Adam got 56 out of 84 correct in his test.
What fraction of the marks did he get correct?
Give your answer in its simplest form.

The parabola x = √(y - 9) opens upwards.The given parabolic equation is x = √(y - 9). Let's identify the direction of opening of this parabola.The general form of the equation of a parabola is y = a(x - h)² + k.

Comparing this to the given equation, we can see that h = 0 and k = 9. The vertex is therefore (h, k) = (0, 9). Now, let's determine whether the parabola opens upwards or downwards.

If the coefficient of (x - h)² is positive, the parabola opens upwards, and if it's negative, the parabola opens downwards. In this case, since the coefficient of (x - h)² is 1, which is positive, the parabola opens upwards.

Therefore, the parabola x = √(y - 9) opens upwards.

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Answer:  Its line AB!

Step-by-step explanation: a tangent is a line that touches the edge of the circle but doesnt go inside :)

Brainliest if correct?

Answer:

24

Step-by-step explanation:

Area of a triangle

A = 1/2 bh

b=12

h=4

A= 1/2 * 12 * 4

A = 24

Answer:

66 degrees

Step-by-step explanation:

All three angles on any given triangle have a sum of 180 degrees.

We know that the measure of angle B is the the same as angle C.

So 57 +57 = 114

180 - 114 = 66

Hope that helps!

Answer: I believe the answer is (A)  (-4,4) because the only corner that's going up towards the (f) is stopped over the 4's.

The range of values of x for which the given approximation is accurate to within the stated error (0.164375 (0.164375)3/3!=9.993513*10(-7))0.000001.

The series ∑∞n=1bnsin(nπLt) is known as the sine series of f(t) and the series a02+∑∞n=1ancos(nπLt) is known as the cosine series of f(t).

The development series of sin(x) near 0 is, according to

Sin(x) = x/1, x/3, and x/5!...............(1) (1)

Using the above estimate, S(x)=x-x3/3! ................(2)

Consequently, the incorrect phrase for the guess is

error=(2)- (1)

= -(x^5/5! - x^7/7! + x^9/9!)

According to the elective series hypothesis, we only want to make sure that the aggregate will be below as much as feasible and that the outright value of the initial term dropped (x5/5!) is not exactly as far as possible.

This declares what

|x^5/5!| < 0.000001

Speaking for x:

x^5=5!*0.000001=0.000120

x=(0.000120)^(1/5)=0.164375

In light of this, the estimation of sin(x) is x-x3/3! has a blatant error for the range [-0.164375,+0.164375] below 0.000001.

Thus,

sin(0.164375)- (0.164375)^3/3!=9.993513*10^(- 7) < 0.000001

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9514 1404 393

Answer:

  C ≈ 0.00106455765168

Step-by-step explanation:

This is the sum of 13 terms of the geometric series that has 10000C/1.05 as the first term and a common ratio of 1/1.05. The sum S is given by ...

  S = a1(1 -r^n)/(1 -r) . . . . a1 is the first term, r is the common ratio

Using the known values, we have ...

  100 = (10000C/1.05)(1 -1.05^-13)/(1 -1/1.05))

  0.01 = C(1 -1.05^-13)/0.05

  C = 0.0005/(1 -1.05^-13) ≈ 0.0005/0.469679

  C ≈ 0.00106455765168

Answer:

C ≈ 0.00106455765168

Step-by-step explanation:

100 = (10000C/1.05)(1 -1.05^-13)/(1 -1/1.05))

 0.01 = C(1 -1.05^-13)/0.05

 C = 0.0005/(1 -1.05^-13) ≈ 0.0005/0.469679

 C ≈ 0.00106455765168

\(\\ \sf\longmapsto C(t)=(t,\dfrac{t^2}{2})\)

\(\\ \sf\longmapsto C(1/2)=,\dfrac{1}{2},\dfrac{(1/2)^2}{2})\)

\(\\ \sf\longmapsto C(1/2)=(\dfrac{1}{2},\dfrac{\dfrac{1}{4}}{2})\)

\(\\ \sf\longmapsto C(1/2)=(\dfrac{1}{2},\dfrac{1}{8})\)

Now

Slope

\(\\ \sf\longmapsto \dfrac{y_2-y_1}{x_2-x_1}\)

\(\\ \sf\longmapsto \dfrac{0-\dfrac{1}{8}}{0-\dfrac{1}{2}}\)

\(\\ \sf\longmapsto \dfrac{\dfrac{1}{8}}{\dfrac{1}{2}}\)

\(\\ \sf\longmapsto \dfrac{1}{4}\)

Answer:

that one before -1

Step-by-step explanation:

Answer:

They are 240 kilometers apart.

Step-by-step explanation:

This question can be solved using the following relation:

\(v = \frac{d}{t}\)

In which v is the velocity, d is the distance and t is the time.

An express train travels 80km/h from Ironton to Wildwood.

Here we have \(v = 80, t = x\). So

\(v = \frac{d}{t}\)

\(80 = \frac{d}{x}\)

\(d = 80x\)

A local train, traveling at 48km/h, takes 2 hours longer for the same trip.

