After four rounds of fatty acid synthase (FAS) activity, the size of the fatty acyl intermediate would be 16 carbons long. Fatty acid synthase is a multi-enzyme complex responsible for the synthesis of fatty acids in organisms. The process involves repetitive cycles of reactions, each adding two carbons to the growing fatty acyl chain.
Starting with an acetyl-CoA (2 carbons), the first round of FAS activity adds two carbons, resulting in a 4-carbon intermediate. The second round adds another two carbons, making it 6 carbons long. In the third round, two more carbons are added, making it 8 carbons long. Finally, in the fourth round, two additional carbons are added, resulting in a 10-carbon intermediate. At this point, the intermediate is released from the fatty acid synthase complex and can undergo further modifications to form longer fatty acids or participate in other metabolic processes. To synthesize a fatty acid that is 16 carbons long, additional rounds of FAS activity or subsequent elongation steps would be required.
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"A star at the stage in its life cycle when it stops burning Hydrogen, begins
burning bigger elements, and the gas is separating from the core..and
grows much bigger to a large star." What stage in the life cycle does this
describe?
Supernova
Main sequence
Black hole
Red giant or Red supergiant
Answer:
ok
Explanation:
Determine the stars colors and types.
Answer:
Explanation:
A- Supergaint
B- White dwarf
C-White dwarf
D-
E-Main sequence
why do food scientists analyse the dna from meat products
Onepage review on why understanding gas and vapors in a work setting is important and what we can do in our workplace to prevent accidents with gases and vapors.
Understanding gas and vapours in a work setting is incredibly important for workplace safety. Gas and vapours can contain noxious substances that, if exposed to, can lead to serious injury or health implications.
In order to prevent such accidents, employers must perform risk assessments in order to assess and identify any areas of risk and put in place control measures to limit them. If gas and vapours are used onsite, then suitable ventilation and extraction systems should be in place.
Employers should also ensure that their staff are aware of the potential risks associated with such substances and provide adequate training and instruction in how to work safely. Finally, employers should also check that any necessary personal protective equipment is provided and communications are in place to be able to notify relevant emergancy responders in case of an accident.
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Which starch molecules has the greatest ability to thicken?
- dextrin - modified starch
- amylose
- amylopectin
Among the starch molecules, modified starch has the greatest ability to thicken. The correct answer is B.
What is modified starch?Starches that have been chemically modified to increase their stability against excessive heat, acid, salt, or shear are known as modified starches. They are used in food and non-food industries as thickeners, emulsifiers, stabilizers, and binders because of their unique properties.
Amylose, dextrin, and amylopectin are three different types of starch molecules that are found naturally in plants. Modified starches are prepared by subjecting them to chemical, enzymatic, or physical treatments, resulting in a variety of molecular, physicochemical, and functional properties.
These modifications alter the starch molecules' viscosity, gelling, and stability features. However, among the various types of starch molecules, modified starches have the greatest ability to thicken.
As a result, it is frequently used as a thickening agent in various food and non-food products. Some common examples of modified starches include acetylated distarch phosphate, octenyl succinate starch, hydroxypropyl starch, and others.
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In 1980, a long dormant volcano, Mount St. Helens in Washington state, erupted violently. The eruption wiped out the forested landscape and the wildlife. Months after the initial disturbance, the ash and rock strewn surface began to undergo primary succession.
Answer:
New vegetation and animals came to this place when the environment is suitable.
Explanation:
The ash and rock strewn surface began to undergo primary succession after few month when the soil is cool down because the soil has nutritive medium that helps the vegetation to grow on that land. In the primary succession, the new vegetation grows which is well suited to that environmental condition and uses the nutrients present in that soil for its growth and development. Many new organisms also came to this new landscape when the environment is suitable.
Which of the following is most likely to contribute to density-dependent regulation of populations? Group of answer choices Individuals voluntarily stop mating so that overcrowding does not occur. Density-independent factors lead to fewer births and increased mortality. The incoming energy decreases in populations experiencing a high rate of increase. Density-dependent factors lead to fewer births and increased mortality.
Answer:
Density-dependent factors lead to fewer births and increased mortality.
Explanation:
The carrying capacity can be defined as the maximum population size an environment can support. Density-dependent limiting factors produce a logistic growth pattern (S curve) in the population until it reaches its carrying capacity, thereby decreasing the birth rate and increasing the mortality rate in the population. Some important density-dependent limiting factors able to control the size of the population are competition (intraspecific competition), predation and diseases.
