ABCDEFGH is a cuboid the cuboid has length 17 cm width 5 cm height 8 cm work out the size of the angle that AH makes with the plane EFGH

Speed is regarded as the rate at which a particular distance is traveled over time. 138.92 miles  has charlotte traveled in feet during this time

From the information given:

The speed at which charlotte is driving = 64.3 ml/h

The time which she took of her eyes from the road = 3.36 s

During the entire journey, the time at which she took her eyes off the road, she is probably not driving.

∴We will have to convert the 64.3 mi/h to m/s

Since 1 mi/hr = 0.44704 m/s

64.3 mi/h will be:

= (64.3 mi/hr × 0.44704 m/s) ÷ 1 mi/hr

= 30.39872 m/s

Now, using the relation:

Speed = distance/ time

30.39872 m/s = (distance)  / 3.36 s

By Cross multiplying

Distance = 30.39872 m/s  × 3.36 s

Distance = 138.92 m

in conclusion, Charlotte traveled by feet for 138.92 m during this time

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Answer:

534.1875

Step-by-step explanation:

7500 ⋅ (1+3.5%)²-7500

534.1875

Answer:

m = 7

Step-by-step explanation:

2m + -4 = 10

Reorder the terms:

-4 + 2m = 10

Solving

-4 + 2m = 10

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '4' to each side of the equation.

-4 + 4 + 2m = 10 + 4

Combine like terms: -4 + 4 = 0

0 + 2m = 10 + 4

2m = 10 + 4

Combine like terms: 10 + 4 = 14

2m = 14

Divide each side by '2'.

m = 7

Simplifying

m = 7

Let \(P(t) = 240.480 / (1 + 39e^(-0.3t))\) = \(2401 + 39e^(-0.3t)\) = \(248e^(-0.3t)\)= 8.Taking the natural logarithm of both sides, we obtain:\(ln e^(-0.3t) = ln (8)\),\(t = (-1/0.3) ln(8)\).We get:t = 7.9 to one decimal point.

Here we are required to find the time at which the number of infected students will be 240. We are given a function which models the number of students infected with the flu on a college campus after t days. The function is given by

\(P(t) = 480 / (1 + 39e^(-0.3t)).\).

To determine the time at which P(t) = 240, we substitute this value of P(t) into the function. That is:

\(240 = 480 / (1 + 39e^(-0.3t))\)

Multiplying both sides of the equation by \((1 + 39e^(-0.3t))\), we get:

\(240(1 + 39e^(-0.3t)) = 480\)

Distributing the left-hand side, we obtain:

\(240 + 936e^(-0.3t) = 480\)

Subtracting 240 from both sides, we get:

\(936e^(-0.3t) = 240\)

Simplifying this expression by dividing both sides by 936, we obtain:

\(e^(-0.3t) = 0.2564\)

Taking the natural logarithm of both sides, we obtain:

\(ln e^(-0.3t) = ln (0.2564)\)

\(ln e^(-0.3t) = -0.3t\\\\ln (0.2564) = -0.3t\)

Dividing both sides by -0.3, we obtain:

\(t = (-1/0.3) ln (0.2564)\)

Simplifying this expression, we obtain:

t ≈ 8 days

Therefore, the number of infected students will be 240 after approximately 8 days.the number of infected students on a college campus after t days is given by \(P(t) = 480 / (1 + 39e^(-0.3t)).\) To determine the time at which the number of infected students will be 240, we substitute this value into the function and solve for t. We obtain t ≈ 8 days.

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Answer:

4,234 dekaliters converted to milliliters is 42340000.

Step-by-step explanation:

Answer: Your answer is going to be 42340000 millimeters.

Step-by-step explanation:

Find out how much one dekaliter is worth; multiply by that amount.

