according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sledgehammer? a - 1000 n b 1000 n c 0 n d 500 n

Answer:

Explanation:

        16093.4

The complete journal entry have been shown in the writing that is below here.

Dear Journal,

I am a colonial settler who has recently arrived in the New World to start a new life in one of the three regions. After much consideration, I have chosen to settle in the Southern colonies. The warm climate and fertile soil are perfect for growing crops such as tobacco, cotton, and indigo. I also appreciate the coastal location, which provides easy access to trade and transportation.

However, life as a colonial settler is not without its struggles. For one, the threat of disease and illness is always present, and the lack of medical resources can be concerning. Additionally, I am constantly wary of attacks from Native American tribes who view us as invaders. Nevertheless, I am determined to make the best of this opportunity and establish a successful life in the New World.

On a more positive note, I have found a number of economic opportunities in the Southern colonies. The growth of the tobacco industry has been particularly promising, and I have already begun planting crops in hopes of a bountiful harvest. I have also established relationships with other settlers and traders, and I am confident that my business ventures will continue to expand.

Overall, I am excited for this new chapter of my life and grateful for the opportunities that the Southern colonies have presented. While there will undoubtedly be challenges along the way, I am determined to make a successful life for myself and my family in this promising new land.

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Isaac Newton's Law on Universal Gravitation provided the first formal definition of the gravitational constant. One of nature's fundamental constants, whose value is (6.6743 0.00015) x 10-11 m3 kg-1 s-2.

If there is a difference in mass between any two things or particles, gravity will tend to pull them in that direction.

The reason it is known as Newton's Law on Gravitation is that it applies to all mass-bearing things, such as the sun, moon, earth, and an apple, and these bodies will all be subject to its effects.

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So, the current when the capacitor has acquired 1/4 of its maximum charge is approximately 0.171 A.

To find the current when the capacitor has acquired 1/4 of its maximum charge, we can use the equation for the current in an RC circuit, which is:

I(t) = V/R * e^(-t/RC)

Here,
I(t) is the current at time t,
V is the battery voltage (12.0 V),
R is the resistor value (14.0 Ω),
C is the capacitor value (1.30 µF),
t is the time when the capacitor has acquired 1/4 of its maximum charge, and
e is Euler's number (approximately 2.718).

First, we need to find the time t when the capacitor has 1/4 of its maximum charge. We can use the equation for the voltage across a charging capacitor:

V(t) = V * (1 - e^(-t/RC))

We know that at 1/4 of its maximum charge, the voltage across the capacitor will be 1/4 of the battery voltage:

V(t) = 0.25 * V = 0.25 * 12 = 3.0 V

Now, we can solve for t:

3.0 V = 12 V * (1 - e^(-t/(14 Ω * 1.30 µF)))

0.25 = 1 - e^(-t/(14 Ω * 1.30 µF))

0.75 = e^(-t/(14 Ω * 1.30 µF))

Now, take the natural logarithm of both sides:

ln(0.75) = -t/(14 Ω * 1.30 µF)

Now, solve for t:

t ≈ 3.14 * 10^(-6) s

Now, we can plug the value of t back into the current equation:

I(t) = 12 V / 14 Ω * e^(-3.14 * 10^(-6) s / (14 Ω * 1.30 µF))

I(t) ≈ 0.857 A * e^(-1.614)

I(t) ≈ 0.857 A * 0.199

I(t) ≈ 0.171 A

So, the current when the capacitor has acquired 1/4 of its maximum charge is approximately 0.171 A.

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The moon's small size is the single factor that resulted in the moon today being so very much different than present-day earth.

The friction created through the stretching and squeezing of the Moon brought on the Moon's price of rotation to sluggish down until its rotational length became the same as its orbital length. At this factor there is no extra tidal friction, the charge of rotation stabilizes and the Moon is locked in synchronous rotation with Earth.

The Earth increases tidal bulges at the moon. as the moon rotated through these bulges, internal friction slowed the moon's rotation until it executed tidal coupling.

Moon shaped elsewhere within the solar device and became ultimately captured at some point of a close encounter with Earth. principle fails due to the fact that seizing is definitely impossible for an item as huge because of the moon.

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Answer:

The force to get the plane moving, and to balance the friction so it does not stop, is provided by the propeller. However, the wheels provide the acceleration of the car.

Explanation:

The voltage drop across the inductor (L) is 29.53 V.

