A
A student thinks that the hexagon in the diagram to the right
has 12 lines of symmetry. Explain and correct the student's
error.
M
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
O A. The student counted the total number of arrow heads when they should have just counted the number of lines. Therefore, the correct answer is
OB. The student counted the total number of lines when they should have just counted the number of arrow heads. Therefore, the correct answer is
O C. The student did not make an error when determining the lines of symmetry.

Answer:

70¢

Step-by-step explanation:

$8.40/12 bars equals $0.70

6/11 is the probability that a randomly selected student speaks French, given that the student is male

It is a branch of mathematics that deals with the occurrence of a random event.

There are 11 members who speak french and 5 are females in 11 members

5/11

p(a given b) = p(a and b) / p(b).

6 of the people in the group are men that speak french, then the probability of (a and b) becomes 6/40

probability that a person speaks french is 11/40

p(a given b)=6/40/11/40

=6/40×40/11=6/11

Hence, 6/11 is the probability that a randomly selected student speaks French, given that the student is male.

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Answer:

x = 3/2 or x = -1

Step-by-step explanation:

2x² - x - 3 = 0

2*(-3) = -6

Factors of -6:

(-1, 6), (1, -6), (-2, 3), (2, -3)

We need to find a pair that adds up to the co-eff of x which is (-1)

Factors :(2,-3)

2 - 3 = -1

so, 2x² - x - 3 = 0 can be written as:

2x² + 2x - 3x - 3 = 0

⇒ 2x(x + 1) -3(x + 1) = 0

⇒ (2x - 3)(x + 1) = 0

⇒ 2x - 3 = 0 or

x + 1 = 0

⇒ 2x = 3 or x = -1

⇒ x = 3/2 or x = -1

The set that represents the range of the function given is -

{-2, 0, 3, 5}

The range of a function is the complete set of all possible resulting values of the dependent variable (y), after we have substituted the domain.

Given is a graph as shown in the image.

For the given graph, the set of {y} coordinates represent the range of the function. So, the set that represents the range of the function given is -

{-2, 0, 3, 5}

Therefore, the set that represents the range of the function given is -

{-2, 0, 3, 5}

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For the  trigonometric identity

11. If cos 27° = x, then the value of tan 63° interims of "x" is  x/√1 - x²

12. If Θ be an acute angle and 7sin²Θ + 3 cos²Θ= 4, then tan Θ is  1/√3

13. The value of tan 80° × tan 10° + sin² 70° + sin² 20° is 2

14. The value of (sin 47°/cos 43°)² + (cos 43°/sin 47°) -  4 cos²45° is 0

15. If 2 (cos²Θ - sin²Θ) = 1, Θ is a positive acute angle them the value of Θ is  30°

16. If 5 tan Θ = 4, then (5 sin Θ - 3 cos Θ)/(5 sin Θ + 2 cos Θ) is equal to 1/6

17. If sin(x + 20)° = cos (x + 10)° then the value of "x" is  30°

18. The value of (sin 65°)/ (cos 25°) is 1

To solve the various   trigonometric identity;

11. Given: cos 27° = x

We know that cos (90 - θ) = sin θ

So, cos 63° = sin 27°

And sin 63° = √1 - cos²27°

Substituting cos 27° = x, we get

sin 63° = √1 - x²

Therefore, Therefore, tan 63° = sin 63° / cos 63° = cos 27° / cos 63° = x / cos 63°.

= x/√1 - x²

12. Given: Θ is an acute angle and 7sin²Θ + 3 cos²Θ= 4

Since Θ is an acute angle, sin²Θ + cos²Θ = 1

Substituting sin²Θ + cos²Θ = 1 into the equation 7sin²Θ + 3 cos²Θ= 4, we get

7 (sin²Θ/ cos²Θ) + 3 = 4/cos²Θ - 4 sec²Θ

⇒ 7tan²Θ + 3 = 4(1 + tan²Θ)

⇒ 7tan²Θ + 3 = 4 + 4 tan²Θ

⇒3 tan²Θ = 1

⇒ tan²Θ = 1/3

⇒ tanΘ = 1/√3

13. For tan 80° × tan 10° + sin² 70° + sin² 20°

⇒ tan 80° = cot (90 - 80)° = cot 10°

⇒  sin 70° = cos (90 - 70) = cos 20°

⇒ cot 10° × tan 10° +  cos 20° + sin² 20°

= 1 + 1 = 2

14. (sin 47°/cos 43°)² + (cos 43°/sin 47°) - 4 cos²45°

= (sin 47°/cos43°)² + (cos 43°/sin 47°)² - 4(1/√2)²

= (sin (90° - 43°)/cos43°)² +  (cos (90° - 47°)/sin)²  = 4(1/2)

