according to the periodic table, how many valence electrons do the elements in group 7a have

The element that doesn't form a stable ion with the same electronic structure as argon is aluminium.

Argon is an element that has 18 electrons in each of its atoms. The question's answer is an element that does not has the same electronic structure as argon.

Chlorine only has 17 electrons in its atoms, but chlorine ion (Cl-) has one added electron in it, meaning it contains 18 electrons.

Phosphorus only has 15 electrons in its atoms, but phosphorus ion (P3-) has three added electrons in it, meaning it contains 18 electrons.

Potassium has 19 electrons in its atom, but potassium ion (K+) has one less electron in it, meaning it contains 18 electrons.

Aluminium has 13 electrons in its atom. Aluminium ion (Al3+) ion, however, only contains 10, making it the correct answer because it's not the same amount of electrons as argon.

Your question seems incomplete, but the complete version is most likely as follows:

Which element does not form a stable ion with the same electronic structure as argon?
A. Aluminium
B. Chlorine
C. Phosphorus
D. Potassium

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The molar mass of aspartame is approximately 294.30 g/mol with 5 oxygen atoms and 1.51 × 10^23 molecules of aspartame. There are approximately 0.068 moles of aspartame in 20.0 g.

i) To calculate the molar mass of aspartame, we need to sum up the atomic masses of all the atoms in its chemical formula, C14H18N2O5:

Molar mass of carbon (C) = 12.01 g/mol

Molar mass of hydrogen (H) = 1.01 g/mol

Molar mass of nitrogen (N) = 14.01 g/mol

Molar mass of oxygen (O) = 16.00 g/mol

Molar mass of aspartame = (14 × molar mass of C) + (18 × molar mass of H) + (2 × molar mass of N) + (5 × molar mass of O)

Calculating the molar mass of aspartame:

Molar mass of aspartame = (14 × 12.01) + (18 × 1.01) + (2 × 14.01) + (5 × 16.00)

Molar mass of aspartame ≈ 294.30 g/mol

Therefore, the molar mass of aspartame is approximately 294.30 g/mol.

ii) To determine the number of moles of aspartame in 20.0 g, we can use the molar mass of aspartame:

moles = mass / molar mass

moles = 20.0 g / 294.30 g/mol

moles ≈ 0.068 moles

Therefore, there are approximately 0.068 moles of aspartame in 20.0 g.

iii) To calculate the number of molecules of aspartame in 0.250 moles, we can use Avogadro's number:

number of molecules = moles × Avogadro's number

number of molecules = 0.250 moles × 6.022 × 10^23 molecules/mol

number of molecules ≈ 1.51 × 10^23 molecules

Therefore, there are approximately 1.51 × 10^23 molecules of aspartame in 0.250 moles.

iv) To calculate the number of oxygen atoms in one molecule of aspartame, we can look at the chemical formula:

C14H18N2O5

There are 5 oxygen atoms in one molecule of aspartame.

Therefore, there are 5 oxygen atoms in aspartame.

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Answer:

The attraction of the Oxygen for an electron as measured by the electronegativity of Oxygen is 3.5 which is higher than the electronegativity of Hydrogen at 2.2

Explanation:

Answer: Higher and longer glide experience.

Explanation:

The new frequency (f1) can be calculated using f1 = (λ0/2λ1)f0, where λ1 represents the new wavelength in the new medium.

When a sound wave with wavelength λ0 and frequency f0 moves into a new medium where the speed of sound is v1 = 2v0, the wavelength and frequency of the wave will change. The new wavelength (λ1) and frequency (f1) can be determined using the relationship between wave speed, wavelength, and frequency.

The wave speed (v) is defined as the product of wavelength (λ) and frequency (f): v = λf.

Since the speed of sound in the new medium is v1 = 2v0, we can write the equation as: v1 = λ1f1.

Comparing this equation with the previous one, we find that λ1f1 = λ0f0.

Given that v1 = 2v0, we can substitute it into the equation: (2v0)(f1) = λ0f0.

From this equation, we can determine the relationship between the new frequency (f1) and the original frequency (f0): f1 = (λ0/2λ1)f0.

Therefore, when a sound wave with wavelength λ0 and frequency f0 moves into a new medium where the speed of sound is v1 = 2v0, the new frequency (f1) is given by f1 = (λ0/2λ1)f0, while the wavelength (λ1) will change accordingly.

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The molar mass of the unknown compound is 58.2 g/mol.

