A women and her dog are out for a morning run to the river,which is located 4.0 km away.The women runs at 2.5 m/s in a straight line . The dog is unleashed and runs back and forth at 4.5 m/s between his owner and the river,until the women reaches the river . What is the total distance run by the dog?
Answers
Answer:
7.2 km
Explanation:
Find the total distance that dog is running by
\(S_{dog} = v_{dog} t\)
and use the time above that woman is taking to reach the river,
t = \(\frac{S_{woman} }{v_{woman} }\)
so,
\(S_{dog}\frac{S_{woman} }{v_{woman} }\)
plug the values You will get the answer.
Related Questions
a small object is placed between two plane mirrors inclined at an angle of 60° to each other in a dark room how many images are seen explain
Answers
Answer:
nothing
Explanation:
bocouse of darkness
A car of weight 11000 N moves with constant velocity along a horizontal road.A driving force of 5000 N acts on the car what is the force opposing the motion of the car
Answers
Answer:
5000 N
Explanation:
Since F - f = ma, where F = driving force = 5000 N, f = opposing force, m = mass of car and a = acceleration of car.
Since the car is moving with constant velocity, a = 0.
So, F - f = ma
F - f = m(0)
F - f = 0
F = f.
Since F = 5000 N and F = f, f = 5000 N.
So, the opposing force is 5000 N
The opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.
The opposing force can be calculated by the formula,
F - f = ma
Where,
F = driving force = 5000 N,
f = opposing force = ?
m = mass of car = 11000 N
a = acceleration of car
Since, the car is at constant velocity, a = 0.
So,
F - f = m(0)
F - f = 0
F = f.
Therefore, the opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.
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a 72.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. he then drops through a height of 1.57 m, and ends with a speed of 8.51 m/s. how much nonconservative work (in kj) was done on the boy?
Answers
The non-conservative work done on the boy is 1.44566 kJ.
Mass of the boy, m = 72.1 kg
Initial velocity of the boy, u = 1.60 m/s
Final velocity of the boy, v = 8.51 m/s
Height through which he drops, h = 1.57 m.
The energy conservation principle states that the initial potential energy plus the initial kinetic energy of the boy is equal to the final potential energy plus the final kinetic energy of the boy.
Initial potential energy (PE) + Initial kinetic energy (KE) = Final potential energy (PE) + Final kinetic energy (KE).
Initial potential energy (PE) + Initial kinetic energy (KE) + Non-conservative work done = Final potential energy (PE) + Final kinetic energy (KE)
Substitute the given values to get the answerInitial potential energy (PE) = mgh. Where m is the mass of the object, g is the gravitational force, and h is the height of the object from the ground
mgh = (72.1 kg) x (9.8 m/s²) x (1.57 m)
mgh = 1,069.7546 J.
Initial kinetic energy (KE) = 1/2 mu²
KE = (1/2) x (72.1 kg) x (1.60 m/s)²
KE = 115.904 J
Final potential energy (PE) = mgh
PE = (72.1 kg) x (9.8 m/s²) x (0 m)
PE = 0 J.
Final kinetic energy (KE) = 1/2 mv²
KE = (1/2) x (72.1 kg) x (8.51 m/s)²
KE = 2,631.32 J.
Substituting all these values to the equation, we get1,069.7546 J + 115.904 J + Non-conservative work done = 0 J + 2,631.32 J.
Non-conservative work done = Final KE - Initial KE - Final PE + Initial PE
= 2,631.32 - 115.904 - 0 - 1,069.7546
Non-conservative work done = 1,445.66 JNon-conservative work done = 1.44566 kJ (approx).
Therefore, the non-conservative work done on the boy is 1.44566 kJ
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a duck is swimming at the center of a circular lake. a fox is waiting at the shore, not able to swim, willing to eat the duck. it may move around the whole lake with a speed four times faster than the duck can swim. as soon as duck reaches the surface, it can fly, but not within the pond. can the duck always reach the shore without being eaten by the fox?
Answers
The duck can always reach the shore without being eaten by the fox.
Assume that the duck is swimming in a circular path around the centre of the lake and that the fox is waiting at a fixed point on the shore. Since the fox is four times faster than the duck, it can run along the shore at a constant speed that is also four times the speed of the duck's swimming.
Now, imagine that the duck swims around the lake one full time, starting at the point farthest from the shore where the fox is waiting. The duck will take some amount of time to complete this circuit, during which the fox will also have travelled some distance around the lake.
