Answer:
∆PE = 749.7 J
At 0.9 m high, PE = 793.8 J
At 1.75 m high, PE = 1543.5 J
Calcular la aceleración que produce una fuerza de 40 N sobre un cuerpo con 88 Kg de masa. Expresar el resultado en m⁄s^2 *
Answer:
a = 0.45 m/s²
Explanation:
The given question is ''Calculate the acceleration that produces a force of 40 N on a body with 88 kg of mass".
Given that,
Force, F = 40 N
Mass of the body, m = 88 kg
The net force acting on the body is given by :
F = ma
Where
a is the acceleration of the body
\(a=\dfrac{F}{m}\\\\a=\dfrac{40\ N}{88\ kg}\\\\a=0.45\ m/s^2\)
So, the required acceleration is 0.45 m/s².
When a bird alights upon a stretched power line wire, does the tension in the wire change? If so, is the increase more than, less than, or about equal to the bird's weight?
When a bird alights upon a stretched power line wire, the tension in the wire does change. The increase in tension is about equal to the bird's weight, as the wire needs to support the additional weight of the bird.
When a bird alights upon a stretched power line wire, the tension in the wire does change. The increase in tension depends on the weight of the bird and the elasticity of the wire. The increase in tension is generally about equal to the weight of the bird. However, if the wire is very elastic, the increase in tension may be less than the weight of the bird. Overall, the change in tension is relatively small and is unlikely to cause any significant issues with the power line.
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Which of the following statements supports the claim that a planet travels around a star in an elliptical orbit? (1 point)
Every 30 days, the area swept in space by the planet is the same.
Every 30 days, the distance traveled by the planet is different.
Every 30 days, the speed the planet is moving is different.
I only
I and II
II and III
I, II, and III
Answer:
A
Explanation:
if it was in the same place it wold be a pattern which is what is usually seen in orbits
A loaded spring launches a 2.50 kg block, using a force of 450 N. If the change in
momentum is 12.0 kg*m/s, how long was the block in contact with the spring?
Answer:
37.5 seconds
Explanation:
The given parameters are;
The mass of the block on the spring, m = 2.50 kg
The force with which the loaded spring launches the block, F = 450 N
The change in momentum of the block, Δp = 12.0 kg·m/s
We have;
Let the force with which the block was launched = The net force, \(F_{NET}\)
By Newton's second law of motion, we have;
F = \(F_{NET}\) = Δp × Δt
Where;
Δt = The time the block is in contact with the spring
Therefore;
\(\Delta t = \dfrac{F_{NET}}{\Delta p}\)
By plugging in the values for \(F_{NET}\) and Δp, we have;
\(\Delta t = \dfrac{450 \ N}{12.0 \ kg \cdot m/s} = 37.5 \ s\)
The time duration the block is in contact with the spring, Δt = 37.5 seconds.
The mass of a certain man is 250g..
I. What is the weight of the man on earth
ii. What is the weight of the man on the moon
I promise to mark u the brainliest, please help me
Answer:
2,450
400
Explanation:
Pls brainliest me
Help me with this question please
Answer:
Its true i'm pretty sure
Explanation:
Answer:
The answer is True
Explanation:
because it is and I suck at explaining
the atmospheric pressure in millibars at altitude x meters can be approzimated by the following function. the function is valid for values of x between 0 and 10,000. f(x)= 1038(1.000134)^-x when x between 0 and 10,000. a. What is the atmospheric pressure at sea level? b. The McDonald Observatory in Texas is at an altitude of 2000 meters. What is the approximate atmospheric pressure there? c. As altitude increases, what happens to atmospheric pressure?
