According to hubble's law, with h0h0h_0 = 70 km/s/mpckm/s/mpc , how far away is a galaxy whose recessional velocity is 6000 km/skm/s ?

True. The retentive timer reset (RES) instruction is always given the same address as the timer it resets.

This ensures that the correct timer is targeted and its accumulated value is reset to zero when the RES instruction is executed.The retentive timer reset (RES) instruction is always given the same address as the timer it resets in order to identify the timer being reset. This allows the instruction to reset the timer safely without affecting any other timers in the system.The Retentive Timer Reset (RES) is a feature of a timer that allows it to retain its current value and continue counting or timing after the timer has been reset. This feature is useful in applications where an event needs to be triggered after a certain period of time and the time period needs to be reset or restarted after it has been previously triggered.

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Answer:

4 ohms

Explanation:

Current = Voltage/resistance

2 = 8/R

2R = 8

R = 4

Answer:

Etc....

Explanation:

#keep learning!!

Explanation:

POTENTIAL energy is the energy that is stored in an object due to its position relative to some zero position.

A horizontal force Fslide is exerted on a 9.0-kg box sliding on a polished floor, the box's speed is approximately 1.39 m/s.

To determine the box's speed at t = 5.0 s, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration:

Fnet = m * a

In this case, the only force acting on the box is the horizontal force Fslide. Since there is no friction between the box and the floor, the net force is equal to the applied force:

Fnet = Fslide

We know that the magnitude of Fslide increases smoothly from 0 to 5.0 N in 5.0 s. This implies that the force is changing uniformly, and we can calculate its average value using the formula:

Favg = (Finitial + Ffinal) / 2

where Finitial is the initial magnitude of the force (0 N) and Ffinal is the final magnitude of the force (5.0 N).

Given:

m (mass of the box) = 9.0 kg

Finitial = 0 N

Ffinal = 5.0 N

t = 5.0 s

Using the formula for average force, we can calculate Favg:

Favg = (Finitial + Ffinal) / 2

Favg = (0 N + 5.0 N) / 2

Favg = 2.5 N

Now, we can use Favg and Newton's second law to find the acceleration (a) of the box:

Fnet = m * a

Favg = m * a

2.5 N = 9.0 kg * a

Solving for a:

a = 2.5 N / 9.0 kg

a ≈ 0.278 m/s²

With the acceleration value, we can determine the box's speed at t = 5.0 s by using the following kinematic equation:

v = u + a * t

where:

v is the final velocity (speed)

u is the initial velocity (speed), which is 0 m/s since the box starts from rest

a is the acceleration (0.278 m/s²)

t is the time (5.0 s)

Plugging in the values, we can calculate the speed at t = 5.0 s:

v = u + a * t

v = 0 m/s + 0.278 m/s² * 5.0 s

v ≈ 1.39 m/s

Therefore, the box's speed at t = 5.0 s, starting from rest, is approximately 1.39 m/s.

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Answer:

30 m

Explanation:

Potential energy = kinetic energy + rotational energy

PE = KE + RE

mgh = ½ mv² + ½ Iω²

For a disk, I = ½ mr².  For rolling without slipping, ω = v/r.

mgh = ½ mv² + ½ (½ mr²) (v/r)²

mgh = ½ mv² + ¼ m v²

mgh = ¾ m v²

gh = ¾ v²

h = 3v² / (4g)

h = 3 (20 m/s)² / (4 × 10 m/s²)

h = 30 m

Answer:

The answer is the First One

Explanation:

Electromagnets can work with a magnetic source, and not just electric. sorry if my answer turns out to be wrong

When trying to establish economical hauling, hauling distance is usually the most important factor to consider. Hauling distance refers to the  point of origin and the destination of the goods being transported.

The farther the distance, the higher the cost of transportation, as it requires more time, fuel, and resources to haul the goods. While other factors such as hauling time, means of hauling, and what is being hauled can also impact the cost and efficiency of transportation, the distance typically has the most significant impact on the overall cost. Therefore, it is crucial to consider the hauling distance when trying to establish an economical hauling plan. To minimize the cost of transportation, various strategies can be employed, such as optimizing the routing to reduce the distance traveled, utilizing more efficient means of transportation, such as rail or water transport, and using technology to improve logistics and reduce waste. Ultimately, the goal of establishing an economical hauling plan is to minimize transportation costs while ensuring that goods are delivered safely, reliably, and on time. By prioritizing hauling distance and utilizing efficient transportation strategies, businesses can achieve a more cost-effective and sustainable transportation plan.