Plants growing high up on mountains tend to be much smaller than those growing at sea level. This is because the rate of photosynthesis for plants on the mountain is slower. Which factor is at a lower level in the mountain environment, causing a limit to the rate of photosynthesis?
Answer:
CO2
Explanation:
what dose the Sixth and Ninth commandment ask us to do?
Answer: To not take a life and to not lie
Explanation: The sixth commandment tells us to not take a life. And the ninth commandment tells us to not lie/ bare false witness.
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Predict the most likely outcome of culturing transformed E. coli in the presence of tetracycline.Justify your prediction.
Answer:
E.coli is a bacterium which is preffered for transformation due to its rapid growth and high efficiency of introduction of DNA molecules into cells.
Tetracycline is an antibiotic used to treat several infections such as cholera, plague, brucellosis, and malaria etcetra.
Plasmid is a small, extrachromosomal DNA molecule present in cell which is seprated from chromosomal DNA and have ability to replicate independently.
When a plasmid resistant to tetracycline and kanamycine is inserted into E.coli, the process is called transformation. E.coli might not be able to survive due to absence of plasmid but the transformed strains having antibiotic tetracycline and kanamycine will probably be able to survive it.
Hence, the culture of bacteria carrying plasmid will be able to survive only.
Maximum transformation to tetracycline achieved when cells were harvested from L broth at 5.0-6.0 cfu/ml , followed by washing twice in cold.
The susceptibility of E.coli strain to culturing transformation by plasmid DNA was examined and optimized.
TransformationCells grown within the presence of D - cycloserine ( Cyc ) rather than Neg Gram (N x) transformed better. The presence of 5 mm Mg2+ ions in washing and CaCl2 solutions stimulated transformation about 2-fold.
Optimal conditions for transformation included a pH range of seven. 25-7.75 and a cell-to-DNA ratio of about 1.6 . 10(8) cfu/ng plasmid DNA.
The frequency of transformation was highest when cells were exposed to 100 mM CaCl2 in 250 mm.
Composition\(\rm KCl + 5 mM \;MgCl2 + 5 mM \;Tris\)
pH 7.6, before mixing with DNA
Therefore, the results of culturing transformed E.coli within the presence of tetracycline is justified.
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Select the correct answer from each drop-down menu. Plants use sunlight to convert nutrients into energy. What form of energy transfer is taking place?
The chemical, potential, radiant, or sound energy of the Sun is converted into chemical, kinetic, mechanical, or thermal energy by the plants.
Answer:
The chemical radiant or sound energy. If thats the way I should answer this question.
Hey guys. So I need your help I have this rock presentation assignment worth 90 points and I have to find a good title. It’s about sample rocks granite sandstone and Phyllite. All from sedimentary igneous and metamorphic please help me find the right title! Thank you. (science)
Answer:
stone is stone , the most beautiful stone it is right I think
in neoproterozoic rocks about 570 million years old, evidence of multicellular animal life called the ediacara fauna consists of group of answer choices imprints of soft-bodied organisms. resting stages (or cysts) of dinoflagellates. trace fossils, imprints of soft-bodied fossils, and skeletal fossils. small skeletonized animals.
Neoproterozoic rocks that are about 570 million years old are known for having evidence of multicellular animal life called the Ediacara Fauna. The Ediacara Fauna are a group of soft-bodied organisms that are only known from their imprints. The Ediacara fauna is unique in that it is the oldest group of animals that has been discovered to date.
The Ediacara fauna was first discovered in 1946 in the Ediacara Hills of South Australia. Since then, similar fossils have been found in other parts of the world including Russia, China, Canada, and Namibia. Trace fossils, imprints of soft-bodied fossils, and skeletal fossils are found in these rocks.
Trace fossils are imprints or marks left by animals as they moved across the sediment at the bottom of the sea. Soft-bodied fossils are imprints of the body parts of animals that did not have hard skeletons. Skeletal fossils are the remains of animals that had hard parts such as shells or bones.
Small skeletonized animals are also found in these rocks. These animals had hard skeletons that are preserved in the rocks. They are the oldest animals with hard skeletons that have been discovered to date. These animals were likely the first animals to be able to move around freely on the seafloor.
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Select the correct answer.
