A wire carries a current of 4 A travelling to the left (-x direction). It is placed in a constant magnetic field of magnitude 0.05 T, pointing upward ( z direction). a. If 25 cm of the wire is in the magnetic field, what is the force on the current

Answer:

\(a=4\frac{m}{s^2}\)

Explanation:

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In this case, for this uniformly accelerated motion in which the car starts from rest at 0 m/s and travels 18 m in 3.0 s, we can compute the acceleration by using the following equation:

\(x_f=x_0+v_0t+\frac{1}{2}at^2\)

Whereas the final distance is 18 m, the initial distance is 0 m, the initial velocity is 0 m/s and the time is 3.0 s, that is why the acceleration turns out:

\(a=\frac{2(x_f-v_ot)}{t^2} =\frac{2(18m-0m/s*3.0s)}{(3.0s)^2}\\ \\a=4\frac{m}{s^2}\)

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Given the distance travelled and the time taken, the magnitude of  the car's acceleration is 4m/s²

Given the data in the question;

Since the car starts from rest,

Acceleration; \(a = \ ?\)

To determine the magnitude of  the car's acceleration

We use the Second Equation of Motion:

\(s = ut + \frac{1}{2}at^2\)

Where s is the speed, u is the initial velocity, a is the acceleration and t is the time.

We substitute our values into the equation and solve for "a"

\(18m = (0m/s\ * 3.0s) + (\frac{1}{2}\ *\ a\ *\ (3.0s)^2) \\\\18m = 4.5s^2 \ *\ a\\\\a = \frac{18m}{4.5s^2} \\\\a = 4 m/s^2\)

Therefore, the magnitude of  the car's acceleration is 4m/s²

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From the measure of 3.4 cm we can see that the minimum uncertainty implied is in the milimeters, that is in the range of 0.1 cm.

Answer:

It is the carrier of genetic information.

Answer:Which type of wave vibrates parallel to the direction the energy travels, like a slinky ... ex: Rainbow is composed of different frequencies of visible light ... ex: sledding down a hill - potential energy TRANSFORMS into kinetic energy ... C mechanical. D heat. B Chemical energy is energy stored in the bonds of a chemical ...

Explanation:

5.73 seconds pass before the centripetal acceleration equals the tangential acceleration in strength.

This enables you to calculate the change in velocity in metres per second squared (m/s²). The change in velocity (v) over the change in time (t) is known as acceleration (a). It can be determined using the formula a = v/t.

a = v²/r

where a is the centripetal acceleration, v is the speed of the car, and r is the radius of the circular track (half the diameter).

a = (2.97 m/s²)

r = (195 m)/2 = 97.5 m

v² = ar = (2.97 m/s²)(97.5 m) = 289.58 m²/s²

v = √(289.58 m²/s²) = 17.01 m/s

at = dv/dt

where at is the tangential acceleration, and v is the speed of the car. Since the car is starting from rest, its initial speed is zero, so we can simplify the formula to:

at = v/t

where t is the elapsed time.

We want to find the time at which the magnitude of the tangential acceleration is equal to the magnitude of the centripetal acceleration, so:

at = ac

v/t = ac

t = v/ac = 17.01 m/s / 2.97 m/s² = 5.73 s

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Answer:

The Total current drawn is 20.83 Ampere.

Explanation:

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

The correct answer is e) both b and c.

The quantities that will always be larger for waves on A than for waves on B are the frequency of the first harmonic and the wave velocity.

The frequency of the first harmonic is determined by the tension in the wire. Since A is stretched more tightly than B, the frequency of the first harmonic will be larger for waves on A than for waves on B.

The wave velocity is also determined by the tension in the wire. A higher tension results in a higher wave velocity. Therefore, the wave velocity will also be larger for waves on A than for waves on B.

The amplitude and wavelength of the first harmonic are not affected by the tension in the wire, so they will not be larger for waves on A than for waves on B.

In conclusion, the frequency of the first harmonic and the wave velocity will always be larger for waves on A than for waves on B.

Therefore, the correct answer for quantities that will be larger for waves on A than for waves on B is option e) both b and c.

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In order to determine which orientation results in a larger depolarization factor for the similar dielectric ellipsoids placed in an electric field, we need to consider the shape and alignment of the ellipsoids with respect to the electric field.

The depolarization factor measures the reduction in the electric polarization of a material due to its shape and alignment in an electric field. It is influenced by the geometry of the material and how it interacts with the electric field.

Qualitatively, if the ellipsoids are aligned in such a way that their major axes are parallel to the electric field lines, the depolarization factor would be smaller. This is because the electric field would act along the long axis of the ellipsoid, resulting in less distortion of the polarized charges inside the material. The polarization would be more effectively aligned with the electric field, minimizing the depolarization effect.

