The moment of inertia of a uniform disk about an axis perpendicular to the disk through the pivot point is (1/2) times the mass of the disk multiplied by the square of its radius.
The moment of inertia (I) of a uniform disk can be calculated using the formula I = (1/2) * m * r^2, where m represents the mass of the disk and r represents its radius. In this case, since the disk is suspended from a point on its rim and rotating about an axis perpendicular to the disk through the pivot point, the moment of inertia can be determined using this formula.
The (1/2) factor arises from the distribution of mass in a uniform disk, where the mass is concentrated towards the outer regions. Therefore, the moment of inertia of the uniform disk is (1/2) * m * r^2.
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What is magnetic force??
O A. A force between protons
O B. A force between two poles
O C. A force caused by air particles
O D. A force between objects with mass
Answer:
I believe it's B.
Explanation:
The force that a magnet exerts on certain materials, including other magnets, is called magnetic force. The force is exerted over a distance and includes forces of attraction and repulsion. North and south poles of two magnets attract each other, while two north poles or two south poles repel each other.
What is the range of a bullet fired horizontally at a height of 1. 5 m with an initial velocity of 120 m/s?.
We are unable to determine the bullet's firing range. Insufficient details exist for the range to be determined (option D)
The projectile's range is what.The horizontal distance that a missile travels from its projection point to its landing location is known as its range.
Range is defined as R= u2 sin 2/g, where u is the beginning velocity and is the angle of projection, hence the information in the previous question is insufficient to determine the bullet's range. Since the projection angle is not specified, this occurs. The projectile's range is influenced by the initial speed of the object.
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An object and its lens-produced real image are 2.4 m apart. If the lens has 55-cm focal length, what are the possible values for the object distance?
The possible object distances are 0.96 m and 3.44 m. We can use the lens equation: 1/f = 1/di + 1/do
where f is the focal length of the lens, di is the distance from the lens to the image, and do is the distance from the lens to the object.
We know that di - do = 2.4 m, so we can substitute this into the equation: 1/0.55 = 1/di + 1/(di - 2.4)
Simplifying this equation, we get:
di^2 - 2.4di - 0.55(di) + 0.55(di - 2.4) = 0
di^2 - 1.85di + 1.32 = 0
Using the quadratic formula, we can solve for di:
di = (1.85 ± sqrt(1.85^2 - 4(1.32)))/2
di = (1.85 ± 0.441)/2
di = 1.146 or 0.704
Now, we can use the lens equation again to solve for do:
1/0.55 = 1/1.146 + 1/do
do = 0.748 m
or
1/0.55 = 1/0.704 + 1/do
do = 1.073 m
Therefore, the possible values for the object distance are 0.748 m and 1.073 m.
To find the possible object distances for a lens with a given focal length and image distance, we'll use the lens formula: 1/f = 1/d_o + 1/d_i, where f is the focal length, d_o is the object distance, and d_i is the image distance. In this case, the lens has a focal length of 55 cm (0.55 m) and the object and its real image are 2.4 m apart. To find the possible values for the object distance, we need to consider two scenarios: when the object is closer to the lens than the image, and when the object is farther from the lens than the image.
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What is the force of gravity on Earth in Newton's?
Answer:
9.8 meters/second^2
Explanation:
formula: Fg=mg
a single-phase motor draws a current of 20a at 0.8pf laggign when operated from a 220 v, 60 hz source. find the value of the capacitance accross the motor that will raise the power factor to 0.9 lagging
The capacitance across the motor must be 86.87 f to increase the power factor to 0.9 lagging.
A single-phase motor is what?An electric rotating machine with the capacity to transform electrical energy into mechanical energy is known as a single-phase motor. It functions using a single-phase power source. They have hot and neutral wiring, respectively. Their supply voltages fluctuate in unison and their power can exceed 3Kw.