This means that when \(v = 48, t = x + 2\(. So

\(v = \frac{d}{t}\)

\(48 = \frac{d}{x+2}\)

Since \(d = 80x\)

\(48 = \frac{80x}{x+2}\)

Applying cross multiplication

\(80x = 48(x + 2)\)

\(80x = 48x + 96\)

\(32x = 96\)

\(x = \frac{96}{32}\)

\(x = 3\)

So the distance is:

\(d = 80x = 80*3 = 240\)

They are 240 kilometers apart.

a) The phasor form of E-field = xˆ 2cos(wt - kz) - yˆ 4cos(wt - kz) is 2√5 L(-63.43).

Polarization type is linearly polarised.

b) The phasor form of E-field = ?

E(z,t) = xˆ 2cos(wt + kz) - yˆ 4sin(wt + kz) is E(z,t) =2√5 L(-143.43). polarization type is elliptical.

We have given that

E⃗(z,t) =2xˆcos(wt - kz) - 4 yˆcos(wt - kz)

|r⃗ | = √((2cos(wt - kz))² + (- 4cos(wt - kz))²)

= √(4cos²(wt - kz) + 16cos²(wt - kz))

= √(20cos²(wt - kz))

= 2√5 cos(wt - kz)

φ = 4cos(wt - kz)/(2cos(wt - kz))

= tan⁻¹ 1(-2) = -63.43°

So, E(z,t) = 2√5 L(-63.43)

b) E(z,t) = xˆ 2cos(wt + kz) - yˆ 4sin(wt + kz)

= xˆ 2cos(wt + kz) - yˆ 4cos(wt + kz -π/2)

|r| = √((2cos(wt + kz))² + (- 4sin(wt -+kz))²)

= √20

phi = tan⁻¹(- 4cos(wt - kz)/(2cos(wt - kz)) - π/2

= tan⁻¹( -2) + π/2 = - 143.43

so, E(z,t) =2√5 L(-143.43)

E(z,t) = xˆ 2cos(wt - kz) - yˆ 4cos(wt - kz)

if wt = 0°

E(z,t) = xˆ 2cos(0 - kz) - yˆ 4cos(0- kz)

= 2xˆ - 4yˆ

wt = 30° , E(z,t) = xˆ 2cos( - kz) - yˆ 4cos(0- kz)

E(z,t) = √3/2(2) xˆ - √3/2(4) yˆ

= √3xˆ - 2√3yˆ

for wt = 45°

E(z,t) = √2 xˆ - 2√2 yˆ

for wt = 90° =>E(z,t) = 0

for wt = 60° , E(z,t) = xˆ - 2 yˆ as seen in above graph that is linear polarised

For part (b) ,

E(z,t) = 2 xˆcos(wt - kz) - 4yˆ sin(wt + kz)

From graph elliptical polarised,

for wt = 0 , E(0,t) = 2 xˆ

for wt = 90° , E(0,t) = -4yˆ

for wt =180° , E(0,t) = -2 xˆ

for wt = 270° , E(0,t) = -4yˆ

Hence, we get the answer of both parts.

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Answer:

A school year is 36 weeks long, so 3/4 of the school year is 36 * (3/4) = 27 weeks.

If Sunny works at the library for three weeks longer than three over four of the school year, he works for 27 + 3 = 30 weeks.

So, Sunny works at the library for 30 weeks in the school year.

The number of weeks in the school year that Sonny worked at the library is; 30 weeks

We are told that Sunny works at the library for three weeks longer than three over four of the school year a school year is 36 weeks long.

Now, since he works three weeks longer than three over four of the school year, then the expression is;

³/₄(36) + 3

= 27 + 3

= 30 weeks

That figure represents the number of weeks in the school year that Sonny worked at the library.

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Using Trigonometry, the value of x in the right triangle is 17.1

Since we have a right angle triangle ; The angle L can be obtained thus ;

L = 180 - (90+67)

L = 23

Using Trigonometry:

Sin23° = opposite/ hypotenuse

Opposite= 6.7

hypotenuse= x

Sin23° = 6.7/x

x = 6.7/sin(23°)

x = 17.14

Therefore, the value of x to the nearest tenth is 17.1

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Answer:

0.75 lbs

Step-by-step explanation:

You see, the puppy weighs 24 lbs now, but at birth it was 32 times less lbs then now.

Answer:

5/6 x 1 = 5/6 2/3 x 2= 4/6. 5/6 is greater than

2/3

Step-by-step explanation:

find a common denominator then see which one has more value

We will use the rule of tangents drawn from a point outside the circle to solve the question

If two tangent segments are drawn from a point outside the circle, then they are equal in length

From the given figure we can see a circle and 8 tangents are drawn from 4 points outside the circle

Then every 2 tangents are drawn from a point outside the circle are equal in lengths

Let us draw a sketch to see them

Now, we can find the length of each side of the quadrilateral

To find the perimeter we will add the lengths of the 4 sides

The perimeter of the quadrilateral is 59.6

The answer is the 3rd choice

Answer:

it is true

it's a quadralateral

The Dialog module prompts the user to select a model, allowing the user to access the database and select data for the decision process or to set criteria for selecting such data .

Given :

prompts the user to select a model, allowing the user to access the database and select data for the decision process or to set criteria for selecting such data.

Dialog module :

The dialog module provides dialog awareness for the Kamailio proxy. It's functionality is to keep track of the current dialog , to offer information about them .

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Step-by-step explanation:

Step 1:  Determine a set of data that has a mean of 21

Having a mean of 21 means that the average of the numbers are 21.  So we can have a set like {20, 21, 22} that would give us a mean of 21.  It really depends on the options that you are given in the problem.

Answer:

70% in favor of building a new playground  

3500 (in favor) + 1500 (against it) = 5000 (total number votes)

3500 (in favor)                                              1500 (against it)

-------------------    = 0.7 / 70%                          -------------------     =0.3 / 30%

5000 (total)                                                      5000 (total)            

Answer: your answer is 13

Step-by-step explanation:

useing the distance formula for two points we will find your answer .

√((x2 – x1)² + (y2 – y1)²)

so we plug in your coordinates in the equation above and solve

√(9(-4))^2+(6-6)^2= √169

√169=13

Answer:

9 4/33.

Step-by-step explanation:

0.12 repeating = 12/99

= 4/33.

if we  that Abby spent 50% of her time on School, 30% on Work, and 20% on Sleep, we can estimate that she spent:

100% - (50% + 30% + 20%) = 100% - 100% = 0% on Other.

If Abby divided her time into four categories (School, Work, Other, and Sleep), the percentage she spent on Other would be 100% less the sum of the percentages she spent on School, Work, and Sleep.

So, assuming Abby spending 50% of her time at school, 30% at work, and 20% sleeping, we can estimate she spent:

On Other, 100% - (50% + 30% + 20%) = 100% - 100% = 0%.

However, this is just a guess based on assumptions about how Abby spent her time. It's difficult to provide a more accurate estimate without more information.

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The rate of the speeding car is 0.493.

We have,

The police car is at 80 mph and it is 44 yards from the intersection, is increasing at 45 mph, while the other car is 117 yards away from the intersection.

So, Rate of speeding car

= (45- 80)/ (117- 44)

= -35/(-73)

= 35/73

= 0.493

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(1) x² - 2 x - 8 and Option (2) x² + 2 x - 8 are two polynomials which has been factored.

Given are the polynomials,

1) x² - 2 x - 8

Factors = (x+2)(x-4)

2) x² + 2 x - 8

Factors = (x-2)(x+4)

3) x²-2x-4 = There will be no integral root.

4) x²+2x-4 = There will be no integral root.

Hence the (1) x² - 2 x - 8 and Option (2) x² + 2 x - 8 are two polynomials which has been factored.

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Answer:

p=32 p<32

Step-by-step explanation:

Answer:

I can write out the sample space for a multi-step experiment, using a list, table, or tree diagram Pause here so your teacher can review your work.  Make sure you list every possible outcome without repeating any. Describe a situation that involves three parts and has a total of 24 outcomes in the sample space.

Step-by-step explanation:

i really don't know but i tried XD hope this help

Therefore, the probability that the first number divided by the second number is greater than zero is 1/3.

In mathematics, probability is a measure of the likelihood or chance of an event occurring. It is a way of quantifying uncertainty and expressing how likely it is that a particular outcome will occur. Probability theory is used in a wide range of fields, including mathematics, statistics, physics, engineering, economics, and social sciences. It is used to model and analyze random phenomena, make predictions, and estimate the likelihood of certain outcomes.

Here,

Since we are returning the first tile to the bag before selecting the second one, the two selections are independent of each other.

There are two cases to consider:

Case 1: We select a positive number on the first draw.

The probability of selecting a positive number on the first draw is 2/3, since there are two positive numbers (-12 and 1) out of a total of three tiles.

Regardless of what number we select on the first draw, there is only one negative number (-2) in the bag, so the probability of selecting a negative number on the second draw is 1/3.

Therefore, the probability of selecting a positive number on the first draw and a negative number on the second draw (which results in a quotient greater than zero) is:

(2/3) x (1/3) = 2/9

Case 2: We select the negative number (-2) on the first draw.

The probability of selecting the negative number (-2) on the first draw is 1/3.

In this case, we must select the positive number on the second draw in order for the quotient to be greater than zero. There is only one positive number (1) in the bag, so the probability of selecting it on the second draw is 1/3.

Therefore, the probability of selecting the negative number (-2) on the first draw and the positive number on the second draw (which results in a quotient greater than zero) is:

(1/3) x (1/3) = 1/9

Since these are the only two cases that satisfy the condition, the overall probability is the sum of the probabilities of these two cases:

2/9 + 1/9 = 3/9 = 1/3

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Answer:

I'm not so very sure but I really need points