Answer:

1 / 243

Step-by-step explanation:

To write 3^-5 using a positive exponent, we can use the rule that a negative exponent is equivalent to the reciprocal of the same quantity raised to the positive exponent. In other words:

a^(-n) = 1 / a^n

Applying this rule to 3^-5, we get:

3^-5 = 1 / 3^5

Now we can simplify 3^5 as:

3^5 = 3 x 3 x 3 x 3 x 3 = 243

So, the answer is 1 / 243

Answer:

\(\frac{1}{3^5}\)

Step-by-step explanation:

using the rule of exponents

\(a^{-m}\) = \(\frac{1}{a^{m} }\)

then

\(3^{-5}\) = \(\frac{1}{3^5}\)

Answer:

1 cup

Step-by-step explanation:

for each cup of cheese you need one cup of milk so for every cup of milk you need one cup of cheese :))

we have the next squared binomial

we have the next formula in order to expand a squared binomial

So we can expand

so the correct answer is the first one

Answer:

X= 70º and Y= 60º

Step-by-step explanation:

Looing at the Triangles, those lines represent that the angles of the other side are equal.

In this case we have an Isosceles triangle and a Equilateral.

We got the angle of 55º and since it is Isosceles we get another 55º getting us 110º.

In a Triangle there is 180º so that would leave x as 70º.

Because there is one solid line for the smaller triangle, this states that it is a equilateral and thus makes y be 60º.

The width of the previous image was 9.5 millimeters.

If the new image is an enlargement of the previous image with a scale factor of 2, it means that the width of the new image is twice the width of the previous image.

Let's denote the width of the previous image as "x" millimeters.

According to the information given, the width of the new image is 19 millimeters.

Since the new image is an enlargement with a scale factor of 2, we can set up the following equation:

\(2x = 19\)

To find the width of the previous image, we need to solve this equation for "x."

Dividing both sides of the equation by 2, we get:

\(x=\frac{19}{2}\)

\(x = 9.5\)

Therefore, the width of the previous image was 9.5 millimeters.

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Answer:

you cut the yards by 0 ez B)

Answer:

g = 8.7

Step-by-step explanation:

3.1 (g - 7) = 5.2

Multiply by 3.1

3.1g - 21. 7 = 5.2

Add 21.7 to both sides

3.1g = 5.2 + 21.7

3.1g = 26.9

Divide both sides by 3.1

g = 26.9 / 3.1

g = 8.677 = 8.7

Answer:

x=4 and y=2

Step-by-step explanation:

The return value of the function call round(3.14159, 3) is c. 3.14. The round function rounds the first argument (3.14159) to the number of decimal places specified in the second argument (3). In this case, it rounds to 3.14.

The function call in your question is round(3.14159, 3). The "round" function takes two arguments: the number to be rounded and the number of decimal places to round to. In this case, the number to be rounded is 3.14159 and the desired decimal places are 3.

The return value is the result of the rounding operation. In this case, rounding 3.14159 to 3 decimal places gives us 3.142.

So, the correct answer is:

b. 3.142

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Answer:

5/64

Step-by-step explanation:

5/8 : 8 = 5/8 * 1/8 = 5/64

Answer:

12 4/5

Step-by-step explanation:

simplified

The measure of angle A in the isosceles triangle ABC is 62.5 degrees.

In an isosceles triangle ABC, where AB = AC, we are given that angle B (denoted as ∠B) measures 55 degrees. We need to calculate the measure of angle A (denoted as ∠A).

Since AB = AC, we know that angles A and C are congruent (denoted as ∠A ≅ ∠C). In an isosceles triangle, the base angles (the angles opposite the equal sides) are congruent.

Therefore, we have:

∠A ≅ ∠C

Also, the sum of the angles in a triangle is always 180 degrees. Hence, we can write:

∠A + ∠B + ∠C = 180

Substituting the given values:

∠A + 55 + ∠A = 180

Combining like terms:

2∠A + 55 = 180

Subtracting 55 from both sides:

2∠A = 180 - 55

2∠A = 125

Dividing by 2:

∠A = 125 / 2

∠A = 62.5

Therefore, the measure of angle A in the isosceles triangle ABC is 62.5 degrees.