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The kinetic energy as it hits the ground with mass of 2kg and velocity 15m/s is found to be 225J

The energy a body has as a consequence of motion is known as kinetic energy. A force has to be applied to an object in order to propel it. We must put in effort in order to apply a force. After the work has been finished, energy is transferred to the item, which then travels at a new, constant speed.

At the bottom when ball hit ground with velocity = 15m/s

KE = 1/2 m v^2 => 1/2 x 2 x 15^2 => 225J

Potential energy is the energy that is kept in reserve in a system or object as a result of its orientation or configuration. An object's kinetic energy is measured in relation to stationary and moving items in its immediate surroundings. Potential energy is irrespective of an object's surroundings.

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The voltage across the 4.2 F capacitor is 28.25 V.

To find the voltage across the 4.2 F capacitor, we can use the formula:

\(V = \frac{Q}{C}\)

Where V is the voltage, Q is the charge on the capacitor, and C is the capacitance.

We know:

First, sing the formula for capacitance in series, we can find the total capacitance:

\(\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{c_3} \\ \frac{1}{C_{total}} = \frac{1}{4,2} + \frac{1}{8,5} + \frac{1}{16,3}\\ \frac{1}{C_{total}} = 0,4213\\ C_{total} = 2,3728 F\)

Now we can use the formula for the total charge on the capacitors:

\(Q = C_{total} . V\\Q = 2.3728 F . (50.0 V)\\Q = 118.64 nC\)

Since the charge is the same on each capacitor, we can use the formula for voltage on a capacitor to find the voltage across the 4.2-f capacitor:

\(V_{4,2} = \frac{Q}{C_{4,2}} \\V_{4,2} = \frac{118.64 nC}{4,2F} \\V_{4,2} = 28.25 V\)

Therefore, the voltage across the 4.2 F capacitor is 28.25 V.

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To calculate the height of water that could rise on the vertical side of the dam, we can use the principles of hydrostatic pressure.

Given:

Dimension of the dam: 32 m (vertical side) and 18 m (base)

Unit weight of concrete: 23.6 kN/m³

Maximum intensity of pressure at the toe is twice the average pressure at the base

Let's break down the problem step by step:

Calculate the average pressure at the base of the dam:

Average pressure = Unit weight of concrete * Height of water on the vertical side

Calculate the maximum intensity of pressure at the toe:

Maximum intensity of pressure = 2 * Average pressure at the base

Determine the height of water that could rise on the vertical side:

Maximum intensity of pressure = Unit weight of water * Height of water on the vertical side

Since the unit weight of water is approximately 9.81 kN/m³, we have:

2 * Average pressure at the base = 9.81 * Height of water on the vertical side

Substitute the values and solve for the height of water:

2 * (23.6 * Height of water on the vertical side) = 9.81 * Height of water on the vertical side

Simplifying the equation, we have:

47.2 * Height of water on the vertical side = 9.81 * Height of water on the vertical side

Dividing both sides by the Height of water on the vertical side (which is nonzero), we get:

47.2 = 9.81

This equation is not valid, which means that the given conditions cannot be satisfied. Therefore, there is no specific height of water that can be determined to meet the condition of the maximum intensity of pressure at the toe being twice the average pressure at the base.

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Answer:

d

Explanation:

In a tensile force measurement using a strain gauge, the strain gauge is typically attached to the surface of the material experiencing the tensile force. The strain gauge is a resistive sensor that changes its electrical resistance in response to the deformation or strain of the material.