To find the molar mass of the unknown compound, we need to use the formula:
Molar mass = (mass of compound / moles of compound)
First, we need to calculate the number of moles of the compound in the solution. We can do this by using the formula:
moles = concentration (M) x volume (L)
We are given that the concentration of the solution is 0.077 M and the volume is 0.25 L (since it was made in a 250.0 mL volumetric flask). Plugging these values into the formula, we get:
moles = 0.077 M x 0.25 L = 0.01925 moles
Now, we can use the formula for molar mass to calculate the mass of the compound. We are given that the mass of the compound is 1.12 grams, so:
Molar mass = 1.12 g / 0.01925 moles = 58.2 g/mol
The given problem is about finding the molar mass of an unknown compound that has been dissolved in water. We know the mass of the compound that was added to the solution, as well as the concentration of the resulting solution. Using this information, we can calculate the number of moles of the compound in the solution, which can then be used to find the molar mass.
To calculate the number of moles of the compound, we used the formula: moles = concentration (M) x volume (L). This formula relates the concentration of a solution to the number of moles of solute present in a given volume of solution. By multiplying the concentration (given as 0.077 M) by the volume (0.25 L), we found that there were 0.01925 moles of the compound in the solution.
Once we knew the number of moles of the compound, we could use the formula for molar mass to find the mass of one mole of the compound. This formula is: molar mass = mass of compound / moles of compound. We were given the mass of the compound as 1.12 grams, so we divided this by the number of moles (0.01925) to get a molar mass of 58.2 g/mol.
In conclusion, by using the concentration of the solution and the mass of the compound added to it, we were able to calculate the molar mass of the unknown compound. This information can be useful in identifying the compound and understanding its properties.

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Answer:

0.0048 mol Cr

Explanation:

Step 1: Define

Molar Mass of Chromium (Cr) - 52.00 g/mol

Step 2: Use Dimensional Analysis

\(0.25 \hspace{3} g \hspace{3} Cr(\frac{1 \hspace{3} mol \hspace{3} Cr}{52.00 \hspace{3} g \hspace{3} Cr} )\) = 0.004808 mol Cr

Step 3: Simplify

We are give 2 sig figs.

0.004808 mol Cr ≈ 0.0048 mol Cr

The pH is measured to have lower pH values than basic or alkaline solutions. The pH scale is logarithmic and inversely indicates the concentration of hydrogen ions in the solution.

In chemistry, pH, traditionally denoting the ability of hydrogen, is a scale used to specify the acidity or basicity of an aqueous answer. Acidic answers are measured to have decreased pH values than basic or alkaline solutions.

The variety goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of extra than 7 shows a base. pH is surely a measure of the relative amount of loose hydrogen and hydroxyl ions inside the water.

To calculate the pH of an aqueous solution you want to recognize the awareness of the hydronium ion in moles in line with liter molarity. The pH has then calculated with the use of the expression: pH = - log [H3O+].

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Different rock and mineral ,soil profile

The main differences in the synthesis of purine and pyrimidine nucleotides -

What are 2 differences between purine and pyrimidine?

What are the structural differences among purines and pyrimidines in DNA and RNA?

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It is anticipated that the N—O bonds in NO3- will be weaker than those in NO⁺. This is due to the fact that NO³⁻ possesses three comparable N—O bonds, and the ion's negative charge renders the bonds more prone to dissociation.

The electrons in the N—O bonds are more dispersed due to the negative charge on the NO³⁻ ion, which causes a lower bond order and a weaker bond. In contrast, NO⁺ possesses a single N—O bond that is strengthened by the ion's positive charge, which pulls electrons towards the N atom. A greater bond order and a stronger N—O bond result from the N atom's increased electron density in NO⁺.

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Answer:

A

Explanation:

In simple terms: Hammer goes one way, air goes the other way.

Answer:

d

Explanation:

i took the test

Answer:

Explanation:

The nucleus of an atom contains protons and neutrons.

Protons have positive charges, neutrons have neutral charges (no charge), and electrons have negative charges.  That is why when you determine net charge of atom you only look at the proton to electron ratio since the neutrons don't matter when it comes to charge.

I hope this helps.  Let me know in the comments if anything is unclear.

The total mass of the products, including any excess reactants, in reaction \(\rm MnS (s) + 2HCl(aq) \rightarrow MnCl_2(aq) + H_2S(g)\) is 264.53g.

The principle of conservation of mass states that in a closed system, the total mass of the system remains constant, regardless of any physical or chemical changes that take place within it.

To determine the mass of the products of a chemical reaction, we need to use stoichiometry and the balanced chemical equation.

The balanced chemical equation for the given reaction is:

\(\rm MnS (s) + 2HCl(aq) \rightarrow MnCl_2(aq) + H_2S(g)\)

The mole ratio of MnS to \(\rm MnCl_2\)is 1:1, which means that if we have 1 mole of MnS, we will produce 1 mole of \(\rm MnCl_2\).

The molar mass of MnS is 54.94 g/mol, and the molar mass of \(\rm MnCl_2\) is 125.84 g/mol.

Assuming we have a large amount of MnS and a small amount of HCl, we can assume that MnS is the limiting reagent and HCl is the excess reagent.

