After brushing, Fluffy's fur has a charge of +8.0 × 10-9 coulombs and her plastic brush has a charge of –1.4 × 10-8 coulombs. If the distance between the fur and brush is roughly 5.0 × 10-1 meters, what is the approximate magnitude of the force between them?

Answer: the water level would rise since the pebble displaces minimal water compared to the boat.

Explanation:..........

Answer:

(a) i) The distance travelled by the cycle in half round is approximately 65.97 m

ii) The displacement is 42 m

(b) (i) The distance travelled in one round is approximately 131.95 m

(ii) The displacement of the cycle in one round is 0

Explanation:

The diameter of the track through which the cycle travels, D = 42 m

(a) i) Half round is the motion of half the length of the circular path

The distance travelled by the cycle in half round = The length of half the circular track = (1/2) × π × D

∴ The distance travelled by the cycle in half round = (1/2) × π × 42 m = 21·π m ≈ 65.97 m

ii) The displacement half round = The change in the location of the cycle = The difference between the start and stop locations of the cycle on a straight line after half round

The angle at the center of the circular path the cycle turns in half round  = 180°

Therefore, the path between the start and stop location of the cycle in half round = The diameter of the circular track

The displacement of the cycle in half round = The diameter of the circular track = 42 m

(b) (i) The distance travelled in one round = The perimeter of the circular track = π·D

∴ The distance travelled in one round = π × 42 m ≈ 131.95 m

(ii) The displacement of the cycle in one round = The change in the location of the cycle

The start and stop location of the cycle after moving one round is the same, therefore, there is no change in the location of the cycle.

Therefore we have;

The displacement of the cycle in one round = 0 (no change in location of the cycle)

it is possible that, when oil reaches a high enough temperature, it can ignite and burn very fiercely, being difficult to extinguish.

The best estimate of gravitational acceleration on that planet is 0.3 times the gravitational acceleration on Earth.

The gravitational field strength, also called acceleration due to gravity or gravitational acceleration, is the gravitational force that acts on a mass of object. It can be expressed as

g = F/m

Where

If your weight on Earth is 850 N, it is 255 N on other planet.

Find the best estimate of the gravitational acceleration on the other planet!

Let's say

From the explanation above, the formula can be written as

g = W/m

The mass of object is always the same in every where it is. So,

m₁ = m₂

850/g₁ = 255/g₂

g₂ = 255g₁/850

g₂ = 0.3g₁

Hence, the gravitational acceleration on the other planet is 0.3 times the gravitational acceleration on Earth.

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The minimum force needed to make the crate start tipping is 294 N.

To find the minimum force required, we need to determine the point at which the torque created by the applied force overcomes the torque created by the crate's weight.

At the tipping point, the applied force acts at a distance equal to the height of the crate (1.6 m), and the weight of the crate acts at a distance of half the crate's depth (0.4 m).
The formula for torque is: torque = force × distance
At the tipping point, the torques balance each other, so:
applied_force × height = weight × (depth/2)
Let's calculate the crate's weight: weight = mass × gravitational_acceleration
weight = 60 kg × 9.8 m/s² = 588 N
Now, we can find the applied force:
applied_force × 1.6 m = 588 N × 0.4 m
applied_force = (588 N × 0.4 m) / 1.6 m
applied_force = 294 N

Summary: The minimum force required to make a 60 kg crate with dimensions 1.6 m x 0.8 m x 0.8 m start tipping is 294 N.

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Answer:

Solid, Liquid and Gas

Explanation:

They are the 3 states or stages of Matter

A driver have to stop for a school bus when the red lights are flashing and there is no barrier between his/her vehicle and the bus.

Traffic rules are rules that are expected to follow by the road users for the safety of everyone using the road.

For instance, when the red lights are flashing , it simply means to stop, while the green light means that the vehicle can continue to move, and yellow light means to be at alert to move.

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Answer:1.5m/s

Explanation:random answer I don’t know anything bro

The acceleration of the eraser is 169.19 m/s².

A body travelling in a circle has centripetal acceleration. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.

Given that angular velocity of the eraser: ω = 127 rpm

= 126×2π/60 radian/second

= 13.2 radian/second.

radius of the circle: r = 0.974 meter.

Hence, its centripetal acceleration is = ω²r

= 13.2×13.2×0.974 m/s²

=169.19 m/s².

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The output force on the piece of food the chopsticks pick up is mechanical advantage times 3 N.

