Buy another one or beg for another one. This is by far the hardest question I have answered. It takes a deep understanding of philosophical, mathematical, and political knowledge. I hope you can achieve your goal.
Answer:
hi again play with it broken glue or tape it back together or... throw it away orrrrrrrrrrrrrrrrrrrr................................... like the person said above buy a newwwwww one
Step-by-step explanation:
write seven hundred fifteen and one thousand one hundred fifty- three ten-thousandths as a decimal number
Answer:
715.1153
Step-by-step explanation:
write
seven hundred fifteen = 715
and
one thousand one hundred fifty- three = 1,153
ten-thousandths = 1/10,000 = 0.000 1
together = 0.1153
as a decimal number
So when added together
the number is
715.115 3
Answer:
715.1153
Step-by-step explanation:
Match the following MATLAB command to its mathematical meaning log(x) Choose) log 10(x) [Choose) In(x) [Choose] log base 10 of Not a valid MATLAB command log base e of x (log base d of x)/(log base d of b)
The Logarithmic function is a mathematical operation that is used to determine the logarithm of a number.
The logarithm of a number x is the exponent to which a fixed number, the base, must be raised to produce x. The most common bases used are 10 and e. The formula for determining the logarithm of a number x base d is: log base d of x = (log base d of x)/(log base d of b).
For example, if we want to calculate the log base 10 of a number x, we would use the formula: log base 10 of x = (log base 10 of x)/(log base 10 of b). We can calculate the log base 10 of a number x by taking the logarithm of x and dividing it by the logarithm of the base, 10. The result will be the log base 10 of x.
For example, if we want to calculate the log base 10 of 25, we would calculate the logarithm of 25 and divide it by the logarithm of 10. The calculation would be: log base 10 of 25 = (log base 10 of 25)/(log base 10 of 10) = (1.3979)/(1) = 1.3979. This means that the log base 10 of 25 is 1.3979.
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Write an expression that is equivalent to 8k²+2(3k+5) + 4k²- 2(2k+1)
\(2(6k^{2} +k+4)\)
The monthly output of a certain product is Qx) - 1700x5/2 where is the capital investment in millions of dollars. Find d/dx, which can be used to estimate the effect on the output if an additional capital investment of $1 million is made dQ/dx-
By applying The Power Rule for Derivatives, it concluded that the value of dQ/dx is 4250\(x^{\frac{3}{2} }\)
The Power Rule for Derivatives is a method of differentiation that is used when a mathematical expression with an exponent needs to be differentiated. The rule is:
d(xⁿ) / dx = n(x)ⁿ⁻¹
It is given that the monthly output of a certain product is defined by the function:
Q(x) = 1700\(x^{\frac{5}{2} }\)
where x denotes the capital investment in millions of dollars.
Now we want to determine the derivative of the giving function:
d(xⁿ) / dx = n(x)ⁿ⁻¹
dQ / dx = d (1700\(x^{\frac{5}{2} }\))
= \(\frac{5}{2} (1700x)^{\frac{5}{2}-1 }\)
= 4250\(x^{\frac{3}{2} }\)
Thus, the value of dQ/dx is 4250\(x^{\frac{3}{2} }\)
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During dismissal time in the afternoon period at Hipercubo , 9 kids are dismissed every 3 minutes . Knowing that 81 kids study at this period , how long will it take for all the kids to have gone home ?
It will take 27 minutes for all the kids to have gone home
How long will it take for all the kids to have gone home?The given parameters are:
9 kids every 3 minutes
This can be represented as
9 kids = 3 minutes
Let the time spent by 81 kids be x
So, we have the following equation
81 kids = x
Rewrite the parameters as
9 kids = 3 minutes
81 kids = x
Cross multiply in the above equation
So, we have:
9 * x = 3* 81
Divide both sides by 9
x = 3 * 9
Evaluate
x = 27
Hence, it will take 27 minutes for all the kids to have gone home
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Find the answer in simplest form.
33/4 divided by 17/6=
Answer:
99/34 i believe
Step-by-step explanation:
The position of an object as a function of time is given as
x
=
A
t
3
+
B
t
2
+
C
t
+
D
.
The constants are A
=
2.10
m
/
s
3
,
B
=
1.00
m
/
s
2
,
C
=
−
4.10
m
/
s
and D
=
3.00
m
A. What is the velocity of the object at t = 10.0 s?
B. At what time(s) is the object at rest?
C. What is the acceleration of the object at t = 0.50 s?
a) The velocity of the object at t = 10.0 s is 645.9 m/s.
b) The object is at rest at t = -0.87 s and t = 0.62 s.
c) The acceleration of the object at t = 0.50 s is 7.20 m/s^2.
