ad2 cannot measure the current directly. based on your observation, how does ad2 impedance analyzer produce the values for the current and resistors?

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Answer:

it's C velocity

Explanation:

The frictional force acting on the car is 504.24 N.

According to equation's of motion,

     v = u + at

since final velocity is zero,

acceleration, a= u/t

= 9/15.7

= 0.573 m/s^2

the frictional force, f = ma

                                  = 880*0.573

                                  = 504.24 N

Frictional force is a force that opposes motion when two objects come into contact with each other. It arises due to the interaction between the surface irregularities of the objects that are in contact. Frictional force can act in both directions, either in the direction of motion or opposite to the direction of motion, depending on the situation.

There are two types of frictional forces: static frictional force and kinetic frictional force. Static frictional force is the force that keeps a stationary object at rest and prevents it from moving. On the other hand, kinetic frictional force is the force that opposes the motion of an object that is already moving. Frictional force plays an important role in everyday life.

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Answer:

a.149 °F into °C

149 - 32 = 117

117 x 5 = 585

585 / 9 = 65

149 °F = 65 °C

b.149 °F into Kelvin

(149°F − 32) × 5/9 + 273.15 = 338.15K

Explanation:

It is given that,

A jogger runs 300 m due west and then turns and runs 500 m due south

(a) Total distance = total path covered

Distance = 500 m + 300 m

= 800 m

(b) Total displacement = shortest path covered

\(D=\sqrt{500^2+300^2} \\\\=583.09 m\)

(c) Speed = distance/time

\(s=\dfrac{800\ m}{135\ s}\\\\=5.92\ m/s\)

Velocity = total displacement/total time

\(v=\dfrac{583.09\ m}{135\ s}\\\\=4.31\ m/s\)

Hence, this is the required solution.

a) The total distance that she ran is 800m.

b) Her total displacement is 583.09 m

c) Her speed= 5.92 m/s and Velocity= 4.31 m/s

Firstly, let's write the given condition:

A jogger runs 300 m due west and then turns and runs 500 m due south

To find: a) Total distance

b) Total displacement

c) Speed and velocity

Let's solve the question:

(a) Total distance = total path covered

Distance = 500 m + 300 m  = 800 m

(b) Total displacement = shortest path covered

For this type of question in which direction is mentioned, so we can use the displacement formula as:

\(D=\sqrt{x^{2} +y^2}\)

D=\(\sqrt{{(500)}^{2}+{(300)^2}\)= \(\sqrt{250000+90000} =\sqrt{340000} =583.09m\)

(c) Speed = distance/time

\(s=\frac{d}{t} =\frac{800 m}{135 s} =5.92 m/s\)

where d= distance and t=time

Velocity = total displacement/total time

\(v=\frac{d}{t} =\frac{583.09 m}{135 s} =4.31 m/s\)

where d= displacement and t=time

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Based on the given information, when you hold a convex lens a few centimeters from your face and look at a tree that is 11 meters away, but the image appears to be even farther away at 12 meters, the image you are looking at is a virtual image.

In this scenario, the convex lens is acting as a magnifying glass, creating an enlarged virtual image of the tree. A virtual image is formed when the light rays appear to diverge from a point behind the lens. Virtual images cannot be projected onto a screen and are not formed by the actual convergence of light rays. Instead, they are perceived by the viewer's eye as if the light rays are coming from a particular point.

So, in this case, the image you see through the convex lens is a virtual image.

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The acceleration due to gravity on another planet is multiplied by your mass to calculate your weight on that planet. The acceleration due to gravity is different on each planet, so your weight will also be different. For example, the acceleration due to gravity on Earth is 9.8 m/s², while the acceleration due to gravity on Mars is 3.711 m/s². This means that if you weigh 100 pounds on Earth, you would weigh only 37.11 pounds on Mars.

The formula for calculating your weight on another planet is:

Weight = Mass * Acceleration due to gravity

For example, if you weigh 100 pounds on Earth and you want to calculate your weight on Mars, you would use the following formula:

Weight on Mars = 100 pounds * 3.711 m/s²

Weight on Mars = 371.1 pounds

Therefore, your weight on Mars would be 371.1 pounds.