The approximate atmospheric pressure at an altitude of 2000 meters is approximately 869.43 millibars. The atmospheric pressure in millibars at altitude x meters can be approzimated by the following function. the function is valid for values of x between 0 and 10,000. \(f(x)= 1038(1.000134)^-x\) when x between 0 and 10,000.
a. The atmospheric pressure at sea level can be found by putting x=0 in the given functionTo find the atmospheric pressure at sea level (x = 0), we can substitute x = 0 into the given function:
f(x) = \(1038(1.000134)^-x\)
f(0) = \(1038(1.000134)^0\)
f(0) = 1038
Therefore, the atmospheric pressure at sea level is approximately 1038 millibars.
b. To find the approximate atmospheric pressure at an altitude of 2000 meters (x = 2000), we can substitute x = 2000 into the given function:
f(x) =\(1038(1.000134)^-x\)
f(2000) = \(1038(1.000134)^-2000\)
Using a calculator or computer program to evaluate this expression, we find that the approximate atmospheric pressure at an altitude of 2000 meters is approximately 869.43 millibars.
c. As altitude increases, the atmospheric pressure generally decreases. This is because as we move higher in the atmosphere, there is less air above us exerting pressure downward. The decrease in atmospheric pressure with increasing altitude is due to the decreasing density of air molecules as we move away from the Earth's surface.
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How do Convergent boundaries move? (I don't need to know "plates move toward each other" which is the only answer I can find. I need to know how. Please help
if space has a hyperbolic geometry, what will happen to two initially parallel flashlight beams as they traverse billions of light-years of space?
In a space with hyperbolic geometry, the behavior of parallel lines differs from that of Euclidean geometry.
In hyperbolic space, parallel lines diverge from each other as they extend further.If two initially parallel flashlight beams traverse billions of light-years of space in a hyperbolic geometry, they will gradually diverge from each other. The divergence between the beams will increase as they travel a greater distance.
This phenomenon is a consequence of the non-Euclidean geometry of space. In hyperbolic space, the curvature causes parallel lines to "spread out" or diverge. The extent of the divergence will depend on the specific curvature of the space and the distance traveled.
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What is the angular acceleration of its tires in rad/s2, assuming they have a radius of 0.29 m and do not slip on the pavement
The angular acceleration of the tire is 35.17 rad/s², assuming that the tires have a radius of 0.29 m and do not slip on the pavement.
We need to find the angular acceleration, α.Here, we know that the tire does not slip on the pavement. Therefore, the linear velocity of the tire can be determined using the equation of linear velocity, which is expressed as
v = rω
where
v = linear velocity,
r = radius of the object
ω = angular Velocity
Let's rearrange the equation of linear velocity to find the angular velocity,ω as follows:
ω = v/r
Now, we can find the linear acceleration of the tire using the given information of its linear speed as follows:
Linear acceleration, a = 10.2 m/s²
Therefore, the value of ω can be calculated as
ω = v/r = a/r = 10.2/0.29 = 35.17 rad/s
Now, substituting the value of a/r and r in the formula of angular acceleration,α = a/r= 10.2/0.29= 35.17 rad/s²
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a ball is dropped from a window and bounces three times. the first bounce is 60 centimeters high. The second bounce is 40 centimeters high. The third bounce is 15 centimeters high. The ball then rolls and comes to a stop. What was happened to the energy of the ball when it has come to stop?
The potential energy of the ball has increased during energy transfer.
We know that potential energy is position relative, and kinetic energy is motion relative. The primary relationship between the two is their ability to transform into each other. In other words, potential energy transforms into kinetic energy, and kinetic energy converts into potential energy, and then back again. It’s a never-ending cycle. So, when the ball came to rest the potential energy of the ball has increased.
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How should the amount of elastic potential energy when the spring is fully stretched compare to the amount of kinetic energy when the spring is relaxed?
If there are no dissipative forces acting on the string, than the principle of conservation of energy holds.
When the string is relaxed, it has zero elastic potential energy
If we were strech the she spring, we would increase it's potential energy. After releasing the spring, when it's relaxed again, all potential energy will have been converted into kinetic energy.
Therefore, the elastic potential energy of the stretched spring should be equal to the amount of kinetic energy when it's relaxed
True or False a stranded conductor with the same circular-mil rating of a solid conductor has a greater surface area and flexibility than the solid conductor.
