Add the two expressions.

−6.5b+11 and 3.3b−2

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The y-intercept of the linear function means that her initial distance from the finish line is of 10 kilometers.

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

In which:

The graph crosses the y-axis at y = 10, hence the intercept b is given as follows:

b = 10.

The y-values represent the distance in the context of this problem, hence the initial distance is of 10 km.

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\( \frac{1}{9} = \frac{1 \times 8}{9 \times 8} = \frac{8}{72} \\ \)

\( \frac{1}{2} = \frac{1 \times 36}{2 \times 36} = \frac{36}{72} \\ \)

\( \frac{1}{8} = \frac{1 \times 9}{8 \times 9} = \frac{9}{72} \\ \)

_________________________________

\( \frac{8}{72} < \frac{9}{72} < \frac{36}{72} \\ \)

\( \frac{1}{9} < \frac{1}{8} < \frac{1}{2} \\ \)

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Thus the order from greatest to least is :

\( \frac{1}{2} \: , \: \frac{1}{8} \: , \: \frac{1}{9} \\ \)

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The volume of a cylinder is given by the equation presented as follows:

V = πr²h.

In which:

The volume of a cylinder of radius r and height h is given by the equation presented as follows:

V = πr²h.

Hence the measures must be identified and have it's values replaced into the formula to obtain the volume of a cylinder.

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Answer:

Step-by-step explanation:

Given that:

To Find:

We know that:

Finding the volume:

⇒ Volume = (2)³

⇒ Volume = 2 × 2 × 2

⇒ Volume = 8

Hence,

The true statements are;

1) AB + BC = AC

Length of BC = |6 - 1|

2) ∠JMK = 50°

∠KML = 35°

1) From the given number line interval, we can deduce the interpretation as follows;

AB + BC = AC

Length of BC = 5 units or |6 - 1|

Length of B = 3 Units

2) We can see that ∠JML is an angle triangle. Thus, ∠JML = 85°. Thus;

6x + 2 + 4x + 3 = 85

10x + 5 = 85

10x = 85 - 5

10x = 80

x = 80/10

x = 8°

Thus;

∠JMK = 6(8) + 2

∠JMK = 50°

∠KML = 85° - 50°

∠KML = 35°

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Answer:

x = 3/2 or x = -1

Step-by-step explanation:

2x² - x - 3 = 0

2*(-3) = -6

Factors of -6:

(-1, 6), (1, -6), (-2, 3), (2, -3)

We need to find a pair that adds up to the co-eff of x which is (-1)

Factors :(2,-3)

2 - 3 = -1

so, 2x² - x - 3 = 0 can be written as:

2x² + 2x - 3x - 3 = 0

⇒ 2x(x + 1) -3(x + 1) = 0

⇒ (2x - 3)(x + 1) = 0

⇒ 2x - 3 = 0 or

x + 1 = 0

⇒ 2x = 3 or x = -1

⇒ x = 3/2 or x = -1

Since the company paid a total of $248,000 in direct labor costs during the period, there is no difference between the standard and actual costs of direct labor.

To determine the total increase recorded in the Work in Process account related to direct labor, we need to first calculate the total standard cost of direct labor for the period and then compare it to the actual cost of direct labor.

According to the standard cost card, each unit of the product requires 2 hours of direct labor at a rate of $16.00 per hour.

This means that the total standard cost of direct labor for the period is 2 * $16.00 * 7,800 = $248,000.

Since the company paid a total of $248,000 in direct labor costs during the period, there is no difference between the standard and actual costs of direct labor. Therefore, the total increase recorded in the Work in Process account related to direct labor would be $0.

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Using the lowest common factor of the shuttles' run times, they will depart again for the campus simultaneously at 10.25 A.M.

We can use the lowest common factor (LCM) of their run time to determine when they depart again for the campus.

The lowest common factor of 30 and 20 is 60 because both 30 and 20 can divide 60 evenly without a remainder, showing that it takes 60 minutes for the two shuttles to depart for the campus at the same time.

We can conclude that every 60 minutes or hour, the two shuttles simultaneously depart for the campus.  Every hour, the shuttle departing from Ball Hall completes 2 runs, while the shuttle departing from Lot A completes 3 runs.