The force amplified by utilising a tool, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, the gadget trades off input forces against movement.

Mathematically:

mechanical advantage = output force/input force

Given that input force = 3 N.

Hence, output force = mechanical advantage × 3 N.

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The distance above the ground the rock  should be dropped such that it hits the ground at 2t after it is released from rest is 4h.

The height of fall of the rock is calculated by applying the following kinematic equation as shown below.

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

g = 2h / t²

h₁ / t₁² = h₂ / t₂²

The distance above the ground the rock  should be dropped such that it hits the ground at 2t after it is released from rest is calculated as;

h₂ = ( h₁ / t₁² )(t₂²)

h₂ = ( h/t²)(2t)²

h₂ = ( h/t²)(4t²)

h₂ = 4h

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The light makes an angle of 81.25° with the normal in the air and the index of refraction of material X will be 1.09. It is determined by Snell's Law.

What is Snell's Law?

Snell's law, also known as the law of refraction, describes the relationship between the angles of incidence and refraction when a wave, such as light, passes from one medium to another. It states:

n₁sin(θ₁) = n₂sin(θ₂),

As the refractive index of water is 1.33. The incidence angle from the image in the first case is 65°, while the refracted angle is 48°. Consequently, the medium X's refractive index will be,

nₓ= n_w*sin48/sin65= 1.09

The incident angle in the second scenario is 48°, and we must determine the refracted angle r for the air.

Since we now know that air has a refractive index of 1, so that the refracted angle is,

sin(r)= n_w* sin48= 0.988

r= sin⁻¹(0.988)= 81.25°

Hence, we can infer that the material X will have an index of refraction of 1.09 and that the angle the light makes with the normal in the air is 81.25° by applying Snell's Law.

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Complete question:

As shown in (Figure 1), a layer of water covers a slab of material X in a beaker. A ray of light traveling upwards follows the path indicated.

a) Using the information on the figure, find the index of refraction of material X .

b) Find the angle the light makes with the normal in the air.

Answer:

The first law, an object will not change its motion unless a force acts on it.

The second law, the force on an object is equal to its mass times its acceleration.

The third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Answer:

Since the mass does not change as the acceleration increases, we can say that force is equal to acceleration. Therefore, if you double the force you double the acceleration. If you increase the mass at a given force the rate of acceleration slows. Therefore, mass is inversely proportional to acceleration.

Answer:

yeet your welcome bro

Explanation:

Answer:

0.1 amps or A

Explanation:

I believe to calculate that you would have to use the formula V = IR and change it to:

I = V/R

I = 1.5/15

I = 0.1 amps or A

The overall magnification of the final image relative to the object m1m2

Magnification is the process of increasing the apparent size of something rather than its physical size. This increase is quantified by a calculated number, also called the "factor". If this number is less than 1, it means size reduction, sometimes called size reduction or reduction.

The term magnification refers to the size of the image produced by the lens compared to the size of the object. For lenses: Magnification "m" is the ratio of image height to object height. The magnification of a lens is defined as the ratio of image height to object height. It is also given by image distance and object distance. equal to the ratio of image distance to object distance.

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Answer:

Before handling money.

Explanation:

Answer:

before handling money

Explanation:

germs are involved with all of the others. you don't have the germs on you that money has before you touch it.

Answer:

acceleration = 0.2 m/s/s

Explanation:

initial velocity u = 14

final velocity v = 20

time = 30

acceleration = ?

v = u + at

20 = 14 + 30a

30a = 6

a = 0.2 m/s/s

Answer:

For the aceleration we have:

V = Vi + a * t

Being:

V = 20 m/s

Vi = 14 m/s

a = ?

t = 30 s

Then, lets replace acording the formula:

20 m/s = 14 m/s + a * 30 s

Clear "a":

a = (20 m/s - 14 m/s) / 30 s

a = (6 m/s) / 30 s

a = 0,2 m/s²

The aceleration of the car is 0,2 meters per second squared.

A. From north to south. Amateur satellites in polar orbits typically have descending passes from north to south.

Amateur satellites, like many other satellites, often follow polar orbits, circling the Earth from the North Pole to the South Pole and vice versa. As they traverse this orbit, the descending pass refers to the portion of the satellite's orbit when it moves from the northern latitudes towards the southern latitudes.

This means that during a descending pass, an amateur satellite will appear to move from north to south across the sky. This direction allows for coverage of different regions of the Earth during each orbit, as the satellite crosses various latitudes from higher to lower as it descends.