I1 = 20A, f = 50 Hz
cosϕ1 = 0.75 ⇒ ϕ1 = 41.41∘ ⇒ tanϕ1 = 0.88
cosϕ2 = 0.9 ⇒ ϕ2 = 25.84∘ ⇒ tanϕ2 = 0.48
Ic = I1 cosϕ1 (tanϕ1 − tanϕ2)
= (20) (0.75) (0.88 – 0.48) = 6 A
C = Ie/2πfv
C = 6/2π × 20 × 220
C = 86.87∪f
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what is the acceleration of the ball when it is moving up, when it is at the maximum height, and when it is moving down? (note: the acceleration graph is shown in red.)
The acceleration of the ball when it is moving up, at the highest point and when moving down is always constant and in downward direction.
When a ball is thrown upward, its acceleration is always constant.
When a ball is thrown, it is under the influence of gravity, the acceleration working on the ball is due to earth.
The acceleration given by the earth is called Acceleration due to gravity. When the ball is going upward. The acceleration is opposite to the motion of the ball. When the ball is moving downwards, the acceleration is in the direction of the motion of the ball.
When the ball is at highest point, the acceleration is still downwards.
Throughout the motion, the acceleration is constant in terms of direction as well as magnitude.
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which of the following are arranged from smallest unit to largest unit?
Which of the following are arranged from smallest unit to largest unit.The correct arrangement of units from smallest to largest is (D) mm, m, cm, km.
Millimeters (mm) are the smallest unit in the list, representing one-thousandth of a meter. They are commonly used to measure small distances or the size of objects. Meters (m) are the next unit in size, representing the basic unit of length in the metric system. They are used for measuring everyday distances and are often the standard unit of measurement in scientific and engineering applications.
Centimeters (cm) come after meters. They represent one-hundredth of a meter and are frequently used to measure smaller distances or dimensions. Kilometers (km) are the largest unit in the list, representing one thousand meters. They are typically used to measure longer distances such as the length of roads, distances between cities, or the size of geographical areas. Thus, the correct arrangement is (D) mm, m, cm, km, which progresses from the smallest unit (mm) to the largest unit (km).
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Complete question:
Which of the following are arranged from smallest unit to largest unit?
(A) cm, m, mm, km
(B) km, m, mm, cm
(C) cm, mm, m, km
(D) mm, m, cm, km
Which legal measure allowed whites in southern states to keep blacks from voting after reconstruction ended?.
Jim Crow laws was the legal measure which allowed whites in southern states to keep blacks from voting after reconstruction ended.
What was JIm Crow law?These were the state and local laws which enforced racial segregation in the Southern part of the United States.
Due to this laws, whites in southern states kept blacks from voting after reconstruction ended.
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derp derp derp chicken strips don't answer lol i just want to be here.
Answer:
ok lol
Explanation:
ok but I will still answer
Answer:daddy
Explanation:
New ecosystems have been created by human land use.
Answer:
Yes
Explanation:
When humans use land, they change it to accommodate their own needs, and thus new locations and new habitats for other organisms are created. These organisms can now live there and create new organisms, and thus create new ecosystems as a result of human use of that particular piece of land.
which statement illustrates how progress in engineering has affected the natural enironment
The statement that illustrates how progress in engineering has affected the natural environment is extracting mineral resources with modern mining equipment removes fertile topsoil.
What is the Natural Environment?The natural environment may be defined as anything that can be present in the surroundings of living entities whether it is a biotic or abiotic factor.
The utilization of contemporary mining tools terminates fertile topsoil and admiringly impacts the fertility of the soil. It is tough to rebuild topsoil and modern mining tools constantly damage soil fertility.
Advancement in engineering has influenced the natural environment and mining is one of the most accepted measures of this.
The complete question is as follows:
Extracting mineral resources with modern mining equipment removes fertile topsoil.Mining companies use modern equipment to extract mineral resources more efficiently.Modern mining equipment has improved the health and safety of workers.Modern mining practices provide materials that can be used for technological advances.Therefore, it is well described above.