It is true that a standard conductor with the same circuit-mil rating of a solid conductor has a greater surface area and flexibility than the solid conductor.
A standard conductor consist of many thin wires of small cross-sectional areas called strands, because of this they can be coiled easily to transport current over long distances. Moreover, the flexibility of the standard conductor increases as the number of strands increase.
This standard conductor has better conductance than the solid conductor because the individual wires together have a greater surface area. This standard conductor is formed by twisting the strands to form layers. This process is called stranding.
The centre of the standard wire is made of steel strand that gives high tensile strength to the conductor and hence is more flexible along with having more surface area than the solid conductor.
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Rank the water levels of a mixed-tide system according to height. Put the highest water level on top.
higher high water
lower high water
higher low water
lower low water
Higher high water
Lower high water
Higher low water
Lower low water
In a mixed-tide system, the water levels exhibit two high tides and two low tides within a tidal cycle. The ranking of the water levels according to height is as follows:
Higher high water: This is the highest water level observed during the tidal cycle. It occurs when the gravitational forces of the Moon and the Sun align to produce a stronger tidal bulge. It typically happens around the time of a new moon or a full moon.
Lower high water: This is the second-highest water level observed during the tidal cycle. It occurs when the gravitational forces of the Moon and the Sun are not aligned, resulting in a weaker tidal bulge. It typically happens around the time of the first quarter and third quarter moon phases.
Higher low water: This is the higher of the two low water levels observed during the tidal cycle. It occurs when the gravitational forces of the Moon and the Sun produce a weaker tidal trough. It typically happens between the two high tides.
Lower low water: This is the lowest water level observed during the tidal cycle. It occurs when the gravitational forces of the Moon and the Sun are not aligned, resulting in a stronger tidal trough. It typically happens between the higher low water and the next high tide.
The ranking of water levels in a mixed-tide system, from highest to lowest, is: higher high water, lower high water, higher low water, lower low water
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A 12.0-V battery can deliver about 8.27 x 10^5 C of charge before dying. calculate the maximum number of kilograms of water (100°C) that could be boiled into steam (100°C) using energy from this battery.
The electrical work needed to heat a kilogram of water by 1.0°C is 4186 J, while the heat of vaporization of water is 2.26 x 106 J/kg. A 12.0 V battery can provide about 8.27 x 105 C of charge until it dies. Determine the maximum number of kilograms of water (100°C) that can be boiled into steam (100°C) using the energy from this battery.
Determine the energy supplied by the batteryThe energy provided by the battery is calculated using:Q = V × I × twhere, Q = Charge supplied by the battery = 8.27 x 105 C (Coulomb)V = Battery voltage = 12.0 VI = Current = Q/tt = Time taken = Q/I = 8.27 x 105/ IThe amount of electrical energy supplied by the battery is:E = V × Q = 12.0 V × 8.27 x 105 C = 9.92 x 106 JStep 2: Determine the mass of water (100°C) that can be heated using the electrical energy supplied by the batteryQ = m × c × ΔTwhere,Q = Electrical energy supplied by the battery = 9.92 x 106 JC = Specific heat capacity of water = 4186 J/kg-KΔT = Change in temperature = 100 - 20 = 80 K (Assuming room temperature is 20°C)m = Mass of water (100°C) to be heated:
Determine the mass of water (100°C) that can be boiled into steam (100°C) using the energy supplied by the batteryQ = m × c × ΔT + mLvwhere,Q = Energy supplied by the battery = 9.92 x 106 JC = Specific heat capacity of water = 4186 J/kg-KΔT = Change in temperature = 100 - 20 = 80 K (Assuming room temperature is 20°C)m = Mass of water (100°C) to be heatedLv = Latent heat of vaporization of water = 2.26 x 106 J/kgm = (Q - mLv) ÷ (c × ΔT) = (9.92 x 106 - (m × 2.26 x 106)) ÷ (4186 × 80)m = (9.92 x 106 - 2.26 x 106m) ÷ (334880)m = (9.92 - 2.26 x 10-3m)/334.88On simplification,m = 32.7 kgThus, 32.7 kg of water at 100°C can be boiled into steam using the electrical energy supplied by the 12.0 V battery.