On the other hand, if the ellipsoids are oriented such that their major axes are perpendicular or at an angle to the electric field lines, the depolarization factor would be larger. In this case, the electric field would act in a direction that is not aligned with the major axis of the ellipsoid, causing more distortion and misalignment of the polarized charges inside the material. This results in a larger depolarization effect.

Without a specific diagram or more information about the orientations shown in Figure P5.5, it is difficult to determine the exact orientation with the larger depolarization factor. However, based on the general understanding of the relationship between alignment and the depolarization effect, the orientation where the major axes of the ellipsoids are perpendicular or at an angle to the electric field lines is likely to result in a larger depolarization factor.

In order to calculate the speed of the spacecraft, use the following formula;

where,

M: mass of the moon = 7.3*10^22 kg

G: Cavendish constant = 6.67*10^-11 Nm^2/kg^2

r: distance in between the spacecraft and the center of the Moon =

172 km + 1840 km = 2012 km

Replace the previous values of the parameters into the formula for v and simplify:

Hence, the speed of the spacecraft is approximately 4.91*10^4 m/s

Answer:

27 N

Explanation:

It will be the force of the book  1.2 kg * 9.81 m/s^2   PLUS the force of your hand  15.3 N    ..... it will be in the OPPOSITE direction

1.2 * 9.81 + 15.3 = ~27.1 N

Information technology has greatly impacted the economy, leading to increased productivity, efficiency, and innovation across industries.

The widespread adoption of information technology in the business world has led to a significant transformation in the way companies operate. Through the use of computers, software, and other digital tools, businesses are now able to streamline their operations, automate processes, and access vast amounts of data that can inform decision-making.

This has resulted in increased productivity, efficiency, and cost savings for companies. Additionally, information technology has facilitated the rise of new industries, such as e-commerce and digital marketing, while also enabling existing industries to adapt and innovate in response to changing market conditions.

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--The complete question is, How has information technology impacted the economy?--

Answer:

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The height of the 4 kilograms book with a gravitational potential energy of 98 Joules is approximately 2.5 meters.

Gravitational potential energy is simply the potential energy an object possessse in relation to another object due to gravity.

It is expressed as;

U = m × g × h

Given that:

Gravitational potential energy of the book U = 98 Joules

Mass of the book m = 4 kilograms

Acceleration due to gravity g = 9.8 m/s²

Height h = ?

Plug these values into the above formula and solve for height.

U = m × g × h

h = U / ( m × g )

h = 98  / ( 4 × 9.8 )

h = 98/39.2

h = 2.5 meters

Therefore, its height is 2.5 meters.

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The net force on particle q3 is 112.11 N

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

The Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m.

The net force F3 = F13 + F23

Substitute the values, we get the force F on q3 as

F3 = 9 x 10⁹x53.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.5+0.95)² + 9 x 10⁹x105.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.95)²

F3 = 112.11 N

Thus, the magnitude of the force on charge q3 is 112.11 N.

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Sun's energy comes from the nuclear fusion taking place inside. In nuclear fusion two light nuclei fuses together to form a heavy nuclei with the release of greater amount of energy.

Nuclear fusion is the process of combining two light nuclei to form a heavy nuclei. In this nuclear process, tremendous energy is released. This is the source of heat and light in stars.

On the other hand, nuclear fission is the process of breaking of a heavy nuclei into two lighter nuclei. Fission also produces massive energy. But in comparison, more energy is produced by nuclear fusion.

Nuclear fission is used in nuclear power generators. The light energy and  heat energy comes form the nuclear fusion of hydrogens to form helium nuclei. Hence, option D is correct.

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Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.

In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.

In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.

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Answer:

m²=m¹

Explanation:

m¹v¹ + m²v² = m¹ v¹+m¹v²

m²v²= m¹v²

m²v²/v² = m¹

m² = m¹

The volume of the rock, given the data is 14 mL (Option A)

From the question given above, the following data were obtained:

The volume of the rock can be obtained by calculating the displacement of the water when the rock was added. this can be obtained as follow:

Displacement of water = (Volume of water + rock) - (volume of water)

Displacement of water = 34 - 20

Displacement of water = 14 mL

Thus, the volume of the rock is 14 mL

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Complete question:

See attached photo

The TV's efficiency rating is 5.56%.

An isolated system has a constant total energy. Energy cannot be generated or destroyed; it can only be transformed from one form to another or transferred between systems. When all energy sources are considered, the overall energy of an isolated system is constant.