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Determine the horizontal displacement of a projectile if it has a flight time of 8 seconds and a horizontal velocity of 14 m/s
\(\\ \rm\bull\rightarrowtail Displacement=Velocity\times Time\)
\(\\ \rm\bull\rightarrowtail Displacement=8(14)\)
\(\\ \rm\bull\rightarrowtail Displacement =112m\)
During capillary action, the water will rise higher in which situation?
During capillary action, the water will rise higher in a narrower tube or channel with a smaller diameter.
This is because the smaller diameter creates a greater surface tension, which pulls the water upward against gravity. Additionally, a surface with a higher degree of attraction to the water molecules will also enhance capillary action, allowing the water to rise higher.
This is because the adhesive forces between the water molecules and the tube's surface, as well as the cohesive forces between the water molecules themselves, are stronger in smaller diameter tubes, leading to a greater capillary rise.
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Light of a certain wavelength passes through
a pair of double slits with separation
21.00 micrometers (um) and falls on a
screen. If the angle between the center and
2nd interference maximum is 3.000°, what is
the wavelength in nanometers (nm)?
[?] nm
The wavelength of the light is approximately 402 nm.
What is the wavelength of the light?The distance between the slits, d = 21.00 μm = 21.00 × 10^-6 m.
The angle between the center and 2nd interference maximum, θ = 3.000° = 0.0523599 radians (using conversion factor 1° = π/180 radians).
The distance between the central maximum and the 2nd interference maximum is given by:
y = L tan(θ)
where;
L is the distance between the double slits and the screen.We can use the small angle approximation to simplify the equation as sin(θ) ≈ θ for small values of θ. So we have:
y ≈ L θ
The path difference between the waves from the two slits that produce an interference maximum is given by:
δ = d sin(θ)
At the 2nd interference maximum, the path difference is equal to the wavelength λ:
λ = δ = d sin(θ)
Substituting the given values, we get:
λ = (21.00 × 10^-6 m) sin(0.0523599 radians)
λ ≈ 4.02 × 10^-7 m = 402 nm
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What type of resistance in an ac transformer circuit?
In an AC transformer circuit, the type of resistance is called "impedance."
Impedance is a complex measure of resistance in AC circuits, which takes into account not only the resistive component (due to resistance in wires and components), but also the reactive component due to inductance and capacitance.
Impedance is crucial in AC transformer circuits, as it affects the voltage and current relationship, and the power transfer efficiency.
Summary: The resistance in an AC transformer circuit is referred to as "impedance," which encompasses both resistive and reactive components and affects the performance of the circuit.
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On a typical day at an ocean port, the water has a maximum depth of 20m at 8:00 am. The minimum depth of 8m occurs 6.2hrs later. Assume that the relation between time and water depth is a sinusoidal function. The period and median depth of this data are
The median depth of the sinusoidal function is 14m represents the average or middle value of the water depth over one complete cycle.
To determine the period and median depth of the sinusoidal function that relates time and water depth at the ocean port, we need to analyze the given information.
The period of a sinusoidal function represents the time it takes for one complete cycle. In this case, the period would be the time it takes for the water depth to repeat its pattern.
Given that the maximum depth of 20m occurs at 8:00 am and the minimum depth of 8m occurs 6.2 hours later, we can calculate the period as follows:
Period = Time for one complete cycle = Time of minimum depth - Time of maximum depth
Period = 6.2 hours
Finally, the period of the sinusoidal function is 6.2 hours.
The median depth represents the average or middle value of the water depth over one complete cycle. To find the median depth, we can calculate the average of the maximum and minimum depths:
Median depth = (Maximum depth + Minimum depth) / 2
Median depth = (20m + 8m) / 2
Median depth = 14m
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if the ball is thrown fast enough at the target, the target will swing into a horizontal position where it will be held in place by a magnet. what is (va)1min , the minimum velocity of the ball required to swing the target into the horizontal position?