However, since the duck is swimming in a circular path, it will eventually cross the point on the opposite side of the lake from where it started. At this point, the duck is closer to the shore than the fox is. Furthermore, since the duck can now fly, it can reach the shore before the fox catches up to it.
So, it will eventually reach a point where it is closer to the shore than the fox and can fly the rest of the way to safety. Therefore, the duck can always reach the shore without being eaten by the fox.
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If you were to look at grains of table salt with a magnifying glass, you would see that each grain is a little cube. Why are salt grains cubical?
Answers
Answer:
All extended structure compounds form cubes. Sodium and chlorine atoms both have cubical shapes. In the extended structure of NaCI, atoms are arranged in a cubical pattern
A force of 24 N will stretch a rubber band 12 cm(0.12 m) Assuming that Hooke's faw applies, how lar will a 20 - N lorce stretch the rubber band? How much wokk does if take fo stretch the nubber band this far? How lar will a 20.N torce stretch the rubber band? B) (Sirnplify your answed) How mach work does ia take la stretch the rubber band this far? (Stmplify your answer)
Answers
Work required to stretch the rubber band by 0.10 meters will be negative, indicating that work needs to be done against the force applied to stretch the rubber band.
To determine how much the rubber band will stretch under a 20 N force and the work required to stretch it, we need to apply Hooke's Law. Hooke's Law states that the force applied to a spring or elastic material is directly proportional to the displacement it undergoes.
We can set up a proportion to find the stretch under Force 2:
(F1 / S1) = (F2 / S2)
Substituting the given values:
(24 N / 0.12 m) = (20 N / S2)
To find S2, we can rearrange the equation:
S2 = (20 N * 0.12 m) / 24 N
Simplifying:
S2 = 0.10 m
Therefore, a 20 N force will stretch the rubber band by 0.10 meters.
Now, let's calculate the work required to stretch the rubber band this far. The work (W) can be calculated using the formula:
W = (1/2) * k * (S2^2 - S1^2)
Where k is the spring constant.
However, we don't have the spring constant (k) given in the problem. So, we cannot determine the exact work without that information.
But, if we assume that the rubber band behaves as a linear spring and Hooke's Law applies, we can simplify the equation. Hooke's Law states that the force applied to a spring is equal to the spring constant (k) multiplied by the displacement (S).
F = k * S
Rearranging the equation:
S = F / k
Since the stretch (S) is directly proportional to the force (F), we can approximate the work required by assuming a constant k value:
W ≈ (1/2) * k * (S2^2 - S1^2)
W ≈ (1/2) * k * [(0.10 m)^2 - (0.12 m)^2]
Simplifying:
W ≈ (1/2) * k * (0.01 m^2 - 0.0144 m^2)
W ≈ (1/2) * k * (-0.0044 m^2)
Without the exact value of the spring constant, we cannot calculate the work precisely. However, we can still conclude that the work required to stretch the rubber band by 0.10 meters will be negative, indicating that work needs to be done against the force applied to stretch the rubber band.
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what vector points from the origin to the point (0,-1,-1)?
Answers
This vector represents the direction and magnitude needed to go from the origin to the point (0, -1, -1). The vector starts at the origin (0, 0, 0) and extends to the coordinates (0, -1, -1).
To obtain the vector that points from the origin to the point (0, -1, -1), we need to calculate the differences between the corresponding coordinates.
Let's break it down:
The origin is defined as (0, 0, 0), where all the coordinates are zero.
The point (0, -1, -1) has coordinates x = 0, y = -1, and z = -1.
To find the vector pointing from the origin to this point, we subtract the coordinates of the origin from the coordinates of the point:
x-coordinate: 0 - 0 = 0
y-coordinate: -1 - 0 = -1
z-coordinate: -1 - 0 = -1
Combining these differences, we get the vector (0, -1, -1). This vector represents the direction and magnitude needed to go from the origin to the point (0, -1, -1). The vector starts at the origin (0, 0, 0) and extends to the coordinates (0, -1, -1).
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Will mark as BRAINLIEST.......
The position vector is given by vector r= 5t² I cap + 2 t³ j cap + 2 k cap. Find it's velocity and acceleration at t=2s.
Answers
Answer:
We have the position vector given in terms of time t. r(t) = t^3*i + t^2*j
To find the velocity vector we have to differentiate r(t) with respect to time.
r'(t) = 3t^2*i + 2t*j
The vector representing acceleration is the derivative of the position vector
r''(t) = 6t*i + 2*j
When time t = 2.