Thus, using the lowest common factor, the next time both shuttles will depart for the campus at the same time is 10:25 A.M.

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The measure of the angles are:

∠1 = 90

∠2 = 90

∠3 = 132

We have,

The angle between the tangent and the radius of a circle is 90.

So,

∠1 = 90

∠2 = 90

And,

48 + 90 + 90 + ∠3 = 360 ______(1)

Solve for ∠3 from (1).

48 + 90 + 90 + ∠3 = 360

48 + 180 + ∠3 = 360

∠3 = 360 - 228

∠3 = 132

Thus,

The measure of the angles are:

∠1 = 90

∠2 = 90

∠3 = 132

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The Intel pays $7,760 to Bally Manufacturing on August 14.

The first step in calculating what Intel Corporation pays Bally on August 14 is to determine the net price of the machinery after the trade discount and the return of $100 due to defects.

The trade discount of 40% is calculated as follows:

Discount = List price × Discount rate

Discount = $13,100 × 0.40 = $5,240

So the net price of the machinery after the trade discount is:

Net price = List price - Discount

Net price = $13,100 - $5,240 = $7,860

After Intel returns $100 of machinery, the cost of the machinery is further reduced to:

Net price after return = Net price - Return

Net price after return = $7,860 - $100 = $7,760

Since the payment terms are 3/10 EOM (end of month), Intel receives a discount of 3% if payment is made within 10 days. The 10-day period begins on August 1 and ends on August 10 (the payment due date). Since Intel pays the bill on August 14, payment is late and the 3% discount does not apply.

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Answer:

109°

Step-by-step explanation:

X = 38+ (180-38)/2

= 38 + (142/2)

= 38 + 71

= 109°

The missing code that can be used to replace / missing code / so that the code segment works as intended is x >= 10.

The code segment is intended to store the sum of all multiples of 10 between 10 and 100, inclusive. The value of x starts at 100 and is decremented by 10 on each iteration of the loop, until it reaches 10. The sum of all the multiples of 10 between 10 and 100 is stored in the variable total.

The missing code in the while statement determines when the loop will stop. If we use x >= 10 as a replacement for / missing code /, the loop will run as long as x is greater than or equal to 10. When x reaches 10, the loop will stop.

Here's the complete code:

int x = 100;

int total = 0;

while(x >= 10)

{

   total = total + x;

   x = x - 10;

}

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Your question is incomplete but probably the complete question is:

Consider the following code segment, which is intended to store the sum of all multiples of 10 between 10 and 100, inclusive (10 + 20 + ... + 100), in the variable total.

int x = 100;

int total = 0;

while( / missing code / )

{

total = total + x;

x = x - 10;

}

Which of the following can be used as a replacement for / missing code / so that the code segment works as intended?

A x < 100

B x <= 100

C x > 10

D x >= 10

E x != 10

Answer:

Step-by-step explanation:

Not clear

Answer:

130

Step-by-step explanation:

I believe that 1 = 13 for this ratio.

The sample mean of the number of movies watched by 25 students is 2.8 and the approximate sample standard deviation is 1.15.

(a) The sample mean X can be calculated by taking the average of the number of movies watched by all 25 students.

Step 1: Sum up the number of movies watched by all 25 students:

\(0 * 1 + 1 * 2 + 2 * 4 + 3 * 10 + 4 * 6 + 3 * 2 = 0 + 2 + 8 + 30 + 24 + 6 = 70\)

Step 2: Divide the sum from Step 1 by the number of students (25):

70 / 25 = 2.8

So the sample mean X = 2.8

(b) The sample standard deviation s can be calculated using the formula:

\(s = \sqrt{\frac{ \sum(X - X_{mean})^2}{(n-1)} }\)

Where \(X_{mean}\) is the sample mean, n is the sample size, and Σ represents the sum of all values.