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What efforts are made to bring uniformity in measurement
Answer: The use of S I Unit brings uniformity in measurements.
Explanation:
The S I unit is the international system of units which are used to express the magnitudes or quantities of important natural phenomena. It is used universally as a standard for measurements thereby creating an avenue for uniformity in measurements. The base units that makes up the SI unit are:
--> Length: this is measured in meters (m)
--> Time: this is measured in seconds (s)
--> Mass: this is measured in kilogram (kg)
--> Temperature: this is measured in Kelvin (k)
--> Electric current: this is measured in ampere (A).
--> Amount of substance: this is measured in mole
--> Luminous intensity: this is measured in candela (cd)
These units are used as the standard to make our judgement of measurement more reliable and accurate. And since there is only one basic unit for each quantity (example length which is measured in meters) there is no need for further conversions.
in order to pass the conductor up through the double-locking grip head, the cam's locking ring around the head needs to be in the ? position.
Unlocked position. The cam is used to lock the conductor in place, so the locking ring needs to be in the unlocked position in order for the conductor to be passed through the grip head.
What is conductor ?A conductor is a person or object that allows the flow of electric current or heat. In electrical systems, a conductor provides a path for the electric current to flow from the power source to the device being powered. In heating systems, a conductor carries the heat from the source to the device or area that needs to be heated. Conductors are typically made of metal, such as copper, aluminum, and silver, as these materials have a higher electrical conductivity than most other materials.
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In induction, what charge does a neutral substance gain compared to the object brought near it?
Explanation:
In induction, what charge does a neutral substance gain compared to the object brought near it?
The neutral object gains the same type of charge as the object that touched it because the electrons move from one object to the other (Figure 10.16). Induction is the movement of electrons within a substance caused by a nearby charged object, without direct contact between the substance and the object.
The charge gained by the neutral substance, gained compared to the object brought near it, had the same kind of charge that was present when it touched it.
What is induction?The alteration of the distribution of electric charge on a substance is caused by the effect of induction. A negatively charged object brought close to an electrically neutral object causes a positive charge on the near side and a negative charge on the far side of the neutral object as a result of the electric force between charged particles that make up materials.
This very little polarization, or separation of charge, lessens the electric field inside the dielectric.
Because the electrons go from one thing into the next, the neutral object acquires the same kind of charge that was present when it touched it. Lacking physical touch, induction is the movement of electrons within a substance as a result of a nearby charged item.
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at what point does water in the air change from a gas (vapor) to a liquid
Answer:
Dew point.
Explanation:
As the temperature of water vapor decreases, it will reach the point at which it turns into a liquid. This point is called dew point. The change of water from its gaseous state to liquid water is called condensation. Dew point is the temperature at which condensation happens.
Which situation will produce the greatest change of momentum for a 1. O-kilogram cart?
(A) accelerating it from rest to 3. 0 m/s
(B) accelerating it from 2. 0 m/s to 4. 0 m/s (C) applying a net force of 5. 0 N for 2. 0 m/s
(D) applying a net force of 10. 0 N for 0,5 m/s
Applying a net force of 10.0 N for 0.5 m/s will produce the greatest change of momentum for a 1.0-kilogram cart.
The situation that produces the greatest change of momentum for a 1.0-kilogram cart is (D) applying a net force of 10.0 N for 0.5 m/s. This option results in the greatest change in momentum as it involves the greatest impulse. Impulse is the product of force and time or the change in momentum of an object. The impulse can be calculated using the formulaImpulse (J) = force (F) x time (t)or J = FtWhen a force is applied to an object, it creates a change in momentum. The greater the force or the longer the time of application of the force, the greater the change in momentum. A net force of 10.0 N is applied for 0.5 s. Therefore, the impulse generated is given by J = (10.0 N) x (0.5 s) = 5.0 Ns.Due to the impulse, the velocity of the cart will change from its initial velocity. As momentum is conserved, the change in momentum of the cart will be equal to the impulse applied to it.