Efficiency is equal to (useful energy output/total energy intake) multiplied by 100%.

Useful energy output = light energy output + sound energy output

= 10 kJ + 30 kJ

= 40 kJ

Total energy input = electrical energy input

= 720 kJ

Substituting these values into the efficiency formula, we get:

Efficiency = (40 kJ / 720 kJ) x 100%

= 0.0556 x 100%

= 5.56%

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The ratio of M/m is approximately 0.155, which is closest to option (b) 1/4.

Let's consider the motion of the system before and after the collisions. We'll use the conservation of momentum and the conservation of energy to solve the problem.

Before the collisions, the leftmost block of mass m has velocity v towards the right and the other two blocks are at rest. The total initial momentum of the system is therefore mv.

At the first collision, the leftmost block collides with the middle block of mass m. The two blocks stick together and move as a single unit. By conservation of momentum, the velocity of the combined block after the collision is mv/(2m) = v/2 towards the right.

At the second collision, the combined block collides with the block of mass M. Again, the two blocks stick together and move as a single unit. By conservation of momentum, the velocity of the combined block after the collision is (mv/2 + 0)/ (m+M) = v/2(m+M) towards the right.

After the collisions, the three blocks move as a single unit with velocity v/2(m+M) towards the right. The total final momentum of the system is therefore (m+2m+M)(v/2(m+M)) = mv/2.

The loss in kinetic energy after all the collisions is given as 5/6th of the initial kinetic energy. Therefore, the final kinetic energy is 1/6th of the initial kinetic energy. Let's use this to solve for M/m.

The initial kinetic energy of the system is (1/2)m(v^2) = (1/2)mv^2.

The final kinetic energy of the system is;

(1/2)(m+2m+M)((v/2(m+M))^2) = (1/2)(mv^2)/(4(m+M)^2).

Therefore, we have:

(1/2)mv^2 - (1/2)(mv^2)/(4(m+M)^2) = (1/6)(1/2)mv^2

Multiplying both sides by 12 and simplifying, we get:

3(m+M)^2 = 8m

Expanding the left side and simplifying, we get:

3M^2 + 6mM - 4m^2 = 0

Solving for M/m using the quadratic formula, we get:

M/m = (-6 ± √(36 + 48))/6 = (-6 ± 2√(3))/6 = (-1 ± √(3))/3

Since M/m is a ratio of masses, it must be positive, so we take the positive root:

M/m = (-1 + (3))/3 ≈ 0.155 ≈ 1/4

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Hi there!

We can use work and energy to solve this problem.

We know that:

Ei = Ef

Ei = Potential energy = mgh

Ef = Rotational kinetic + Translational kinetic = 1/2Iω² + 1/2mv²

The barrel is comprised of a hollow cylinder and disk-shaped bottom, so:

I (hollow cylinder) = mr²

I (disk) = 1/2mr²

Calculate the moment of inertias of each.

Since the mass on the base is one-fourth of its side:

x = mass of side

x + x/4 = 15

4x + x = 60

5x = 60

x = 12 kg

end mass = 3 kg

Solve for each moment of inertia:

Side: (12)(0.4²) = 1.92 Kgm²

Bottom: 1/2(3)(0.4²) = 0.24 Kgm²

Side + bottom = 2.16 Kgm²

We can now solve:

mgh = 1/2mv² + 1/2(2.16)v²/r²

(15)(9.8)(33) = 1/2(15)v² + 1/2(13.5)v²

4851 = 14.25v²

v = 18.45 m/s

1 ) Resultant force if the forces act in the same direction = 41 N

2 ) Resultant force if the forces act in the opposite direction = 9 N

3 ) Resultant force if the forces act at right angles to each other = 29.68 N

F1 = 16 N

F2 = 25 N

1 ) If the forces act in the same direction,

F = F1 + F2

F = 16 + 25

F = 41 N

2 ) If the forces act in the opposite direction,

F = F2 - F1

F = 25 - 16

F = 9 N

3 ) If the forces act at right angles to each other,

F² = F1² + F2²

F² = 16² + 25²

F² = 256 + 625

F² = 881

F = 29.68 N

Therefore,

1 ) F = 41 N

2 ) F = 9 N

3 ) F = 29.68 N

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Answer:

The advantages of Hovercraft:

They can travel over almost any non-porous surface.

They can operate to and from any unprepared beach or slipway.

They take fast, direct routes compared to a conventional marine vessel.

Answer:

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Explanation:

F=force, m=mass, a=acceleration, v=velocity

v=displcement/time

a= v/t

F= m×a

F= m× (v/t)

Answer:

option B is the correct answer

Explanation:

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The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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