According to solubility rules, which compound should dissolve in water? Select one: ОКРО, 0 MgCO3 O Caso O AgBI

The normal force is less than the 10 N

Since we are given a box weight that is  10 N  tilted at 45⁰, so the formula we refer  from the figure to for calculating the normal force is:

N=mg⋅cos θ , where mg is the weight of the  box and θ is the angle at which the box is shifted.

The flatter the incline to be,  the normal force becomes greater. The littler an angle gets to be making the greater the esteem of cosine gets to be, and along these lines the greater the normal force becomes.

So, we get that the normal force will be

= 10 cos 45 (Since the value of mg  is 10 N and θ = 45⁰)

= 7.07 N

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The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

\(F= \frac{mv}{t}\)

The force applied to an object increases with increases in the velocity of the object.

In the given diagram, the resultant velocity of the puck is calculated as follows;

Figure a:

\(\Delta v = v_f -v_i\\\\\Delta v = 5 - 6 = - 1 \ m/s\)

Figure b:

\(v = \sqrt{4^2 + 3^2} \\\\v = 5 \ m/s\)

Figure c:

\(\Delta v = 4 - (-2)\\\\\Delta v = 6 \ m/s\)

Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.

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A. the change in volume of the cube is approximately 0.120601 cm^3. B. the average rate of change of volume of the cube with respect to an edge length is approximately 12.0601 cm^3/cm. C. the equation of the line that passes through the point (1, 5) and is parallel to the tangent line to f(x) = 1/x at x = 3 is y = (-1/9)x + 14/9.

(a) To find the change in volume of the cube as x increases from 2.00 to 2.01 centimeters, we need to calculate the difference in volume between these two values.

The volume of a cube is given by V = x^3, where x is the edge length.

For x = 2.00 cm, the volume V1 = (2.00 cm)^3 = 8.00 cm^3.

For x = 2.01 cm, the volume V2 = (2.01 cm)^3 = 8.120601 cm^3.

The change in volume is ΔV = V2 - V1 = 8.120601 cm^3 - 8.00 cm^3 ≈ 0.120601 cm^3.

Therefore, the change in volume of the cube is approximately 0.120601 cm^3.

(b) The average rate of change of volume of the cube with respect to an edge length as x increases from 2.00 to 2.01 centimeters can be calculated by dividing the change in volume by the change in edge length.

ΔV = 0.120601 cm^3 (from part a)

Δx = 2.01 cm - 2.00 cm = 0.01 cm

The average rate of change of volume is ΔV/Δx = 0.120601 cm^3 / 0.01 cm ≈ 12.0601 cm^3/cm.

Therefore, the average rate of change of volume of the cube with respect to an edge length is approximately 12.0601 cm^3/cm.

(c) The instantaneous rate of change of volume of the cube with respect to an edge length at the instant when x = 2 centimeters can be found by taking the derivative of the volume function V = x^3 with respect to x and evaluating it at x = 2.

dV/dx = 3x^2

At x = 2 cm, the instantaneous rate of change of volume is dV/dx evaluated at x = 2:

dV/dx = 3(2 cm)^2 = 12 cm^2.

Therefore, the instantaneous rate of change of volume of the cube with respect to an edge length at x = 2 centimeters is 12 cm^2.

To find the equation of the line that passes through the point (1, 5) and is parallel to the tangent line to f(x) = 1/x at x = 3, we need to determine the slope of the tangent line.

The derivative of f(x) = 1/x is given by f'(x) = -1/x^2.

At x = 3, the slope of the tangent line is f'(3) = -1/(3^2) = -1/9.

Since the line we want to find is parallel to the tangent line, it will have the same slope. So the slope of the line is -1/9.

Using the point-slope form of a linear equation, we can write the equation of the line as:

y - y1 = m(x - x1),

where (x1, y1) is the given point (1, 5) and m is the slope.

Substituting the values, we have:

y - 5 = (-1/9)(x - 1).

Expanding and rearranging the equation, we get:

y = (-1/9)x + 14/9.