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Answer:

Unit Conversion

Answer:

22 cm ^3

Explanation:

P1 V1   = P2 V2         with constant mass and temperature

11 ( 5 x 10^5 ) =  x  ( 2.5 * 10^5)

x = 22 cm^3              ( when you 1/2 the pressure, you double the volume)

Answer:

125 meters

Explanation:

we know that

v × t = d

v = 25

t = 5

so the distance should be 5 × 25

answer is 125 meters

Answer:

the Moon is smaller in diameter than the United States

however. The United States is 2,545 km / 1,582 mi from north to south, and thus, the Moon is smaller across than the United States is wide.

Answer:

The moon is smaller than the earth.

Explanation:

Moon's Diameter is 2,159.1 mi

Earth's Diameter is 7,917.5 mi

Answer: They change the shape of the lens

Explanation: It enables the lens to change its shape to focus on objects at various distances

A puck moves at 2.35 m/s in a -22° angle.It is pushed for 0.215 seconds by a hockey stick, changing its velocity to 6.42 m/s in a 50.0° direction. The negative sign indicates that the puck has fallen below its initial height.

How to solve the given problem with the help of trigonometry?

To solve the problem, we need to use the equations of motion and trigonometry.

First, let's find the initial velocity components:

\(\mathrm V_{i,x} = v_i cos(\theta_i) = 2.35 cos(-22^\circ) \approx 2.216\text{ m/s}\)

\(\mathrm V_{i,y} = v_i sin(\theta_i) = 2.35 sin(-22^\circ) \approx -0.891\text{ m/s}\)

where \(v_i\) is the initial velocity and \(\theta_i\) is the initial angle in degrees.

Next, we need to find the final velocity components:

\(\mathrm V_{f,x} = v_f cos(\theta_f) = 6.42 cos(50^\circ) \approx 4.121\text{ m/s}\)

\(\mathrm V_{f,y} = v_f sin(\theta_f) = 6.42 sin(50^\circ) \approx 4.936\text{ m/s}\)

where \(v_f\) is the final velocity and \(\theta_f\) is the final angle in degrees.

The change in velocity components are:

\(\Mathrm\Delta V_x = V_{f,x} - V_{i,x} \approx 1.905\text{ m/s}\)

\($\Delta V_y = V_{f,y} - V_{i,y} \approx 5.827\text{ m/s}\)

The time of the push is t = 0.215 s.

Using the equation of motion, we can find the change in position in the y-direction:

\($\Delta y = V_{i,y} t + \frac{1}{2} a_y t^2\)

where a_y is the acceleration in the y-direction.

Since the puck is in flight, the only force acting on it is gravity, which causes an acceleration of \(-9.8 m/s^2\) in the y-direction.

Plugging in the values, we get:

\(\Delta y = (-0.891\text{ m/s})(0.215\text{ s}) + \frac{1}{2} (-9.8\text{ m/s}^2)(0.215\text{ s})^2 \approx -0.139\text{ m}\)

Note that the negative sign indicates that the puck has fallen below its initial height.

Therefore, the change in position in the y-direction is approximately 0.139 m.

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Answer:

0.434

Explanation:

Answer:It’s A

Explanation:

Answer: 30 m/s going west

Explanation:

APE X

200 ms²  is the kinetic energy for an object that weighs 40g and moving at 10 m/s.

Kinetic energy is the power that an object has had as a result of motion. To accelerate an object, a power must be supplied to it. To apply a force, we must exert effort. The power is transported to the object when work is accomplished, which causes it to move at a new, constant pace.

The capacity to perform work is unquestionably the most important characteristic of kinetic energy. Force acting on to an object while it is traveling is referred to as work. Energy and work are interchangeable because of their close relationship.

Using Kinetic Energy Formula:

K.E  = 1/2 mv²

K.E. = 1/2 * 40 * 10

K.E. = 200 ms²

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The support force acting on the 200-N girl standing on a weighing scale is 200 N. The correct option is A.

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the girl stands on the weighing scale, her weight exerts a downward force of 200 N due to gravity. In response to this downward force, the weighing scale exerts an equal and opposite upward force, which we refer to as the support force.

The support force is necessary to counterbalance the girl's weight and prevent her from sinking through the scale. It acts perpendicular to the surface of the scale and is equal in magnitude but opposite in direction to the weight of the girl.