A man has blood type AB and his wife has blood type B. What are the possible blood types for their child?
OA blood types A and B
OB. blood type AB
OC blood types A, B, and AB
Reset
Next
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O
Lenovo
Answer:
If a man has blood type AB ans his wife has blood type B. The possible blood types for their child is A, B and AB.
Growth _____.
usually increases the complexity of an organism's structure
is unpredictable
occurs only in multicellular organisms
only increases size of cells
Answer:
A.
Explanation:
Seems like A. would be the best option here.
Answer:
Growth usually increases the complexity of an organism's structure
Explanation:
starting with the cecum and ending with the anus, name all parts of the large intestine in order. how does the large intestine convert liquid waste from the small intestine into solid waste to be stored then eliminated from the body?
Large intestine starts with cecum, then ascending colon, transverse colon, descending colon, sigmoid colon, rectum. Large intestine convert liquid waste into solid waste by absorbing water from it.
Large intestine continues with the small intestine through an ileocecal valve, then it moves upwards in abdomen which is called ascending colon, then it moves transversely in the abdomen which is called transverse colon then it moves downward which is called descending colon then it connects to rectum . Waste that reaches ascending colon will be in liquid form then waste will be converted to solid form as it moves through the Large intestine. Feces will be stored in rectum until it gets defecated.
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Describe one feature that a spreadsheet has
that a database does not have.
The estimated percentage of cancers that are due to poor diet and lifestyle habits is approximately Group of answer choices3/41/21/31/4
Solution:
A large body of literature indicates that 30% to 40% of all cancer cases are related to poor dietary or lifestyle habits.
That is equivalent to 1/3.
So that the correct answer is:
1/3
which of the following sections of the spinal cord does not form a nerve plexus? a) Cervical b) Lumbar c)sacral d)thoracic
The section of the spinal cord that does not form a nerve plexus is d) thoracic. The other sections, a) cervical, b) lumbar, and c) sacral, form nerve plexuses.
A nerve plexus is a network of nerves that arise from the merging of several spinal nerves. The cervical, lumbar, and sacral sections of the spinal cord form major nerve plexuses that innervate the limbs and other areas of the body. However, the thoracic section of the spinal cord has a different function and does not participate in the formation of a nerve plexus.
Nerve plexuses are networks of nerves that branch and recombine, providing pathways for nerve signals to travel. The cervical plexus corresponds to the neck region, the lumbar plexus to the lower back, and the sacral plexus to the pelvic area. The thoracic region, located in the upper and middle back, does not form a nerve plexus; instead, it has individual spinal nerves known as intercostal nerves.
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Colonial organisms are a type of multicellular organism.
O True
O False
Most of the skin's resident biota are found in the uppermost, superficial layers of the epidermis. True False.
False.The skin's resident biota are predominantly located in the deeper layers of the epidermis, hair follicles, and sweat glands, rather than the uppermost, superficial layers of the epidermis.
Most of the skin's resident biota are found in the deeper layers of the epidermis and within the hair follicles and sweat glands. The uppermost, superficial layers of the epidermis are relatively devoid of microbial populations.The skin is home to a diverse microbial community, collectively known as the skin microbiota. These microorganisms, including bacteria, fungi, and viruses, colonize various niches on the skin. While some microbes can be found on the surface of the skin, the majority reside in the deeper layers of the epidermis and within the hair follicles and sweat glands.This distribution pattern is primarily due to the presence of sebaceous glands, sweat glands, and hair follicles, which provide the necessary nutrients and microenvironments for the growth and survival of these microorganisms. Additionally, the composition and abundance of the skin microbiota can vary across different body regions and individuals.
The skin's resident biota are predominantly located in the deeper layers of the epidermis, hair follicles, and sweat glands, rather than the uppermost, superficial layers of the epidermis.
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How might the carbon cycle be altered after a large scale reforestation effort ?
Answer:
Deforestation has an effect on the Carbon Cycle also known as the Greenhouse gas effect and global warming. Trees and forests balance the amount of Carbon in the atmosphere through the process of photosynthesis in which plants make their own food with carbon dioxide. This excess heat warms the earth.
Explanation:
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what do you notice is the main difference between the structure of the connective tissues and the structure of the epithelium? make sure to note the organization of cells in these two tissue types. how does this structure relate to function?