Therefore, all of the MnS will react with HCl to form \(\rm MnCl_2\) and \(\rm MnCl_2\)\(\rm MnCl_2\).

To find the mass of the products, we need to first find the number of moles of Mns, which is equal to the mass of MnS divided by its molar mass.

If we assume we have 100 g of MnS, we have 1.82 moles of MnS. Therefore, we will produce 1.82 moles of \(\rm MnCl_2\) and 0.91 moles of \(\rm H_2S\). The mass of \(\rm MnCl_2\) is 228.47 g (1.82 moles x 125.84 g/mol), and

The mass of \(\rm H_2S\) is 36.06 g (0.91 moles x 39.99 g/mol).

Therefore, the total mass of the products, including any excess reactants, is 264.53g

(\(\rm 100 g\ {of}\ { MnS} + 0.22 g \ {of}\ { HCl} + 228.47 g \ {of} \ { MnCl_2} + 36.06 g\ {of} \ {H_2S}\)).

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Yes, compounds are pure substances as they are made of molecules that are formed by the union of atoms of different elements through chemical bonding. Hence, molecules are the fundamental unit of compounds. Each compound is made of only one type of molecule.

Answer:

1134

Explanation:

(the ones place was rounded up). 1133.981 is the unrounded answer.

Explanation:

\(\Large\textbf{B) Products}\)

The number of moles of \(Al_2O_3\) formed when 5.0 moles of Al are used up would be 2.5 mol.

The balanced equation of the reaction would be as follows:

\(4AI +3O_2--- > 2Al_2O_3\)

From the balanced equation of the reaction, the mole ratio of Al that reacts to the \(Al_2O_3\) produced is 2:1.

Using this established mole ratio, the amount, in mols of \(Al_2O_3\) that would be formed when 5.0 mol of Al reacts completely would be calculated as follow:

2 mol Al = 1 mol \(Al_2O_3\)

5.0 mol Al = 5.0 x 1/2

                  = 2.5 mol

2.5 mol to the tenth's place = 2.5 mol

In other words, the amount of \(Al_2O_3\) that would be formed is 2.5 mol.

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The large-scale patterns in the atmosphere brought on by the interactions of solar radiation, the size of the Earth's ocean, its varied topography, and motion in space are what determine the local weather that affects our daily life.

Some areas of the Earth receive more solar radiation than others as a result of the Earth's orbit around the sun and tilted axis. Global circulation patterns are produced by this uneven heating. For instance, the equator's availability of energy causes hot, humid air to climb far into the atmosphere.

Temperature, water (moisture), and light (solar radiation) are the three primary determinants of weather.

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Your question is incomplete, most probably your full question was:

Earth's geography has been affected by —

A map that shows the location of volcanoes is called a Geologic Map. This kind of map contains information about the geological history and condition of volcanic sites.

Geologic maps indicate the following:

Note that the map specific to the question is unavailable hence the general response.

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Answer:

The highest temperature is 302K

Explanation:

The answer is C

The highest temperature among the given options is 302 K.

To determine the highest temperature among the given options, we need to convert them to a common scale and compare.

Option A) 38 °C: This is a temperature in Celsius.

Option B) 96 °F: This is a temperature in Fahrenheit.

Option C) 302 K: This is a temperature in Kelvin.

Option D) None of the above: This option does not provide a specific temperature.

Option E) The freezing point of water: This is 0 °C, 32 °F, and 273.15 K.

Comparing the given options, we can see that 302 K is the highest temperature among them.

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The set of elements and symbols that is paired correctly is:

a) Beryllium, Be

In the periodic table, each element is represented by a unique symbol consisting of one or two letters. These symbols are used to identify and distinguish between different elements. It is essential to have accurate element-symbol pairings to ensure proper communication and understanding in the field of chemistry.

The other options provided do not have correct element-symbol pairings:

b) Manganese is represented by the symbol Mn, not Mg, which stands for magnesium.

c) Calcium is represented by the symbol Ca, not Cm, which stands for curium.

d) Tungsten is represented by the symbol W, not Tg or Tu.

e) Lead is represented by the symbol Pb, not La, which stands for lanthanum.

In summary, the correct element-symbol pairing is beryllium (element) and Be (symbol) from option a). The other options have incorrect pairings of elements and symbols.

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Since they are the main producers of the organic compounds needed for the development and survival of other organisms, phototrophs are essential for the flow of energy in the biosphere.

The flow of energy in the biosphere begins primarily with phototrophs. Phototrophs are organisms that use energy from the sun to convert carbon dioxide and water into organic compounds, such as sugars and carbohydrates, through the process of photosynthesis. These organic compounds provide a source of energy and nutrients for other organisms in the biosphere, which ultimately fuels the flow of energy through the food chain. Other organisms, such as chemotrophs, can also obtain energy from oxidized chemicals or inorganic compounds, but the primary source of energy in most ecosystems is derived from photosynthesis.