= (cos 43°/cos 43°)² + (sin 47°/ sin   47°)² - 2

= 1 + 1 - 2 = 0

15. 2 (cos²Θ - sin²Θ) = 1

cos²Θ - sin²Θ = 1/2

Since Θ is an acute angle, sin²Θ + cos²Θ = 1

Substituting sin²Θ + cos²Θ = 1 into the equation cos²Θ - sin²Θ = 1/2, we get

cos²Θ - (1 - cos²Θ) = 1/2

2cos²Θ = 3/2

cos Θ = √3/2(cos 30° = (√3)/2

= 30°

16. Given: 5 tan Θ = 4

We know that tan Θ = sin Θ / cos Θ

So, 5 sin Θ / cos Θ = 4

5 sin Θ = 4 cos Θ

Dividing both sides of the equation by 5, we get

sin Θ / cos Θ = 4/5

∴ sin Θ = 4/5 cos Θ

given that the expression is (5 sin Θ - 3 cos Θ)/(5 sin Θ + 2 cos Θ)

we substitute sin Θ = 4/5 cos Θ  into the equation

⇒(5 × 4/5 cos Θ  - 3 cos Θ)/(5 × 4/5 cos Θ  + 2 cos Θ)

= (4-3)/(4 + 2) = 1/6

17. Given: sin(x + 20)° = cos (x + 10)°

We know that sin(90 - θ) = cos θ

So, sin(x - 20)° = sin(90 - (3x + 10))°

⇒ (x - 20)° = (90 - (3x + 10))°

⇒ x - 20° = 90° - 3x + 10

⇒ 4 x = 120°

⇒ x = 120°/4

⇒ x = 30°

18. To find the value of (sin 65°) / (cos 25°), we can use the trigonometric identity:

To solve this, we can use the following trigonometric identities:

sin(90 - θ) = cos θ

cos(90 - θ) = sin θ

We can also use the fact that sin²θ + cos²θ = 1.

Rewrite sin (65°) / cos (25°)

⇒ sin (65°) = cos (25°)

∴ cos (25°)/ cos (25°) = 1

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Answer: the answer is 55

The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:

Equilateral triangle MNQ inscribed in circle C

Regular hexagon AMNBPQ inscribed in circle C

Brian is constructing figures inscribed in circle C.

Equilateral triangle MNQ inscribed in circle C:

This option is possible since the points M, N, and Q are labeled and they lie on circle C.

Equilateral triangle ANP inscribed in circle C:

This option is not possible. The points A and P are labeled, but the third vertex of the equilateral triangle is not specified.

Regular hexagon AMNBPQ inscribed in circle C:

This option is possible since the points A, M, N, B, P, and Q are labeled and they lie on circle C.

Square MNPQ inscribed in circle C:

This option is not possible based on the given information. The label points do not form a square.

Square ANBQ inscribed in circle C:

This option is not possible . The points A, N, B, and Q are labeled, but they do not form a square.

The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:

Equilateral triangle MNQ inscribed in circle C

Regular hexagon AMNBPQ inscribed in circle C

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Answer:

3-√11  must also be a root of f(x)

Step-by-step explanation:

Answer:

I think it is 20 < x > 9. But I am not completely sure.

Luisa's total annual contribution is $2,776 and her biweekly deduction is $106.77.

Algebraic expressiοn can be defined as cοmbinatiοn οf variables and cοnstants.

First, let's calculate hοw much Luisa's emplοyer pays fοr the traditiοnal grοup medical insurance prοgram:

Employer contribution = 75% of $6,288 = 0.75 x $6,288 = $4,716

Next, let's calculate Luisa's annual contribution for the medical insurance program:

Luisa's contribution = Total cost - Employer contribution

Luisa's contribution = $6,288 - $4,716

Luisa's contribution = $1,572

To calculate Luisa's total annual contribution, we need to add her contributions for the optional dental and vision premiums:

Total annual contribution = Luisa's contribution + Dental premium + Vision premium

Total annual contribution = $1,572 + $880 + $324

Total annual contribution = $2,776

To calculate Luisa's biweekly deduction, we divide her total annual contribution by the number of pay periods in a year. Assuming there are 26 biweekly pay periods in a year:

Biweekly deduction = Total annual contribution / Number of pay periods

Biweekly deduction = $2,776 / 26

Biweekly deduction = $106.77 (rounded to the nearest cent)

Therefore, Luisa's total annual contribution is $2,776 and her biweekly deduction is $106.77.

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Transformation is a process in which the dimensions or orientation of a given plane shape is changed. The required answers are:

Graph 1: Reflection

Graph 2: Translation

Graph 3: Rotation

Graph 4: Rotation

Graph 5: Translation

Graph 6: Reflection

Transformation is the process in which the dimensions or orientation is a given shape is changed. The major types are reflection, dilation, translation, and rotation.