A. To find the velocity of the object at t = 10.0 s, we need to take the derivative of the position function with respect to time:
v(t) = 3At^2 + 2Bt + C
Plugging in the given constants, we get:
v(10.0) = 3(2.10)(10.0)^2 + 2(1.00)(10.0) - 4.10
v(10.0) = 630.0 + 20.0 - 4.10
v(10.0) = 645.9 m/s
Therefore, the velocity of the object at t = 10.0 s is 645.9 m/s.
B. The object is at rest when its velocity is zero. So, we need to find the value(s) of t that make v(t) = 0. Using the same velocity function from part (A), we can set it equal to zero and solve for t:
3At^2 + 2Bt + C = 0
Plugging in the given constants, we get a quadratic equation:
6.30t^2 + 2.00t - 4.10 = 0
Using the quadratic formula, we can solve for t:
t = (-2.00 ± sqrt(2.00^2 - 4(6.30)(-4.10))) / (2(6.30))
t = (-2.00 ± sqrt(104.80)) / 12.60
t = (-2.00 ± 10.24) / 12.60
t = -0.87 s or 0.62 s
Therefore, the object is at rest at t = -0.87 s and t = 0.62 s.
C. To find the acceleration of the object at t = 0.50 s, we need to take the derivative of the velocity function with respect to time:
a(t) = 6At + 2B
Plugging in the given constants, we get:
a(0.50) = 6(2.10)(0.50) + 2(1.00)
a(0.50) = 7.20 m/s^2
Therefore, the acceleration of the object at t = 0.50 s is 7.20 m/s^2.
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Which function in cryptography takes a string of any length as input and returns a string of any requested variable length?
The sponge function in cryptography takes a string of any length as input and returns a string of any requested variable length.
According to the statement
we have to explain about the function in which cryptography takes a string of any length as input and returns a string of any requested variable length.
So, For this purpose,
we know that the
A sponge function or sponge construction is any of a class of algorithms with finite internal state that take an input bit stream of any length and produce an output bit stream of any desired length.
So from definition and its working process it is clear that for this purpose the sponge function is used.
this function returns the string of any variable length.
So, The sponge function in cryptography takes a string of any length as input and returns a string of any requested variable length.
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Pls help math!!!!!!!
A sample of 4 different calculators is randomly selected from a group containing 13 that are defective and 39 that have no defects. What is the probability that at least one of the calculators is defective? Show your answer in decimal format to three places (0.000).
The probability that at least one of the calculators is defective is approximately 0.522.
First, we need to find the probability that none of the calculators are defective.
The probability that the first calculator selected is not defective is 39/52. The probability that the second calculator selected is also not defective is 38/51. The probability that the third calculator selected is not defective is 37/50. And finally, the probability that the fourth calculator selected is also not defective is 36/49.
So, the probability that all four calculators are not defective is:
(39/52) * (38/51) * (37/50) * (36/49) ≈ 0.478
Therefore, the probability that at least one of the calculators is defective is:
1 - 0.478 ≈ 0.522
So, the probability that at least one of the calculators is defective is approximately 0.522.
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A waiter earns tips that has a mean of 7.5 dollars and a standard deviation of 2 dollars. Assume that he collects 100 tips in one week, and each tip is given independently. a. Find the expected total amount of his tips. Express your answer accurate to the three decimal places. b. Find the standard deviation for the total amount of this tips. Express your answer accurate to the three decimal places. c. Find the approximate probability that the total amount of this tips exceeds 720 dollars. d. Express your answer accurate to three decimal places.
To find the probability of exceeding 720, we subtract this value from 1:
Probability = 1 - 0.0668 = 0.9332.
What is Z-score?
The Z-score, also known as the standard score, is a measure of how many standard deviations an individual data point is from the mean of a distribution. It is calculated by subtracting the mean from the data point and dividing the result by the standard deviation. The Z-score allows for the comparison of data points from different distributions and helps determine the relative position of a data point within a distribution.