Therefore, the equation of the line that passes through the point (1, 5) and is parallel to the tangent line to f(x) = 1/x at x = 3 is y = (-1/9)x + 14/9.

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Answer:

Hey buddy, here is your answer.Hope it helps you.

Explanation:

A catapult is a launching device that allows us to experimentally observe projectile motion. Once the ball is launched, the only forces acting are gravity and air resistance.

Explanation:

the speed of sound depends on the particles of the medium of the sound wave is moving through because the particles in the solid and tightly packed together South Wales weekly transfers energy from particle to particle in a solid

Answer:

1.27551m

Explanation:

This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.

Thus, we get:

\(KE_{initial} + PE_{initial} = KE_{final} + PE_{final}\)

We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using \(\frac{1}{2}mv^2\)

One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.

\(KE_{initial} = PE_{final}\)

Plugging in:

\(\frac{1}{2}*30*5^2 = 30*9.8*h\)

Solving for h, we get 1.27551m

Answer:

the answer for this is Letter B

When a person sings in a shower and causes the shower to resonate with a fundamental frequency of 73 Hz, this is an example of a standing wave, also known as a resonance.

The fundamental frequency of a standing wave is determined by the length of the resonant cavity, which in this case is the shower. The fundamental frequency is related to the length of the cavity by the equation:

f = v / 2L

where f is the frequency, v is the velocity of sound in the medium (in this case, air), and L is the length of the cavity. Given that the shower has a length of 2.40 meters and the fundamental frequency is 73 Hz, we can use the equation above to calculate the velocity of sound in air.

73 = v / (2 * 2.40)

Solving for v, we get:

= v

= (73 * 2 * 2.40)

= 350.4 m/s

The speed of sound in air is approximately 343 m/s at 20 °C at sea level. The velocity of sound in air can change with temperature, humidity and pressure. Given that the velocity of sound in air is around 343 m/s, the frequency of 73 Hz is a close match to the fundamental frequency of the shower with 2.40 meters high, It is important to note that the fundamental frequency is not the only frequency that could resonate in the shower, other overtones and harmonics might also resonate.

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Question- Someone is singing in a shower that measures 2.40 meters from floor to ceiling, and notices their voice causes the shower to resonate with a fundamental frequency of 73 Hz. Here, this situation is an example of? justify. The given situation is an example of which physics phenomenon and justify the given example with some details.

Answer:

19.98Joules

Explanation:

Energy possessed by the body is the kinetic energy

Kinetic Energy = 1/2mv²

m is the mass

v is the velocity

For the 4kg moving at 6m/s

kE = 1/2 * 4 * 6^2

KE = 1/2 * 4 * 36

KE = 72Joules

For the 4kg moving at 5.1m/s

kE = 1/2 * 4 * 5.1^2

KE = 1/2 * 4 *26.01

KE = 52.02Joules

Amount of Energy lost = 72 - 52.02

Amount of Energy lost = 19.98Joules

Hence the amount of Energy lost is 19.98Joules

Answer:

4/3 times its original value

Explanation:

hope this helped

When ship A increases its speed by 0.10c relative to Earth, the relative speed between ship A and ship B depends on the initial relative speed between the two ships and the direction in which ship A increases its speed.

If ship A and ship B are initially at rest relative to each other, the relative speed between them will increase by exactly 0.10c when ship A increases its speed by 0.10c.

If ship A and ship B are initially moving in the same direction, the relative speed between them will increase by less than 0.10c when ship A increases its speed by 0.10c.

If ship A and ship B are initially moving in opposite directions, the relative speed between them will increase by more than 0.10c when ship A increases its speed by 0.10c.

In summary, the change in relative speed between ship A and ship B can be equal to, less than, or greater than 0.10c depending on their initial relative speeds and directions.

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Electrostatic force the force between static charges.Net force is 12056.9 q N in the positive y-direction, found by vector summing forces from charges q1, q2, and q3.