In the structure of epithelium, the cells are arranged in a regular fashion, either in a single layer or stacked one upon another to form many layers. Whereas in the connective tissues, the arrangement of the cells depends upon the location of the tissue, the cells are arranged irregularly. They can be either loosely packed or densely packed.
Since the function of epithelium is to form the outer layer of the skin or form the lining of organs, therefore the cells are arranged in a regular fashion to completely cover the organ they are present in.
Connective tissues have the function of supporting the other tissues or organs. For this the cells are arranged in an irregular haphazard manner so that they support the organ as well as remain light-weighed.
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which of the following is generally true of k-strategist species as compared to r-strategist species? responses they reach sexual maturity earlier. they reach sexual maturity earlier. they have more young. they have more young. they are more likely to be invasive species. they are more likely to be invasive species. they have longer life spans. they have longer life spans. their population cycles are more rapid.
They have longer life spans is generally true of k-strategist species as compared to r-strategist species.
What do you mean by r-strategist species?R- and K-selection constrain the range of viable species through the colonization-competition tradeoff, with strong r-selection favoring colonizers and strong K-selection favoring competitors.
Moreover, dandelions are particularly good examples of R-selected traits because they have several of the physical characteristics associated with R-selected traits including: rapid development, small size, and short lifespan.
r/K selection theory relates to the selection of combinations of traits in an organism that trade off between quantity and quality of offspring.
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Certain things need to come in and other things need to be send out of the cellWhich of the following is NOT example a the cell needs to bring into the cell?
A.Sugars
B.Oils
C.protein
D.fats
During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the
a) β‑1,4 linkages, but not the β‑1,6 linkages.
b) β‑1,4 linkages, but not the α‑1,6 linkages.
c) α‑1,4 linkages, but not the α‑1,6 linkages.
d) α‑1,6 linkages, but not the α‑1,4 linkages.
During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the option c- c) α‑1,4 linkages, but not the α‑1,6 linkages.
During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the α-1,4 linkages between glucose residues in the glycogen molecule. However, it cannot break the α-1,6 linkages present at the branch points of the glycogen molecule.
Therefore, the correct answer is: c) α-1,4 linkages, but not the α-1,6 linkages.
Glycogen phosphorylase is an enzyme that catalyzes the breakdown of glycogen to release glucose-1-phosphate. It cleaves the α-1,4 linkages between glucose residues by adding a phosphate group from inorganic phosphate to the C1 carbon of glucose, forming glucose-1-phosphate.
This process continues until a point of four glucose residues remaining on a branch.
At the branch points of glycogen, there are α-1,6 linkages that hold the glucose residues together. These branch points are cleaved by another enzyme called α-1,6 glucosidase, also known as debranching enzyme.
The debranching enzyme first moves three glucose residues from the branch to the non-reducing end of another chain by breaking the α-1,4 linkage. It then cleaves the α-1,6 linkage, releasing a free glucose molecule and the remaining glucose chain.
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During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the option c- c) α‑1,4 linkages, but not the α‑1,6 linkages.
During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the α-1,4 linkages between glucose residues in the glycogen molecule. However, it cannot break the α-1,6 linkages present at the branch points of the glycogen molecule.
Therefore, the correct answer is: c) α-1,4 linkages, but not the α-1,6 linkages.
Glycogen phosphorylase is an enzyme that catalyzes the breakdown of glycogen to release glucose-1-phosphate. It cleaves the α-1,4 linkages between glucose residues by adding a phosphate group from inorganic phosphate to the C1 carbon of glucose, forming glucose-1-phosphate.
This process continues until a point of four glucose residues remaining on a branch.
At the branch points of glycogen, there are α-1,6 linkages that hold the glucose residues together. These branch points are cleaved by another enzyme called α-1,6 glucosidase, also known as debranching enzyme.
The debranching enzyme first moves three glucose residues from the branch to the non-reducing end of another chain by breaking the α-1,4 linkage. It then cleaves the α-1,6 linkage, releasing a free glucose molecule and the remaining glucose chain.
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Why is it in the best interest of a parasite not to kill its host? Explain.
A parasite typically does not want to kill its host, as doing so would lead to its own death. If a parasite kills its host, it would lose its source of food and shelter, which is why it's in the parasite's best interest not to kill its host. A parasite is a type of organism that lives on or inside another organism, known as the host.