Calculate the minimum kinetic energy needed for the target to reach the horizontal position against the force of gravity and the magnetic force. The minimum velocity of the ball (va)1min required to achieve this outcome.
We need to consider the relationship between the velocity of the ball and the force required to swing the target into a horizontal position. This can be calculated using the formula: F = ma
where F is the force required, m is the mass of the target, and a is the acceleration caused by the ball hitting the target.
Assuming that the magnet can hold the target in place once it swings into a horizontal position, we can determine the minimum velocity (va)1min required by setting the force required equal to the magnetic force holding the target in place.
This can be expressed as: F = BIL
where B is the magnetic field strength, I is the current passing through the magnet, and L is the length of the target.
By equating these two forces, we can solve for (va)1min :
ma = BIL
(va)1min = sqrt(BIL/m)
The minimum velocity required to swing the target into a horizontal position can be calculated using the above equation. To determine the minimum velocity (va)1min of the ball required to swing the target into a horizontal position, three factors need to be considered: the mass of the ball, the mass of the target, and the force exerted by the magnet.
Analyze the energy and momentum involved in the collision between the ball and the target. The ball's kinetic energy before impact must be sufficient to overcome the target's rotational energy and gravitational potential energy after the collision.
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a 60 kg skydiver is falling at a terminal velocity of 50 m/s. calculate the amount of gravitational force acting on the skydiver. responses 0 n 0 n 588 n 588 n 3000 n 3000 n 9.8 n
The amount of gravitational force acting on the skydiver is 588 N.
Gravitational force, also known as gravity, is a fundamental force of nature that attracts objects with mass towards each other. It is the force that gives weight to objects and keeps them grounded on the Earth's surface.
The gravitational force acting on an object can be calculated using the formula:
F = m * g
Where:
F is the gravitational force
m is the mass of the object
g is the acceleration due to gravity
In this case, the mass of the skydiver is given as 60 kg, and the acceleration due to gravity is approximately 9.8 m/s².
Plugging these values into the formula:
F = 60 kg * 9.8 m/s²
F = 588 N
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define refraction of light
Answer:
Refraction is the slowing down of light waves as they pass into a different medium and speeding as they pass out.
hope it helps. plz mark me as brainliest.
2.2 Forces of 9 N acting horizontally to the right and 5 N in the opposite direction; 12 N acting vertically upwards and 6 N vertically downwards. Forces of 75 N acting vertically downwards and 50 N vertically upwards;
2.3 Forces of 75N acting vertically downwards and 50N vertically downwards;45 N horizontally towards the right and 23N in the opposite direction
(2.2 ) The resultant of the forces are 19 N downwards and 4 N to the right.
(2.3 ) The resultant of the forces are 125 N downwards and 22 N to the right.
What is the resultant force on the object?
The resultant force on the object is the sum of all the forces acting on the object in a particular direction.
for the first given forces,
sum of the vertical forces = 12 N + 50 N - 6 N - 75 N = 19 N downwards
sum of horizontal forces = 9 N - 5 N = 4 N to the right
for the second given forces,
sum of the vertical forces = -75 N - 50 N = 125 N downwards
sum of horizontal forces = 45 N - 23 N = 22 N to the right
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The complete question is below:
2.2 Forces of 9 N acting horizontally to the right and 5 N in the opposite direction; 12 N acting vertically upwards and 6 N vertically downwards. Forces of 75 N acting vertically downwards and 50 N vertically upwards;
2.3 Forces of 75N acting vertically downwards and 50N vertically downwards;45 N horizontally towards the right and 23N in the opposite direction . find the resultant of each forces
Use trigonometry to find the missing values of the sides of the triangles below.
Explanation:
tan ● = opposite / adjacent
tan 31.5 = 19 / F
0.613 = 19 / F
0.613F = 19
F = 31
sin ● = opposite / hypotenuse
sin 31.5 = 19 / a
0.52 = 19 / a
0.52a = 19
a = 36. 36
Using trigonometry, the base of the triangle is approximately 33.476, and the hypotenuse of the triangle is approximately 38.118.