To find the net electrostatic power applied on the point charge, we want to compute the power applied by every one of different charges and afterward find the vector amount of these powers.To start with, we can compute the power applied on the point charge by q1. We can utilize Coulomb's regulation to track down the extent of the power:

F1 = k * q1 * q/\(d^2\)

Where k is the Coulomb steady (\(9 x 10^9 N m^2/C^2\)). Connecting the qualities, we get:

F1 = \(9 x 10^9 * 12 x 10^-6 * q/(0.016)^2\)

F1 = 2535.94 q N

The heading of the power applied by q1 is towards the point charge, since q1 is positive.Then, we can ascertain the power applied on the point charge by q2. Since q2 is negative, the power will be the other way of the vector joining the two charges. Utilizing Coulomb's regulation once more, we get:

F2 = k * q2 * q/\(d^2\)

F2 = \(9 x 10^9 * (- 2.0) * 12 x 10^-6 * q/(0.016)^2\)

F2 = - 5071.88 q N

The extent of the power is more noteworthy than the power applied by q1, yet the heading is inverse.At long last, we can compute the power applied on the point charge by q3. Utilizing Coulomb's regulation once more, we get:

F3 = k * q3 * q/\(d^2\)

F3 =\(9 x 10^9 * 30 * 12 x 10^-6 * q/(0.016)^2\)

F3 = 11462.5 q N

The heading of the power applied by q3 is towards the point charge, since q3 is positive.To find the net power, we really want to add these three vectors. Since the heading of the power applied by q2 is inverse to that of q1 and q3, we want to take away it from the amount of the other two vectors. Composing the vectors in part structure and adding them, we get:

Fnet = (2535.94 - 5071.88) I + (0) j + (11462.5) k

Fnet = - 2535.94 I + 11462.5 k

The greatness of the net power is:

|Fnet| = \(sqrt((- 2535.94)^2 + (0)^2 + (11462.5)^2) = 12056.9 q N\)

The heading of the net power is towards the positive y-pivot, since there is no part of the power in the x-bearing. Accordingly, the net electrostatic power applied on the point charge is 12056.9 q N in the positive y-course.

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This question involves the concepts of the parallel combination of springs, Hooke's Law and equivalent spring constant.

Each spring will stretch by "25 cm".

For static condition of spring:

Weight of Brick = Extension Force

using Hooke's Law:

\(mg = kx\)

Consider the following data for a single spring:

K₁ = spring constant of single spring = K

x₁ = stretch in single spring = 50 cm

m = mass of brick

g = acceleration due to gravity

Therefore,

\(mg = k_1x_1\\mg = K(50\ cm) ---- eqn(1)\)

Now, for the second scenario, where two identical copies of the single spring are placed side by side in a parallel combination:

K₂ = Equivalent spring constant of the parallel combination of springs

K₂ = K + K = 2K

x₂ = stretch in each spring in the parallel combination of springs = ?

m = mass of brick

g = acceleration due to gravity

Therefore,

\(mg = k_1x_1\\mg = 2K(x_2) ---- eqn(2)\)

dividing eqn (1) and eqn(2), we get:

\(1 = \frac{50\ cm}{2x_2}\\\\\)

x₂ = 25 cm

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The attached picture illustrates Hooke's Law.

According to the question the magnitude of the resultant force is approximately 22.47 lb.

Magnitude is a measure of the size or intensity of something. It is most commonly used to describe the size of earthquakes, but can also be used to describe the size of other phenomena such as storms, winds, and floods. Magnitude can also refer to the size of a star or other celestial body. Magnitude is expressed as a number on a logarithmic scale, with larger numbers representing larger magnitudes.

We can use the Law of Cosines to calculate the magnitude of the resultant force. The Law of Cosines states that for a triangle with side lengths a, b, and c and angle C opposite side c, the following formula holds:

c2 = a2 + b2 - 2abcos(C)

In this case, a is 18 lb, b is 12 lb, and C is the angle between the two forces, 25 degrees. We can substitute these values into the formula and solve for c, the magnitude of the resultant force:

c2 = (18 lb)2 + (12 lb)2 - 2(18 lb)(12 lb)cos(25 degrees)

c2 = 324 + 144 - 432cos(25 degrees)

c2 = 324 + 144 - 216cos(25 degrees)

c2 = 468 - 216cos(25 degrees)

Now we can solve for c:

c = √(468 - 216cos(25 degrees))

c ≈ 22.47 lb

Therefore, the magnitude of the resultant force is approximately 22.47 lb.

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Explanation:

Distance = rate × time

1 m = (2.99792×10⁸ m/s) t

t = 3.33565×10⁻⁹ s

Light is the fastest thing in the universe. The speed of light is 2.99792 x 10⁸ m/s . The time that light takes to cover a distance of 1 meter is just 3.39  x 10⁻⁹seconds.

Speed is a physical quantity that means the distance in meter covered by a moving body in one second.  The speed of light is  2.99792 x 10⁸ m/s. Light from sun only takes 8 min to travel to the earth surface.

The speed of a moving particle or wave is mathematically the ratio of distance and time. Thus time of travel can be found out from the distance and speed.

It is given that the distance travelled by light is 1 m and its speed is 2.99792 x 10⁸ m/s. Thus the time taken to  travel is calculated as follows:

Time = distance/speed

         = 1 m/ (2.99792 x 10⁸ m/s)

         = 3.39  x 10⁻⁹s

Therefore, the time that light takes to cover a distance of 1 meter is just 3.39  x 10⁻⁹seconds.

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Answer:

125.5J

Explanation:

Given parameters:

Mass of the bowling ball  = 6.1kg

Height of lifting  = 2.1m

Unknown:

Increase in the ball energy  = ?

Solution:

The ball has changed position by moving it from one point to another. So, it has acquired more potential energy.

 Potential energy  = mgh

     m is the mass

     g is the gravity  

     h is the height

Now insert the given parameters and solve;

       Potential energy  = 6.1 x 9.8 x 2.1  = 125.5J

Average Speed ( Velocity ) = [ Distance traveled ] ÷ [ time of the traveled distance in seconds ]

_______________________________

AS = 600 ÷ 10

AS = 60 m/s

______________________________

2 minutes = 2 × 60 = 120 seconds

AS = 1000 ÷ 120

AS = 100 ÷ 12

AS = 25 ÷ 3

AS = 25/3 = 8.33 m/s ( approximately )

When Galileo observed Venus, he saw something that didn't fit with the Ptolemaic model for the Solar System and it was option a. Venus shows phases, instead of always looking nearly full at times.

In October 1610, Galileo made his first telescopic views of Venus. He was eager to find out if Venus has phases like the Moon did. Before the telescope was created, Venus and the other planets appeared to be blazing stars. Galileo was able to determine that Venus circled the Sun, not the Earth, by observing the phases of the planet.

The centuries-old notion that the sun and planets rotated around Earth were disproved by Galileo Galilei's observation that Venus appeared in our sky in phases that were comparable to those of the Earth's Moon. This proved that Venus orbited the sun.

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To find the time it takes to polish the entire lens, we first need to know the total surface area of the lens. If we assume that the lens is spherical and has a diameter of 1.24 x 10^2 mm, then its surface area can be calculated using the formula for the surface area of a sphere:

A = 4πr^2, where r is the radius of the sphere

The radius of the sphere can be found by dividing the diameter by 2:

r = d/2

Plugging in the values for d and r, we get:

A = 4π(1.24 x 10^2 mm / 2)^2

A = 4π(62^2) mm^2

A = 4π(3844) mm^2

Now that we know the surface area of the lens, we can divide it by the time it takes the technician to polish 1.24 x 10^2 mm^2 to find the total time:

T = (4π * 3844 mm^2) / (54 s / 1.24 x 10^2 mm^2)

T = (4π * 3844) / 54

T = (15246.88) / 54

T = 282.6 s

Rounding to two significant figures, the time it takes the technician to polish the entire lens is approximately:

T = 283 s

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To stay in a circular orbit at a specific distance, the satellite must have a speed that is three times the square root of that distance. Therefore, the correct answer is option B.

The speed of a satellite in a circular orbit around a planet can be determined by equating the centripetal force required to keep the satellite in orbit with the gravitational force of the planet on the satellite.