Since the girl's weight is 200 N, the support force must also be 200 N to maintain equilibrium. This ensures that the net force acting on the girl in the vertical direction is zero, resulting in a stable standing position on the weighing scale.

Therefore, the correct answer is A. The support force acting on the girl is 200 N, which balances her weight and keeps her in equilibrium on the scale.

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Force at the supporting point = 1890 N

Force at the left hand end = 1130 N

When there is no net force exerted on an object and it is considered to be in equilibrium if the amount and direction of the forces acting on it are precisely balanced.

Given:

Length of diving board = 3 m

Distance of pivot = 1.0 m

\(d_{1}\) = 1.5 m distance of board's center of gravity to left end measurement

Weight of the diver = 500 N

Weight of the diving board = 260 N

The total force multiplied by each force's respective distance equals the force at the support point.

\(F_{s} = f_{1} d_{1}+f_{2}d_{2}\)

\(F_{s}\) = 260 x 1.5 + 500 x 3

\(F_{s}\) = 1890

supporting force at a distance of 1 m.

\(F_{s} = \frac{1890}{1}\) = 1890 N

Hence, the force at the supporting point is 1890 N.

Net torque = 0

Therefore, \(F_{1}d -f_{1}d_{1}-f_{2} d_{2}=0\)

\(F_{1} d=f_{1}d_{1} +f_{2} d_{2}\)

\(d_{1}\) = 1.5 - 1 = 0.5 m

\(d_{2}\) = 2 m

d = 1

\(F_{1}\) = (260 x 0.5)+(500 x 2)/1

\(F_{1}\) = 1130 N

Hence, the force at the left hand end is 1130 N.

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Answer:

I = 0.82A

Explanation:

I = W/V

I = 90W/110V

I = 0.82A

The parakeets swing with a frequency of approximately 1.14 Hz.

The frequency at which the two parakeets swing on the swing can be determined by considering the relationship between the period of oscillation and the length of the pendulum.

The period of a pendulum is the time it takes for one complete oscillation, while the frequency is the reciprocal of the period, representing the number of oscillations per unit time.

In this case, we are given the distance of the combined center of mass of the parakeets below the pivot, which is 19.5 cm.

To find the frequency, we need to calculate the length of the equivalent pendulum, which is the distance from the pivot point to the combined center of mass of the parakeets.

Assuming the length of the equivalent pendulum is L, we can substitute the given values into the formula for the period of a pendulum, T = 2π√(L/g), where π is a constant (approximately 3.14159) and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Converting the distance from centimeters to meters, we have L = 0.195 m. Substituting the values into the formula, we obtain T = 2π√(0.195/9.8).

Simplifying the equation, we have T = 2π√(0.02), which evaluates to approximately 0.879 s.

To calculate the frequency, we take the reciprocal of the period: f = 1/T = 1/0.879 ≈ 1.14 Hz.

Therefore, the parakeets swing with an approximate frequency of 1.14 Hz.

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The equation should be used to calculate the speed of a wave is speed = frequency x wavelength.

The speed of a wave is calculated by the equations: V = λ . f or V = λ/T, and the unit of measurement is m/s. This speed depends on the medium: in gaseous media, the speed is lower than in solid media.

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The equation should be used to calculate the speed of a wave is speed = frequency x wavelength.

Wave speed is the movement of a progressive wave, which is an energy-moving disturbance that takes the shape of an oscillation and moves from one place to another.

The wavelength and frequency of a wave both affect its speed. A wave's speed is a crucial factor because it enables us to estimate how quickly the wave will disperse in the medium, which is the substance or material that will carry it.

This is the water in the case of ocean waves and the air in the case of sound waves. The kind of wave and the physical properties of the medium in which it is flowing also affect a wave's velocity.

Therefore, The equation should be used to calculate the speed of a wave is speed = frequency x wavelength.

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A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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Answer:

Negitive

Explanation:

Electrons have a negitive charge, protons have a positive charge, and neutrons have no charge.

The distance , d, of the wave front is determined as 0.894 cm.

The wavelength of the wave is calculated is calculated by applying the following formula.