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Which of the following is a consequence of the special theory of relativity?
A) A moving object's mass is constant regardless of its speed.
B) Time slows as the speed of an observer's frame of reference increases
C) A stretching of time due to a moving object can be seen under normal conditions
D) It is possible for an object with mass to travel at the speed of light.
Answer:
D.
Explanation:
Specifically, Special Relativity showed us that space and time are not independent of one another but can be mixed into each other and therefore must be considered as the same object, which we shall denote as space-time. The consequences of space/time mixing are: time dilation. and length contraction.
In order to change a 2.15 kg handcart's velocity from 1.2 m/s
east to 1.8 m/s east, what's the magnitude of the impulse that
should be applied to the handcart?
a
38.7 N-s
b 12.9 N-S
2.58 N-S
d 3.87 N-s
e
1.29 N.S
Answer: E 1.29 N•s
Explanation: math
Can I answer my own question
Answer:
Well okay do it what's your question ?
Answer:
yes
Explanation:
A telephoto lens for a camera has focal length 0.250 m and maximum aperture f/4.00. Take the wavelength of visible light to be 5.50 x 10-7m. Assuming that the resolution is limited by diffraction, how far away can an object be for you to be able to resolve two points on the object that are 5.00 mm apart? Express your answer with the appropriate units. ЦА ? Value Units Submit Request Answer Part D How far apart are the corresponding points on the image made by the lens? Express your answer with the appropriate units. μΑ ? Value Units Submit Request Answer Reviewi Constants Part C An astronomer who is studying the light from a galaxy has identified the spectrum of hydrogen but finds that the wavelengths are somewhat shifted from those found in the laboratory. In the lab, the H, line in the hydrogen spectrum has a wavelength of 656.3 nm. The astronomer is using a transmission diffraction grating having 5558 lines/cm in the first order and finds that the first bright fringe for the Holine occurs at 23.31 from the central spot. How fast is the galaxy moving? Express your answer in m/s and as a percentage of the speed of light. Is the galaxy moving toward us or away from us? Find the wavelength of the H, spectral line in the received light. Express your answer with the appropriate units. View Available Hint(s) μΑ ? AR = Value Units Submit Part D Rewrite the equation of Doppler effect as a formula for the velocity v of the galaxy in terms of the received wavelength and the wavelength emitted by the source. Express your answer in terms of the emitted wavelength is, the velocity of the source v, and the speed of light c.
The formula for the velocity of the galaxy is given asv = (cλ - λ0) / λ0where v is the velocity of the galaxy, λ is the received wavelength, and λ0 is the actual wavelength. getv = (3.00 x 10^8 m/s x 6.562 x 10^-7 m - 656.3 x 10^-9 m) / 656.3 x 10^-9 mv = 29985 m/s
Part AThe formula for diffraction is given asD = λ / aWhere D is the angular resolution, λ is the wavelength of the light, and a is the diameter of the lens.The diameter of the lens is given asD = f / (2r)Where D is the diameter of the lens, f is the focal length, and r is the aperture of the lens.Substituting the value of D in the formula for diffraction, we getD = λ (2r) / fPutting the values of the given parameters, we getD = (5.50 x 10^-7 m) (2 x 0.250 m) / 4.00D = 8.63 x 10^-8 radThe angular separation of the two points is given asθ = d / Dwhere d is the linear separation of the two points.Substituting the given values, we get8.63 x 10^-8 rad = 5.00 x 10^-3 m / dSolving for d, we getd = 5.78 x 10^4 mPart B.
Using the formula for angular magnificationm = f / (f - d)where m is the angular magnification, f is the focal length, and d is the distance of the object from the lens.Substituting the given values, we getm = 0.250 m / (0.250 m - 5.78 x 10^4 m)m = -3579.6As the angular magnification is negative, the image is inverted and real.Using the formula for linear magnificationM = -f / (f - d)where M is the linear magnification, f is the focal length, and d is the distance of the object from the lens.