When a tensile force is applied to the material, it causes the material to deform. This deformation results in a change in the length and cross-sectional area of the material. The strain gauge, being bonded to the surface of the material, also experiences this deformation, which causes a change in its resistance.
The relationship between the change in resistance (∆R) and the tensile force (P) can be derived using the concept of strain and the gauge factor (GF) of the strain gauge. The gauge factor is a constant that represents the sensitivity of the strain gauge and is typically provided by the manufacturer.
The relationship is given by the equation:
∆R = GF * R * ε
Where:
∆R is the change in resistance of the strain gauge,
GF is the gauge factor of the strain gauge,
R is the initial resistance of the strain gauge,
ε is the strain experienced by the material.
To determine the change in resistance for a strain gauge installed on a beam being pulled axially by a 50 kN tensile force, additional information is required. Specifically, the length of the beam and the modulus of elasticity (E) of the material. With this information, the strain (ε) can be calculated using the equation
ε = δL / L
Where:
δL is the change in length of the beam,
L is the initial length of the beam.
Once the strain is determined, the change in resistance can be calculated using the derived relationship ∆R = GF * R * ε, where GF and R are given as 2 and 1200, respectively.

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Therefore, the tension in the string at its lowest point is equal to the weight added to the required centripetal force.

The rope tension is always directed towards the center of the circle. Below it means tension is UP and gravity is DOWN. At the top, downward gravity provides the necessary centripetal force. Therefore the voltage is 0. At the bottom, tension must provide the necessary centripetal force and balance gravity equal to mg downwards. Zero voltage is loose. Strings and ropes are often idealized as dimensions with length but no mass and zero cross-section.

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As the height of the hole increases, the velocity of the stream increases, results in a higher distance from the beaker. Therefore, the distance of the stream from the hole Y will be less than that from X thus, less than 5 cm is correct.

The speed of stream can be determined using the height and acceleration due to gravity g. We can use the equation for velocity using the parameters g and h.

v = √2gh

Therefore, as the height h increases, v increases.

Similarly the distance s = vt

therefore, the distance increases with v.

Here, the hole x is above the hole Y. Then the stream from X will have the greater speed and it covers greater distance (5 cm )from the beaker. Stream from Y slow compared to that in X hence covers a distance less than 5 cm. Hence, option 2 is correct.

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Imaging would not be possible at any wavelength greater than the electron wavelength. It follows that an electromagnetic wave with a shorter wavelength would have more energy.

The distance between two successive crests or troughs of a wave is known as its wavelength. It is calculated by determining the wave's direction. The distance between two identical points (adjacent crests) in adjacent cycles that make up a waveform signal's wavelength while it moves through space or along a wire.

By dividing the wave's speed by its frequency, the wavelength may be calculated. The equation above is frequently used to express this.

The field of electromagnetism, a branch of physics, is concerned with the study of the electromagnetic force, a sort of physical interaction between electrically charged particles. Electromagnetic fields, which are composed of electric and magnetic fields, convey the electromagnetic force that creates electromagnetic radiation such as light.

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Answer: A.0,0097s

Mas a unidade aí deveria ser Hertz (Hz)

Explanation:

Answer:

103 hz

Explanation:

Answer:

  a = -1,33 m / s²

Explanation:

This problem is kinematic in one dimension, let's use the equations

         v = v₀ + a t

         v₀ = v - at

          x = v₀ t + ½ a t²

we substitute the first in the second equation

         x = (v-at) t + ½ a t²

         x -v t = a t² (1 + ½)

         a = (x -vt) / t² (1.5)

we calculate

         a = (100 - 30 10) / 10² (1.5) =-200 / 150

         a = -1,33 m / s²

10.6 m/s² is the acceleration for a ball that starts from rest, rolls down a ramp, and gains a speed of 36 m/s in 3.4 s.

Any object's acceleration is defined as the change in speed that occurs when time changes. Since acceleration is a vector concept, its magnitude and direction must be specified. The acceleration can be measured in m/sec², miles/sec², etc.

Any increase in speed in the positive direction would be a positive acceleration, any increase in the negative direction would be a negative acceleration, and any decrease in speed would be a decrease in acceleration. Acceleration is the increase in speed that an object exhibits or experiments in a certain amount of time. You have positive and negative acceleration depending on the negative and positive directions, for example, when using the vertical plane falling would be the negative direction and going up would be the positive direction.

The acceleration for the ball can be found using the equation:
acceleration = (final velocity - initial velocity) / time
Since the ball starts from rest, its initial velocity is 0 m/s. Therefore:
acceleration = (36 m/s - 0 m/s) / 3.4 s
acceleration = 10.6 m/s²
To two significant figures, the acceleration of the ball is 10.6 m/s².

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Answer:

No, they do not function in the same manner.

Explanation:

I actually don't know why.

Answer: 8.6

Explanation:

Answer:

+8.6

Explanation:

acellus

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

       F = \(k' \frac{q_1 q_2 }{r^2}\)

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

         F₀ = \(k \frac{q_1 q_2 }{r^2}\)

assuming the constant k is the same

the relationship between the two forces is

        F / F₀ = 1 / r

        F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

The primary indicator of an object's position and speed is its velocity.It is the distance that an object travels in one unit of time.The displacement of the item in one unit of time is the definition of velocity.

Smax = 400 feet.

c) v = 32 ft/s

c) v = - 32 ft/s

(a)

The following is the function provided for ball height:

s = 160 t - 16 t²

Therefore, we must take the derivative with respect to t and make it equal to zero in order to get the time to reach maximum height (in-flexion point):

So, 160 - 32 t = 0, 32 t = 160 t, and 160/32 t = 5 sec.

As a result, the maximum distance is covered every 5 seconds.

Smax = (160)(5) - (16)(5)²

Smax = 800 - 400

Smax=400 feet

b)First, we determine the speed at which the ball travels 384 feet.

384 = 160 t - 16 t

16 t² - 160 t + 384 = 0

Quadratic Equation Solving:

Either:

t = 6 sec

or t = 4 seconds

Since it takes 5 seconds to reach the highest point,

t then equals 5 seconds.

t then equals 4 seconds.

Now, by taking a derivative of ods with respect to t at 4 sec, we can find velocity:

v = 160 - 32 t

v = 160 - (32)(4)

v = 32 ft/s

c,Because t = 6 s > 5 s

The second number of t = 6 sec must represent the point in the ball's downward motion when it is 384 feet above the earth.

So, at that moment, velocity will be:

v = 160 - (32)(6)

v = -32 ft/s

downward motion is a bad sign.

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To evaluate the integral (x² + y² + z²)²dv over the ball with center at the origin and radius 1, we can use spherical coordinates.

Spherical coordinates are given by (ρ, θ, φ), where ρ is the distance from the origin, θ is the azimuthal angle (measured from the positive x-axis), and φ is the polar angle (measured from the positive z-axis).

In this case, we have a ball with center at the origin and radius 1, so we know that ρ ranges from 0 to 1, θ ranges from 0 to 2π, and φ ranges from 0 to π.

To compute the integral using spherical coordinates, we first need to express the integrand in terms of ρ, θ, and φ. We have:

(x² + y² + z²)² = ρ⁴

And the differential volume element in spherical coordinates is given by:

dv = ρ² sin(φ) dρ dθ dφ

Putting it all together, we have:

∫∫∫ (x² + y² + z²)² dv = ∫φ=0²π ∫θ=0²2π ∫ρ=0¹ ρ⁴ ρ² sin(φ) dρ dθ dφ

Simplifying the integral, we get:

∫φ=0²π ∫θ=0²2π ∫ρ=0¹ ρ⁶ sin(φ) dρ dθ dφ

Integrating with respect to ρ first, we get:

∫φ=0²π ∫θ=0²2π [(1/7)ρ⁷ sin(φ)]_ρ=0¹ dθ dφ

Simplifying further, we have:

∫φ=0²π ∫θ=0²2π (1/7) sin(φ) dθ dφ

Integrating with respect to θ, we get:

∫φ=0²π [(1/7)θ sin(φ)]_θ=0²2π dφ

This evaluates to 0, so the integral is 0. Therefore,the value of ∫(x² + y²+ z²)² dv over the ball with center at the origin and radius 1 is 0.

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Answer:

Explanation:

A cold region of dust that scatters the light of nearby stars produces a nebula that appears blue in color, such as the one encompassing the Pleiades cluster.

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Answer:

Answer to An object undergoes constant acceleration from rest and travels 5m in the first second. What is the distance in the next second? by Brian Alan Whatcott https://www.quora.com/An-object-undergoes-constant-acceleration-from-rest-and-travels-5m-in-the-first-second-What-is-the-distance-in-the-next-second/answer/Brian-Alan-Whatcott?ch=15&oid=197956546&share=8d4dbec5&srid=uFw3N6&target_type=answer

Answer:

Yes

Explanation:

\(v = \frac{ds}{dt} \\ where \: we \: need \: to \: know \\ \: change \: in \: displacement \\ \: and \: the \: time \: taken\)

if you know the time it took an object to travel between two points and the position of the object at the points, then we can determine the object's instantaneous velocity by using the differential rate of the displacement function with respect to the time.

Instantaneous velocity =  \(\frac{dS}{dt}\)

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

velocity= displacement  / time taken

for instantaneous velocity =  \(\frac{dS}{dt}\)

Thus, If you know how long it took an item to go between two places and where it was when it got there, you can use the differential rate of the displacement function with respect to time to calculate the object's instantaneous velocity.

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\( = \sf \frac{1}{2} m {v}^{2} \)

\( \sf = \frac{2.4J}{9.6J} \\ \sf= \frac{24}{96} = \frac{1}{4} \\ \sf = 1 : 4\)

Answer:

The kinetic energies of the bullets are 2.4 J and 9.6 J.

The bullet having greater velocity has more kinetic energy.

The ratio of their kinetic energies is 1 : 4.

Hope you could get an idea from here

Doubt clarification - use comment section.

The kinetic energy of the two bullets are 2.4 J and 9.6 J respectively.

The ratio of the kinetic energy of the bullets is 1:4.

The kinetic energy of an object is the energy possessed by the object due to its motion.

The kinetic energy of the two bullets is calculated as follows;

\(K.E_1 = \frac{1}{2} \times 0.003 \times 40^2 = 2.4 \ J\\\\K.E_2 = \frac{1}{2} \times 0.003 \times 80^2 = 9.6 \ J\)

Ratio of the kinetic energy of the bullets is calculated as follows;

\(K.E_1 : K.E_2 = 2.4: 9.6 \ = \ 1: 4\)

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a. Therefore, the work required to accelerate an electron from rest to 1.60c is 813 keV. b. Therefore, the final speed of the electron is approximately 0.999999784 times the speed of light (c).

(a) The kinetic energy of a particle with mass m and velocity v is given by:

KE = 1/2 \(mv^2\)

An electron has a rest mass of 9.11 x 10^-31 kg. To accelerate an electron from rest to a velocity of 1.60 times the speed of light (c), we can use the relativistic kinetic energy formula:

KE = (γ - 1)\(mc^2\)

where γ is the Lorentz factor given by:

γ = 1 / \(\sqrt{(1 - (v/c)^2)}\)

At a velocity of 1.60c, the Lorentz factor is:

γ = 1 / \(\sqrt{(1 - (1.60c/c)^2)}\) = 2.29

Substituting the values into the relativistic kinetic energy formula, we get:

KE = \((2.29 - 1) x (9.11 x 10^{-31} kg) x (3.00 x 10^{8} m/s)^2\)

= \(1.30 *10^{-13} J\)

KE = (\(1.30 x 10^{-13} J) / (1.60 x 10^{-19} J/eV) = 813 keV\)

(to three significant figures)

(b) If we do that much work on an electron, its final speed can be calculated by equating the work done to the change in kinetic energy:

Work done = ΔKE = KE_final - KE_initial

where the initial kinetic energy is zero, since the electron is initially at rest. Therefore:

Work done = KE_final

Solving for the final velocity using the relativistic kinetic energy formula and the Lorentz factor:

KE_final = (γ - 1)\(mc^2\)

KE_final = (813 keV) * \((1.60 x 10^{-16} J/eV) = 1.30 x 10^{-7} J\)

γ = 1 + KE_final / (mc^2)

γ = \(1 + (1.30 x 10^{-7} J) / ((9.11 x 10^{-31} kg) * (3.00 x 10^8 m/s)^2)\)

= 1.000000432

v/c = \(\sqrt{(1 - 1 / gamma^2) }\)= 0.999999784

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Because the current flowing through both bulbs in a series connection is equal, the power P = I2R states that the 60W bulb will expend more power and so be brighter than the 40W bulb (100W bulb).

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