To find the base and hypotenuse of a right triangle with one angle of 31.5 degrees and a given height of 19:
Here,
Opposite side = height = 19 (given)
Adjacent side = base (unknown)
Hypotenuse = hypotenuse (unknown)
First, let's find the base (adjacent side):
tan(θ) = opposite ÷ adjacent
tan(31.5 degrees) = 19/base
To find the base, we can rearrange the equation:
base = opposite ÷ tan(θ)
base = 19 ÷ tan(31.5 degrees)
Calculating the value:
base ≈ 33.476
So, the base of the triangle is approximately 33.476.
Now, using the Pythagorean theorem, we can write:
hypotenuse² = base² + opposite²
hypotenuse² = (33.476)² + 19²
hypotenuse ≈ 38.118
Therefore, the hypotenuse of the triangle is approximately 38.118.
Thus, base is 33.476, and hypotenuse is 38.118.
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An energy service company wants to use hot springs to power a heat engine. If the groundwater is at 95 Celsius, estimate the maximum power output if the mass flux is 0.2 kg/s. The ambient temperature is 20 Celsius. Enter the value in kW, use all decimal places and enter only the numerical value.
The estimated maximum power output of the heat engine using hot springs with a groundwater temperature of 95 °C and a mass flux of 0.2 kg/s is approximately 0.0128 kW.
To estimate the maximum power output of the heat engine using hot springs, we can utilize the concept of the Carnot cycle, which provides an upper limit for the efficiency of a heat engine.
The Carnot efficiency is given by the formula:
η = 1 - (Tc/Th)
Where η is the efficiency, Tc is the temperature of the cold reservoir (ambient temperature), and Th is the temperature of the hot reservoir (groundwater temperature).
Given:
Tc = 20 °C = 293 K
Th = 95 °C = 368 K
The maximum power output can be calculated using the formula:
P = η * Q
Where P is the power output and Q is the heat transfer rate.
The heat transfer rate can be calculated using the formula:
Q = m * Cp * (Th - Tc)
Given:
m = 0.2 kg/s (mass flux)
Cp = specific heat capacity of water ≈ 4.18 kJ/kg°C
Let's calculate the maximum power output:
Tc = 293 K
Th = 368 K
m = 0.2 kg/s
Cp = 4.18 kJ/kg°C = 4.18 J/g°C = 4.18 * 10⁻³ J/kg°C
Q = m * Cp * (Th - Tc)
= 0.2 kg/s * 4.18 * 10⁻³ J/kg°C * (368 K - 293 K)
= 0.2 * 4.18 * 10⁻³ * 75
= 0.0627 kW
η = 1 - (Tc/Th)
= 1 - (293/368)
≈ 0.204
P = η * Q
= 0.204 * 0.0627 kW
≈ 0.0128 kW
Therefore, the estimated maximum power output of the heat engine using hot springs with a groundwater temperature of 95 °C and a mass flux of 0.2 kg/s is approximately 0.0128 kW.
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PLEASE NEED THIS ASAP GRADE DEPENDS ALOT OF POINTS FOR AN ANSWER WILL MARK BRAINLIEST PLEASE
Three point charges are arranged in a straight line. The point charges are q₁ = -10.0 μC, q2 = 20.0 μC, and q3 = -10.0 µC. Charge q, is 20.0 cm from charge q2, and charge q3 is 10.0 cm from charge 92. Determine the magnitude of the net electric force on charge q1
Answer:
-44.95N
Explanation:
electric force = kQ / r²
= 8.99×10^9 × -10.0×10^-6 / 20×10^-2 = -44.95N
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2. the wave Speed is 0.25m/s and the cark moves
Up and down 4 times in 8 seconds.
Caculate The
wavelength?
Since we don't know the frequency, we can't give a specific numerical value for the wavelength. But by using another we can get wavelength = 0.25m/s / frequency as wavelength.
