogonally diagonalizable to be symmetric.

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Answer:

Two statement are true.

O The function is increasing on the interval (-∞, 0).

O The function is increasing on the interval (0, ∞).

Step-by-step explanation:

The function h(x) = 3x is a linear function (straight line) with a slope of 3, and a y-intercept of 0.  The constant, positive slope means that h(x) will increase over the interval (-∞, ∞).

See the attached graph.

After calculating, the dot product of the vectors v and e is -3/2. When the angle between them is (2π/3)

The problem asks us to find the dot product of two vectors v and e, where ||v||=3, e is a unit vector, and the angle between e and v is 2π/3.

The dot product of two vectors v and e is the product of the magnitude of the vectors and the cosine of the angle between them.

That is,v ⋅ e = ||v|| ||e|| cos θ,where θ is the angle between v and e.

We are given that ||v||=3 and e is a unit vector, so ||e||=1. We also know that the angle between e and v is 2π/3.

Substituting these values into the dot product formula, we get:v ⋅ e = 3(1) cos(2π/3)

We know that cos(2π/3) is equal to -1/2, so we can simplify the expression as follows:v ⋅ e = 3(1) (-1/2)v ⋅ e = -3/2

Therefore, the dot product of the vectors v and e is -3/2.

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Answer:

24

Step-by-step explanation:

(1+25) - (16)(1/8)

26 - 2

24

Cheers

Answer:

24

Step-by-step explanation:

(1+5^2) -16 ( 1/2)^3

PEMDAS

Parentheses first

Exponents in the parentheses

(1+25) -16 ( 1/2)^3

Then add in the parentheses

(26) -16 ( 1/2)^3

Then exponents

(26) -16 ( 1/8)

Then multiply

26 - 2

Then subtract

24

u is orthogonal to w, which means it is orthogonal to every vector in w. Hence, u is in w⊥.

What is Vector?

A vector is a living organism that transmits an infectious agent from an infected animal to a human or another animal. The vectors are often arthropods such as mosquitoes, ticks, flies, fleas and lice.

To prove that the subspace w⊥ consists of all vectors in v that are orthogonal to every basis vector {w1, w2, ..., wk}, we need to show two things:

Any vector in w⊥ is orthogonal to every basis vector.

Any vector in v that is orthogonal to every basis vector is in w⊥.

Let's prove these two statements:

Let's assume that a vector u is in w⊥. We need to show that u is orthogonal to every basis vector {w1, w2, ..., wk}.

Since u is in w⊥, by definition, it is orthogonal to every vector in w. Now, since {w1, w2, ..., wk} is a basis for w, any vector in w can be written as a linear combination of the basis vectors:

v = a1w1 + a2w2 + ... + ak*wk,

where a1, a2, ..., ak are scalars.

Now, consider the dot product of u with v:

u · v = u · (a1w1 + a2w2 + ... + ak*wk).

Using the distributive property of dot product, we have:

u · v = a1*(u · w1) + a2*(u · w2) + ... + ak*(u · wk).

Since u is orthogonal to every vector in w, each dot product term on the right-hand side becomes zero:

u · v = a10 + a20 + ... + ak*0 = 0 + 0 + ... + 0 = 0.

Therefore, u is orthogonal to v, which means it is orthogonal to every basis vector {w1, w2, ..., wk}.

Now, let's assume that a vector u is in v and is orthogonal to every basis vector {w1, w2, ..., wk}. We need to show that u is in w⊥.

To prove this, we'll show that u is orthogonal to every vector in w. Let's take an arbitrary vector w in w:

w = c1w1 + c2w2 + ... + ck*wk,

where c1, c2, ..., ck are scalars.

Now, consider the dot product of u with w:

u · w = u · (c1w1 + c2w2 + ... + ck*wk).

Using the distributive property of dot product, we have:

u · w = c1*(u · w1) + c2*(u · w2) + ... + ck*(u · wk).

Since u is orthogonal to every basis vector, each dot product term on the right-hand side becomes zero:

u · w = c10 + c20 + ... + ck*0 = 0 + 0 + ... + 0 = 0.

Therefore, u is orthogonal to w, which means it is orthogonal to every vector in w. Hence, u is in w⊥.

By proving both statements, we have shown that w⊥ consists of all vectors in v that are orthogonal to every basis vector {w1, w2, ..., wk}.

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Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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Answer:

58°+90°+x=180°

148°+x=180°

x=180°+148°

x= 32° is your answer ☺️☺️☺️

Answer:

32

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

The answer is correct and cannot be simplified any further. Can I get that brainliest thay you promised me last time?

Hope this helps

Answer:

The Answer is D!

Step-by-step explanation:

I think the answer is A sorry if it's wrong