The total distance made in circular form = vt

where;

D = 0.24 m/s x 0.35 s

D = 0.084 m

The radius of the circular form is calculated as;

D = 2πr

r = D/2π

r = 0.084 m/2π

r = 0.0134 m

radius of each = 0.0134 / 3 = 0.00446 m

The distance of d is calculated as;

d = 0.0134 m - 0.00446 m

d = 0.00894 m = 0.894 cm

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Answer:

if you are not wearing a seatbelt you would slide which ever way you are turning but if you are wearing a seatbelt you would fell pressua when you are turning.

Explanation:

The range of speeds the object can have before the string breaks is approximately 4.63 m/s to 9.77 m/s.

To determine the range of speeds, we need to consider the tension in the string. At maximum speed, the tension in the string is equal to the centripetal force required to keep the object moving in a circle. This can be calculated using the formula: T_max = m * v_max² / r, where T_max is the maximum tension, m is the mass of the object, v_max is the maximum speed, and r is the radius of the circle.

Since the tension in the string cannot exceed the breaking strength of 250 N (25.0 kg × 9.8 m/s²), we can set up the following inequality: m × v_max² / r ≤ 250 N. Simplifying the inequality, we have v_max² ≤ 250 N × r / m.

Taking the square root of both sides, we get v_max ≤ √(250 N × r / m). Plugging in the given values (r = 0.800 m, m = 3.00 kg), we can calculate the maximum speed: v_max ≤ √(250 N × 0.800 m / 3.00 kg) ≈ 9.77 m/s.

Similarly, we can calculate the minimum speed by considering the tension at minimum speed, which is zero. Using the same formula, we get v_min ≤ 0 m/s. Therefore, the range of speeds is approximately 0 m/s to 9.77 m/s.

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Complete question:

A light string can support a stationary hanging load of 25.0 kg before breaking. An object of mass m = 3.00 kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r = 0.800 m, and the other end of the string is held fixed. What range of speeds can the object have before the string breaks?

The process of a gas cylinder floating in a large tank of water is an example of an equilibrium process.

The gas cylinder floating in a large tank of water represents a state of equilibrium. In this scenario, the gas cylinder is immersed in the water, and the forces acting on it are in balance.

When the gas cylinder is placed in the water, it experiences an upward buoyant force due to the displacement of water by the cylinder. This buoyant force is equal to the weight of the water displaced by the cylinder. According to Archimedes' principle, this buoyant force is equal to the weight of the gas cylinder itself.

Simultaneously, the gas cylinder experiences a downward gravitational force due to its own weight. For the cylinder to float, these two forces must be equal.

As a result, the floating gas cylinder represents an equilibrium state, where the buoyant force and the gravitational force are balanced. This equilibrium occurs because the density of the gas in the cylinder is lower than the density of the water, allowing it to displace a volume of water that is equal to its own weight.

Therefore, the process of a gas cylinder floating in a large tank of water is an example of an equilibrium process where the upward buoyant force equals the downward gravitational force.

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Hey mate there is a same question answered by me correctly .Visit the link below for your answer

https://brainly.com/question/24502753?

Answer: 160 km

Explanation:

Newton's laws state that until a force acts upon an item, it continues to move while in motion. Momentum, which is an object's compound of mass and velocity, is used to measure this "motion" value.

Simply put, momentum is the quantity of motion. Since an item has momentum if it is moving and already has mass, quantity may be measured in this situation. An item lacks momentum if it is immobile.

Momentum may be viewed as a body's "power" while it is moving, or the amount of force it can exert on another body. For instance, a slow-moving bowling ball might have the same acceleration as a baseball being thrown fast.

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To find the average velocity on a velocity-time graph, you need to calculate the slope of the line connecting two points on the graph. The average velocity represents the change in velocity divided by the change in time between those two points.

To calculate the average velocity, you can use the formula:

Average velocity = (change in velocity) / (change in time)

You can determine the change in velocity by finding the difference between the final velocity and the initial velocity. The change in time is the difference in the time coordinates of the two points.

Select two points on the velocity-time graph, typically denoted by (t₁, v₁) and (t₂, v₂), where t represents time and v represents velocity. Then, substitute the values into the formula mentioned above to calculate the average velocity.

It's important to note that the average velocity provides information about the overall change in velocity over a specific time interval, rather than instantaneous velocity at a particular moment.

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When you park and your vehicle is facing uphill and there is no curb, your wheels should be turned so that they point towards the side of the road .

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