Therefore, phototrophs play a crucial role in the flow of energy in the biosphere, as they are the primary producers of organic compounds that support the growth and survival of other organisms.

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(a) The speed of light in the unknown substance is determined 1.82 x 10⁸ m/s.

(b) The light will bend away from the normal since speed of light in air is not equal to speed of light in the substance.

The speed of light passing from air into the substance is calculated as follows;

refractive index = speed of light in air / speed of light in the substance

speed of light in the substance = speed of light in air/refractive index

speed of light in the substance = (3 x 10⁸) / (1.65)

speed of light in the substance = 1.82 x 10⁸ m/s

Thus, the light will bend away from the normal since speed of light in air is not equal to speed of light in the substance.

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Iodine is not as effective an oxidizer as bromine. In order to produce iodine, bromine can strip iodide ions of their electrons, and the iodine cannot recover its electrons from the resulting bromide ions.

Sulfuric acid concentration working as an oxidizing agent

containing chloride or fluorine

The oxidizing power of concentrated sulfuric acid is insufficient to oxidize fluorine or chloride. Only the steamy vapors of the hydrogen halide—hydrogen fluoride or hydrogen chloride—are generated in those circumstances. Fluoride and chloride are not powerful enough reducing agents to decrease sulfuric acid in terms of the halide ions. For iodides and bromides, this is not the situation.

with bromine

Sulfuric acid can be reduced by bromide because it is a powerful reducing substance. In the procedure, bromine is produced from bromide.

The oxidation state of sulfur changes from +6 to +4 when bromide converts sulfuric acid to sulfur dioxide gas.

In actuality, the steamy hydrogen bromide fumes tainted with brown bromine vapor serve as evidence of this interaction. Since sulfur dioxide is an invisible vapor, it is impossible to see it.

Using iodide

Iodide is a more potent reduction agent than bromide, and sulfuric acid converts it to iodine.

Sulfuric acid reduction is trickier than bromine reduction. It can be lowered in three stages using iodide.

(Sulfur oxidation state = +4) sulfuric acid to sulfur dioxide

pure sulfur to sulfur dioxide (oxidation state = 0)

hydrogen sulfide from sulfur (sulfur oxidation state = -2).

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Boyle's Law, the first to explain the link between a gas's pressure and Volume 2.34L is attributed to Robert Boyle.

Boyle's law, Charles' law, and Gay-law Lussac's are combined to create the "combined gas law."

As the pressure rose, the volume decreased. As a result, it was determined that the two variables are equally connected, Boyle's Law was established. The kinetic proposal of feasts, which explains how feasts yield fruit, heavily relies on Boyle's rule.

The equation for a mixed gas is

P1V1/T1= P2V2/T2

where

P1 is the starting gas pressure of 0.850 atm.

P2 = 1.50 atm final pressure of gas

V1 = 4.25 L, initial gas volume

V2 = ultimate gas volume equals x

T1 is the gas's first temperature.

T2 is the gas's final temperature.

When we plug in all the values into the equation above, we get:

0.850*425/293.0K=1.50*V2/284.K

V2= 2.34L

Thus the final volume 2.34L

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Answer:

what is it asking???? I'm confused on what it wants you to do

For an FCC crystal: calculate the density of atoms (atoms/a² where a is the lattice constant) for the (100), (110) and (111) planesThe unit cell of a FCC crystal is shown below:Here, each corner atom contributes 1 atom, and each face atom contributes 1/2 atoms.

For (100) plane:Length of unit cell along (100) plane direction = a Density of atoms = No. of atoms / Area of the plane Area of the plane = a²Density of atoms for (100) plane = 4 / a²For (110) plane:Length of unit cell along (110) plane direction = a√2Density of atoms = No. of atoms / Area of the plane Area of the plane = a x a√2Density of atoms for (110) plane = 2 x 2 / (a x a√2) = 4√2 / a²

For (111) plane:Length of unit cell along (111) plane direction = a√3Density of atoms = No. of atoms / Area of the plane Area of the plane = a²√3/2 Density of atoms for (111) plane = 3 x 4 / (a²√3) = 4√3 / a²Hence, the density of atoms for the (100), (110) and (111) planes in an FCC crystal are as follows:For (100) plane: 4 / a²For (110) plane: 4√2 / a²For (111) plane: 4√3 / a².

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Answer:

Volume = 10ml

Density = 1/5 g/ml or 0.20g/ml

Explanation:

The rocks are 10ml since the initial volume went up by 10.

Since density = mass/volume, you divide 2 by 10.

D = 2/10

D = 1/5 g/ml or 0.20g/ml

(Unit is g/ml aka grams/millileter)