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Answer:

1/3

Step-by-step explanation:

4 • 1/12

1/3

Answer:

2/5

Step-by-step explanation:

Answer:

rise over run (change in y divided by change in x)

so it would go as follows

\(\frac{(3-1)}{(4-9)}\)

= \(\frac{2}{-5}\)

= \(-\frac{2}{5}\)

Answer: - (2/5)

Step-by-step explanation:

(y2-y1) / (x2- x1) =

(1-3) / (9-4)

= - (2/5)

Answer:

A.) 93

B.) 77

C.) 369

Step-by-step explanation:

Answer:

Its the same one that I answered lol

Step-by-step explanation:

The answers to the questions are:

a) The acceleration of the system is approximately 6.92 m/s^2 to the right, given an applied force of 45 N.

b) The tension in the cord connecting the 3.5 kg and 3.0 kg blocks is 24.22 N.

c) The force exerted by the 1.0 kg block on the 2.0 kg block is 13.84 N. If the 2.0 kg block is stacked on top of the 1.0 kg block and they stick together, the new acceleration is 15 m/s^2 to the right and the tension remains 24.22 N.

a) To determine the acceleration of the system, we can apply Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, the net force acting on the system is the applied force of 45 N. Since the system consists of the three blocks connected by a cord, the acceleration will be the same for all the blocks. Therefore, we can calculate the acceleration using the total mass of the system:

Total mass (m_total) = m1 + m2 + m3 = 1.0 kg + 2.0 kg + 3.5 kg = 6.5 kg

Using Newton's second law, we can calculate the acceleration (a):

Net force (F_net) = m_total * a

45 N = 6.5 kg * a

a = 45 N / 6.5 kg ≈ 6.92 m/s^2 (to the right)

b) To determine the tension in the cord connecting the 3.5 kg and 3.0 kg blocks, we need to consider the forces acting on the 3.5 kg block. The tension in the cord will be equal to the force exerted by the 3.5 kg block on the 3.0 kg block.

Using Newton's second law for the 3.5 kg block:

Tension = m3 * a

Tension = 3.5 kg * 6.92 m/s^2 = 24.22 N

Therefore, the tension in the cord connecting the 3.5 kg and 3.0 kg blocks is 24.22 N.

c) To determine the force exerted by the 1.0 kg block on the 2.0 kg block, we need to consider the forces acting on the 2.0 kg block. The force exerted by the 1.0 kg block on the 2.0 kg block will be equal in magnitude but opposite in direction to the force exerted by the 2.0 kg block on the 1.0 kg block.

Using Newton's second law for the 2.0 kg block:

Force exerted by 1.0 kg block = m2 *

Force exerted by 1.0 kg block = 2.0 kg * 6.92 m/s^2 = 13.84 N

Therefore, the force exerted by the 1.0 kg block on the 2.0 kg block is 13.84 N.

d) If the 2.0 kg block is now stacked on top of the 1.0 kg block and they stick together, the total mass of the combined blocks will change. The new total mass (m_total) will be the sum of the masses of the 1.0 kg and 2.0 kg blocks:

m_total = m1 + m2 = 1.0 kg + 2.0 kg = 3.0 k

Using Newton's second law, we can calculate the new acceleration (a):

Net force (F_net) = m_total * a

45 N = 3.0 kg * a

a = 45 N / 3.0 kg = 15 m/s^2 (to the right)

The tension in the cord connecting the blocks will remain the same, as the 3.0 kg block is now part of the combined mass. Therefore, the tension will still be 24.22 N.

The question is:

Assume the three blocks, (m1= 1.0kg, m2= 2.0 kg,  and m3=3.5 kg) move on a frictionless surface and a force, f = 45 N acts on the 3.5kg block.

a) Determine the acceleration given this system (m/s^2 to the right)

b) Determine the tension in the cord connecting the 3.5 kg and 3.0 kg blocks. (in N)

c) Determine the force exerted by 1.0 kg block on 2.0 kg block. (in N)

d) How would the answers to part a) and part b) change if the 2.0 kg block is now stacked on the top 1.0 kg block?