The velocity vector is 3*2^2*i + 2*2*j
=> 12*i + 4*j
The speed is the absolute value of the velocity vector or sqrt(12^2 + 4^2) = sqrt (144 + 16) = sqrt 160
The acceleration vector is 6*2*i + 2*j
=> 12*i + 2*j
The required acceleration at t=2 is 12*i + 2*j and the speed is sqrt 160.
Explanation:
Can I have thx and brainliest?
which type of energy does a ball falling through the air have?
Answers
Answer:
the answer would be kinetic energy
What duty cycle should transformer-rectifier units have (at least) for CAC-A?
Made from graphite, copper coated, and operated on direct type current.
Should be three phase units with at least a 60% duty cycle
No--trash containers are not fabricated to the quality of a nuclear power plant
Answers
Transformer-Rectifier units for CAC-A (Constant Current Arc Welding) should have a minimum of 60% duty cycle, with at least three-phase units.
Constant Current Arc Welding is also known as "stick welding." The acronym CAC stands for "constant current," which means the power source must be able to produce a constant output current, regardless of the resistance of the welding arc.
To create the appropriate current for the welding, a transformer-rectifier is used. A transformer-rectifier unit comprises of a transformer and a rectifier. The transformer converts high voltage, low current AC electricity from the power source to low voltage, high current AC electricity, which is then supplied to the rectifier. The rectifier transforms the AC input into a direct current (DC) output that the welding equipment requires.
The duty cycle is defined as the amount of time during which the machine can operate without overheating. The transformer-rectifier should have a 60% duty cycle or higher because welding generates a lot of heat and needs a lot of power. If the duty cycle is too low, the unit will shut down too often and be unable to perform effectively.
A 60% duty cycle ensures that the welding machine can run continuously for six minutes out of every ten minutes. It is recommended that you choose a transformer-rectifier with a duty cycle that meets your requirements, as a higher duty cycle would allow you to weld for longer periods of time before requiring a cool down period.
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Parker completed 4 laps around a 400 m track. He ran for a total of 30 mins. What is the
distance and displacement of his travel?
Answers
Answer:
Distance: 1600 m Displacement: 0
Explanation:
The distance is because He ran 400 meters 4 times getting 1600 m
4*400=1600
The displacement is 0 because displacement is the total distnce away from the starting point and since he ran laps around the track in the end he ended up in the same spot as last time.
a train is moving 4.82 m/s when it begins to accelerate. after 24.8 s it is moving 7.09 m/s. How far did it move in that time?
Unit=m
Answers
find the volume of the wedge in the figure by integrating the area of vertical cross‑sections. assume that =8, =4, and =3.
Answers
To find the volume of the wedge in the figure by integrating the area of vertical cross-sections, we need to first determine the limits of integration. From the given information, we know that the length of the wedge is 8, the height is 4, and the width is 3.
Since we are integrating the area of vertical cross-sections, our limits of integration will be from 0 to 3 (the width). For each value of x (the distance from the y-axis), we need to find the area of the cross-section at that point.
From the figure, we can see that the cross-section is a triangle with base length (8 - x) and height 4. Therefore, the area of the cross-section at a given value of x is:
A(x) = 0.5 * (8 - x) * 4 = 16 - 2x
Now we can integrate this function from 0 to 3 to find the total volume of the wedge:
V = ∫[0,3] A(x) dx
V = ∫[0,3] (16 - 2x) dx
V = [16x - x^2] from 0 to 3
V = (16(3) - 3^2) - (16(0) - 0^2)
V = 39
Therefore, the volume of the wedge is 39 cubic units.
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the atmosphere of the "young" earth contained which gas or gases as major components?
Answers
The atmosphere of the young Earth contained primarily nitrogen, carbon dioxide, and water vapor.
The early Earth's atmosphere is believed to have been primarily composed of nitrogen, carbon dioxide, and water vapor, with smaller amounts of other gases such as methane, ammonia, and sulfur dioxide. This atmosphere was very different from the present-day atmosphere, which is dominated by nitrogen and oxygen. The lack of oxygen in the early atmosphere was due to the absence of photosynthetic organisms that produce oxygen as a byproduct.
The composition of the early atmosphere played a crucial role in the development of life on Earth, as it provided the necessary conditions for the formation of organic molecules and the evolution of life. Over time, the Earth's atmosphere has undergone significant changes, including the addition of oxygen due to the emergence of photosynthetic organisms and human activity.
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A camera lens used for taking close-up photographs has a focal length of 23.5 mm. The farthest it can be placed from the film is 33.0 mm. (a) What is the closest object that can be photographed? (b) What is the magnification of this closest object?
Answers
The closest object that can be photographed is 81.63mm and the magnification of this closest object is -0.404.
The focal length of a lens is determined when the lens is focused at infinity. It is obtained from the reciprocal of objects' distance and image distance. Magnification is the enlarged image that is formed over the object size.
From the given,
focal length (f) = 23.5mm
object's distance (u) = 33mm
imagen distance(v) =?
Focal length, (1/f) = 1/u + 1/v
1/v = 1/f - 1/u
=1/23.5 - 1/33
1/v = 12.2mm
v = 1/12.2 mm
= 81.96mm
Thud, the image distance is v= 81.96mm.
Magnification (M) = -v/u
M = -33 / 81.96
= - 0.402.
Thus, the magnification is -0.402.
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A graduate student is trying to follow the weather on Jupiter for her PhD thesis. To see the big weather patterns in the upper atmosphere of the planet, she needs to have excellent resolution. What type of telescope would be best for her to use? a. a refractor, with as small an aperture as possible b. a radio telescope c. a large reflector in an observatory located at sea level d. a large reflector located in orbit above the Earth's atmosphere e. you can't fool me, all these telescopes have the same resolution
Answers
Answer: large reflector located in orbit above the Earth's atmosphere
Explanation:
Since the student wants to see the big weather patterns in the upper atmosphere of the planet, and she will therefore need to have excellent resolution, the type of telescope that is ideal for her to use is a large reflector located in orbit above the Earth's atmosphere.
It should be noted that the refractor or a radio telescope isn't ideal in this situation as they will not capture the bug weather pattern and doesn't have an excellent resolution like the large reflector.
Consider the following situations:
A. A 2.5 kg physics book is resting on the edge of a table 1.4 m above the floor
B. A 10.0 kg backpack is on the floor beside the door
C.A 1 kg backpack is on the shelf that is 2.0 m above the floor
In which situation(A, B or C) is the potential energy the most?
OA
O
O
A, B and C all have the same potential energy
C
B
Answers
Given the data from the question, the potentiel energy is most in A
To obtain the correct answer to the question, we shall determine the potential energy in each case
How to determine the potential energyPE = mgh
Where
PE is the potential energym is the massg is the acceleration due to gravityh is the heightCase A
Mass (m) = 2.5 KgHeight (h) = 1.4 mAcceleration due to gravity (g) = 9.8 m/s²Potential energy (PE) = ?PE = mgh
PE = 2.5 × 9.8 × 1.4
PE = 34.3 J
Case B
Mass (m) = 10 KgHeight (h) = 0 mAcceleration due to gravity (g) = 0 m/s²Potential energy (PE) = ?PE = mgh
PE = 2.5 × 0 × 0
PE = 0 J
Case C
Mass (m) = 1 KgHeight (h) = 2 mAcceleration due to gravity (g) = 9.8 m/s²Potential energy (PE) = ?PE = mgh
PE = 1 × 9.8 × 2
PE = 19.6 J
SUMMARY
Potential energy in case A = 34.3 JPotential energy in case B = 0 JPotential energy in case C = 19.6 JThus potential energy is most in A
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a small but rigid u shaped wire carrying a 5.0 a current is placed inside a solenoid the solenoid is 17 cm long and has 800 loops of wire and the current in each loop is
Answers
The current in each loop of the solenoid is 6.25 A. current is placed inside the solenoid, we can assume that the current passing through each loop is the same.
The solenoid is 17 cm long and has 800 loops of wire. Since the wire carrying the 5.0 A current is placed inside the solenoid, we can assume that the current passing through each loop is the same.
To find the current in each loop, we can use the formula:
I_solenoid = N * I_wire
Where:
I_solenoid is the current in the solenoid,
N is the number of loops,
I_wire is the current in the wire.
Plugging in the values, we have:
I_solenoid = 800 * I_wire
5.0 A = 800 * I_wire
Solving for I_wire, we get:
I_wire = 5.0 A / 800 = 0.00625 A
Therefore, the current in each loop of the solenoid is 6.25 A.
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Impulse equals?
A) momentum x velocity
B) momentum x time
C) mass x velocity
Answers
Answer:
B
Explanation:
The impulse experienced by an object is the force•time.
What statement about energy transfer in a wave is true?
Answers
Answer:
Energy moves between the particle of the medium.
Explanation:
True/false: a polarized material must have a nonzero net electric charge.
Answers
The answer is False. A polarized material does not need to have a nonzero net electric charge. Polarization occurs when the positive and negative charges within a material are displaced relative to each other, creating an electric dipole moment.
This can happen in materials such as dielectrics or insulators, which do not conduct electricity. The net electric charge of a polarized material can still be zero, as the overall positive and negative charges remain balanced, but the charges are spatially separated. Polarization plays an important role in phenomena such as capacitance, dielectric constant, and polarization-induced electric fields.
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Which object would have the greatest kinetic energy? *
A car driving down a hill at a speed of 40 m/s A person walking on the street at 2 m/s A ball rolling across the field at 5m/s A leaf falling at 10 m/s
Answers
Kinetic energy is directly proportional to its velocity
a proton in a high-energy accelerator moves with a speed of c/2. use the work–kinetic energy theorem to find the work required to increase its speed to the following speeds. (a) 0.740c (b) 0.873c
Answers
The work required to increase the speed of the proton to Therefore, the work required to increase the speed of the proton to (a) 0.740c is -3.52 x 10⁻¹¹ J and (b) 0.873c is 5.27 x 10⁻¹¹ J
The work-kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we can use this theorem to find the work required to increase the speed of a proton in a high-energy accelerator.
Let's first find the kinetic energy of the proton with speed c/2. The kinetic energy (K) of an object with mass m and speed v is given by:
K = (1/2)mv²
Since the proton has a rest mass of 1.67 x 10⁻²⁷ kg, we can calculate its kinetic energy:
K = (1/2)(1.67 x 10⁻²⁷ kg)(c/2)²
K = 9.41 x 10⁻¹¹ J
(a) To find the work required to increase the speed of the proton to 0.740c, we first need to find its final kinetic energy. Since kinetic energy is proportional to the square of the speed, we can use the ratio of speeds to find the final kinetic energy:
(K_final)/(K_initial) = (v_final²)/(v_initial²)
(K_final) = (v_final²)/(v_initial²) * (K_initial)
(K_final) = (0.74c/c/2)² * (9.41 x 10⁻¹¹J)
(K_final) = 5.89 x 10⁻¹¹ J
The change in kinetic energy is:
ΔK = K_final - K_initial
ΔK = 5.89 x 10⁻¹¹ J - 9.41 x 10⁻¹¹J
ΔK = -3.52 x 10⁻¹¹ J
Since the final speed is greater than the initial speed, the work done on the proton is positive. Therefore, the work required to increase the speed of the proton to 0.740c is:
W = ΔK
W = -3.52 x 10⁻¹¹J
(b) To find the work required to increase the speed of the proton to 0.873c, we follow the same steps as in part (a). The final kinetic energy is:
(K_final) = (0.873c/c/2)² * (9.41 x 10⁻¹¹ J)
(K_final) = 1.47 x 10⁻¹⁰J
The change in kinetic energy is:
ΔK = K_final - K_initial
ΔK = 1.47 x 10⁻¹⁰ J - 9.41 x 10⁻¹¹ J
ΔK = 5.27 x 10⁻¹¹ J
Since the final speed is greater than the initial speed, the work done on the proton is positive. Therefore, the work required to increase the speed of the proton to 0.873c is:
W = ΔK
W = 5.27 x 10⁻¹¹J
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A car with a mass of 1400 kg is being driven along the motorway at 30 m/s. Calculate the kinetic energy of the car.
Answers
Answer:
630,000 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\\)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 1400 \times {30}^{2} \\ = 700 \times 900 \\ = 630000\)
We have the final answer as
630,000 JHope this helps you
Discussion: Two-Dimensional Motion, Forces, and Newton's Third Law
Choose a real world situation, such as diving off a diving board, rocket propulsion, or birds flying, and select a motion within that situation that does not occur in a straight line, and is set in motion by the interaction of two objects. Motion that does not occur in a straight line indicates that more than one force is acting on the object and they are responsible for what you are seeing. Try to identify the forces that are causing the motion you selected. Describe how Newton’s third law applies to that motion. Since the forces are equal and opposite, be sure to account for size and directions of the motion of the two objects before and after the interaction.
Answers
Discussion: Two-Dimensional Motion, Forces, and Newton's Third Law is as follow:
Let's take a real-world example of a bird flying and discuss the Two-Dimensional Motion, Forces, and Newton's Third Law of it:
When birds fly, they flap their wings in such a way that air is forced to move down. Due to this downward force, an upward reaction force is exerted on the bird by the air according to Newton's Third Law of Motion. This upward force is what keeps the bird afloat and allows it to soar.
The bird is pushed forward by the air as a result of this exchange of forces. This is due to the fact that the forward motion of the bird is equal to the opposite reaction to the force pushing the bird backward. The bird will slow down if the force pushing it backward is greater than the force of motion. This force can be counteracted by the bird flapping its wings with more force.
The bird can move in all directions, including up, down, forward, backward, and even diagonally. When the bird is changing directions or speed, it's not moving in a straight line, implying that more than one force is acting on it.
These forces may come from a variety of sources, including the bird's own muscles and the air around it. These forces can be difficult to measure and quantify, making it difficult to precisely predict a bird's flight.
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HELLLP PLEASE || the graph below shows a conversion of energy for a skydive jumping out of a plane and landing safely on the ground. which energy is represented by line A? A) Potential B) Thermal C) Kinetic D) Total Energy
Answers
Answer: If i'm not mistaken I think it A) potential
How much total mechanical energy (ME) is in a system if the PE is 10 J and the KE is 40 J? Hint: ME=KE+PE
A. 10 J
B. 40 J
C. 30 J
D. 50 J
Answers
Answer:
D. 50 J
hope it helps you you just need to put the values or substitute the value in me=ke+pe
Answer:
D.\(\pmb{ 50~J}\)
Explanation:
As we know that \(\sf{M_{E}=K_{E}+P_{E} }\)
where,
ME=mechanical energy KE=kinetic energy PE=potential EnergyAccording to the question
ME=KE+PEME=40J+10JME=50JWhat is the kinetic energy of a 2000kg boat moving at 5m/s?
Answers
Answer:
25000 J or 25 kJ
Explanation:
K = 1/2 mv^2
where mass is in kilograms kg
and velocity is in metres per seconds m/s
Here, m = 2000, v = 5
v^2 = 5*5 = 25
1/2 mv^2 = 1/2 * 2000 * 25
= 50000/2
= 25000
Hope it helps!
An electromagnetic wave moves through electric and magnetic fields. What
is the relationship between the wave and the fields?
O A. The vibrations of the fields are in the same direction but
perpendicular to the motion of the wave.
B. The vibrations of the fields are at 90° angles to the direction of
motion of the wave.
C. The vibrations of the fields and wave motion are all parallel to
each other.
D. The vibrations of the fields and the wave motion are at 180°
angles to each other.
Answers
Answer:
B. The vibrations of the fields are at 90° angles to the direction of
motion of the wave.
Explanation:
Electromagnetic waves are waves that are produced by the vibration of the electric and magnetic fields.
Both fields are oriented perpendicularly to one another. This vibration produces the electromagnetic waves.
These waves are very unique in that they do not require any material medium for propagation.
There is a broad spectrum of electromagnetic waves with gamma rays being the most energetic and radio waves being the least energetic.
Answer: B is the correct answer
Explanation:
if the moment of inertia of the shaded area about the a-a' axis is 18e6mm^4 what is the moment of inertia about the b-b' axis
Answers
The moment of inertia about the b-b' axis is 24.6E6 mm^4.
To find the moment of inertia of the shaded area about the B-B' axis, we can use the formula I = ∑m*r^2, where m is the mass of each particle in the shaded area, r is the distance of each particle from the B-B' axis, and the sum is taken over all particles in the shaded area.
We are given that the moment of inertia of the shaded area about the A-A' axis is
18E6 mm^4,and that the area of the shaded region is
A = 6E3 mm^2.We are also given the distances
ds = 50 mm and d₂ = 10 mm,which correspond to the distances of the two particles in the shaded region from the B-B' axis.
The mass of each particle in the shaded region can be calculated by dividing the total mass of the region (which is equal to the product of the area and the density of the material) by the number of particles. Since the density of the material is not given, we cannot calculate the mass of each particle.
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Complete Question:
If the moment of inertia of the shaded area about the A-A' axis is 18E6 mm, what is the moment of inertia about the B-B' axis?
Given: A6E3 mm², ds-50 mm, d₂-10 mm
a. none of these answers
B. 21.2E6 mm^4
C 25.2E6 mm^4
D. 26.3E6 mm^4
E. 24.6E6 mm^4