Step 1: Calculate \((X - X_{mean})^2\)for each data point and sum up the values:

\((0 - 2.8)^2 * 1 + (1 - 2.8)^2 * 2 + (2 - 2.8)^2 * 4 + (3 - 2.8)^2 * 10 + (4 - 2.8)^2 * 6 + (3 - 2.8)^2 * 2\\ = 7.84 + 3.24 + 0.64 + 9.6 + 1.44 + 7.84\\ = 31.36\)

Step 2: Divide the sum from Step 1 by (n - 1) = 24:

31.36 / 24 = 1.31

Step 3: Take the square root of the result from Step 2:

\(\sqrt{1.31} = 1.15\)

So the approximate sample standard deviation s = 1.15 (rounded to two decimal places).

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the true statements for 8u + 5 + 3v are:

1.) 8u+3v+5 is written as a sum of three terms.

4.)5 is a constant.

The word "constant" in mathematics has several different connotations. When used as a noun, it can have either of the following two meanings: Non-variance (i.e., not changing in relation to some other value) or Variance.

an unchanging number or other non-changing mathematical object that is fixed and well-defined. Sometimes, to distinguish between these two meanings, the terms mathematical constant or physical constant are used.

a function with a constant value (i.e., a constant function).

These constants are frequently represented by a variable that is independent of the main variable or variables in question.

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Answer: 80%. Hope this helps, please consider making me Brainliest.

Step-by-step explanation:

To find the percentage, divide the sale cost by the original cost:

27.60/34.50

Let's multiply both sides by 10 to make the operation easier:

27.6/34.5 ( I eliminated the zero's because they kind of have no use) -->

276/345, now solve:

276/345 = 0.8

0.8 = 80%

The percentage is 80%.

The critical points of the given function are p = 2 ± √13.

A relation between a collection of inputs and outputs is known as a function.

A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.

Each function has a range, codomain, and domain.

Critical function:

The key points are locations inside the function's domain where the function's nature changes.

The function stops increasing or decreasing at these places.

The function is: \(h(p)=\frac{p-2}{p^2+9}\)

The derivative test will be applied here:

\(\begin{aligned}& \therefore h^{\prime}(p)=0 \\& \Rightarrow \frac{d}{d p}\left(\frac{p-2}{p^2+9}\right)=0 \\& \Rightarrow \frac{\frac{d}{d p}(p-2)\left(p^2+9\right)-\frac{d}{d p}\left(p^2+9\right)(p-2)}{\left(p^2+9\right)^2}=0 \\& \Rightarrow \frac{1 \cdot\left(p^2+9\right)-2 p(p-2)}{\left(p^2+9\right)^2}=0 \\& \Rightarrow \frac{-p^2+4 p+9}{\left(p^2+9\right)^2}=0 \\& \Rightarrow-p^2+4 p+9=0\end{aligned}\)

Then,

\(\begin{aligned}& \Rightarrow p_{1,2}=\frac{-4 \pm \sqrt{4^2-4(-1) 9}}{2(-1)} \\& \Rightarrow p_{1,2}=\frac{-4 \pm \sqrt{52}}{-2} \\& \Rightarrow p_{1,2}=-\frac{-4 \pm \sqrt{52}}{2} \\& \Rightarrow p_{1,2}=-\frac{-4 \pm 2 \sqrt{13}}{2} \\& \Rightarrow p_{1,2}=2 \pm \sqrt{13}\end{aligned}\)

Therefore, the critical points of the given function are p = 2 ± √13.

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Answer:

Step-by-step explanation:

a) It has 3 terms.So,  trinomial

b) It has one term. So, monomial

c) It has two terms. So, Binomial

d) It has 3 terms.So,  trinomial

e)  -9x - 2 + 3x = -9x + 3x - 2 = -6x - 2

It has 2 terms.So, binomial

f) It has 2 terms.So,  binomial

Answer:

Given number = 0.44

Find how many times the value of the hundredths place digit to the value of the tenths place digit.

=> Since this is a decimal number, I believe, the value you mean is tenths and hundredths, not tens and hundreds.