Assume that the 2.0 kg block sticks to and does not slide on the 1.0 kg block when the system is accelerated (Enter the acceleration in m/s^2  to the right and the tension in N).

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Answer:

36

Step-by-step explanation:

consider the multiples of each denominator

9 : 9, 18, 27, 36, 45, .....

12 : 12, 24, 36, 48, 60, ......

the lowest multiple gives the lowest common denominator , that is 36

Answer:

The mass of Sun is \(65\times 10^5\) times greater than mass of Mercury.

Step-by-step explanation:

We are given that

Mass of the sun=\(M=2.13525\times 10^{30}\) kg

Mass of Mercury, \(m=3.285\times 10^{23}\)kg

We have to find how many times greater is the mass of the sun than the mass of Mercury.

Mass of sun/Mass of mercury=\(\frac{2.13525\times 10^{30}}{3.285\times 10^{23}}\)

Mass of sun/Mass of mercury\(=0.65\times 10^{30-23}\)

Using the property

\(a^x/a^y=a^{x-y}\)

Mass of sun/Mass of mercury\(=0.65\times 10^{7}\)

Mass of sun/Mass of mercury\(=65\times 10^5\)

Mass of Sun=\(65\times 10^5\) times Mass of Mercury

Hence, the mass of Sun is \(65\times 10^5\) times greater than mass of Mercury.

The probability of being dealt a 3, 4, 5, 6, 7, all in the same suit is approximately 0.0000031.

To calculate the probability of being dealt a 3, 4, 5, 6, 7, all in the same suit, we can use the following formula:

P = (number of favorable outcomes) / (total number of possible outcomes)

the order in which the cards are chosen does not matter, so we need to divide by the number of ways we can arrange 5 cards, which is 5! (5 factorial).

Therefore, the total number of possible outcomes is (52 * 51 * 50 * 49 * 48) / (5 * 4 * 3 * 2 * 1), which simplifies to 2,598,960.

Finally, we can calculate the probability of being dealt a 3, 4, 5, 6, 7, all in the same suit:

P = 8 / 2,598,960

P = 0.00000308 (rounded to seven decimal places)

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Answer:

x=9, y=15. (9, 15).

Step-by-step explanation:

y=2x-3

y=x+6

----------

2x-3=x+6

2x-x-3=6

x-3=6

x=6+3

x=9

y=9+6=15

The required solution for the hypothesis testing is shown.

Statistics is the study of mathematics that deals with relations between comprehensive data.

Here,
Part A:

The null hypothesis (H0) is that the company's claim is true, and the proportion of defective batteries is 5% or less.

The alternative hypothesis (Ha) is that the company's claim is false, and the proportion of defective batteries is greater than 5%.

H0: p ≤ 0.05

Ha: p > 0.05

where p represents the proportion of defective batteries.

Part B:

A Type I error in this context would be rejecting the null hypothesis (i.e., finding significant evidence that the proportion of defective batteries is greater than 5%) when it is actually true (i.e., the proportion of defective batteries is 5% or less). This would be a false positive result.

A Type II error would be failing to reject the null hypothesis (i.e., not finding significant evidence that the proportion of defective batteries is greater than 5%) when it is actually false (i.e., the proportion of defective batteries is greater than 5%). This would be a false negative result.

Part C:

If the hypothesis is tested at a 5% level of significance instead of 1%, this means that the criteria for rejecting the null hypothesis will be less stringent. In other words, it will be easier to find significant evidence that the company's claim is false. Therefore, increasing the level of significance from 1% to 5% will increase the power of the test.

Part D:

If the hypothesis is tested based on the sampling of 500 boxes of batteries rather than 100 boxes of batteries, this means that the sample size is larger. As a result, the standard error of the estimate will be smaller, and the test will be more precise. This increased precision will increase the power of the test.

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Answer:

$1.2

Step-by-step explanation:

18 Chicken Wings / $15 = $1.2