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The distanve travelled is d=1200 miles

Time taken is t=420 miles.

The velocity is

The velocity is 2.85 miles/min

Answer:

192 joules

Explanation :

W=Force*distance

Force=m*a

mass=24kg

acceleration=2m/s²

Force=24*2=48

Work done=Force*distance

Force=48

distance=4

Force*distance=48*4=192J

Answer:

Տᗩᗰᗴ ᵐᵃᵗᵉ Տᗩᗰᗴ

\( \infty \infty \)

Answer:

The thunder I know it is to loud

It scares me sooooo much :O

I hope you are having a great day :3❤️

If you build a common-source amplifier with an NMOS input transistor, and you want a current source as a load, and that current source goes from VDD to a node, the type of current source would be the diode-connected transistor.

An NMOS current source implemented as a diode-connected transistor is a type of bipolar transistor circuit that creates a constant current from an input voltage. The collector and emitter of the bipolar transistor are connected together in the circuit, effectively turning the transistor into a diode. The main advantage of diode-connected transistors is that they can generate currents of a specific magnitude and not be influenced by changes in the supply voltage.

The current generated by the diode-connected transistor is almost completely determined by the physical characteristics of the transistor and the biasing resistors used in the circuit. Another advantage of diode-connected transistors is that they may be cascaded in series to create current sources of various sizes. These devices have been commonly used to generate reference currents, voltage-to-current (V-I) converters, and bias currents in linear integrated circuits. So therefore diode-connected transistor is the type of current source, if you build a common-source amplifier with an NMOS input transistor, and you want a current source as a load, and that current source goes from VDD to a node.

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Destructive interference will not occur. When waves interfere constructively, they add up their amplitudes. On the other hand, when waves interfere destructively, they reduce their amplitudes. For two sources of waves to interfere constructively or destructively, they must meet certain conditions.

Constructive interference: When two waves meet each other and interfere constructively, the wave amplitudes add up together. Constructive interference occurs when two waves meet and their phases are in phase with each other, and they have the same frequency. The path difference between the two sources of waves must be an integer multiple of the wavelength. This means that the two waves will be in phase with each other.

For the given observation point, 91.0 m from one source and 221 m from the other source, the path difference can be calculated by taking the difference of the two distances. The distance between two sources is 221-91 = 130 m, which is the path difference. If the wavelength is known, the path difference can be expressed as a fraction of the wavelength. If the path difference is an integer multiple of the wavelength, constructive interference will occur.

Destructive interference: When two waves meet each other and interfere destructively, the wave amplitudes cancel each other out. The wave amplitudes must be in antiphase with each other for destructive interference to occur. This means that the wave from one source is in the opposite phase to the wave from the other source. To produce destructive interference, the path difference between the two sources must be half a wavelength, 1.5 wavelengths, 2.5 wavelengths, etc. For the given observation point, the path difference of 130 m is not half a wavelength, 1.5 wavelengths, 2.5 wavelengths, etc. Therefore, destructive interference will not occur.

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The launch speed of the box is approximately 6 m/s. To find the launch speed of the box, follow these steps:

1. Calculate the elastic potential energy (PE) stored in the spring when it's compressed by 20 cm (0.2 m):

\(PE = (1/2) * k * x^2\)

\(PE = (1/2) * 270 N/m * (0.2 m)^2\)

\(PE = 5.4 J (joules)\)

2. Calculate the work done by friction (W) as the box slides across the floor:

W = friction force * distance

W = (coefficient of kinetic friction * normal force) * distance

Since the box is on a horizontal floor, the normal force equals the gravitational force on the box:

Fg = m * g

where m is the mass of the box and g is the acceleration due to gravity (approximately 9.81 m/s^2).

\(W = (0.23 * m * g) * distance\)

3. Apply the work-energy theorem, which states that the work done on an object is equal to its change in kinetic energy (KE):

\(W = KE_final - KE_initial\)

Since the box starts from rest, KE_initial = 0. So,

\(W = KE_final\)

\(KE_final = 1/2 * m * v^2,\) where v is the launch speed.

4. Equate the work done by friction to the elastic potential energy and solve for v:

\(5.4 J = 1/2 * (0.3 kg) * v^2\)

\(v^2 = (5.4 J * 2) / 0.3 kg\)

\(v^2 ≈ 36\)

\(v ≈ 6 m/s\)

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Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.

Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500

Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000

a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units

Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units

b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production

Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit

Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit

c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production

Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700

Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300

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