In a series circuit with resistance R = 20 ohms, inductance L = 20 mH, and an AC supply of 60 V with frequency f = 100 Hz, the voltage drop across the inductor (V_L) can be calculated using the formula:

V_L = 2 * π * f * L * I

First, we need to find the impedance (Z) of the circuit, which is given by the formula:

Z = √(R² + (2 * π * f * L)²)

Plugging in the given values:

Z = √(20² + (2 * π * 100 * 0.02)²) ≈ 25.49 ohms

Next, we need to find the current (I) in the circuit, using Ohm's law:

I = V / Z

I = 60 V / 25.49 ohms ≈ 2.35 A

Now we can find the voltage drop across the inductor (V_L):

V_L = 2 * π * 100 Hz * 0.02 H * 2.35 A ≈ 29.53 V

Therefore, the voltage drop is approximately 29.53 V.

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Answer:

So 55 Newtons are needed.

Answer:

80 N

Explanation:

mass (m) = 20kg

acceleration (a) = 4m/s^2

Force (F) = ?

.°. F = ma

= 20 × 4 = 80

.°. F = 80 N

Thus, The Force is needed to accelerate a 20 kg mass at a rate of 4 m/s^2 is 80 N

-TheUnknownScientist

Answer:

D. 1.35

Explanation:

Answer:

D. 1.35

Explanation:

0.27/0.2

After three half-lives of a radioactive isotope, you would expect to have 12.5 grams of the daughter isotope.

The concept of half-life refers to the time it takes for half of the radioactive substance to decay. During each half-life, the amount of the original radioactive isotope decreases by half, while the amount of the daughter isotope increases.

Since we start with 100 grams of the radioactive isotope, after one half-life, we would have 50 grams of the original isotope remaining, and 50 grams would have decayed into the daughter isotope.

After the second half-life, half of the remaining 50 grams would decay, leaving us with 25 grams of the original isotope and 75 grams of the daughter isotope.

After the third half-life, half of the remaining 25 grams would decay, resulting in 12.5 grams of the original isotope and 87.5 grams of the daughter isotope.

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The minimum temperature of the flat plate that is mounted on a coordinate plane is -36 Fahrenheit, occurs at (4,-2) in the x,y plane

Given :

The equation to solve is -

2x² + y²-16x + 4y

let the function be denoted by f(x)

f(x) = 2x² + y²-16x + 4y

Step 1: Taking partial differentiation with respect to x

df /dx = 4x -16

putting df /dx=0

we get:

x = 4

Step 2: Taking partial differentiation with respect to y

df /dy = 2y + 4

putting df /dy=0

we get:

y = -2

so the calculated points are (4,-2)

At value (4,-2)

f(x) = 2(4)² + (-2)²-16(4) + 4(-2)

f(x) = -36

Hence, the minimum temperature is -36 Fahrenheit occurs at (4,-2)

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Force pairs that must be equal because they are action/reaction pairs. According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. This means that action and reaction forces are always equal in magnitude but opposite in direction.

Some examples of action/reaction force pairs include:
1. When you push a book across a table (action), the book pushes back with an equal force (reaction).
2. When a person jumps off a diving board (action), the diving board exerts an equal and opposite force on the person (reaction).
3. A person walking on the ground pushes against the ground (action), and the ground pushes back with an equal force (reaction).

In all these cases, the action/reaction force pairs are equal and opposite, illustrating Newton's Third Law of Motion.

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Answer: It has the skill to nest

sorry if I'm wrong

Answer:

B: A colorful beak

Explanation:

i hope this helped!

Answer:

C. Plant A orbits its star faster than Plant B

Explanation:

Did it on study island

The reservoir pressure is depleted to 3500 psi, the expected oil rate would be approximately 4759.15 bbl/day.

To calculate the oil rate of the well, we can use Darcy's law for radial flow in porous media. The formula is as follows:

Q = (2πkh) / (μ ln(re/rw))

Where:

Q is the oil rate (bbl/day),

k is the permeability (mD),

h is the thickness of the reservoir (ft),

μ is the oil viscosity (centipoise),

re is the drainage radius (ft), and

rw is the wellbore radius (ft).

a. Given:

Reservoir pressure (P1) = 4000 psi,

Bottom-hole flowing pressure (P2) = 3000 psi,

Thickness of the reservoir (h) = 25 ft,

Permeability (k) = 500 mD,

Viscosity (μ) = 1 centipoise,

Drainage radius (re) = 2000 ft,

Wellbore radius (rw) = 4 inches = 1/3 ft.