To solve this problem, we'll use the properties of the mean and standard deviation of a random variable. Let's go through each part step by step:
a. Expected total amount of tips:
The expected value of a random variable is equal to the mean. Since each tip is given independently, the expected total amount of tips is simply the product of the mean and the number of tips:
Expected total amount = Mean * Number of tips = 7.5 * 100 = 750 dollars.
b. Standard deviation for the total amount of tips:
When the random variables are independent, the standard deviation of their sum is the square root of the sum of their variances. Since each tip has a standard deviation of 2 dollars, the standard deviation for the total amount of tips is:
Standard deviation = Square root of (Variance * Number of tips)
Variance = Standard deviation squared = 2^2 = 4
Standard deviation = Square root of (4 * 100) = Square root of 400 = 20 dollars.
c. Probability that the total amount of tips exceeds 720 dollars:
To find this probability, we need to standardize the total amount using the mean and standard deviation, and then find the area under the standard normal distribution curve. Let's calculate the z-score first:
Z = (X - Mean) / Standard deviation
Z = (720 - 750) / 20 = -30 / 20 = -1.5
Using a standard normal distribution table or a calculator, we can find the area to the left of -1.5 (since we want the probability of exceeding 720). This area is approximately 0.0668.
To find the probability of exceeding 720, we subtract this value from 1:
Probability = 1 - 0.0668 = 0.9332.
d. The approximate probability that the total amount of tips exceeds 720 dollars is 0.933.
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please answer as soon as possible, and show work
The instantaneous rate of change of a function let it be f(x) is given by it's first Derivative i.e f'(x) and at a particular point like x = a , it's given by f'(a) . But let's recall a basic formula first :
\({\boxed{\bf{\dfrac{d}{dx}(x^{n})=n{x}^{n-1}}}}\)So , now here ;
\({:\implies \quad \sf f(x)=-4x^{2}+2x}\)
Differentiating both sides w.r.t.x ;
\({:\implies \quad \sf f^{\prime}(x)=-4\dfrac{d}{dx}(x^2)+2\dfrac{dx}{dx}}\)
\({:\implies \quad \sf f^{\prime}(x)=-4\cdot 2 \cdot x+2}\)
\({:\implies \quad \sf f^{\prime}(x)=-8x+2}\)
Now , at x = 3 ;
\({:\implies \quad \sf f^{\prime}(3)=-8(3)+2}\)
\({:\implies \quad \sf f^{\prime}(3)=-24+2}\)
\({:\implies \quad \bf \therefore \quad \underline{\underline{f^{\prime}(3)=-22}}}\)
Hence , the required answer is -22
I will Mark Brainly!!! Please Help its A Math Problem ! image is attached below
The triangles are not similar. Option E
hat are similar triangles?Similar triangles are those triangles that may not be of the same size but a related in the sense of the proportionality in the following ways;
Side Side SideAngle Angle SideSide Angle SideLooking at the two triangles as shown, we can see that they are not related in any of the ways by which we define proportionality of two triangles as such, the triangles are not similar. Option E
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Harry tosses a nickel 4 times. The probability that he gets at least as many heads as tails is.
Solve i dont know if this is one or 2 step equation
I need help with number 4
Answer:
-1=(5+x)/6
mulitply both sides by 6
-6=5+x
subtract both sides by 5
-11=x
Find out the answer to 4x+12=63
Answer:
The answer to this question is x= 51/4
A survey was done that asked people to indicate whether they preferred to ride a
street bike or a mountain bike. The results of the survey are shown in the two-way
table.
Amjed is making a relative frequency table from this data.
What operation should Amjed perform to determine the relative frequency of a
person over 30 years old who prefers to ride a mountain bike? 1) Subtract 25 from 462, then divide by 462. 2) Divide 25 by 462. 3) Add 180 to 462, then divide by 463. 4) Divide 180 by 462
The operation that Amjed should perform to determine the relative frequency of a person over 30 years old who prefers to ride a mountain bike is given as follows:
2) Divide 25 by 462.
How to calculate a probability?The parameters that are needed to calculate a probability are listed as follows:
Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.
The total number of people is given as follows:
58 + 164 + 215 + 25 = 462.
Out of these people, 25 prefer mountain bike, hence the relative frequency is given as follows:
25/462.
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The following quadrilateral is a trapezoid. What is the measurement of the angle J?
Answer:
65
Step-by-step explanation:
A trapezoid means that the lines are parallel, meaning that angle K + angle J = 180. So angle J = 180 = 115 = 65
what is the radius of convergence? what is the intmake sure you name the test that you use. consider the following power series.rval of convergence? use interval notation. what test did you use?
The radius of convergence is the distance from the center of a power series to the nearest point where the series converges, determined using the Ratio Test. The interval of convergence is the range of values for which the series converges, including any endpoints where it converges.
The radius of convergence of a power series is the distance from its center to the nearest point where the series converges.
To determine the radius of convergence, we can use the Ratio Test.
Step 1: Apply the Ratio Test by taking the limit as n approaches infinity of the absolute value of the ratio of consecutive terms.
Step 2: Simplify the expression and evaluate the limit.
Step 3: If the limit is less than 1, the series converges absolutely, and the radius of convergence is the reciprocal of the limit. If the limit is greater than 1, the series diverges. If the limit is equal to 1, further tests are required to determine convergence or divergence.