Substituting the given values, we getM = -0.250 m / (0.250 m - 5.78 x 10^4 m)M = 0.0004The image is 0.0004 times the size of the object, and is inverted and real. Part CThe observed wavelength of the hydrogen spectral line is given asλ = λ0 (sin θ + k)where λ is the observed wavelength, λ0 is the actual wavelength of the spectral line, θ is the angle made by the first bright fringe with the central spot, and k is a constant. Substituting the given values, we getλ = 656.3 nm (sin 23.31° + k)Solving for k, we get k = -0.3814Substituting the value of k in the equation for λ, we getλ = λ0 (sin θ - 0.3814)Solving for λ0, we getλ0 = λ / (sin θ - 0.3814).
Substituting the given values, we getλ0 = (656.3 x 10^-9 m) / (sin 23.31° - 0.3814)λ0 = 6.562 x 10^-7 mThe Doppler formula is given asΔλ / λ0 = v / cwhere Δλ is the difference between the observed wavelength and the actual wavelength, v is the velocity of the source, and c is the speed of light.Substituting the given values, we getΔλ / λ0 = (v / c)Δλ = λ0 (v / c)Solving for v, we getv = Δλ / λ0 x cSubstituting the given values, we getv = (6.562 x 10^-7 m - 656.3 x 10^-9 m) / (656.2 x 10^-9 m) x 3.00 x 10^8 m/sv = 29985 m/sThe velocity is 29985 m/s or 0.1% of the speed of light. As the wavelength is redshifted, the galaxy is moving away from us.
Part D. The formula for the Doppler effect is given asΔλ / λ0 = v / c Rearranging the terms, we get v = (cΔλ / λ0) / 2where v is the velocity of the galaxy, Δλ is the difference between the received wavelength and the actual wavelength, λ0 is the actual wavelength, and c is the speed of light. Substituting the given values, we get v = [(3.00 x 10^8 m/s) (6.562 x 10^-7 m - 656.3 x 10^-9 m)] / (2 x 656.3 x 10^-9 m)v = 29985 m/s. The formula for the velocity of the galaxy is given as v = (cλ - λ0) / λ0where v is the velocity of the galaxy, λ is the received wavelength, and λ0 is the actual wavelength. Substituting the given values, we get v = (3.00 x 10^8 m/s x 6.562 x 10^-7 m - 656.3 x 10^-9 m) / 656.3 x 10^-9 mv = 29985 m/s
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at a distance d from a point charge q, the energy density in its electric field is u. if we now go to a distance d/2 from the charge, what is the energy density at the new location
The energy density in the electric field of a point charge decreases as we move away from it. The energy density at a distance d from a point charge q is u.
If we now go to a distance d/2 from the charge, the energy density at the new location will be four times the energy density at distance d. This is because the energy density is inversely proportional to the square of the distance from the charge.
To understand this, consider the formula for energy density in an electric field:
u = (1/2)ε₀E²
where u is the energy density, ε₀ is the permittivity of free space, and E is the electric field strength. Since the electric field strength at a distance d/2 is four times stronger than at distance d (as E is inversely proportional to the distance from the charge), the energy density at the new location is four times greater than at distance d. Therefore, the energy density at the new location would be 4u.
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Which have different numbers of electrons? different ions of an element different isotopes of an element the nucleus of an element each of the atoms of an element
Answer:
Different ions of an element
Explanation:
From the options given, it is only the different ions of an element that can have different electrons.
This is because ions carry charge which could be positive or negative due to a deficit or excess of electrons.
A cation would be formed if there is a deficit of electrons and the atom becomes positively charged, and an anion would be formed if there is an excess of electrons and the atom becomes negatively charged.
For different ions of the same element, the electron number would vary and this would thus lead to each different ion carrying a greater or lesser charge than the other ions of the same element.
Different numbers of electrons occurs in different ions of an element.
Different isotopes of an element have the same number of number of protons and electrons but different number of neutrons.
Different ions of an element have different number of electrons.
For cations, such as;
potassium ion [\(k^{+1}\)], the number of electrons it contain is 18 while in ground state [K] the number of electrons it contain is 19.
Thus, we can conclude that different numbers of electrons occurs in different ions of an element.
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Choose the +x+x-axis as east and the +y+y-axis as north. Consider the following vectors A⃗ A→, B⃗ B→, and C⃗ C→:
A⃗ A→: 72.4 mm, 32.0∘∘ east of north
B⃗ B→: 57.3 mm, 36.0∘∘ south of west
C⃗ C→: 17.8 mm due south
part A
If a fourth vector D⃗ D→ is added to A⃗ +B⃗ +C⃗ A→+B→+C→, the result is zero: A⃗ +B⃗ +C⃗ +D⃗ =0A→+B→+C→+D→=0. Find the magnitude of D⃗ D→
part B
State the direction of D⃗ D→ in terms of an angle measured counterclockwise from the positive xx-axis.
A. the magnitude of D⃗ D→ -147.5 mm
B. 88.4o counterclockwise from the positive x-axis.
Part A:
Magnitude of D⃗ D→ = |0| - |A⃗ A→| - |B⃗ B→| - |C⃗ C→|
= 0 - 72.4 mm - 57.3 mm - 17.8 mm
= -147.5 mm
Part B:
Angle of D⃗ D→ = cos-1((|A⃗ A→|2 + |B⃗ B→|2 - |C⃗ C→|2) / (2 * |A⃗ A→| * |B⃗ B→|))
= cos-1((72.42 + 57.32 - 17.82) / (2 * 72.4 * 57.3))
= 88.4o counterclockwise from the positive x-axis.
Part A:
The magnitude of vector D⃗ D→ can be calculated by adding the magnitudes of the three given vectors, then subtracting the result from zero. The magnitude of vector D⃗ D→ is then equal to:
Part B:
To calculate the direction of vector D⃗ D→, we can use the Law of Cosines. Using the angle from the x-axis of vectors A⃗ A→ and B⃗ B→, and the magnitudes of all three vectors, we can calculate the angle of vector D⃗ D→ from the x-axis. This angle is equal to:
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Can a line on a position-time graph have a negative slope?
Answer:
Yes, when the velocity of the object is negative.
Explanation:
In position and time graphs, the slope of line indicates the velocity. Therefore negative slope of a position-time graph actually indicates negative velocity. Negative velocity is defined as the velocity of the object moving in an opposite direction.
The time graph reveals pertinent information about an object's velocity. For example, a small slope means a small velocity; a negative slope means a negative velocity; a constant slope (straight line) means a constant velocity; a changing slope (curved line) means a changing velocity.
deviance amplification is the theory that cosmic vibrations will transform human consciousness. True or false?
False. Deviance amplification is not a theory that cosmic vibrations will transform human consciousness.
Deviance amplification is a sociological theory that explains how social reactions to deviant behavior can lead to an escalation or amplification of that behavior. According to this theory, when deviant behavior is responded to with heightened social control, stigmatization, or punishment, it can result in an increase in the frequency or severity of the behavior. Deviance amplification focuses on the social processes and dynamics that contribute to the reinforcement or exacerbation of deviant behavior within a given social context. It does not relate to cosmic vibrations or transformations of human consciousness, which fall into metaphysical or spiritual realms of thought and are not addressed by sociological theories like deviance amplification.
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A man pushes a 49 kg mower with a force of 650 N at a downward angle of 35° as shown in the picture to the right. If the mower experiences a frictional force of 493.249 N, find:
The acceleration of the mower.
The normal force acting on the mower.
Answer:
a = 0.8m/s^2
F = 39.28 N
Explanation:
Sum of forces in X direction = 650cos(35)N-493.249N
Sum of forces in X direction= 39.28 N
F = m*a
a = F/m
a = 39.28N/49kg
a = 0.8 m/s^2