Thus the transformation process that was applied to the original figure for each graph is:

Graph 1: Reflection along the y-axis

Graph 2: Translation at 4 units in the -x direction

Graph 3: \(90^{o}\)  clockwise Rotation

Graph 4: \(180^{o}\)  clockwise Rotation

Graph 5: Translation

Graph 6: Reflection along the x-axis

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Answer:

44

Step-by-step explanation:

The angle measuring x is an exterior angle of the triangle. Its remote interior angles are the angles measuring 14 deg and 30 deg.

Theorem:

The measure of an exterior angle of a triangle is equal to the sum of the measures of its remote interior angles.

x = 14 + 30

x = 44

Answer:

x = 44°

Step-by-step explanation:

Given: Angle A, Angle C

Angle A + Angle C + Angle B = 180

14° + 30° + Angle B = 180°

44° + Angle B = 180°

Angle B = 180° - 44°

Angle B = 136°

Now,

Angle B + Angle x = 180°

136° + Angle x = 180°

Angle x = 180° - 136°

Angle x = 44°

Hope it helps!

Answer:

Step-by-step explanation:

THE ANSWER TO YOUR QUESTION IS C.

Answer:-50/7 or -7.143

Step-by-step explanation:

you have to turn the 3 4/7 into an improper fraction by this:

3x7=21

21+4=25

which makes it 25/7

(25/7)x(-2) = -50/7 or -7.143

Answer:

B

Step-by-step explanation:

The interest paid for the loan is $1748

Given that there is a 6.1% interest rate for a loan of $28,654 in student loan debt pay in the first year,

We need to find the interest paid for the same.

So,

Simple Interest = principal × time × rate / 100

= 28654 × 1 × 6.1 / 100

= 28654 × 0.061

= 1747.894

= 1748

Hence the interest paid for the loan is $1748

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Answer: 2.117647

Step-by-step explanation:

Answer:

just ecause you have the name juan in ur name i will answer. 2 2/17.  ill even do 7 for ya. . . its 3

Step-by-step explanation:

The correct option of system of equations that can be used to find the temperature at which the degrees Celsius and the degrees Fahrenheit would be equivalent is the option;

5·F - 9·C = 160

F - C = 0

A system of equation, is a set of equation that have common variables.

The equation for conversion of the temperature in degrees Celsius to the temperature in degrees Fahrenheit is; 9·C = 5·F - 160

When the temperature in degrees Celsius is equivalent to the temperature in degrees Fahrenheit, we get;

F = C

Therefore;

F - C = 0

Similarly, from the specified equation, we get;

9·C = 5·F - 160

5·F - 9·C = 160

The system of equation that would give the temperature where the degrees Celsius and degrees Fahrenheit are equivalent is therefore;

5·F - 9·C = 160

F - C = 0

(Which yields a temperature of 40°)

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Answer:

£21

Step-by-step explanation:

Cost of 18 drinks = £54

Cost of 1 drink

= Cost of 18 drinks/18

= £54/18

= £3

Cost of 7 drinks

= Cost of 1 drink × 7

= £3 × 7

= £21

Answer:

-2

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

Step 1: Define

y = -2x + 3

Step 2: Identify

Break function

Slope m = -2

y-intercept b = 3

Answer:

The slope of the tangent line to the curve at the given point is -11/7.

Step-by-step explanation:

Differentiation is an algebraic process that finds the gradient (slope) of a curve.  At a point, the gradient of a curve is the same as the gradient of the tangent line to the curve at that point.

Given function:

\(4x^2+5xy+y^4=370\)

To differentiate an equation that contains a mixture of x and y terms, use implicit differentiation.

Begin by placing d/dx in front of each term of the equation:

\(\dfrac{\text{d}}{\text{d}x}4x^2+\dfrac{\text{d}}{\text{d}x}5xy+\dfrac{\text{d}}{\text{d}x}y^4=\dfrac{\text{d}}{\text{d}x}370\)

Differentiate the terms in x only (and constant terms):

\(\implies 8x+\dfrac{\text{d}}{\text{d}x}5xy+\dfrac{\text{d}}{\text{d}x}y^4=0\)

Use the chain rule to differentiate terms in y only. In practice, this means differentiate with respect to y, and place dy/dx at the end:

\(\implies 8x+\dfrac{\text{d}}{\text{d}x}5xy+4y^3\dfrac{\text{d}y}{\text{d}x}=0\)

Use the product rule to differentiate terms in both x and y.

\(\boxed{\dfrac{\text{d}}{\text{d}x}u(x)v(y)=u(x)\dfrac{\text{d}}{\text{d}x}v(y)+v(y)\dfrac{\text{d}}{\text{d}x}u(x)}\)

\(\implies 8x+\left(5x\dfrac{\text{d}}{\text{d}x}y+y\dfrac{\text{d}}{\text{d}x}5x\right)+4y^3\dfrac{\text{d}y}{\text{d}x}=0\)

\(\implies 8x+5x\dfrac{\text{d}y}{\text{d}x}+5y+4y^3\dfrac{\text{d}y}{\text{d}x}=0\)

Rearrange the resulting equation in x, y and dy/dx to make dy/dx the subject:

\(\implies 5x\dfrac{\text{d}y}{\text{d}x}+4y^3\dfrac{\text{d}y}{\text{d}x}=-8x-5y\)

\(\implies \dfrac{\text{d}y}{\text{d}x}(5x+4y^3)=-8x-5y\)

\(\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{-8x-5y}{5x+4y^3}\)

To find the slope of the tangent line at the point (-9, -1), substitute x = -9 and y = -1 into the differentiated equation:

\(\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{-8(-9)-5(-1)}{5(-9)+4(-1)^3}\)

\(\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{72+5}{-45-4}\)

\(\implies \dfrac{\text{d}y}{\text{d}x}=-\dfrac{77}{49}\)

\(\implies \dfrac{\text{d}y}{\text{d}x}=-\dfrac{11}{7}\)

Therefore, slope of the tangent line to the curve at the given point is -11/7.

The probability of getting a black card and a numbered card is 9/26.

To calculate the probability of getting a black card (E1), we need to determine the number of black cards in a standard deck of 52 cards.

There are 26 black cards in total, which consist of 13 spades (black) and 13 clubs (black).

Therefore, the probability of drawing a black card (P(E1)) is:

P(E1) = Number of favorable outcomes / Total number of possible outcomes

P(E1) = 26 / 52

Simplifying this fraction, we get:

P(E1) = 1/2

So the probability of drawing a black card is 1/2.

To calculate the probability of drawing a numbered card (E2), we need to determine the number of numbered cards (2 through 10) in a standard deck.

Each suit (spades, hearts, diamonds, clubs) contains one card for each numbered value from 2 to 10, totaling 9 numbered cards per suit.

Therefore, the probability of drawing a numbered card (P(E2)) is:

P(E2) = Number of favorable outcomes / Total number of possible outcomes

P(E2) = 36 / 52

Simplifying this fraction, we get:

P(E2) = 9/13

So the probability of drawing a numbered card is 9/13.

To calculate the probability of both events occurring together (getting a black card and a numbered card), we multiply the individual probabilities:

P(E1 ∩ E2) = P(E1) × P(E2)

P(E1 ∩ E2) = (1/2) × (9/13)

Simplifying this fraction, we get:

P(E1 ∩ E2) = 9/26

Therefore, the probability of getting a black card and a numbered card is 9/26.

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Step-by-step explanation:

I need followers please

Answer:

learning only lang po yan

Answer:

Area = 30

Step-by-step explanation:

Formula for triangle: bh/2

12*5/2

60/2

= 30

Yes, Matrix B is invertible.

And, The eigenvalues of B−1 are;

⇒ (5 ± 7.68) / 14 - 1

An Invertible Matrix is a square matrix defined as invertible if the product of the matrix and its inverse is the identity matrix.

Given that;

B be a 2 ×2 matrix such that;

⇒ 7B² −5B + 3I = 0

Now,

Since, B be a 2 ×2 matrix.

And, The expression is,

⇒ 7B² −5B + 3I = 0

⇒ B² −5/7B + 3I/7 = 0

Multiply by B⁻¹, we get;

⇒ B - 5/7 + 3B⁻¹ = 0

Solve for B⁻¹;

⇒ 3B⁻¹ = - B + 5/7

⇒ B⁻¹ = - B/3 + 5/21

Thus, The matrix B is invertible.

And, The eigen value of B are;

⇒ 7B² −5B + 3I = 0

⇒ 7B² −5B + 3I = 0

⇒ B = - (-5) ± √(-5)² - 4×7×3 / 2×7

⇒ B = 5 ± √25 - 84/14

⇒ B = 5 ± √- 59 / 14

⇒ B = 5 ± 7.68 i / 14

⇒ B - 1 = (5 ± 7.68) / 14 - 1

Thus, Matrix B is invertible.

The eigenvalues of B−1 are = (5 ± 7.68) / 14 - 1

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The limit of the function As x → - ∞, f(x) → 2.

The limit of a function is the value the function tends to as the independent variable tends to a given value.

Given the graph of the function above, to find the limit of the function As x → -∞, f(x) →? We proceed as follows

Looking at the graph, we see that f(x) has a horizontal asymptote at y = 2. Now, we see that As x → -∞, f(x) approaches 2.

So, As x → - ∞, f(x) → 2.

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