This relationship is parasitic because the parasite benefits from the host while the host is harmed by the parasite. A parasite can be harmful to its host in various ways, such as by consuming its tissues, competing with it for nutrients, and releasing toxins. However, most parasites do not want to kill their host, as doing so would mean that they would lose their home and source of nutrition. Parasites have evolved over time to live in harmony with their hosts, allowing both to survive. Parasites have adapted to live within their hosts without killing them by developing various strategies to avoid detection by the host's immune system. For example, some parasites can change their outer coat to evade detection by the host's immune system. Overall, it's in the parasite's best interest not to kill its host so that it can continue to feed and reproduce.
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arrange the steps of gluconeogenesis in order, from pyruvate to glucose
Gluconeogenesis is the process through which piruvate is converted into glucose. The order is 1. Carboxylation of pyruvate , 4. phosphorylation of 3-phosphoglycerate , 2. hydrolysis of fructose 1,6-bisphosphate, 5. isomerization of fructose 6-phosphate., 3. hydrolysis of glucose 6-phosphate.
What is gluconeogenesis?
Gluconeogenesis is the glucose synthesis from piruvate molecules. Any metabolite capable of being converted into piruvate can be a glucose precursor.
Gluconeogenesis steps are as follows,
1) First occurs the convertion of piruvate to phosphoenolpiruvate.
2) Phosphoenolpiruvate turns into glyceraldehyde 3-phosphate.
3) The next step is to convert Glyceraldehyde 3-phosphate into fructose 1,6-bisphosphate.
4) Then occurs the conversion of fructose 1,6-bisphosphate into fructose 6-phosphate
5) Finally, conversion of glucose 6-phosphate into glucose
The correct order is,
1. Carboxylation of pyruvate
4. phosphorylation of 3-phosphoglycerate
2. hydrolysis of fructose 1,6-bisphosphate
5. isomerization of fructose 6-phosphate.
3. hydrolysis of glucose 6-phosphate
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Complete question
Crrange the steps of gluconeogenesis in order, from pyruvate to glucose
carboxylation of pyruvatehydrolysis of fructose 1,6-biphosphatehydrolysis of glucose 6-phosphatephosphorylation of 3-phosphoglycerateisomerization of fructose-6-phosphateWhat is the human genome project?
Answer:
The Human Genome Project was an international scientific research project with the goal of determining the base pairs that make up human DNA, and of identifying and mapping all of the genes of the human genome from both a physical and a functional standpoint
Answer:
The HGP was an international research program responsible for mapping all understandings of human DNA
Explanation:
This project was started 1990 and completed in April of 2003. Hope this helped :)
State the beginning reactants and the end products glycolysis, alcoholic fermentation, the citric acid cycle, and the electron transport chain. Describe where these processes take place in the cell and the conditions under which they operate (aerobic or anaerobic), glycolysis: alcoholic fermentation: citric acid cycle: electron transport chain
Glycolysis, the initial step in cellular respiration, begins with glucose as the reactant and produces two molecules of pyruvate as the end product. This process occurs in the cytoplasm of the cell and is anaerobic, meaning it can occur in the absence of oxygen.
Alcoholic fermentation begins with pyruvate, which is converted into ethanol and carbon dioxide. This process takes place in the cytoplasm of yeast cells and some bacteria, operating under anaerobic conditions. Alcoholic fermentation is utilized in processes such as brewing and baking.
The citric acid cycle, also known as the Krebs cycle or the tricarboxylic acid cycle, starts with acetyl-CoA as the reactant. Acetyl-CoA is derived from pyruvate through a series of enzymatic reactions. The cycle takes place in the mitochondria of eukaryotic cells. During the citric acid cycle, carbon dioxide, ATP, NADH, and FADH2 are produced as end products. This cycle operates under aerobic conditions, meaning it requires the presence of oxygen.
The electron transport chain is the final stage of cellular respiration. It takes place in the inner mitochondrial membrane of eukaryotic cells. The reactants for this process are the electron carriers NADH and FADH2, which were generated during glycolysis and the citric acid cycle. The electron transport chain uses these carriers to generate ATP through oxidative phosphorylation. Oxygen acts as the final electron acceptor in this process, combining with protons to form water. The electron transport chain operates under aerobic conditions, as it requires the presence of oxygen to function properly.
Overall, glycolysis and alcoholic fermentation are anaerobic processes occurring in the cytoplasm, while the citric acid cycle and the electron transport chain are aerobic processes taking place in the mitochondria
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