The interval of convergence can be found by testing the convergence of the series at the endpoints of the interval obtained from the Ratio Test. If the series converges at one or both endpoints, the interval of convergence includes those endpoints. If the series diverges at one or both endpoints, the interval of convergence does not include those endpoints.
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In your reservoir, you have a production well which flows for 48 hours at 200 STB/day, and then shut-in for 24 hours. The following additional data are given : Pi = 3100 psi Ct = 15x10^-6 psi^-1 Bo = 1.3 bbl/STB ϕ = 15% μ=1.2 cp K = 45 md and h = 60 ft
a-) Calculate the pressure in this production well at 12 hours of shut in
b-) Explain how can you use superposition in time to analyze a pressure build-up test.
a) To calculate the pressure at 12 hours of shut-in:
substitute the given values into the pressure buildup equation and solve for P(t=12).
b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.
We have,
a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:
P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))
Where:
P(t) = Pressure at time t
Pi = Initial reservoir pressure
Q = Flow rate
K = Permeability
h = Reservoir thickness
ϕ = Porosity
μ = Viscosity
Ct = Total compressibility
t = Shut-in time (12 hours)
Δt = Time since the start of the flow period
Bo = Oil formation volume factor
ΔP = Pressure drop during the flow period
Given:
Pi = 3100 psi
Q = 200 STB/day
K = 45 md
h = 60 ft
ϕ = 15%
μ = 1.2 cp
Ct = 15x10^-6 psi^-1
Bo = 1.3 bbl/STB
t = 12 hours
Δt = 48 hours
ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))
Substituting the given values into the equation:
ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))
After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.
b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.
It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.
The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.
Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.
It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.
Thus,
a) To calculate the pressure at 12 hours of shut-in:
substitute the given values into the pressure buildup equation and solve for P(t=12).
b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.
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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag
the item to the trashcan. Click the trashcan to clear all your answers.
Find the following expression by multiplying.
(a + b)2
Answer:
\(a^2+2ab+b^2\)
Step-by-step explanation:
If we have \((a+b)^2\) we can calculate this as:
\((a+b)*(a+b)\)
So, applying distribution property, we get:
\((a+b)*(a+b)=a*a+a*b+b*a+b*b\)
Where:
\(a*a=a^{2}\)
\(b*b=b^2\)
\(a*b=b*a=ab\)
so:
\((a+b)*(a+b)=a^2-ab+ab+b^2\\(a+b)*(a+b)=a^2+2ab+b^2\)
Which equation represents a line that passes through the point ( 6 , − 3 ) and is parallel to the graph of y = 3 x + 1 ?
Answer:
y + 3= 3(x - 6) ← point-slope form
y = 3x - 21 ← slope-intercept form
3x - y = 21 ← standard form
Step-by-step explanation:
The point-slope form of the equation of line it's y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the point the line passing through.
y=m₁x+b₁ ║ y=m₂x+b₂ ⇔ m₁ = m₂
{Two lines are parallel if their slopes are equal}
y = 3x + 1 ⇒ m₁ = 3 ⇒ m₂ = 3
(6, -3) ⇒ x₁ = 6, y₁ = -3
point-slope form:
y - (-3) = 3(x - 6)
y + 3 = 3(x - 6)
y + 3 = 3x - 18 {subtact 3 from both sides}
y = 3x - 21 ← slope-intercept form
-3x + y = -21 {multiply both sides by (-1)}
3x - y = 21 ← standard form
A sphere S lying in the first octant (where x, y, and z are all ? 0) has its center C in the plane with equation z = 5 and is tangent to the xz-plane and to the yz-plane. The
page1image3720
distance from the origin to C is sqrt(43)
(a) Find an equation for S of the form (x ? a)2 + (y ? b)2 + (z ? c)2 = r2.
(b) Find the distance between the origin and the point where S touches the xz-plane.
(a) The center of the sphere is in the first octant and is tangent to the xz-plane and to the yz-plane. This means that the center of the sphere is at a point of the form (a,b,5) where a,b≥0. The distance from the origin to the center of the sphere is \(\sqrt{43}\), so we have \(x^{2} +x^{2} +(5-0)^{2} =43\) This gives us \(a^{2} +b^{2} =38\)
The radius of the sphere is the distance from the center of the sphere to the point where the sphere touches the xz-plane. This distance is equal to the length of the hypotenuse of a right triangle with legs of length a and b. Therefore, the radius of the sphere is \(\sqrt{a^{2}+ b^{2} } =\sqrt{38}\)
The equation of the sphere is \((x-a)^{2}+ (y-b)^{2}+ (z-5)^{2} =38\)
(b) The point where the sphere touches the xz-plane is (a,0,5). The distance between the origin and this point is \(\sqrt{a} ^{2}+\sqrt(5-0)^{2} =\sqrt{a^{2} +25}\)
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Please HElppppppppppppp meeeeeeee! I have less than 10 minutes!