Substituting these values into the equation, we can calculate the oil rate (Q1):

Q1 = (2π * 500 * 25) / (1 * ln(2000/(1/3)))

  ≈ 5241.81 bbl/day

Therefore, the well is expected to produce at a rate of approximately 5241.81 bbl/day.

b. To calculate the expected oil rate (Q2) when the reservoir pressure is depleted to 3500 psi, we can use the same formula with the new pressure value:

Reservoir pressure (P1) = 3500 psi.

Using the equation:

Q2 = (2π * 500 * 25) / (1 * ln(2000/(1/3)))

  ≈ 4759.15 bbl/day

Therefore, if the reservoir pressure is depleted to 3500 psi, the expected oil rate would be approximately 4759.15 bbl/day.

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Answer:

D

Explanation:

Answer:

ΔV=Vi + Vf

           2

ΔV= 11m/s + 19m/s

                 2

ΔV= 15m/s

Explanation:

The work done by gravity when lifting an 850 kg elevator at a constant speed of 1.0 m/s through a height of 23.5 m is approximately -200 kJ.

The work done by gravity is equal to the weight of the elevator times the distance through which it moves. The weight of the elevator can be calculated as mass multiplied by gravity. Here, the mass of the elevator is 850 kg and the gravitational force is 9.8 m/s². Therefore, the weight of the elevator is given as W = m × g = 850 kg × 9.8 m/s² = 8330 N. The distance through which the elevator moves is 23.5 m.

Therefore, the work done by gravity is given as W = F × d = 8330 N × 23.5 m = 195505 J. To convert the unit of work to kilojoules, we divide the answer by 1000. Therefore, the work done by gravity is -195.5 kJ, which can be approximated as -200 kJ. The negative sign indicates that the work done is against gravity.

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Answer:

2m/s

Explanation:

Given parameters:

Mass of truck  = 9000kg

Kinetic energy = 18000J

Unknown:

Speed  = ?

Solution:

Kinetic energy is the energy due to the motion of a body;

  K.E  = \(\frac{1}{2}\) mv²  

 So;

 m is the mass

  v is the speed

   2 KE = mv²

  2 x 18000 = 9000 x v²

     v²  = 4

     v = 2m/s

The force that causes the water to exit the rocket is equivalent but opposite in direction to the force that causes the rocket to launch.

Force can cause a still body to move. It has the ability to either stop or slow a moving body. It has the ability to increase the speed of a moving body. It can also affect the shape and size of a moving body as well as its direction. A force exerted on an object causes it to change shape or size, begin or stop moving, accelerate or decelerate. When two things contact, they exert a force on one other; these exerted forces are equal in size but opposite in direction. The strong force is thought to be nature's most powerful force. The electromagnetic, weak, and gravitational forces follow in declining sequence.

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ANSWER:

1st option: left

STEP-BY-STEP EXPLANATION:

Direction is the location of something in relation to something else. Direction can be described in relative terms, such as up, down, in, out, left, right, forward, backward, or sideways. L

A motion map can look like this:

Which means that by saying backwards, on the map it has a movement to the left

So the correct answer is the 1st option: left

Answer:

V = 2 π R / T        speed V where T is period

T = 2 π R / V     = 2 π * .2 m / 1.5E5 m/s = 8.38E-6 sec

Period = 8.36 * 10-6 sec

The rabbit is running at approximately 1.77 m/s.

The kinetic energy of an object can be calculated using the formula:

KE = (1/2) * m * \(v^{2}\)

Where:

KE is the kinetic energy,

m is the mass of the object, and

v is the velocity of the object.

In this case, the kinetic energy of the rabbit and the Irish Setter is the same. Let's denote the velocity of the rabbit as vr and the velocity of the Irish Setter as vs.

We are given:

Mass of the rabbit (mr) = 5.0 kg

Mass of the Irish Setter (ms) = 12 kg

Velocity of the Irish Setter (vs) = 1.3 m/s

Since the kinetic energy is the same for both, we can set up the equation:

\((1/2) * m_r * v_r^2 = (1/2) * m_s * v_s^2\)

Plugging in the given values:

\((1/2) * 5.0 kg * v_r^2 = (1/2) * 12 kg * (1.3 m/s)^2\)

Simplifying the equation:

2.5 * \(vr^2\) = 7.8

Dividing both sides by 2.5:

\(vr^2\)  = 7.8 / 2.5

\(vr^2\)  = 3.12

Taking the square root of both sides:

vr = √3.12

vr ≈ 1.77 m/s

Therefore, the rabbit is running at approximately 1.77 m/s.

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Answer:

its when a liquid, prolly water, turns into a vapor !!

Explanation:

and nice pic uwu

A liquid turning into a gas is evaporation. It is how water gets from the surface of the Earth to the atmosphere.

Latent heat is a form of energy held in the evaporated water when it evaporates and cools.

Evaporation plays a significant role in the energy exchange that results in atmospheric motion, affecting weather and climate in the Earth-atmosphere system.

The particles with the highest kinetic energy are the first to evaporate from a liquid.

Most of the air's moisture evaporates from rivers, lakes, seas, and oceans. Water at the surface of the Earth evaporates into water vapor, which rises into the sky and forms clouds, which eventually release water back onto Earth as precipitation.

Refer to the photo taken.

In order to determine the number of particles of methane, use the following expression:

number of particles = (mass /molar mass ) x Avogadro's number

in this case, you have:

molar mass = 16.03 grams/mole

mass = 120 grams

Avogadro's number = 6.02*10²³ particles/mol

replace the previos values of the parameters into the formula for the number of particles:

number of particles=(120 grams/ 16.03 grams/ mol)x(6.02*10²³particles/mol)

= (7.46 mol) x (6.02*10²³ particles/mol)

= 4.50*10²⁴ particles

Hence, the number of particles of methane, in 120 grams, is 4.50*10²⁴

The four tires of an automobile are inflated to an absolute pressure of 2.0 x 10⁵ Pa. A total of 0.024 m2 of each tire is in touch with the ground. Then the weight (Fg) of the automobile is 19.2 × 10³ N.

The definition of pressure is "force per unit area." P = F/A, for example, yields the force on a unit area. Its Pascal (Pa) SI unit is equivalent to N/m2. is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].  Mass times the gravitational acceleration equals weight.

Pressure is P = F/A

Force on each tire,

F' = PA = 2.0 x 10⁵ Pa × 0.024 m²

F' = 4.8 × 10³ N

For on for tires,

F = F'×4

F =  4.8 × 10³ N × 4

F =  4.8 × 10³ N × 4

F = 19.2 × 10³ N

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Jupiter is about 465 million miles away from the Sun. Jupiter lies about 5 Astronomical Units (A.U.) from the Sun.

You asked about the distance between Jupiter and the Sun. An A.U. is a unit of measurement that represents the average distance between the Earth and the Sun, which is approximately 93 million miles or 150 million kilometers. So, at its distance, Jupiter is about 5 times farther from the Sun than Earth is.

To calculate the actual distance between Jupiter and the Sun, you can simply multiply the number of A.U. by the average distance between the Earth and the Sun:

5 A.U. x 93 million miles (or 150 million kilometers) = 465 million miles (or 750 million kilometers)

So, Jupiter lies approximately 465 million miles (or 750 million kilometers) away from the Sun.

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For RC circuit: the value of the time constant τ is 12 μs.

For RL circuit: the value of the time constant τ is 0.115 ms.

It is proved that, τ = t1/2/ln(2) = 1.443 t1/2. This shows that the time constant is directly proportional to the square root of the half-life of the voltage decay.

For the RC circuit, the time constant τ is given by:

τ = RC = (10 nF)(1,200 Ω) = 12 μs

For the RL circuit, the time constant τ is given by:

τ = L/RL = (15 mH)/(130 Ω) = 0.115 ms

Now, for the RC circuit, the voltage across the capacitor can be given by:

vC(t) = Vmax(1 - e^(-t/τ))

where Vmax is the maximum voltage of the square wave, τ is the time constant, and t is the time. The voltage across the resistor is equal to vR(t) = vC(t), since the capacitor and resistor are in series.

For the RL circuit, the voltage across the resistor can be given by:

vR(t) = Vmax(1 - e^(-t/τ))

where Vmax is the maximum voltage of the square wave, τ is the time constant, and t is the time.

To show that τ = t1/2/ln(2), we start with the equation for voltage across the capacitor in the RC circuit:

vC(t) = Vmax(1 - e^(-t/τ))

Let t = τ, then we have:

vC(τ) = Vmax(1 - e^(-1))

vC(τ) = 0.632 Vmax

Now, let t = t1/2, then we have:

vC(t1/2) = Vmax(1 - e^(-t1/2/τ))

vC(t1/2) = Vmax(1 - e^(-1/2))

vC(t1/2) = 0.393 Vmax

The voltage across the resistor at t = τ and t = t1/2 can be found using the same equations as above.

Now, the half-life t1/2 is defined as the time it takes for the voltage to decay to half of its initial value. Thus, we have:

t1/2/τ = ln(2)

Solving for τ, we get:

τ = t1/2/ln(2) = 1.443 t1/2

This shows that the time constant is directly proportional to the square root of the half-life of the voltage decay.

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