The centripetal force is given by \(F = mv^2/r\), where m is the mass of the satellite, v is its speed, and r is the distance from the center of the planet.

The gravitational force is given by \(F = G(Mm)/r^2\), where G is the gravitational constant, M is the mass of the planet, and m is the mass of the satellite. Equating these two forces and solving for v gives \(v = \sqrt{(GM/r)}\)

Substituting the given values for g = 9 m/s² and r, we get \(v = \sqrt{(gr)}\), which simplifies to \(v = \sqrt{(9r)} = 3\sqrt{r}\).

Therefore, the correct answer is v = 3r. This means that the speed of the satellite must be three times the square root of the distance from the center of the planet to remain in a circular orbit at that distance.

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Answer:

two protons and two neutrons

it's the answer. hope it helps

Alpha particles have two protons and two neutrons. Therefore, option (D) is correct.

Alpha particles can be defined as positively charged particles released from the decay of several radioactive materials. The mass of the Alpha particle is because of the presence of two protons and two neutrons. Therefore, the Alpha particles nucleus is very similar to the nucleus of the Helium atom and are denoted by the Greek alphabet α.

An alpha particle or ray is also known as doubly ionized helium nuclei (He²⁺). The alpha particle's mass is equal to 6.64 × 10⁻²⁷ Kg. Alpha particles are generally generated during the standard radioactive decay of atomic nuclei.

Alpha particles contains the kinetic energy of 5MeV and a speed of 5 % of that of the speed of light. They are also formed in high-energy particle accelerators and are highly ionized particles with low penetration depth compared to other particles.

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Answer:

I'm not ASTRO physicist but an electro field is where I put my bets on

Explanation:

could be wrong

The current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.

When three resistors are connected in series with a six resistor and a 12-volt battery, the total resistance of the series circuit is R = R1 + R2 + R3 + ...

The current flowing through the circuit is the same at every point. So, if we want to know the current flowing through each resistor, we need to use Ohm's law, I = V/R, where V is the voltage of the battery and R is the resistance of each resistor.

I1 = V/R1 = 12/3 = 4 AI2 = V/R2 = 12/6 = 2 AI3 = V/R3 = 12/3 = 4 A. The voltage drop across each resistor can be calculated using Ohm's law, V = IR.

V1 = I1R1 = 4 x 3 = 12 VV2 = I2R2 = 2 x 6 = 12 VV3 = I3R3 = 4 x 3 = 12 V.

Therefore, the current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.

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Answer:

dissociation of acetic acid (like vinegar) in water

Explanation:

CH3COOH is basically vinegar (aka acetic acid)

dissociation of acetic acid in water

so when you put vinegar in water it makes 2 hydrogen ions (H+) and acetate ( CH3C00 ) a chemical that used in making film

A girl pulls her school box with force of 78N inclined at 27 degrees to the ground.  The part of the force moving the box along the ground will be 35.1 N

there will be two components of forces :

vertical as well as horizontal component

vertical component = F sin ( 27 )

horizontal component = F sin ( 27 ) = 78 sin ( 27 )

                                                          = 35.1 N  

The part of the force moving the box along the ground will be 35.1 N

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The correct answer is centrifuge.

Your complete blood is drawn out during an apheresis procedure, which is used to donate platelets. Your blood is spun in a centrifuge to separate your plasma, platelets, and red blood cells. As the blood is divided, the heavier reds cells drop to the bottom and are given back to you.

Between the liquid plasma and the platelets that are tracked into a small pouch that is wrapped around the centrifuge cylinder as the liquid plasma rises. When you donate blood, your spleen releases stockpiled platelets into your bloodstream in an effort to stop the bleeding.

As a result, more platelets and plasma are collected, enabling you to donate one, two, or even three doses of platelets in a single visit. Your healthy bone marrow quickly starts producing additional platelets from stem cells to replace those that have been given while this is happening.

Since only one donor is used for the donation, platelet donors are able to provide patients with a greater amount and higher-quality platelets to aid in their fight for survival.

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