Now, how many times is the value of each digit differs from each other:

The answer is 10 times

=> 4 hundredths x 10 = 4 tenths

=> 0.04 x 10 = 0.4, which is correct

Step-by-step explanation:

\(\begin{array}{llll} f(x)~from\\\\ x_1 ~~ to ~~ x_2 \end{array}~\hfill slope = m \implies \cfrac{ \stackrel{rise}{f(x_2) - f(x_1)}}{ \underset{run}{x_2 - x_1}}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array} \\\\[-0.35em] ~\dotfill\\\\ f(x)= 2x^2 + x -3 \qquad \begin{cases} x_1=0\\ x_2=2 \end{cases}\implies \cfrac{f(2)-f(0)}{2 - 0} \\\\\\ \cfrac{[2(2)^2 + (2) -3]~~ - ~~[2(0)^2 +(0) -3]}{2}\implies \cfrac{7-(-3)}{2}\implies \cfrac{7+3}{2}\implies \text{\LARGE 5}\)

The rate of change for the interval between 0 and 2 for the quadratic equation will be 5. Then the correct option is C.

It is the average amount by which the function varied per unit throughout that time period. It is calculated using the gradient of the line linking the interval's ends on the graph depicting the function.

Average rate = [f(x₂) - f(x₁)] / [x₂ - x₁]

The function is given below.

f(x) = 2x² + x - 3

The rate of change of the function for the interval between 0 to 2 is calculated as,

Average rate = [f(2) - f(0)] / [2 - 0]

Average rate = [(2(2)² + 2 - 3) - (2(0)² + 0 - 3)] / 2

Average rate = 10 / 2

Average rate = 5

The rate of change for the interval between 0 and 2 for the quadratic equation will be 5. Then the correct option is C.

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Bring the variable to the left side and all the remaining values to the right side to find the value of x. To find the answer, simplify the values.

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The value for the expression, (f * g)(x) is calculated as: C. 8x³ - 12x² - 6x -1

How to Evaluate the Expressions of Functions?

We are given the following functions,

f(x) = 4x² – 4x + 1 and g(x) = 2x – 1.

To find the value of the expression, (f * g)(x), it means we have to multiply the functions together. See the steps explained below.

(f * g)(x) = f(x) * g(x)

Plug in the values:

(f * g)(x) = f(x) * g(x) = (4x² – 4x + 1)(2x – 1)

(f * g)(x) = 4x²(2x – 1) - 4x(2x – 1) + 1(2x – 1)

Apply the distribution property of equality:

(f * g)(x) = 8x³ – 4x² - 8x² + 4x + 2x – 1

Combine like terms:

(f * g)(x) = 8x³ - 12x² - 6x - 1

Therefore, the answer is: C. 8x³ - 12x² - 6x - 1.

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The fraction that represents the daily value of calcium for 1 cup of the snack food is \(\frac{4}{3}\)

Given that,

So, the fraction should be

\(= \frac{1}{\frac{3}{4} } \\\\= \frac{4}{3}\)

Therefore we can conclude that the fraction that represents the daily value of calcium for 1 cup of the snack food is \(\frac{4}{3}\)

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Step-by-step explanation:

Hey there!

See explanation in picture!

Hope it helps...

Answer:

65,536 kg

Step-by-step explanation:

A nail's length in x weeks of m=0.7 slope with a growth rate of mm per week b starting length follows.

The slope-intercept form of a straight-line equation is indicated by y = mx + b. X and y denote the line's distance from the x- and y-axes, respectively. When x = 0, the value of b equals y, and m indicates how steep the line is.

Given, r(0) = 12

According to the question, fingernail increases by 0.7 millimeters every week. So, m = 0.7 which is the slope of the equation of a straight line.

r(0) = 12 is the b of the y = mx + b.

Now, the final equation is:

r(x) = 0.7x + 12

As a result, the slope of r(x) length of a nail in x number of weeks of m=0.7, with growth rate in mm per week b starting length.

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The coefficient of variation for the given data set is approximately 7.7922%.

The coefficient of variation (CV) is a measure of relative variability that expresses the standard deviation as a percentage of the mean. It is often used to compare the variability of different data sets with different units or scales.

To compute the coefficient of variation, we first divide the standard deviation by the mean:

CV = (standard deviation / mean) x 100%

Substituting the given values, we get:

CV = (12 / 154) x 100% = 7.7922%

Therefore, the coefficient of variation for the given data set is approximately 7.7922%. This means that the standard deviation is about 7.8% of the mean, which indicates a moderate degree of relative variability.

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_____The given question is incorrect, the correct question is given below:

a data set has a mean of 154 and a standard deviation of 12. compute the coefficient of variation.