To calculate the wavelength, we need to use the formula:
wavelength = wave speed/frequency
However, the frequency is not given in the question. Therefore, we need to use another formula that relates frequency to the speed and wavelength:
frequency = wave speed/wavelength
We can rearrange this formula to solve for wavelength:
wavelength = wave speed/frequency
Substituting the given wave speed of 0.25m/s, we have:
wavelength = 0.25m/s / frequency
However, we can say that the wavelength will be inversely proportional to the frequency. This means that if the frequency is high, the wavelength will be short, and vice versa.
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A force of 450 newtons was necessary to lift a cement block. a total of 250 joules of work was done. how far was the cement block lifted?
Answer:
0.56 meters
Explanation:
Work = Force x Displacement
Let X be the displacement.
250 Joules = (450 Newtons)*X
X = (250 Joules)/(450 Newtons)
A Joule is 1kg*m^2/sec^2 or Newton*m
A Newton is 1kg*m/sec^2
X = (250 Newton*m)/(450 Newtons)
X = 0.56 meters
Find the minor measurement of the vernier scale by taking 49, 1mm divisions of the main scale and dividing it into 50 vernier divisions.
length of V-50 = 49mm
length of V-1 = 49/50mm
= 0.98mm
so,
minor measurement = (M-1) - (V-1)
= 1mm -0.98mm
= 0.02mm
☆ Therefore,
The minor measurement of the vernier scale is 0.02mm.
☆...hope this helps...☆
_♡_mashi_♡_
how much work is done per cycle if the engine's thermal efficiency is 40.0 % ? give your answer in kj
When it comes to a heat engine, how much work is done per cycle if the engine's thermal efficiency is 40.0 %?To calculate the amount of work done per cycle by a heat engine, the Carnot efficiency formula may be used, which is given as:η = 1 - T2/T1whereη: Thermal efficiency, T1
Temperature at which heat is added, and T2: Temperature at which heat is rejected.The Carnot cycle is an idealized thermodynamic cycle that includes four distinct steps :isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression. The work produced per cycle by the engine is the difference between the heat absorbed during the isothermal expansion and the heat rejected during the isothermal compression.To calculate the amount of work done per cycle, we'll start with the equation:η = 1 - T2/T1whereη = 0.40 (Given), andT2/T1 = (100 + 15) / (100 + 815) = 115 / 915 = 0.1253, which was converted to a percentage by multiplying by 100.ΔT = T1 - T2 = 815 – 15 = 800 KQH = QL / η = W = QL – QH = QL (1- η)Since QH = QL + W, the above equation becomesQL(1 – η) = QL + WSubstituting values,QH = (QL) [1 / (1 – η)]QL (1 – 0.40) = QL + WQL(0.60) = QL + W0.60QL = QL + WThus, W = 0.60QLThe amount of work done per cycle if the engine's thermal efficiency is 40.0 % is 60% of the heat absorbed during isothermal expansion.for more such question on thermodynamic
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work done by a gravitational force by lowering the bucket into the well is
Answer:
when we lower a bucket into a well to fetch water, the work done by gravity is positive since force and displacement are in the same direction.
Explanation:
Hello, I am trying to solve this physics question, thanks.
When they were falling, their acceleration is equal to the gravity acceleration.
When they started stopping, the time required to stop is 1.5 seconds, that is, 3 times less than the time accelerating.
Since the change in velocity when falling and when stopping is the same (same magnitude but opposite signal), the acceleration when stopping will be 3 times more than the acceleration when falling (because the change in velocity is the same and the time is 3 times less).
So we have:
\(\begin{gathered} a=-3g\\ \\ a=-3\cdot(-9.8)\\ \\ a=29.4\text{ m/s^^b2} \end{gathered}\)Therefore the acceleration is 29.4 m/s².
2.
The IMA of an inclined plane 8m long and 2m high is ______.
16
4
2
8
Answer:
Explanation:
4