Add:
A. 2 1/5 + 3 1/10
B. 472 2/5 + 312 3/4
Answer:
A) 5 3/10
B) 785 3/20
Step-by-step explanation:
Hope this helps <3
you find a common denominator and then simplify all fractions to that common denominator. then, you add them up!
2 1/5 + 3 1/10
5 can fit into 10 twice so it becomes...
2 2/10 + 3 1/10 which equals
5 3/10
472 2/5 + 312 3/4
5 times 4 is 20
472 8/20 + 312 15/20
there is a remainder of 3 for the fractions so you put it over 20.
785 3/20
4-2(x-3)=24 whats the answer to it
\(4 - 2(x - 3) = 24 \\ \)
\(⇒4 - 2x + 6 = 24 \)
\(⇒ - 2x = 24 - 6 - 4\)
\(⇒ - 2x = 14\)
\(⇒x = \frac{14}{ - 2} \)
\(⇒x = - 7\)
Hence, Answer is -7.
_______________________Answer:
- 7
Step-by-step explanation:
Step 1:
4 - 2 ( x - 3 ) = 24 Equation
Step 2:
4 - 2x + 6 = 24 Multiply
Step 3:
- 2x + 10 = 24 Combine Like Terms
Step 4:
- 2x = 14 Subtract 10 on both sides
Step 5:
x = 14 ÷ - 2 Divide
Answer:
x = - 7
Hope This Helps :)
We went to the store and bought 6 giant candy bars and 2 small
bags of jawbreakers and spent $13.00. My friend went to the store
and bought 4 giant candy bars and 6 small bags of jawbreakers
and spent $11.00. How much did a candy bar cost? How much did
a bag of jawbreakers cost?
Answer:
Giant Candy Bar: 2$
Small Bags of Jawbreakers: .50$
Step-by-step explanation:
First you make out the equations, with the variables of c for giant candy bars and j for the small bags of jaw breakers.
First equation we make is 6c+2j=13
The second equation is 4c+6j=11.
You can then make one of the equations a negative and equal to the other. What I mean is we can use the elimination method. So I choose to do -18c+-6j=-39 (Multiplied by -3) so we can eliminate the 2 6js and get 4c=11 and -18c=-39. You then add the remaining equations together to get -14c=-28, so c=2. Using that we can then chose an equation to substitute c with. Ill choose the first one, so you get 6(2)+2j=13. 12+2j=13; 2j=1. By simplifying, you get the jawbreakers as .50 dollars.
A four-sided figure is resized to create a scaled copy. The proportional relationship . between any given side length in the original figure, f, and the corresponding side length in the scaled copy, s, can be represented by the equation s f. What is the constant of proportionality from side lengths in the original figure to side lengths in the scaled copy?
Step 1. When two variables are related, for example, x and y, there will be a constant of proportionality between the x-values and the y-values, this constant of proportionality ''k'' is represented in the general formula for proportionality:
\(y=kx\)Step 2. In this case, we are relating two variables: f and s, through the following equation:
\(s=\frac{1}{7}f\)If we compare this with the equation from step 1, we can see that 1/7 represents the constant of proportionality:
\(k=\frac{1}{7}\)Answer: The constant of proportionality is 1/7
I need help will give 20 points
Answer:
x=136 degrees
Step-by-step explanation:
A quadrilateral inscribed in a circle has opposite angles that add up to 180 degrees. So x + 44 deg = 180 deg. We can solve this to get x = 136 deg.
I hope this solution was helpful. Happy mathing!
23. How many different outfits can be put together using 3 different pairs of pants, 2 shirts and 2 pairs of shoes
There are 12 different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.
There are 12 different outfits that can be put together using 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.
How to solve the problem:
To find out the number of different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes, we will simply multiply the number of options for each category together.
Number of options for pants = 3
Number of options for shirts = 2
Number of options for shoes = 2
Number of different outfits that can be put together
= 3 × 2 × 2
= 12
Therefore, there are 12 different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.
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Cleveland woods earns 126,000 per year he is paid monthly how much is deducted in august for social security for medicare
Answer: The amount deducted for Social Security and Medicare for Cleveland Woods for the month of August would be $1,585.30 ($126,000 x 0.01239).
Step-by-step explanation: